Perform the followingmathematical operation, andreport the answer to the correctnumber of significant figures.0.008 : 51.3[? ]x100

Perform The Followingmathematical Operation, Andreport The Answer To The Correctnumber Of Significant

Answers

Answer 1

Firsly, we can write the numbers in scientific form:

\(\begin{gathered} 0.008=8\times10^{-3} \\ 51.3=5.13\times10^1 \end{gathered}\)

Notice that 0.008 has no tailing zeros, so the only significant figure is "8". 51,6 has 3 significant numbers.

In a division, the result will have the same number of significant figures as the one with less significant figure.

Since the one with less is 0.008, that has only one, the result also only has one significant figure:

\(\frac{0.008}{51.3}=\frac{8\times10^{-3}}{5.13\times10^1}=\frac{8}{5.13}\times10^{-4}=1.559\ldots\times10^{-4}\approx2\times10^{-4}\)


Related Questions

a 2.0 ml pipet transfers the 0.10 m cu2 stock solution to a 25.0 ml volumetric flask which is then diluted. what is the molar concentration of the diluted copper solution?

Answers

The  2.0 ml pipet transfers the 0.10 M stock solution to the 25.0 ml volumetric flask which is then diluted. The molar concentration of the diluted copper solution is 0.008 M.

The initial molar concentration, M₁ = 0.10 M

The initial volume , V₁ = 2.0 mL

The final molar concentration, M₂ = ?

The final volume, V₂ = 25.0 mL

The expression is as follows :

M₁ V₁ = M₂ V₂

M₂ = M₁ V₁ /  V₂

M₂ = (0.10 × 2 ) / 25

M₂ = 0.008 M

Thus, the molar concentration of the diluted copper solution is 0.008 M.

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Cody's car accelerates from 0m/s to 45m/s northward in 15 seconds. What is the acceleration of the car?

Answers

Cody's vehicle accelerates by 3 m/s2 (northward) in the 15 seconds it takes to go from 0 m/s to 45 m/s (northward).

What is the secret to motion?

Newton's second law, which states that the force acting on a body is equal to the mass of the body, is the fundamental equation of motion in classical mechanics acceleration an of its center of mass, or F = ma.

When the final velocity is 45 m/s (northward), the beginning velocity is 0 m/s, and the time is 15 seconds, we can calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.

When these values are added to the formula, we obtain:

acceleration = (45 m/s - 0 m/s) / 15

acceleration = 3 m/s² (northward).

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What is the term for the sum of all space, matter, and energy that exist, that have existed in the past, and that will exist in the future?

Answers

Answer: The universe is often defined as "the totality of existence", or everything that exists, everything that has existed, and everything that will exist.

Explanation:

The term for the sum of all space, matter, and energy that exist, that  may have existed in the past, and which will exist in the future is called the "universe."

The universe is a vast expanse that contains everything we know, including galaxies, stars, planets, and all forms of matter and energy The universe encompasses all physical matter and energy, including galaxies, stars, planets, gases, and particles. It is a vast and ever-expanding entity that contains everything we observe.

Universe comes from the Latin word "universum," which means "all things turned into one." It refers to the totality of everything that exists.The concept of the universe has been explored by scientists, philosophers, and astronomers for centuries. Through observations, experiments, and theoretical models, we have gained a better understanding of its structure, evolution, and composition.

To summarize all, the term for the sum of all space, matter, and energy that exist, have existed in the past, and will exist in the future is the universe.

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what are the 3 factors that affect the movement of cathode rays?

Answers

Answer:  1: Cathode rays travel in a straight line and can cast sharp shadows. Property 2: Cathode rays are negatively charged. Property 3: Electric field and magnetic field deflect cathode rays.

Explanation:

Scenario: The effectiveness of various metals in preventing rusting of iron.

Several weeks after Allen conducted a classroom experiment on the effectiveness of various metals in releasing hydrogen gas from hydrochloric acid, he read that the gas company was burying sheets of magnesium next to iron pipelines in order to prevent rusting. Allen wondered if other active metals would also be effective in preventing rust.

To investigate, he placed each of the following into a separate test tube containing water: one iron nail; one iron nail wrapped with an aluminum strip; one iron nail wrapped with a magnesium strip; and one iron nail wrapped in a lead strip. He used the same amounts of water from the same source, equal amounts of the metal wraps and the same type of iron nails. At the end of five days, he described the amounts of rusting either as small, moderate or large. He also recorded the color of the water.

Allen predicted that this the lead and aluminum would be less effective than the aluminum. Question 15 pts
What is the primary question under investigation in this scenario?
Group of answer choices

Will other metals rust as quickly as iron?

Will metals other iron prevent the rusting of iron?

Does magnesium dissolve as quickly as aluminum or lead?

Which type of iron nails are best for building with wood?
Question 25 pts
What is the analysts' hypothesis concerning the experiment?
Group of answer choices

The size of the test tubes will affect the rate of rusting more than the type of metal wrapped around the nail.

The rate of rusting will be unaffected by any of the other metals.

The magnesium will reduce the rate at which iron rusts more than the aluminum or lead.

The magnesium will reduce the rate at which iron rusts less than the aluminum or lead. Question 35 pts
What is the independent variable in this scenario?
Group of answer choices

the amount of time

the temperature

the amount of hydrochloric acid

the type of metal wrapped around the nail
Question 45 pts
What is the dependent variable in this scenario?
Group of answer choices

what type of metal is used

how much each nail rusts

how hard it is to wrap the test metal around the nail

the color of the waterQuestion 55 pts
What factors are kept constant in this scenario? Select all constants.
Group of answer choices

the amount of water

the source of the water

the type of test tube

the amount of metal wrapped around the nail

Answers

Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy


Question 1
1. Na2O + H20 --->
NaOH
A. Single Replacement
B. Double Replacement
c. Decomposition
D. Synthesis
E. Combustion

Answers

Answer: D. Synthesis

Explanation:

Sodium Oxide + Water = Sodium Hydroxide

For a snack, I ate 40 gummy bears. Each gummy bear weighs 3g.

If gummy bears are 100% carbohydrates and carbohydrates are 4 kcal/g, how many kcal I eat?

Answers

Taking into account the rule of three, you eat 480 kcal.

Rule of three

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, the direct rule of three must be applied as follow, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

kcal of eaten gummy bears

To know the mass of eaten gummy bears, the following rule of three applies: if 1 gummy bear weighs 3 g, 40 gummy bears weigh how much mass?

1 gummy bear ⇒ 3 g

40 gummy bears ⇒ x

So: x= (40 gummy bears× 3 g)÷ 1 gummy bear

Solving:

x= 120 g

If gummy bears are 100% carbohydrates and carbohydrates are 4 kcal/g, the following rule of three applies: If 1 g has 4 kcal, 120 g has how many kcal?

1 g ⇒ 4 kcal

120 g⇒ x

So: x= (120 g× 4 kcal)÷ 1 g

Solving:

x= 480 kcal

In summary, you eat 480 kcal.

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2. There is a toxic spill in Birch Bay. The material has a half-life of 3 days. What is the daily decay rate of the substance? Do not just give an answer. Show all work and any equations you used to find your answer. Round your answer to 3 decimal places

Answers

The daily decay rate of the substance is approximately 0.793 (rounded to 3 decimal places).

The half-life of the material = 3 days To calculate:

The daily decay rate of the substance Formula used:

1/2^(t/h), where t = time elapsed and h = half-life of the substance Solution:

The formula for calculating the daily decay rate of the substance is given by:

1/2^(t/h)Where t is the time elapsed and h is the half-life of the substance.

The daily decay rate of the substance is calculated as follows:1/2^(1/3) ≈ 0.793.

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help !!! pretty please ❤️

help !!! pretty please

Answers

Answer:

See below!

Explanation:

To find the symbol of the element, you have to use the periodic table.  

The mass number is the number of protons and neutrons in the atom.  

The atomic number is the number of protons in the atom.

You can find the number of protons from the periodic table.

You can find the neutrons by subtracting the mass number by the number of protons in the atom.

Unless you have an ion, you will have the same amount of electrons as you do protons.

To write in nuclear notation, you write the chemical symbol with the mass number and atomic number shown in the attachment.  It is preferable to have the mass number and atomic number directly above each other.

help !!! pretty please

Hi anyone can help me do these questions,I will mark brainlest,Thank You.​

Hi anyone can help me do these questions,I will mark brainlest,Thank You.

Answers

Explanation:

a.

P. When potassium reacts with hydrochloric acid, the salt produced is potassium chloride and sulphur-di-oxide gas is evolved after performing these.

Q.Addition of acid with metal gives salt and hydrogen gas. When dilute Hydrochloric acid is added to iron filings, so chloride & hydrogen gas is produced.

