Parallelogram P Q S R is shown. The length of P Q is (2 x + 5) centimeters and the length of R S is (4 x + 1) centimeters. In parallelogram PQSR, what is PQ

Answer:

53.1°

Step-by-step explanation:

Look at the right triangle formed. You are given the Hypotenuse and an adjacent side to the angle needed to calculate the measure of the arc.

To find measure of angle use Cosine

Once you find measure of angle (central angle), you'll have the measure of the arc because they are the same.

cos -1 (9/15)  = 53.13

Answer:

The CORRECT answer is cos

Step-by-step explanation:

It would read csc x cotx(1 - cos ^2 x)=cosx

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The required trigonometric function is cos x.

Given that cosec x cot x \((1-cos^{2}x )\).

By using trigonometric identities  \(cos^{2}x + sin^2x=1\),

that gives \(1-cos^2x=sin^2x\). -----(1)

By using the trigonometric functions,

cosec x = \(\frac{1}{sin x}\)    -------(2)

cot x = \(\frac{cos x}{sin x}\)    -----------(3)

By substituting equation 1, 2 and 3 in the given expression,

That implies, cosec x cot x \(sin^{2}x\) =  \(\frac{1}{sin x}\) × \(\frac{cos x}{sin x}\) × \(sin^2 x\)

On algebraic simplifying gives,

cosec x cot x \(sin^{2}x\) = \(\frac{cos x}{sin^2 x}\) × \(sin^2 x\)

On simplifying trigonometric functions gives,

cosec x cot x \(sin^{2}x\) = cos x.

Hence, the required trigonometric function is cos x.

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Answer:

I think the answer is D. 2

Answer:

The answer is A

Step-by-step explanation:

x is equal to - 4

so the the x is replaced by the- 4 and then you will group like- items

Divide both sides by - 5 to get - 2

The instantaneous velocity of the object at t = 6 is 2.

Suppose that s is the position function of an object, given as s(t) = 2t - 7. We compute the instantaneous velocity of the object at t = 6 as follows. Use exact values. First we compute and simplify (6 + h). s(6 + h) = 2(6 + h) - 7 = 12 + 2h - 7 = 2h + 5Then we compute and simplify the average velocity of the object between t = 6 and t = 6 + h.8(6+h) - s(6) h = 8(6 + h) - (2(6) - 7) h= 8h + 56

Then, to rationalize the numerator in the average velocity. (If it applies, simplify again.)$(6 + h) - $(6) h(h(h) + 56)/(h(h)) = (8h + 56)/h The instantaneous velocity of the object att = 6 is the limit of the average velocity as h approaches zero.s(6 + h) – $(6) v(6) lim h -0s(6 + h) – s(6) v(6) lim h -0Using the above calculation, we get:s(6 + h) – s(6) / h lim h -0s(6 + h) = 2(6 + h) - 7 = 2h + 5So,s(6 + h) – s(6) / h lim h -0(2h + 5 - (2(6) - 7)) / h= (2h + 5 - 5) / h = (2h / h) = 2

Therefore, the instantaneous velocity of the object at t = 6 is 2.

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Answer:

36 mph.

Step-by-step explanation:

Speed is a rate. It can be represented as the distance traveled/the time spent traveling.

\(s=d/t\)

In this problem, we know the distance and the time. All that needs to be done is some conversion and then plugging in.

In the problem, we know that Wendy travels 12 miles in 20 minutes. But to get her speed in miles per hour, we need to convert 20 minutes into hours.

To do this, let's set up a quick proportion. Let's call the number of hours in 20 minutes x.

I\(\frac{20minutes}{xhours}=\frac{60 minutes}{1 hour}\)

If there are 60 minutes in an hour, then there are 20 minutes in 1/3 of an hour.

Now we can plug 1/3 hours in.

\(s=\frac{12}{1/3}\)

This is the same as saying

\(s=12*3\)

\(s=36\)

Answer:

$20

Step-by-step explanation:

If you buy 4 pounds of chicken, you multiply 5.75 times 4. That gives you $23. You have a coupon for $3 off the final amount. $23-$3 = $20.

Answer:

20

Step-by-step explanation:

(5.75x4)-3

23-3

20

After analyzing all the critical paths  the maximum possible reduction in the project duration is 1 week. The correct option is d. 1 week.

To determine the maximum possible reduction in the project duration within the given budget, we need to analyze the critical paths and crashing costs.

The crashing cost per week for activity A is $540 in the first week and $1080 per week from the second week onwards. For activity E, it is $545 in the first week and $1350 per week thereafter. For all other activities, the crashing cost is $135 per activity per week in the first week and $405 per activity per week thereafter.

Considering the crashing budget of $2300, let's calculate the maximum reduction for each critical path:

A-B-C-D-E: The total crashing cost for this path is $1350 (for A and E) + $405 (for B, C, and D) = $1755 per week. With a budget of $2300, this path can be crashed for a maximum of $2300 / $1755 = 1.31 weeks. Therefore, the maximum reduction for this path is 1 week.

A-F-E: The total crashing cost for this path is $1350 (for E) + $405 (for F) = $1755 per week. With the given budget, this path can be crashed for a maximum of $2300 / $1755 = 1.31 weeks. Hence, the maximum reduction for this path is 1 week.

A-B-H-J-K-E: The total crashing cost for this path is $1350 (for A and E) + $810 (for B, H, J, and K) = $2160 per week. This path can be crashed for a maximum of $2300 / $2160 = 1.06 weeks. Thus, the maximum reduction for this path is 1 week.

A-S-T-E: The total crashing cost for this path is $1350 (for A and E) + $540 (for S and T) = $1890 per week. This path can be crashed for a maximum of $2300 / $1890 = 1.22 weeks. Hence, the maximum reduction for this path is 1 week.

After analyzing all the critical paths, we observe that the maximum possible reduction in the project duration is 1 week.

The correct option is d. 1 week.

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Answer:

The answer is C.

Answer:b

Step-by-step explanation:

Answer:

Value of \(p-q=1\)

Step-by-step explanation:

We need to find \(p-q\)

\(p-q=14-13\\\\=1\)

\(\huge\boxed{\sf{Hello\:there!}}\)

We are asked to evaluate p-q.

Now, if we aren't given the value of every variable, evaluating this expression is impossible. However, we do have the value of p (14) and the value of q (13)

We plug these numbers instead of the variables:

p-q

p=14

q=13

14-13

1

Hence, the value of the expression is 1.

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\(\huge\mathfrak{LoveLastsAllEternity}\)

The equation that represents the graph is y = -(2/3)x + 6 .

The X- intercept is defined as the point at which the line crosses the x axis.

The Y- intercept is defined as the point at which the line crosses the y axis.

When a and b are the x and y intercept of a line then

the equation of line in intercept form is x/a + y/b = 1 .

Form the graph in the question

we can see that the graph crosses the x axis at 9, so it's x intercept is 9.

and the graph crosses the y axis at 6, so it's y intercept is 6.

So the intercept form of the line will be given by

x/9 + y/6 = 1

taking LCM of 6 and 9 as 18 ,

and solving further we get ,

2x/18 + 3y/18 = 1

(2x + 3y)/18 = 1

2x + 3y = 18

3y = 18 - 2x

Dividing both sides by 3 , we get

y = 18/3 - (2/3)x

y = 6 - (2/3)x

y = -(2/3)x + 6

Therefore , the equation that represents that represents the graph is                  y = -(2/3)x + 6 .

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The solution to the differential equation is y(t) = -1/4 cos(4t) - sin(4t).

The characteristic equation is r^2 + 16 = 0, which has solutions r = ±4i. Thus the general solution to the differential equation is

y(t) = c1 cos(4t) + c2 sin(4t).

Using the initial conditions, we have

y(π/8) = c1 cos(π/2) + c2 sin(π/2) = c2 = -1,

and

y'(t) = -4c1 sin(4t) + 4c2 cos(4t),

so

y'(π/8) = -4c1 sin(π/2) + 4c2 cos(π/2) = 4c2 = 4.

Thus, c2 = -1 and c1 = -1/4, so the solution to the differential equation is

y(t) = -1/4 cos(4t) - sin(4t).

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\(y \geqslant - x + 3\)

\(y < \frac{1}{2} x + 3 \\ \)

now just put the coordinates of point ( 1 , 1 ) in the above inequalities and check if they correct or wrong :

\(1 \geqslant - 1 + 3\)

\(1 < \frac{1}{2} (1) + 3 \\ \)

So :

\(1 \geqslant 2\)

\(1 < 3.5\)

1 is lower than 3.5 of course but geuss what ?

Is 1 higher than 2 or equal to 2 ? Nope not at all

Thus the correct answer would be :

" no , it is not a solution "

The probability in question is a right-tail probability because it is asking for the probability that the mean bond percent for the sample will be at least 28 percent, which is greater than the mean of 26.9 percent.

To calculate the probability, first find the z-score:
z = (sample mean - population mean) / (population standard deviation / sqrt(sample size))
z =\( (28 - 26.9) / (3.6 / sqrt(35))\)
z = \( 1.1 / (3.6 / 5.916)\)
z =\(  1.1 / 0.608\)
z ≈ \( 1.809\)

Using the z-table, the area to the left of this z-score is 0.965. Since we are looking for the right-tail probability, we need to subtract this value from 1:
Probability = 1 - 0.965
Probability ≈ 0.035

Thus, the probability that the mean bond percent for the sample will be at least 28 percent is approximately 0.035. The correct answers are right-tail probability and 0.035.

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Answer: $7.65 for a dozen/12

Step-by-step explanation: 2.55 x 3

Answer: (-3,5)

Step-by-Step Solution:

1. Set 1 equation equal to y

3y-2x=21

3y=2x+21

y=2/3x+7

2. Set the other equation equal to y

4y+5x=5

4y=-5x+5

y=-5/4x+5/4

3. Set the equations equal to each other, and solve for x

2/3x+7=-5/4x+5/4

2/3x+23/4=-5/4x

(Multiply by 12 on both sides to get rid of fractions)

8x+69=-15x

8x=-15x-69

23x=-69

x=-3

4. Solve for y

(Choose any of the equations)

y=2/3x+7

y=2/3(-3)+7

y=-2+7

y=5

ANSWER: (-3,5)

Answer:

5894 seconds

Step-by-step explanation:

Convert  1 hour 38 min 14 seconds to seconds​

1 hour = 3600 seconds

1 min = 60 seconds

38 mins = 60 x 38 = 2280 seconds

Now add all numbers together

3600 + 2280 + 14 = 5894 seconds

So, 1 hour 38 minutes 14 seconds is 5894 seconds.

Answer:

The ratio of 2 times x minus three to 5

Step-by-step explanation:

Fractions can be represented as ratios: for instance, X/Y can be represented as x : y

Answer:

7x+y=-5

Step-by-step explanation:

-y=7x+5

7x+y=-5

Answer:

Step-by-step explanation:

T + 3 = 17 - 5

T + 3 = 12

T = 12 - 3

T = 9

Answer:

T = 9

Step-by-step explanation:

Lets evaluate

T + 3 = 17 - 5

T + 3 = 12

T = 12 - 3

T = 9

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The probability of both A and B occurring is 0.15.

The probability of both A and B occurring can be found using the formula P(A∩B) = P(A) + P(B) - P(A∪B), where P(A∩B) is the probability of both A and B occurring, P(A) is the probability of A occurring, P(B) is the probability of B occurring, and P(A∪B) is the probability of either A or B occurring.

Plugging in the given values, we get:

P(A∩B) = 0.50 + 0.45 - 0.80

P(A∩B) = 0.95 - 0.80

P(A∩B) = 0.15

Therefore, the probability of both A and B occurring is 0.15.

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Answer:

6

Step-by-step explanation: 12 x 5 = 60

One tenth of 60 is *6

Check the picture below.

Answer:

14.1

Step-by-step explanation:

You add all of your numbers up, and then you divide by how many numbers you have.

Answer:

a couple different obes

Step-by-step explanation:

there are five

The high temperature for today using a 3-day moving average is 92 degrees.

To calculate the high temperature for today using a 3-day moving average, we take the average of the temperatures from the past three days, including today.

Given the daily high temperatures in St. Louis for the last week:

92, 92, 93, 95, 95, 86, 95 (yesterday)

To find the 3-day moving average for today's high temperature, we consider the temperatures from yesterday, the day before yesterday, and three days ago.

(95 + 86 + 95) / 3 = 92

Therefore, the high temperature for today, calculated using a 3-day moving average, is approximately 92 degrees Fahrenheit, rounded to one decimal place.

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Answer:

5/27

30/81 = 10/17

it's just ratios but if you need then vice versa, swap numerator and denominator

Answer:

the person on top is correct :)

Step-by-step explanation:

Answer:

To find the value of a4, we need to use the recursive formula for the sequence. The formula gives us the nth term in the sequence in terms of the (n-1)th term.

We are given that a1 = -7, so we can use the recursive formula to find a2, a3, and a4:

a2 = a1 - 4 = -7 - 4 = -11

a3 = a2 - 4 = -11 - 4 = -15

a4 = a3 - 4 = -15 - 4 = -19

Therefore, the value of a4 is -19.

The weight of the circle that is double the weight of the triangle is 20 grams.

The weight of the rectangle is 80 grams.

The weight of the triangle is double the weight of the  weight of the circle.

A rectangle is made up of 2 triangles. Therefore,

weight of each triangle = 80 / 2 = 40 grams

Since, the weight of the triangle is double the weight of the circle, the weight of the circle can be calculated as follows:

weight of circle = 40 / 2

Therefore,

weight of the circle = 20 grams.

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Answer:

9x^2 + 17x

Step-by-step explanation:

(5x - 2)(2x + 3)-3(x - 1)^2

12x^2 + 15x - 4x - 6 -3(x - 1)^2

12x^2 + 11x - 6 - 3(x^2-2-2x)

12x^2 + 11x - 6 - 3x^2 + 6 + 6x

9x^2 + 17x

Answer:

c/sin(60°) = 14/sin(25°)

c = 14sin(60°)/sin(25°) = 28.7

depending on the size of both i would say 3 inches

Step-by-step explanation: