PLEASE ANSWER CORRECTLY FOLLOWING GUIDLINES SO ANSWER WONT GET DELETED I REALLY NEED HELP

Use the terms in the boxes to fill in the blanks in the following paragraphs.

Atoms, Balanced, Chemical Reaction, Coefficients, Correct, Element, Equation, Formula, Mass, Mg, Numbers, Products, Reactants, Substance, Two, Yields

A ___________________________ is a well defined example of a chemical change. A chemical ___________________________ can be used to show the changes that occur in a chemical reaction. In a chemical reaction, the substance on the left side of the arrow are the starting substance. These substances are called ___________________________. The substances on the right side of the arrow are the substances that result from the reaction. These substances are called ___________________________. The arrow is read as either produces or ___________________________. According to the law of conservation of ___________________________, atoms are neither lost nor gained during a chemical reaction. This law is illustrated when a chemical equation is ___________________. When this is done, there will be the same number of ___________________________ of each kind on both sides of the equation. In a chemical equation, the numbers that are placed in front of the symbols and the formulas are called ___________________________. They are necessary to keep the ___________________________ of atoms in balance. There are several rules for balancing an equation. First, write the correct _________________________ for each reactant and product. Next, choose the coefficients that make the number of atoms of each ___________________________ on each side of the equation equal. The correctly written formula should not be changed. If you change the formula of a substance, the equation is no longer ________________________. Changing a formula will indicate a ___________________________ different than the one intended. To balance the equation Mg + O2 à MgO, first choose coefficients to make the number of atoms of each element on each side of the equation equal. You would need to place a coefficient of ____________________

Answer:

Cytokinesis

Explanation:

Answer:

1 mole H2O has 6.02 × 10^23 molecules

Explanation:

Answer:

A.

Explanation:

Potential energy. Potential energy is energy that is stored.

Answer:

46.97g

Explanation:

Hello,

To find the theoretical yield, we must first of all get the equation of reaction right in order to know how the compounds combine together.

Equation of reaction;

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

From the equation of reaction,

2 moles of C₂H₆ reacts with 7 moles of O₂ to produce 4 moles of CO₂.

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of CO₂ = 4 × 44 = 176g

Mass of C₂H₆ = 2 × 30 = 60g

Mass of O₂ = 7 × 32 = 224g

Therefore, 224g + 60g (O₂ + C₂H₆) = 176g of CO₂.

284g of reactants = 176g of product(CO₂)

(18 + 57.8)g of reactants = x g of products(CO₂)

X = (75.8 × 176) /284

X = 46.97g of CO₂.

Theoretical yield of CO₂ is 46.97g

First of all, Z is unknown. I hope it is a mistake.

        Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.

        As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.

        Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.

( No internal links available for reference. For clarification, check the periodic table).

Answer:

In equation form, Newton's second law of motion is a=Fnetm a = F net m . This is often written in the more familiar form: Fnet = ma. The weight w of an object is defined as the force of gravity acting on an object of mass m. ... Friction is a force that opposes the motion past each other of objects that are touching.

F = ma, or force equals mass times acceleration, is Newton's second law of motion.

According to the first law, an object's motion will not change unless a force acts on it.

According to the second law, the force acting on an object is equal to its mass multiplied by its acceleration.

When two objects interact, they apply forces of equal magnitude and opposite direction to each other, according to the third law.

His second law states that a force is defined as the change in momentum divided by the change in time. Newton's second law of motion is F = ma, or force equals mass times acceleration.

F → A B = − F → B A. The conservation of momentum is associated with Newton's third law of motion.

Every action must have an equal and opposite reaction, according to the law.

Thus, this is the equation for Newton's second law of motion.

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Hydrogen can be obtained in large quantities from water gas by the reaction of water vapor with carbon monoxide. The gas mixture produced can be used in various hydrogen production processes such as steam reforming, partial oxidation, and autothermal reforming.

