x = 0
Simplify — x/ 2
x ((((cs•(c2))•x)-2c3sx2ot)+((co•(t2))•x))-((ta•(n2))•—) = 0 2
xtan2 ((((cs•(c2))•x)-2c3sx2ot)+((co•(t2))•x))
Equivalent Fraction:
Rewrite the whole as a fraction using 2 as the denominator :
-2c3sx2ot + c3sx + cxot2 (-2c3sx2ot + c3sx + cxot2) • 2 -2c3sx2ot + c3sx + cxot2 = 0
The equations are solved below using trigonometric identities.
What are trigonometric identities?Trigonometric identities are equalities that involve trigonometric functions and are true for every value of the occurring variables for which both sides of the equality are defined.
\(\frac{sin(x)}{1-cos(x)} -cot(x) = cosec(x) \\\\LHS= \\\\=\frac{sin(x)}{1-cos(x)} -cot(x) \\\\=\frac{sin(x)}{1-cos(x)} -\frac{cos(x)}{sin(x)}\\ \\\frac{sin^{2}(x) - (1-cos(x))cos(x) }{sin(x)(1-cos(x))}\\\\=\frac{sin^{2}(x)-cos(x) +cos^{2}(x) }{sin(x)(1-cos(x))}\\\\=\frac{1-cos(x)}{sin(x)(1-cos(x))}\\ \\=\frac{1}{sin(x)} \\\\=cosec(x)\\\\RHS=\\\\=cosec(x)\)
\(cosec(x)^{2} - 2cosec(x)cot(x) + cot(x)^{2} = tan^{2}(\frac{x}{2})\\\\LHS= \\\\= cosec(x)^{2} - 2cosec(x)cot(x) + cot(x)^{2} \\\\=( cosec(x) - cot(x) )^{2} \\\\=(\frac{1-cos(x)}{sin(x)}) ^{2}\\\\=(\frac{(1-cos(x))(1+cos(x))}{sin(x)(1+cos(x))}) ^{2}\\\\=(\frac{sin(x)^{2} }{sin(x)(1+cos(x))}) ^{2}\\\\=(\frac{sin(x) }{1+cos(x)}) ^{2}\\\\=(\frac{2sin(x/2)cos(x/2) }{1+2cos^{2}(x/2)-1}) ^{2}\\\\= (\frac{sin(x/2)cos(x/2) }{cos^{2}(x/2)}) ^{2}\\\\= tan^{2}\frac{x}{2}\\\\RHS = \\\\=tan^{2}\frac{x}{2}\)
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if there are 30 skaters competing at the olympic games, in how many different ways can the gold, silver, and bronze medals be given?
If there are 30 skaters competing at the olympic games, then the required number of ways = 24360
The term permutation refers to a mathematical calculation of the number of ways a particular set can be arranged. Put simply, a permutation is a word that describes the number of ways things can be ordered or arranged. With permutations, the order of the arrangement matters.
Given that,
There are 30 skaters competing in the competition.
To find,
The number of ways in which they can win gold, silver, and bronze medal.
So,
We can write,
In distribution of medals(gold, silver, and bronze) we require 3 winners in a particular order, so for this we use Permutations.
According to permutation , number of ways of selecting r things out of ,
n = \(\frac{n!}{(n-r)!}\)
Then, The number of ways in which 18 skaters can win 3 medals,
= \(\frac{30!}{(30-3)!}\)
= \(\frac{30!}{27!}\)
= \(\frac{30*29*28*27!}{27!}\)
= \(30*29*28\)
= 24360
Therefore,
If there are 30 skaters competing at the olympic games, then the required number of ways = 24360
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Thereisalinewhoseslopeis0andwhose y -intercept is –6 . What isitsequationin slope -intercept form? Write your answer using integers, proper fractions, and improper fractions in simplest form.
Answer:
The equation of a line with slope 0 and y-intercept -6 in slope-intercept form is \(y = -6\).
Step-by-step explanation:
From Analytical Geometry we know that equation of the line in slope-intercept form is represented by:
\(y = m\cdot x + b\) (Eq. 1)
Where:
\(x\) - Independent variable, dimensionless.
\(y\) - Dependent variable, dimensionless.
\(m\) - Slope, dimensionless.
\(b\) - y-Intercept, dimensionless.
If we know that \(m = 0\) and \(b = -6\), then the equation of the line is:
\(y = 0\cdot x +(-6)\)
\(y = -6\)
The equation of a line with slope 0 and y-intercept -6 in slope-intercept form is \(y = -6\).
Answer:
ummmmmmmmmmmmmmmmmmmmmme'[4wszmdg
Aw;3;ootgkokgm bkttmo[
q324wky
['
Step-by-step explanation:
help me answer the last question
Find the sum of the following
-50, -90 and -100
Answer:
-240
Step-by-step explanation:
Answer:
-240
Step-by-step explanation:
-50-90-100
-140-100
-240
Adding negatives is the same as subtracting.
mia made 7 trips to visit her grandmother. she walked 498.75 meters in all. how far did mia walk on each trip?
Answer: 71.25 meters
Step-by-step explanation:
1. 498.75/7
2. 71.25
Mia made 7 trips to visit her grandmother. she walked 498.75 meters in all, mia walks on each trip is 71.25 m
Mia made 7 trips to visit her grandmother
she walked 498.75 meters in all
In order to calculate the distance she walks on each trip, we calculate it by dividing the total distance by the number of trips
The total distance is 498.75
The number of trips is 7
walk on each trip is 498.75/ 7 = 71.25
Therefore, mia made 7 trips to visit her grandmother. she walked 498.75 meters in all, mia walks on each trip is 71.25 m
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-4 + 8m + 9 - 3m help plssd
Answer:
5m + 5
Step-by-step explanation:
Combine like terms (terms with like & the same amount of the variable).
Set the equation:
(8m - 3m) + (9 - 4)
Simplify by combining like terms:
(8m - 3m) = 5m
(9 - 4) = 5
5m + 5 is your answer.
~
Answer:
5m+5
Step-by-step explanation:
HELP PLEASE!!!
-15 < x - 8 < -4
SOLVE COMPUND INEQUALITY
\( \sf \: -15 < x - 8 < -4 \)
Add 8 to all parts\(\sf \longmapsto−15+8<x−8+8<−4+8\)
\(\sf \longmapsto−7<x<4\)
\( \boxed{\sf−7<x<4 }\)
Graph attachedBilly bought an iced tea for $1.79 and some tootsie rolls that were $0.13 each he spent a total of $2.83
Answer:
Whats the Question
Step-by-step explanation:
Answer:
I dont really understand the question but here what I got.
Step-by-step explanation:
1.73$+$0.13=1.86$
So he bought something else that cause 0.97$ to equal =2.83$
Find the next 3 terms. J30, J31, A31, S30
Answer:
Next 3 terms 031, N30, D31
Step-by-step explanation:
J30, J31, A31, S30
The above series represent the
first letter of the month and the days in it
J30= June which have 30 days
J31= July which has 31 days
A31= August which have 31 days
S30= September which have 30 days
30 days hath September, April, June and November. All the rest have 31 except February alone which has but 28 or 29 days
The next 3 terms of the series J30, J31, A31, S30 are 031, N30, D31
Customer number two gives you a
15% off coupon. What is the new cost
of the order? 11.50
Answer:
$8.50 ? let me know if im wrong
Step-by-step explanation:
HELPPP PLEASEEEE LIKE ASAPP
Answer:
4+(-5)=-1. C was just irrelevant here
Answer:
replace the variables in the equations with the values they give you, and solve it. it'll give you -1
Step-by-step explanation:
a + b becomes
4 + (-5), which is 4-5
so the answer is -1
What is 50,000 + 7,000 + 400 + 10 + 6 in standard form?
Answer:
57,416
Step-by-step explanation:
50,000 + 7,000 + 400 + 10 + 6
50,000 is in the ten thousands place.
7,000 is in the thousands place.
400 is in the hundreds place.
10 is in the tens place.
6 is in the ones place.
BRAINLIEST PERSON WHO GETS IT
Nyoko wrote these two questions.
Equation 1: 6x-5+2x = 4(2x-1) - 1
Equation 2: 3x +7 = bx+7
Part A
Nyoko says that Equation 1 has one solution. Do you agree with her? Explain your reasonings.
Part B
Can Nyoko find a value for b in Equation 2 so that the equation has no solutions? Explain Your REASONING!
a) The equation 1 has an infinite number of solutions, as both linear functions have the same slope and internet, hence Nyoko is incorrect.
b) Nyoko cannot find a value of b so that the equation has no solutions.
How to solve the equations?The equation 1 is given as follows:
6x - 5 + 2x = 4(2x - 1) - 1.
Combining the like terms and applying the distributive property, the simplified equations are given as follows:
8x - 5 = 8x - 4 - 1
8x - 5 = 8x - 5.
As they are linear functions with the same slope and intercept, the number of soltuions is of infinity.
The equation 2 is given as follows:
3x + 7 = bx + 7.
A system of linear equations will have zero solutions when:
The equations have the same slope.The equations have different intercepts.As they have the same intercept for this problem, it is not possible to attribute a value of b such that the equation will have no solution.
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Consider a relation R(A,B,C,D,E) with the following dependencies: {AB-> C, CD -> E, DE -> B} Is AB a candidate key of this relation? If not, is ABD? Explain your answer. No. The closure of AB does not give you all of the attributes of the relation.
If not, is ABD? Explain your answer. A -> A
B -> B
C -> C
D -> D
E -> E
AB -> ABC
AC -> AC
AD -> AD
AE -> AE
BC -> BC
BD -> BD
BE -> BE
CD -> BCDE
CE -> CE
DE -> BDE
ABD -> ABCDE
Yes, ABD is a candidate key. No subset of its attributes is a key.
What is the magnitude and direction of the PQ with tail and head points P(-6, 0) and Q(2, 4)?
8.9 units, 63.4° north of east
8.9 units, 26.6° north of east
13.4 units, 180° west
13.4 units, 0° east
Answer:
What is the magnitude and direction of the PQ−→− with tail and head points P(-6, 0) and Q(2, 4)? magnitude = √(64+16) = √80 = appr 8.9 , ruling out c.
hope this helps
The magnitude of PQ is 8.9 and PQ is making an angle of 26.57° so 8.9 units, 26.6° north of east will be the correct answer.
What is a vector?A vector is a quantity in which direction and magnitude both matters called a vector.
A vector joining by two points (x₁,y₁) and (x₂,y₂) will be (x₂-x₁)\(\hat{i}\) + (y₂-y₁)\(\hat{j}\)
The magnitude of this vector will be
\(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2\)
The direction of this vector will be
\(\\tan^{-1}(\frac{y_2-y_1}{x_2-x_1)}\)
Given P(-6,0) and Q(2,4) so vector joining by
\(\vec{PQ}\) = [2-(-6)]\(\vec{i}\) + [4-0]\(\vec{j}\)
\(\vec{PQ}\) = 8\(\vec{i}\) + 4\(\vec{j}\)
now, the magnitude \(\vec{PQ}\) will be
⇒ \(\sqrt{(8^2+4^2)}\)
⇒ 8.944
The direction of the vector \(\vec{PQ}\) will be
⇒ \(\tan^{-1}(\frac{4}{8})\)
⇒26.57°
So, the magnitude of PQ is around 8.944 and the direction is 26.57° from the positive x axis so it's north of the east.
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Zoey walked from school to the grocery store, and then to her house. The diagram shows the top view of the three locations and some of the distances between them.
Answer:
56
Step-by-step explanation:
Find the diameter of each circle.
Answer:
Diameter Length: ( About ) 5.4 km; Option B
Step-by-step explanation:
~ Let us apply the Area of the Circle formula πr^2, where r ⇒ radius of the circle ~
1. We are given that the area of the circle is 22.9 km^2, so let us substitute that value into the area of the circle formula, solving for r ( radius ) ⇒ 22.9 = π * r^2 ⇒ r^2 = 22.9/π ⇒ r^2 = 7.28929639361.... ⇒
radius = ( About ) 2.7
2. The diameter would thus be 2 times that of the radius by definition, and thus is: 2.7 * 2 ⇒ ( About ) 5.4 km
Diameter Length: ( About ) 5.4 km
I-ready Solve the equqation -2y + 6 = -12 y=
Answer:
y = 9
Step-by-step explanation:
I think you might have written this problem wrong, but I think the question is asking me to find y in the equation:
\(-2y+6=-12\)
Lets start by subtracting 6 from both sides:
\(-2y+6-6=-12-6\)
Simplify:
\(-2y = -18\)
Multiply both sides by -1
\((-1)(-2y) = (-18)(-1)\)
Simplify(cancel duplicate negatives)
\(2y = 18\)
Divide both sides by 2
\(\frac{2y}{2}=\frac{18}{2}\)
Simplify(remove denominator)
\(y = 9\)
Therfore, y = 9
I hope this helped!~~~Harsha~~~Please help I will give brainliest
Answer:
1. ∠YZX = 37°
2. ∠YXZ = 53°
3. XZ = 30 meters
Step-by-step explanation:
1. To solve for an unknown angle, we need to utilize the inverse of a trigonometric function.
⭐What are the inverses of the trigonometric functions?
\(sin^-1 (opposite/hypotenuse)\)\(cos^-1 (adjacent/hypotenuse)\)\(tan^-1(opposite/adjacent)\)To know which inverse of the trigonometric functions we use, we have to see the type of side lengths we are given (opposite, adjacent, or hypotenuse)
We are given side length XY, which is opposite of ∠YZX, and we are given side length YZ, which is adjacent to ∠YZX. Therefore, we will use \(tan^-1 (opposite/adjacent) =\)
Substitute the values we are given into the function:
\(tan^-1 (18/24) =\)
Compute this equation using a scientific calculator. I recommend using the Desmos Scientific Calculator:
\(= 37\)
∴ ∠YZX = 37°
2. We already know 2 angles (∠YZX = 37°, and ∠ZYX = 90°) Therefore, to find ∠YXZ, we have to utilize the triangle sum theorem.
⭐ What is the triangle sum theorem?
\(angle_1 + angle_2 +angle_3 = 180\)The sum of all angles in a triangle is 180°Substitute the angles we know already (∠YZX and ∠ZYX), and solve for ∠YXZ.
\(< YZX + < ZYX + < YXZ = 180\)
\(37 + 90 + YXZ = 180\)
\(127 + YXZ = 180\)
\(< YXZ = 53\)
∴ ∠YXZ = 53°
3. We already know 2 side lengths (ZY = 24 meters, and XY = 18). Therefore, to find XZ, we have to utilize the Pythagoras' theorem.
⭐ What is the Pythagoras' theorem?
\((C)^2 = (A)^2 + (B)^2\)C is the hypotenuse of the triangle, A is a leg of the triangle, and B is another leg of the trianglePythagoras' theorem can only be used on right trianglesSubstitute the values of the side lengths into the formula:
\((XZ)^2 = (XY)^2 + (ZY)^2\)
\((XZ)^2 = 18^2 + 24^2\)
Solve for XZ:
\((XZ)^2 = 324 + 576\)
\((XZ)^2 = 900\)
\(\sqrt{(XZ)^2} = \sqrt{900}\)
\(XZ = 30\)
∴ XZ = 30 meters
Which explains whether or not the graph represents a direct variation?
On a coordinate plane, a line goes through points (0, 0) and (1, 3).
The graph has a constant of variation of 3, so it represents a direct variation.
The graph has a slope of 3, so it represents a direct variation.
The graph has a positive slope, so it does not represent a direct variation.
The graph does not begin at the origin, so it does not represent a direct variation.
The line passes through the origin and if it has a constant of variation of 3, so it represents a direct variation , Option A is the correct answer.
What is Direct Variation ?When a quantity increases and the other quantity also increases , then those two quantities are said to be in direct variation.
It is asked in the question that which option depicts whether On a coordinate plane, a line goes through points (0, 0) and (1, 3) , represents a direct variation
As it is mentioned in the question that the line passes through the origin and if it has a constant of variation of 3, so it represents a direct variation.
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Answer:
a
Step-by-step explanation:
if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelgram
A number is a restriction on a rational expression if the number makes the denominator of the rational expressionTrueFalse
Answer: The values that make the denominator equal to zero for a rational expression are known as restricted values. How do you identify restrictions in rational expressions? The restriction is that the denominator can not be equal to zero. So in this problem, since 4x is in the denominator it can not equal zero.
determine the solution of the differential equation (1) y′′(t) y(t) = g(t), y(0) = 1, y′(0) = 1, for t ≥0 with (2) g(t) = ( et sin(t), 0 ≤t < π 0, t ≥π]
The solution of the differential equation y′′(t) y(t) = g(t),
y(0) = 1, y′(0) = 1, for t ≥ 0 with
g(t) = (et sin(t), 0 ≤ t < π 0, t ≥ π] is:
y(t) = - t + \(c_4\) for 0 ≤ t < πy(t) = \(c_5\) for t ≥ π.
where \(c_4\) and \(c_5\) are constants of integration.
The solution of the differential equation
y′′(t) y(t) = g(t),
y(0) = 1,
y′(0) = 1, for t ≥ 0 with
g(t) = (et sin(t), 0 ≤ t < π 0, t ≥ π] is as follows:
The given differential equation is:
y′′(t) y(t) = g(t)
We can write this in the form of a second-order linear differential equation as,
y′′(t) = g(t)/y(t)
This is a separable differential equation, so we can write it as
y′dy/dt = g(t)/y(t)
Now, integrating both sides with respect to t, we get
ln|y| = ∫g(t)/y(t) dt + \(c_1\)
Where \(c_1\) is the constant of integration.
Integrating the right-hand side by parts,
let u = 1/y and dv = g(t) dt, then we get
ln|y| = - ∫(du/dt) ∫g(t)dt dt + \(c_1\)
= - ln|y| + ∫g(t)dt + \(c_1\)
⇒ 2 ln|y| = ∫g(t)dt + \(c_2\)
Where \(c_2\) is the constant of integration.
Taking exponentials on both sides,
we get |y|² = \(e^{\int g(t)}dt\ e^{c_2\)
So we can write the solution of the differential equation as
y(t) = ±\(e^{(\int g(t)dt)/ \sqrt(e^{c_2})\)
= ±\(e^{(\int g(t)}dt\)
where the constant of integration has been absorbed into the positive/negative sign depending on the boundary condition.
Using the initial conditions, we get
y(0) = 1
⇒ ±\(e^{\int g(t)}dt\) = 1y′(0) = 1
⇒ ±\(e^{\int g(t)}dt\) dy/dt + 1 = 0
The above two equations can be used to solve for the constant of integration \(c_2\).
Using the first equation, we get
±\(e^{\intg(t)\)dt = 1
⇒ ∫g(t)dt = 0,
since g(t) = 0 for t ≥ π.
So, the first equation gives us no information.
Using the second equation, we get
±\(e^{\intg(t)}dt\) dy/dt + 1 = 0
⇒ dy/dt = - 1/\(e^{\intg(t)dt\)
Now, integrating both sides with respect to t, we get
y = \(- \int1/e^{\intg(t)\)dt dt + c₃
Where c₃ is the constant of integration.
Using the second initial condition y′(0) = 1,
we get
1 = dy/dt = - 1/\(e^{\int g(t)}\)dt
⇒ \(e^{\int g(t)}\)dt = - 1
Now, substituting this value in the above equation, we get
y = - ∫1/(-1) dt + c₃
= t + c₃
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Please help I will mark brainiest!!!
Answer:
-27
Step-by-step explanation:
(-3)^4 / (-3)^1 = 81/-3
= -27
Answer:
Exact Form: 3/2,Decimal Form: 1.5 ,Mixed Number Form:1 1/2
Step-by-step explanation:
I need help pleaseeee
Find the y intercept for the equation of the line that passes through point (-1 , 5)if the slope is 5
Answer:
the y-intercept is 10
Step-by-step explanation:
The parametric equations of a line are given as x=-10-2s, y=8+s, se R. This line crosses the x-axis at the point with coordinates 4(a,0) and crosses the y-axis at the point with coordinates B(0.b). If O represents the origin, determine the area of the triangle AOB.
The area of triangle AOB is 26 square units.
To determine the area of the triangle AOB formed by the line defined by the parametric equations x = -10 - 2s and y = 8 + s, where A is the point (4, 0), O is the origin (0, 0), and B is the point (0, b), we need to find the coordinates of point B.
Let's substitute the coordinates of point B into the equations of the line to find the value of b:
x = -10 - 2s
y = 8 + s
Substituting x = 0 and y = b:
0 = -10 - 2s
b = 8 + s
From the first equation, we have:
-10 = -2s
s = 5
Substituting s = 5 into the second equation:
b = 8 + 5
b = 13
So, the coordinates of point B are (0, 13).
Now, we can calculate the area of triangle AOB using the formula for the area of a triangle given its vertices:
Area = 0.5 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
Substituting the coordinates of points A, O, and B:
Area = 0.5 * |4(0 - 13) + 0(13 - 0) + (-10)(0 - 0)|
= 0.5 * |-52|
= 26
Therefore, the area of triangle AOB is 26 square units.
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y=3x +5
y=x+3
Graph the system. Then write its solution. Note that you can also answer "No solution" or "Infinitely many" solutions.
what is the answer ??
Certain product requires 3 assembly operations \( (1, m, q) \) are sequentially done automatic assembly line. this assembly line to produce 6000 parts/month and the plant operating 4 weeks per month,
The production rate of the assembly line is 6000 parts per month.The assembly line produces 6000 parts per month, with a weekly production rate of 1500 parts.
To calculate the production rate of the assembly line, we need to consider the number of weeks in a month. Since the plant operates for 4 weeks per month, we can divide the total production by the number of weeks to find the weekly production rate.
Given that the assembly operations are sequential, we can calculate the weekly production rate as follows:
6000 parts/month ÷ 4 weeks/month = 1500 parts/week.
Therefore, the assembly line produces 1500 parts per week.
The assembly line produces 6000 parts per month, with a weekly production rate of 1500 parts. This information can be used for planning and managing production schedules efficiently.
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4. A group of friends wanted to raise $200 to throw an end-of-the-year party. Five friends
decided they could not attend, so each person now had to pay $2.00 more. How many
friends originally planned the party?
The original number of friends planning the party was 25.
Let's assume the total number of friends originally planning the party is 'x'.
Initially, each friend would contribute an equal amount to raise $200. So the initial contribution per friend would be $200/x.
When five friends decided not to attend, the number of friends remaining is (x - 5). Now, each friend has to contribute $2.00 more than before.
So, the new contribution per friend is $200/(x - 5) + $2.
According to the given information, the new contribution is $2.00 more than the initial contribution:
$200/(x - 5) + $2 = $200/x
To solve this equation, we can eliminate the dollar signs and simplify:
200/(x - 5) + 2 = 200/x
Multiplying both sides of the equation by x(x - 5) to eliminate the denominators:
200x + 2x(x - 5) = 200(x - 5)
200x + 2x^2 - 10x = 200x - 1000
Rearranging the equation and simplifying:
2x^2 - 10x - 1000 = 0
Dividing the equation by 2:
x^2 - 5x - 500 = 0
Using the quadratic formula, we can find the values of x:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 1, b = -5, and c = -500.
x = (-(-5) ± √((-5)^2 - 4(1)(-500))) / (2(1))
x = (5 ± √(25 + 2000)) / 2
x = (5 ± √2025) / 2
x = (5 ± 45) / 2
Simplifying further:
x1 = (5 + 45) / 2 = 50 / 2 = 25
x2 = (5 - 45) / 2 = -40 / 2 = -20
Since the number of friends cannot be negative, we discard x2 = -20 as an extraneous solution.
Therefore, the original number of friends planning the party was 25.
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