Please do these please do all of them and no fake stuff

A 500 N force is applied to a 25m/s2 object. The mass of the object is 20kg. The correct answer is option: A.

The force applied to an object is related to its mass and acceleration through the equation:

F = ma,

where F is the force, m is the mass, and a is the acceleration. Rearranging this equation, we get:

m = F/a.

In the given problem, a force of 500 N is applied to the object, and its acceleration is 25 m/s^2.

Substituting these values in the formula, we get :

m = 500 N / 25 m/s^2 = 20 kg.

Therefore, the mass of the object is 20 kg, which is option A.

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Answer:

The power of the kettle is P = 1 watt.

Explanation:

The definition of power is:

Power equals the quotient between work and time, or:

P = w/t.

In this case, we know that the work is:

w = 1J

And the time is:

t = 1 s

Then the power will be:

P = 1J/1s = 1 J/s

Also knowing that:

1 J/s = 1 W

(w is the unit for Watt)

We can conclude that the power of the kettle is:

P = 1 W

Answer:

if there isn't a shorting mechanism, the whole sets will be blown out several lamps and then shortened, the overall resistance of the remaining operating lamps will be decreased resulting in an increased working current that is adequate to blast the fuse

Answer:

Since there is more centrifugal force at the equator to cancel gravity, your overall weight at the equator versus at the poles is even less

Explanation:

Answer:

Please find the calculated values entered into the following table;

\(\left\begin{array}{ccccc}Object & Mass \ (kg)& Weight \ (N) & Height \ (m)&G.P.E.\\A&5&50&2&100\\B&2&20&6&120\\C&8&80&5&400\\D&20&200&0.6&120\\E&5,000&50,000&2&100,000\\F&0.2&2&10&20\\G&67&670&44&29,480\end{array}\)

Explanation:

The given parameters are;

The acceleration due to gravity, g ≈ 10 N/kg

The Gravitational Potential Energy, G.P.E. = m × g × h

The weight of the object, W = m × g

∴ G.P.E. = W × h

The table is filled using the above formula for calculations as follows;

For object A, we have;

Weight = 5 kg × 10 N/kg = 50 N

G.P.E. = 50 N × 2 m = 100 J

For object B, we have;

Weight = 2 kg × 10 N/kg = 20 N

G.P.E. = 20 N × 6 m = 120 J

For object C, we have;

Weight = 8 kg × 10 N/kg = 80N

G.P.E. = 80 N × 5 m = 400 J

For object D, we have;

Weight = 20 kg × 10 N/kg = 200 N

G.P.E. = 200 N × 0.6 m = 120 J

For object E, we have;

Weight = 5,000 kg × 10 N/kg = 50,000 N

G.P.E. = 50,000N × 2 m = 100,000 J

For object F, we have;

Weight = 0.2 kg × 10 N/kg = 2 N

G.P.E. = 2 N × 10 m = 20 J

For object G, we have;

Weight = 67 kg × 10 N/kg = 670 N

G.P.E. = 670 N × 44 m = 29,480 J

Therefore, we have the table filled as follows;

\(\left\begin{array}{ccccc}Object & Mass \ (kg)& Weight \ (N) & Height \ (m)&G.P.E.\\A&5&50&2&100\\B&2&20&6&120\\C&8&80&5&400\\D&20&200&0.6&120\\E&5,000&50,000&2&100,000\\F&0.2&2&10&20\\G&67&670&44&29,480\end{array}\)

Main answer: The maximum acceleration of a platform that oscillates with an amplitude of 2.3 cm at a frequency of 7.1 Hz is approximately 101.91 m/s^2.

The formula for acceleration in simple harmonic motion is: a = -w^2 x where a is the acceleration, w is the angular frequency (2πf), and x is the displacement from equilibrium. In this case, the amplitude (A) is given as 2.3 cm, which means that the displacement (x) is half of that, or 1.15 cm (0.0115 m). The frequency (f) is given as 7.1 Hz, so the angular frequency (w) is: w = 2πf = 2π(7.1) = 44.62 rad/s

Now we can use the formula for acceleration to find the maximum acceleration (a): a = -w^2 x = -(44.62)^2(0.0115) = -107.46 m/s^2 However, we need to remember that this is the acceleration at the maximum displacement, which is only half of the amplitude. To get the maximum acceleration, we need to multiply this value by 2: a_max = 2|a| = 2(107.46) = 214.92 m/s^2 Finally, we need to remember that the acceleration is negative because it is in the opposite direction of the displacement. So the maximum acceleration is: a_max = -214.92 m/s^2

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Answer:

D

Explanation:

To determine the effect of stirring on the time for sugar to dissolve in water.

There's no mention of temperature so it can't be b. There's the same amount of sugar and water in each cup so It can't be A or C therefore D is the only likely answer.

Answer:

Epicenter

Explanation:

The epicenter is the location of tectonic plate movement where an earthquake begins.

Answer:

6500g

Explanation:

7000 - 500 = 6500

The mass of paint will be "6500 g".

Given:

Total mass,

Volume,

Mass of empty tin,

Now,

The mass of paint will be:

= Total mass - Mass of empty tin

By putting the values, we get

= \(7000-500\)

= \(6500 \ g\)

Thus the approach above is correct.

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Intensity changes as a result in resultant wave.

When two waves are in phase and their maxima add, a process known as constructive interference occurs where the combined amplitude of the two waves equals the sum of their individual amplitudes. The minima of the waves would line up similarly.

A wave of amplitude 2A is produced when two waves with the same phase, frequency, and amplitude (A) superimpose. As a result, its intensity doubles. The maximum angle at which fringes can be seen on a screen is 90°.

Condition for constructive interference: ΔL = nλ, where n is any integer. The quantity I represents the wave's intensity as a function of the two (identical) parent waves' phase differences.

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Answer:

violet has the highest frequency

Explanation:

The correct answer would be (c), because the orbits cannot be associated with the spiral arms of a galaxy.

Therefore the correct answer is c) The orbits.

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Option A is a true. An SUV strikes a motorcycle that is standing still. The motorcycle can withstand more force than the SUV since it is stationary.

Every time one object applies force to another, the other object applies an equal and opposing force to the first. His third law argues that there is an equal and opposite reaction to every action (force) in nature. If you push a truck and a vehicle with the same amount of effort, the car will accelerate faster than the truck since it is lighter. Due to the full shopping cart's greater bulk compared to the empty one, it is simpler to push one than the other.

In the early stages of having enough grip, engineers frequently discuss "power to weight ratio" because this impacts acceleration. Since it takes longer (more time) to accelerate a heavier car with the same amount of power to go the same distance, more fuel is consumed.

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A brown dwarf is a starlike body that do do not have enough mass to ignite hydrogen fusion in their centers.

Brown dwarf refer to a body of substellar that is not huge or big enough to undergo nuclear fusion of o hydrogen into helium in their cores. This formed when there is contraction of gases in the intercellar spaces. The have a mass between 13 to 80 times that of Jupiter.

Therefore, brown dwarf is a starlike body that do don't not have enough mass to ignite hydrogen fusion in their centers.

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Answer:

1. 360/6=60 Kilometers per hour

2. 120/3=40 Kilometers per hour

The new power required to maintain a constant speed on the incline is 18.27 hp.

a. The power the car must produce Pi to maintain its speed is given by the equation:
\(Pi = Fd x v\)
where Fd is the drag force and v is the constant speed. Substituting the values given:
\(Pi = 260 N x 26 m/sPi = 6760 W\)
b. To convert the power to horsepower (hp), we use the conversion factor:
\(1 hp = 746 W\)
Therefore, the power in horsepower (hp) is:
\(Pi (hp) = Pi / 746Pi (hp) = 9.06 hp\)
c. When the car encounters an incline, it experiences an additional force due to gravity. The new power required to maintain a constant speed is given by:
\(Pi' = (Fd + Fg) x v\)
where Fg is the force due to gravity, which is given by:
\(Fg = m x g x sin(theta)\)
where m is the mass of the car, g is the acceleration due to gravity, and theta is the angle of the incline.
Substituting the values given:
\(Fg = 2050 kg x 9.81 m/s^2 x sin(6)Fg = 219.9 NPi' = (260 N + 219.9 N) x 26 m/sPi' = 13633.4 W\)
Converting to horsepower (hp):
\(Pi' (hp) = Pi' / 746Pi' (hp) = 18.27 hp\)
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Answer: Green line

Explanation:

When an object is moving at constant velocity or speed rather, the line on a graph will be represented by a straight line.

They would be maintaining the same speed over a period of time so on a graph with time like the above, their journey would appear to be horizontal which would make the green line correct.

Answer:

Hope this helps!!!

Explanation:

Answer:

89.53    North

Explanation:

Total N-S displacement

   23.72  -  39.25 + 105.06   =  + 89.53

Answer:

Potassium and iodine

Explanation: I took the quick check

Answer:

W= 20000j

Explanation:

W= fd = 1000N(20m) = 20000j

The displacements and velocities at times (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for the ball thrown straight up with an initial velocity of 15.0 m/s are as (a)10.1 m/s (upwards),(b) 5.0 m/s (upwards),(c)0.2 m/s (downwards) and (d) -4.8 m/s (downwards)

To calculate the displacement and velocity at different times for a ball thrown straight up with an initial velocity of 15.0 m/s, we can use the following equations of motion:

Displacement:

y = y₀ + v₀t - (1/2)gt²

Velocity:

v = v₀ - gt

where:

y is the displacement at time t

y₀ is the initial position (point of release)

v₀ is the initial velocity

g is the acceleration due to gravity (approximately -9.8 m/s²)

t is the time

Given that the point of release is taken as the origin (y₀ = 0), we can calculate the displacement and velocity at different times:

(a) At t = 0.500 s:

Displacement:

y = 0 + (15.0 m/s)(0.500 s) - (1/2)(9.8 m/s²)(0.500 s)²

y ≈ 5.12 m

Velocity:

v = 15.0 m/s - (9.8 m/s²)(0.500 s)

v ≈ 10.1 m/s (upwards)

(b) At t = 1.00 s:

Displacement:

y = 0 + (15.0 m/s)(1.00 s) - (1/2)(9.8 m/s²)(1.00 s)²

y ≈ 10.1 m

Velocity:

v = 15.0 m/s - (9.8 m/s²)(1.00 s)

v ≈ 5.0 m/s (upwards)

(c) At t = 1.50 s:

Displacement:

y = 0 + (15.0 m/s)(1.50 s) - (1/2)(9.8 m/s²)(1.50 s)²

y ≈ 11.6 m

Velocity:

v = 15.0 m/s - (9.8 m/s²)(1.50 s)

v ≈ 0.2 m/s (downwards)

(d) At t = 2.00 s:

Displacement:

y = 0 + (15.0 m/s)(2.00 s) - (1/2)(9.8 m/s²)(2.00 s)²

y ≈ 12.0 m

Velocity:

v = 15.0 m/s - (9.8 m/s²)(2.00 s)

v ≈ -4.8 m/s (downwards)

Therefore, the displacements and velocities at times (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for the ball thrown straight up with an initial velocity of 15.0 m/s are as 10.1 m/s (upwards), 5.0 m/s (upwards),0.2 m/s (downwards) and  -4.8 m/s (downwards)

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Among the given options d. Shatong​ is not a target game.

In the Filipino game of "Batuhang Bola," participants aim tiny stones or balls towards a target to get points. In the Filipino game of "Tumbang Preso," participants attempt to topple a tin can by hurling slippers or other things at it. Chinese Garter is a jumping game where participants attempt to conquer higher levels with each successful jump over a stretched garter or elastic band held by two persons.

Shatong is not a game of aim or a target. Using sticks or straws, participants attempt to flick or strike tiny shells or pebbles in order to get them to drop on a target or inside a defined area. In contrast to the other games listed above, it does not entail hitting or aiming at a particular target. Thus, it is not a target game.

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Motion is created by kinetic energy. K.E. = 1/2 mv2 can be used to calculate an object's kinetic energy.

Motion is the change in an object's location with relation to time. Motion is described mathematically using terms like displacement, velocity, distance, kinetic energy, and speed.

Kinetic energy is essentially the energy underlying motion and can be observed in the movement of objects or subatomic particles. Every atom or object in motion contains kinetic energy.

A human walking, a baseball flying through the air, food falling from a desk, and an alpha object in an electric field are all example of kinetic in action.

The equation for calculating the angular momentum of an object with mass m and motion is K.E. = 1/2 mv^2.

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The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Answer:

$18

Explanation:

Each of the was qiven $18

All together =24

24 divide it by 4 (because there were 4 people there)

= 6  (6+6+6+6)

= 24

=6+12=18    

.Hence each of them was given $18

Answer:

4(m−12)=24

4m-48=24

4m= 24+48

4m=72

m=18

Explanation:

it correct i did it on my school work and get an A+

Answer:

The mass of the object and its height in the gravitational field of the Earth.

Explanation:

If we are talking about gravitational potential energy which is defined as:

\(U=m\,*\,g\,*\,h\)

being "m" the object's mass, "g" the acceleration due to gravity, and "h" the height at which the object is located relative to the conventionally picked level for zero of potential energy.

As long as the value of "g" is constant, the only two variables that determine the gravitational potential energy are the mass (m) of the object and its relative height (h).

Answer:

The objects weight and height above Earth's surface

Explanation:

K12 :)

a) The angular velocity of a geostationary satellite is the same as the angular velocity of the Earth, which is approximately 2*pi radians per day. Therefore, the angular velocity of a geostationary satellite is approximately 2*pi/86400 = 7.27*10^-5 rad/s.

b) The acceleration of a freely falling body is given by the formula g = GM/r^2, where G is the gravitational constant, M is the mass of the Earth, and r is the radius of the orbit. Substituting the values given in the problem, we get g = (6.67*10^-11 N*m^2/kg^2)*(5.97*10^24 kg)/(4.2*10^4 m)^2 = 9.8 m/s^2. This is the same value as the acceleration due to gravity at the surface of the Earth.

A geostationary orbit is otherwise known as a geosynchronous equatorial orbit. It is a circular geosynchronous orbit 35,786 km in altitude above Earth's equator and following the direction of Earth's rotation.

Therefore, the correct answer is as given above

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Answer:

Many factors have been shown to affect reaction times, including age, gender, physical fitness, fatigue, distraction, alcohol, personality type, and whether the stimulus is auditory or visual.

Explanation:

\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Kinematics.

So here we use the newton 3rd equation of motion,

\( {v}^{2} = {u}^{2} - 2as\)

so after solving we get as,

Velocity= 14 m/s