Pentanol (C₅H₁₁OH; M = 88.15 g/mol) has nearly the same molar mass as hexane (C₆H₁₄; M = 86.17 g/mol) but is more than 12 times as viscous at 20°C. Explain.

3 methyl 2 hept-yne is the first compound. 2,3- dimethyl- 2- heptene is the second compound. 2,3,4 trimethyl octane is third compound. 2-pentyne is fourth compound.

The first substance, 3-methyl-2-heptyne, contains a triple bond between the second and third carbon atoms and a chain of seven carbon atoms. The third carbon atom is joined to the methyl group.

The second substance, 2,3-dimethyl-2-heptene, has a double bond between the second and third carbon atoms and a chain of seven carbon atoms. The second carbon atom has two methyl groups bonded to it.

Eight carbon atoms make up the chain of the third chemical, 2,3,4-trimethyl-octane, which also has three methyl groups connected to its carbon atoms 2, 3, and 4.

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The hydrocarbon is C₄H₁₀ and its name is butane. It contains 14.3% by mass of hydrogen and gives a molecular ion peak with an m/z value of 56 in its mass spectrum.

The m/z value of 56 in the mass spectrum indicates that the molecular ion peak corresponds to a fragment with a mass of 56. The molecular formula of the hydrocarbon can be determined by considering the percentage by mass of hydrogen, which is 14.3%.

Using the molecular weight of hydrogen and the percentage of hydrogen, we can calculate the molecular weight of the hydrocarbon, which is 56/0.143 = 392.3. The only hydrocarbon with a molecular weight close to this value and containing four carbon atoms is butane, with a molecular formula of  C₄H₁₀. Therefore, the hydrocarbon in question is butane.

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Answer:

Density = 5 g/mL

Explanation:

Given data:

Volume of water = 2.0 mL

Volume of water + stone = 7.0 mL

Mass of stone = 25 g

Density of stone = ?

Solution:

Volume of stone = (volume of water + stone) - volume of water

Volume of stone = 7.0 mL - 2.0 mL

Volume of stone = 5.0 mL

Density of stone = mass/ volume

Density = 25 g/ 5.0 mL

Density = 5 g/mL

The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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Answer:

cumulonimbus

Explanation:

Answer:

there you go man

Explanation:

In an electrolytic cell, the cathode is where (D) reduction occurs.

Reduction is the gain of electrons, and the cathode is the electrode where electrons are supplied to the system. The cathode is connected to the negative terminal of the power supply and is thus negatively charged. When the positively charged cations in the electrolyte solution migrate towards the cathode, they gain electrons and are reduced.

The reduction reaction at the cathode is the half-reaction that consumes electrons, and it is the opposite reaction to the oxidation reaction that occurs at the anode.

Therefore, option D ("reduction occurs") is the correct answer. Option A is incorrect because anions are attracted to the anode, which is connected to the positive terminal of the power supply, and option E is incorrect because electrons are not created but rather supplied from the external power source. Option B is irrelevant to the function of the cathode in an electrolytic cell.

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Answer:

YesEdit: sorry I thought you asked "Is Sodium a metal?" It is a metal because it is on the left side of the periodic table and it has metallic properties such as:

It is malleable

Shiny when polished

Forms positive ions when it reacts

And has a high boiling pointpoint

Explanation:

Answer:

Decomposition

Explanation:

This shows a compound splitting into two

By definition, PbSO₄ → PbSO₃ + O₂ is a decomposition reaction, because a single substance decomposes producing two different substances.

First, you have to know that in a decomposition reaction, a single substance decomposes, producing two or more different substances. That is, in this type of reaction, two or more substances are formed from a compound.

The atoms that make up a compound are separated to give the products according to the formula:

AB → A + B

This type of reaction can occur spontaneously or caused by certain external factors, such as heat, which promote the decomposition of the molecule into simpler substances.

In this case, it is possible to observe that PbSO₄ → PbSO₃ + O₂ is a decomposition reaction, because a single substance decomposes producing two different substances.

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Answer:

its potassium acetate

Explanation:

.............................

Answer:

8.38×10raise to power 23

Explanation:

mass of sugar=density ×volume

=. 1.59g/ml×25ml=39.75

no. of miles= given mass/ molar mass

= 39.75/342.3g / mole

1 mole of sugar =C12 H22 O11

contains

12× 6.023 × 10 ∆23=72.28× 10∆ 23 ×6.023×10²³

= 8.38× 10²³

Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

Answer:

flourine(1681),carbon(1086),lithium(520) and potassium(419)

as we can see that the ionization energy of flourine is the highest than carbon than lithium and than potassium

Explanation:

i hope it will help you

Answer:

Potassium, Lithium, Carbon, Fluorine

Explanation:

potassium has the least and Fluorine has the most

Answer:

3. the symbol of each element in the substance

Explanation:

The given statement, production associates are not allowed to view the process safety management documents. They are only for supervisors and upper management is true.

Since they provide advice on how to manage the risks and hazards connected to certain operations or processes, these documents are often written with supervisors and top management in mind. This is done to make sure the management team has the knowledge it needs to decide on process safety in an informed manner and to make sure the right safety measures are in place to safeguard employees and the neighbourhood.

It is crucial to remember that a person's unique job responsibilities and the level of access required to carry out those duties should determine who has access to PSM documents. If it's necessary for them to carry out their duties, some production associates might have access to particular PSM documents.

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A cell wall, a large central vacuole, and plastids like chloroplasts are all present in plant cells.

The plant cell wall is a thick, rigid covering that surrounds and structurally supports the cell. It exists outside the cell membrane. The central vacuole maintains turgor pressure across the cell wall.

A plant cell wall with a cell membrane further protects the cell. The typical plant cell structure consists of organelles, cytoplasmic components, the cytosol, the cell wall, and the cell membrane (which is also referred to as the plasma membrane).

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The labelled image of the plant cell is attached below.

Answer:

\({ \sf{Al _{2} O _{3(s)} + 6HCl _{(aq)} → 2Al Cl _{3(aq)} + 3H _{2} O _{(l)} }}\)

Answer:

I think you have to put a coefficient of 6 in front Hcl,and a 2 infront of AlCl3 then a 3 in front of H2O,so that you can have 2 Al on both sides,6 Hcl,6 Cl and 3 o.

Al2O3+6HCl--->2AlCl3+3H2O.

I hope this helps

Answer:

B

Explanation:

Answer: H2 and M2 would react to produce more NH3

Explanation:

Answer:

To understand this first we must understand what is happening at the molecular level. When we heat any substance it changes its state of matter because its molecules get excited. For example, when we heat water it turns into gas so the molecules get excited. The hot air balloon will move faster if we add heat because the gas molecules will get excited and push against the balloon, making it faster. If we start removing heat, the balloon's acceleration will slow down because the molecules will get less excited.

Hot air balloons flies by means of it being lighter than air

The flame can be used to move the pilot to different directions by increasing the temperature of the air in the balloon and therefore, the volume, therefore, decreasing the density of the air which changes the elevation of the balloon to the appropriate elevation having winds moving in the desired direction

The principle by which the above process works is as follows:

According to Charles law, the volume of a mass of gas is directly proportional to its Kelvin temperature

V ∝ T

\(\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}\)

\(V_2 = T_2 \times \dfrac{V_1}{T_1}\)

\(Density, \rho = \dfrac{Mass, \ m}{Volume, \ V}\)

Therefore, as the temperature is increased, the volume occupied the mass gas increases, and therefore, the density decreases

The principle on which the hot air balloon operates on is the principle that hot air is less dense than and therefore, rises above cool air

Therefore, the pilot of an hot air balloon heats up the air in the balloon to allow the balloon to rise and the pilot switches off the burner so that the air in the balloon cools and the balloon looses altitude

The mechanism of the hot air balloon does not have a steering, and therefore, the wind direction is used to steer the balloon

The direction of the wind is different at different altitude, such that by obtaining the direction of the wind at a given altitude, the pilot can raise or lower the balloon up or down to the altitude having the desired wind direction, by increasing the temperature of the air in the balloon by switching on the burner to go to a higher altitude, or by switching off the burner so the air in the balloon cools and the balloon loses some of its altitude to reach the wind going in the direction of the pilot

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Sigma bonds are produced when two atomic orbitals overlap one another head-to-head, whereas pi bonds are produced when two atomic orbitals overlap one another laterally.

The strongest covalent chemical bond is a sigma bond, or bond. They are created by atomic orbitals overlapping directly one another. For diatomic molecules, the language and methods of symmetry groups provide the most straightforward definition of sigma bonding. A -bond is symmetrical with regard to rotation about the bond axis in this formal method. By this concept, s+s, pz+pz, s+pz, and dz2+dz2 are examples of common sigma bonds (where z is defined as the axis of the bond or the internuclear axis). Quantum theory also suggests that identically symmetric molecular orbitals (MO) actually mix or hybridize. The wavefunctions of the s+s and pz+pz molecular orbitals blend as a practical result of this mixing of diatomic molecules.