Hydrogen, a colorless, odorless, and tasteless gas, is obtained from water gas by the reaction of water vapor with carbon monoxide. When water is reacted with coke or other raw materials, a mixture of hydrogen and carbon monoxide gases is produced. The gas mixture is known as water gas, and it can be used to produce large quantities of hydrogen.There are several methods for producing hydrogen from water gas, including the following:

1. Steam reforming: In this process, water gas is reacted with steam to produce hydrogen and carbon dioxide. The reaction is endothermic and requires high temperatures and pressure.

2. Partial oxidation: In this process, water gas is partially oxidized with oxygen or air to produce hydrogen and carbon dioxide. The reaction is exothermic and can produce high temperatures.

3. Autothermal reforming: In this process, water gas is partially oxidized and reacted with steam in a single step. This process can produce high purity hydrogen with low emissions of greenhouse gases.

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Answer:

Solid---> Liquid

The periodic table is an arrangement of elements based on their atomic structure. Dirt is not an element, but a mixture of many substances, including minerals, organic matter, and water.

Therefore, dirt cannot be listed on the periodic table because it does not have a single atomic structure. Dirt is composed of a variety of components, and its composition can vary depending on the environment.

For example, the dirt in a desert will contain different minerals than the dirt in a forest. The periodic table is a useful tool for understanding the properties of elements, but not for understanding the composition of dirt.

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To make an E9 mixture 8657.14 gal of E7 should be mixed with 3000 gal of E10

Given to us is the amount of ethanol in the E10 mixture is 10% of 3000 gallons:

Ethanol in E10 = 10% × 3000 gal = 0.10 × 3000 gal = 300 gal

To solve this problem, we can set up an equation based on the amount of ethanol in each mixture.

Let x represent the amount of E7 mixture (in gallons) that needs to be added to the E10 mixture to obtain the desired E9 mixture.

The amount of ethanol in the E7 mixture is 7% of x gallons:

Ethanol in E7 = 7% ×  gal = 0.07 × gal

The resulting E9 mixture will contain 9% ethanol of the total volume of 3000 + x gallons:

Ethanol in E9 = 9% × (3000 + x) gal = 0.09 × (3000 + x) gal

According to the problem, the resulting E9 mixture contains 906 gallons of ethanol:

Ethanol in E9 = 906 gal

Now we can set up the equation:

Ethanol in E10 + Ethanol in E7 = Ethanol in E9

300 gal + 0.07x gal = 906 gal

Subtracting 300 gal from both sides:

0.07x gal = 606 gal

Dividing both sides by 0.07:

x = 606 gal / 0.07

x = 8657.14

Therefore, approximately 8657.14 gallons of E7 mixture should be mixed with 3000 gallons of E10 to make an E9 mixture.

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Complete question: Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E7 should be mixed with 3000 gal of E10 to make an E9 mixture?

A. when the volume of the gas is halved, the pressure of the gas will be doubled.

PV = nRT

P = nRT/V

when the volume is halved

P= nRT/0.5V

P = 2nRT/V

P(new) = 2P(initial)

Thus, when the volume of the gas is halved, the pressure of the gas will be doubled.

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Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

Heat of vaporization:

Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

When a substance is heated, the added energy increases the kinetic energy of the molecules, causing them to move faster. As the temperature rises, the average kinetic energy of the molecules increases, and eventually, the molecules have enough energy to overcome the intermolecular forces and escape from the liquid phase, forming a gas.

The heat of vaporization is specific to each substance and is typically expressed in units of joules per gram (J/g) or calories per gram (cal/g). It is an important property in various applications, such as in the design of cooling systems, understanding phase changes, and calculating energy requirements for processes involving vaporization.

Fact:

The heat of vaporization for water is approximately 40.7 kilojoules per mole (kJ/mol) at its boiling point of 100 degrees Celsius.

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The heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature. It is denoted by delta Hvap.

This is a measure of the energy that is required to overcome the intermolecular forces that hold a liquid together and break the bonds between the molecules to form a gas.Heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature.

There are many interesting phenomena where the heat of vaporisation can be seen. For instance, heat is continuously added to liquid water when it boils on a hob in order to overcome the intermolecular interactions and turn it into water vapour. Similar to how sweat evaporates from our skin, the heat that is removed from us as the sweat changes from a liquid to a gas cools us down.

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Forward component of the reaction When CO₂ is added to water, it dissolves and reacts to form carbonic acid (H₂CO3) in the forward reaction.

The formula CO₂ + H₂O → H₂CO3 → H* + HCO3 represents the carbon dioxide equilibrium. The forward and reverse components of the reaction can be explained as follows:  H₂CO3 has two possible reactions: It either releases a hydrogen ion (H+) and forms bicarbonate (HCO3-) or it releases two hydrogen ions (2H+) to form carbonate (CO32-) and water (H₂O).

CO₂ + H₂O → H₂CO3 → H+ + HCO3Reverse component of the reactionWhen hydrogen ions (H+) are added to bicarbonate ions (HCO3-) or carbonate ions (CO32-), the reverse reaction takes place and carbonic acid (H₂CO3) is formed. Carbonic acid (H₂CO3) can also be decomposed into carbon dioxide (CO₂) and water (H₂O).

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Answer:

THE CORRECT ANSWER IS D

Explanation:

A, B, and C are incorrect. I took the test so I know. Hope this helps

The abundance of an element in nature, its percent composition in compounds, and its average atomic mass are all interconnected and can be used to draw conclusions about the properties and behavior of elements and compounds.

There are several conclusions that can be drawn between abundance in nature, percent composition, and average atomic mass. First, the abundance of an element in nature is directly related to its percent composition. Elements that are more abundant in nature will have a higher percent composition in a compound. For example, oxygen is the most abundant element in the Earth's crust, making up 46.6% of its mass. Therefore, compounds that are found in the Earth's crust, such as silicates, will have a high percent composition of oxygen.

Secondly, the average atomic mass of an element is also related to its abundance in nature. The average atomic mass of an element is the weighted average of the masses of its isotopes, which takes into account the abundance of each isotope. For example, the element chlorine has two stable isotopes, Cl-35 and Cl-37. The average atomic mass of chlorine is 35.45, which reflects the fact that Cl-35 is more abundant in nature than Cl-37.

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In order to completely precipitate the silver ions in one mole of silver nitrate (AgNO3), an equal number of moles of sodium chloride (NaCl) must enter the solution.

The balanced chemical equation for the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) is:

NaCl(aq) + AgNO3(aq) ⟶ NaNO3(aq) + AgCl(s)

From the equation, we can see that one mole of sodium chloride reacts with one mole of silver nitrate to produce one mole of sodium nitrate (NaNO3) and one mole of silver chloride (AgCl) precipitate.

Since the reaction is stoichiometric, it means that the mole ratio between sodium chloride and silver nitrate is 1:1. This indicates that to completely precipitate the silver ions in one mole of silver nitrate, one mole of sodium chloride must enter the solution.

Therefore, if you have one mole of silver nitrate, you will need one mole of sodium chloride to ensure that all the silver ions are precipitated as silver chloride.

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The percent dissociation of hydrocyanic acid under these conditions is 11.81 %.

Balanced equation of hydrocyanicacid acid dissociation in water:

HCN(aq) → H⁺(aq) + CN⁻(aq)

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

pH(HCN) = 2.33

c(H⁺) = 0.467 M; concentration of hydrogen ions

c(H⁺) = c(CN⁻); from the chemical equation

c(HCN) = 4.420 M; concentration of the hydrocyanic acid

percent dissociation = (concentration of H⁺/concentration of acid) x 100%

the percent dissociation = (0.467 M / (4.420 M - 0.467 M)) × 100%

the percent dissociation = 11.81 %.

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A) If, the pressure is 10.0 atm, the temperature in the 2.50 L container filled with 175 g of argon is approximately 57.3 K. B) If the temperature is 225 K, the pressure in the 2.50 L container filled with 175 g of argon is approximately 79.1 atm.

