paul owns his own plumbing company. He charges customers a $50 call fee plus $25 an hour for labor plus parts. if h, represents hours and p, represents parts, which equation can be used to represent c, the total cost of the customers bill

Answer:

a) 6n+11

b)41, 47

c) 101

Step-by-step explanation:

a) 17, 23, 29, 35

+6. +6. +6

6n

17-6=11

a) =6n+11

b) 41, 47

c) 6n+11

replace the n with 15

15×6=90

90+11=101

Answer:

The commutative or associative property! Hope that helps!

Step-by-step explanation:

The time in hours for the Tran family's sprinkler will be 30 hours.

The time in hours for the Campbell family's sprinkler will be 35 hours.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The water output rate for the Tran family's sprinkler was 35 L per hour.

The water output rate for the Campbell family's sprinkler was 25 L per hour.

And, The families used sprinklers for a combined total of 65 hours, which is resulting in a total water output of 1925 L.

Now,

Let time in hours for the Tran family's sprinkler = t

And, The time in hours for the Campbell family's sprinkler = 65 - t

So, We can formulate by the given condition,

⇒ 35t + 25 (65 - t) = 1925

Solve for t as;

⇒ 35t + 25 (65 - t) = 1925

⇒ 35t + 1625 - 25t = 1925

⇒ 10t + 1625 = 1925

⇒ 10t = 1925 - 1625

⇒ 10t = 300

⇒ t = 30

Thus, The time in hours for the Tran family's sprinkler = t

                                                                                   = 30 hours

And, The time in hours for the Campbell family's sprinkler = 65 - t

                                                                                          = 65 - 30

                                                                                          = 35 hours.

Therefore, we get;

The time in hours for the Tran family's sprinkler will be 30 hours.

The time in hours for the Campbell family's sprinkler will be 35 hours.

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Answer:

A: 1/4

Step-by-step explanation:

we rewrite the answers in decimals to see the fraction closest to 1(We do this by dividing the fractions)

A: 1/4(0.25)

B: 1/5(0.2)

C: 1/6(0.1667)

D: 1/8(0.125)

thus from the above answers the fraction closest to is 1/4(0.25)

Answer:

49.2F

Step-by-step explanation:

To find the difference you can see how far they both are from 0 and add them together. So for this, it would be 36.6+12.6=49.2

Answer:

Strong positive

Step-by-step explanation:

I had that question on a test

Answer:

so what was the answer

Step-by-step explanation:

Answer:

  (b)  Add 15.9 to both sides because it is the inverse operation of subtraction

Step-by-step explanation:

The goal of the solution process for an equation is to get to the form ...

  variable = constant

Generally, you're starting from the form ...

  (operations on variable) = (operations on variable)

The solution process is one of "undoing" the operations in such a way as to obtain the desired form. In general, that means using inverse operations.

__

The given equation has a single variable term on one side of the equal sign, which is what we want. However, it has an added constant, which is what we don't want. We undo that addition of -15.9 by adding its opposite, 15.9. The properties of equality tell us we can only keep the equal sign valid if we do that operation (add 15.9) to both sides of the equation.

The first step in the solution is to add 15.9 to both sides of the equation.

__

The solution looks like ...

  3.7x -15.9 = 2.97

  3.7x -15.9 +15.9 = 2.97 +15.9 . . . . . add the opposite of -15.9

  3.7x = 18.87

  (3.7x)/3.7 = 18.87/3.7 . . . . . multiply by the reciprocal of 3.7

  x = 5.1

_____

Additional comment

When we add a negative number, we usually call that subtracting the positive value of that number. Adding -15.9 is called subtracting 15.9, for example.

When we multiply by a unit fraction, we usually call that division by the fraction's denominator. Multiplying by 1/3.7 is called dividing by 3.7, for example.

The point of inverse operations is to get you the identity element for that operation. Adding an opposite gives a sum of 0, the identity element for addition. (-15.9 +15.9 = 0) Multiplying by a reciprocal gives a product of 1, the identity element for multiplication. (3.7/3.7 = 1)

These ideas generalize to more complicated operations, including operations on collections of data.

The correct option is B which is Add 15. 9 to both sides because it is the inverse operation of subtraction.

The solution of the equation is 5.1.

Given

Equation;  3. 7x – 15. 9 = 2. 97

Subtracting and adding the same number have the effect of cancelling each other out.

To solve the equation follow all the steps given below.

Add 15. 9 to both sides because it is the inverse operation of subtraction.