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Answer

Explanation:

he most recent Ebola virus outbreak in West Africa, which was unprecedented in the number of cases and fatalities, geographic distribution, and number of nations affected, highlights the need for safe, effective, and readily available antiviral agents for treatment and prevention of acute Ebola virus (EBOV) disease (EVD) or sequelae1. No antiviral therapeutics have yet received regulatory approval or demonstrated clinical efficacy. Here we report the discovery of a novel small molecule GS-5734, a monophosphoramidate prodrug of an adenosine analogue, with antiviral activity against EBOV. GS-5734 exhibits antiviral activity against multiple variants of EBOV and other filoviruses in cell-based assays. The pharmacologically active nucleoside triphosphate (NTP) is efficiently formed in multiple human cell types incubated with GS-5734 in vitro, and the NTP acts as an alternative substrate and RNA-chain terminator in primer-extension assays using a surrogate respiratory syncytial virus RNA polymerase. Intravenous administration of GS-5734 to nonhuman primates resulted in persistent NTP levels in peripheral blood mononuclear cells (half-life, 14 h) and distribution to sanctuary sites for viral replication including testes, eyes, and brain. In a rhesus monkey model of EVD, once-daily intravenous administration of 10 mg kg−1 GS-5734 for 12 days resulted in profound suppression of EBOV replication and protected 100% of EBOV-infected animals against lethal disease, ameliorating clinical disease signs and pathophysiological markers, even when treatments were initiated three days after virus exposure when systemic viral RNA was detected in two out of six treated animals. These results show the first substantive post-exposure protection by a small-molecule antiviral compound against EBOV in nonhuman primates. The broad-spectrum antiviral activity of GS-5734 in vitro against other pathogenic RNA viruses, including filoviruses, arenaviruses, and coronaviruses, suggests the potential for wider medical use. GS-5734 is amenable to large-scale manufacturing, and clinical studies investigating the drug safety and pharmacokinetics are ongoing.

Main

The 2013–2016 outbreak of EVD in West Africa was the largest and most complex EBOV outbreak in the recorded history of the disease, with >28,000 EVD cases and >11,000 reported deaths1. Medical infrastructures in Guinea, Sierra Leone, and Liberia were seriously impacted by a loss of >500 healthcare workers1. Additionally, EVD-related sequelae (joint and muscle pain, as well as neurological, ophthalmic, and other symptoms) together with viral persistence and recrudescence in individuals who survived the acute disease have been documented2,3,4,5.

EBOV is a single-stranded negative-sense non-segmented RNA virus from the Filoviridae family. In addition to EBOV, other related viruses, namely Marburg, Sudan, and Bundibugyo viruses, have caused outbreaks with high fatality rates6. Although the efficacy of various experimental small molecules and biologics have been assessed in EVD animal models and in multiple clinical trials during the West African outbreak7,8,9,10,11,12,13,14,15,16,17,18, there are no therapeutics for which clinical efficacy and safety have been established for treatment of acute EVD or its sequelae. The availability of broadly effective antiviral(s) with a favourable benefit/risk profile would address a serious unmet medical need for the treatment of EBOV infection.

A 1′-cyano-substituted adenine C-nucleoside ribose analogue (Nuc) exhibits antiviral activity against a number of RNA viruses19. The mechanism of action of Nuc requires intracellular anabolism to the active triphosphate metabolite (NTP), which is expected to interfere with the activity of viral RNA-dependent RNA-polymerases (RdRp). Structurally, the 1′-cyano group provides potency and selectivity towards viral RNA polymerases, but because of slow first phosphorylation kinetics, modification of parent nucleosides with monophosphate promoieties has the potential to greatly enhance intracellular NTP concentrations20. GS-5734, the single Sp isomer of the 2-ethylbutyl L-alaninate phosphoramidate prodrug (Supplementary Information), effectively bypasses the rate-limiting first phosphorylation step of the Nuc (Fig. 1a). In human monocyte-derived macrophages, incubation with GS-5734 caused rapid loading of cells with high levels of NTP that persist with a half-life (t1/2) of 24 h following removal of GS-5734 (Extended Data Fig. 1a), resulting in up to 30-fold higher levels compared to incubation with Nuc (Fig. 1b). In cell-based assays, GS-5734 is active against a broad range of filoviruses including Marburg virus and several variants of EBOV (Fig. 1c). GS-5734 inhibits EBOV replication in multiple relevant human cell types including primary macrophages and human endothelial cells with half-maxi

The mass of oxygen gas produced, given that 15.8 g of potassium permanganate is heated until no more oxygen gas is given off is 1.6 g

From the question given, the following data were obtained:

The mass of oxygen gas produced from the reaction can be obtained as follow:

Mass of potassium permanganate = Mass of remaining substance + mass of oxygen

Inputting the given parameters, we have:

15.8 = 14.2 + mass of oxygen

Collect like terms,

Mass of oxygen = 15.8 - 14.2

= 1.6 g

Thus, we can conclude that the mass of oxygen gas produced from the reaction is 1.6 g

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The value of x in the figure is

An angle is a geometric figure formed by two rays or line segments that share a common endpoint. This common endpoint is called the vertex of the angle, and the two rays or line segments that form the angle are called its sides.

Angles are measured in degrees, and a full circle contains 360 degrees. Angles can be classified based on their measure. A right angle measures exactly 90 degrees, an acute angle measures less than 90 degrees, and an obtuse angle measures more than 90 degrees but less than 180 degrees.

The figure consist of angel which is an acute angle, an acute angle are angles less than 90 hence 55 is the possible value

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In an open container, an equilibrium vapor pressure can be reached as long as the liquid has molecules capable of evaporating and the surrounding space allows for the escape and mixing of vapor molecules with the air.

Vapor pressure is the pressure exerted by the vapor molecules when the liquid and vapor are in equilibrium. It is a measure of the tendency of a liquid to evaporate. At any given temperature, molecules within the liquid have a range of kinetic energies. Some molecules have sufficient energy to overcome intermolecular forces and escape into the gas phase, forming vapor. As more molecules escape, the vapor density increases, creating a pressure known as the vapor pressure.

In an open container, the vapor molecules can freely escape into the surrounding space and mix with the air. Initially, the evaporation rate is high as molecules escape from the liquid surface. As the concentration of vapor molecules increases, collisions between the vapor and liquid surface also result in some molecules returning to the liquid phase, which is called condensation. Eventually, a dynamic equilibrium is established where the rate of evaporation and condensation become equal.

At this equilibrium, the vapor pressure above the liquid remains constant as long as the temperature is constant. The concentration of vapor molecules in the air above the liquid reaches a steady state, and the system is said to be saturated. The equilibrium vapor pressure is determined by the temperature and the characteristics of the liquid, such as its volatility and intermolecular forces.

Therefore, In an open container, an equilibrium vapor pressure can be reached above a liquid.

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Balanced Equation: CaSiO3 + 2 CO2 + H2O = Ca(HCO3)2 + SiO2

One or more chemical substances can react with each other and form one or more new substances through a process which is referred to as chemical reaction.

Reactants are the elements required for a reaction's initialization.

The components that remain after a reaction are called products.

Each kind of atom is to be present on both the reactant and product side of a chemical equation in a chemical reaction in order for it to be balanced.

On both sides of balanced chemical equations, the same number and type of each atom can be found.

A balanced chemical equation must have coefficients that are the smallest whole number ratio.

Mass is always conserved in chemical processes.

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The land accounts of the subsidiary be reported on consolidated financial statements will be book value for parent and Fair value for Subsidiary.

Option A is correct.

A business transaction known as an acquisition occurs when one company acquires control of another. These exchanges are a centerpiece of consolidations and acquisitions (M&A), a profession way in corporate regulation or money that spotlights on the purchasing, selling, and combination of organizations.

An obtaining is characterized as a corporate exchange where one organization buys a part or another organization's all's portions or resources. Acquisitions are regularly made to assume command over, and expand on, the objective organization's assets and catch collaborations.

Incomplete question :

In an acquisition where 100% control is acquired, how would the land accounts of the parent and the land accounts of the subsidiary be reported on consolidated financial statements on the date of acquisition?

A. Book value for both parent and subsidiary

B. Book value for parent, fair value for subsidiary

C. Fair value for subsidiary, book value for parent

D. Fair value for both parent and subsidiary

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Explanation:

For the first question, the correct compound that the highway engineer should use is magnesium combined with chlorine and second, when CaCl dissolves in water, it dissociates into its constituent ions: Ca2+ and Cl-. This means that the compound breaks up into its individual ions in water.



The highway engineer looking for a de-icing compound should use magnesium combined with chlorine, as this combination will result in a compound with a +2 ion and a -1 ion. This is because magnesium has a +2 charge and chlorine has a -1 charge, which allows them to form a compound with the required ion charges. When CaCl dissolves in water, it dissociates into its constituent ions: Ca2+ and Cl-. This means that the compound breaks up into its individual ions in water.



In conclusion, the highway engineer should use magnesium combined with chlorine for de-icing compounds, as it will result in a compound with the required ion charges. When CaCl dissolves in water, it dissociates into its constituent ions, Ca2+ and Cl-.

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