Firstly, we can use the ideal gas law equation;

PV = nRT

Where;

P = pressure (in atm)

V = volume (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (in Kelvin)

Given;

V = 2.50 L

m (mass of argon) = 175 g

P = 10.0 atm

First, we need to calculate the number of moles of argon using the given mass and the molar mass of argon.

The molar mass of argon will be approximately 39.95 g/mol.

Number of moles (n) = mass/molar mass

n = 175 g / 39.95 g/mol

n ≈ 4.38 mol

Now, we rearrange the ideal gas law equation to solve for temperature (T);

T = PV / (nR)

Substituting the given values, we have:

T = (10.0 atm) × (2.50 L) / (4.38 mol × 0.0821 L·atm/mol·K)

Calculating this expression, we find;

T ≈ 57.3 K

Therefore, if the pressure is 10.0 atm, the temperature in the 2.50 L container filled with 175 g of argon is approximately 57.3 K.

Given;

T = 225 K

To find the pressure (P), we rearrange the ideal gas law equation as follows;

P = nRT / V

Substituting the given values, we have:

P = (4.38 mol × 0.0821 L·atm/mol·K × 225 K) / (2.50 L)

Calculating this expression, we find:

P ≈ 79.1 atm

Therefore, if the temperature is 225 K, the pressure in the 2.50 L container filled with 175 g of argon is approximately 79.1 atm.

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--The given question is incomplete, the complete question is

"A 2.50-L container is filled with 175 g argon. a. If the pressure is 10.0 atm, what is the temperature? b. If the temperature is 225 K, what is the pressure? "--

Answer:

There are four main factors that can affect the reaction rate of a chemical reaction:

Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...

Physical state of the reactants and surface area. ...

Temperature. ...

Presence of a catalyst.

For standard 1, the volume of stock solution required is 2.00 mL, while for standard 2, it is 4.00 mL.

In order to calculate the volume of 0.0315 m Bromocresol green (HBCG) standard stock solution required to make 10.00 ml of the three standards, we need to use the formula:

M1V1 = M2V2

Where M1 is the concentration of the stock solution,

V1 is the volume of the stock solution required,

M2 is the concentration of the final solution, and

V2 is the final volume of the solution.

To calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.00630 m Bromocresol green (HBCG) standard 1, we can plug in the values into the formula as:

M1V1 = M2V2V1 = (M2V2)/M1= (0.00630 mol/L x 0.01000 L)/0.0315 mol/L= 0.00200 L = 2.00 mL

Therefore, the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.00630 m Bromocresol green (HBCG) standard 1 is 2.00 mL.

To calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.0126 m Bromocresol green (HBCG) standard 2, we can use the same formula as above:

M1V1 = M2V2V1 = (M2V2)/M1= (0.0126 mol/L x 0.01000 L)/0.0315 mol/L= 0.00400 L = 4.00 mL

Therefore, the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make 10.00 ml of 0.0126 m Bromocresol green (HBCG) standard 2 is 4.00 mL.

In conclusion, we can use the formula M1V1 = M2V2 to calculate the volume of 0.0315 m Bromocresol green (HBCG) stock solution required to make different standards.

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[Fe(CN)₆]⁴⁻ ion has one unpaired electron with d₆ electronic configuration.

We must take into account the electronic structure of the Fe3+ ion, which has five 3d electrons and no 4s electrons, in order to calculate the number of unpaired electrons in the [Fe(CN)₆]⁴⁻ ion. CN- ligands donate two electrons to form a coordinate covalent bond with Fe³⁺ when they coordinate with the metal ion. Each CN- ligand consequently takes up one of the six coordination sites surrounding Fe³⁺.

The [Fe(CN)₆]⁴⁻ ion has a d₆ electronic configuration, meaning that electrons occupy each of its six d orbitals. When degenerate orbitals are available, electrons first occupy them alone before pairing up, according to Hund's rule. As a result, given that there are six electrons in the d orbitals, we can anticipate that at least one of them will be unoccupied, leading to one unpaired electron.

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A. The percentage of sulphur in tetraoxosulphate (vi) acid, H₂SO₄ is 32.7%

B. The percentage of phosphorus in tetraoxophoshate (v) acid, H₃PO₄ is 31.6%

B. The percentage of oxygen in calcium trioxonitrate (v), Ca(NO₃)₂ is 58.5%

The percentage of sulphur in tetraoxosulphate (vi) acid H₂SO₄ can be obtained as follow:

Percentage of S = (mass of S / mass of H₂SO₄) × 100

Percentage of S = (32 / 98) × 100

Percentage of S = 32.7%

The percentage of phosphorus in tetraoxophoshate (v) acid, H₃PO₄ can be obtained as follow:

Percentage of P = (mass of S / mass of H₃PO₄) × 100

Percentage of P = (31 / 98) × 100

Percentage of P = 31.6%

The percentage of oxygen in calcium trioxonitrate (v), Ca(NO₃)₂ can be obtained as follow:

Percentage of O = (mass of S / mass of Ca(NO₃)₂) × 100

Percentage of O = (96 / 164) × 100

Percentage of O = 58.5%

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Answer:

Suppression

Explanation:

suppression is used to reduce pest populations below the economic threshold if prevention and avoidance tactics have failed--chemical, bio and cultural and other tactics are used which minimize environmental impacts

Answer:

i know im late again but its suppression

Explanation:

Answer:

Ground state electronic configuration of nitrogen atom can be represented by 1, 4 only. All the unpaired electrons have spins aligned in the same direction only.

Explanation:

Part a)1) After adding 18.0 mL of the NaOH solution, the mixture is "before" the equivalence point on the titration curve.
2) The pH of the solution after adding NaOH is 5.30.

To determine this, we use the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid])At the start of the titration, we have a solution of 0.75 M CH3CH2COOH, which is an acid. As we add NaOH, it reacts with the acid to form a salt and water: CH3CH2COOH + NaOH -> CH3CH2COONa + H2O

At the equivalence point, we have added enough NaOH to completely neutralize the acid, and the solution is a mixture of the salt and water.

To find the pH after adding 18.0 mL of 0.30 M NaOH, we need to calculate the moles of acid and base present. The initial moles of acid are: moles acid = 0.75 M x 0.0100 L = 0.0075 mol, The moles of NaOH added are: moles NaOH = 0.30 M x 0.0180 L = 0.0054 mol

At this point, we have not added enough NaOH to reach the equivalence point, so there is still some acid left in the solution. The moles of acid remaining are: moles acid remaining = 0.0075 mol - 0.0054 mol = 0.0021 mol

The moles of base (NaOH) that have reacted with the acid are: moles base = 0.0054 mol, The new concentration of acid is: [acid] = moles acid remaining / (0.0100 L + 0.0180 L) = 0.063 M, The new concentration of base is: [base] = moles base / (0.0100 L + 0.0180 L) = 0.190 M

Plugging these values into the Henderson-Hasselbalch equation gives:
pH = pKa + log([base]/[acid])
pH = 4.86 + log(0.190/0.063)
pH = 5.30

So the pH of the solution after adding 18.0 mL of NaOH is 5.30.

Part b):
3) After adding 25.0 mL of the NaOH solution, the mixture is "at" the equivalence point on the titration curve.
4) The pH of the solution after adding NaOH is 9.38.

At the equivalence point, we have added enough NaOH to completely neutralize the acid. The moles of acid and base are equal, and we have a mixture of the salt and water. The moles of acid at the equivalence point are: moles acid = 0.75 M x 0.0100 L = 0.0075 mol

The moles of base needed to neutralize this amount of acid are: moles base = 0.0075 mol, To find the volume of NaOH needed to reach the equivalence point, we can use the equation: moles base = concentration x volume

Solving for volume, we get:
volume = moles base / concentration
volume = 0.0075 mol / 0.30 M
volume = 0.025 L = 25.0 mL

