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Examples of Newton's three law of motion.

First law of motion: A rocket being launched up in the atmosphere.

Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.

Third law of motion:when we jump off from the boat,the boat moves backward.

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(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.

(a) Flowchart:

(b) Total flow rate of the feed stream:

The flow rate of N2 leaving the condenser is given as 5.18 mol/s.

The flow rate of water vapor entering the condenser is 58.0 mol% of F.

80% of the above water vapor is condensed and removed, leaving 20% remaining.

So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.

The flow rate of O2 is given as 8.8 mol% of F.

The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:

Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2

              = 0.116F + 0.088F + 5.18

              = 5.296F mol/s

(c) Inlet-Outlet Enthalpy Table:

To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).

The enthalpy change for water vapor can be calculated as:

ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C

      = [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]

      = -13.607 kJ/kmol

Enthalpy of water leaving the condenser (H4) can be calculated as:

H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol

Enthalpy of O2 leaving the condenser (H5) can be taken as:

H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol

The heat transferred by the condenser (q) can be calculated as:

q = Total flow rate × ΔH

 = (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J

 = -0.072 kF kW (where kF is the constant conversion factor 10⁶)

Therefore, the heat transferred by the condenser is -0.072 kF kW.

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The x and y component of the vector are -18.32 m and 3.23 m respectively.

The x and y component of the vector is calculated by applying the following formula.

Bx = B cosθ

By = B sinθ

where;

The vector is located in negative x direction but positive y direction.

The angle of the vector from x axis = 90⁰ - 80⁰ = 10⁰

Bx = B cosθ  =  -18.6 m x cos ( 10 ) = -18.32 m

By = B sinθ = 18.6 m x sin ( 10 ) = 3.23 m

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Answer:The equation is balanced for both charge and nucleon number, as required.

Explanation:2713Al + 42He → 3015P + n

Answer:

A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity.

Answer:

At the time of zero gravity there is no weight and at the time of where is there is no air and there is vaccum there is no weight

Explanation:

In an explosion a 6 g piece comes out of the right end and a 4 g piece comes out of the left end at twice the speed of the 6 g piece and the third piece comes out of the right end.

Initially all three balls are at rest so u = 0

Given m1 = 6g and m2=4g where m is the mass of balls

Let v1 be the velocity of the first ball = v(i) (denoted as (i) since the right end points to the positive X axis)

Let velocity v2 of second ball = 2(v)(-i) (denoted as (-i) since left end points negative X axis)

Mass of the third ball m3 = m and its velocity v3 = v'

By applying conservation of momentum

m1(u1) + m2(u2) + m3(u3) = m1(v1) + m2(v2) + m3(v3)

Since all balls are initially at rest u1 = u2 = u3 = u = 0

0 = (6×10⁻³)(v)(i) + (4×10⁻³)(2v)(-i) + m(v')

m(v') = (2×10⁻³)(v)(i)

v’ = (2×10⁻³)(v)(i)/(m)

So positive (i) indicates right end

So the third ball comes from the right end.

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The drift mobility of electrons in Cu is the ratio of the electric field to the charge carried by an electron and the time it takes for an electron to reach from one end of a conductor to the other under an applied electric field.

The Hall coefficient is defined as \(RH = (1/ne) * (dVH/dB)\) where n is the charge density, e is the charge of an electron, VH is the Hall voltage, and B is the magnetic field. To calculate the drift mobility of the electrons in Cu, we will first determine the charge density n using the Hall coefficient.

We can then use the conductivity and charge density to calculate the drift mobility. Given, Hall coefficient \(RH = 0.45 × 10^-10 m^3/A s\)  and Conductivity \(σ = 6.5 /ohm\) meter at a temperature of 400K. (Magnetic field)

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The difference in speeds at the beginning of the 2.10-second interval was 35.49 m/s. Motorcycle B was moving faster.

The problem requires us to find the difference in speeds of two motorcycles that were traveling due east. We are also given their accelerations. The first step is to identify all the known quantities in the problem:

(i) The acceleration of motorcycle A = 1.90 m/s²

(ii) The acceleration of motorcycle B = 17.8 m/s²

(iii) The time interval = 2.10 s

We can use the following kinematic equations to solve for the initial velocity of each motorcycle:

For motorcycle A, we have

v = u + at

Where, v is the final velocity of the motorcycle, u is the initial velocity, a is the acceleration of the motorcycle, t is the time taken.

