Our best measurements from Earth indicate that the star system Alpha Centauri is 4.2 lightyears (ly) away: Suppose some of our astronauts traveled there at a speed v 0.95c. What would the astronauts measure as the distance to Alpha Centauri? 75.2 ly 5.2 ly 56.5 ly 1.3 ly 2.6 ly

Answer:

C. 28.2 deg

Explanation:

The horizontal range of a projectile is given as:

\(R = \frac{v^2Sin2\theta}{g}\)

where,

R = Range

v = speed

θ = angle of launch

g = acceleration due to gravity = 9.81 m/s²

First, we will find the launch speed (v) by using the initial conditions:

R = 120 m

θ = 45°

Therefore,

\(120\ m = \frac{v^2Sin 90^o}{9.81\ m/s^2}\\\\v = \sqrt{(120\ m)(9.81\ m/s^2)}\\\\v = 34.31\ m/s\)

Now, consider the second scenario to hit the target:

R = 100 m

Therefore,

\(100\ m = \frac{(34.31\ m/s)^2Sin2\theta}{9.81\ m/s^2}\\\\Sin2\theta = \frac{(100\ m)(9.81\ m/s^2)}{(34.31\ m/s)^2}\\\\2\theta = Sin^{-1}(0.833)\\\\\theta = \frac{56.44^o}{2}\\\theta = 28.22^o\)

Hence, the correct option is:

C. 28.2 deg

Two resistors have resistances r(smaller) and r(larger), where r(smaller) When the resistors are connected in series to a 12.0-V battery, the current from the battery is 1.13 A. When the resistors are connected in parallel to the battery, the total current from the battery is 10.6 A.the two resistances are 2.40 Ω and 8.30 Ω.

The current through both resistors is the same, and can be found using Ohm's law:

I_series = \(\frac{V}{R}\)_series

where V is the voltage of the battery. We are given that I_series = 1.13 A and V = 12.0 V, so we can solve for R_series:

R_series = \(\frac{V}{I}\)_series = 12.0  \(\frac{V}{I}\) 1.13 A = 10.62 ΩWhen the resistors are connected in parallel, the total resistance is:

\(\frac{1}{R}\)_parallel = 1/r(smaller) + 1/r(larger)

The total current from the battery is the sum of the currents through each resistor:

I_parallel = \(\frac{V}{R}\)_parallel

where V is the voltage of the battery. We are given that I_parallel = 10.6 A and V = 12.0 V, so we can solve for R_parallel:

R_parallel =  \(\frac{V}{I}\)_parallel = 12.0 V / 10.6 A = 1.13 Ω

Now we have two equations with two unknowns (r(smaller) and r(larger)):

R_series = r(smaller) + r(larger)

1/R_parallel = 1/r(smaller) + 1/r(larger)

We can solve for r(smaller) and r(larger) using algebra. Rearranging the first equation, we get:

r(larger) = R_series - r(smaller)

Substituting this expression into the second equation and simplifying, we get:

1/R_parallel = 1/r(smaller) + 1/(R_series - r(smaller))

Multiplying both sides by r(smaller)(R_series - r(smaller)), we get:

r(smaller)(R_series - r(smaller))/R_parallel = R_series - r(smaller) + r(smaller)

Simplifying, we get:

\(r(smaller)^{2}\) - R_series r(smaller) + R_series/R_parallel = 0

Using the quadratic formula, we get:

r(smaller) = [R_series ± \(\sqrt{(R_series^2 - 4R_series/R_parallel)}\)] / 2

Plugging in the values for R_series and R_parallel, we get:

r(smaller) = [10.62 Ω ± \(\sqrt{(10.62^2 - 4(10.62/1.13))}\)] / 2 = 2.40 Ω or 8.30 Ω

Since r(smaller) is the smaller resistor, it must be 2.40 Ω and r(larger) must be 8.30 Ω.

Therefore, the two resistances are approximately 2.40 Ω and 8.30 Ω.

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Answer:

C?

Explanation:

I think its c cuz the character would be falling and cakes don't bounce when they fall, they just splat

also can we pretend i was watching demon slayer when this happens

Using the theories of protonephridia, we got that  the statements about the protonephridia of freshwater flatworms which is accurate is e)Fluid from the body enters the protonephridia without first being filtered.

The flame cell is a specialized excretory cell found in the simplest freshwater invertebrates, including flatworms, rotifers, and the nemerteans. Bundles of the flame cells are called Protonephridia. Protonephridia helps in the osmoregulation or ion-regulation. They are also helpful in the excretion.

Protonephridium is the network of dead-end tubules lacking internal openings found in the phyla Platyhelminthes, Nemertea

Hence, the  the statements about the protonephridia of freshwater flatworms is accurate is option e) Fluid from the body enters the protonephridia without first being filtered.

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Explanation:

20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

Answer:

Option C as it stops flies from sitting on the food

v=λf

v=0.5 x 100

v = 50 m/s

A child has an ear canal that is 1. 3 cm long. Sound frequencies in the audible range for the child to have increased hearing sensitivity is 6600 Hz to 19,800 Hz

The shape of the human ear is similar to a pipe that has a closed end and other end is open. Hence,

λ = 4L where L is the length of child's ear

Wavelength, λ = 4 × Length of the ear of the child

                     λ = 4 × 0.013m

                     λ = 0.052m

Frequency is the no. of oscillations per unit time.

The frequency of the sound, ν = c/λ

where c is the speed of sound i.e. 343 m/s

           λ is the wavelength of sound

The child's audible range is equal to

ν = 343/0.052

ν = 6600Hz

We can also say that, ν is 13200 Hz or 19,800 Hz.

In general, the audible range of frequency for human ear is 20Hz to 20,000Hz.

Hence, sound frequencies in the audible range will the child have increased hearing sensitivity is 6600Hz to 19800 Hz.

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Answer:

b. has landforms made by flowing liquid water

- has many huge on its surface

- gets its red color from iron oxide present in soil and rocks on surface

- reflects light from sun

Explanation:

To find Jupiter's magnetic dipole moment, we must use the formula given below:M = B × r³ ÷ 2μ₀Where:M = Magnetic dipole momentB = Magnetic field strengthr = Radius of the planetμ₀ = Magnetic constantFirst.

Given that the magnetic field strength at Jupiter's poles, B = 1.4 mT = 0.0014 TNow, the radius of Jupiter is approximately 71,492 km = 7.1492 x 10⁷ mWe can assume that Jupiter's magnetic field can be approximated by that of a dipole, so:μ₀ = 4π × 10⁻⁷ T m/A.

The magnetic dipole moment of Jupiter using the given formula:M = B × r³ / 2μ₀M = 0.0014 T × (7.1492 × 10⁷ m)³ ÷ 2(4π × 10⁻⁷ T m/A)M ≈ 1.59 × 10²² A m²Therefore, the magnetic dipole moment of Jupiter is approximately 1.59 × 10²² A m².

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When one mole of ammonium is mixed with 5 moles of ammonium sulfate, there are 10 ammonium ions present.

When one mole of ammonium is mixed with 5 moles of ammonium sulfate, we need to determine how many ammonium ions are present.

First, let's determine the chemical formula of ammonium sulfate. Ammonium has a chemical formula of NH4+, and sulfate has a chemical formula of SO4^2-. To balance the charges, we need two ammonium ions for every sulfate ion. Therefore, the chemical formula of ammonium sulfate is (NH4)2SO4.

Next, we need to determine the number of moles of ammonium sulfate present when one mole of ammonium is mixed with 5 moles of ammonium sulfate. Since the molar ratio between ammonium and ammonium sulfate is 1:5, we can multiply the number of moles of ammonium by the ratio.

So, 1 mole of ammonium * 5 moles of ammonium sulfate/1 mole of ammonium = 5 moles of ammonium sulfate.

Finally, we need to determine the number of ammonium ions present in 5 moles of ammonium sulfate. Since there are 2 ammonium ions per mole of ammonium sulfate, we can multiply the number of moles of ammonium sulfate by 2.

So, 5 moles of ammonium sulfate * 2 ammonium ions/mole of ammonium sulfate = 10 ammonium ions.

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Answer:

- maintain its state of motion

- Keep its velocity constant (either at zero or non-zero value)

Answer:

Yes, the magnet force will cause the motor rotate through a full rotation. So the friend who claims to have built a motor by attaching a shaft to the core of a galvanometer and removing the spring is correct.

Answer:

The answer to your question is the Photoelectric effect.

Explanation:

The speed of flow of water at the lower level is 13.9 m/s.

The speed of flow of water at the lower level can be calculated using the equation of continuity, which states that the product of the cross-sectional area and the speed of flow of a fluid is constant in a closed system.
We can begin by using the given values for the initial speed of flow and the cross-sectional area to calculate the initial volume flow rate of water through the pipe.
Volume flow rate = speed x cross-sectional area
Volume flow rate = 27.8 m/s x 0.0004 m2
Volume flow rate = 0.01112 m3/s
Since the pipe's cross-sectional area increases by a factor of two, the cross-sectional area at the lower level is 8.0 cm2. We can use the equation of continuity to find the speed of flow at the lower level.
Volume flow rate = speed x cross-sectional area
0.01112 m3/s = speed x 0.0008 m2
speed = 13.9 m/s
Therefore, the speed of flow of water at the lower level is 13.9 m/s.

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Answer:

73.1 m/s

Explanation:

Given:

Δx = 160 m

v = 6.9 m/s

t = 4 s

Find: v₀

Δx = ½ (v + v₀) t

160 m = ½ (6.9 m/s + v₀) (4 s)

v₀ = 73.1 m/s

The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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Answer:

Writing of a story that ends with the character becoming poor with no friends.

Explanation:

There was a young girl who believed that all things revolve around her. She had the money, the power, the family, and the beauty to ensure she was the center of attention. She would always be the main focus, everywhere she goes.

But there came a time when she had a major misfortune. Her family had come upon unfortunate times. They are going to lose their money and may even be jailed for embezzlement. It was true that she had no idea what her parents had done but she was also so familiar with the 'princess' lifestyle that she did not know how to downgrade her lifestyle. And so, when this misfortune happened, she was unsure how to react. She also assumed that her friends will be there for her. Little did she know everyone was just after her wealth and influence and had nothing to do with genuine friendship.

In a few months, their family position moved from top to bottom, which everyone found hard to accept. She had to maintain her status while at the same time try to live up with that without losing her circle. But as rumors spread fast and she wasn't able to spend the way she would normally send, she eventually experienced a dwindled friend circle. And in about a year, she had lost all of her friends, couldn't even convince someone to stay with her faithfully and worse of all, she was also poor, the very status she had degradingly taunted other people with.

The main answer to your question is that the sign of the torque τw due to the rod's weight with the given choice of axis and counterclockwise torques being positive is (a) Negative.

When a torque is generated due to the weight of the rod acting downward, it tends to create a clockwise rotation around the axis, which is the opposite of the given counterclockwise positive direction.

Therefore, the torque τw is considered negative in this case.

Summary: With the choice of axis and counterclockwise torques being positive, the sign of the torque τw due to the rod's weight is negative.

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Collisions between two balls can change their angular velocities, with possible scenarios including equal angular velocities, a valid equation co^xdg, or the term "myj" not relevant. The equation co^xdg does not describe the relationship between angular velocities after the collision, and the term "myj" has no significance.

When two balls, A and B, collide with each other, their angular velocities can change depending on the specific conditions of the collision. Let's examine the possible scenarios:

(a) Both balls have the same angular velocities after the collision:
In some cases, when the collision is perfectly elastic and the balls have similar masses and moments of inertia, their angular velocities can become equal after the collision. This means that both balls will rotate at the same speed.

(b) The angular velocities of the balls are given by the equation co^xdg:
The equation co^xdg does not represent a valid expression for the angular velocities after the collision. It appears to be a combination of the symbols co^ (angular velocity of ball A) and dg (angular velocity of ball B), but it does not provide any meaningful information about their relationship after the collision.

(c) The term "myj" does not appear to have any relevance to the question or the concept of angular velocities after a collision.

In summary, after the collision of two balls with initial angular velocities co^ and tog, the outcome can vary. It is possible for both balls to have the same angular velocities if the conditions are appropriate. However, the equation co^xdg does not describe the relationship between the angular velocities after the collision, and the term "myj" does not have any significance in this context.

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Option b. 4.86 million km2 of sea ice would remain in 2020 if the decline rate continued at 10% per decade.

Ocean ice is a significant piece of the World's environment framework, reflecting daylight and managing the planet's temperature. Be that as it may, environmental change has caused a decrease in how much ocean ice over ongoing many years, with a typical decay pace of around 10% each 10 years. This intends that for each decade that passes, how much ocean ice remaining is 90% of the earlier ten years' sum.

To work out how much ocean ice would stay in a specific year, we can utilize the recipe: remaining ice = (1-0.1)^n * beginning ice, where n is the quantity of many years that have passed and starting ice is how much ocean ice in the beginning year. For instance, in the event that there were 6 million km2 of ocean ice in the year 2000 and 20 years (twenty years) have passed, we can compute the excess ice in 2020 as follows: remaining ice = (1-0.1)^2 * 6 million km2, which approaches around 4.86 million km2.

This computation features the huge loss of ocean ice over a generally brief timeframe, with practically 20% of the ice vanishing more than twenty years. This deficiency of ocean ice has extensive ramifications for worldwide environment examples, natural life, and human networks living in the Cold.

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The complete question is:

every decade, the sea ice declines by 10 percent. if there were 6 million km2 of sea ice in the year 2000, how much would remain in 2020? group of answer choices are a. 7.85 b.4.86 c. 6.80 d. 3.67

========================================================

Explanation:

At 0 Kelvin, we're at the coldest temperature possible which is referred to as absolute zero. We cannot get any colder than this. At this temperature, the molecules aren't moving or vibrating to provide heat energy. The higher the temperature, the more the molecules are moving or vibrating.

The 0 degree mark on the Celsius scale is well above absolute zero. So that allows for negative Celsius temperatures to be possible. The same can be said about Fahrenheit as well. We cannot have negative Kelvin temperatures.

Answer:

(a)3.09 m/sec (b)θ= 35.28° (c) t =3.43 sec

Explanation:

Solution

Given that:

The swimming speed of swimmer =5.35 m/s

The downstream angle = 30°

Now,

(a)we find speed of the current which is given below:

V = V swimmer + V river

Tan 30° = Vr/Vs

Thus

Vr = 5.35 * tan 30°

Vr = 5.35 * 0.5773

= 3.09 m/sec

(b)She would have velocity at direction such that she reaches across the shore

Then

Vs sin θ =Vr

sin θ = Vs/Vr

sin θ = 3.09/5.35

θ= 35.28°

Therefore, She had to make θ= 35.28° on another side of the river

(c) Thus

t = d/Vs cosθ

=15/5.35 * cos (35.28°)

t =3.43 sec

The threshold wavelength for emission from a metallic surface is 500 nm and the work function for that particular metal is \(3.98 \times 10^{-19} J\).  The maximum speed of a photoelectron produced by each of the following wavelengths of light i) 400 nm is 8.2x10⁵ m/s ii) 500 nm is 5.16 x 10⁵ m/s and iii) 600 nm is 3.41 x 10⁵ m/s.

The work function of the metal can be given by the formula; hf = Φ + KE. Here, Φ is the work function of the metal and KE is the maximum kinetic energy of the photoelectron. The threshold frequency for the metal can be given as; f = c / λ. 500 nm is the threshold wavelength for the emission of electrons from the metallic surface. So, the corresponding frequency can be calculated as;

\(f = (3 \times 10^8) / (500 \times 10^{-9}) = 6 \times 10^{14} Hz\). The value of the plank constant can be taken as; h = \(6.63 \times 10^{-34} Js\). Now, the work function of the metal can be calculated as;
hf = Φ + KEΦ = hf - KE =\((6.63 \times 10^{-34}) \times (6 \times 10^{14}) - 0 = 3.98 \times 10^{-19} J\)

(b) Calculate the maximum speed of a photoelectron produced by each of the following wavelengths of light:
i) 400 nm) The frequency of the light is given by; f = c / λf \(= (3 \times 10^8) / (400 \times 10^{-9}) = 7.5 \times 10^{14} Hz.\).
The maximum kinetic energy of the photoelectron is given by;

KE = hf - ΦKE =\((6.63 \times 10^{-34}) \times (7.5 \times 10^{14}) - 3.98\times 10^{-19} = 3.61 \times 10^{-19} J.\)
The maximum speed of the photoelectron can be given by;
KE = 1 / 2 mv². So. v = √(2KE / m).
So, \(v = \sqrt {(2 \times 3.61  \times 10^{-19} / 9.1  \times 10^{-31})} = 8.2 \times 10^5 m/s.\)
ii) The frequency of the light is given by; f = c / λf \(= (3 \times 10^8) / (500 \times 10^{-9})= 6 \times 10^{14} Hz\).
The maximum kinetic energy of the photoelectron is given by;
KE = hf - ΦKE =\((6.63 \times 10^{-34}) \times (6 \times 10^{14}) - 3.98 \times 10^{-19} = 1.65 \times 10^{-19} J.\).
The maximum speed of the photoelectron can be given by; v = \(\sqrt {(2 \times 1.65 \times 10^{-19} / 9.1 \times 10^{-31})} = 5.16 \times 10^5 m/s\)
iii) The frequency of the light is given by; f = c / λf = \(= (3 \times 10^8) / (600 \times 10^{-9})= 5 \times 10^{14} Hz\),
The maximum kinetic energy of the photoelectron is given by;
KE = hf - ΦKE = \((6.63 \times 10^{-34}) \times (5 \times 10^{14}) - 3.98 \times 10^{-19} = 9.62 \times 10^{-20} J.\).
The maximum speed of the photoelectron can be given by; v = \(\sqrt {(2 \times 9.62 \times 10^{-20} / 9.1 \times 10^{-31})} = 3.41 \times 10^5 m/s\).

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Explanation:

initial velocity=0

final velocity=40m/s

time=50s

acceleration=?

now,

a=v-u/t

a=40-0/50

a=40/50

a=0.8m/s^2

answer

Answer:

C. electron

Explanation:

the magnetic field produces whenever an electric charge is in motion

The magnetic force of a material comes from the spinning of electrons. Electrons have a property called "spin" which is a type of intrinsic angular momentum. The correct option is E. electronr.

This spin generates a magnetic dipole moment, which causes the electron to act like a tiny magnet. When these magnetic dipoles are oriented in the same direction, they can create a macroscopic magnetic field, such as in the case of a magnet.

The behavior of these magnetic dipoles can be manipulated by external magnetic fields, leading to various magnetic phenomena.

Therefore, the spinning of electrons (option E) is responsible for the magnetic properties of materials.

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