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The products of the following single replacement reaction, Zn + HNO3 = Zn(NO3)2 + H2, are zinc nitrate and hydrogen gas.

Single replacement reaction: A single-replacement reaction happens when an element trades places with another element in a compound. The new element goes into the compound, and the old element is thrown out. Zinc (Zn) is more active than hydrogen (H), so it replaces hydrogen in HNO3, resulting in the formation of zinc nitrate and hydrogen gas.

The balanced chemical equation for the reaction is: Zn + HNO3 → Zn(NO3)2 + H2 Hence, the products of the following single replacement reaction, Zn + HNO3 = Zn(NO3)2 + H2, are zinc nitrate and hydrogen gas.

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Answer:

palisade cell due to presence of chloroplasts

Answer:

Letter B.

Explanation:

Changing its direction and climbing a steep incline can't be proven only by the graph info. You can see that it's speed isn't constant in the graph.

We have letter B left.

Explanation:

When a base dissolves in water it is an alkali and makes an alkaline solution.

...

Litmus.

Red Litmus Blue Litmus

Acidic solution Stays red Turns red

Neutral solution Stays red Stays blue

Alkaline solution Turns blue Stays blue

Answer:

CH4

Explanation:

The number of moles of carbon and hydrogen has been given as follows:

C = ​0.300 mol​ ​

H = ​1.20 mol

Next, we divide each mole value by the smallest (0.300)

C = 0.300 ÷ 0.300 = 1

H = 1.20 ÷ 0.300 = 4

The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4

The process of breathing involves exchanging oxygen for carbon dioxide gas.

The process of breathing involves inhalation and exhalation.

Inhalation is the process of taking in oxygen and Exhalation is the process of taking out carbon dioxide. Air contains 21 % oxygen and 71 % nitrogen and 8 % other gases.

When we breathe in(inhalation) our diaphragm contracts downward while during breath out(exhalation) our diaphragm contracts upward. As food and water are important for us in similar way breathing is also essential for life.

So during the process of breathing, we take in oxygen and take out carbon dioxide.

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If Magnesium-21 undergoes beta position decay, I would expect the products of this decay to be a positron and a Sodium-21. Thus, option B is correct. Here is an explanation to support the answer.

The beta-positive decay is also known as a positron emission. In this process, the nucleus of an atom emits a positron and turns into a different element. A positron is an antiparticle of the electron, which is positively charged. When a positron is emitted, it carries a positive charge with it, which means that the atomic number of the nucleus changes as a result of this decay.

Magnesium-21 is an unstable isotope that can undergo positron emission. When it undergoes this decay, it emits a positron and turns into sodium-21. The balanced equation for the decay of Magnesium-21 can be written as follows:Mg-21 → Na-21 + e+

Thus, the correct answer to this question is option B, Sodium-21.

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a) Compound (A) can be converted into butane through hydrogenation, undergoes decomposition at high temperatures through pyrolysis,  b) and can be prepared from Kolbe's electrolysis by obtaining the alkene or alkyne as an intermediate product. c) The specific reaction conditions and mechanisms would depend on the particular structure and properties of compound (A).

a. To convert compound (A) into butane, we need to add two more carbon atoms to the unsaturated hydrocarbon.

This can be achieved through a process called hydrogenation, where compound (A) reacts with hydrogen gas (H2) in the presence of a suitable catalyst, such as palladium (Pd), to form butane. The reaction can be represented as follows:

Compound (A) + 2H2 -> Butane

b. When compound (A) is passed through a red-hot copper tube at 400°C, it undergoes a process called pyrolysis or thermal cracking. This process involves the breaking of chemical bonds within the compound due to the high temperature.

As a result, compound (A) decomposes into smaller fragments, including alkenes and alkynes, which are unsaturated hydrocarbons. The specific products obtained will depend on the structure of compound (A) and the conditions of the reaction.

c. Compound (A) can be prepared from Kolbe's electrolysis, which involves the electrolysis of a dilute solution of sodium or potassium salt of a carboxylic acid.

During the process, the carboxylic acid undergoes decarboxylation, where a carbon dioxide molecule is removed, resulting in the formation of an alkene or alkyne. These unsaturated hydrocarbons can be the starting material for the synthesis of compound (A) through subsequent reactions.

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(a) Using the ideal gas law, the pressure in the flask is approximately 11.43 atm.

(b) Using the van der Waals equation, the pressure in the flask is approximately 9.44 atm.

(c) There is a difference between the pressures because the van der Waals equation accounts for the volume of the molecules and the attractive and repulsive forces between them.

(d) The correction for the volume of the molecules is more significant than the correction for the attractive forces between molecules because the volume correction is proportional to the amount of gas. Since the amount of gas is relatively small compared to the square of the amount of gas, the correction for the volume of the molecules is more significant.

a) The ideal gas law is PV = nRT. Here, P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Using the ideal gas law:

PV = nRTP = (nRT)/V

Where,

P = Pressure of CO₂

n = Number of moles of CO₂

V = Volume of CO₂

T = Temperature of CO₂

R = Gas constant = 0.08206 L-atm/mol-K (This value can be converted to other units based on the unit of pressure, volume, and temperature used in the problem)

Substitute the values into the formula:

P = (0.467 mol * 0.08206 L-atm/mol-K * (159°C + 273.15)) / 0.245 L

P = 11.43 atm (approximately)

b) The van der Waals equation is given as (P + an²/V²)(V - nb) = nRT, where a and b are constants based on the properties of the gas being used. Since CO₂ is a gas composed of polar molecules, the van der Waals constant, "a," is nonzero, while the van der Waals constant, "b," accounts for the size of the gas molecules and is also nonzero for CO₂.

Using the van der Waals equation:

(P + an²/V²)(V - nb) = nRT

Solve for P. The value of a and b are 3.59 L²-atm/mol² and 0.0427 L/mol, respectively. Plug in the given values:

P = (nRT/(V - nb)) - (an²/V²)(a)

P = ((0.467 mol * 0.08206 L-atm/mol-K * (159°C + 273.15 K))/(0.245 L - (0.0427 L/mol * 0.467 mol))) - ((3.59 L²-atm/mol² * 0.467 mol²)/(0.245 L)²)(b)

P = 9.44 atm (approximately)

c) The van der Waals equation is an improvement over the ideal gas law because it accounts for the volume of the molecules and the attractive and repulsive forces between them that become significant at high pressures and low temperatures. At low pressures and high temperatures, the ideal gas law works well since the forces between molecules are negligible and the volume of the molecules is relatively small. However, at high pressures and low temperatures, the volume of the molecules and the attractive forces between them become significant, resulting in the deviation of gases from ideal behavior.

d) In this case, the correction for the volume of the molecules (represented by "b") is more significant than the correction for the attractive forces between molecules (represented by "a"). This is because the volume correction is proportional to the amount of gas, while the correction for the attractive forces is proportional to the square of the amount of gas. Since the amount of gas is relatively small compared to the square of the amount of gas, the correction for the volume of the molecules is more significant.

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Hello! HNO2 is not a strong acid so therefore your answer is A.

A rule of thumb, the rest are strong acids, so when you ever come across a similar question you will be able to rule out the wrong answers quicker :).

Strong acid list:

H2SO4

HNO3

HCLO4

HCLO3

HCL

HBr

HI

hope this helps!

The difference between 8.1456 - 5.12 will be 3.0256 and rounding it off will give 3.

It should be noted that the information given is that we should subtract 5.12 from 8.1456.

It should be noted that subtraction is used when we want to deduct a number from another number. It is taking away a number form another one.

In this case, we will take away 5.12 from 8.1456. This will give the difference between the numbers.

Therefore, 8.1456 - 5.12 = 3.0256

Therefore, the difference is 3.0256 and rounding it appropriately will give a value of 3.

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Answer:

The ionisation energy increases.

Explanation:

This is because the force of attraction between the electrons and the positive nucleus will increase

Solids are the most organized state of matter. States of matter change when energy is added or removed. Gas is the state of matter has the most movement of its particles.

The states of matter are the different forms of the matter in which it can exist. They are solids, liquids and gases. Solids are the states of matter in which molecules are very near to each other. They have fixed shape and volume. Liquids is the states of matter in which molecules are a little far from each other. They have different shape and fixed volume. Gas is the states of matter in which molecules are a very far from each other. They have different shape and different volume.

There are two more states of matter which are called as Plasma, Bose Einstein Condensate.

Plasma have highest energy and Bose Einstein Condensate have lowest energy.

Therefore, Solids are the most organized state of matter. States of matter change when energy is added or removed. Gas is the state of matter has the most movement of its particles.

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The equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) can be calculated using the expression K= [HI]2/([H2][I2]). Since the concentrations of H2, I2, and HI are given in the question, we can calculate the equilibrium constant, K, for the reaction.

K = [HI]2/([H2][I2]) = (1.77 × 10-2)2/((1.83 × 10-3)(3.13 × 10-3)) = 4.43 × 104. Therefore, the equilibrium constant, K, for the reaction H2(g) + I2(g) ⇄ 2HI(g) at 425°C is 4.43 × 104.

Using the specified concentrations of H2, I2, and HI, it appears that you have correctly calculated the equilibrium constant, K, for the reaction H2(g) + I2(g) 2HI(g) at 425°C. The ratio of the concentrations of the reactants and products at equilibrium, K, is represented by each concentration being raised to the power of its stoichiometric coefficient.

The concentration of the product, HI, is preferred above the concentrations of the reactants, H2 and I2, at equilibrium, as shown by the value of K = 4.43 104 in this instance. This suggests that at equilibrium, the forward reaction—the creation of HI—is preferred.

It is significant to remember that the equilibrium constant, K, is temperature-dependent, and that temperature changes affect K's value.

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a. The final temperature is 29.9°C.

b. The temperature change of the copper is 69°C.

c. The temperature change of the water is 1.7°C.

d. The energy absorbed by the water is 1892.67 J

a. To find the final temperature, we can use the principle of conservation of energy, which states that the heat lost by the copper will be gained by the water and calorimeter. The equation we can use is:

heat lost by copper = heat gained by water + heat gained by calorimeter

The heat lost by the copper can be calculated using the equation:

Q = mcΔT

where Q is the heat lost, m is the mass of copper, c is the specific heat capacity of copper, and ΔT is the change in temperature.

Q = (104 g) * (0.385 J/g°C) * (98.9°C - T)

The heat gained by the water and calorimeter can be calculated using the equation:

Q = (m_water + m_calorimeter) * c_water * ΔT

where m_water is the mass of water, m_calorimeter is the mass of the calorimeter, c_water is the specific heat capacity of water, and ΔT is the change in temperature.

Q = (63 g + 2 g) * (4.19 J/g°C) * (T - 22°C)

Setting the two equations equal to each other and solving for T, we get:

(104 g) * (0.385 J/g°C) * (98.9°C - T) = (63 g + 2 g) * (4.19 J/g°C) * (T - 22°C)

Simplifying and solving for T, we get:

T = 29.9°C

Therefore, the final temperature is 29.9°C.

b. The temperature change of the copper can be calculated using the equation:

ΔT = (Q / (m * c))

where Q is the heat lost by the copper, m is the mass of copper, and c is the specific heat capacity of copper.

ΔT = (104 g) * (0.385 J/g°C) * (98.9°C - 29.9°C) / (104 g * 0.385 J/g°C)

ΔT = 69°C

Therefore, the temperature change of the copper is 69°C.

c. The temperature change of the water can be calculated using the equation:

ΔT = (Q / ((m_water + m_calorimeter) * c_water))

where Q is the heat gained by the water and calorimeter, m_water is the mass of water, m_calorimeter is the mass of the calorimeter, and c_water is the specific heat capacity of water.

ΔT = ((63 g + 2 g) * (4.19 J/g°C) * (29.9°C - 22°C)) / ((63 g + 2 g) * (4.19 J/g°C))

ΔT = 1.7°C

Therefore, the temperature change of the water is 1.7°C.

d. The energy absorbed by the water can be calculated using the equation:

Q = (m_water * c_water * ΔT)

where m_water is the mass of water, c_water is the specific heat capacity of water, and ΔT is the temperature change of the water.

Q = (63 g) * (4.19 J/g°C) * (29.9°C - 22°C)

Q = 1892.67 J

Therefore, the energy absorbed by the water is 1892.67 J.

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The quantum numbers for the electron removed to form the Cu²⁺ ion are: n=4, l=1, ml=-1, ms=+1/2.

When a copper atom (Cu) loses one electron to form the Cu²⁺ ion, we can determine the quantum numbers of the removed electron based on the rules governing electron configurations.

The principal quantum number (n) represents the energy level of the electron. In this case, the electron is being removed from a copper atom, which has an electron configuration of [Ar] 3d¹⁰ 4s¹. Since the electron is being removed from the 4s orbital, the principal quantum number is n=4.

The azimuthal quantum number (l) specifies the orbital shape. The 4s orbital has l=0, and the 3d orbital has l=2. Since the electron being removed is from the 4s orbital, the azimuthal quantum number is l=0.

The magnetic quantum number (ml) determines the orientation of the orbital. Since the 4s orbital has only one orientation, ml can be either -1 or +1. In this case, ml=-1.

The spin quantum number (ms) describes the spin state of the electron. It can be either +1/2 or -1/2. The removed electron has a spin state of +1/2.

Therefore, the quantum numbers for the electron removed to form the Cu²⁺ ion are n=4, l=1, ml=-1, and ms=+1/2.

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4 liters of the 70% solution are required by the chemist.

8 liters of saline solution divided by 25%

Saline solution at 25% = 0.25 x 8 = 2 liters

Let there be x liters of saline solution at 70%.

Salt = 8 plus x

40% of salt is equal to 25% of saline solution plus 70% of saline solution.

2 + (70/100)x = (40/100)(8 + x)

2 + 0.7x = 0.4(8 + x)

2 + 0.7x = 3.2 + 0.4x

0.7x - 0.4x = 3.2 - 20.3

x = 1.2

x = 1.2 / 0.3

x = 4

4 liters of the 70% solution are required by the chemist.

The following equation can be used to determine the volume or concentration of a concentrated or diluted solution: M1V1 = M2V2.

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Tetrachloroethylene is a liquid that has been commonly used in the process of dry cleaning. However, it is now being phased out due to its potential to cause cancer.

Tetrachloroethylene, also known as perchloroethylene or "perc," is a colorless liquid that is primarily used as a solvent in dry cleaning. It is effective at removing grease, oil, and other stains from fabrics. However, it has been found to have carcinogenic properties, meaning it has the potential to cause cancer in humans.

The International Agency for Research on Cancer (IARC) has classified tetrachloroethylene as a Group 2A carcinogen, which means it is probably carcinogenic to humans. It has been associated with an increased risk of various types of cancer, including bladder, esophageal, and cervical cancer. In summary, tetrachloroethylene is a liquid used in dry cleaning that is being phased out due to its potential to cause cancer.

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The first set of quantum numbers is invalid. According to the quantum number rules, the principal quantum number (n) must be a positive integer greater than zero. However, in this set, the principal quantum number is listed as -3, which violates this rule. Additionally, the azimuthal quantum number (l) should be an integer ranging from 0 to (n-1), but in this set, it is given as 2, which is outside the allowed range. The magnetic quantum number (m_l) should also be an integer ranging from -l to +l, but in this set, it is given as -3, which exceeds the allowed range for the given azimuthal quantum number.

The second set of quantum numbers is valid. The principal quantum number (n) is listed as 4, which satisfies the rule that it should be a positive integer greater than zero. The azimuthal quantum number (l) is given as 2, which is within the allowed range of values (0 to n-1). The magnetic quantum number (m_l) is listed as -1, which also falls within the acceptable range of values (-l to +l) for the given azimuthal quantum number.

In summary, the first set of quantum numbers is invalid due to violations of the rules regarding the principal quantum number, the azimuthal quantum number, and the magnetic quantum number. On the other hand, the second set of quantum numbers is valid as it adheres to the rules for each quantum number.

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Answer:

protons have a positive, neutrons have no charge and electrons have a negative chage

Explanation:

Answer:

Protons have a positive charge

Explanation:

Electrons have a negative charge and neutrons are neutral

Answer:

correct answer is d)

Explanation:

This answer demonstrates law of conservation of mass because the mass of the products is equal to the mass of reactants with the help of the coefficients which is the process known as balancing. This answer also includes the correct formulas, as Br is a gas so it MUST be written as Br2. hope this helps:)

2Al(s) + 3Br2(1) - 2AlBr3(s) is the  correct formulas and demonstrates conservation of mass.

Every action has an equal and opposite response, states Newton's Third Law. This indicates that any force applied to an item will have an equal and opposite-directed response force of the same magnitude. A force pair is the collective name for these connected forces.

Each individual object will have a different force pair with each other object in systems of numerous objects where all things interact. In the case of charged particles, the charge of each object will dictate the direction of each force in the force pair.

Similar charges will cause particles to repel one another by directing their forces away from one another. With their forces pointing in the same direction, particles with opposing charges attract one another.

Therefore, 2Al(s) + 3Br2(1) - 2AlBr3(s) is the  correct formulas and demonstrates conservation of mass.

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Answer:

Addition

Explanation:edg 2020

Answer:

The correct answer is A.

Explanation:

Edge 2022

Muhammad Ali is a professional boxer and American activist. He is known as "The Greatest" and is regarded as one of the greatest sports stars of all time.

Ali famously said, "I am the greatest!" after defeating the much favoured Sonny Liston in six rounds on February 25, 1964, to win the heavyweight title.

He became a Muslim in 1961. He won the heavyweight world championship by defeating Sonny Liston on February 25, 1964, when he was only 22 years old. He considered to his old name as a "slave name" and changed it to Muhammad Ali that year.

The first heavyweight championship battle, for the WBC/Ring/Lineal title, was on November 22, 1965, and the second, for the North American Boxing Federation (NABF) heavyweight title, happened on September 20, 1972.

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Vertical and horizontal movement caused by the expansion of freezing water are called as frost heaving and frost thrusting.

These phenomena occur when water within the soil or porous materials freezes, causing it to expand and exert pressure on its surroundings.

Frost heaving refers to the upward movement of the ground or other materials due to the expansion of freezing water. When water freezes, it forms ice crystals that push and lift the soil or material above it. This upward movement can result in the displacement of rocks, pavement, or structures. Frost heaving is commonly observed in regions with freezing temperatures and moisture in the ground.

Frost thrusting, on the other hand, involves the horizontal movement of objects or structures caused by the expansion of freezing water. When water freezes and expands, it exerts pressure against barriers or structures in its path, causing them to shift horizontally. This can lead to the displacement of objects, damage to underground utilities, or deformation of structures.

Both frost heaving and frost thrusting can have significant impacts on infrastructure, including roads, buildings, and pipelines. The expansion of freezing water can exert considerable force, leading to the deformation, cracking, or destruction of materials. These processes are particularly prevalent in areas with fluctuating freeze thaw cycles, where the repeated formation and melting of ice can exacerbate the movement.

To mitigate the effects of frost heaving and frost thrusting, various engineering techniques can be employed. These may include proper insulation of structures, installation of frost barriers or insulation layers in the ground, and the use of flexible or frost-resistant materials in construction. By understanding these processes and implementing appropriate measures, it is possible to minimize the adverse impacts of freezing water expansion on infrastructure and maintain the stability of the surrounding environment.

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Answer:

Explanation:

Electron Configuration - [Ne] 3s² 3p⁵

Orbital Notation - Can't type that out, please see the image.

The carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burns hydrogen to helium in their cores.

In high-mass main-sequence stars, such as massive stars with a mass greater than about 1.5 times that of the Sun, the primary nuclear reaction that powers their cores is the carbon-nitrogen-oxygen (CNO) cycle. This cycle converts hydrogen nuclei (protons) into helium nuclei (alpha particles) through a series of fusion reactions.

The CNO cycle involves the catalytic action of carbon, nitrogen, and oxygen isotopes. In the first step of the cycle, a proton fuses with a carbon-12 nucleus to produce nitrogen-13 and release a gamma ray. Nitrogen-13 then undergoes beta decay, converting a proton into a neutron and transforming into carbon-13. Carbon-13 can capture another proton, forming nitrogen-14. Nitrogen-14 can further undergo fusion reactions with other protons to produce oxygen-15 and eventually return back to carbon-12, completing the cycle.

Overall, the CNO cycle allows high-mass main-sequence stars to convert hydrogen into helium, releasing energy in the process and sustaining the star's energy production.

What elements does the carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burn in their cores?

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Cofactor most commonly known for its ability to bind to oxygen, iron also plays the important role of acting as a to many enzymes in numerous oxidation-reduction reactions.

Chemical processes occur when atoms form or break chemical bonds. The molecules that start a chemical are known as reactants, and the compounds which are generated as the result of reaction are known as products.

A physical response is a reaction that modifies the physical characteristics of an item or material Physical characteristics encompass items like mass, volume, etc density.

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The Ea of the forward reaction is 297.5 kJ/mole. The E of the products is 33.6 kJ/mole LOWER than that of the reactants, hence the negative value. Thus, the Ea of the reverse reaction requires 33.6 kJ/mole to get back to the starting point and then an additional 297.5 kJ/mole to reach the threshold. Total = 331.1 kJ/mole.

Chemical reaction is the process by which one or more compounds, known as reactants, change into one or more new ones, known as products. Chemical components or compounds make up substances. The atoms that make up the reactants are rearranged in a chemical reaction to produce various products.

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the answers to the questions based on the element sodium:

Is it metal? - Yes

Is it a non-metal? - No

Is it gas at room temperature? - No

Is it a solid at room temperature? - Yes

Is it a liquid at room temperature? - No

Is it in the first row (period) of the periodic table? - No

Is it in the second row (period) of the periodic table? - Yes

Is it in the third row (period) of the periodic table? - No

Is it in the fourth row (period) of the periodic table? - No

Is it in the fifth row (period) of the periodic table? - No

Is it in the sixth row (period) of the periodic table? - No

Is it in the seventh row (period) of the periodic table? - No

Is it in the eighth row (period) of the periodic table? - No

Is it a noble gas? - No

Is it a halogen? - No

Is it an alkali metal? - Yes

Is it an alkaline earth metal? - No

Is it a transition metal? - No

Does its symbol start with the letter "C"? - No

Does it have an atomic number greater than 50? - No (Sodium has an atomic number of 11)

Periodic Table 20 Questions" is a game where one player thinks of an element from the periodic table, and the other player asks up to 20 yes or no questions to guess the element.

The questions are usually related to the element's properties, such as its atomic number, symbol, group, or period, as well as its physical and chemical characteristics.

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the question is incomplete. complete question is

The element is sodium(Na)

Is it metal? - Yes or No

Is it a non-metal? - Yes or No

Is it gas at room temperature? - Yes or No

Is it a solid at room temperature? - Yes or No

Is it a liquid at room temperature? - Yes or No

Is it in the first row (period) of the periodic table? - Yes or No

Is it in the second row (period) of the periodic table? - Yes or No

Is it in the third row (period) of the periodic table? - Yes or No

Is it in the fourth row (period) of the periodic table? - Yes or No

Is it in the fifth row (period) of the periodic table? - Yes or No

Is it in the sixth row (period) of the periodic table? - Yes or No

Is it in the seventh row (period) of the periodic table? - Yes or No

Is it in the eighth row (period) of the periodic table? - Yes or No

Is it a noble gas? - Yes or No

Is it a halogen? - Yes or No

Is it an alkali metal? - Yes or No

Is it an alkaline earth metal? - Yes or No

Is it a transition metal? - Yes or No

Does its symbol start with the letter "C"? - Yes or No

Does it have an atomic number greater than 50? - Yes or No