Please answer quick!!! TYSM!

Answer:

Hello!

I'm currently new to Log, but can help in the best way possible.

We can rewrite this into exponential form:

(x+3) = 4^1 + 4x^1

------------------

If not shown correctly, above, further apologize.

If factored and isolated;

1-xlog(4) = log(256x)

x

≈

0.03710403

-----------------------

#Team Trees #Team Seas #PAW #Spread_Positivity

I hope this helps,

-Oceanbreeze24

Answer: x=1

Step-by-step explanation: plato

Answer:

31

Step-by-step explanation:

Let x and (x + 1) be the page numbers Josiah can see

Hint 1: x(x + 1) = 930

⇒ x² + x = 930

⇒ x² + x - 930 = 0

Using quadratic formula,

\(x = \frac{-b\pm\sqrt{b^2 -4ac} }{2a}\)

a = 1, b = 1 and c = -930

\(x = \frac{-1\pm\sqrt{1^2 -4(1)(-930)} }{2(1)}\\\\= \frac{-1\pm\sqrt{1 +3720} }{2}\\\\= \frac{-1\pm\sqrt{3721} }{2}\\\\= \frac{-1\pm61 }{2}\\\)

\(x = \frac{-1-61 }{2}\;\;\;\;or\;\;\;\;x= \frac{-1+61 }{2}\\\\\implies x = \frac{-62 }{2}\;\;\;\;or\;\;\;\;x= \frac{60 }{2}\\\\\implies x = -31\;\;\;\;or\;\;\;\;x= 30\)

Sice x is a page number, it cannot be negative

⇒ x = 30 and

x + 1 = 31

The two pages Josiah can see are pg.30 and pg.31

Hint 2: The page he is reading is an odd number

Out of the pages 30 and 31, 31 is an odd number

Thereofre, Josiah is reading page 31

Step-by-step explanation:

It is looking for the value of the function when x is equal to 4

  f(4)

FOUR   is GREATER than 1  so you use the bottom portion of the function definition :   -x +2      when x is equal to 4   this is equal to -2

so  f(4) = -2

The LCM of the numbers 12, 240 and 48 is: 240

The LCM of any given two numbers is commonly defined as the particular value that is evenly divisible by the specific two given numbers. The full meaning of of the acronym LCM is called Least Common Multiple. It is also referred to as the Least Common Divisor (LCD). For example, LCM (3, 4) = 12.

Now, we want to find the LCM of 12, 240 and 48.

Using the concept of LCM, we can easily see that the number that is evenly divisible by the three given numbers is 240.

This is because we see that the numbers have similar multiples and as 240 is the highest, then it can also be divided by 12 and 48.

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If Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

To show that x is also an eigenvector of QT, we need to demonstrate that QT * x is a scalar multiple of x.

Given that Q is an orthogonal matrix, we know that QT * Q = I, where I is the identity matrix. This implies that Q * QT = I as well.

Let's denote x as the eigenvector corresponding to the eigenvalue λ1 This means that Q * x = λ1 * x.

Now, let's consider QT * x. We can multiply both sides of the equation Q * x = λ1 * x by QT:

QT * (Q * x) = QT * (λ1 * x)

Applying the associative property of matrix multiplication, we have:

(QT * Q) * x = λ1 * (QT * x)

Using the fact that Q * QT = I, we can simplify further:

I * x = λ1 * (QT * x)

Since I * x equals x, we have:

x = λ1 * (QT * x)

Now, notice that λ1 * (QT * x) is a scalar multiple of x, where the scalar is λ1. Therefore, we can rewrite the equation as:

x = λ2 * x

where λ2 = λ1 * (QT * x).

This shows that x is indeed an eigenvector of QT, with the eigenvalue λ2 = λ1 * (QT * x).

In conclusion, if Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

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\((3-2)^2+(7+5)(3-2)=(3-2)(3-2)+(7+5)(3-2)=(3-2)(3-2+7+5)=1*13=13\)

e. Hourly rate = $975.84 / 38 = $25.68

f. Overtime rate = $25.68 * 1.5 = $38.52

g. Earnings (4 hours OT) = $38.52 * 4 = $154.08

h. Overtime hours = ($1226.22 - $975.84) / $38.52 ≈ 6.5 hours

Begin by determining the number of overtime hours worked by evaluating the discrepancy between his weekly salary and his regular wage:

Take note that the difference = $250.38, specifically from a calculation derived by subtracting $975.84 from $1226.22.

