Please answer correctly

Answer:

I’m not sure but I think it’s 5.88

Step-by-step explanation:

Answer:

2134

Step-by-step explanation:

Answer:

Its not what the first person said its 321

Step-by-step explanation:

First you multiply the stuff in the parenthesis which gets you 125-30 in the parenthesis

Then you multiply 3 to 125 and 30 to get 375-90

Multiply 4 and 3 to the second power which is 9 and you will get

375-90+36 and you will subtract 375 and 90 to get 285 then add 36 to get the final answer of 321

I am not 100% sure this is right but you can try it

In this case, det(A) = 3/4 and det(B) = 1458/4096.

If A is 3x3 and det(2A−1)=5=det[(A)2(BT)−1], we have to find det(A) and det(B).

Firstly, let's write out the determinant property of 2A - 1. By expanding the determinant, we get:

det(2A - 1) = 5⟺ 8 det(A) - det(I) = 5⟺ 8 det(A) - 1 = 5⟺ 8 det(A) = 6⟺ det(A) = 3/4

Now let's consider the second equation.

We have:

det[(A)2(BT)−1] = 5

We know that det(A) = 3/4.

Therefore, we can rewrite the above equation as:

det[(A)2] × det(BT)−1 = 5

Taking the determinant of the transpose of B is the same as taking the determinant of B

Therefore,

det[(A)2] × det(B)−1 = 5⟺ [det(A)]6 × det(B)−1 = 5⟺ (3/4)6 × det(B)−1 = 5⟺ (729/4096) × det(B)−1 = 5⟺ det(B)−1 = 4096/1458⟺ det(B) = 1458/4096

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Answer:the answer is 53 900

Step-by-step explanation:

if you  you have to add subtract an then divid

Answer:

They're parallel.

Step-by-step explanation:

The reason is that any equation only with a y coordinate is a horizontal line. As they're both horizontal, they'd be parallel.

Answer:

shusidvxxosbsbzbz

Step-by-step explanation:

usjzkdofjfbf

Answer:

50 degree for X look at pic attached

Answer:

8 is congruent 9 isnt

Step-by-step explanation:

Answer: 8. is Congruent and 9. Isn't Congruent

Step-by-step explanation:

The phase of inferential statistics which is sometimes considered to be the most crucial because errors in this phase are the most difficult to correct is "data gathering".

Inferential statistics are frequently employed to compare treatment group differences.

Some characteristics of inferential statistics are-

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The quotient is 1111. The process continues until the result is less than the divisor.

To perform the division using the restoring-division algorithm with the given divisor and dividend, follow these steps:

Step 1: Initialize the dividend and divisor

Divisor: 00011

Dividend: 1011

Step 2: Append zeros to the dividend

Divisor: 00011

Dividend: 101100

Step 3: Determine the initial guess for the quotient

Since the first two bits of the dividend (10) are greater than the divisor (00), we can guess that the quotient bit is 1.

Step 4: Subtract the divisor from the dividend

101100 - 00011 = 101001

Step 5: Determine the next quotient bit

Since the first two bits of the result (1010) are still greater than the divisor (00011), we guess that the next quotient bit is 1.

Step 6: Subtract the divisor from the result

101001 - 00011 = 100110

Step 7: Repeat steps 5 and 6 until the result is less than the divisor

Since the first two bits of the new result (1001) are still greater than the divisor (00011), we guess that the next quotient bit is 1.

100110 - 00011 = 100011

Since the first two bits of the new result (1000) are still greater than the divisor (00011), we guess that the next quotient bit is 1.

100011 - 00011 = 100001

Since the first two bits of the new result (1000) are still greater than the divisor (00011), we guess that the next quotient bit is 1.

100001 - 00011 = 011111

Since the first two bits of the new result (0111) are less than the divisor (00011), we guess that the next quotient bit is 0.

011111 - 00000 = 011111

Step 8: Remove the extra zeros from the result

Result: 1111

Therefore, the quotient is 1111.

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The maximum Number of  scholars in each row is 12. This means that the  scholars can be arranged in rows with an equal number of  scholars, and each row can have a  outside of 12  scholars.

To find the maximum number of  scholars in each row, we need to determine the  topmost common divisor( GCD) of the total number of  scholars in each section. The GCD represents the largest number that divides all the given  figures unevenly.  

Given that there are 24, 36, and 60  scholars in the three sections, we can calculate the GCD as follows    Step 1 List the  high factors of each number  24 =  23 * 31  36 =  22 * 32  60 =  22 * 31 * 51    

Step 2 Identify the common  high factors among the three  figures  Common  high factors 22 * 31    Step 3 Multiply the common  high factors to find the GCD  GCD =  22 * 31 =  4 * 3 =  12  

 thus, the maximum number of  scholars in each row is 12. This means that the  scholars can be arranged in rows with an equal number of  scholars, and each row can have a  outside of 12  scholars.

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Rounding to four decimal places, we get the probability that the weight will be less than 4664 grams as 0.9991.

Let X be the weight of a newborn baby boy born at the local hospital. We know that X follows a normal distribution with mean μ = 3996 grams and variance σ² = 111,556 grams².

We want to find the probability that the weight will be less than 4664 grams. That is, we need to find P(X < 4664).

To standardize X, we can use the z-score formula:

z = (X - μ) / σ

Substituting the given values, we get:

z = (4664 - 3996) / √111556

z = 3.1217

Using a standard normal table or calculator, we can find that the probability of a standard normal random variable being less than 3.1217 is approximately 0.9991.

Therefore, P(X < 4664) = P(Z < 3.1217) ≈ 0.9991.

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Statistical conclusion validity is the extent to which inferences and conclusions drawn from statistical data are valid.

The main threat to statistical conclusion validity discussed in class is the potential for spurious correlations. This is when two variables appear to be related when in fact they are not.

Statistical conclusion validity is a measure of how valid the conclusions drawn from statistical data are. This is important because it allows us to draw valid inferences from the data. The main threat to statistical conclusion validity discussed in class is the potential for spurious correlations. This is when two variables appear to be related when in fact they are not. For example, a study may show that there is a correlation between ice cream sales and crime rate, when in fact it is merely a coincidence that both variables increase during the summer months. By controlling for other variables and using appropriate statistical tests, it is possible to identify and avoid spurious correlations.

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Answer:

9 dollars that dena owes the aunt,and no you could not

Step-by-step explanation:

because u cant express on the numberline

9514 1404 393

Answer:

  74

Step-by-step explanation:

The recursive definition is for an arithmetic sequence with a first term of -6 and a common difference of 4.

The general term of such a sequence is ...

  a(n) = a(1) +d(n -1)

This sequence is ...

  a(n) = -6 +4(n -1) = 4n -10

Then for n = 21, the term is ...

  a(21) = 4(21) -10 = 84 -10

  a(21) = 74

Answer:

68,67 cm^2

Step-by-step explanation:

Let's calculate first the total area of pastry that we have.

Let A be that area.

The pastry has rectangular form so its area is:

● A = width × length

The width here is 16 and the length is 20

● A = 20 × 16

● A = 320 cm^2

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let's calculate the are of the 20 pastry circles

Let A' be the area of one circle.

● A' = Pi × r^2

r is the radius wich is the diameter over 2.

● d/2 = 4/2 = 2 cm

● A' = Pi × 2^2

● A' = 4Pi cm^2

The area of 20 pastry circles is 20A'

● 20A'= 20 × 4 × Pi

● 20A'= 80Pi

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let A" be the area of the remaining pastry

● A" = A-20A'

● A" = 320 - 80Pi

● A" = 68.67 cm^2

The IQR of the ages, in years include the following: B. 16.

Based on the information provided about the given box plot or box-and-whisker plot, the five-number summary for the given data set include the following:

In Mathematics and Statistics, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):

Interquartile range (IQR) of data set = Q₃ - Q₁

Interquartile range (IQR) of data set = 38 - 22

Interquartile range (IQR) of data set = 16.

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The stage of group development that is characterized by disagreements and conflicts is called storming. During this stage, group members may have different ideas and opinions about how to approach tasks and goals, and they may struggle to find a common understanding.

Conflict can arise as individuals compete for leadership roles or try to assert their ideas over others. However, this stage is important for groups to progress towards their goals as it allows for open communication and the airing of different perspectives. Eventually, through negotiation and compromise, groups move on to the norming stage where a common understanding is established and roles are defined. From there, groups move on to performing, where they are able to work together effectively towards their goals.

Finally, the adjourning stage is where the group disbands after reaching their goals or completing their tasks.

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Answer:

You need the distance of all four sides so that is:

2 * (5y +1) + 2 * (2y -3) which equals

10y + 2 + 4y -6 and that equals

14y -4

Step-by-step explanation:

11 dummy variables will be needed.

A dummy variable is a numerical variable used in regression analysis to represent subgroups of the sample in your study. In research design, a dummy variable is often used to distinguish different treatment groups.

we know that,

dummy variable formula = K- 1,

here, K = 12 (months in a year)

this implies, K - 1 = 12 - 1 = 11

Therefore, no. of dummy variables needed = 11.

