Answers
Self-management entails utilising what you know about your emotions to regulate them so that you may have pleasant connections with others and motivate yourself in all situations.
What distinguishes a high level of emotional intelligence?Those with a high EQ are acutely aware of their own emotions as well as the emotions of those around them. They can recognise and comprehend the varied sentiments that wash over them and control them correctly.
The capacity to properly observe the emotions of people and "read" circumstances effectively is referred to as social awareness. It is about perceiving what other people are thinking and feeling in order to take their point of view utilising your empathy.
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Related Questions
WHAT IS THE MEAING OF- Grouping Data
Answers
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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If a 20kg mass hangs from a spring, whose elastic constant is 1800 N / m, the value of the spring elongation is
Answers
Explanation:
F = kx
mg = kx
(20 kg) (10 m/s²) = (1800 N/m) x
x = 0.11 m
A mom pushes her 19.3 kg daughter on the swing. If she gives her an initial velocity of 7.5 m/s at the bottom of the swing and the swing sits 0.6 m above the ground at it's lowest point, what height does she reach above the ground?
Answers
Answer:
3.17333333333? I hope I get it right
Explanation:
..................hello
If someone's diet includes 2,000 calories/day, calculate the average power this represents in watts over a 24-hour period. 1 food calorie equals 4,187 KJ.
Answers
96.92 watts
Explanation
Step 1
find the energy of a day( 24 hours)
to solve this we can use a rule of three, then let x represents the energy in 2000 calories
if
\(\begin{gathered} 1\text{ food calorie}\Rightarrow4.187k\text{ J} \\ \text{then} \\ 2000\text{ calories}\Rightarrow x \end{gathered}\)so, the proportion is
\(\frac{1}{4.187}=\frac{2000}{x}\)solve for x
\(\begin{gathered} \frac{1}{4.187kj}=\frac{2000}{x} \\ \text{cross multiply} \\ 1\cdot x=2000\cdot4.187 \\ x=8374k\text{ j} \\ x=8374000 \end{gathered}\)hence, So a 2000 calorie diet corresponds to about 8.37 million joules
Step 2
now, we need to find the power (power is the amount of energy transferred or converted per unit time)
\(Power(watts)=\frac{\text{work done(Joules)}}{\text{time(seconds)}}\)then ,let
work done= energy= 8374000 Joules
-we need convert hours into seconds, to do this, just multiply the number of hours by 3600 to obtain the time in seconds, so
\(24\text{ h}\Rightarrow24\cdot3600\text{ sec}\Rightarrow86400\text{ seconds}\)now, replace in the formula
\(\begin{gathered} Power(watts)=\frac{\text{work done(Joules)}}{\text{time(seconds)}} \\ Power(watts)=\frac{8374000\text{ Joules}}{86400\text{ seconds}} \\ Power(watts)=96.92\text{ watts} \end{gathered}\)therefore, the answer is 96.92 watts
I hope this helps you
Define invariant transformations
Answers
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".
if the 52 lb bucket is released from rest, determine its velocity after it has fallen a distance of 12 ft . the windlass a can be considered as a 31 lb cylinder, while the spokes are slender rods, each having a weight of 2 lb . neglect the pulley's weight.(figure 1)
Answers
The velocity of the bucket after falling a distance of 12 ft is 7.54 m/s.
To determine the velocity of the bucket after it has fallen a distance of 12 ft, we need to use the equation of motion for an object falling under the influence of gravity:
v = √(2gh)
where v is the velocity of the object, g is the acceleration due to gravity (9.8 m/s²), h is the height the object has fallen, and h is the distance the object has fallen.
In this case, h = 12 ft = 3.66 m, so the velocity of the bucket after falling a distance of 12 ft is:
v = √(2 × 9.8 m/s² × 3.66 m) = 7.54 m/s
Note that this is the velocity of the bucket relative to the ground, and does not take into account any effects of the windlass or the spokes.
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When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answers
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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A spring is resting vertically on a table. A small box is dropped onto the top of the spring and compresses it. Suppose the spring has a
spring constant of 300 N/m and the box has a mass of 1.9 kg. The speed of the box just before it makes contact with the spring is 0.39
m/s.
(a) Determine the magnitude of the spring's displacement at an instant when the acceleration of the box is zero.
(b) What is the magnitude of the spring's displacement when the spring is fully compressed?
Answers
(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.
Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.
The gravitational potential energy is given by:
mgh = (1.9 kg)\((9.8 m/s^2)h\)
The elastic potential energy stored in the spring is given by:
1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.
The kinetic energy of the box just before it makes contact with the spring is given by:
\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.
Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.
mgh = 1/2 \(kx^2\)
Substituting the given values, we have:
\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)
Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.
(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.
At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.
mgh = 1/2 \(kx^2\)
Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.
It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.
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A delusion is best characterized as
Answers
Answer:
This is the most common form of delusional disorder. In this form, the affected person fears they are being stalked, spied upon, obstructed, poisoned, conspired against or harassed by other individuals or an organization.
Explanation:
hope this help
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A snowshoe hare can run 27 m/sHow far can the hare run in 3 minutes?
Answers
Explanation: 27x60 = 1620, 1620 x 3 = 4860
the weight of an object is measured in air to be 7N the object is then immersed in water and its apparent weight is measured to be 4N determined the buoyant force and state whether or not the object float
Answers
The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.
Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.
Floating occurs when the buoyant force is greater than or equal to the weight of the object.
In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.
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If a football quarterback runs into and tackles another player by grabbing onto them, what type of collision would this technically be?
a. Elastic
b. Inelastic
Which of the following would be an example of a closed system?
a. A person pushing a refrigerator box across a rough floor
b. A water bucket being pulled up by rope from a well
c. A rolling oil drum across a smooth, frictionless marble floor
d. A large moving rock slowing down while ploughing through loose sand
Answers
''If a football quarterback runs into and tackles another player by grabbing onto them'' is Elastic collision. A closed system is a rolling oil drum across a smooth, frictionless marble floor.
What is meant by Elastic collision?A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision.When two small objects collide, the kinetic energy of the collision is first transformed into the potential energy of an attractive or repulsive force between the particles. (when the particles move against this force, that is, when the angle between the force and the relative velocity is acute), and then this potential energy is transformed back into the kinetic energy of the collision (when the particles move with this force, i.e. the angle between the force and the relative velocity is acute).Learn more about Elastic collision refer to :
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Calculate the molar heat capacity at pressure and volume constant ( ) when knowing = = 1.4 and the gas density: 0 = 1.3 /3 .
Answers
(a) The molar heat capacity at pressure is 29.1 J/K.mol.
(b) The molar heat capacity at volume is 20.785 J/K.mol.
Molar heat capacity of gas at volumeMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its volume is constant.
Cv = R/(γ - 1)
where;
R is universal gas constant = 8.314 J/K.mol.γ is heat ratio = 1.4Cv = (8.314) / (1.4 - 1)
Cv = 20.785 J/K.mol
Molar heat capacity of gas at pressureMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its pressure is constant.
γ = Cp/Cv
Cp = γCv
Cp = 1.4 x 20.785
Cp = 29.1 J/K.mol
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How much work can an engine do in 15 minutes if it generates 22 MW of power and has a mass of 330 kg? *
Answers
Answer: 1/gk
Explanation: 15(22/330kg) (330/330gk) = 1/gk
PLS THIS IS DUE IN 2 MINUTES
Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?
Answers
Answer:
The toy car
Explanation:
the real car is parked so yeah but maybe in some way technically the real car has more "momentum"
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
Answers
The charge of the capacitive series circuit with a battery of 240v connected to it is 3.47×10⁻⁴ C.
What is charge?Charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field.
To calculate the charge, we use the formula below
Formula:
Q = C'V..................................... Equation 1Where:
Q = ChargeC' = Total CapacitanceV = VoltageFrom the question,
Given:
V = 260 VC' = 12/(2+3+4) = 12/9 = 4/3μF = 4/3×10⁻⁶ FSubstitute these values into equation 1
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Please respond to this for 15 points. Please don’t put in a link.
Answers
Answer:
e. Combustion
Explanation:
In Combustion reaction, a substance reacts with oxygen from the air and resultant product is that it releases carbon dioxide and water.
Here,
2C2H6 is the substance that reacted with 7O2 (Oxygen) to release 4CO2 (Carbon Dioxide) and 6H2O (Water).
The graph shows a car’s velocity over time, What is the car’s acceleration between 6 and 7 seconds
Answers
Based on the given graph of the car’s velocity over time, the car’s acceleration between 6 and 7 seconds is 0 m/s².
What is the acceleration of a body?The acceleration of a body is defined as the rate of change of velocity of a body with time.
Mathematically, the acceleration of a body is given below as follows:
Acceleration = change in velocity / change time
The change in the velocity of a body is given as follows:
Change in the velocity = Final velocity - initial velocity
A velocity-time graph is a graph that plots the velocity of a body against the time taken by the body to move. The slope of a velocity-time graph gives the acceleration of the body.
The acceleration of the car is calculated from the given velocity-time graph as follows:
Acceleration = (60 - 50) m/s / (7 - 6) s
Acceleration = 10 m/s²
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An object of height 5cm is placed 20cm in front of pin hole camera from a cubic box of side 6cm . Determine the height of the image formed
Answers
All of the following steps are included in a self-modification program except __________. A. specifying target behavior B. designing a program C. focusing on one goal at a time D. gathering data about target behavior
(Psychology)
Answers
Answer:
C)focusing on one goal at a time
Explanation:
Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;
✓ specifying target behavior ✓designing a program
✓ gathering data about target behavior
Answer:
c
Explanation:
on edge 2020
A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave
Answers
Answer:
b
Explanation:
If a student wishes to conduct an experiment to prove the conservation of momentum between two colliding objects, what are the minimum quanitities the student must record in order to complete this experiment and explain why you think they must record those.
Answers
The Logic Behind Momentum Conservation
Consider a collision between two objects - object 1 and object 2. For such a collision, the forces acting between the two objects are equal in magnitude and opposite in direction (Newton's third law). This statement can be expressed in equation form as follows.
The forces act between the two objects for a given amount of time. In some cases, the time is long; in other cases the time is short. Regardless of how long the time is, it can be said that the time that the force acts upon object 1 is equal to the time that the force acts upon object 2. This is merely logical. Forces result from interactions (or contact) between two objects. If object 1 contacts object 2 for 0.050 seconds, then object 2 must be contacting object 1 for the same amount of time (0.050 seconds). As an equation, this can be stated as
Since the forces between the two objects are equal in magnitude and opposite in direction, and since the times for which these forces act are equal in magnitude, it follows that the impulses experienced by the two objects are also equal in magnitude and opposite in direction. As an equation, this can be stated as
But the impulse experienced by an object is equal to the change in momentum of that object (the impulse-momentum change theorem). Thus, since each object experiences equal and opposite impulses, it follows logically that they must also experience equal and opposite momentum changes. As an equation, this can be stated as
Freestar
The Law of Momentum Conservation
The above equation is one statement of the law of momentum conservation. In a collision, the momentum change of object 1 is equal to and opposite of the momentum change of object 2. That is, the momentum lost by object 1 is equal to the momentum gained by object 2. In most collisions between two objects, one object slows down and loses momentum while the other object speeds up and gains momentum. If object 1 loses 75 units of momentum, then object 2 gains 75 units of momentum. Yet, the total momentum of the two objects (object 1 plus object 2) is the same before the collision as it is after the collision. The total momentum of the system (the collection of two objects) is conserved.
A useful analogy for understanding momentum conservation involves a money transaction between two people. Let's refer to the two people as Jack and Jill. Suppose that we were to check the pockets of Jack and Jill before and after the money transaction in order to determine the amount of money that each possesses. Prior to the transaction, Jack possesses $100 and Jill possesses $100. The total amount of money of the two people before the transaction is $200. During the transaction, Jack pays Jill $50 for the given item being bought. There is a transfer of $50 from Jack's pocket to Jill's pocket. Jack has lost $50 and Jill has gained $50. The money lost by Jack is equal to the money gained by Jill. After the transaction, Jack now has $50 in his pocket and Jill has $150 in her pocket. Yet, the total amount of money of the two people after the transaction is $200. The total amount of money (Ja
Before Collision
Momentum
After Collision
Momentum
Change in
Momentum
Dropped Brick
0 units
14 units
+14 units
Loaded Cart
45 units
31 units
-14 units
Total
45 units
45 units
as it was after the collision.
there is very little hydrogen or helium in the inner part of the solar system today. astronomers believe the reason for this is that
Answers
Astronomers believe that the reason for the low levels of hydrogen and helium in the inner part of the Solar System is that these elements were lost due to the Sun's strong solar wind
. Most of the gas in the solar nebula was hydrogen and helium. However, there is very little hydrogen or helium in the inner part of the solar system today. Astronomers believe this is because the intense solar winds from the young Sun blew the lighter gases out into space.
The solar winds also blew away any smaller particles that had not yet stuck together to form larger objects, which is why there are very few small objects close to the Sun. This is why there is more hydrogen and helium in the outer part of the solar system.
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3. When a magnetic sector instrument was operated with an accelerating voltage of 4.50*103 V, a field of 0.251 T was required to focus the CH4 on the detector. a) What range of field strengths would be required to scan the mass range between 12.5 and 2.50*102 , for singly charged ion, if the accelerating voltage is held constant
Answers
Answer:
The answer is "\(4,500 - 225 \ V\)".
Explanation:
Using formula for calculating the Voltage:
\(M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\\)
Hence the range of accelerating in voltage is \(4,500 - 225 \ V\)
While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.
Answers
Answer:
His displacement is 260 – 169 = 91 km
His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km
Explanation:
The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 10^22 kg. From this
information, what is the radius of the
Moon?
Answers
Answer:
Near the Earth's surface, the acceleration due to gravity is approximately constant. ... Its value is = 6.673 x 10-11 N·m2/kg2. ... The mass of the moon is 7.35 x 1022 kg. ... moon, the distance to the center of mass is the same as the radius: r = 1.74 x ... Handwriting · Spanish · Facts · Examples · Formulas · Difference Between ...
Explanation:
The acceleration of gravity on the Moon is 1.62 m/s2. The mass of the Moon is 7.35 x 10^22 kg. From this information, then the radius of the Moon is 3 * 10¹² m.
What is moon ?The sole natural satellite of Earth is the Moon. With a diameter around one-quarter that of Earth (equivalent to the breadth of Australia), it is the largest and most massive compared to its home planet and the fifth largest satellite in the Solar System. The Moon is bigger than any known dwarf planets of the Solar System and is a planetary-mass object with a distinct rocky body, making it a satellite planet according to geophysical definitions of the word. There isn't much of an atmosphere, hydrosphere, or magnetic field there. With a surface gravity of 0.1654 g, it has a gravity that is around one-sixth that of Earth. Jupiter's moon Io is the only satellite in the Solar System that is known to have a greater gravity and density.
The Moon travels an average distance around Earth.
Given,
g = 1.62 m/s²
m = 7.35*10²² kg
according to formula,
g = GM/r²
1.62 = 6.67× 10⁻¹¹ m³ kg⁻¹ s⁻²*7.35*10²² kg/r²
solving this for r we get
r = 1.7 * 10⁶ m
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An object traveling at 1.5 rad
accelerates at 0.75d for 12
S
seconds. What is the object's final
velocity?
Answers
The object's final velocity, given the data is 10.5 rad/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocityThe following data were obtained from the question
Initial velocity (u) = 1.5 rad/sAcceleration (a) = 0.75 rad/s²Time (t) = 12 sFinal velocity (v) = ?The final velocity can be obtained as follow:
a = (v – u) / t
0.75 = (v – 1.5) / 12
Cross multiply
v – 1.5 = 0.75 × 12
v – 1.5 = 9
Collect like terms
v = 9 + 1.5
v = 10.5 rad/s
Thus, the final velocity of the object is 10.5 rad/s
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A truck with mass m has a brake failure while going down an icy mountain road of constant downward slope angle α (Figure 1). Initially the truck is moving downhill at speed v0. After careening downhill a distance L with negligible friction, the truck driver steers the runaway vehicle onto a runaway truck ramp of constant upward slope angle β. The truck ramp has a soft sand surface for which the coefficient of rolling friction is μr.
What is the distance that the truck moves up the ramp before coming to a halt? Solve using energy methods.
Express your answer in terms of m , α , v0 , L , g , β and μr .
Answers
((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ) is the distance that the truck moves up the ramp before coming to a halt.
Let the distance the truck moves up the ramp be by x.
The kinetic energy of the truck on an icy road is given by,
K1 = (1÷2)mv²
The potential energy of the truck on an icy road is given by,
U1 = mgLSinα
The kinetic energy of the truck on the tuck ramp is given by,
K2 = 0
The potential Energy of the truck-on-truck ramp is given by,
U2 = mgxSinβ
Work done is given by,
W(others) = -µ×mg×cosФ
Hence, by using the work-energy theorem,
W(others) = (K2 + U2)(K1 + U1)
Therefore, by putting the values we get,
((1÷2)mv² + mgLSinα)(0 + mgxSinβ) = -µ×mg×cosФ
x = (K1 + mgLSinα) ÷ (mg(Sinβ + µcosβ))
x = ((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ)
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Which chart correctly describes the properties of magnets and electromagnets?
Answers
Answer:
The second chart seems to be correct
Explanation: