Phosphorus-32 has a half-life of 14.0 days days. starting with 2.00 g of 32p32p, how many grams will remain after 112 daysdays pearson?

SO3 only would exist as a set of resonance structures

Define resonance.

In valence bond theory, resonance, also known as mesomerism, is a means to describe bonding in specific molecules or polyatomic ions by combining numerous contributing structures into a resonance hybrid.

The electronic bonding of a single polyatomic species, including fractional bonds and fractional charges, is described by resonance structures, which are a collection of two or more Lewis structures.

There are three resonance configurations in sulfur trioxide. However, because all of the oxygen atoms in SO3 are equal, all of the structures are equivalent. Three oxygen atoms and one sulfur atom make up sulfur trioxide. With a bond angle of 120, sulphur is sp2 hybridized with a trigonal planar structure in SO3.

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Answer:

B: 1s²2s²2p¹

Na: 1s²2s²2p⁶3s¹

Explanation:

A = 2

B = 1

C = 2

D = 6

E = 1

Answer:

  (A) is the answer

Explanation:

(A) heat a saturated sugar water solution, dissolve more sugar, then let the solution cool

Answer:

the answer is a

Explanation:

im on edg rn

Answer:

Molar mass of H3PO4  = 97.99 g/mol (Approx.)

Explanation:

Find:

Molar mass of H3PO4

Given;

Molar mass of H = 1.0079 g/mol

Molar mass of P = 30.974 g/mol

Molar mass of O = 15.999 g/mol

Computation:

Molar mass of H3PO4  = (1.0079)(3) + 30.974 + 15.999(4)

Molar mass of H3PO4  = 3.0237 + 30.974 + 63.996

Molar mass of H3PO4  = 97.9937

Molar mass of H3PO4  = 97.99 g/mol (Approx.)

Answer:

The above answer is correct

Explanation:

I took the test

Answer:

Single Displacement (Substitution)

Explanation:

Answer:

single replacement

Explanation:

did the test !!

Answer:

D. tap water

keep on learning!

Answer: ethanol

Explanation: as it is a pure compound and can sometimes be a mixture while all the rest are mixtures.

The statement "molecules move in random directions when heated in a heat engine, and because of the lack of uniformity in the direction of molecular movement" is true.

When a heat engine is heated, molecules absorb heat energy and their kinetic energy increases. The kinetic energy of molecules causes them to move around. However, this movement is not uniform, and the molecules move in random directions.

A heat engine is a device that converts thermal energy into mechanical energy. Heat engines operate on the principle of thermodynamics.

They work by taking in thermal energy from a high-temperature reservoir, converting some of it into mechanical energy, and then releasing the remaining thermal energy to a low-temperature reservoir.The internal combustion engine in a car, the steam engine in an old locomotive, and the turbine in a power plant are all examples of heat engines. They all convert heat energy into mechanical energy to perform work.

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Answer:

The answer is Iron phosphide (Fe2P)

Answer:

MgO.

Explanation:

charges of both satisfy one another (balanced) -- producing a compound MgO.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.

The tissue that plays this outer covering of a plant for is the  epidermis and its waxy cuticle. It prevents damage to the plant.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

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Answer: Cu is oxidized while Au is reduced. The oxidizing agent is Au while the reducing agent is Cu

Answer:

Both blanks are "Ag"

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Explanation:

Answer:

Hello, I can help!

Explanation:

Molecular Formula: ZnSO4. 7H2O or H14O11SZn

Molecular Weight: 287.6 g/mol

Functional groups: D, Ph, Me, Et, Bu, AcAc, For, Ts, Tos, Bz, TMS, tBu, Bzl, Bn, Dmg

Common compound names.

Examples of molar mass computations: NaCl, Ca(OH)2, K4[Fe(CN)6], CuSO4*5H2O, water, nitric acid, potassium permanganate, ethanol, fructose.

-Molecular mass (molecular weight) is the mass of one molecule of a substance and is expressed in the unified atomic mass units (u). (1 u is equal to 1/12 the mass of one atom of carbon-12)

-Molar mass (molar weight) is the mass of one mole of a substance and is expressed in g/mol.

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Mass percentage is a term that represents the concentration, basically mass by mass percentage. It tells about the percentage of a component in a whole component. Therefore,  the mass percentage of water in given compound is 43.8%.

Mass percentage represents the the percentage of each element that is making a particular compound. Mass percentage does not have any unit as numerator and denominator contains the same unit.

Mathematically,

Percentage of mass = (component’s mass ÷ total mass) x 100%

molar Mass of ZnSO\(_4\) · 7H\(_2\)0=287.57gram/mole

Mass of water =18g/mol

mass of 7 molecule of water=18×7

                                             =126gram/mole

substituting all the given values in the above equation, we get

Percentage of mass of water=(126÷287.57)×100

                                                 =43.8%

Therefore,  the mass percentage of water in given compound is 43.8%.

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The decomposition of hydrogen peroxide into water and oxygen is a slow process, but it can be catalyzed by iodide ion. The iodide ion acts as a catalyst by lowering the activation energy required for the reaction to occur.

During the reaction, the iodide ion is oxidized to form iodine, which then reacts with hydrogen peroxide to form water and oxygen. The iodine can then react with more hydrogen peroxide to continue the reaction.

The concentration of the catalyst, iodide ion, affects the rate of the reaction. An increase in the concentration of the iodide ion will increase the rate of the reaction, as there will be more catalyst available to facilitate the reaction. Conversely, a decrease in the concentration of the iodide ion will slow down the rate of the reaction.

However, once the reaction has finished, the concentration of the catalyst will remain the same. This is because the catalyst is not consumed in the reaction and can be used again in subsequent reactions. Therefore, the concentration of the catalyst will remain constant as long as there is enough iodide ion present to catalyze the reaction.

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The correct formula that can be used to determine the partial pressure of nitrogen gas (\(N_2\)) in the mixture from the total pressure of the mixture and the partial pressures of the other two gases is: Partial Pressure of \(N_2\)= Total Pressure - Partial Pressure of \(H_2\)- Partial Pressure of He

In a mixture of gases, each gas contributes to the total pressure of the system independently. According to Dalton's Law of Partial Pressures, the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of each individual gas.

In this case, the partial pressure of nitrogen gas (\(N_2\)) can be obtained by subtracting the partial pressures of the other two gases (\(H_2\)and He) from the total pressure of the mixture.

For example, if the total pressure of the mixture is given as P_total, and the partial pressures of hydrogen gas (\(H_2\)) and helium gas (He) are given as P_\(H_2\) and P_He, respectively, the formula can be applied as follows:

Partial Pressure of \(N_2\)= P_total - P_\(H_2\) - P_He

By using this formula, we can determine the partial pressure of nitrogen gas in the mixture based on the provided information about the total pressure and the partial pressures of the other gases.

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The specific values of EL, EC, and ER will determine the precise behavior of the system and the probabilities of the electron being in each state over time.

To study the time evolution in this three-state system, we can write down the Hamiltonian matrix for the system.

The Hamiltonian describes the energy of the system and the transitions between different states. In this case, we have three states ∣L⟩, ∣C⟩, and ∣R⟩.

The Hamiltonian matrix can be written as:

H = [[EL 0 EC],

[0 EC 0],

[EC 0 ER]]

Here, EL represents the energy of state ∣L⟩, EC represents the energy of state ∣C⟩, and ER represents the energy of state ∣R⟩.

Since the electron can hop between the carbon atom and the oxygen atoms, we have nonzero off-diagonal elements in the Hamiltonian.

To solve for the time evolution of the system, we can find the eigenvalues and eigenvectors of the Hamiltonian matrix.

The eigenvectors represent the energy eigenstates of the system, and the eigenvalues represent the corresponding energies.

Once we have the energy eigenstates, we can determine the probabilities of the electron being in each state at a given time by calculating the time evolution of the initial state.

The specific values of EL, EC, and ER will determine the precise behavior of the system and the probabilities of the electron being in each state over time.

It is worth noting that the problem statement doesn't provide explicit values for EL, EC, and ER, so further information is needed to obtain a more detailed analysis of the time evolution in this three-state system.

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Answer:

Total we want 48 titanium to make 12.0moles

According to the research, a nuclear reaction releases less energy per gram and appears to violate the law of conservation of mass.

It is a procedure that leads to combining and modifying the nuclei of atoms and subatomic particles and appears to violate the law of conservation of mass.

Through this kind of process, the nuclei can be combined or fragmented, absorbing or releasing particles and energy according to each case.

Therefore, we can conclude that according to the research, a nuclear reaction releases less energy per gram and appears to violate the law of conservation of mass.

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To calculate the work done on the gas, we can use the formula:

Work (W) = -PΔV

Where:

W is the work done on the gas,

P is the constant external pressure, and

ΔV is the change in volume of the gas.

Given:

Initial volume (V1) = 4.65 L

Final volume (V2) = 6.21 L

External pressure (P) = 2.33 atm

First, we need to calculate the change in volume (ΔV):

ΔV = V2 - V1

ΔV = 6.21 L - 4.65 L

ΔV = 1.56 L

Now, we can substitute the values into the formula to calculate the work done on the gas:

W = -PΔV

W = -(2.33 atm) * (1.56 L)

Since we need the answer in joules, we need to convert atm·L to joules. The conversion factor is 101.325 J = 1 L·atm.

W = - (2.33 atm) * (1.56 L) * (101.325 J / 1 L·atm)

W = - 375.75 J

Therefore, the work done on the gas is approximately -375.75 joules. The negative sign indicates that work is done on the gas, as the volume increases under constant external pressure.

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The quantity of energy that cannot be used to perform work is measured by an object's entropy. The number of alternative arrangements that the atoms in a system can have is also measured by entropy. Entropy is a measure of uncertainty or unpredictability in this sense.

a. ne(s,−250°c)⟶ne(s,−273°c)

In the above situation, the pressure remains constant while the temperature rises. Additionally, the neon is still solid. Since molecular movements and temperature are inversely proportional. The mobility of solid molecules will increase with temperature. Thus, the entropy starts to rise in this situation as well.

b.o2(g,300k)⟶o2(g,800k).

In the above situation, the pressure remains constant while the temperature rises. Additionally, oxygen is still in a gaseous condition. Since molecular movements and temperature are inversely proportional. The mobility of gaseous molecules will increase with temperature. Thus, the entropy starts to rise in this situation as well.

c. n2(I, 75 K) -----> n2(g, 100k)

In the reaction described, liquid nitrogen is changed into a gaseous form. In comparison to a liquid, a gaseous molecule flows more randomly. As a result, nitrogen's entropy will rise in its gaseous state.

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Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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Reverse direction: Reaction is not spontaneous; reactants favored at 25°C.

To calculate ΔS°rxn, we can use the following equation:

ΔG°rxn = -RTlnK

where R is the gas constant (8.314 J/mol*K), T is the temperature in Kelvin (298 K), K is the equilibrium constant, and ΔG°rxn is the standard Gibbs free energy change for the reaction.

Since ΔG°rxn = ΔH°rxn - TΔS°rxn, we can rearrange the equation as:

ΔS°rxn = (ΔH°rxn - ΔG°rxn) / T

We are given ΔH°rxn as -44.2 kJ, so we need to calculate ΔG°rxn and then use the equation above to find ΔS°rxn.

To calculate ΔG°rxn, we can use the following equation:

ΔG°rxn = ΣnΔG°f(products) - ΣnΔG°f(reactants)

where ΔG°f is the standard Gibbs free energy of formation of each compound, n is the number of moles of each compound in the balanced chemical equation, and the values are given in the table of thermodynamic properties.

For the given reaction, the equation becomes:

ΔG°rxn = [ΔG°f(C2H5OH) - ΔG°f(C2H4) - ΔG°f(H2O)] = [-277.6 - (2*68.3) + (-237.1)] = -39.9 kJ

Now we can substitute the values we have calculated into the equation for ΔS°rxn:

ΔS°rxn = (-44.2 kJ - (-39.9 kJ)) / (298 K) = -0.014 J/K

Since ΔS°rxn is negative, the reaction is not spontaneous at 25°C and standard pressure in the direction as written. However, we can use the Gibbs free energy equation to determine in which direction the reaction will be spontaneous:

ΔG°rxn = -RTlnK

For a spontaneous reaction, ΔG°rxn must be negative, which means that lnK must be negative. Since lnK is negative, K must be less than 1, which means that the reactants are favored at equilibrium. Therefore, the reaction will proceed in the reverse direction as written (i.e. from C2H5OH to C2H4 and H2O) at 25°C and standard pressure.

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Answer:The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotope).

Explanation:try to find what i ment and  think you will get the answer

Answer:

I think the answer is b or d

Explanation:

I THINK IS THE KEY WORD HERE

Answer:

The hydroxide ion concentration in an aqueous solution, [OH-], in mol L-1, can be calculated if the pOH of the solution is known.

pOH is defined as the negative logarithm (to base 10) of the hydroxide ion concentration in mol L-1 pOH = -log10[OH-]

Explanation:

The intermolecular forces are in the solid NaCl salt is ion - ion forces or the dipole - dipole forces of the interaction.

The Na is the metal and is capable of the donating the electrons and the Cl is the non metal and have capability of accepting the electrons. This makes the Na to form the cation and the Cl to make the anion. The dipole - dipole forces are present in the molecule which contains the oppositely charged ions one is positively charged ion and the other is the negatively charged ion.

Thus , the NaCl solid has the ion - ion intermolecular forces of the interaction .

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Unsaturated solution: a solution in which more solute can be dissolved.

Explanation:

Salt dissolved in water or even sugar dissolved in water is an unsaturated solution if the quantity of dissolved salt/sugar is below the saturation point.

unsaturated solution: a solution in which more solute can be dissolved.

Explanation:

A solution in which the maximum amount of solvent has been dissolved. Any more solute added will sit as crystals on the bottom of the container.

To write the isotope symbol for a radioisotope, we need to include the atomic number and the mass number. The atomic number represents the number of protons in the nucleus of an atom and is denoted by the letter Z.

The mass number represents the total number of protons and neutrons in the nucleus and is denoted by the letter A. for example, let's say we have a radioisotope with 7 protons and 9 neutrons. The atomic number is 7 (since there are 7 protons) and the mass number is 16 (since there are 7 protons and 9 neutrons). The isotope symbol for this radioisotope would be:
X-16
7
where X represents the element symbol (in this case, nitrogen) and 16 represents the mass number. The number 7 is written as a proper integer because it represents the atomic number to write the isotope symbol for other radioisotopes, we would need to know their atomic number and mass number. By including these numbers in the isotope symbol, we can uniquely identify each radioisotope.

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13.29 X \(10^{21}\) moles of NaCl are in a pinch of salt and a pinch of salt has

approximately 3.29x\(10^{21}\) formula units of NaCl.

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is “mol”.

We know that 1 formula unit of sodium chloride has a molar mass of 58.44g/mol

Hence;

Mass of 1 formula unit = 58.44g

Mass of 3.29 x \(10^{21}\) formula units

13.29 x \(10^{21}\) x 58.44g

776.6676 x \(10^{21}\)

Moles =\(\frac{776.6676 X 10^{21} }{ 58.44g}\)

Moles = 13.29 X \(10^{21}\)

Therefore;

13.29 X \(10^{21}\) moles of NaCl are in a pinch of salt.

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methane

Which molecule has a tetrahedral arrangement of electron pairs but is not a tetrahedral molecule? methane