persimmon and bitter gourd are bitter why?​

Answer:

D. Electric and solar

Answer:

Gasoline and Electric

Explanation:

Quite simply, a hybrid combines at least one electric motor with a gasoline engine to move the car, and its system recaptures energy via regenerative braking. Sometimes the electric motor does all the work, sometimes it's the gas engine, and sometimes they work together.

The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.

The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.

The equation of the reaction is given below:

\(CuSO_4 + Fe \rightarrow FeSO_4 + Cu\)

The mole ratio of both reactants and product is 1 : 1

molar mass of copper sulfate = 160 g

molar mass of Cu = 64

molar mass of iron = 56 g

moles of Cu in 1.5 g = 1.5/64 = 0.00234

mass of iron required = 0.00234 × 56 = 1.31 g of iron

Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.

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The compound with molecular formula C H200 that exhibits the following 'H NMR spectrum is likely an alkane with a chain of 200 carbon atoms.

The peaks in the spectrum correspond to the different hydrogen atoms in the alkane chain. Specifically, the peak at 1.17 ppm is from the methyl group, the peak at 1.30-1.35 ppm is from the primary hydrogen atoms and the peak at 1.80-2.00 ppm is from the secondary hydrogen atoms.

The peak at 3.7-3.9 ppm is from the tertiary hydrogen atoms and the peak at 4.50-5.00 ppm is from the quaternary hydrogen atoms. The broad peak at around 3.2 ppm is due to the methylene hydrogens.

Alkanes consist of a single carbon-carbon bond, and when the molecular formula is C H200, it is likely an alkane with a chain of 200 carbon atoms.

The peak at 1.17 ppm is due to the methyl group, the peak at 1.30-1.35 ppm is due to the primary hydrogen atoms, the peak at 1.80-2.00 ppm is due to the secondary hydrogen atoms, the peak at 3.7-3.9 ppm is due to the tertiary hydrogen atoms and the peak at 4.50-5.00 ppm is due to the quaternary hydrogen atoms.

The broad peak at around 3.2 ppm is due to the methylene hydrogens. NMR spectroscopy is a powerful technique used to identify different chemical compounds and determine their structure.

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The medication can treat people who have the disease described. According to the commercial, the drug has FDA approval to treat a condition whose symptoms are listed.

Additionally, the narrator notes that the medication only comes with a prescription and has 1% of the active substance. We can deduce from this information that the drug can effectively treat persons who have the condition generating these symptoms, but obtaining it requires a prescription. The commercial provides no support for the other possibilities.

Therefore, the correct option is D.

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Answer:

Same i have headaches daily, maybe from infections such as meningitis or Intracranial pressure that's either too high or too low or id.k.

Answer:

180.155 g

Explanation:

True. It would take more energy to boil water( which is polar) than to boil a liquid made of non-polar molecules.

Thus we can conclude that it takes more energy to boil water than to boil a liquid made of non-polar molecules.

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The percent composition of Hg in the compound is approximately 49.94%.

To find the percent composition of Hg in the compound, we need to calculate the molar masses of Hg and the compound and then use the mass of Hg to determine its percentage.

The molar mass of Hg (mercury) is approximately 200.59 g/mol.

First, we need to determine the number of moles of Hg and Br in the compound:

Moles of Hg = mass of Hg / molar mass of Hg

= 60.2 g / 200.59 g/mol

= 0.2997 mol

Moles of Br = mass of Br / molar mass of Br

= 24.0 g / 79.90 g/mol

= 0.3004 mol

Next, we can calculate the percent composition of Hg in the compound:

Percent composition of Hg = (moles of Hg / total moles of the compound) x 100

= (0.2997 mol / (0.2997 mol + 0.3004 mol)) x 100

= 49.94%

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sound waves travel faster in solids than in liquids, and faster in liquids than in gasses. While the density of a medium also affects the speed of sound, the elastic properties have a greater influence on the wave speed.

hope this helped

Answer:

B. melting of ice caps

Explanation:

Explanation:

P_H

and

li_n

hope it helps

A chemist counts the quantity of mercury present in sediment samples collected from three different riverbanks (the source, the midway point, and the mouth).

A scientist who has received training inside the study of chemistry is known as a chemist (from the Greek chm(a) alchemist; replacing chymist from Latin “ alchemist). Chemists look into the composition and characteristics of stuff.

A pharmacist is a medical professional who helps prepare, controls, formulates, preserves, distributes, and advises and guides the general public on the proper use of medications to achieve maximum results. They are also referred to as chemists (Commonwealth English), druggists (North American, and, archaically, Commonwealth English) and chemists (Commonwealth English).

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The rate at which the volume is changing, represented as dV/dt, is given by the equation (0.4155 - 0.32V(t)) / 16, where V(t) is the volume, and the values are substituted accordingly.

To find the rate at which the volume is changing, we need to differentiate the given equation with respect to time (t) using the chain rule:

PV = 8.31T

Differentiating both sides with respect to time:

P(dV/dt) + V(dP/dt) = 8.31(dT/dt)

We are given:

dT/dt = 0.05 K/s (rate of temperature change)

(dP/dt) = 0.02 kPa/s (rate of pressure change)

P = 16 kPa (initial pressure)

T = 295 K (initial temperature)

Substituting the given values into the equation, we have:

16(dV/dt) + 16V(0.02) = 8.31(0.05)

Simplifying the equation:

16(dV/dt) + 0.32V = 0.4155

Rearranging the equation to solve for dV/dt:

16(dV/dt) = 0.4155 - 0.32V

(dV/dt) = (0.4155 - 0.32V) / 16

To find the rate at which the volume is changing when T = 295 K, we substitute V = V(t) and T = 295 into the equation:

(dV/dt) = (0.4155 - 0.32V(t)) / 16

Calculating the value of (dV/dt) at the given temperature and rounding to at least 4 decimal places will provide the final answer.

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The pH of each of the following solutions of a strong acid in water for (a) 0.16 M HCl is 0.78, (b) 4.4 M HClO4 is 3.35, (c) 2.31011 M HI is 10.64.

A strong acid is an acid that is completely ionized in water. Therefore, the pH of a solution of a strong acid in water can be calculated using the following formula:

pH = -log[H+]

(a) 0.16 M HCl:

= [H+]

= 0.16 M

pH

= -log(0.16)

= -(-0.78)

= 0.78

(b) 4.4 M HClO4:

[H+]

= 4.4 M

pH

= -log(4.4)

= -(0.35)

= 3.35

(c) 2.3 x 10^-11 M HI:

[H+]

= 2.3 x 10^-11 M

pH

= -log(2.3 x 10^-11)

= -(-10.64)

= 10.64

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Answer:

the volume of the gas when pressure 0.974atm is equal to 127.06ml

To buy two chocolate bars, one pack of peanuts, and a can of soda with a snack machine that only accepts 5-centavo coins, we need to Solve the Equation to calculate the total cost and the number of coins required. The answer to this question is 21 coins.

One chocolate bar costs 25 cent, so two chocolate bars cost 25 x 2 = 50 cent.One pack of peanuts costs 75 cent.A can of soda costs 50 cent.The total cost of these snacks is 50 + 75 + 50 = 175 cent.Now, we need to find how many 5-centavo coins make up 175 cent.1 centavo is equal to 0.05 cents.Therefore, 175 cent is equal to 175/0.05 = 3,500 centavos.

To find the number of 5-centavo coins required, we need to divide 3,500 by 5.3,500 ÷ 5 = 700 coins.So, it will take 700 5-centavo coins to buy two chocolate bars, one pack of peanuts, and a can of soda.

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Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.

Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)

The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).

HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1

= 1.0x10⁻⁷,

Ka2 = 1.0x10⁻¹⁹

To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.

It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.

To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0Change -x +x +x

Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹

= x² / (6.89x10⁻² - x)

Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)

Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]

x = 2.31x10⁻¹¹ M

Thus, [S²⁻] = 2.31x10⁻¹¹ M

To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0

Change -x +x +x

Equilibrium (6.89x10⁻² - x) x x

Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷

= x(6.89x10⁻² - x) / (6.89x10⁻²)

Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)

Thus: x = 1.66x10⁻⁸ M[H₃O⁺]

= 1.66x10⁻⁸ M

Then, pH = -log[H₃O⁺]

= -log(1.66x10⁻⁸)

= 7.78 (rounded to two decimal places)

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Answer:

If the earth had on Axis, there will be no seasons.

When something about the size of mars clashed with Earth about 4.5 billion years ago, it hit off a piece that became the moon.

The percent by mass of mercury in mercuric oxide is

93 %.

The molecular formula of mercuric oxide is HgO. Mercury is liquid at room temperature and readily combines with oxygen to form mercuric oxide. Mercury is represented by the symbol Hg. The mass percent is defined as the ratio of the mass of the reactant to the mass of the product into 100. When mercuric oxide undergoes decomposition, it gives mercury and oxygen. And this reaction is endothermic.

The balanced equation for the reaction of mercury oxide is,

\(2HgO (s)→ 2Hg (l) + O _{2}(g)\)

Mass of mercury oxide = 28.4 g

Mass of the oxygen = 2 g

The percent by mass of mercury in mercury oxide is,

\(Mass ℅= \frac{Mass \: of \: Mercury }{Mass \: of \: Mercury \: oxide} \times 100\)

\(= \frac{28.4 - 2}{28.4} \times 100\)

= 93 %

Therefore, the percent by mass of mercury in mercury oxide is 93 %.

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Answer:

Explanation:

A

The number of moles of water that would be produced will be 4 moles

From the balanced equation of the reaction:

2H2 + O2 ---------> 2H2O

Mole ratio of H2 and H2O = 2:1

Mole of H2 = 8 moles

Equivalent mole of H2O = 8/2

                                         = 4 moles

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Answer:

which question is it for

Q = -1776.5J  this is the Heat.

The specific heat capacity, or massic heat capacity, of a substance, is calculated using thermodynamics as the heat capacity of a sample of the substance divided by the mass of the sample.

Specific heat capacity of lead= 0. 11 j/g⁰c

Q=MCΔT

ΔT=T2-T1,

where T1=200degrees Celsius and T2=10 degree Celsius.

ΔT=10-200 = -190°C

Q = Change in energy

M = mass of a substance

C= Specific heat capacity

Q = (85g) * (0.11J/g°c) * (-190°C)= -1776.5J

Q=-1776.5J

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Answer:

134,061.9 dollars and 118,222.45 lbs.

Explanation: you're welcome :)

Answer:

capital organisation and management of natural resources and information policy

If the shot was wet and included water at the same temperature as the shot, the extra water would increase the total heat capacity of the calorimeter and reduce the temperature change measured.

A calorimeter is a device used to measure the amount of heat energy released or absorbed in a chemical reaction. It is typically a closed container that consists of two compartments, one which holds the reactants and another which captures the heat released during the reaction. The heat energy absorbed or released is calculated by measuring the temperature change of the reactants and the calorimeter itself. Calorimeters are commonly used in chemistry labs to help students better understand the concepts of heat energy and chemical reactions.

This is because the extra water would absorb some of the heat released by the shot, reducing the amount of heat available to heat up the calorimeter and its contents. Therefore, the temperature change would be smaller than if the shot were dry.

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Answer: A. Chemical energy transforms into mechanical energy.

Proof of validity is shown below.