The final velocity of motorcycle A is the same as the final velocity of motorcycle B. This means that their speeds were equal after 2.10 seconds. Thus:

vA + 1.90 × 2.10 = vB

Let the initial velocity of motorcycle A be uA and the initial velocity of motorcycle B be uB. Thus:

uA + 1.90 × 2.10 = uB

For motorcycle B, we have

v = u + at,

Where, v is the final velocity of the motorcycle, u is the initial velocity, a is the acceleration of the motorcycle, t is the time taken

The final velocity of motorcycle A is the same as the final velocity of motorcycle B. This means that their speeds were equal after 2.10 seconds. Thus:

vA = vB = v

Let the initial velocity of motorcycle A be uA and the initial velocity of motorcycle B be uB. Thus:

v = uB + 17.8 × 2.10

We can now substitute for v in the first equation to get:

uA + 1.90 × 2.10 = uB + 17.8 × 2.10

uA - uB = 16.9 × 2.10

uA - uB = 35.49

Hence, the speeds differ by 35.49 m/s at the beginning of the 2.10-second interval.

Motorcycle B was moving faster.

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Hi there!

Part 1:

If the blocks are moving at a constant velocity:

∑F = 0

Begin by summing the forces acting on each block. Let the upward direction be positive.

∑F₁ = Ta - M₁g - Tb

∑F₂ = Tb - M₂g

Sum the forces:

∑F = Ta - M₁g - Tb + Tb - M₂g

∑F = Ta - M₁g - M₂g = 0

Solve for Tension A:

Ta = M₁g + M₂g (Let g = 9.8 m/s²)

Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N

Now, solve for tension B using the summation of ∑F₁:

0 = Tb - M₂g

Tb = (2.6* 9.8) = 25.48 N

Part 2:

We can use the same method, but incorporate the acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

(M₁ + M₂)a + M₁g + M₂g = Ta

(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N

∑F₂ = Tb - M₂g

M₂a + M₂g = Tb  = 28.6 N

Part 3:

Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

a = (90 - M₁g - M₂g)/(M₁ + M₂)

a = 3.435 m/s²

According to the given information temperature and velocity  of the following is a vector quantity

A vector quantity is one that just has magnitude, whereas a vector quantity has both orientation and magnitude. Given that it is direction-independent at a given position, heat is a scalar number.

Vectors include gravity and displacement. They possess both a value and a direction. The fact that gravity and displacement are pointing in the same direction in this instance allows us to derive a scalar energy from them (in this example, their direction are down and down, respectively).

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13.The color with the longest wavelength is option A. Red.

14.The sky appears blue due to option D. Scattering of light.

Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.

The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.

The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day.  The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.

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Answer:

option B is correct

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Capacitors in parallel refer to two or more capacitors that are connected together in parallel, meaning that both of their terminals are connected to the same voltage source.

A capacitor is an electrical device that stores energy in an electric field. It is made up of two conductors (plates) separated by an insulator (dielectric). When a voltage is applied to the two plates, an electric field is created that stores energy. The stored energy can then be released when the capacitor is discharged. Capacitors can be used in a variety of applications including filtering, signal processing, energy storage, and power delivery. They are often used to bridge the gap between power sources, such as when a motor needs a higher current than the power source can provide. Capacitors can also be used to shape and filter electronic signals, allowing for more control over the frequency, amplitude, and phase of the signal.

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Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

Answer:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field.

It is given by P.E = mgh

where m = mass

Explanation:

g= acceleration due to gravity

h = height of the object

Here,

h = 1.45km = 1450 m

P.E = 3.36 x J

g = 9.8m/

therefore, m = P.E/ gh = (3.36 x s J)/ 9.8 x 1450

m = 2.36 x

Hence mass of the airplane is 2.36 x

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Answer:

Wouldn't it be 17.5. Force doubles in weight.

Explanation:

Answer:

B.

Goals are scored by kicking the ball through goalposts.

Explanation:

To calculate the impulse acting on the golf ball, we need to use the formula:
Impulse = force x time interval
Plugging in the given values, we get:
Impulse = 4800 N x 0.006 s
Impulse = 28.8 N*s
Therefore, the magnitude of the impulse acting on the golf ball is 28.8 N*s.

To calculate the magnitude of the impulse acting on the golf ball, we can use the formula: Impulse = Force x Time interval. In this case, the average force is 4800 N and the time interval is 0.006 s. So the impulse would be:
Impulse = 4800 N × 0.006 s = 28.8 Ns

The magnitude of the impulse acting on the golf ball is 28.8 Newton-seconds (Ns).

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Five activities that will see the application of relation between pressure and area include:

When the handle of a pump is squeezed, the pressure inside the tire increases, causing the tire to inflate. By adjusting the size of the opening in the showerhead, the water pressure can be increased or decreased.

When a car is placed on a hydraulic lift, the pressure in the lift's cylinder is increased, causing the lift to raise the car off the ground. When a hydraulic jack is used to lift a heavy object, the pressure in the jack's cylinder is increased, causing the jack to lift the object.

A blood pressure cuff uses pressure to measure the blood pressure in a person's artery. The pressure in the cuff is increased until it is high enough to stop the flow of blood, and then the pressure is slowly released. The pressure readings at various points during this process can be used to determine a person's blood pressure.

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Answer:

75 N

Explanation:

F = μF = 0.5(150) = 75N

Answer:

Strong acid

Explanation:

.... ..............

The  functional groups that are represented in this molecular structure are; a methyl group, a hydroxyl group, and a carboxyl group

We know that the functional group would be defined as that atom, or a group of atoms or even a bond that is the major point where a chemical reaction occurs among the members of a particular hom----ologous series. Note that the hom----ologous series is a family of compounds that differ from each other by chain length only.

Now we have to look at the compound and of course the attachments to the compound would tell us how many of the functional groups that we do have in the molecule and we can take a cursory look at the image attached for this detail.

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Shocks cause shifts in AD and AS curves, and the placement of point E, representing the new equilibrium, depends on these shifts.

Shocks can affect the economy through changes in aggregate demand or aggregate supply. An increase in aggregate demand would shift the AD curve to the right, reflecting higher overall demand for goods and services. This shift would result in a higher level of output and prices in the short run. Consequently, point E would be placed at a higher level of output and higher price level.

On the other hand, a positive supply shock, such as a decrease in production costs or an increase in productivity, would shift the AS curve to the right. This shift implies higher output and lower prices in the short run. In this case, point E would be located at a higher level of output and a lower price level.

Conversely, a negative supply shock, such as an increase in production costs or a decrease in productivity, would shift the AS curve to the left. The resulting equilibrium at point E would be characterized by lower output and higher prices in the short run.

To determine the placement of point E, it is necessary to identify the specific shifts caused by the shocks, such as an AD shift, a positive supply shock (AS shift to the right), or a negative supply shock (AS shift to the left). Once the shifts are identified, the corresponding changes in output and price level can be determined, and point E can be placed accordingly in the new short-run equilibrium.

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Answer:

I love yourself help yourself

∑ Hey, Lethality ⊃

Answer:

5.30 + 6.2=11.5

640 - 28.3 = 612

7,000 + 5=7005

8,000. - 6.0 = 7994

1.00 + 0.006=1.01

Explanation:

Given:

Add and Subtract these numbers using SIG FIGS. (Significant Figures)

5.30 + 6.2

640 - 28.3

7,000 + 5

8,000. - 6.0

1.00 + 0.006

Solution~:

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 4

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Number of significant figures: 4

-------------------------------------------------------------------------------------------------------------

Number of significant figures: 3

-------------------------------------------------------------------------------------------------------------

xcookiex12

8/23/2022

A. covalent. The covalent compound must possess a covalent link in which the two atoms involved have substantial disparities in their electronegativity for a polar covalent bond to exist.

The most electronegative element is fluorine. Therefore, C and F exhibit the largest variation in electronegativity . The most polar bond is the C-F one as a result.

The electron pair is shared evenly by the two linked atoms in a non-polar covalent connection. H2 is a kind of hydrogen gas. Since the two hydrogen atoms are the same, their bond is non-polar.

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D) the presence of many long, tall cliffs

The observational evidence that supports the idea that Mercury once shrank by some 20 kilometers in radius is the presence of many long, tall cliffs on its surface. These cliffs, known as "lobate scarps," are found on Mercury and are believed to be a result of the planet's contraction and subsequent cooling.

Lobate scarps are long, curved cliffs that extend for several kilometers and can reach heights of hundreds of meters. They are formed when the crust of a planet or moon wrinkles and buckles as it contracts. On Mercury, these scarps indicate that the planet underwent a significant decrease in size, causing the crust to crumple and form these distinctive features.

The presence of these scarps provides direct evidence of the shrinking of Mercury's interior and supports the hypothesis that the planet experienced a period of contraction in its geological history. This evidence, combined with other factors such as Mercury's unusually high density and the characteristics of the Caloris Basin, further strengthens our understanding of the planet's geological evolution.

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