\(\rm 3. 7x - 15. 9 = 2. 97\\\\ 3. 7x - 15. 9+15.9 = 2. 97+15.9\\\\3.7x=18.87\\\\x=\dfrac{18.87}{3.7}\\\\x=5.1\)

Hence, the solution of the equation is 5.1.

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c.) The group of people that watched the documentary at the festival represents the population.

In this scenario, the production company is interested in collecting information on the impact of an educational documentary on everyone that watched it at the film festival. Therefore, the group of people that watched the documentary at the festival represents the population of interest.

Thus, the correct answer is c.) The group of people that watched the documentary at the festival represents the population.

Option a.) The production company is the sample is incorrect because the production company is not a group of people who watched the documentary, but rather the entity interested in collecting information on the impact of the documentary.

Option b.) The production company represents the population is incorrect because the production company is not a group of people who watched the documentary, but rather the entity interested in collecting information on the impact of the documentary.

Option d.) The group of people that watched the documentary at the festival is the sample is also incorrect because the group of people that watched the documentary at the festival is not a subset of a larger group being studied. Instead, they represent the entire population of interest.

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The value of k is -1 of tangent over the parabola.

Equation of a line: y = (2 + x - k) ÷ 2, in line form of y = mx + c.

Equation of the parabola: x² = (y - 6x - 3) ÷ 2

Given,

y = (x ÷ 2) + (1) - (k ÷ 2)

where, m = 1 ÷ 2 and c = (1 - k) ÷ 2

For parabola equation in parabola form,

y = 2x² + 6x - 3

y = 2(x² + 3x - n) - 3

n = (b ÷ 2)²

n = (6 ÷ 2)²

n = 9

y = 2(x² + 3x - 9 + 9) - 3

y = 2(x² + 3x + 9) - 9 - 3

y = 2(x² + 3x + 9) - 12

y = 2(x + 3)² - 12, Hence the parabola equation is in vertex form.

Now, comparing the above vertex form with the parabola equation,

x² = 4ay

(x + 3)² = (y ÷ 2) + 6

where a = 1 ÷ 2

Now using the condition of tangency c = a ÷ m

c = (1 - k) ÷ 2

m = 1 ÷ 2

a = 1 ÷ 2

(1 - k) ÷ 2 = (1 ÷ 2) ÷ (1 ÷ 2)

1 - k = 2

k = -1

Therefore, the value of k is -1.

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The Calculation of the degree 2 Taylor polynomial of f around the point x0 = 1: Let the function f be f(x) = cos(x) (x-1)². Differentiating the function twice with respect to x, we obtain the following:

\($$f'(x) = -2\cos(x)(x-1) + \sin(x)(x-1)^2$$$$f''(x) = -2\cos(x)(x-2) -4\sin(x)(x-1)$$\)

Let p2(x) be the degree 2 Taylor polynomial of f(x) around

\(x0 = 1p2(x) = f(1) + f'(1)(x-1) + (f''(1)/2)(x-1)^2\)

Let's calculate p2(x) :

\($p2(x) = f(1) + f'(1)(x-1) + (f''(1)/2)(x-1)^2$$$$= cos(1)(1-1)^2 + [-2\cos(1)(1-1) + \sin(1)(1-1)^2](x-1)$$$$+ [-2\cos(1)(1-2) -4\sin(1)(1-1)](x-1)^2$$$$= -2\cos(1)(x-1) + 0(x-1)^2 - 2\cos(1)(x-1)^2 - 4\sin(1)(x-1)^2$\)

The degree 2 Taylor polynomial of f around the point x0 = 1 is \($p2(x) = -2\cos(1)(x-1) - 2\cos(1)(x-1)^2 - 4\sin(1)(x-1)^2$.b)\)Calculation of an approximation of f(1:1) and its absolute error using the Taylor polynomial obtained in point .

where p2 is the polynomial obtained in the previous paragraph\($f(x) - p2(x)$\)is the upper bound for the error that arises due to the use of p2(x) as an approximation for f(x).