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The expected number of streaks of 7 consecutive successful shots in n shots = (n - 6) * p7, where n is the number of shots and p is the probability of success.The probability of making 7 consecutive successful shots in exactly k shots is given by Pk = (1-p)k-7 * p7. The expected value of X is given by E(X) = [k=7,] k. We can use the formula for the sum of an infinite geometric series to simplify the expression and evaluate the numerator of the expression. Thus, E(X)  7 / p7.

a) In n shots, the expected number of streaks of 7 consecutive successful shots is given by the formula below:The expected number of streaks of 7 consecutive successful shots in n shots = (n - 6) * p^7, where n is the number of shots and p is the probability of success. In other words, for each block of 7 shots, we have a probability of p^7 of making 7 consecutive successful shots, and there are (n-6) blocks of 7 shots in n shots. Therefore, the expected number of streaks of 7 consecutive successful shots is the product of these two values.

b) We know that X is the number of shots taken until the player makes 7 consecutive successful shots for the first time. Therefore, X is a random variable that follows the geometric distribution with parameter p. The probability of making 7 consecutive successful shots in exactly k shots is given by:Pk = (1-p)^{k-7} * p^7Therefore, the expected value of X is given by:E(X) = Σ[k=7,∞] k * PkWe can use the formula for the sum of an infinite geometric series to simplify this expression:

\(E(X) = Σ[k=1,∞] k * (1-p)^{k-1} * p^7 / (1 - (1-p)^7)\) We can also use the formula for the sum of a geometric series to simplify the denominator:

\(E(X) = Σ[k=1,∞] k * (1-p)^{k-1} * p^7 / (p^7 + Σ[j=1,6] (1-p)^j * p^7)\)

\(E(X) = (p^7 * Σ[k=1,∞] k * (1-p)^{k-1}) / (p^7 * (1 + Σ[j=1,6] (1-p)^j))\)

\(E(X) = (1 / p^7) * (Σ[k=1,∞] k * (1-p)^{k-1}) / (1 + Σ[j=1,6] (1-p)^j)\)

We can use the formula for the derivative of a geometric series to evaluate the numerator of this expression:

\(Σ[k=1,∞] k * (1-p)^{k-1} = d/dp\)

Σ[k=1,∞] (1-p)^k

= d/dp (1-p) / (1 - (1-p))²

= 1 / p^2

Therefore, \(E(X) = (1 / p^7) * (1 / (1 + Σ[j=1,6] (1-p)^j)) * (1 / p^2) ≤ (1 / p^7) * (1 / (1 + Σ[j=1,6] (1-p)^j)) * (1 / p^7) = 1 / p^{14} ≤ 7 / p^7\)

Thus, \(E(X) ≤ 7 / p^7.\)

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The cost of each pizza is $14 and the cost of each cool drink is $3.

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

Given that, John told Serena that when he ordered from Tony's last week, he paid $34 for two 16-inch pizzas and two drinks.

Let the cost of each pizza be x and the cost of each cool drink be y.

Now, 2x+2y=34

x+y=17 -------(i)

Jodi told Serena that when she ordered one 16-inch pizza and three drinks, it cost $23.

x+3y=23 -------(ii)

Subtract equation (i) from (ii), we get

x+3y-(x+y)=23-17

2y=6

y=3

Substitute y=3 in equation (i), we get

x=14

Therefore, the cost of each pizza is $14 and the cost of each cool drink is $3.

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Answer:

$60

Step-by-step explanation:

Let x = the original cost

x - .25x = 45

.75x = 45  Divide both sides by .75

x = 60

Answer:

A. 5 hours

Step-by-step explanation:

Following the same steps as in Case 1, we find the fixed points by setting ( \dot{x}{1} = \dot{x}{2} = 0 ):

To apply the Poincaré-Bendixson criterion to the given system:

( \dot{x}{1} = x{1} + x_{2} - x_{1} h(x) )

( \dot{x}{2} = -2x{1} + x_{2} - x_{2} h(x) )

where ( h(x) = \max \left{ \left| x_{1} \right|, \left| x_{2} \right| \right} ), we need to determine if there exists a periodic orbit.

The Poincaré-Bendixson criterion states that if a system's trajectory is bounded and does not approach a fixed point or a limit cycle, then it must contain a closed trajectory (a periodic orbit).

To analyze the system, let's consider the region where ( h(x) ) is at its maximum. This occurs when either ( \left| x_{1} \right| ) or ( \left| x_{2} \right| ) is larger.

Case 1: ( \left| x_{1} \right| > \left| x_{2} \right| )

In this case, ( h(x) = \left| x_{1} \right| ), so the system becomes:

( \dot{x}{1} = x{1} + x_{2} - x_{1} \cdot \left| x_{1} \right| )

( \dot{x}{2} = -2x{1} + x_{2} - x_{2} \cdot \left| x_{1} \right| )

Case 2: ( \left| x_{2} \right| > \left| x_{1} \right| )

In this case, ( h(x) = \left| x_{2} \right| ), so the system becomes:

( \dot{x}{1} = x{1} + x_{2} - x_{1} \cdot \left| x_{2} \right| )

( \dot{x}{2} = -2x{1} + x_{2} - x_{2} \cdot \left| x_{2} \right| )

Now, let's analyze each case separately.

Case 1: ( \left| x_{1} \right| > \left| x_{2} \right| )

In this case, the system becomes:

( \dot{x}{1} = x{1} + x_{2} - x_{1} \cdot \left| x_{1} \right| )

( \dot{x}{2} = -2x{1} + x_{2} - x_{2} \cdot \left| x_{1} \right| )

To find potential fixed points, we set ( \dot{x}{1} = \dot{x}{2} = 0 ):

( x_{1} + x_{2} - x_{1} \cdot \left| x_{1} \right| = 0 )

( -2x_{1} + x_{2} - x_{2} \cdot \left| x_{1} \right| = 0 )

Simplifying the equations, we have:

( (1 - \left| x_{1} \right|)x_{1} + x_{2} = 0 )

( (-2 - \left| x_{1} \right|)x_{1} + (1 - \left| x_{1} \right|)x_{2} = 0 )

From these equations, we can see that the fixed points occur when either ( x_{1} = 0 ) or ( x_{2} = 0 ). However, in both cases, the system is not globally asymptotically stable, and trajectories can escape to infinity.

Since the system is not globally asymptotically stable, we cannot conclude the existence of a periodic orbit in Case 1.

Case 2: ( \left| x_{2} \right| > \left| x_{1} \right| )

In this case, the system becomes:

( \dot{x}{1} = x{1} + x_{2} - x_{1} \cdot \left| x_{2} \right| )

( \dot{x}{2} = -2x{1} + x_{2} - x_{2} \cdot \left| x_{2} \right| )

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Answer:

3x ( 4x-3 )( 2x - 5 )

Step-by-step explanation:

24x^3 - 78x^2 + 45x

factor out biggest common values

3x ( 8x^2 - 26x + 15 )

3x ( 4x-3 )( 2x - 5 )

One way of solving the following system by elimination is to multiply equation (2) by 2 to eliminate the y-terms by direct addition.

To solve the given system of equations, we can use the method of elimination. The goal is to eliminate one variable by adding or subtracting the equations in a way that allows us to solve for the remaining variable. In this case, we want to eliminate the y-terms. To do this, we can multiply equation (2) by **2** to make the coefficients of the y-terms the same in both equations.

Multiplying equation (2) by 2, we get:

2 * (2x + y) = 2 * 19

4x + 2y = 38

Now we have two equations:

14x + 13y = 71

4x + 2y = 38

By multiplying equation (2) by 2, the coefficients of the y-terms in both equations are now the same, namely **2**. We can proceed to eliminate the y-terms by subtracting the second equation from the first equation.

Subtracting equation (2) from equation (1), we get:

(14x + 13y) - (4x + 2y) = 71 - 38

14x + 13y - 4x - 2y = 33

10x + 11y = 33

Now we have a new equation:

10x + 11y = 33

We can now solve this equation simultaneously with one of the original equations to find the values of x and y.

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By mathematical induction, we have proved that for any positive integer n, 4 evenly divides 11n - 7n.

WHat is Divisibility?

Divisibility is a mathematical property that describes whether one number can be divided evenly by another number without leaving a remainder. If a number is divisible by another number, it means that the division process results in a whole number without any remainder. For example, 15 is divisible by 3

To prove that 4 evenly divides 11n - 7n for any positive integer n, we can use mathematical induction.

Base Case:

When n = 1, 11n - 7n = 11(1) - 7(1) = 4, which is divisible by 4.

Inductive Step:

Assume that 4 evenly divides 11n - 7n for some positive integer k, i.e., 11k - 7k is divisible by 4.

We need to prove that 4 evenly divides 11(k+1) - 7(k+1), which is (11k + 11) - (7k + 7) = (11k - 7k) + (11 - 7) = 4k + 4.

Since 4 evenly divides 4k, and 4 evenly divides 4, it follows that 4 evenly divides 4k + 4.

By mathematical induction, we have proved that for any positive integer n, 4 evenly divides 11n - 7n.

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When we calculate the value of tan82 then we have to round off to hu ndreth place.