Answer:
3 and 2
May be
ok may be subscribeIsenberg Isenberg Ignatius
A filament electron interacts with an outer shell electron of a tungsten but does not remove it. Which of the following is produced?
A) 50 keV photon
B) 70 keV photon
C) heat
D) brems photon
When a filament electron interacts with an outer shell electron of tungsten but does not remove it, the most likely outcome is the production of a bremsstrahlung photon. Therefore, the correct answer is D) brems photon.
Bremsstrahlung radiation, also known as braking radiation, occurs when a charged particle (in this case, the filament electron) is deflected by the electric field of an atomic nucleus (the outer shell electron of tungsten). As the filament electron is decelerated, it emits a photon with energy equal to the lost kinetic energy. The energy of the bremsstrahlung photon depends on the initial energy of the filament electron. In this scenario, since the outer shell electron is not removed, the filament electron loses a portion of its kinetic energy, resulting in the emission of a bremsstrahlung photon. The given options of 50 keV photon and 70 keV photon are less likely because they suggest a specific energy value, which might not correspond to the actual energy of the bremsstrahlung photon produced in this particular interaction. The option of heat (C) is less probable since it implies a non-radiative transfer of energy, whereas bremsstrahlung photons are characterized by their electromagnetic radiation.
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A car is going 60.0 mi/h and has to stop in 6.0 seconds. What is the car’s acceleration?
Explanation:
Convert mi/h to ft/s.
60.0 mi/h × (5280 ft/mi) × (1 h / 3600 s) = 88.0 ft/s
Find the acceleration.
a = Δv / Δt
a = (0 ft/s − 88.0 ft/s) / 6.0 s
a = -14.7 ft/s²
The driver must accelerate the car at the average rate of
- 10 mile / hour-second
for 6 seconds .
How many uses of aerosol
cans in the home can you
think of?
Answer: Well, think of all the aerosol products that are available: shaving cream, bathroom cleaners, rug shampoo, spray paint, hair spray, insect sprays, room deodorizers, automotive products -- the list goes on.
The radiation pressure exerted by the Sun on the Earth counteracts the gravitational attraction and puts the Earth into an orbit that is farther from the Sun than if there were no radiation pressure. It can be shown that the distance added to Earth's orbital radius is given by (Frad/Fg)r, where Frad is the radiation force exerted on Earth by the Sun, Fg is the gravitational force between the Earth and Sun, and r is the average orbital radius.
Part A Part complete If the intensity of sunlight that strikes Earth is 1260 W/m2, what is Frad, assuming the Earth is a perfect absorber? Express your answer to three significant figures and include appropriate units. 5.35×108 N Correct
Part B Assuming r=1.50×1011m, what is Fg? Express your answer to three significant figures and include appropriate units.
Part C What is the additional distance added to Earth's orbital radius by the radiation pressure? Express your answer to three significant figures and include appropriate units.
The additional distance added to Earth's orbital radius by the radiation pressure is approximately 228 kilometers.
Part A:
The radiation force (Frad) exerted on Earth by the Sun can be calculated using the formula Frad = (intensity of sunlight) × (area), where the intensity of sunlight is given as 1260 W/m^2 and the area is the cross-sectional area of Earth. Assuming the Earth is a perfect absorber, all the incoming sunlight is absorbed. The cross-sectional area of Earth can be approximated as the area of a circle with a radius equal to the average orbital radius (r). Therefore, the area is given by A = πr^2.
Substituting the values into the equation, we have:
Frad = (1260 W/m^2) × πr^2
Calculating Frad with the given average orbital radius:
Frad = (1260 W/m^2) × π(1.50×10^11 m)^2
Frad ≈ 5.35×10^8 N
Part B:
The gravitational force (Fg) between the Earth and the Sun can be calculated using the formula Fg = (G × mass of Earth × mass of Sun) / (distance^2), where G is the gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2), the mass of the Earth is approximately 5.972 × 10^24 kg, the mass of the Sun is approximately 1.989 × 10^30 kg, and the distance (r) is given as 1.50 × 10^11 m.
