Answers
Related Questions
A pulley in the form of a uniform disk)
with mass 63 kg and a radius 20 cm is at-
tached to the ceiling in a uniform gravita-
tional field and rotates with no friction about
its pivot. The masses are connected by a
massless inextensible cord and T1, T2, and T3
are magnitudes of the tensions.
T3
20 cm
T2
63 kg
1
39 kg
T1
3.8 m
15 kg
2
What is the magnitude of the tension T?
The acceleration due to gravity is 9.8 m/s?.
Assume up is positive.
Answer in units of N.
Answers
For a pulley in the form of a uniform disk with a mass of 63 kg and a radius of 20 cm, the magnitude of the tension T is mathematically given as
T1=292.4N
What is the magnitude of the tension T?For 20kg
T1=196+20a
For
33kg
T2=323.4-33a
Generally, the simultaneous equation is mathematically given as
T2-T1=(323.4-33a)-(196+20a)
Hence
127.4-53.a
a=1.67m/s^2
T1=196+20(1.67)
T1=292.4N
In conclusion, the magnitude of the tension T
T1=292.4N
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According to the nebular theory of solar system formation, what key difference in their early formation explains why the jovian planets ended up so different from the terrestrial planets
Answers
Answer:
The Jovian planets formed beyond the Frostline while the terrestrial planets formed in the Frostline in the solar nebular
Explanation:
The Jovian planets are the large planets namely Saturn, Jupiter, Uranus, and Neptune. The terrestrial planets include the Earth, Mercury, Mars, and Venus. According to the nebular theory of solar system formation, the terrestrial planets were formed from silicates and metals. They also had high boiling points which made it possible for them to be located very close to the sun.
The Jovian planets formed beyond the Frostline. This is an area that can support the planets that were made up of icy elements. The large size of the Jovian planets is as a result of the fact that the icy elements were more in number than the metal components of the terrestrial planets.
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
Answers
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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what is kinematics ;-;
explain.
Answers
Answer:
the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.
Explanation:
A body of mass 100g is fixed to a wheel and rotates in a circular path of 500mm diameter Calculate The moment of inertia nertial when the speed of the wheel from creases from 450rpm to 750rpm
Answers
The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds
To calculate the moment of inertia when the speed of the wheel increases, we need to know the distribution of mass in the body. Assuming the body is a thin ring with the mass concentrated on the rim, we can use the formula for the moment of inertia of a thin ring:
I = m * \(r^2\)
where I is the moment of inertia, m is the mass, and r is the radius.
Given:
Mass of the body (m) = 100 g = 0.1 kg
Diameter of the circular path = 500 mm
Radius (r) = Diameter / 2 = 500 mm / 2 = 250 mm = 0.25 m
Calculate the initial moment of inertia:
Initial speed = 450 rpm
Initial angular velocity (ω1) = 450 rpm * 2π / 60 = 47.12 rad/s
Using the formula for moment of inertia:
I1 = m * r^2
I1 = 0.1 kg * (0.25 m)^2
I1 = 0.00625 kg·m^2
Calculate the final moment of inertia:
Final speed = 750 rpm
Final angular velocity (ω2) = 750 rpm * 2π / 60 = 78.54 rad/s
Using the formula for moment of inertia:
I2 = \(m * r^2\)
I2 = \(0.1 kg * (0.25 m)^2\)
I2 = \(0.00625 kgm^2\)
Therefore, the moment of inertia remains the same as the mass and radius do not change. The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds.
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Many adventures like to go rafting on the Colorado River through Grand Canyon National Park. There are many locations where the river becomes more narrow, both the distance between the canyon walls as well as the depth changes due to debris like boulders on the bottom of the river; this leads to changes in the water speed. In the park, the Colorado River has an average width of 100m and an average depth of 8m, and an average speed of 3 m/s. At the Lava Falls Rapids, the river has an average width of about 25m and an average depth of about 15m. What is the approximate speed of the water in this location
Answers
Answer:
6.4 m/s
Explanation:
Given that :
The average width of the Colorado river = 100 m
Average depth of the river is = 8 m
Therefore, area = \($A_1= 100 \ m \times 8 \ m$\)
Speed of the river, \($v_1 = 3 \ m/s$\)
After the lava falls on the river,
Width of the river becomes = 25 m
Depth of the river became = 15 m
Therefore, area = \($A_2= 25 \ m \times 15 \ m$\)
Now, since the volume flow rate of the Colorado river is same, then from the Continuity equation,
\($Q_1=Q_2$\)
\($A_1v_1=A_2v_2$\)
∴ \($100 \times 8 \times3 = 25 \times 15 \times v_2$\)
\($v_2=\frac{100 \times 8 \times 3}{25 \times 15}$\)
= 6.4 m/s
Therefore, the speed of the river in this location is 6.4 m/s
30) When a compact disk with a 12.0-cm diameter is rotating at 34.6 rad/s, what are (a) the linear speed and (b) the centripetal acceleration of a point on its outer rim? (c) Consider a point on the CD that is halfway between its center and its outer rim. Without repeating all of the calculations required for parts (a) and (b), determine the linear speed and the centripetal acceleration of this point.
Answers
.Given:
The radius of the disk is,
\(\begin{gathered} r=\frac{12.0}{2}\text{ cm} \\ =6.0\text{ cm} \\ =0.06\text{ m} \end{gathered}\)The angular speed is
\(\omega=34.6\text{ rad/s}\)(a)
the linear speed at a point on the outer rim is,
\(\begin{gathered} v=\omega r \\ =34.6\times0.06 \\ =2.07\text{ m/s} \end{gathered}\)Hence the linear speed is 2.07 m/s.
(b)
The centripetal acceleration is,
\(\begin{gathered} a=\frac{v^2}{r} \\ =\frac{2.07\times2.07}{0.06} \\ =71.4m/s^2 \end{gathered}\)Hence the acceleration is 71.4 m/s^2.
(c)
The linear speed at halfway between the center and the outer rim is
\(\begin{gathered} v_1=\omega\frac{r}{2} \\ =34.6\times\frac{0.06}{2} \\ =1.04\text{ m/s} \end{gathered}\)The centripetal acceleration is,
\(\begin{gathered} a_1=\frac{(v_1)^2^{}^{}_{}}{\frac{r}{2}} \\ =\frac{1.04\times1.04}{\frac{0.06}{2}} \\ =36.0m/s^2 \end{gathered}\)Hence the linear speed is 1.04 m/s, and the centripetal acceleration is 36.0 m/s^2.
The drivers of two cars having equal speeds hit their brakes at the same time, but car A has four times the acceleration as car B .
Part A
If car A travels a distance D before stopping, how far (in terms of D ) will car B go before stopping?
Express your answer as an integer.
Part B
If car B stops in time T , how long (in terms of T ) will it take for car A to stop?
Express your answer to two significant figures
Answers
Car A's time to halt, tA = 0.33T. This is the right response to the question that was asked. The answer has two significant figures.
What is a good illustration of two vehicles with similar speeds but differing velocities?Provide an illustration of two vehicles with similar speeds but differing velocities. Example: Two 40 km/hr automobiles, one heading east and the other north.
If two cars accelerate at the same rate, do they move at the same speed? If not, why not?Equal accelerations do not necessarily imply identical velocities, and vice versa. For instance, even if both of your cars have the same acceleration, if one of them accelerates first, it will certainly go more quickly than the other.
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The motion of a particle
executing S.H.M is given by x
= 0.01 sin 100 ti (t+0.5)
where x is in meter and 't' in
second. The time period is
Answers
Answer:0.02 seconds
Explanation:
A 0.23 kg rock is projected from the edge of the top of a building with an initial velocity of 11.5 m/s at an angle 46? above the horizontal. The building is 7.67 m in height.At what horizontal distance, x, from the base of the building will the rock strike the ground? Assume the ground is level and that the side of the building is vertical. The acceleration of gravity is 9.8 m/s2.
Answers
Answer:
x = 17,978 m
Explanation:
This is a projectile launching exercise, to solve it the time it takes to reach the ground in the vertical movement and the time it takes to make the horizontal tour, by which we begin by finding the time it takes to reach the ground in the vertical movement
y = y₀ + \(v_{oy}\) t - ½ g t²
let's use trigonometry to find the components of the initial velocity
sin 46 = v_{oy} / v₀
cos 46 = v₀ₓ / v₀
v_{oy} = vo sin 46
v₀ₓ = vo cos 46
v_{oy} = 11.5 sin 46 = 8.27 m / s
v₀ₓ = 11.5 cos 45 = 7.99 m / s
the height of the building is y₀ = 7.67 m, we substitute
0 = 7.67 + 8.27 t - ½ 9.8 t²
t² - 1,688 t - 1,565 = 0
let's solve the quadratic equation
t = [1,688 ±√ (1,688² + 4 1,565)] / 2
t = [1,688 + - 2,819] / 2
t₁ = 2.25 s
t₂ = -0.57 s
Time cannot be negative so the correct result is t = 2.25 s, let's find what horizontal distance it reaches with this time
x = v₀ₓ t
x = 7.99 2.25
x = 17,978 m
ASAP
What is the area under the curve for the histogram below?
Answers
The area under the curve for the histogram in this problem is given by the following option:
B. 97.
How to obtain the area of the histogram?The histogram is composed by rectangular bins, hence the total area under the histogram is given by the sum of the areas of each bin.
The area of a rectangle of base b and height h is given by the multiplication of these dimensions, as follows:
Area = b x h.
From the histogram given in this image, all the bins have a base of 1, hence the total area is given by the sum of the heights of the histogram.
Thus the total area is calculated as follows:
Area = 5 + 7 + 11 + 15 + 17 + 14 + 12 + 9 + 4 + 3 = 97.
Meaning that option B is correct.
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Air is matter which backs best support the statement
Answers
Answer: A. Balloons can be filled with air.
C. Air has mass.
Explanation:
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Balloons are able to be filled with air and air has mass.
A helpful association method like remembering the Allies during World War II as BAR
(Britain, America, and Russia) is called
O an acronym
O the DAP flashcard method
O a visual image
O a mind map
Answers
Answer:
an acronym because it is shorted to remember like mvemjsun it's the planet
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15. A puck is set in motion across a frozen pond. Friction and air resistance may be neglected. If you see the puck change its direction but not its speed, then the
force on the puck is
OA Non-zero, and equal to the product of its mass times its weight
OB. Non-zero, and equal to its weight
OC. Zero
OD. Non-zero, and depends on the puck's new direction
Reset Section
Answers
Answer:
the answer is equal to non zero
If a quantity of heat equal to the magnitude of the change in mechanical energy of the water goes into the water, what is its increase in temperature
Answers
Explanation:
Change in mechanical energy = Potential energy
Potential energy = mgh
Mass, m = Mass of 1 L water = 1 kg
Acceleration due to gravity, g = 9.81 m/s²
Height, h = 225 m
Potential energy = 1 x 9.81 x 225 = 2207.25 J
Because of this 2207.25 J water gets heated.
Heat energy, E = mcΔT
Mass, m = Mass of 1 L water = 1 kg
Specific heat of water, c = 4200 J/kg/C
Energy, E = 2207.25 J
Change in temperature, ΔT = ?
Substituting
2207.25 = 1 x 4200 x ΔT
ΔT = 0.53 °C
Increase in temperature of water = 0.53 °C
Mrs. Tate travels in her car. She goes from mile marker 15 to 125 in 2.75 hours. What is her average speed?
Answers
Answer:
Explanation:
Step 1: Subtract 15 from 125
\(125-15=110\)
She traveled 110 miles in 2.75. We need to find her avg. speed.
Step 2: Divide 110 by 2.75
\(110/2.75=40\)
The answer is: Her average speed is 40 miles per hour.
Hope this helped!
Waves propagate along a stretched string at a speed of 6.9 m/s. The end of the string
vibrates up and down once every 3.6 s. What is the wavelength of the waves traveling
along the string?
Answers
Answer:
24.64m
Explanation:
The formula for calculating the wavelength is expressed as;
wavelength = Speed/frequency
Given
Speed = 6.9m/s
Frequency = 1/Period
Frequency = 1/3.6
Frequency = 0.28Hz
Get the wavelength
wavelength = 6.9/0.28
wavelength = 24.64m
Hence the wavelength of the waves traveling along the string is 24.64m
A short tennis player hits a ball that is
r meters from their elbow with an angular acceleration
αalpha. A tall tennis player hits a ball with the same angular acceleration where the ball is
2, r from their elbow .
Answers
The tangential acceleration of the short player's ball is twice the tangential acceleration of the tall player's ball.
How does the acceleration affect the ball?The ball of the shorter player experiences twofold of the ball of the taller player's tangential acceleration. The reason behind this is that the magnitude of the tangential acceleration correlates directly with the radius of the circle.
The ball belonging to the smaller player is positioned nearer to the elbow, resulting in a decreased radius. It can be deduced from this statement that the ball of the short player experiences twice the magnitude of tangential acceleration compared to the ball of the tall player.
The answer is: ashort = 2atall
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The Complete Question
A short tennis player hits a ball that is r meters from their elbow with an angular acceleration a. A tall tennis player hits a ball with the same angular acceleration where the ball is 2r from their elbow. How does the tangential acceleration of the short player's ball Ashort compare with the tall player's ball a tall? Choose 1 answer: ashort 2atall ashort Otall ashort 1 atall 2
A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
Answers
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.
Answers
Answer:
a. the amount of work done on a system is dependent of pathway
Explanation:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.
ΔU = Q - W
Where;
Q, the net heat transfer into the system depends on the pathway
W, the net work done by the system also depends on the pathway
But, ΔU, the change in internal energy is independent of pathway
Therefore, the correct option is "A"
a. the amount of work done on a system is dependent of pathway
Three sticks are arranged in such a way that they form a right triangle. The
lengths of the three sticks are 0.47 m, 0.62 m, and 0.78 m. What would the
three angles of this triangle? *
Answers
Answer:
one right angel = 90 degrees
and two acute angels?
Explanation:
George burnt his fingertips so badly that he can't feel anything with them anymore.
Which part of his skin must have been damaged?
O papillary layer
Hypodermis
hyperdemis
subcutaneous layer
Answers
George burnt his fingertips so badly that he can't feel anything with them anymore, then the papillary layer part of his skin must have been damaged, therefore the correct answer is option A.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
As given in the problem George burnt his fingertips so badly that he can't feel anything with them anymore.
Option A is the appropriate response since George must have injured the papillary layer of his skin if his fingertips were burned so badly that he can no longer feel anything with them.
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An object in free fall is at heights y1, y2, and y3 at times t1, t2, and t3 respectively.
Part (a) Which of the following is the correct algebraic expression for the average velocity v12 of the object as it moves from y1 to y2?
ANSWER: (y2-y1)/(t2-t1)
Part (b) Which of the following is the correct expression for the midpoint of the time interval t12 at which the instantaneous velocity is exactly equal to this average velocity?
ANSWER: (t1+t2)/2
Part (c) Based on your answers to parts (a) and (b), you can now write similar expressions for the average velocity v23, and the midpoint t23 of the time interval from t2 to t3. Use your answers from parts (a) and (b), and the above information to write the algebraic expression for the average acceleration for these two time intervals. (Use the following as necessary: t12, t23, v12, v23.)
aaverage = _____________
Answers
Answer:
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
Explanation:
This is an exercise of average speed, which is defined with the variation of the distance in the unit of time
v = (y₃ - y₂) / (t₃-t₂)
the midpoint of a magnitude is the sum of the magnitude between 2
t_mid = (t₂ + t₃) / 2
the same reasoning is used for the mean acceleration
a = (v_f - v₀) / (t_f - t₀)
in our case
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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Which of the following actions will increase the electric field strength at the position of the dot? - Make the rod longer without changing the charge. - Make the rod shorter without changing the charge. - Make the rod fatter without changing the charge.- Make the rod narrower without changing the charge. - Remove charge from the rod
Answers
E: "Removing charge from the rod" will increase the electric field strength at the position of the dot.
The electric field strength at the position of the dot depends on the charge and the distance from the charge. Therefore, any change that affects the charge or the distance will also affect the electric field strength.
A and B - Changing the length of the rod without changing the charge does not affect the charge density, and thus does not affect the electric field strength at the position of the dot. Therefore, options A and B are not correct.C and D - Changing the cross-sectional area of the rod without changing the charge does affect the charge density, and therefore can affect the electric field strength at the position of the dot. However, it is not clear how changing the rod's shape will affect the charge density, and so it is not possible to determine whether option C or D will increase or decrease the electric field strength. Therefore, options C and D are not correct.E - Removing charge from the rod will decrease the charge, and therefore decrease the electric field strength at the position of the dot. Therefore, option E is correct.You can learn more about electric field strength at
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What is the shape of a line graph that shows the temperature change over time of the liquid before it starts to boil.
Answers
The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.
In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.
This is because as heat is applied to the liquid, its temperature increases at a consistent rate.
During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.
Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.
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A 50kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3m/s. What was the force acting on the mass?
Answers
Answer:
75N
Explanation:
a = v/t = 3/2
F = ma = 50(3/2) = 75
You have four identical conducting spheres: A, B, C, and D. In each scenario below, sphere A starts with a charge of -Q, sphere C starts out with a charge of Q, and spheres B and D start out neutral. Then the spheres are touched to each other and separated in the order described. Any spheres not in contact are held very far away. For each scenario, give the final charge of sphere C as a whole number fraction of Q. For example, if you decide that the final charge of sphere C is -Q/7, enter \"-1\" in the numerator and \"7\" in the denominator. Remember! Before each scenario begins, spheres A, B, C, and D are reset to charges of -Q, 0, Q, and 0 again.
Scenario 1: A and B touch and are separated, then A and C touch and are separated, then A and D touch and are separated.
Scenario 2: A and D touch and are separated, then D and C touch and are separated, then D and A touch and are separated, then A and B touch and are separated.
Scenario 3: A and B touch and are separated, then B and D touch and are separated, then C and D touch and are separated.
Answers
Answer:
1) Q_c = - ½ Q , 2) Q_c = + ¼ Q , 3) Q_c= 3/8 Q
Explanation:
For this exercise we must use that equal charges repel and charges with different signs attract. When two objects are in contact, the charges are evenly distributed between them.
Scenario 1.
when the two spheres touch the charge -Q is distributed between them, when separating each sphere has a charge = -1/2 Q
as there are no more interacts sphere C its charge is
Q_c = - ½ Q
Scenario 2
when the two spheres touch the charge -Q is distributed between them, when separating each one has a charge
Q_a = Q_d = - ½ Q
now the sphere D and C touch the charge is Q_net = -1/2 Q + Q = + ½ Q
when separating each sphere has half the charge
Q_d = Q_c = + ¼ Q
since sphere C has no more interaction, its charge is
Q_c = + ¼ Q
Scenario 3
A and B touch the net charge is Q_net = - Q + 0 = - Q
when parting
Q_a = Q_b = - ½ Q
now B and D touch, the charge is Q_net = - ½ Q +0 = - ½ Q
when parting
Q_b = Q_d = - ¼ Q
finally C and D touch
the net charge is Q_net = Q- ¼ Q = ¾ Q
when separating each one is left with half the load
Q_c = Q_d = 3/8 Q
Q_c= 3/8 Q
If a bullet with a mass of 0.005kg is fired from a
gun at a speed of 1000 m/s, what is its
momentum?
what’s the v?
Answers
Answer:
5kgm/s
Explanation:
Given parameters:
Mass of bullet = 0.005kg
Speed = 1000m/s
Unknown:
Momentum = ?
Solution:
Momentum is the amount of motion a body possesses.
Mathematically;
Momentum = mass x velocity
Now insert the parameters and solve;
Momentum = 0.005 x 1000 = 5kgm/s
A 50.0kg woman climbs a flight of stars 6.00 high in 15.0s. How much power dose she use?
Answers
First, calculate the weight
Weigth = mass x gravity = 50 kg x 9.8 m/s^2 = 490 Newton
Then, the work
Work = Weight x height = 490 N x 6m
finally, calculate the power:
Power = Work / time = (490N x 6m) / 15s
Power = 196 newton * m /s
Power = 190 watts