Oops, this is the shape for the previous question. Find the area

Answer:

he works 20 per week, so in a month, he will have 20*4= 80 hours, here 4 is the number of weeks in one month, and we have as information that he is paid for one hour $8.50, so you can do: 80*($8.50)= $680

Step-by-step explanation:

(20hours)*(4 weeks)= 80hours

(80hours)*($8.50)= $680

Answer:

Pretty sure it's B. 1

Step-by-step explanation:

y = mx + b is y-intercept form and B is usually where you put the first dot on the y axis, and that is positive 1, as you can see on the graph.

Hope you get a good grade! :)

Answer:

Step-by-step explanation:

3y = 2x - 9

2y = -3x + 4

3x + 2y = 4

-2x  + 3y = -9

6x + 6y = 8

-6x + 9y = -27

15y = -15

y = -1

3(-1) = 2x - 9

-3 = 2x - 9

6 = 2x

3 = x

(3, -1)

Answer:

C: 38 units

hope this helps!!

The sample space of possible sets of 5-drone observations is the set of all possible combinations of five numbers taken from the set of numbers 1 to N, where N is the total number of drones. There are 252 possible observations in this case.

The sample space of possible sets of 5-drone observations is the set of all possible combinations of 5 drones from the total number of drones, N. This can be represented as the combination formula: C(N, 5) = N! / (5! * (N-5)!).

The number of possible observations is simply the size of the sample space, which is equal to the combination formula. So, the number of possible observations is C(N, 5) = N! / (5! * (N-5)!).

To calculate the number of possible observations for a given value of N, we can plug in the value of N into the combination formula and simplify. For example, if N = 10, the number of possible observations is:

C(10, 5) = 10! / (5! * (10-5)!) = 10! / (5! * 5!) = 252

So, there are 252 possible observations of 5 drones when there are a total of 10 drones.

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The evaluation of the improper integral:

∫(1-p)^(∞) 4xln(x) dx = 4lim(∞→(1-p)) [xln(x) - x] = 4(1-p)ln(1-p) - 4(1-p).

We first showed that the function f(x) is positive and decreasing for sufficiently large x, so the Integral Test applies.

We then set up the improper integral with the limits of integration from (1-p) to infinity.

We used integration by parts to evaluate the integral:

Let u = ln(x) and dv = 4x dx

Then du = dx/x and v = 2x^2

Applying the formula for integration by parts, we get:

∫(1-p)^(∞) 4xln(x) dx = 4[xln(x) - ∫(1-p)^(∞) 2x dx]

= 4[xln(x) - [x^2]_(1-p)^(∞)]

= 4lim(∞→(1-p)) [xln(x) - x]

We evaluated the limit using L'Hopital's rule:

lim(∞→(1-p)) [xln(x) - x] = lim(∞→(1-p)) [(ln(x) + 1) / x]

= lim(∞→(1-p)) [(1/x) / (-1/x^2)]

= lim(∞→(1-p)) [-x]

= -(1-p)

Finally, we substituted the value of the limit back into our integral:

∫(1-p)^(∞) 4xln(x) dx = 4lim(∞→(1-p)) [xln(x) - x]

= 4(1-p)ln(1-p) - 4(1-p)

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The lengths of LV and OE are 15cm, and the lengths of LD and EV are 3√7 cm and 9/√7 cm, respectively.

Since LOVE is a kite, LV and OE are perpendicular bisectors of each other. Let the length of LD be x, and the length of EV be y. Then, we can use the Pythagorean theorem and the fact that the diagonals bisect each other to set up two equations:

x² + (LV/2)² = DV²/4

y² + (OE/2)² = LE²/4

Simplifying each equation and substituting the given values, we get:

x² + (LV/2)² = 81/4

y² + (OE/2)² = 225/4

We also know that the diagonals bisect each other, so we can set up another equation:

LV/2 + OE/2 = LO = VE

Substituting the given value for LE, we get:

LV/2 + OE/2 = 15

Solving this equation for one of the variables, we get:

LV = 30 - OE

Substituting this expression into the first equation above, we get:

x² + ((30 - OE)/2)² = 81/4

Simplifying and rearranging, we get:

OE² - 60OE + 675 = 0

Using the quadratic formula, we get:

OE = (60 ± √(3600 - 2700)) / 2

OE = 15 or 45

If OE = 15, then LV = 30 - 15 = 15, and we can solve for x and y:

x² + 7.5² = 81/4

y² + 7.5² = 225/4

Solving these equations, we get:

x = 3√7

y = 9/√7

If OE = 45, then LV = 30 - 45 = -15, which is impossible for a length. Therefore, the solution is:

LV = OE = 15

x = 3√7

y = 9/√7

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Complete question:

LOVE is a kite. LV and OE are diagonals. The segments DV = 9cm and LE = 15cm are given. Find the lengths of the other segments of the diagonals, DV, OE, and LV.

Answer: 3ad^3

Step-by-step explanation: they have the same terms

Answer:

-25 can be expressed as a ratio of -50/2, -75/3, etc

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

The value of the variable h in the given fraction problem (h/6) - 1 = -3 is; h = -12

We are given the fraction problem as (h/6) - 1 = -3

Now, from this given fraction problem, the first step will be to rearrange the equation by adding 1 to both sides to get;

(h/6) - 1 + 1 = -3 + 1

(h/6) = -2

Now, the next step will be to multiply both sides by 6 to get;

(h/6) * 6 = -2 * 6

h = -12

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Complete question is;

Solve for h if (h/6) - 1 = -3

Answer:

yes they are congruent

Step-by-step explanation:

they have congruent sides to each other

The given figures are congruent.

Given are two figure ABCD and EFGH on a cartesian plane, we need to check if the figures are congruent or not,

The coordinates of the figure ABCD are:
A = (-1, 1), B = (-3, 2), C = (-4, 4) and D = (-2, 6).

The coordinates of the figure EFGH are:
E = (2, 0), F = (4, 1), G = (5, 3) and H = (3, 5).

To check if the figures ABCD and EFGH are congruent, we need to compare the corresponding sides and angles of the two figures.

Congruent figures have the same shape and size, so their corresponding sides must be equal.

Let's compare the corresponding sides of ABCD and EFGH, using the distance formula:

\(|D| = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

AB and EF:

\(|AB| = \sqrt{(-3+1)^2 + (2-1)^2}\\\\ |AB| = \sqrt{-2^2+1^2} \\\\ |AB| = \sqrt{5}\)

And,

\(|EF| = \sqrt{(4-2)^2 + (1-0)^2}\\\\ |EF| = \sqrt{2^2+1^2} \\\\ |EF| = \sqrt{5}\)

∴ AB = EF

Similarly,

\(BC =\sqrt{\left(-4-\left(-3\right)\right)^2+\left(4-2\right)^2}\\\\ BC = \sqrt{5}\)

And,

\(FG =\sqrt{\left(5-4\right)^2+\left(3-1\right)^2}\\\\ FG = \sqrt{5}\)

\(CD = \sqrt{\left(-2-\left(-4\right)\right)^2+\left(6-4\right)^2} \\\\ CD = 2\sqrt{2}\)

And,

\(GH=\sqrt{\left(3-5\right)^2+\left(5-3\right)^2}\\\\ GH=2\sqrt{2}\)

\(AD =\sqrt{\left(-2-\left(-1\right)\right)^2+\left(6-1\right)^2}\\\\ AD =\sqrt{26}\)

And,

\(EH = \sqrt{\left(3-2\right)^2+\left(5-0\right)^2}\\\\EH =\sqrt{26}\)

Therefore, we get,

FG = BC, GH = CD and AD = EH = √26.

Since we get all the corresponding sides are equal.

Hence the figures are congruent.

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The solution is Option A.

The point B ( -8 , 1 ) reflected over y-axis is B' ( 8 , 1 )

What is Reflection?

Reflection is a type of transformation that flips a shape along a line of reflection, also known as a mirror line, such that each point is at the same distance from the mirror line as its mirrored point. The line of reflection is the line that a figure is reflected over. If a point is on the line of reflection then the image is the same as the pre-image. Images are always congruent to pre-images.

The reflection of point (x, y) across the x-axis is (x, -y). When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is taken to be the additive inverse. The reflection of the point (x, y) across the y-axis is (-x, y).

Given data ,

Let the point be B ( x₁ , y₁ ) = B ( -8 , 1 )

Now , when the point B is reflected , we get

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is taken to be the additive inverse. The reflection of point (x, y) across the y-axis is (-x, y)

So , B' ( x₂ , y₂ ) is the reflection of point B ( -8 , 1 ) over y axis

And , B' ( x₂ , y₂ ) = B' ( 8 , 1 )

Therefore the point B' is B' ( 8 , 1 )

Hence , The point B ( -8 , 1 ) reflected over y-axis is B' ( 8 , 1 )

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Algebra gives the result of each of the following expressions as follows;

1) -y^2 - 2y - 4

2) 15x^2 - 19x - 8

3) 2a^3 - 9a^2 +  18a - 16

4) 24x + 64

5) (x + 3) (x - 8)

6) (x - 6) (x + 6)

The term expression refers to a mathematical statement that lacks the equality sign. Now let us answer the questions individually;

1) In order to subtract (3y2-4y+5)  from (4y2+2y-9), we must remove the brackets to have and collect like terms;

3y^2-4y+5 - 4y^2+2y-9

3y^2 - 4y^2 -4y +2y +5 -9

-y^2 - 2y - 4

2) to multiply the polynomials, we have;

(5x-8) (3x+1)

15x^2 + 5x - 24x - 8

15x^2 - 19x - 8

3) This multiplication gives;

(a-2) (2a^2-5a+8)

2a^3 - 5a^2 + 8a - 4a^2 + 10a - 16

Collecting like terms

2a^3 - 5a^2  - 4a^2 + 8a + 10a - 16

2a^3 - 9a^2 +  18a - 16

4) The product is;

(2x+8)(x+8)

2x^2 + 16x + 8x + 64

2x^2 + 24x + 64

Hence;

2x^2 + 24x + 64 - 2x^2

24x + 64

5) The expression is; x^2-5x-24

x^2 -8x + 3x - 24

x(x - 8) +3(x - 8)

(x + 3) (x - 8)

6) The expression x^2-36 represents difference of two squares hence;

x^2 - 6^2

(x - 6) (x + 6)

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Answer:

Option B

Step-by-step explanation:

Slope of the line is calculated by the formula:

\(m=\frac{y_2-y_1}{x_2-x_1}\\\\\)

We have the points ( -2 , 4) and (3 , -5) so plug in the values in the formula:

\(m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{-5-4}{3-(-2)}\\\\m=\frac{-9}{5}\\\)

so the slope(m) equals -9/5

An arithmetic succession, is defined by constant sums or substractions. A geometric succession, is defined by constant products. In this case, we can define this succession as a product

It means this succession is geometric.

Answer:

a

Step-by-step explanation:

Answer:

A - The Moon reflects light from the Sun.

Step-by-step explanation:

As the moon moves around the sun in a one month cycle, different parts of it are exposed to the sun. When it is exposed to the light from the Sun it is reflected and people on Earth could see it at night, and sometimes during the day as well.

Answer:

Hi! The answer to your question is A. \(5^{4} * 4^{8}\)

Step-by-step explanation:

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i think Is 9p centímetros

In a case whereby the sum of two consecutive numbers is 25 the largest of the consecutive numbers is 13.

Given that sum of two consecutive numbers is 25 , ans we were required to locatye the  largest of the consecutive numbers. The we can represent the consecutive numbers as x and x+1. According to the problem, the sum of these two consecutive numbers is 25:

x + (x+1) = 25

Simplifying the left side of the equation:

2x + 1 = 25

2x = 24

Dividing both sides by 2:

x = 12

So the first consecutive number is 12. The second consecutive number is 12 + 1 = 13. Therefore, the largest of the consecutive numbers is 13.

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Answer:

I think it may be A

Step-by-step explanation:

Answer:

180 glasses.

Step-by-step explanation:

capacity of glass: 25 ml

capacity of vessel: 4l 500 ml

4500 / 25 = 180

All three reasons (1, 2, and 3) can be valid for using a normal probability model to represent the distribution of sample means.

1, 2, and 3 are correct.We can use a normal probability model to represent the distribution of sample means for the following reasons:

1. The sample is randomly selected. This ensures that each member of the population has an equal chance of being selected, reducing potential biases and allowing the use of a normal probability model.

2. The distribution of the variable in the population is normally distributed. When the population distribution is normal, the distribution of sample means will also be normally distributed, as stated by the Central Limit Theorem.

3. The sample size is large enough to ensure that sample means will be normally distributed. As the sample size increases, the distribution of sample means approaches a normal distribution, even if the original population distribution is not normal. This is also part of the Central Limit Theorem, which typically suggests a sample size of 30 or more.

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Answer:

Step-by-step explanation:

1-1=0

Answer:You will have 0 moms.

Step-by-step explanation:

First you take 1 away from 1.

After that you get your answer of 0.

The error she made is Emi evaluated (46-78)² as - (32)² is wrong.

Variance is calculated as the average of squared differences of the data observations from the mean.

Given data: 87, 46, 90, 78, and 89.

Here, the first Emi find the difference of 89 - 78 correctly.

Now, Emi division is also correct.

Now, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

(46-78)² = (-32)²

Here she used the negative sign outside.

Hence, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

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Answer:

C.) Emi evaluated (46 - 78)2 as -(32)2.

Step-by-step explanation:

Answer:

1.21x

Step-by-step explanation:

we can write 100% as 1

then 10% is 0.1

then 1.1x = is first

1.1*1.1x = 1.21x or 121% of x

The savings of $x grows 10% each year after 2 year it will become  1.21x .

Compound interest is an interest accumulated on the principal and interest together over a given time period. The interest accumulated on a principal over a period of time is also accounted under the principal.

The formula of Compound interest :

\(A= P(1+\frac{r}{100} )^{t}\)

where,

A = Final amount

P = initial Principal

t = Time in years

r = rate of interest per annum  

According to the question

Principal = $x

Rate of interest per annum  =  10%

Time in years = t

By using formula of Compound interest :

\(A= P(1+\frac{r}{100} )^{t}\)  

Now ,

Substituting the values in the formula

\(A= x(1+\frac{10}{100} )^{2}\)

\(A= x(1.1} )^{2}\)  

\(A= 1.21x\)

Hence, the savings of $x grows 10% each year after 2 year it will become   1.21x .

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To analyze the investment decision between Machine A and Machine B, various financial metrics are calculated. The payback period, accounting rate of return, net present value, and internal rate of return are determined. Based on these calculations, the suitable machine is chosen, considering the payback period, cost of capital, and other factors.

The payback period of both machines is calculated by determining the time required to recover the initial investment. It is expressed in years, months, and days. The machine with the shorter payback period indicates a faster return on investment.
Using the payback period as the sole criterion for decision-making, the machine with the shorter payback period should be chosen. However, it's important to note that the payback period does not consider the time value of money or the profitability beyond the payback period.
The accounting rate of return on average investment for Machine A is calculated by dividing the average annual profit by the average investment cost, expressed to two decimal places. This metric provides an indication of the profitability of the investment.
The net present value (NPV) of each machine is calculated by discounting the expected cash flows using the company's cost of capital (12%). NPV represents the present value of the expected cash inflows and outflows associated with the investment. The machine with the higher NPV indicates a higher value addition to the company.
The internal rate of return (IRR) of Machine B is determined using interpolation. IRR is the discount rate that equates the present value of expected cash flows to the initial investment. It indicates the profitability and return on investment of Machine B.
Considering all these factors and the company's cost of capital, a comprehensive evaluation can be made to determine the most suitable machine for investment.

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