Let\(t G(x) = $f(x) - p2(x)$G'(x) = $f'(x) - p2'(x)$G''(x) = $f''(x) - p2''(x)$Now, $|G(x)|$ $\leq$ $(M/2)(x-1)^2$,\) where M is the maximum value of \($|G''(x)|$\) on the interval [0.9,1.1]Max value of \($|G''(x)|$\) occurs at either \(x=0.9 or x=1.1.G''(0.9) = $-2\cos(0.9)(0.1) - 2\cos(0.9)(0.01) - 4\sin(0.9)(0.01)$$= -0.36664$G''(1.1) = $-2\cos(1.1)(0.1) - 2\cos(1.1)(0.01) - 4\sin(1.1)(0.01)$$= 0.44708$, $M = max(|G''(0.9)|, |G''(1.1)|)$ $= 0.44708$$|G(x)|$ $\leq$ $(0.44708/2)(x-1)^2$, $f(x) - p2(x)$ $\leq$ $0.11177(x-1)^2$\)

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Answers: a) The Taylor polynomial of degree 2 around x₀ = 1 for the function f(x) = cos(x)(x-1)² is P₂(x) = -2(x-1)².

b) The approximation of f(1.1) using the Taylor polynomial is P₂(1.1) = -0.02. The absolute error is |f(1.1) - P₂(1.1)|.

c) To set an upper bound for f(x) - P₂(x) in [0.9, 1.1], find the maximum absolute error between f(0.9) and f(1.1) using the same method as in part b). This gives the upper bound.

The degree 2 Taylor polynomial of a function f(x) around the point x0 = 1 can be calculated using the formula:

P2(x) = f(x0) + f'(x0)(x-x0) + f''(x0)(x-x0)²/2

Let's calculate the Taylor polynomial step by step:

a) We need to find f(1), f'(1), and f''(1).
f(x) = cos(x)(x-1)²
f(1) = cos(1)(1-1)² = 0
f'(x) = -2(x-1)cos(x) + (x-1)²sin(x)
f'(1) = -2(1-1)cos(1) + (1-1)²sin(1) = 0
f''(x) = -2cos(x) + 2(x-1)sin(x) + 2(x-1)sin(x) + (x-1)²cos(x)
f''(1) = -2cos(1) + 2(1-1)sin(1) + 2(1-1)sin(1) + (1-1)²cos(1) = -2

Now, we can use the formula to calculate the Taylor polynomial:
P2(x) = f(1) + f'(1)(x-1) + f''(1)(x-1)²/2
P2(x) = 0 + 0(x-1) + (-2)(x-1)²/2
P2(x) = -2(x-1)²

b) To approximate f(1.1) using the Taylor polynomial, we substitute x = 1.1 into P2(x):
P2(1.1) = -2(1.1-1)²
P2(1.1) = -2(0.1)²
P2(1.1) = -2(0.01)
P2(1.1) = -0.02

The absolute error can be calculated by finding the difference between the approximation and the actual value:
Absolute error = |f(1.1) - P2(1.1)|
To calculate f(1.1), substitute x = 1.1 into f(x):
f(1.1) = cos(1.1)(1.1-1)²
Now, calculate the absolute error.

c) To set an upper bound for f(x) - P2(x) in the interval [0.9, 1.1], we need to find the maximum value of the absolute error in this interval.
Calculate the absolute error for both x = 0.9 and x = 1.1 using the same method as in part b).
Find the maximum value of the absolute error between these two values. This will give us the upper bound for f(x) - P2(x) in the given interval.

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The curve with parametric equations x = sin(t), y = 3sin(2t), z = sin(3t) can be graphed in three-dimensional space. To find the total length of this curve, we need to calculate the arc length along the curve.

To find the arc length of a curve defined by parametric equations, we use the formula:

L = ∫ sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2) dt

In this case, we need to find the derivatives dx/dt, dy/dt, and dz/dt, and then substitute them into the formula.

Taking the derivatives:

dx/dt = cos(t)

dy/dt = 6cos(2t)

dz/dt = 3cos(3t)

Substituting the derivatives into the formula:

L = ∫ sqrt((cos(t))^2 + (6cos(2t))^2 + (3cos(3t))^2) dt

To calculate the total length of the curve, we integrate the above expression with respect to t over the appropriate interval.

After performing the integration, the resulting value will give us the total length of the curve. Rounding this value to four decimal places will provide the final answer.

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True. When calculating the process capacity of a specific process, it is important to consider the order in which a stage occurs when determining its stage capacity.

This statement is true. Considering the order of stages helps to accurately identify bottlenecks and ensures an efficient process flow. This is because the capacity of a stage can be affected by the preceding stages and the flow of the process. The stage capacity will also determine the overall capacity of the process.

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Answer:

hope it helps

.........

Answer:

Te answer is (b)

Step-by-step explanation:

When you subtract negative numbers, the operation automatically becomes addition.

According to the rule negative plus negative equals positive.

(-1)-(-5)= 6

(-)+(-)=+

(-1)+(-5)= 6

The given statement " The allowable range for an objective function coefficient assumes that the original estimates for all the other coefficients are completely accurate so that this is the only one whose true value may differ from its original estimate " is false because the allowable range for an objective function coefficient assumes that the original estimates for other coefficients are approximately correct

The allowable range for an objective function coefficient assumes that the original estimates for all the other coefficients are approximately correct, but not necessarily completely accurate. The allowable range takes into account the potential variability or uncertainty in the estimated values of the other coefficients, as well as the impact of any errors or discrepancies in the data used to estimate the model.

Therefore, the allowable range provides a range of values within which the objective function coefficient can vary while still producing a valid and useful model. It does not assume that the other coefficients are completely accurate or that this is the only coefficient whose true value may differ from its original estimate.

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Answer:

\( \frac{2}{ |1 - x| \times |1 - x| } = \)

\( = \frac{2}{ |1 - x|^{2} } \)

or

\( \frac{2}{ |1 - x| \times |1 - x| } = \)

\( = |1 - x| \times |1 - x| = 0\)

\( = |1 - x |^{2} = 0\)

\( = |1 - x| = 0\)

\( = 1 - x = 0\)

\( = ( - x) = ( - 1)\)

\( x = 1\)

Step-by-step explanation:

I Hope This Help

A complex number z = a + bi has the trigonometric form z = r(cosθ + I sinθ ), where r = |a + bi| is z's modulus and tanθ = b.

the angle generated by the complex number on a polar graph having one real axis and one imaginary axis. This may be calculated using the right angle trigonometry for the trigonometric functions. Complex numbers are those that are represented as a+ib, where a and b are actual numbers and I is a fictitious number termed a "iota." I has the value (-1). As an illustration, the complex number 2+3i is made up of the real number 2 (Re) and the imaginary number 3i (Im).

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Answer:

× = 0

Step-by-step explanation:

equation: 2x - 31 = -2x - 31

2x + 2x = -31 + 31 -----(taking like terms together)

4x = 0

x = 0/4

x = 0

Answer:

Only 1 solution

Step-by-step explanation:

2x - 31 = - 2x - 31

2x + 2x = - 31 + 31

4x = 0

x = 0 / 4

x = 0

This expression is with 1 variable. So 1 solution.

Answer:

p = 0.70z

Step-by-step explanation:

p is the food the penguins eat

z is the food the zebras eat

We are told that:  p < z

Then we are told that:  p = 70% of z

This can be written as p = 0.70z

An alternative way this can be written is:  p/z = 0.70  [The ratio of p to z is 0.7]

Answer:

Y=-1

Step-by-step explanation:

-4(y-2)

-4y+8=12

-8.       -8

-4y=4

-4.  -4

y=-1

Answer: Y = -1

Step-by-step explanation:

This is solved using the distributive property.

1. Distribute, so now it should look like -4y + 8 = 12

2. Now subtract the 8 from both sides to isolate -4y = 4

3. Divide -4 on both sides to get y = -1

The resultant moment about a both forces is zero. The statement is true.

A man B exerts a force on the rope, P = 30 lb

To find:

The magnitude of force, F

Consider a statement:

"The resultant moment about A of both forces is Zero."

Diagram attached at the end of the  solution

\($ \theta=\tan ^{-1}\left(\frac{3}{4}\right) \\\)

\(& \theta=36.87^0\)

To prevent the pole from rotating, so that the resultant moment is about A = 0

We will apply the equilibrium Equation \($\sum \mathrm{M}_{\mathbf{A}}=0$\)

Here force \($P \times \sin (45)$\) and \($F \times \sin (\theta)$\) will not produce the moment at A.

Taking clockwise moment as a negative and anticlockwise moment as a positive.

\(& \mathrm{P} \times \cos (45) \times(18)-\mathrm{F} \times \cos (\theta) \times 12=0 \\\)

\(& 30 \times \cos (45) \times(18)=\mathrm{F} \times \cos (\theta) \times 12 \\\)

\($ \mathrm{~F}=\frac{30 \times \cos (45) \times(18)}{\cos (36.87) \times 12} \\\)

F = 39.77 lb

Based on the given parameters,

The magnitude of force, F = 39.77 lb

So there exists the force by considering the resultant moment about an of both forces as zero.

The statement is true.

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Answer:

Median

Step-by-step explanation

The median is the value in the center of the data

I REALLY NEED BRAINLIEST PLZ PLZ PLZ

(a) To find the displacement of the ball during the time interval from 0 to 4 seconds, we need to integrate the velocity function over that interval.

The velocity function is given as v(t) = -32t + 140 feet per second. Integrating v(t) with respect to t will give us the displacement function s(t).

∫v(t) dt = ∫(-32t + 140) dt

Integrating, we get s(t) = -16t^2 + 140t + C, where C is the constant of integration.

To find the displacement specifically during the time interval from 0 to 4 seconds, we evaluate the definite integral:

∫[0,4] v(t) dt = ∫[0,4] (-32t + 140) dt

Evaluating this definite integral will give us the displacement of the ball during the time interval from 0 to 4 seconds.

(b) Given the initial position of the ball s(0) = 13 feet, we can use the result from part (a) to determine its position at time t = 4 seconds.

From part (a), we found the displacement function s(t) = -16t^2 + 140t + C. To find the constant of integration C, we substitute t = 0 and s(0) = 13 into the displacement function:

13 = -16(0)^2 + 140(0) + C

C = 13

So, the displacement function becomes s(t) = -16t^2 + 140t + 13.

To find the position of the ball at time t = 4 seconds, we substitute t = 4 into the displacement function:

s(4) = -16(4)^2 + 140(4) + 13

Evaluating this expression will give us the position of the ball at time t = 4 seconds.

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Answer: Everything except 3 * 129

Step-by-step explanation:

You can break 388 in half twice in order to find the answer.

Since 388/2 = 194, then 194 * 2 = 388

Since 388/4 = 97, then 97 * 4 = 388

Do note that 3 and 129 are both odd. Two odd factors can never make an even product. So that is out immediately.

Hope this helped a little bit, I tried to be quick with the explanation because I know how annoying those online things are. If you need anything explained more, just let me know.

Answer: 2

Step-by-step explanation: 12 divided by 3 is 4 so 6 divided by 3 would be 2

⇒I will use the similarity theorem which works by proportion of sides in similar shapes.

⇒The side with magnitude 12 in the bigger triangle is proportional with the  side with magnitude 4 in the  smaller triangle

⇒The side with magnitude 6 in the bigger triangle is proportional with the side with magnitude x in the smaller triangle. The proportionality theorem allows us to equalize the proportions of the sides

⇒HOW? HERE it is the solution

⇒\(\frac{12}{4} =\frac{6}{x} \\\)

⇒\(12(x)=4(6)\\12x=24\\\frac{1x}{12} =\frac{24}{12} \\x=2\)

⇒I used cross multiplication

Answer:

3a+5

Step-by-step explanation:

add-4a and 7a

3a+14-9

subtract 9 from 14

3a+5

Answer:

\( \sf \: 3a + 5\)

Step-by-step explanation:

Given expression,

→ -4a + 14 + 7a - 9

Let's simplify the expression,

→ -4a + 14 + 7a - 9

→ (-4a + 7a) + (14 - 9)

→ (3a) + (5)

→ 3a + 5

Hence, the answer is 3a + 5.

The 90% confidence interval for the proportion of district residents in favor of starting the school day 15 minutes later is (0.392, 0.548). The true proportion is estimated to lie within this interval with 90% confidence.

To calculate the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later, we can use the following formula:

CI = p ± z*(√(p*(1-p)/n))

where:

CI: confidence interval

p: proportion of residents in favor of starting the day later

z: z- score based on the confidence level (90% in this case)

n: sample size

First, we need to calculate the sample proportion:

p = 94/200 = 0.47

Next, we need to find the z- score corresponding to the 90% confidence level. Since we want a two-tailed test, we need to find the z- score that cuts off 5% of the area in each tail of the standard normal distribution. Using a z-table, we find that the z- score is 1.645.

Substituting the values into the formula, we get:

CI = 0.47 ± 1.645*(√(0.47*(1-0.47)/200))

Simplifying this expression gives:

CI = 0.47 ± 0.078

Therefore, the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later is (0.392, 0.548). We can be 90% confident that the true proportion lies within this interval.

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The measurement of altitude BE is 4 unit.

As the average level of the sea's surface, sea level is used to measure altitude. A high altitude is defined as being significantly higher than sea level, such as Mount Everest. It is referred to as having a low altitude when something is closer to the ground, like a plane coming in to land.

As ABCD is rectangle

AD = BC = 12

ΔABC = ΔBCD

BE = FD

5² = 3²+BE²

AE = 3

BE = √(5²-3²)

BE = 4

Thus, The measurement of altitude BE is 4 unit.

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