So after adding 25.0 mL of NaOH, we have reached the equivalence point. The moles of NaOH added are: moles NaOH = 0.30 M x 0.0250 L = 0.0075 mol. The moles of base remaining in the solution are: moles base remaining = 0.0075 mol - 0.0075 mol = 0 mol

So the concentration of base at the equivalence point is 0 M. The moles of salt formed are equal to the moles of acid neutralized, which is 0.0075 mol. The new volume of the solution is: volume = 0.0100 L + 0.0250 L = 0.035 L

So the concentration of the salt is:
[salt] = moles salt / volume
[salt] = 0.0075 mol / 0.035 L
[salt] = 0.214 M

The salt is the conjugate base of the acid, so we can use the Kb expression to find the pOH of the solution: Kb = Kw/Ka
Kb = 1.0 x 10^-14 / 1.3 x 10^-5
Kb = 7.69 x 10^-10

pOH = pKb + log([salt]/[OH-])
pOH = 9.12 + log(0.214/0.214)
pOH = 9.12

So the pH of the solution after adding 25.0 mL of NaOH is:
pH = 14 - pOH
pH = 14 - 9.12
pH = 4.88

Part c):
5) After adding 30 mL of the NaOH solution, the mixture is "after" the equivalence point on the titration curve.
6) The pH of the solution after adding NaOH is 12.57. After the equivalence point, we have added more base than necessary to neutralize the acid. The excess base will react with the salt (conjugate base) to form a basic solution. The moles of acid and base at this point are: moles acid = 0.75 M x 0.0100 L = 0.0075 mol, moles base = 0.30 M x 0.0300 L = 0.0090 mol

The moles of excess base are: moles excess base = 0.0090 mol - 0.0075 mol = 0.0015 mol

The volume of the solution is now: volume = 0.0100 L + 0.0300 L = 0.0400 L

The concentration of the salt is:
[salt] = moles salt / volume
[salt] = 0.0075 mol / 0.0400 L
[salt] = 0.188 M

The concentration of excess base is:
[OH-] = moles excess base / volume
[OH-] = 0.0015 mol / 0.0400 L
[OH-] = 0.038 M

The concentration of H+ ions can be found using the Kw expression:
Kw = [H+][OH-]
1.0 x 10^-14 = [H+][0.038]
[H+] = 2.63 x 10^-13

So the pH of the solution after adding 30 mL of NaOH is:
pH = -log[H+]
pH = -log(2.63 x 10^-13)
pH = 12.57

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Answer:

In 7.1g of potassium, there are 1.09 * 10^23 atoms

Explanation:

HERE, we want to get the number of atoms on 7.1g of potassium

The first thing we have to do here is to convert the given mass to moles

We can do this by dividing the mass by the atomic mass unit of potassium

The atomic mass unit of potassium is 39.1 amu

We can get the number of moles mathematically as follows:

Finally,we can get the number of atoms

In 1 mole of a substance, the number of atoms is:

To get the number of atoms in 0.1816 mole, we simply multiply the two as follows:

The molecular formula for the proper reagent to give the highest yield in the conversion of (1S,3S)-3-methylcyclohexan-1-ol into (1R,3S)-1-chloro-3-methylcyclohexane while considering stereochemistry is:

Thionyl chloride (SOCl2)

Thionyl chloride (SOCl2) is commonly used for the conversion of alcohols to alkyl chlorides. In this specific case, it will result in the inversion of the stereochemistry at the carbon bearing the hydroxyl group (C1), while maintaining the stereochemistry at carbon C3.

The reaction proceeds as follows:

(1S,3S)-3-methylcyclohexan-1-ol + SOCl2 → (1R,3S)-1-chloro-3-methylcyclohexane + HCl + SO2

Thionyl chloride (SOCl2) reacts with the alcohol to form an alkyl chloride, with the chlorine substituting the hydroxyl group. The stereochemistry at C1 is inverted, resulting in the (1R,3S) configuration in the final product.

Please note that this is a general answer based on the given stereochemistry. The reaction conditions and other factors may need to be considered for a specific reaction setup.

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Answer:

condenser is the answer

Answer:

condenser is the answer