If we know the stall torque and no load speed of a pm dc motor, the maximum power motor can deliver is P max = 1/2* Tstall * 1/2* ω(no load).
A mechanical device that produces stall torque has an output rotational speed of zero. Electric motors are capable of developing torque when stalled.
However, as the current flowing is at its maximum while an electric motor is halted, they are vulnerable to overheating and potential damage.
The no load speed is the speed when running at nominal voltage and zero load.
So, the maximum power motor can deliver is P max = 1/2* Tstall * 1/2* ω(no load).
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If the density of an object is 9.331 x 10−2 lbs/cubic inch, what is its density in g/cm3?
A substance's density is defined as its mass per unit of volume. Density is most frequently represented by the symbol ρ, however Latin letter D may also be used.
If the density of an object is 9.331 x 10−2 lbs/cubic inch, what is its density in g/cm3?
9.331 x 10−2 lbs/cubic inch = 258 281 190,85 g/m³
To calculate the density:
Determine an object's weightFind out an object's volume.Weight to volume ratio.Alternately, switch the unit.The following is the density formula:
D = m/v, where D = Density, m = mass, v = volume.
Write down the data and the density equation, solve for the mass, add the density to the volume, then multiply the result to get the density in grams.
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a circuit breaker is tripped when the current in the circuit is greater than 15 A. If the voltage difference is 120, what is the power being used when the circuit breaker is tripped?
Answer:
The answer would be 1800W
Explanation:
P=15a × 120 V
What is the maximum electric field strength in an electromagnetic wave that has a maximum magnetic field strength of (about 10 times earth’s magnetic field)?
The maximum electric field strength in an electromagnetic wave that has a maximum magnetic field strength of 5 × 10^-4 T (about 10 times earth’s magnetic field) is 15 × 10^4 V/m
Given,
Maximum magnetic field strength, \(B_{max}\) = 5 × 10^-4 T
Then,
Maximum electric field strength, \(E_{max}\) = \(B_{max}\) c
Where, c is the speed of light
Substituting all values in formula, we get,
\(E_{max}\) = 5 × 10^-4 × 3 × 10^8
= 15 ×× 10^4 V/m
Concept
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An object moving in a circle is represented by the motion map.An illustration of a circle with four black dots on the top labeled W, bottom labeled Y, left labeled Z and right labeled X of the circle. Each dot has a vector toward the center of the circle of equal length and a vector tangent to the circle in a counterclockwise direction of equal length.Based on the map, at which point is the object accelerating toward the right?WXYZ
Since this is a circular motion, we know that the we have a centripetal acceleration; we know that this type of acceleration always points towards the center of the circle. This means that the acceleration is represented by the vectors that point towards the center. Looking at them we notice that at point Z the acceleration is pointing to the right.
Therefore, the object is accelerating to the right at Z
A Bar Suspended by Two Vertical Strings
The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 80.00kg and length L = 5.100m is supported by two vertical massless strings. String A is attached at a distance d = 1.200m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500kg is supported by the crane at a distance x = 4.900m from the left end of the bar.
Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.
Find TA, the tension in string A. Express your answer in newtons using four significant figures.
Find TB, the magnitude of the tension in string B. Express your answer in newtons using four significant figures.
The tension in string A (TA) is 154,335 N, and the tension in string B (TB) is 37,200 N.
Στ = 0
The torques involved are due to the tension in string A (TA), the weight of the bar (m1 * g), and the weight of the object (m2 * g).
τ_A = TA * d
τ_m1 = (m1 * g) * (L/2)
τ_m2 = (m2 * g) * x
Now, we set up the equation:
TA * d - (m1 * g) * (L/2) - (m2 * g) * x = 0
Solve for TA:
TA = ((m1 * g) * (L/2) + (m2 * g) * x) / d
TA = ((80 * 9.807) * (5.1/2) + (3500 * 9.807) * 4.9) / 1.2
TA = 154335.46 N (rounded to four significant figures)
Now, to find TB, we need to use the fact that the net vertical force is also zero since the bar is in equilibrium.
ΣFy = 0
TB - TA - m1 * g - m2 * g = 0
Solve for TB:
TB = TA + m1 * g + m2 * g
TB = 154335.46 + (80 * 9.807) + (3500 * 9.807)
TB = 37199.60 N (rounded to four significant figures)
Hence, the tension in string A (TA) is 154,335 N, and the tension in string B (TB) is 37,200 N.
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What do we call the study of solar system and the objects in it.
Answer:
I'm pretty sure it's called Astronomy
Explanation:
Hope this helps:)...if not then sorry for wasting your time and may God bless you:)
Answer: Astronomy
Explanation: Astronomy is objects we can see with our eyes, like the Sun , the Moon , the planets, and the stars . It also includes objects we can only see with telescopes or other instruments, like faraway galaxies and tiny particles.
I hope this helps ;o o;
How is blue colour made?
Answer:
In terms of the light spectrum, blue is a primary color, which means that it is one of the base colors that exist in the universe and it cannot be created by combining different colors together. The primary pigment colors are cyan, magenta, and yellow. Cyan absorbs red, yellow absorbs blue, and magenta absorbs green.
Explanation:
Hope this helped Mark BRAINLEST!!!
f ( 9 ) = 42.5 . what does this tell us about the numerator and denominator of f ?
The given information, f(9) = 21.5, tells us that when x = 9, the numerator, x² + 5, is equal to 21.5 times the denominator, (x - 5). The answer is D.
We are given f(x) = x² + 5 / (x - 5).
Substituting x = 9 into the expression, we get f(9) = (9² + 5) / (9 - 5).
Simplifying further, we have f(9) = (81 + 5) / 4 = 86 / 4 = 21.5.
Therefore, when x = 9, the numerator (x² + 5) is equal to 21.5 times the denominator (x - 5). This relationship is specific to the value of x = 9, and it does not hold true for all values of x. Hence, D is the answer.
The complete question is:
Suppose that f(x) = x² + 5 / (x - 5). Notice that f(9) = 21.5. What does this tell us about the numerator and denominator of f?
A. When x = 9, x - 5 is 21.5 times as large as x² + 5.
B. When x = 21.5, x² + 5 is 9 times as large as x - 5.
C. x² + 5 is always 21.5 times as large as x - 5.
D. When x = 9, x² + 5 is 21.5 times as large as x - 5.
E. When x = 9, x² + 5 is equal to 21.5.
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what piece of lab equipment is used to measure volume
A graduated cylinder is used to measure volume in a laboratory setting.
A graduated cylinder is a cylindrical container with volume markings along its length. It is made from glass or plastic and is designed to accurately measure the volume of liquids. To use a graduated cylinder, the liquid is poured into the cylinder, and the volume is read by aligning the bottom of the meniscus (the curved surface of the liquid) with the appropriate marking on the cylinder. The graduated markings on the cylinder allow for precise volume measurements, making it a common tool in chemistry, biology, and other scientific disciplines where accurate volume measurements are required.
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Astronauts appear weightless while working in the International Space Station because
A) they are in a state of free fall.
B) there isn't any gravity in outer space.
C) they have very little mass when in outer space.
Eliminate
D) they have gravitational attractions to the sun and moon
A) they are in a state of free fall.
A point charge q1=5. 00μC is held fixed in space. From a horizontal distance of 8. 00 cm, a small sphere with mass 4. 00×10−3kg and charge q2=+2. 00μC is fired toward the fixed charge with an initial speed of 35. 0 m/s. Gravity can be neglected.
What is the acceleration of the sphere at the instant when its speed is 27. 0 m/s
According to the given statement , the acceleration of the sphere at the instant when its speed is 27.0 m/s.
We can use the principles of electrostatics and kinematics. a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
1. Determine the electric force between the two charges:
- The electric force between two charges can be calculated using Coulomb's Law:
F = k * |q1 * q2| / r².
- In this case, q1 = 5.00 μC and q2 = +2.00 μC. The distance between them, r, is the horizontal distance of 8.00 cm (which is 0.08 m).
- The constant k is 9.00 x 10⁹ N * m^2 / C².
- Plugging in the values, we get F = (9.00 x 10^9 N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)².
2. Calculate the net force acting on the sphere:
- At any instant, the net force acting on the sphere is the sum of the electric force and the force due to gravity.
- However, in this case, gravity can be neglected, as stated in the question.
- Therefore, the net force acting on the sphere is equal to the electric force between the two charges.
3. Calculate the mass of the sphere:
- The mass of the sphere is given as 4.00 x 10⁻³ kg.
4. Apply Newton's second law:
- Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
- In this case, the net force acting on the sphere is the electric force between the charges.
- Plugging in the values, we get (9.00 x 10⁹ N * m^2 / C²) * |5.00 μC * 2.00 μC| / (0.08 m)² = (4.00 x 10⁻³ kg) * a.
5. Solve for the acceleration:
- Rearranging the equation, we have a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
- Evaluating the expression, we find the value of acceleration.
By following these steps, you can find the acceleration of the sphere at the instant when its speed is 27.0 m/s.
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This image shows layers underground.
Top to bottom: Soil, Clay, Rocks, Granite.
Which layer will become saturated first when rain falls?
clay
granite
rocks
soil
Answer:
soil
Explanation:
CORRECT
Answer:
soil
Explanation:
Hope this will help
Several radio telescopes are combined into an interferometer in order to1) observe over a wider range of frequencies. 2) observe astronomical objects during daylight hours when the sky is otherwise too bright. 3) decrease the strength of the signal transmitted. 4) decrease the smallest angle which can be observed by the telescope.
Several radio telescopes are combined into an interferometer in order to 2) observe astronomical objects during daylight hours when the sky is otherwise too bright.
Why is an interferometer made of many radio telescopes?Radio astronomers may combine the signals from several antennas and even telescopes using interferometry. They are able to produce images that are more brighter and more precise than what is feasible with only one antenna dish.
To investigate objects in space, astronomers utilize a variety of telescopes sensitive to various regions of the electromagnetic spectrum. Despite the fact that all light is fundamentally the same, astronomers view light differently depending on the part of the spectrum they are interested in.
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The radius of the sun is 695,700 km and the mass of the sun is 2x1030 kg. What would the force of gravity be on a 60 kg person "standing" on the surface of the sun? What is the acceleration of gravity at the surface of the sun?
a) The gravitational force is 1.7 * 10^4 N.
b) The acceleration due to gravity is 277 m/s^2.
What is the gravitational force?We know that the gravitational force is the force of attraction that acts in the universe between any two masses that are close to each other. We can see that we have the following information;
Mass of the sun = 2 x 10^30 kg
Mass of the person = 60 kg
Radius of the sun = 695,700 km or 695,700000 m
Force of gravity = Gm1m2/r^2
G = gravitational constant
m1 = mass of the sun
m2 = mass of the person
r = radius of the sun
Hence;
F = 6.67 x 10^-11 * 2 x 10^30 * 60/( 695,700000)^2
F = 8 * 10^21 /4.8 * 10^17
F = 1.7 * 10^4 N
The acceleration due to gravity is gotten from;
g = Gm/r^2
g = 6.67 x 10^-11 * 2 x 10^30/( 695,700000)^2
g = 1.33 * 10^20/4.8 * 10^17
g = 277 m/s^2
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The experimenter had observed that some colors of birthday balloons seem to be harder to inflate than others. She ran this experiment to determine whether balloons of different colors are similar in terms of the time taken for inflation to a diameter of 7 inches. Four colors were selected from a single manufacturer. An assistant blew up the balloons and the experimenter recorded the times (to the nearest 1/10 second) with a stop watch. Questions for all the following cases: Please identify: Independent variable and number of level? Dependent variable? Study design (i.e., between or within-subject design)? Confounding variable (if any)? Violation of Validity (if measureable)?
Case: The effect of balloon color on inflation time.
Independent variable: Balloon color (categorical) with four levels (e.g., red, blue, green, yellow).
Dependent variable: Time taken for inflation to a diameter of 7 inches (continuous, measured in seconds).
Study design: Within-subject design (the same group of participants inflating balloons of different colors).
Confounding variable: Possible confounding variables could be the size or material of the balloons, as these factors might affect the inflation time. To control for this, it would be important to ensure that all balloons used in the experiment are of the same size and material.
Violation of Validity: A violation of validity could occur if the measurement of inflation time is not accurate or consistent (e.g., if the stopwatch used is unreliable or if the experimenter's recording of times is inconsistent). Ensuring proper measurement procedures and equipment would help mitigate this violation.
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The quantity of matter in an object. More specifically, it is the measure of the inertia that an object exhibits in response to any effort made to start it, stop it, or change in any way its state of motion
Answer:
Mass
Explanation:
The mass of an object expresses the amount of matter it comprises. Which implies that objects with higher mass contains higher matter compared to objects with lesser masses. Thereby it determines the measure of inertia experienced by an object when a force is applied to change its direction of motion, or to set it in motion when at rest, or bring it to rest when in motion.
The mass of an object the same no matter its location, and it is measured in kilograms.
how do i find the answer
Which statement is always true when nuclear fusion occurs?(1 point)
A) The total number of protons and neutrons in each nucleus remains constant.
B) The number of protons in the resulting nucleus is less than in each starting nucleus.
C) The number of protons in the resulting nucleus is double that of a starting nucleus.
D) The combined number of protons and neutrons remains constant.
Answer:A
Explanation:
Took the test
18. Calculate the velocity of a ball that rolled to the right 20 cm in 3 seconds.
-4m/s^2 the velocity of a ball that rolled to the right 20 cm in 3 seconds
Vi = 20m/s
Vf = 0
t = (t2 - t1) = 8s -3s = 5s
Vf - Vi = a*5s
a = (0- 20m/s)/5s = -4m/s^2
What does velocity mean?Velocity is a measure of speed in motion or activity. A more concise word for celerity is speed. Physics uses the word "velocity" specifically to describe how quickly and in what direction an object's location changes. It is a vector quantity that expresses the speed and direction of a body's motion.
Velocity is the term for the rate at which a displacement changes. Acceleration is the measure of a change in velocity. Velocity is a vector quantity because it comprises both magnitude and direction. Acceleration is a vector quantity because it is the speed at which velocity varies.
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How would a speed vs. time line graph appear if an airplane moved at a
positive acceleration?
Answer:
Explanation:
Acceleration is the time rate of change, or the rate, of the velocity. Therefore, the slope y/x of a speed vs time graph would give the acceleration. If the acceleration is said to be positive, the graph would be a straight line that is at a constant increase over time.
the minimum stimulus required to trigger an action potential is known as the
The minimum stimulus required to trigger an action potential is known as the "threshold." The threshold refers to the minimum level of depolarization that a neuron or muscle cell must reach to initiate an action potential.
In neurons, the threshold is typically around -55 millivolts (mV) relative to the resting membrane potential. When the cell membrane reaches this threshold voltage, usually due to the influx of sodium ions, it triggers a rapid depolarization and the generation of an action potential. If the membrane potential does not reach the threshold, no action potential is initiated.
The threshold concept is crucial in understanding how neurons transmit signals and communicate with each other. It ensures that only strong enough stimuli, such as sensory inputs or signals from other neurons, can initiate the generation and propagation of action potentials, allowing for precise and selective signaling in the nervous system.
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What is a major problem with CFCs?
A-it is toxic to breathe.
B-It does not readily break down in the atmosphere.
C-It is a greenhouse gas.
D-It isn't a good refrigerant
Answer:
I think
C- It's a greenhouse gas
Explain, using a diagram, why electrons travel easily between atoms, while protons do not.
Answer:
Electrons are located in shells surrounding the nucleus of the atom,whereas protons are present inside the nucleus.
Explanation:
Electrons can move out of the shells on providing energy, but movement of proton will require a very high amount of energy (so as to break the nuclear force).
Compare your everyday experiences to the simulation. Design a few tests like rolling things off a table or tossing some things into a basket or bowl to determine how well the simulation represents projectile motion. Some good objects are tightly rolled socks or paper crumpled into a ball. Write about your experiments and compare them to the simulation
If we throw a socks in to the bowl then it is going with a few unfold situation by means of the projectile and follows the trajectory. Crumpled paper use for the projectile additionally works gud for the simulation.
Crumpled paper has irregular form and mild in weight and it is able to divert in a way by air force or by means of any other motive mild weight. hence simulation and projectile interest are interlinked to every different.
Projectile motion is used in many real-life applications such as designing rockets, ballistic missiles, and artillery, as well as in sports such as baseball, golf, and archery. The concept of projectiles is also relevant in fields such as engineering, military science, and sports. For example, the design of a projectile such as a bullet or missile can affect its accuracy and effectiveness, while knowledge of projectile motion can aid in the design of sports equipment such as golf clubs or javelins.
When a projectile is launched, it follows a curved path known as a trajectory, which is determined by the initial velocity, angle of launch, and the gravitational and atmospheric forces acting on it. The motion of projectiles is studied in physics, where concepts such as projectile motion, trajectory, range, and maximum height are analyzed.
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A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0 x 10^5 Pa. What are the correct values for heat and work for the piston?
Answer:
value of heat is 18 J
2. step by step
formular w=p(volume1-volume2)
w= 1.0×10^5(0.0006-0.0004)
w= 40 J
An 893-kg (1974 lb) dragster, starting from rest, attains a speed of 25.8 m/s (57.8 mph) in 0.59 s.
(a) Find the average acceleration of the dragster during this time interval.
(b) What is the magnitude of the average net force on the dragster during this time?
(c) Assume that the driver has a mass of 68 kg. What horizontal force does the seat exert on the driver?
Hello,
I hope you and your family are doing well!
(a) To find the average acceleration of the dragster, we can use the equation:
average acceleration = (final velocity - initial velocity)/time interval
Plugging in the values from the problem, we get:
average acceleration = (25.8 m/s - 0 m/s)/0.59 s = 43.7 m/s^2
(b) The net force on an object is equal to its mass times its acceleration, so the net force on the dragster during this time interval is:
net force = 893 kg * 43.7 m/s^2 = 38,971 N
(c) To find the horizontal force the seat exerts on the driver, we can use the equation:
force = mass * acceleration
The acceleration of the driver is the same as the acceleration of the dragster, which we found to be 43.7 m/s^2. Plugging this value into the equation, we get:
force = 68 kg * 43.7 m/s^2 = 2970 N
So the seat exerts a force of 2970 N on the driver.
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Happy Holidays!
Please help!
1. If a soldier lifts a 2-kg counterweight 0.5 meters, what is the gravitational force of the counterweight? (Include the equation and appropriate units.)
2. If a soldier lifts a 2-kg counterweight 0.5 meters, how much work is done? (Include the equation and appropriate units.)
please please please please help!!!
Answer:
the gravitational force of the counterweight is 19.6 Nthe work done is 9.8 JExplanation:
Question 1:
Given;
a counterweight of mass, m = 2-kg
distance moved by this weight, d = 0.5 meters
the gravitational force of the counterweight is calculated as;
F = mg
where;
F is gravitational force
m is the mass
g is acceleration due to gravity
F = 2 x 9.8 = 19.6 N
Thus, the gravitational force of the counterweight is 19.6 N
Question 2:
Given;
a counterweight of mass, m = 2-kg
height moved by this weight, h = 0.5 meters
the work done is calculated as;
Work done = Force x distance moved by this weight
Work done = 19.6 x 0.5 = 9.8 J
Thus, the work done is 9.8 J
anyone know the answer?
Answer:
closed
Explanation:
sorry if I'm wrong
how many logical partitions can be created in an extended partition
The number of logical partitions that can be created in an extended partition depends on the file system used and the size of the disk.
An extended partition is a type of partition on a computer's hard drive that can be further divided into logical partitions. It is used to overcome the limitation of having only four primary partitions on a disk.
The number of logical partitions that can be created in an extended partition depends on the file system used and the size of the disk. For example, with the FAT32 file system, you can create up to 32 logical partitions in an extended partition. However, with the NTFS file system, the limit is much higher and can support thousands of logical partitions.
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An extended partition is a type of partition that allows you to have multiple logical partitions within it. The number of logical partitions that can be created within an extended partition is dependent on a number of factors.
Firstly, it's worth noting that you can only have one extended partition per disk. This means that if you have already created an extended partition on your disk, you will not be able to create another one. Secondly, the number of logical partitions that can be created within an extended partition is limited by the available space on your disk.In general, you can create as many logical partitions as you have available space within your extended partition.
However, there is a limit to the number of logical partitions that you can create on a disk. This limit is determined by the size of your disk and the file system that you are using.For example, if you are using the NTFS file system, you can create up to 24 logical partitions on a single disk. However, if you are using the FAT32 file system, you are limited to just 8 logical partitions per disk. These limits are based on the maximum number of drive letters that can be assigned to a logical partition within each file system.
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4cm cubed = ?m cubed
Answer:
\({ \rm{1 \: {cm}^{3} = \frac{1}{100 {}^{3} } \: {m}^{3} }} \\ \\ { \rm{4 \: {cm}^{3} = \frac{4}{1000000} \: {m}^{3} }} \\ \\ { \boxed{ \rm{ = 0.000004 \: {m}^{3} }}}\)