Next, divide this incongruity by his rate of pay for working overtime to establish the actual quantity of time augmented:

Upon performing our overall assessment with $38.52 as the hourly short-term remuneration rate towards supplementing regular pay projections, we determine roughly 6.5 additional work hours incrementally added onto one's overall timesheet.

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Answer:

2/35

Step-by-step explanation:

\(\frac{9}{35}-\frac{1}{5}=\frac{9}{35}-\frac{7}{35}=\frac{2}{35}\)

Answer:

4.8 or if rounded up then 5.

Step-by-step explanation:

If you multiply 8 hours with 60 you find out 480 minutes. Then you divide the 96 toys with 20 minutes and you get 4.8 toys.

Answer:

Assuming u meant 2y - 13y^(11), the degree is 11

Step-by-step explanation:

Answer:

Step-by-step explanation:

The highest power is 11 so the degree of polynomial is 11.

Answer:

D. No x-intercept, y-intercept 9

Step-by-step explanation:

The line intercepts at (0, 9)

Let's determine the product of the following equation:

We get,

Therefore, the answer is:

The surface area of the pyramid is A = 265.23 inches²

The total surface area is the summation of the areas of the base and the three other sides. A = B + ( 1/2 ) ( P x h ), where B is the area of the base of the pyramid, P is the perimeter of the base, and h is the slant height of the pyramid

Surface Area of Pyramid = B + ( 1/2 ) ( P x h )

Given data ,

Let the surface area of hexagonal pyramid be represented as A

Surface area of hexagonal pyramid = Area of base + area of lateral surface

Area of the base = 93.5 inches²

Now , the Area of the lateral surface = 3a √ ( h² + ( 3a²/4 ) )

where a = 6 inches

h = 8 inches

Substituting the values in the equation , we get

Area of the lateral surface = ( 3 x 6 ) √ ( 64 + ( 3 x 36 / 4 ) )

On simplifying the equation , we get

Area of the lateral surface = 171.7 inches²

So , Surface area of hexagonal pyramid = Area of base + area of lateral surface

Surface area of hexagonal pyramid A = 93.5 inches² + 171.7 inches²

Surface area of hexagonal pyramid A = 265.23 inches²

Hence , the surface area of hexagonal pyramid is 265.23 inches²

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Answer:

y = x + 1

Step-by-step explanation:

Parallel lines have same slope.

y = x - 1

Compare with the equation of line in slope y-intercept form: y = mx +b

Here, m is the slope and b is the y-intercept.

m =1

Now, the equation is,

         y = x + b

The required line passes through (-3 ,-2). Substitute in the above equation and find y-intercept,

        -2 = -3 + b

  -2 + 3 = b

         \(\boxed{b= 1}\)

    Equation of line in slope-intercept form:

                  \(\boxed{\bf y = x + 1}\)      

The equation is :

Solution:

If two lines are parallel to each other, then their slopes are equal. The slope of y = x - 1 is 1. Hence, the slope of the line that is parallel to that line is 1.

We shouldn't forget about a point on the line : (-3, -2).

I plug that into a point-slope which is :

\(\sf{y-y_1=m(x-x_1)}\)

Slope is 1 so

\(\sf{y-y_1=1(x-x_1)}\)

Simplify

\(\sf{y-y_1=x-x_1}\)

Now I plug in the other numbers.

-3 and -2 are x and y, respectively.

\(\sf{y-(-2)=x-(-3)}\)

Simplify

\(\sf{y+2=x+3}\)

We're almost there, the objective is to have an equation in y = mx + b form.

So now I subtract 2 from each side

\(\sf{y=x+1}\)

Answer:

56.7

Step-by-step explanation:

Just Add all numbers

Answer: 6(y) + 6(x)

Step-by-step explanation:

The temperature at the bottom of the mountain is 50.9 °C.

Let's work through the given information step by step to find the temperature at the bottom of the mountain.

The temperature in the hotel is 21 °C.

The temperature in the hotel is 26.7 °C warmer than at the top of the mountain.

Let's denote the temperature at the top of the mountain as T_top.

So, the temperature in the hotel can be expressed as T_top + 26.7 °C.

The temperature at the top of the mountain is 3.2 °C colder than at the bottom of the mountain.

Let's denote the temperature at the bottom of the mountain as T_bottom.

So, the temperature at the top of the mountain can be expressed as T_bottom - 3.2 °C.

Now, let's combine the information we have:

T_top + 26.7 °C = T_bottom - 3.2 °C

To find the temperature at the bottom of the mountain (T_bottom), we need to isolate it on one side of the equation. Let's do the calculations:

T_bottom = T_top + 26.7 °C + 3.2 °C

T_bottom = T_top + 29.9 °C

Since we know that the temperature in the hotel is 21 °C, we can substitute T_top with 21 °C:

T_bottom = 21 °C + 29.9 °C

T_bottom = 50.9 °C

Therefore, the temperature at the bottom of the mountain is 50.9 °C.

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Answer:

60 degrees

Step-by-step explanation:

90 digress minus 30 degrees will be 60 degrees

Answer:

Step-by-step explanation:

115% = 115/100 = 1.15

of means multiply

1.15 * 95 = 109.25

Answer:

4.25 in total

Step-by-step explanation:

separate it is 4 and 0.25

Answer:

14.86%

Step-by-step explanation:

The principal = $5800

Time = 5 years

Amount = $ 11600

From;

A= P(1 + r)^n

Substituting values;

11600=5800(1 + r)^5

Rate= (11600/5800)^1/5 - 1

Rate= 0.1486

Therefore

Rate= 14.86%

Answer:

I think the answer is MEAN

Step-by-step explanation:

Answer: -1/2

Step-by-step explanation: To solve this problem, we can use the properties of logarithms to isolate the variable x on one side of the equation. The properties of logarithms tell us that the logarithm of a product is the sum of the logarithms of the factors, and that the logarithm of a power is the exponent times the logarithm of the base.

If log₂(4x + 6) = 4, we can rewrite the left side of the equation as follows: log₂(4x + 6) = log₂(2^4 * (2x + 3))

Then, using the property of logarithms that the logarithm of a product is the sum of the logarithms of the factors, we can simplify the equation as follows: log₂(4x + 6) = 4 + log₂(2x + 3)

Now, we can use the property of logarithms that the logarithm of a power is the exponent times the logarithm of the base to simplify the equation even further: log₂(4x + 6) = 4 + 1 * log₂(2x + 3)

Since the logarithm of a power is the exponent times the logarithm of the base, this means that the logarithm of a number is the logarithm of that number divided by the logarithm of the base. Therefore, we can divide both sides of the equation by log₂ to isolate the variable x on one side of the equation:

log₂(4x + 6) / log₂ = 4 + 1 * log₂(2x + 3) / log₂

(4x + 6) / 1 = 4 + (2x + 3) / 1

4x + 6 = 4 + 2x + 3

4x + 6 = 2x + 7

2x = -1

x = -1/2

Therefore, if log₂(4x + 6) = 4, then x = -1/2.

The statement about the linear equation 3a + 1/3(6a −9) = 1/2(10a − 6) that is true is: "The equation has an infinite number of solutions." (Option B)

A linear equation is defined as an equation with a maximum of one degree. A nonlinear equation is one with a degree greater than or equal to two.

On the graph, a linear equation looks like a straight line. On the graph, a nonlinear equation creates a curve.

To justify the above answer, we state the linear equation above:


3a + 1/3(6a −9) = 1/2(10a − 6) ; Simplified by opening the brackets, we have

3a + 2a − 3 = 5a − 3; collecting like terms on the left side, we have

5a -3 = 5a -3

Because 5a -3 = 5a -3, the expression holds true regardless of what integer or value a represents. Hence, it has an infinite number of solutions.

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The system of equations -9x+8y = 9x and 7y+8=8x is linear.

A system of equations is considered linear if each equation in the system is linear, meaning that the highest power of any variable in each equation is 1.

In this case, the first equation -9x+8y = 9x is linear because the highest power of any variable is 1 (x is raised to the first power).

Similarly, the second equation 7y+8=8x is also linear because the highest power of any variable is 1 (x is raised to the first power and y is not raised to any power).

Therefore, the system of equations is linear.

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Answer:

Both are correct

Step-by-step explanation:

3. ×3. 9

5. ×3. 15

3. ×5. 15

5. ×5. 25

Answer:

3200.00

Step-by-step explanation:

took the test

Anderson's monthly income is 3,200.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Anderson's car payment is 2/25 of his monthly income.

Anderson pays a total = $3,072 per year in car payments.

So, he pays for 12 month = 3072

then for 1 month he pays = 3072 / 12

                                         = $256

let Anderson's income was = x

Then,

2/25 * x = 256

x= 256*25/2

x= 6400 / 2

x= 3200

Hence, the monthly income is 3200.

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Answer:

6.6×10²¹

Step-by-step explanation:

6,600,000,000,000,000,000,000 → there are 21 place values after the first non-zero number ''6''

to convert to standard form, we move the decimal point after the first non-zero number.  

6,600,000,000,000,000,000,000.0 ← decimal in the end

the decimal will be moved, all the digits after the decimal are counted and they will resemble the index.

6.6×10²¹  

Okay, let's do this step-by-step:

1) We have in-state tuition amounts and out-of-state tuition amounts for some state colleges.

2) We want to find a linear model that relates the in-state and out-of-state tuition.

3) Once we have the linear model, we can use it to predict the out-of-state tuition for an in-state tuition of $6,000.

Let's assume the data points are:

In-state tuition | Out-of-state tuition

$3,000 | $9,000

$5,000 | $11,000

$7,000 | $13,000

$9,000 | $15,000

To find the linear model:

1) Find the slope:

Slope = (Out-of-state tuition for $9,000 in-state tuition) - (Out-of-state tuition for $3,000 in-state tuition)

= $15,000 - $9,000 = $6,000

Slope = $6,000

2) Find the y-intercept:

y-intercept = Out-of-state tuition when In-state tuition = 0

= $9,000

So the linear model is:

Out-of-state tuition = Slope * In-state tuition + y-intercept

= $6,000 * In-state tuition + $9,000

To predict Out-of-state tuition for $6,000 In-state tuition:

Out-of-state tuition = $6,000 * $6,000 + $9,000

= $36,000 + $9,000

= $45,000

Rounding to the nearest choice:

Out-of-state tuition for $6,000 In-state tuition = $45,000

So the answer is c. about $12,450

Let me know if you have any other questions!

In spherical coordinates, the region R is the set

\(R = \left\{ (\rho, \theta, \varphi) \, : \, 0 \le \rho \le 3, \, 0 \le \theta \le 2\pi, \, \dfrac\pi6 \le \varphi \le \pi\right\}\)

Then the volume of R is

\(\displaystyle \iiint_R dV = \int_0^3 \int_0^{2\pi} \int_{\frac\pi6}^\pi \rho^2 \sin(\varphi) \, d\varphi \, d\theta \, d\rho\)

The integrand is free of \(\theta\), so we can immediately compute that integral and pull out a factor of 2π :

\(\displaystyle \iiint_R dV = 2\pi \int_0^3 \int_{\frac\pi6}^\pi \rho^2 \sin(\varphi) \, d\varphi \, d\rho\)

and the remaining double can be factorized as

\(\displaystyle \iiint_R dV = 2\pi \left(\int_0^3 \rho^2 \, d\rho\right) \left(\int_{\frac\pi6}^\pi \sin(\varphi) \, d\varphi\right)\)

The single integrals are trivial:

\(\displaystyle \int_0^3 \rho^2 \, d\rho = \frac13 (3^3 - 0^3) = 3^2 = 9\)

\(\displaystyle \int_{\frac\pi6}^\pi \sin(\varphi) \, d\varphi = -\cos(\pi) - \left(-\cos\left(\frac\pi6\right)\right) = 1 + \frac{\sqrt3}2\)

So, the volume of R is

\(\displaystyle \iiint_R dV = 2\pi \cdot 9 \cdot \left(1 + \frac{\sqrt3}2\right) = \boxed{9(2+\sqrt3)\pi}\)