Please answer the question

Michael will need 54 yards of fencing.

Dimensions of Michael's rectangular yard =  22 yards, 16 yards

Length of Michael's rectangular yard = 22 yards

Breadth of Michael's rectangular yard = 16 yards

Perimeter of Michael's yard = 2 [l+b] = 2 [22+16]   = 2×38 = 76 yards                            

As Michael nee

ds to fence only 3 sides leaving a long side, so he needs to fence = perimeter - length = 76-22 = 54 yards

Hence, Michael will need 54 yards of fencing.

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Answer:

T = 12

Step-by-step explanation:

12/6=2

Answer:

x = 4k

Step-by-step explanation:

6kx = 4kx + 8

The first step in solving for x is to get both numbers with kx on the same side. Move the 4kx to the left side of the = by subtracting 4kx from each side.

2kx = 8

Next, move the 2k to the right side of the = by dividing both sides by 2k

x = 8/2k

The last thing to do is to simplify the equation by making the 8/2 to 4/1 or 4.

x = 4k

The general solution to the given differential equation is

y = ± √(1 / (2ln|t| + 4/t - C2))

To solve the given differential equation, we can use the method of separable variables. Let's go through the steps:

Rearrange the equation to separate the variables:

t^2y' + 2ty - y^3 = 0

Divide both sides of the equation by t^2:

y' + (2y/t) - (y^3/t^2) = 0

Now, we can rewrite the equation as:

y' + (2y/t) = (y^3/t^2)

Separate the variables by moving the y-related terms to one side and the t-related terms to the other side:

(1/y^3)dy = (1/t - 2/t^2)dt

Integrate both sides of the equation:

∫(1/y^3)dy = ∫(1/t - 2/t^2)dt

To integrate the left side, let's use a substitution. Let u = y^(-2), then du = -2y^(-3)dy.

-1/2 ∫du = ∫(1/t - 2/t^2)dt

-1/2 u = ln|t| + 2/t + C1

-1/2 (y^(-2)) = ln|t| + 2/t + C1

Multiply through by -2:

y^(-2) = -2ln|t| - 4/t + C2

Now, take the reciprocal of both sides to solve for y:

y^2 = (-1) / (-2ln|t| - 4/t + C2)

y^2 = 1 / (2ln|t| + 4/t - C2)

Finally, taking the square root:

y = ± √(1 / (2ln|t| + 4/t - C2))

Therefore, the general solution to the given differential equation is:

y = ± √(1 / (2ln|t| + 4/t - C2))

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To find x2 + 8y2 + 7z2 = 1 using equations, we need to use partial differentiation with respect to x (represented by ∂x) and z (represented by ∂z). We start by taking the partial derivative of the given equation with respect to x, which gives us: 2x + 0 + 0 = 0

Simplifying this, we get:

x = 0

Next, we take the partial derivative of the given equation with respect to z, which gives us:

0 + 0 + 14z = 0

Simplifying this, we get:

z = 0

Now, substituting x and z in the given equation, we get:

8y2 = 1

Solving for y, we get:

y = ±√(1/8)

Therefore, the equation x2 + 8y2 + 7z2 = 1 can be represented as x = 0, y = ±√(1/8), and z = 0.
To solve the equation x^2 + 8y^2 + 7z^2 = 1, follow these steps:

1. Identify the terms: In this equation, x, y, and z are variables, and 1 is a constant. You want to find the values of x, y, and z that satisfy the equation.

2. Rewrite the equation: You can rewrite the equation as ∂z/∂x = - (x^2 + 8y^2 - 1) / 7z^2. This equation helps us see how z changes with respect to x.

3. Observe constraints: The given equation represents an ellipsoid in 3D space. As x, y, and z vary, they are constrained by the equation.

4. Find solutions: Solving the equation involves finding values of x, y, and z that satisfy the equation. You can solve this by using substitution, elimination, or graphing methods.

Keep in mind that there might be multiple solutions depending on the context or constraints given.

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Choir B has a higher percentage of students who like musicals.

what is percentage ?

Percentage is a way of expressing a proportion or a fraction out of 100. It is a widely used concept in mathematics, finance, statistics, and other fields. For example, if 20 out of 100 students in a class like pizza, we can say that the percentage of students who like pizza is 20%. To calculate the percentage, we usually multiply the given fraction by 100. For instance, if 3 out of 5 students like math, we can calculate the percentage of students who like math as follows:

(3/5) x 100 = 60%

Thus, 60% of the students in the class like math.

To determine which choir has a higher percentage of students who like musicals, we need to calculate the percentage of students in each choir who like musicals.

For choir A, 39 out of 52 students like musicals:

39/52 = 0.75 or 75%

For choir B, 35 out of 44 students like musicals:

35/44 = 0.795 or 79.5%

Therefore, choir B has a higher percentage of students who like musicals.

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Answer:

33

Step-by-step explanation:

[(3+5)⋅2−5]⋅3

[8·2−5]⋅3

[16−5]⋅3

11⋅3

33

Answer:

33

Step-by-step explanation:

Lets break it down. Remember PEMDAS

[(3+5)⋅2−5]⋅3

[(8)⋅2-5]⋅3 start with the parenthisis

[16-5]⋅3 multiply

[11]⋅3

33

hope this helps :)

Answer:

D or 4

Step-by-step explanation:

3x3.1415 is ~9.42

sq. rt. of 10 is ~3.16 so order them.

3.16 3.25 9.42 or 10, 3.25, 3pi

Answer:

15 ft

Step-by-step explanation:

10/4

=2.5

6*2.5

=15 ft

PLS GIVE BRAINLIEST

We were given a function with the following expression:

And we need to calculate the value of this function for a pair of inputs. In this case a = 4 and b = 5. So we have:

The probability of drawing 4 balls at random, without replacement, that include each of the three colors is 0.0061.

The bowl contains 12 balls6 of the balls are blue2 of the balls are white 4 of the balls are red

Sample space = \(n(S) = ^{12}C_4=\frac{12!}{4! (12 - 4)!} = 495\)

The formula for conditional probability is:

P(A ∩ B) = P(A) × \(P(\frac{B}{A})\)

P(A ∩ B) is the probability that both A and B occur

P(A) is the probability of event A occurring

\(P(\frac{B}{A})\) is the probability of event B occurring given that A has occurred

The probability of drawing 4 balls at random that include each of the three colors can be calculated as follows:

First, we calculate the probability of drawing one ball of each color

P (Drawing one ball of each color) = \(\frac{(^6C_1^2C_1^4C_1)}{^{12}C_3} = \frac{(6X2X4)}{220} = 0.0545\)

Next, we calculate the probability of drawing a fourth ball of any color

P (Drawing a fourth ball of any color) = \(\frac{^9C_1}{^9C_1} = 1\)

Finally, we use the formula for conditional probability to find the probability of drawing 4 balls at random that include each of the three colors

P (Drawing 4 balls at random that include each of the three colors) = P (Drawing one ball of each color) × P (Drawing a fourth ball of any color | Drawing one ball of each color) = \((0.0545)\frac{1}{9}= 0.0061\)

The probability of drawing 4 balls at random, without replacement, that include each of the three colors is 0.0061.

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Answer:

A' (7,-8)

B' (8,-11)

C' (4,-10)

Answered by GAUTHMATH

Answer:

Step-by-step explanation:

A will be 7,-8

B will be 8,-11

C will be 4,-10

How?

add 3 to the x coordinate of the original points and -7 to the y coordinate of the original points, Example: 4+3 = 7 and -1+-7 = -8

Answer:

250

Step-by-step explanation:

265/1.06=250

you take the 6 percent and add it to the hundred percent. Then divide the new amount by the percentage.  

Answer:899,396

Step-by-step explanation:

The correct option is B• "The LP has multiple optimal solutions". Because  feasible region, intersects with the objective function in multiple points.

The given linear programming (LP) problem consists of two constraints and two decision variables, x1 and x2. The objective function to be minimized is x1 + 2x2.

To determine the nature of the LP problem, we need to analyze its feasible region and objective function.

The first constraint, x1 + x2 ≤ 4, defines a region in the xy-plane that lies below the line x1 + x2 = 4. The second constraint, x1 - x2 ≥ 5, defines a region that lies to the right of the line x1 - x2 = 5. The feasible region is the intersection of these two regions.