Substituting the values into the equation, we have:
Fg = (6.67430 × 10^-11 m^3 kg^-1 s^-2 × 5.972 × 10^24 kg × 1.989 × 10^30 kg) / (1.50 × 10^11 m)^2
Calculating Fg:
Fg ≈ 3.52 × 10^22 N
Part C:
The additional distance added to Earth's orbital radius by the radiation pressure can be calculated using the formula Frad/Fg × r.
Substituting the values into the equation:
Additional distance = (Frad / Fg) × r
Additional distance = (5.35 × 10^8 N / 3.52 × 10^22 N) × 1.50 × 10^11 m
Calculating the additional distance:
Additional distance ≈ 2.28 × 10^5 m or 228 km
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What's unusual about our Moon? (a) It's the only moon that orbits a terrestrial planet. (b) It's by far the largest moon in the solar system. (c) It's surprisingly large relative to the planet it orbits.
Unusual about our Moon is It's surprisingly large relative to the planet it orbits.
What's unusual about our Moon?The Moon is unusual because it is relatively large compared to its host planet, Earth.
It has a diameter of about one-quarter that of Earth, making it the largest moon relative to its host planet in the solar system.
In fact, some scientists consider the Earth-Moon system to be a double planet because of the Moon's relatively large size.
Most other moons in the solar system are much smaller compared to their host planet.
Additionally, the Moon is the fifth largest moon in the entire solar system, despite orbiting a relatively small planet.
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let e be any edge of minimum weight in g. then e must be part of some mstT/F
This statement is True. If e is the edge of the minimum weight in the graph, then it must be included in any minimum spanning tree (MST) of the graph.
This is because an MST is a tree that spans all the vertices of the graph with the minimum total weight, and removing any edge from it would result in a disconnected graph or a tree with a higher weight. Therefore, since e is the edge of minimum weight, it must be part of some MST.
Explanation:
1. Start with an empty MST.
2. Select the edge 'e' of minimum weight from the given graph G.
3. Add this edge 'e' to the MST.
4. Continue adding the next minimum weight edges to the MST while ensuring that no cycles are formed.
5. Repeat the process until the MST includes all the vertices from graph G.
Since the edge 'e' is of minimum weight in G, it will be included in the MST during the construction process, ensuring that the final MST is also of minimum weight.
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A 67.3-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behaves like a spring with a spring constant of 1.23 x 103 N/m. He accidentally slips and falls freely for 0.921 m before the rope runs out of slack. How much is the rope stretched when it breaks his fall and momentarily brings him to rest
Answer:
\(d=0.59m\)
Explanation:
From the question we are told that:
Mass \(m=67.3 kg\)
Spring constant \(\mu=1.23 * 10^3 N/m\)
Fall Height \(h=0.921m\)
Generally the Energy theorem equation for momentum is mathematically given by
Change in KE=Work done by gravity + work done by spring
\(0=mg*(h + d) - \frac{\mu d^2}{2}\)
\(0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}\)
\(0=608.1-660.213d-615d^2\)
Solving Quadratic equation
\(d=0.59m\)
older stars that are more original to the galaxy, reddish in color, and much cooler than their newer counterparts are classified as what kind of stars?
POPULATION || STARS are older stars that are more common in the galaxy, redder in hue, and considerably colder than their more recent counterparts.
A star is a massive celestial object or astronomical object made of a brilliant sphere of plasma that is held together by its own gravitational pull.
Usually, it consists of two (2) major heated gases: hydrogen (H) and helium (He).
The total quantity of light emitted by a star per second is known as its luminosity, and it is expressed in watts (w). The rate at which emitted energy from a star reaches an observer on Earth per square meter per second is measured by a star's apparent brightness.
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An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
80 amperes
Explanation:
Current = Voltage/Resistance
160/2 = 80
acrostic poem for cell theory. Especially theory
Answer:
In biology, cell theory is the historic scientific theory, now universally accepted, that living organisms are made up of cells, that they are the basic structural/organizational unit of all organisms, and that all cells come from pre-existing cells. Cells are the basic unit of structure in all organisms and also the basic unit of reproduction.
Explanation:
The three tenets to the cell theory are as described below:
All living organisms are composed of one or more cells.
The cell is the basic unit of structure and organization in organisms.
Cells arise from pre-existing cells.
There is no universally accepted definition of life. Some biologists consider non-cellular entities such as viruses living organisms,[1] and thus reasonably disagree with the first tenet. Throughout this article, it will lead you through the history of cell theory, how the discovery of cells was made possible, what the cell theory has become today and background information and history regarding other opposing concepts of cell theory.
Write an expression for the coefficient of kinetic friction between the block and the horizontal surface. Your answer should be in terms of x, vB, and g (the acceleration due to gravity)
An expression for the coefficient of kinetic friction between the block and the horizontal surface is given as μk = Ff/mg.
What is coefficient of kinetic friction?
The coefficient of kinetic friction is the force of frcition between a moving object and the horizontal surface.
The expression for the coefficient of kinetic friction between the block and the horizontal surface is given as;
Ff = μkFₙ
Ff = μkmg
μk = Ff/mg
where;
μk is the coefficient of kinetic frictionFf is the kinetic frictional forcem is mass of the blockg is acceleration due to gravityThus, an expression for the coefficient of kinetic friction between the block and the horizontal surface is given as μk = Ff/mg.
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Im just a little confused right now
Answer:
C
YExplanation:
which option is an example of chemical energy being transformed into thermal energy?
A. a furnace burning coal
B. lightning striking a signal tower
C. a woman rubbing her hands together for warmth
D. a plant storing energy from the sun in its leaves.
Answer:
it's a.... a furnace burning coal
What cause sound seismic and electromagnetic waves to transmit energy through different mediums
Answer:
Explanation:
Sound, seismic, and electromagnetic waves transmit energy through different mediums due to the motion of particles in the medium.
Sound waves transmit energy through the vibration of particles in a solid, liquid, or gas. The energy is transferred from particle to particle as the wave travels through the medium.
Seismic waves are created by the sudden release of energy from earthquakes, volcanic eruptions, or other geological events. These waves travel through the Earth's solid mantle and crust, transmitting energy through the vibration of particles in the rock.
Electromagnetic waves are a type of wave that does not require a medium to travel through. They are created by the motion of charged particles, such as electrons, and can travel through a vacuum, such as space. Electromagnetic waves transfer energy through the oscillation of electric and magnetic fields.
Mercury receives about 1.77 x 1017 W from the Sun, of which it absorbs 88%, and has total surface area 7.78 x 1013 square meters. If half of Mercury's surface area is at the night side temperature and half at the day side temperature, estimate its daytime temperature in kelvin if Mercury radiates all of the light energy it absorbs from the Sun as a blackbody. Although this is only a rough estimate of a typical daytime temperature, it's enough to tell you that Mercury's day side is, uh, rather hostile to water-based life. (And 100 kelvin on the night side isn't any better.)
To estimate Mercury's daytime temperature, we can use the Stefan-Boltzmann law, which relates the radiated power of a blackbody to its temperature.
According to the problem, Mercury receives a total power of 1.77 x 10^17 W from the Sun, and it absorbs 88% of this power. This means that the absorbed power by Mercury is:
Absorbed power = 0.88 * (1.77 x 10^17 W) = 1.5576 x 10^17 W
Given that Mercury radiates all of the absorbed light energy as a blackbody, we can equate the absorbed power to the radiated power using the Stefan-Boltzmann law:
Radiated power = σ * A * T^4
Where:
σ is the Stefan-Boltzmann constant (approximately 5.67 x 10^-8 W/m^2·K^4)
A is the total surface area of Mercury (7.78 x 10^13 m^2)
T is the temperature of Mercury in Kelvin (which we want to find)
Since half of Mercury's surface is at the night side temperature and half at the day side temperature, we can assume that the radiated power is evenly distributed over the entire surface. Therefore, we can divide the total surface area by 2:
Radiated power = (1/2) * σ * A * T^4
Equating the absorbed and radiated powers:
1.5576 x 10^17 W = (1/2) * σ * A * T^4
Simplifying the equation:
T^4 = (2 * 1.5576 x 10^17 W) / (σ * A)
T^4 = (2 * 1.5576 x 10^17 W) / (5.67 x 10^-8 W/m^2·K^4 * 7.78 x 10^13 m^2)
T^4 ≈ 4.02 x 10^11 K^4
Taking the fourth root of both sides:
T ≈ (4.02 x 10^11 K^4)^(1/4)
T ≈ 467 K
Therefore, the estimated daytime temperature of Mercury is approximately 467 Kelvin.
Based on the rough estimate using the Stefan-Boltzmann law, Mercury's daytime temperature is estimated to be approximately 467 Kelvin. This high temperature indicates that Mercury's day side is extremely hostile to water-based life, and even the night side with a temperature of 100 Kelvin is inhospitable.
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Identify each of the following coordination complexes as either diamagnetic or paramagnetic v(h2)6) 3
The coordination complex [V(H2O)6]3+ can be identified as paramagnetic. Paramagnetic substances are weakly attracted to a magnetic field and exhibit magnetic properties. Therefore, [V(H2O)6]3+ is paramagnetic.
Paramagnetic substances are attracted to a magnetic field due to the presence of unpaired electrons, whereas diamagnetic substances are not affected by a magnetic field as all the electrons are paired. To determine the magnetic nature of [V(H2O)6]3+, we need to examine the electron configuration of the central vanadium (V) ion.
Vanadium (V) has an atomic number of 23, and its electronic configuration in the ground state is [Ar] 3d3 4s2. When vanadium forms coordination complexes, it often utilizes its d-orbitals for bonding. In [V(H2O)6]3+, the vanadium ion is in a +3 oxidation state, which means it has lost three electrons from its neutral state. Therefore, we remove the electrons from the 4s and 3d subshells to obtain the electron configuration of [V(H2O)6]3+ as [Ar] 3d2.
The 3d2 configuration indicates that two of the five 3d orbitals of vanadium are occupied by electrons, leaving three unpaired electrons. Since [V(H2O)6]3+ has unpaired electrons, it is paramagnetic.
Identify each of the following coordination complexes as either diamagnetic or paramagnetic
[ZnCl4^2-]
[Pd(NH3)2CL2]
[V(H2O)6]3+
Ni(en)3]2+
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If I travel at a velocity of 2m/s to the right for 4 seconds, what is my displacement?
Using F=mXa
1.
Maria's bicycle has a mass of 18.0 kg. What is the net force needed to attain the
acceleration of 1.62 m/s2?
Answer:
29.16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 18 × 1.62
We have the final answer as
29.16 NHope this helps you
what is frictional force?
how to Express frictional force?
Answer:
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.
What type of image is formed by the following mirror?
A) virtual, upright, enlarged
B) virtual, upright, reduced
C) real, inverted, enlarged
D) real, inverted, reduced
Answer:
b. virtual uprigthExplanation:
this is my answer is perfect please help
Newton second law of motion is F =ma
Answer: ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
Hi there!
Using Newton's Second Law:
\(F = ma\)
F = Net Force (60 N)
m = mass (30 kg)
a = acceleration (m/s²)
Solve for acceleration given the other values.
\(60 = 30a\\\\a = \frac{60}{30} = \boxed{2 \frac{m}{s^2}}\)
If the net force increases (while the mass is held constant), the acceleration will INCREASE.
If the mass of the object increases (while the net force is held constant), then the acceleration will DECREASE.
suppose your bathroom scale reads your mass is 55 kg, with a 1% uncertainty. what is the uncertainty in your mass in kilograms?
Answer:
± .55 kg
Explanation:
55 * 1% = .55 kg
± .55 kg
10.The heat capacity of an object, of mass 2.0 kg, is C. The energy needed to
A increase the temperature of the whole object by At is CAt.
B increase the temperature of unit mass of the object by At is CAt.
C melt the whole object is C.
D melt unit mass of the object is C.
The heat capacity of an object, of mass 2.0 kg, is tbe energy needed to increase the temperature of the whole object by 1°C
What is heat capacity of a substance?The heat capacity of a substance is the amount of heat energy required to raise the temperature of the object by 1°C.
The heat capacity differs from specific heat capacity in that specific heat capacity is the amount of heat energy required to raise a unit mass of a substance by 1°C.
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.terminal velocity is 0.8 N .
Simply put, what is terminal velocity?As a result, a object achieves terminal velocity when its acceleration (or deceleration) are zero and its speed is no longer increasing or decreasing.
What is the Earth's terminal velocity?around 53 m/s Unaffected by its mass, an item in free fall inside a vacuum would accelerate at a velocity of about 9.8 m/s2 close to the Earth's surface.When an object is dropped, air resistance causes it to finally achieve its terminal velocity, which for a human skydiver is about 53 m/s (190 km/h or 118 mph).
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Disilicon Trisulfide formula?
Using the Skygazer's Almanac for 2022 at 40 degrees.
What day will Venus and Saturn be in opposite parts of the sky
this year?
According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.
The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.
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An egg falls off a table. The floor is 0.8 m from the table top.
a) Calculate the time taken to reach the ground.
b) Calculate the velocity of impact with the ground.
Explanation:
u=0, h=0.8m, t=?, g=9.8m/s², v=?
finding b first,
v²-u²=2gh
v²=2×9.8×0.8
v=√15.68
v=3.959 m/s.
finding a now,
v=u+at
3.959-0=9.8t
3.959/9.8=t
0.40s=t
hope this helps you.
The rate of increase of the Earth's gravity field at latitudes 30° and 60° are in the ratio
Answer:
1 : 2 (30 : 60)
Explanation:
The rate of increase of the Earth's gravity field at latitudes 30° and 60° are in the ratio 1 : 2 because 30 : 60 simplified is 1 : 2.
If the answer does not ask for the ratio to be simplified leave its as 30 : 60.
a change in which of the following will affect the buoyant force experienced by an object that is totally submerged in a liquid?
Density of the fluid and volume of the body immmerse in it will affect the buoyant force experienced by an object that is totally submerged in a liquid.
Hence, the correct option is D.
A change in the following factors will affect the buoyant force experienced by an object that is totally submerged in a liquid:
a) Weight of the fluid displaced: The buoyant force is equal to the weight of the fluid displaced by the submerged object. Therefore, the weight of the fluid displaced, which is determined by the volume of the object submerged and the density of the fluid, will affect the buoyant force.
b) Density of the fluid: The buoyant force is directly proportional to the density of the fluid. If the density of the fluid changes, it will affect the buoyant force acting on the object.
c) Volume of the object submerged: The buoyant force is directly proportional to the volume of the object submerged in the fluid. If the volume of the object changes, it will result in a change in the buoyant force.
d) Mass of the fluid displaced: The buoyant force is also equal to the mass of the fluid displaced. This is determined by the volume of the object submerged and the density of the fluid.
So, to summarize, changes in the weight of the fluid displaced, the density of the fluid, the volume of the object submerged, or the mass of the fluid displaced will affect the buoyant force experienced by an object that is totally submerged in a liquid.
Hence, the correct option is D.
The given question is incomplete and the complete question is '' a change in which of the following will affect the buoyant force experienced by an object that is totally submerged in a liquid?
a. weight of the immersed in it
b. shape of the body immersed in the fluid
c. density of the fluid ande mass of the body immmerse in it.
d. density of the fluid and volume of the body immmerse in it.
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