Parents have a major role in observing how young children grow at home. Create and discuss simple developmental monitoring tips a parent can use at home before consulting a health professionals

Answer:

no

Explanation:

it aint got them wings

Answer: No, potatoes do not fly

Explanation: They not butterflies and they don’t have no wings unless you carve the skin into wings then that would just be funny.

Answer:

t = 7.8 seconds

Explanation:

Given that,

The initial speed of the car, u = 28 m/s

Acceleration of the car, a = 3.6 m/s²

We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.

\(v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s\)

So, the required time is 7.8 seconds.

Answer:

see below

Explanation:

Kind of like when yo open a warm soda .....excess gas is released

Answer:

3.348 × 10^-9 N

Explanation:

The force of attraction between two objects can be calculated using the gravitational force equation:

F = G * (m1 * m2) / r^2

where F is the force of attraction, G is the gravitational constant (6.674 × 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between the centers of the objects.

Plugging in the given values, we get:

F = 6.674 × 10^-11 * (35 kg * 60 kg) / (5m)^2

F = 3.348 × 10^-9 N

Therefore, the force of attraction between the two objects is 3.348 × 10^-9 N.

Answer:

0.1014 J

Explanation:

This is the answer if the toy airplane was 120-GRAMS

if you meant KG then it's 101.4 J

Answer:

a

Explanation:

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Answer:204.2

Explanation:

F = 375 N

M = 45 KG

T = 7 SECONDS

U = 0

S = ?

F = ma

a = F/M

= 8.33m/s

from second equation of motion

s = ut + 1/2at^2

S = 204.166....

Time: s (second)

Mass: kg (kilogram)

Length: m (meter)

The SI units (International System of Units) are a standard system of measurement used in science, engineering, and many other fields. They provide a universal language for expressing and comparing measurements. The SI units are based on seven fundamental physical quantities, and each of these quantities is associated with a specific base unit, which is defined independently of any other unit.

Seven base units of the SI system are:

Length: meter (m)

Mass: kilogram (kg)

Time: second (s)

Electric current: ampere (A)

Temperature: kelvin (K)

Amount of substance: mole (mol)

Luminous intensity: candela (cd)

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Answer:

The average speed of the train is 45 km/h

Explanation:

Speed

It's defined as the distance (d) per unit of time (t) traveled by an object. The formula is:

\(\displaystyle v=\frac{d}{t}\)

Let's call x the total distance covered by the train. It covered d1=1/3x with a speed of v1=25 km/h. The time taken is calculated solving for t:

\(\displaystyle t_1=\frac{d_1}{v_1}\)

\(\displaystyle t_1=\frac{1/3x}{25}\)

\(\displaystyle t_1=\frac{x}{75}\)

Now the rest of the distance:

d2 = x - 1/3x = 2/3x

Was covered at v2=75 km/h. Thus the time taken is:

\(\displaystyle t_2=\frac{d_2}{v_2}\)

\(\displaystyle t_2=\frac{2/3x}{75}\)

\(\displaystyle t_2=\frac{2x}{225}\)

The total time is:

\(\displaystyle t_t=\frac{x}{75}+\frac{2x}{225}\)

\(\displaystyle t_t=\frac{3x}{225}+\frac{2x}{225}\)

\(\displaystyle t_t=\frac{5x}{225}\)

Simplifying:

\(\displaystyle t_t=\frac{x}{45}\)

The average speed is the total distance divided by the total time:

\(\displaystyle \bar v=\frac{x}{\frac{x}{45}}\)

Simplifying:

\(\boxed{\displaystyle \bar v=45\ km/h}\)

The average speed of the train is 45 km/h

the initial velocity of the bike rider is 10.35 m/s.

12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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The measurement of length and time is calculated the average speed with the expression

         \(v_{avg} = \frac{\Delta x}{\Delta t}\)

Average velocity is defined as the change in displacement between the interval time

      \(v_{avg} = \frac{\Delta x}{\Delta t}\)

where \(v_{avg}\) is the average velocity, Δx is the displacement in the interval, and Δt the time.

To carry out this measurement, it must be taken into account that the velocity is a vector, for which we define a reference system, it can be a vertical axis with the upward direction as positive, therefore the downward displacement is negative.

A tape measure is placed and the interval during which the scalar distance measurement is performed is defined, the most as is to use time as an independent variable (controlled by the researcher) that is measured with a stopwatch.

The displacement is measured for each given time interval and these two quantities are divided. The sign of the velocity is negative because it goes down

Using the measurements of length and time, the average velocity is calculated with the expression

         \(v_{avg} = \frac{\Delta x}{\Delta t}\)t

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Answer:

a) because this is in series, we have:

the total resistance is 3 + 1 = 4 (ohm)

b) the curren in the circuit is 12/4 = 3 (A)

c) the voltage in R = 3 ohm is 3.3 = 9 (V)

the voltage in R = 1 ohm is 12 - 9 = 3 (V)

Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.

Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.

The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the  wavelength.

Given the time period of the wave = 2.09 Hz

then frequency = 1/2.09 Hz = 0.47 s.

Therefore, the time period  of the wave is 0.47 seconds.

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Answer:

Its graph 1

Explanation:

She started at the origin and kept riding her bike until she stopped which causes the line to go staright because she's not moving.

Answer:

1 Answer. The Periodic Table can predict the properties of new elements, because it organizes the elements according to their atomic numbers. Creating new elements is not a simple process. Scientists use a particle accelerator to smash light atoms into a thin metallic foil that contains heavier atoms.

Explanation:

Answer: Brainliest?

Explanation:

Isobars and isotherms are both types of contour lines used to represent data on weather maps, specifically for atmospheric pressure and temperature, respectively.

The similarities between isobars and isotherms are:

Both are contour lines that connect points of equal value on a map.

Both are used to depict weather patterns and conditions.

Both help to identify areas of high and low values.

The differences between isobars and isotherms are:

Isobars connect points of equal atmospheric pressure, whereas isotherms connect points of equal temperature.

Isobars are measured in units of pressure such as millibars, while isotherms are measured in units of temperature such as degrees Celsius or Fahrenheit.

Isobars are typically used to show pressure patterns associated with wind, while isotherms are used to show temperature patterns.

Isobars are often used to forecast weather conditions, including the movement and intensity of storm systems. Isotherms are used to identify areas of warm and cold air masses, which can affect local weather patterns.

In summary, both isobars and isotherms are useful tools for understanding weather patterns, but they represent different types of data and are used for different purposes.

Isobars and isotherms are both concepts used in meteorology and climatology to represent important variables that help to describe atmospheric conditions. While they share some similarities, they also have several key differences.

Isobars refer to lines of equal pressure, meaning they connect points on a map or graph where the atmospheric pressure is the same. Isobars are drawn on weather maps to indicate areas of high and low pressure, and to show the general movement of air masses. When isobars are closely spaced, it indicates a steep pressure gradient, which can result in strong winds.

On the other hand, isotherms refer to lines of equal temperature, meaning they connect points on a map or graph where the temperature is the same. Isotherms are often drawn on weather maps to show the boundaries between warmer and cooler air masses, and to indicate areas where temperature changes rapidly.

One similarity between isobars and isotherms is that they are both used to describe atmospheric conditions in terms of spatial variation. They are also both used to infer information about the movement of air masses and the development of weather patterns.

However, there are also some key differences between isobars and isotherms. The most obvious difference is that isobars represent pressure while isotherms represent temperature. Additionally, while isobars are generally oriented parallel to each other and indicate the direction of winds, isotherms are typically oriented perpendicular to isobars and indicate the location of temperature gradients. Finally, while isobars are more commonly used to describe weather conditions associated with areas of high and low pressure, isotherms are often used to identify the location of fronts and other weather boundaries.

In summary, isobars and isotherms are similar in that they both describe atmospheric conditions in terms of spatial variation, and can be used to infer information about the movement of air masses and the development of weather patterns. However, isobars represent pressure and are oriented parallel to each other, while isotherms represent temperature and are oriented perpendicular to isobars.

Answer:

Volume of metal piece = 0.0069 m³ (Approx.)

Explanation:

Given:

Weight of metal in air = 300 N  

Weight of metal in water = 232.5 N

Find:

Volume of metal piece

Specific gravity of metal

Computation:

We know that;

Density of water = 1,000 kg/m³

Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water

Buoyant force applied on metal piece = 300 N - 232.5 N

Buoyant force applied on metal piece = 67.5 N

Buoyant force = Volume of metal x Density of water x Gravitational force

67.5 = Volume of metal x 1,000 x 9.8

Volume of metal piece = 0.0069 m³ (Approx.)

Answer:

B

speed.

Explanation:

hope it helps you

The momentum of first player can be given as,

The momentum of second player can be given as,

The total momentum of both the players can be given as,

Plug in the known expressions,

Substitute the known values,

Thus, the total momentum of both the players is 1531.7 Ns.

equal in magnitude but opposite in direction

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

Question Parameters:

Ladakh is 800 mb.

assuming that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level pressure we need to add,

Ps=800+350

Ps= 1150 mb

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The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

An 85.0 kg fishermen jumps from a dock into an135 kg boat at rest. If the velocity of the fisherman as he leaves the dock is 4.30 m/s west, what is the final velocity of the boat and fisherman together?

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer:

30 km/h

Explanation:

V=S:t

speed=length:time

150:5=30

Answer:

Normal force=7.48 N

Explanation:

N+F~1 sinθ-mg=0

=>N=1.5*9.8-12 sin37◦

=>N=14.7-7.22=7.48 N

Answer:

the mass of the reactants must equal the mass of product

The  temperature outside is 1.6 degrees Celsius

Charles's law, also known as the law of volumes, is a fundamental gas law that describes the relationship between the volume and temperature of a gas at a constant pressure.

It states that, for a fixed mass of gas at a constant pressure, the volume of the gas is directly proportional to its absolute temperature.

By the use of the Charlee's law;

V1/T1 = V2/T2

V1T2 = V2T1

T2 = V2T1/V1

T2 = 4.9 * 297/5.3

T2 = 1.6 degrees Celsius

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