By analyzing the feasible region, we can determine the potential optimal solutions. Since the feasible region is a bounded region, there are finite points within it. The objective function, x1 + 2x2, represents a straight line in the xy-plane with a positive slope. As long as this line intersects the feasible region, there will be multiple points of intersection, each representing a potential optimal solution.

Therefore, the LP problem has multiple optimal solutions because there are multiple points of intersection between the objective function and the feasible region.

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Answer:

y+5 = 4/3(x - 2)

Step-by-step explanation:

i took the test

15/19 + 14/19 = 29/19

Step-by-step explanation:

Add the number of balls in the basket together.

Subtract the number of white balls from the sample space ( the total amount of balls) your answer is written over the sample space and the same process is done for the green ball

Option 2. Both lines have the same slope but start at a different y-intercept so they would be parallel. The other choices are false as well.

Answer:

it would be c

Step-by-step explanation:

Answer:

A first-order observation is that earthquakes and volcanoes occur across most of the continental region, and in parts of the oceanic region offshore East Africa.

Step-by-step explanation:

Ο   Ο

  ω

Answer:

a) \(x(x+3)\)

b) \(2x(x-8)\)

c) \(3x(2+3x^{2})\)

d) \(4x^{2} (3x-1)\)

Step-by-step explanation:

a) \(x^{2} +3x=x(x+3)\)

b) \(2x^{2} -8x=2x(x-8)\)

c) \(6x+9x^{3} =3x(2+3x^{2})\)

d) \(12x^{3} -4x^{2} =4x^{2} (3x-1)\)

Factors of the following algebraic expression are

a. Factors of x² + 3x   are x and x+3

b. Factors of 2x² -8x  are 2, x and ( x-4)

c. Factors of 6x +9x³ are 3, x  and (2 + 3x²)

d. Factors of 12x³ - 4x² are 4, x, x and (3x -41)

The factor of an given algebraic expressions are one or more numbers or linear or other expressions that multiply to form the given algebraic expression and cannot be broken down further into simpler expressions.

For finding factors of an algebraic expression we can simply take out common expressions from all the terms of the expression and try to simplify it.

a. x² + 3x = x( x+3), (taking x common from both terms)

b. 2x² -8x = 2x ( x-4) (taking 2x common from both terms)

c.  6x +9x³ = 3x (2 + 3x²)   ( taking 3x common from both terms)

d.12x³ - 4x² = 4x× x × (3x -41) ( taking 4x²  common from both terms)

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Considering the diagram,

the angle of elevation of the guy wire AD 56.31 degrees

the length of the guy wire  10.8 ft

for the two guy wires 21.6 ft

length AB = 24 ft

The angle of elevation is worked using SOH CAH TOA

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

Using tan, TOA

let the angle be x

tan x = Opposite / Adjacent

tan x = 9 / 6

x = arc tan 3/2

x = 56.31 degrees

The length of the guy wire

length of guy wire  = √(9^2 + 6^2) = 3√13 = 10.8 ft

for the two guy wires = 10.8 * 2 = 21.6 ft

length AB

= 6 + 12 + 6

= 24 ft

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Answer:

-72

Step-by-step explanation:

-32+(2-6)(10)

-32+(-4)(10)

-32+(-40)

-72

Answer:

its -49

Step-by-step explanation:

i got it right on edge 2021

The value of x is 14

HJ = 79

JK = 50

From the question, we are to determine the value of x and the length of each segment

From the given information,

Point J is between points H and K

Then, we can write that

HJ + JK = KH

Also, from the given information,

HJ = 6x - 5

JK = 4x - 6

KH = 129

6x - 5 + 4x - 6 = 129

6x + 4x -5 -6 = 129

10x - 11 = 129

10x = 129 + 11

10x = 140

x = 140/10

x = 14

∴ The value of x is 14

HJ = 6x - 5

∴ HJ = 6(14) - 5

HJ = 84 - 5

HJ = 79

Also,

JK = 4x - 6

JK = 4(14) - 6

JK = 56 - 6

JK = 50

Hence,

The value of x is 14

HJ = 79

JK = 50

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Answer:

B on edge

Step-by-step explanation:

The graph that represents the function g(x) = |x + 4| + 2 is graph A.

