Other:
2. Nicole can make 4 gift baskets in 1/2 an hour. How many baskets can
she make in 3 hours? *
34 points
8
16
24
36
3. At a store each bag of Takis has a cost of x dollars. Which situation can

Answer:

1 A. 1080°

1 B. 142°, 74°,74°, 125°, 125°

Step-by-step explanation:

1A.

The sum of the measure of the interior angle of a convex octagon is given as

S = (n-2)180°................. Equation 1

Where n = 8 sides

S = (8-2)180°

S = 6×180°

S = 1080°

1B.

The sum of the angle of a convex pentagon is given as

S = (5-2)180°

S = 3×180°

S = 540°

From the diagram,

2x+142+2x+(3x+14)+(3x+14) = 540

10x+170 = 540

10x = 540-170

10x = 370

x = 37°

Hence,

∠H = ∠K = 2(37) = 74°,

∠M = ∠L= (3×37)+14 = 111+14 = 125°

Answer: 5 3/5

Step-by-step explanation: Just divide.

The measure of the angle ∠S, obtained using the law of cosines is about 59.4°

The law of cosines states that the square of the length of a side of a triangle is equivalent to the sum of the squares of the other two sides less the product of the length of the other two sides and the angle between them. Mathematically; a² = b² + c² - 2·b·c·cos(A)

Where;

a, b, and c = The length of the sides of the triangle

A = The angle between b and c

The lengths of the sides of the triangle, obtained from a similar triangle are;

s = 50 inches, t = 58 inches, and u = 27 inches

The measure of the angle ∠S is required

The angle ∠S is the angle facing TU or the side s

According to law of cosines, we get;

s² = t² + u² - 2·t·u·cos(∠S)

Therefore;

50² = 58² + 27² - 2 × 58 × 27 × cos(∠S)

2 × 58 × 27 × cos(∠S) = 58² + 27² - 50²

cos(∠S) = (58² + 27² - 50²)/(2 × 58 × 27)

∠S = cos((58² + 27² - 50²)/(2 × 58 × 27)) ≈ 59.4°

The measure of the angle ∠S is about 59.4°

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Independent and dependent variables are interdependent.

Dependent Variable: The term "dependent variable" refers to the variable that is being measured or tested in an experiment.

The results of the participants' tests, for instance, would be the dependent variable in a study looking at how tutoring affects test scores because that is what is being measured.

If you keep in mind that the dependent variable depends on the independent variable, finding it can be simpler.

This isn't the same as an experiment's independent variable, which is a variable that can stand on its own. The dependent variable (test results), however, may alter depending on the independent variable (tutoring).

The unrelated factor

Because the experimenters are allowed to change the independent variable as necessary, it is called a "independent" variable.

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Answer:

7

Step-by-step explanation:

do you really need one?

Answer:

17×6=102 because he gave 2 boxes to his brother so he have 6 boxes

Answer:

b

Step-by-step explanation:

u start at (0,9.5) and with every increasing x value the y value is decreasing by .5 units

Answer:

The diameter of the circle is 7/2.

Step-by-step explanation:

⭐What is the radius of a circle?

⭐What is the diameter of a circle?

Thus, the diameter of said circle is twice the radius of said circle.

diameter = 2(radius)

diameter = 2(7/4)                   . . . . substitute known values

diameter = 14/4                      . . . . multiply the numerator & denominator

diameter = 7/2                       . . . . simplify

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Answer:

y=8x+15

Y Is the total cost, x is the months paid.

For three years, it would cost $303. To find this, you would plug 36 months in for x.

For $431, you streamed for 52 months. To find this, you plug 431 in for Y and solve.

A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.

z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)

Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.

B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.

The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.

Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm

Now we can calculate the z-score for a mean length of 122 cm:

z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)

Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.

C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.

Probability = (0.9999)^3 ≈ 0.9997

Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.

Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.

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The value of x is 4

A Rectangle is a four sided-polygon, having all the internal angles equal to 90 degrees.

The area of a figure is the number of unit squares that cover the surface of a closed figure.

The area of a rectangle is expressed as;

A = l× w

where l is the length and w is the width.

Area of the whole rectangle = 14 × 12

= 168 in²

The sum of the three areas will give the area of the rectangle.

= 168 = 18x + 7x + 68

168 = 25x + 68

25x = 168-68

25x = 100

divide both sides by 25

x = 100/25

x = 4

Therefore the value of x is 4

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Answer:

I believe 2.

z/8 and 3*5

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

z is a term -3 is a term and 5 is a term

The most likely action that the researcher will take will depend on the specific details of the experiment, the resources available, and the scientific objectives of the study. However, the researcher should aim to address the sources of uncertainty and variability in the data to obtain a more accurate estimate of the response time that can be of practical use.

The wide confidence interval indicates that there is a large amount of uncertainty in the estimate of the average response time. To obtain a more precise estimate, the researcher may need to increase the sample size or use a different experimental design to reduce variability and improve the accuracy of the estimate.

Alternatively, the researcher may need to revise the methodology or protocol to identify potential sources of error or bias in the data collection process. For instance, if the stimulus is poorly calibrated, or if the mice are not acclimated to the testing environment, this could contribute to variability in the response time.

Another possibility is to explore alternative statistical methods that may provide a more precise estimate of the response time. For instance, if the distribution of response times is known to be skewed, the researcher could use a nonparametric method to estimate the median response time instead of the mean.

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There are a total of 15,504 different groups of five students that could be selected for the competition from the 20 students in the math club.

To arrive at this answer, we can use the combination formula, which is given by:

nCk = n! / (k! * (n-k)!)

where n is the total number of students in the math club (20), and k is the number of students selected for the competition (5).

Substituting these values into the formula, we get:

20C5 = 20! / (5! * (20-5)!) = 15,504

Therefore, there are 15,504 different groups of students that could be selected for the competition.

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1.  The option D) SSRIs, The greatest success in treating major depression has been observed with the use of selective serotonin reuptake inhibitors (SSRIs).

These drugs are a type of antidepressant that work by increasing the levels of serotonin in the brain. SSRIs are considered to be the most effective medication for the treatment of depression, particularly in the long-term.

2.  the option B) delusion of reference ,A belief that an individual is being singled out for attention is known as delusion of reference. Delusions are a common symptom of schizophrenia and other psychotic disorders.

A delusion of reference is characterized by the belief that everyday events or objects have a special meaning that is directed specifically towards the individual. For example, an individual with this delusion may believe that the radio is broadcasting a message meant for them or that strangers on the street are staring at them because they are part of a conspiracy.

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Answer:

Green

Step-by-step explanation:

All you have to do is retrace retrace Alison’s steps. Note that there are 10 beads in the pattern, the 10th bead black. 210, 200, 190, 180, 170, 160, 150, 140. The 140th bead is black, because it is a multiple of 10. The 139 bead is black as well, because the end of Alison’s pattern contained 2 black beads. The next bead, bead 138, is green. So your answer would be green.

Part A) Estimated Populations of Cities A and B are given.

Part B)  City A's estimated population is increasing at a faster rate than City B's estimated population for each decade.

Part C) the estimated population of City A first exceeds the estimated population of City B at the start of the 4th decade (t = 3)

Part D) The models may not realistically predict population growth over very long time scales, as they do not take into account other factors  

Part A:

Estimated Populations of Cities A and B

Decades Since 1980  City A (in thousands)          City B (in thousands)

0                                       15                                           16

1                                  19.5                                   16.4

2                                  25.2                                   17.8

3                                  32.7                                   19.2

4                                  42.4                                    20.6

Part B:

Population Increases from the previous Decade for Cities A and B

Decades Since 1980 City A (in hundreds)           City B (in hundreds)

0                                         -                                                   -

1                                       450                                              40

2                                       570                                               140

3                                       750                                               140

4                                       970                                               140

Interpretation:

From the table, we can see that City A's estimated population is increasing at a faster rate than City B's estimated population for each decade. This indicates that City A is growing more rapidly than City B, and may continue to do so in the future.

Part C:

To find the start of the decade when the estimated population of City A first exceeds the estimated population of City B, we need to solve the equation:

15\((1.03)^t\) > 0.4t + 16

where t is the number of decades since 1980.

One way to solve this is to use a graphing calculator to graph both functions and find their intersection point. Alternatively, we can use trial and error to test different values of t until we find the smallest one that satisfies the inequality.

Using a graphing calculator, we find that the estimated population of City A first exceeds the estimated population of City B at the start of the 4th decade (t = 3), when the estimated population of City A is approximately 32.7 thousand people, and the estimated population of City B is approximately 19.2 thousand people.

Part D:

The models may not realistically predict population growth over very long time scales, as they do not take into account factors such as changes in birth and death rates, migration patterns, and economic or environmental changes that may affect population growth. Additionally, the models assume that population growth will continue to follow a linear or exponential pattern, which may not be accurate in the long term. Therefore, while the models can provide useful estimates for short- to medium-term population trends, they should be used with caution when making long-term projections.

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The correct question should be:

The estimated population, in thousands of people, of city A can be modeled by the function SO) = 15(1.03), where is the number of decades (10-year period) since 1980 The estimated population, in thousands of people, of the city can be modeled by the function (1)-0.41 +16, where is the number of decades since 1980

Part A)     Complete this table, showing both estimated population values, rounded to the nearest tenth for each city based on the number of decades since 1980 Estimated Populations of Cities A and B City Decades Since 1980 City B (thousands of people) (thousands of people) 0 . 2 3 4

Part B)      Using the table in Part A, complete this table showing population increases, in hundreds of people, cach decade Population Increases from previous Decade for Cities A and B Decades Since 1980, Increase of City A Increase of City B (hundreds of people), (hundreds of people), fin)-(-1) g) -R-1) 2 3 4 Interpret the differences in the increases of the estimated populations of the two cities based on the functions that model cach city's population. Provide evidence to support your answer

Part C)    At the start of which decade will the estimated population of city A first exceed the estimated population of city B? What will be the estimated populations of each city at the start of that decade? Provide evidence to support your answers.

Part D)   Based on the behavior of the functions, do the models realistically predict population growth over very long time scales? Provide evidence to support your answer.

Answer:

Step-by-step explanation:

1/6

The intervals of concavity for f(x) = 3 cos x, with 0 < x < 21, are (0, π/2) and (3π/2, 2π).

To find the intervals of concavity for f(x) = 3 cos x, we need to analyze the second derivative of the function.

First, let's find the second derivative of f(x):

f'(x) = -3 sin x (derivative of cos x)

f''(x) = -3 cos x (derivative of -3 sin x)

Now, we can analyze the concavity of f(x) by considering the sign of the second derivative:

When x ∈ (0, π/2): In this interval, cos x > 0, so f''(x) < 0. The second derivative is negative, indicating concavity downwards.

When x ∈ (π/2, 3π/2): In this interval, cos x < 0, so f''(x) > 0. The second derivative is positive, indicating concavity upwards.

When x ∈ (3π/2, 2π): In this interval, cos x > 0, so f''(x) < 0. The second derivative is negative, indicating concavity downwards.

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Answer:

Exact Form:

(41036433850368 ^6  x  2419 ^54 )− 328

Decimal Form:

2.48516121  x  10 ^264

Answer:

Heyyy T-T

Step-by-step explanation:

The arithmetic and geometric average returns for a stock with annual returns of 9.4 percent, 8.2 percent, -7.3 percent, 4.1 percent, and 9.5 percent are 4.78% and 4.58% respectively.

The shares of ownership in a corporation or company that make up stock (also known as capital stock) in the financial world. A single share of stock represents a fractional ownership in the firm in relation to the entire number of shares (especially in American English, where the word "stocks" is also used to refer to shares). This typically entitles the shareholder (stockholder) to that portion of the company's earnings, proceeds from the sale of assets (after paying off all senior claims such as secured and unsecured debt), or voting rights, often allocating these in proportion to the amount of money each stockholder has invested.

Calculations:

Arithmetic returns=Total returns/Total time period

=(9.4+8.2-7.3+4.1+9.5)/5=4.78%

Geometric returns=[(1+rate1)(1+rate2)........(1+rate5)]^(1/5)

=[(1+0.094)(1+0.082)(1-0.073)(1+0.041)(1+0.095)]^(1/5)

=4.58%

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After 52 hours, approximately 70.7 milligrams of the radioactive substance will remain.

To solve this problem, we can use the exponential decay formula:
N(t) = N0 * e^(-λt)
where N(t) is the amount of substance remaining at time t, N0 is the initial amount of substance, λ is the decay constant, and e is the base of the natural logarithm.
We can find λ by using the fact that half of the substance decays in 36 hours:
N(36) = N0/2
100 mg = 200 mg * e^(-λ * 36)
e^(-λ * 36) = 0.5
-λ * 36 = ln(0.5)
λ = ln(2)/36
Now we can use this value of λ to find N(52):
N(52) = 200 mg * e^(-λ * 52)
N(52) = 200 mg * e^(-ln(2)/36 * 52)
N(52) ≈ 78.1 mg
Therefore, approximately 78.1 milligrams of the radioactive substance will remain after 52 hours.
A scientist is observing a radioactive substance that decays exponentially. Initially, there are 200 milligrams of the substance. After 36 hours, 100 milligrams remain. To determine how many milligrams will remain after 52 hours, we can use the formula:
Final amount = Initial amount * (1/2)^(time elapsed/half-life)
First, we need to find the half-life of the substance. Since it decays to half its initial amount in 36 hours:
Half-life = 36 hours
Now we can plug in the values to find the amount remaining after 52 hours:
Final amount = 200 mg * (1/2)^(52/36) = 200 mg * (1/2)^1.44 ≈ 70.7 mg
After 52 hours, approximately 70.7 milligrams of the radioactive substance will remain.

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Answer:

\(Density = 5.29\ lb/quarts\)

Step-by-step explanation:

Given

\(Density = \frac{6kg}{5\ pints}\)

Required

Convert to pounds per quarts

All we need to do is convert kg to pounds and convert pints to quarts

In standard conversion:

\(1\ kg = 2.20462\ lb\)

and

\(1\ pint = 0.5\ quarts\)

So:

\(Density = \frac{6kg}{5\ pints}\)

\(Density = \frac{6 * 2.20462\ lb}{5 * 0.5\ quarts}\)

\(Density = \frac{13.22772\ lb}{2.5\ quarts}\)

\(Density = 5.291088\ lb/quarts\)

\(Density = 5.29\ lb/quarts\) --- Approximated

Answer:

B

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

i just know

The circumstance that the score is located 5 points above the mean a central value, relatively close to the mean is when the population standard deviation is much greater than 5.

Standard Deviation is a measure which shows how much variation (such as spread, dispersion, spread,) from the mean exists. The standard deviation indicates a “typical” deviation from the mean. It is a popular measure of variability because it returns to the original units of measure of the data set.

Here, we have

We have to find under what circumstances is a score that is 5 points above the mean considered a central value--meaning it is relatively close to the mean.

We concluded from the above statement that when the population standard deviation is much greater than 5.

Hence, when the population standard deviation is much greater than 5 then, the score that is 5 points above the mean is considered a central value.

Therefore, the correct option is D.

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Answer:

388.8

Step-by-step explanation:

Thats correct i think

Answer:

4

Step-by-step explanation:

First, use the distributive property: 2x+16=4x+8

Second, move +8 to the other side(and turn it negative): 2x+8= 4x

Do the same for +2x: 8=2x

divide both sides by 2: 4=x

Using BODMAS, the solutions of the expressions are: (1) 9, (2)-12, (3) 0.27, and (4) 0.24

We should know that BODMAS is a mathematical approach which means

In each of the expressions, we must follow the approach

1)    \(\frac{(6+3)^{2} }{3*9}\)

Simplifying this we have 9²/9=81/9

=9

2)  \(\frac{3^{2} -6*2}{(12-8)/2^{2} *10}\)

Using BODMAS we have

(9-12)/4/40

-3÷1/9

⇒-3*4

=-12

(3)   \(\frac{4.5+2*2.5^{2}-6 }{8*4+9}\)

Using BODMAS we have

(4.5+2*6.25-6)/32+9

⇒(4.5+12.5-6)/41

=11/41=0.27

4     (\(\frac{3.5+16-2.5^{2} }{10.5-6*11}\))

Using BODMAS we have  

(3.5+16-6.25)/10.5-66

Simplifying

(13.25)/-55.5

=0.24

Therefore, the values when simplified are  (1) 9, (2)-12, (3) 0.27, and (4) 0.24

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