R. and if you talk about gold, gold do not react easily with HCL

b.

# in ascending order P -> Q -> R

c.

# I think its potassium chloride reaction.

hope this helps you

have a great day :)

Consider the following reaction, where A and
E are hypothetical elements.
A + 3E --> AE3
The atomic mass of A is 42.1 amu.
The atomic mass of E is 56.2 amu.
If 42.6 g of A fully reacts, how many grams of
AE3 are expected to form?
Enter your numerical answer to 1 decimal
place. Do not include the units of "g".

Answers

Answer:

Enter your numerical answer to 1 decimal place. Do not include the units of "g". Question: Question 14 1 pts Consider the following reaction, where A and E are hypothetical elements. A+3E --> AE The atomic mass of A is 42.1 amu. The atomic mass of Eis 56.2 amu. If 42.6 g of A fully reacts, how many grams of AE, are expected to form?

For the reaction represented by the equation 2H2 O2 → 2H2O, how many grams of water (H2O) are produced from 6.00 mol of hydrogen (H2)?

Answers

The amount of water created by 6.00 mol of hydrogen is 108.12 grams.

To determine the number of grams of water produced from 6.00 mol of hydrogen, we need to use the stoichiometry of the balanced equation.

The balanced equation is:

2H₂ + O₂ → 2H₂O

From the balanced equation, we can see that for every 2 moles of hydrogen (H₂), 2 moles of water (H₂O) are produced. This means that the molar ratio of hydrogen to water is 2:2 or 1:1. Given that we have 6.00 mol of hydrogen, we can conclude that an equal number of moles of water will be produced. Therefore, 6.00 mol of hydrogen will produce 6.00 mol of water.

To convert moles to grams, we need to use the molar mass of water, which is approximately 18.02 g/mol.

Hence, 6.00 mol of hydrogen will produce:

6.00 mol * 18.02 g/mol = 108.12 g of water.

Therefore, 6.00 mol of hydrogen will produce 108.12 grams of water.

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Calculate the Ka of lactic acid (CH3CH(OH)COOH) given the following information. 40.0 mL of 0.2 M KOH are added to 100. mL of a 0.500 M lactic acid solution producing a pH of 3.134. Because it's a small number Canvas tries to round it to zero and can't handle it. You need to enter your answer in two parts as Ka = A x 10B. What is B (the exponent)?

Answers

The values of pKₐ is 3.8, and Kₐ is 1.66×10⁻⁴ of lactic acid (CHCH(OH)COOH).

What are pKₐ and Kₐ?

The quantitative measure of an acids potency in a solution is the acid dissociation constant, or Kₐ. The Bronsted-Lowry definition states that an acid serves as a proton donor and a base as a proton receiver. Chemists simplify Kₐ to a smaller quantity called pKₐ because Kₐ is frequently a very large number. The same object is expressed differently as Kₐ and pKₐ.

We know that,

pKₐ= -log Kₐ

Hence, Kₐ = 10^(-pKₐ).

As given,

Lactic acid will act as a weak acid and on reaction with strong base like KOH it will form acidic buffer.

HA + KOH ⇒ AK + H₂O

Concentration of Lactic acid (HA) = 0.500 m.

Volume = 100 ml

No. of moles = m × V

                     = 50.0 m moles.

Similarly, no. of moles in KOH = 8.0 m moles.

HA + KOH ⇒ KA + H₂O

Also using Henderson-Hasselbalch equation,

pH = PKₐ + log [salt]/[Acid]

pH = PKₐ + log [KA]/[HA]

Substitute values,

3.058 = PKₐ + log [8]/[42]

PKₐ = 3.058 + 0.72

PKₐ = 3.778

PKₐ ≈ 3.8

Then evaluate the value of Kₐ respectively,

Kₐ = 10⁻³°⁸

Kₐ = 16.63×10⁻⁵

Kₐ = 1.66×10⁻⁴

Hence, the values of pKₐ is 3.8, and Kₐ is 1.66×10⁻⁴ of lactic acid (CH₃CH(OH)COOH).

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Identify the atom below.
Be
C
H
He

Identify the atom below.BeCHHe

Answers

Answer:

He

Explanation:

Helium is the only atom on the list with 2 protons and 2 neutrons

How many grams of carbon should be burned in an excess of oxygen at stp to obtain 2. 21 l of carbon dioxide?.

Answers

You must burn 1.17 g C to obtain 2.21 L CO2 at
STP.
The balanced chemical equation is
C+02+ CO2.
Step 1. Convert litres of CO, to moles of CO2.
STP is 0 °C and 1 bar. At STP the volume of 1 mol
of an ideal gas is 22.71 L.
Moles of CO2= 2.21 L CO2 × (1 mol CO2/22.71 L
CO2) = 0.097 31 mol CO2
Step 2. Use the molar ratio of C:CO2 to convert
moles of CO to moles of C
Moles of C= 0.097 31mol CO2 × (1 mol C/1 mol
CO2) = 0.097 31mol C
Step 3. Use the molar mass of C to calculate the
mass of C
Mass of C= 0.097 31mol C × (12.01 g C/1 mol C) =
1.17 g C
It looks as if you are using the old (pre-1982)
definition of STP. That definition gives a value of
1.18 g C.

How does the temperature change when a layer of glass is added?

Answers

Answer:

thermal shock

Explanation:

the temperatures inside the glass jar should have continued to increase over time. Internal stresses due to uneven heating. This is also known as “thermal shock”.

In general, the thicker the glass, the more prone it will be to breaking due to the immediate differences in temperature across the thickness of glass.

Borosilicate glass is more tolerant of this, as it has a higher elasticity than standard silicon glass.

You may also note that laboratory test tubes and flasks are made with thinner walls, and of borosilicate glass, when designated for heating.

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

Answers

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\(\%C_E = \frac{E}{T} * 100\%\)

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In \((Ca(OH)_2)\)

The amount of all elements is: (i.e formula mass of \((Ca(OH)_2)\))

\(T = 1 * Ca + 2 * H + 2 * O\)

\(T = 1 * 40 + 2 * 1 + 2 * 16\)

\(T = 74\)

The amount of calcium is: (i.e formula mass of calcium)

\(E = 1 * Ca\)

\(E = 1 * 40\)

\(E = 40\)

So, the percentage component of calcium is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{40}{74} * 100\%\)

\(\%C_E = \frac{4000}{74}\%\)

\(\%C_E = 54.05\%\)

The amount of hydrogen is:

\(E = 2 * H\)

\(E = 2 * 1\)

\(E = 2\)

So, the percentage component of hydrogen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{2}{74} * 100\%\)

\(\%C_E = \frac{200}{74}\%\)

\(\%C_E = 2.70\%\)

Similarly, for oxygen:

The amount of oxygen is:

\(E = 2 * O\)

\(E = 2 * 16\)

\(E = 32\)

So, the percentage component of oxygen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{32}{74} * 100\%\)

\(\%C_E = \frac{3200}{74}\%\)

\(\%C_E = 43.24\%\)

A 5-newton ball and a 10-newton ball are released simultaneously from a point 50 meters above the surface of the Earth. Neglecting air resistance, which statement is true?
At the end of 3 seconds of free-fall, the 10-N ball will have a greater momentum than the 5-N ball

Answers

The 10-newton ball will have a greater momentum than the 5-newton ball at the end of 3 seconds of free fall, since momentum is directly proportional to mass. The statement "At the end of 3 seconds of free-fall, the 10-N ball will have a greater momentum than the 5-N ball" is true.

In the absence of air resistance, both the 5-newton ball and the 10-newton ball will experience the same acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s²) near the surface of the Earth. Therefore, the gravitational force acting on both balls will be proportional to their respective masses.

The mass of an object is directly related to its inertia and momentum. Since the 10-newton ball has a greater mass than the 5-newton ball, it will also have a greater momentum if their velocities are the same.

When both balls are released simultaneously from a point 50 meters above the Earth's surface, they will both experience the same downward acceleration. After 3 seconds of free fall, their velocities will be the same, as they have fallen for the same amount of time.

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do the equilibrium concentrations of the reactants and products depend on their initial concentrations?

Answers

The value of Keq is unaffected by the initial concentrations, despite the fact that the equilibrium concentrations of the reactants and products are. No matter the initial concentrations, the equilibrium state will always be reached (same Keq).

The equilibrium constant of a chemical reaction depends only on temperature. The initial concentrations will change during the reaction and will, at the end, respect the equilibrium constant. The equilibrium constant does not imply specific concentrations, but only the relation between them. Therefore, for a reaction in equilibrium, shifting to the right will result in a decrease in one of the reactants if the concentration of one of the reactants, such as hydrogen or nitrogen, is increased. The temperature is constant when melting. This is due to the fact that heat energy is not used to increase temperature but rather is absorbed by the particles to dissipate forces between them.

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if we say 2p6, the 2 corresponds to:group of answer choicesthe magnetic quantum numberthe number of orbitals that exist of that typethe energy levelthe number of electrons in those orbitals

Answers

If we say 2p6, the 2 corresponds to the energy level, and the 6 corresponds to the number of electrons in those orbitals.

In the electron configuration notation, the term "2p6" describes the arrangement of electrons in an atom's valence shell. The "2" in this term refers to the principal quantum number, which indicates the energy level of the valence shell. The "p" refers to the type of orbital, specifically the "p" orbital. The "6" indicates the total number of electrons present in that set of "p" orbitals. Therefore, the term "2p6" tells us that the valence shell of the atom has two energy levels and contains six electrons in the "p" orbitals. Overall, electron configuration notation helps us understand the electronic structure of atoms and their chemical properties.

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A gas-filled balloon with a volume of 2.00 L at 1.20 atm and 20°C is allowed to rise to the stratosphere (about 30 km above the surface of the Earth), where the temperature and pressure are −23°C and 3.00 × 10−3 atm, respectively. Calculate the final volume of the balloon.

Answers

To solve this problem, we can use the combined gas law, which relates the pressure (P), volume (V), and temperature (T) of a gas:

P1V1/T1 = P2V2/T2

where the subscripts 1 and 2 refer to the initial and final states of the gas, respectively.

We can start by converting the initial and final temperatures to Kelvin, which is necessary when using the gas laws:

T1 = 20°C + 273.15 = 293.15 K
T2 = −23°C + 273.15 = 250.15 K

Next, we can plug in the given values and solve for the final volume:

P1V1/T1 = P2V2/T2

(1.20 atm)(2.00 L)/(293.15 K) = (3.00 × 10−3 atm)V2/(250.15 K)

Multiplying both sides by (250.15 K)/(3.00 × 10−3 atm), we get:

V2 = (1.20 atm)(2.00 L)(250.15 K)/(293.15 K)(3.00 × 10−3 atm)

V2 = 310 L

Therefore, the final volume of the balloon is 310 L when it rises to the stratosphere where the temperature and pressure are −23°C and 3.00 × 10−3 atm, respectively.

Steel is formed by Group of answer choices oxidizing some of the iron to iron oxides. combining iron, carbon and transition metals such as chromium and nickel. heating iron at high temperature for a long time. adding sand and heating to a high temperature.

Answers

Answer:

combining iron, carbon and transition metals such as chromium and nickel.

Explanation:

Steels are alloys of iron and carbon. Steel is hard, tough and strong. The amount of carbon present in varies between 0.1 and 1.5% and it determines the hardness of steel. The higher the carbon content, the harder the steel produced. Also, the amount of heat treatment as well as presence of other elements determines the properties of steel produced.

Steel can be combined with other elements such as nickel, chromium, and manganese to produce various other alloys of steel . These alloys have various desirable properties than ordinary steel such as resistance to corrosion, high tensile strength and luster.

How to fronts and air masses affect weather?

Answers

Answer:

Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.

Explanation:

Good luck!

In the following acid-base reaction hpo42- is the_____________

Answers

In the following acid-base reaction, hpo₄²⁻ is the base.

This can be seen as it accepts a proton (H⁺) from H₂O to form the conjugate acid, H₂PO₄⁻. The other reactant, H₂O, donates the proton, making it the acid in the reaction. It is important to note that in an acid-base reaction, the species that donates a proton is the acid and the species that accepts the proton is the base.

The strength of the acid and base can also be determined by the equilibrium constant of the reaction. The larger the equilibrium constant, the stronger the acid or base. In this particular reaction, hpo₄²⁻ is a weak base, as it only partially accepts the proton from H₂O.

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Which process occurs at each link in a food chain?

Answers

Explanation:

1. All the energy is stored in newly made structure

2. Some energy is released into the environment as heat

3. Chemical energy is recycled

4. Atom cycle among living organism, producing energy

if a substance x has a solubility of 2.4×10−5 mg/l, and a molar mass of 188 g/mol, what is the molar solubility of the substance?

Answers

To find the molar solubility of substance X, we need to convert the given solubility from milligrams per liter (mg/L) to moles per liter (mol/L). The molar solubility of substance X is 1.28 × 10^(-10) mol/L.

Step 1:

We need to convert 2.4×10−5 mg/L to grams per liter (g/L) by dividing by 1000, which gives us 2.4×10−8 g/L.

Solubility = 2.4 × 10^(-5) mg/L
1 mg = 0.001 g, so:
Solubility = 2.4 × 10^(-5) × 0.001 g/L = 2.4 × 10^(-8) g/L

Step 2:
Next, we need to convert the mass to moles using the molar mass of substance X.

Molar mass = 188 g/mol
Molar solubility =2.4×10−8 g/L ÷ 188 g/mol = 1.28×10−10 mol/L
This is the molar solubility of substance X.

The molar solubility of substance X is 1.28×10−10 mol/L.

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for the following reaction, 0.270 moles of iron are mixed with 0.579 moles of oxygen gas
For the following reaction, 0.270 moles of iron are mixed with 0.579 moles of oxygen gas. iron(s) oxygen(g) → iron(II) oxide(s) What is the formula for the limiting reagent? What is the maximum amount of iron(II) oxide that can be produced?

Answers

The formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

To determine the limiting reagent and the maximum amount of iron(II) oxide that can be produced, we need to compare the moles of each reactant and their stoichiometric ratios in the balanced equation.

The balanced equation for the reaction is:

4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)

From the balanced equation, we can see that the stoichiometric ratio between iron and oxygen is 4:3. This means that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron(II) oxide.

Moles of iron(II) oxide = min (0.270 moles of Fe, (0.579 moles of O₂) × (2 moles of Fe₂O₃ / 3 moles of O₂))

To determine the limiting reagent, we compare the moles of iron and oxygen and choose the reactant that produces the lesser moles of iron(II) oxide. In this case, we have:

Moles of iron(II) oxide produced from 0.270 moles of Fe = 0.270 moles × (2 moles of Fe₂O₃ / 4 moles of Fe) = 0.135 moles

Moles of iron(II) oxide produced from 0.579 moles of O₂ = 0.579 moles × (2 moles of Fe₂O₃ / 3 moles of O₂) = 0.386 moles

Since 0.135 moles of iron(II) oxide is less than 0.386 moles, the limiting reagent is iron.

Therefore, the formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

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Which statement describes heterogeneous mixtures?

1. They are made up of two or more Pure substances that are not chemically bonded together and appear non-uniform

2. The substances they are composed of can only be separated chemically

3. The substances they are composed of have fixed ratio between their components

4. They are made up of two or more pure substances that are chemically bonded together appear uniform

Answers

Answer:

1. They are made up of two or more Pure substances that are not chemically bonded together and appear non-uniform

Explanation:

edge2020 :)

Heterogenous mixtures are made up of two or more substances that are not chemically bounded together  and which appear non-uniform.

What are heterogenous mixtures?

Heterogenous mixtures is defined as a type of mixture where in the composition is not uniform throughout the mixture.It consists as two or more phases. The phases are chemically distinct from each other.

As there are two or more phases present in heterogenous mixtures they can be separated by solvent extraction where in one phase is miscible with the solvent and the other phase is immiscible.

Components of a heterogenous mixtures are distinctly visible . There are two types of heterogenous mixtures, the colloids and the suspensions.These two vary with each other with respect to particle size.

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A shiny piece of metal has a volume of 315 cm3 and a mass of 851 g. what is the density of the metal?

Answers

D=M/V, so density is 2.7 g/cm cubed (cube the centimeters)

The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. The density of aluminum in g/cm³ is 2.70 g/cm³.

A substance's density is a measurement of how heavy it is in relation to its size. If an object is placed in water, it will float if it is less dense than the water, and it will sink if it is more dense. The density of a material is a distinguishing quality that is independent of the substance's volume.

The volume of the metal =315 cm³

Then density is:

Density = mass /volume

Density of metal = 851 g / 315cm³

D = 2.70 g / cm³

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Why is it appropriate to describe the Sun and its orbiting celestial bodies as a system?

Answers

Because the sun is the most important thing in this world, we live because of it and we need to understand other ones

As the bodies present in the gravitational force of sun, so it is appropriate to describe the sun and its celestial bodies as system.

What are celestial bodied?

Celestial bodies are those objects which are present in the space not in the land.

In the space all the planets are present in their orbitals under the gravitational force of the sun and do the motion around the sun, because of that force planets are present in the orderly arrangement. Because of the revolution of the earth around the sun, seasons will change on the earth.

Hence, it is appropriate to describe the sun and its celestial bodies as system.

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