Option A is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The function g(x) = |x + 4| + 2 is a transformation of the absolute value function f(x) = |x|.

The absolute value function has a V-shaped graph that passes through the origin with a slope of 1 on both sides.

When a constant is added to the absolute value function, it shifts the graph vertically.

In this case, the constant 4 is added inside the absolute value, which shifts the graph horizontally to the left by 4 units.

Next, the constant 2 is added to the result of the previous operation, which shifts the graph vertically upwards by 2 units.

The graph of g(x) = |x + 4| + 2 is a V-shaped graph that has been shifted 4 units to the left and 2 units upwards, as shown below:

The vertex of the V-shape is at (-4, 2), where the absolute value function crosses the x-axis.

The slope of the graph on both sides of the vertex is 1.

Thus,

The graph that represents the function g(x) = |x + 4| + 2 is graph A.

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Answer:

A, C, E, F

Step-by-step explanation:

since nothing else was said, it is a general triangle. nothing special about it.

so, the only rules are that the sum of any pair of sides must be longer than the 3rd side (otherwise, if the 3rd side is longer, the sides could not connect).

A. 10.

so, we have

6 + 9 > 10 true

6 + 10 > 9 true

9 + 10 > 6 true

therefore this is a possible 3rd side.

B. 2.

so, we have

6 + 9 > 2 true

6 + 2 > 9 false

9 + 2 > 6 true

therefore this is NOT a possible 3rd side.

C. 4.

so, we have

6 + 9 > 4 true

6 + 4 > 9 true

9 + 4 > 6 true

therefore this is a possible 3rd side.

D. 15.

so, we have

6 + 9 > 15 false

6 + 15 > 9 true

9 + 15 > 6 true

therefore this is NOT a possible 3rd side (this triangle is a special case as 6+9 = 15 : it can only exist as a completely flat line and is therefore not a triangle).

E. 12.

so, we have

6 + 9 > 12 true

6 + 12 > 9 true

9 + 12 > 6 true

therefore this is a possible 3rd side.

F. 7.

so, we have

6 + 9 > 7 true

6 + 7 > 9 true

9 + 7 > 6 true

therefore this is a possible 3rd side.

These standardization methods are crucial in chromatography to ensure accurate quantification and comparability of results.

In chromatography, standardization methods are used to ensure accurate and reliable results by establishing reference points or calibration standards. Here are three common methods of standardization in chromatography: External Standardization: In this method, a set of known standard samples with known concentrations or properties is prepared separately from the sample being analyzed. These standards are then analyzed using the same chromatographic conditions as the sample. By comparing the response of the sample to that of the standards, the concentration or properties of the sample can be determined. Internal Standardization: This method involves the addition of a known compound (internal standard) to both the standard solutions and the sample. The internal standard should ideally have similar properties to the analyte of interest but be different enough to be easily distinguished. The response of the internal standard is used as a reference to correct for variations in sample preparation, injection volume, and instrumental response. Internal standardization helps improve the accuracy and precision of the analysis. Standard Addition: This method is useful when the matrix of the sample interferes with the analysis or when the analyte concentration is unknown. It involves adding known amounts of the analyte of interest to different aliquots of the sample. The response of the analyte is then measured, and the concentration is determined by comparing the response with that of the standards. The difference in response between the sample and the standards allows for the determination of the analyte concentration in the original sample.

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Answer:

360 miles

Step-by-step explanation:

to find the distance, multiply speed and time

120*3= 360

Can I have brainliest plz

The data set would list each day in February with a temperature measurement, measured on an interval scale.

The data set in question would list the temperatures in Albany, NY each day in the month of February. This data set would be classified as interval data, as it would measure temperatures on a numerical scale. Interval data is composed of numerical values that are measured on an interval scale, meaning that the difference between any two values is the same, regardless of their position on the scale. Temperature is an example of an interval data type, as it is measured numerically and the difference between two temperatures is the same regardless of where they are on the scale (e.g. the difference between 50°F and 55°F is the same as the difference between 90°F and 95°F). This data set would be useful for tracking temperature trends over a period of time, and for making predictions about future temperatures in a certain area.

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Answer:

9/30

Step-by-step explanation: