People are looking to see why some people get bit more by mosquitos than others. Some people have
wondered if the scent of their perfume can have an effect on how often they are bit.
a)
independent variable:
b) dependent variable:
c) three possible constants in the
scenano

The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

The term vapor pressure is defined as the tendency of a material to change into the vapour state, and it increases with temperature.

For calculating mole fraction of C₂H₄Br₂ as follows

X C₂H₄Br₂ = moles of C₂H₄Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 0.3 / 0.3 + 1.80

= 0.14

For calculating mole fraction of C₃H₆Br₂ as follows:

XC₃H₆Br₂ =  moles of C₃H₆Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 1.80 / 2.1

= 0.85

For calculating total vapor pressure as follows:

P total = [ ( 0.14 × 127) + (0.85 × 173) ]

= 17.78 + 147.05

= 164.83 torr

Thus, The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

To learn more about the vapor pressure, follow the link;

https://brainly.com/question/11864750

#SPJ1

Answer:

-219

Explanation:

1.5(339) - 1.5(485) = -219

The approximate enthalpy change for this substitution reaction is -219 kJ.

In the case of this substitution reaction, we need to find the enthalpy change when NaO₂C₂H₂Cl is converted to NaO₂C₂H₂F.

This reaction involves the breaking of the C-Cl bond and the formation of the C-F bond.

We have to subtract the bond energy of the C-F bond from that of the C-Cl bond and multiply by the number of moles involved.

So we will have;

ΔH= 1.500 mole [339.0  kJ/mol - 485.0 kJ/mol]

ΔH= -219 kJ

Learn more: https://brainly.com/question/1301642

Answer:

3.9 seconds

Explanation:

Given:

To find:

Solution:

We can use the equation,

v = u + at

where,

We know that the initial velocity is 0, so the equation becomes,

v = at

We can also use the equation,

s = ut + ½* at²

where,

We know that the distance covered is 540 m and the final velocity is 72 m/s, so we can substitute these values into the equation to solve for the time taken.

540 = 0 * t + ½ * a * t²

540 = ½ * a * t²

1080 = a * t²

\(t^2= \frac{1080}{a}\)

\(t = \sqrt{ \frac{1080}{a}}\)

We know that the acceleration is the change in velocity divided by the time taken, so we can substitute this value into the equation to solve for the time taken.

\(t = \sqrt{\frac{1080 }{ 72 m/s}}\)

\(t = \sqrt{15} s\)

t = 3.9 s

Therefore, the time taken is t = 3.9 seconds

Answer:

Glass cleaner is: acidic

Aspirin is: basic

Sugar water is: neutral

Answer:

basic

acidic

nuetral

Explanation:

in that order

The Kp of the reaction is seen to be  1.75 * 10^4

A high Kp value indicates that the equilibrium is in favor of the products, whereas a low Kp value suggests that the equilibrium is in favor of the reactants.

The relative concentrations of reactants and products at equilibrium are shown  by the equilibrium constant.

We know that;

Kp = pSO3^2/pO2 . pSO2^2

Kp =(0.0166)^2/ 0.002930  (0.002318)^2

Kp = 2.8 * 10^-4/1.6 * 10^-8

Kp = 1.75 * 10^4

The Kp of the reaction is gotten as 1.75 * 10^4.

Learn more about equilibrium constant:https://brainly.com/question/10038290

#SPJ1

The concentration in weight percent is 40%

The following data were obtained from the question:

Concentration in weight percent = (mass of sugar / total mass) × 100

Concentration in weight percent = (6.000 / 15.000) × 100

Concentration in weight percent = 0.4 × 100

Concentration in weight percent = 40%

Learn more about percentage composition:

https://brainly.com/question/23158390

#SPJ1

the answer is that it is a

The chemical shift of the proton from TMS is 3.112 Hz.

Generally, The chemical shift of a proton from TMS (tetramethylsilane) in Hz can be calculated as follows:

δ (in Hz) = δ (in ppm) x (frequency in MHz) / 10^6

Plugging in the values, we get:

δ (in Hz) = 7.78 ppm x (400 MHz) / 10^6 = 3.112 Hz

Read more about chemical shift

https://brainly.com/question/4289021

#SPJ1

Answer:

See explanation

Explanation:

Number of moles of naphthalene = 0.32g/128.1705 g/mol = 0.0025 moles

Molality = number of moles/ mass of Solvent in kilograms

Molality = 0.0025/0.025 Kg

Morality = 0.1 m

But

∆T= K × i × m

Where ∆T = boiling point elevation

i= number of particles (this is equal to 1 because naphthalene is molecular and not ionic)

m= molality of naphthalene = 0.1 m

K= boiling point elevation constant = 5.12 °C/m

∆T= 5.12 °C/m ×0.1 = 0.512°C

For freezing point depression

∆T= K× i × m

Where ∆T= freezing point depression

i= number of particles (this is equal to 1 because naphthalene is molecular and not ionic)

m= molality of naphthalene = 0.1 m

K= freezing point depression constant = 2.67 °C/m

∆T= 2.67 °C/m ×0.1 = 0.267°C

From Raoult's law;

∆P = XBPA°

Where;

∆P = vapour pressure lowering

XB = mole fraction of solute

PA° = vapour pressure of pure solvent

Number of moles of solvent = mass/molar mass = 25g/ 78 g/mol= 0.3205 moles

Total number of moles = number of moles of solute + number of moles of solvent = 0.0025 moles + 0.3205 moles = 0.323 moles

Mole fraction of solute = 0.0025 moles/0.323 moles = 0.0077

Vapour pressure of benzene = 100 torr

Therefore;

∆P = 0.0077 × 100torr = 0.77 torr

Hence;

∆P = 0.77 torr

We know at NTP each gas has 22.4L of volume .

\(\boxed{\sf 1mol\:of\:CO_2=22.4L=44g}\)

Hence 1g of CO2 contain

\(\\ \sf\longmapsto \dfrac{22.4}{44}\)

\(\\ \sf\longmapsto 0.5L\)

Now 44.4g of CO_2 has

\(\\ \sf\longmapsto 0.5\times 44.4=22.2L\)

The formula represents dissociated free ions as dissolved ionic compounds. An illustration is AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3 (aq).

We only need to take out the spectator ions in order to formulate the net ionic equation. We are left with the net ionic equation after removing the spectator ions! The net ionic equation can be obtained by repeating this procedure for any reaction.

When a reaction reaches equilibrium, or when the concentrations of the reactants and products stop changing, it is said to be "finished." The answer becomes more straightforward if the equilibrium constant is large: the reaction is complete when the concentration of a reactant reaches zero.

to know more about ionic equations here:

brainly.com/question/29299745

#SPJ4

Answer:

             287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

Answer

T2 = 7.9 °C

Explanation

Given:

Volume 1 = 8.5 L

Volume 2 = 4.5 L

Temperature 1 = 15.0 °C

Temperature = ?

Required: Final temperature

Solutions:

We use Charles Law to solve this question

V1/T1 = V2/T2

T2 = T1V2/V1

T2 = (15 x 4.5)/8.5

T2 = 7.9 °C

Answer:

11

Explanation:

electronic configuration = 1s^2, 2s^2, 2p^6, 3s^1

therefore total electrons = 2+2+6+1 = 11

Hope it helps youu ｡◕‿◕｡

1.2 × 10²⁴ atoms C

Chemistry

Atomic Structure

Stoichiometry

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

Identify variables

[Given] 24 g C

[Solve] atoms C

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C: 12.01 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.2034 × 10²⁴ atoms C ≈ 1.2 × 10²⁴ atoms C

Answer:Yes

Explanation:

Because Chinstrap penguins eat krills

Answer:

Explanyour mmation:

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

Read more about pH

https://brainly.com/question/11300720

The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer: its the first answer

Explanation:

Answer

(4) C₃H₈

Explanation

Saturated hydrocarbons are hydrocarbons that contain only single bonds between carbon atoms. As a result, each carbon atom is bonded to as many hydrogen atoms as possible. Saturated hydrocarbons are given the general name of alkanes. The general formula for a straight-chain saturated hydrocarbon is CnH2n+2 where n is the number of carbon.

When n = 2

C2H(2 x 2) + 2 = C2H6

When n = 3

C3H(2 x 3) + 2 = C₃H₈

Hence, the formula that represents a saturated hydrocarbon in the options is:

(4) C₃H₈

Answer: Topical Anesthesia.

Explanation:

Topical anesthetics are used to treat ailments including small burns, insect bites, poison ivy, poison oak, poison sumac, and minor cuts and scratches that cause discomfort and irritation.

The nerve terminals in the skin are numbed by topical anesthesia. They don't render patients unconscious like general anesthetics used during surgery do. The majority of topical anesthetics are accessible over-the-counter, but your doctor may have specific recommendations for their usage and dosage given your particular medical condition.

Answer:

20 mL OF 6 M HYDROCHLORIC ACID WILL BE NEEDED

Explanation:

M1 V1 = M2 V2

M1 = Molarity of sodium hydroxide = 3 M

V1 = volume of sodium hydroxide = 40 mL

M2 = Molarity of hydrochloric acid = 6 M

V2 = Volume of hydrochloric acid = unknown

Rearranging the equation, we have:

V2 = M1 V1 / M2

V2 = 3 * 40 mL / 6

V2 = 120 / 6

V2 = 20 mL

To precipitate the benzoic acid by 6 M of hydrochloric acid, 20 mL volume will be needed.

The half-life of the carbon-14 obtained from the graphical representation of radioactive material remaining in a sample versus time is 5730 years.

The half-life a radioactive material is the time taken for half the material to decay or disintegrate.

For example, if the initial mass of a material is 10 g and the material becomes 5 g after 2 days. Then, we can say that the half-life of the material is 2 days.

With the above information in mind, we can obtain the half-life of the carbon-14 as illustrated below:

From the graph, we obtain:

Now, we shall obtain the time for 1/2 in the graph.

The time for 1/2 in the graph is 5730 years.

Thus, we can conclude that the half-life of the carbon-14 is 5730 years.

Learn more about half life:

https://brainly.com/question/2279134

#SPJ1

Answer:

the answer is 373

Explanation:

K=°C + 273

K=100+273=373

Answer:

b

Explanation:

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

HEBW EISJS A A RID RO J KNE SINS DMO C EIS

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

The given statement is false ~

As we know, large distances can only be measured by using larger units like kilometers, miles, or other units, and it's much convenient. so, it's so different if we were to measure that distance using small unit like " decimeters "

I hope that was reasonable for you to understand, let me know if you have any questions ~