One mole of potassium permanganate, KMnO4, contains how many
grams of oxygen.

The basic chemical formula for all sugar monomers can be described as (CH₂O)n, where "n" represents the number of carbon atoms in the sugar molecule.

Glucose is the most prevalent natural monomer among sugars. Starch, cellulose, and glycogen combine to create polymers as a result of their linking. Many species rely on glucose as a critical source of energy.

This formula indicates that sugars are composed of carbon (C), hydrogen (H), and oxygen (O) atoms in a ratio of 1 ratio 2 ratio 1. The "n" value varies depending on the specific sugar monomer. For example monosaccharide, glucose, a common sugar monomer, has a chemical formula of C₆H₁₂O₆, where "n" is 6.

Therefore, the correct description of the basic chemical formula for all sugar monomers is (CH₂O)n.

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Answer:

true

Explanation:

Answer:

In graphite, each carbon atom is covalently bonded to 3 other carbon atoms. ... These extra electrons are delocalised, or free to move, in the area between layers of carbon atoms. As these electrons are free to move they are able to carry charge and thus graphite can conduct electricity.

Explanation:

Graphite has a layered structure, with each layer consisting of a two-dimensional hexagonal lattice of carbon atoms. Within each layer, carbon atoms are covalently bonded in a flat, trigonal planar arrangement, forming strong σ bonds.

In graphite, carbon atoms are arranged in a flat, hexagonal lattice within each layer, forming strong covalent σ bonds. These layers are stacked on top of each other, held together by weaker van der Waals forces, which allow for easy slippage.

The presence of π bonds between the carbon atoms in each layer results in delocalized π electrons above and below the plane, creating a "sea" of mobile electrons. This delocalization gives graphite its remarkable properties, including electrical conductivity and lubrication.

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The amino acid chain that is made during translation is determined by the sequence of codons (groups of three nucleotides) in the mRNA molecule.

Each codon corresponds to a specific amino acid, and the ribosome reads the mRNA and adds the corresponding amino acids to the growing protein chain in the order specified by the mRNA.

For example, if the mRNA sequence is AUG GCC GGC AUG, the ribosome would add the amino acids methionine, alanine, glycine, and methionine to the protein chain in that order. The final protein chain would be a sequence of four amino acids: Methionine-Alanine-Glycine-Methionine.

The specific amino acid sequence of a protein is determined by the genetic code contained in the DNA of an organism. Different sequences of amino acids can fold up into different three-dimensional structures, which give proteins their unique properties and functions. Thus, the sequence of amino acids in a protein is an important factor in determining its function and role in the cell.

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Step 1

The reaction must be completed and balanced as follows:

C3H8 + 5 O2 => 3 CO2 + 4 H2O

-------------

Step 2

Information provided:

20.0 g of C3H8

10.0 g of O2

----

Information needed:

1 mole of C3H8 = 44.1 g

1 mole of O2 = 32.0 g

(use your periodic table please)

-------------

Step 3

By stoichiometry,

C3H8 + 5 O2 => 3 CO2 + 4 H2O

44.1 g C3H8 ---------- 5 x 32.0 g O2

20.0 g C3H8 ---------- X

X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8

X = 72.6 g O2

For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.

Therefore,

Answer:

The limiting reactant = O2

The excess = C3H8

Given the freezing-point depression for a solution is 2. 5 °C and the cryoscopic constant is 4.5 °c/m, the molality of the solution is 0.56 m.

Freezing-point depression is a drop in the temperature at which a substance freezes, caused when a smaller amount of another, non-volatile substance is added.

The freezing-point depression for a solution is 2. 5 °C. We can calculate the molality of the solution using the following expression.

ΔT = Kf × b

b = ΔT / Kf = 2.5 °C / (4.5 °C/m) = 0.56 m

where,

Given the freezing-point depression for a solution is 2. 5 °C and the cryoscopic constant is 4.5 °c/m, the molality of the solution is 0.56 m.

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The molality of a solution will be 0.56 m. if the freezing point depression for a solution is 2.5° C.

Molality is the measure of the moles of any solute in a solution per unit kg of the solvent.

Given, the freezing-point depression for a solution is 2. 5 °C

The kf is 4.5° c/m

\(\rm \Delta T = Kf \times b\\\\b = \dfrac{\Delta T}{kf} \\\\b = \dfrac{2.5^ \circ C}{4.5 \circ C/m} = 0.56 m\)

Where T is freezing point depression

kf is cryoscopic constant of the solvent

b is molality of the solution

Thus, the molality of the solution is 0.56 m.

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The answer would be an atom.

Atom : An atom is a tiny piece of a matter that unparalleled defines a chemical element.

An atom comprise of a mid nucleus that is neighbouring by one or more negatively charged electrons. The nucleus is positively charged and consist one or more relatively bulky particles known as protons and neutrons.

It is the littlest unit of an element.

Cannot be made or annul in a chemical reaction.

Atoms of various elements have various masses and chemical attributes.

Atoms merged in the ratio of compact whole numbers to form compounds.

Characteristics of an atom : atomic number, mass number and net charge.

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Answer:

25%  

Explanation:

I assume you menat 20 cm^3 of water

5 gm / 20 gm = 25 %

Explanation:

We have to find the net charge of a polyatomic ion that contains 49 protons and 50 electrons.

n° of protons = 49 n° of electrons = 50

The charge of each electron is -1 and the charge of each proton is +1.

charge of electron = -1 charge of proton = +1

Finally the net charge will be:

Net charge = n° of electrons * charge of electron + n° of protons * charge of proton

Net charge = 50 * (-1) + 49 * (+1)

Net charge = -1

Answer: C) -1

To calculate the standard Gibbs free energy change (ΔG°) for the reaction: Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)We can use the equation:ΔG° = -nFΔE°, where:ΔG° is the standard Gibbs free energy change, n is the number of electrons transferred in the balanced equation, F is the and Faraday constant (approximately 96485 C/mol),

ΔE° is the standard cell potential (also known as E°cell) for the reaction. A number of electrons are transferred in the balanced equation. From the equation, we can see that 2 electrons are transferred. Next, we calculate ΔE°cell by summing the standard reduction potentials (E°) of the half-reactions involved:

ΔE°cell = E°cathode - E°anode

ΔE°cell = (0.00V) - (-0.76V) = 0.76V

Now, we substitute the values into the equation to calculate ΔG°:

ΔG° = -nFΔE°

    = -(2 mol) × (96485 C/mol) × (0.76 V)

    ≈ -147,207 J

Expressing the answer in three significant figures, the value of ΔG° for the reaction is approximately -147,207 J (or -147 kJ).

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The density of a substance can be defined as the mass of the subtance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:

\(Density = \frac{Mass}{Volume }\)

With the above information in mind, we can obtain the volume of the substance given in the question above as illustrated below:

Density = 3.89 g/mL

Mass = 2.58 g

\(Density = \frac{Mass}{Volume} \\\\3.89 = \frac{2.58}{Volume }\)

Cross multiply

3.89 × Volume = 2.58

Divide both side by 3.89

\(Volume = \frac{2.58}{3.89}\\\\\)

Therefore, the volume of the substance is 0.66 mL

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Answer:

5.0X10 -6 M-

Explanation:

The second radiation is less energetic than the former because it has a longer wavelength.

Recall that;

c = λf

c = Speed of light

λ = wavelength

f = Frequency

Now;

λ = c/f = 3 × 10^8 m/s/6.00 x 10^13 s-1

λ = 5  × 10^-6 m

Also;

When f = 5.40 x 10^13 s^-1

λ = c/f = 3 × 10^8 m/s/5.40 x 10^13 s^-1

λ = 5.6 × 10^-6 m

This radiation is less energetic than the former because it has a longer wavelength.

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Answer: The number of atoms = Avogadro's number = 6.022 × 10²³

Number of atoms in a mole = Avogadro's number = 6.022 × 10²³

Explanation:

1.

Mole = \(\frac{given mass}{molar mass}\)

Also, Mole = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

∴  \(\frac{given mass}{molar mass}\)  = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

\(\frac{12}{12}\) = \(\frac{number of atoms}{Avogadro's number}\)

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

2.

Mole = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

1 =  \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

Answer:

1 moles Carbon Dioxide = 44.0095 gram using the molecular weight calculator and the molar mass of CO2

Explanation:

The molecules in 0.87 mole of carbon dioxide are 5.2 x 10²³.

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

If there are 6.023 × 10²³ molecules present in one mole of carbon dioxide then for 0.87 moles

\(6.023 \times 10^2^3 \times 0.87 = 5.2 \times 10^2^3\)

Thus, the molecules in 0.87 mole of carbon dioxide are 5.2 x 10²³

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After ingesting 1 L of 80-proof whiskey, the student's consumption of ethanol would, after the application of dimensional analysis, be 5.798 g of ethanol per kilogram of the body.

First, we calculate the mass of ethanol ingested by the student by using dimensional analysis. To do that, we must calculate its volume, which we can do using the total volume (1 L = 1000 mL) and alcohol volume percentage (40% = 0.40). When we have the volume in hand, we can calculate the mass of ethanol using its density (0.789 g/cm³ = 0.789 g/mL).

m(EtOH) = V(EtOH) * d(EtOH) = 0.40 * V(total) * d(EtOH) = 0.40 * 1000 mL * 0.789 g/mL = 315.6 g

So the student would ingest 315.6 g of ethanol. We can now divide that mass by the student's mass to calculate their consumption.

1 lb = 453.59 g = 0.45359 kg

315.6 g / (120.0 * 0.45359 kg) = 5.798 g/kg

This is dangerously close to the median lethal dose and definitely above the lower threshold of 5 g/kg, so the student would definitely be in danger of overdosing.

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Answer:

2.04 g/cm3

Explanation:

Density = mass ÷ volume

= 5100 ÷ 2500

=2.04 g/cm3

Answer

Through the leaves

Explanation:

The best evidence that the moon has been extensively heated is the lack of volatiles.

The following are the characteristics of the Moon

:Mass of the moon.Lack of iron core.

Oxygen isotopes like the Earth.

Lack of volatiles.

Volatiles are materials with low boiling points that exist in solid or liquid form at the Earth's surface. Water and carbon dioxide are two examples of volatile materials. The lack of volatiles on the moon is a strong indication that the moon was subjected to high temperatures. It also indicates that volatiles have been expelled from the moon's surface due to the loss of gas molecules that occurred as a result of the heat. As a result, the absence of volatiles is the best evidence that the Moon has been extensively heated.

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The number of molecules in 10.0 gram of NaOH is 15 * 10²².

To solve this question, we need to understand some terms of mole concept,

Mole - It is the amount of substance containing same number of molecules or atoms as there are atoms in 12 gram of carbon-12 isotope.

Molecules - It is group of atoms bonded together, representing the smallest fundamental unit of a chemical compound taking part in chemical reaction.

Molecular weight - The sum of atomic masses of all atoms in molecules.

Avogadro number - It is the number of atoms, ions, electrons, molecules in one mole of substance. It is represented as NA.

NA = 6.0 * 10²³ (approx)

To calculate the number of molecules, we apply the formulae,

no. of molecules = moles * NA

moles = weight / molecular weight

moles = 10.0 / 40

          = 0.25

Substituting this value to calculate number of molecules,

no. of molecules = 0.25 * 6.0 * 10²³

                            = 15 * 10²²

Therefore the number of molecules of in 10.0 g of NaOH is 15 * 10²².

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The range in km downstream from the WWTP discharge point would be the area to avoid for siting the fish hatchery. Based on the information provided, the fish hatchery requires more than 4.5 mg/l of dissolved oxygen. To determine where in the river to avoid siting the fish hatchery, we need to find the point where the dissolved oxygen level falls below 4.5 mg/l.

The river flows at a rate of 3.2 km/day. We can estimate the location by plotting data points. By calculating the distance downstream from the wastewater treatment plant (WWTP) discharge point, we can determine the range to avoid.

Please note that without specific data or a plot, I cannot provide an exact answer. However, you can estimate the distance by analyzing the dissolved oxygen levels at various points along the river and identifying where it drops below 4.5 mg/l. The range in km downstream from the WWTP discharge point would be the area to avoid for siting the fish hatchery.

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Answer:

Explanation:

Symmetry can help resolve many chemistry problems and usually the first step is to determine the symmetry. If we know how to determine the symmetry of small molecules, we can determine symmetry of other targets which we are interested in. Therefore, this module will introduce basic concepts of group theory and after reading this module, you will know how to determine the symmetries of small molecules.

Introduction

Symmetry is very important in chemistry researches and group theory is the tool that is used to determine symmetry. Usually, it is not only the symmetry of molecule but also the symmetries of some local atoms, molecular orbitals, rotations and vibrations of bonds, etc. that are important. For example, if the symmetries of molecular orbital wave functions are known, we can find out information about the binding. Also, by the selection rules that are associated with symmetries, we can explain whether the transition is forbidden or not and also we can predict and interpret the bands we can observe in Infrared or Raman spectrum.

Symmetry operations and symmetry elements are two basic and important concepts in group theory. When we perform an operation to a molecule, if we cannot tell any difference before and after we do the operation, we call this operation a symmetry operation. This means that the molecule seems unchanged before and after a symmetry operation. As Cotton defines it in his book, when we do a symmetry operation to a molecule, every points of the molecule will be in an equivalent position.

Symmetry Elements

For different molecules, there are different kinds of symmetry operations we can perform. To finish a symmetry operation, we may rotate a molecule on a line as an axis, reflect it on a mirror plane, or invert it through a point located in the center. These lines, planes, or points are called symmetry elements. There may be more then one symmetry operations associated with a particular symmetry

Identity E

The molecule does not move and all atoms of the molecule stay at the same place when we apply an identity operation, E, on it. All molecules have the identity operation. Identity operation can also be a combination of different operations when the molecule returns to its original position after these operations are performed.1 This will be demonstrated later.

The Moon, Mercury, Edge of the Universe, Milky Way Galaxy, Hubble Galaxy, Pluto's Moon. Closest to Earth/ Farthest.

The universe is the entirety of everything that exists, including all matter and energy, space and time, and the physical laws and constants that govern them. The known universe is thought to be made up of billions of galaxies, each containing billions of stars and planets. The universe is also thought to be expanding, with all the galaxies moving away from each other.

The current scientific understanding of the universe is based on the Big Bang theory, which suggests that the universe began as a singularity, an infinitely dense and hot point, about 13.8 billion years ago. From this singularity, the universe expanded and cooled, giving rise to the formation of matter, stars, galaxies and eventually, the emergence of life.

The universe is also thought to be filled with dark matter and dark energy, which are thought to make up the majority of the universe's mass and energy, respectively.

The universe is a vast and complex place, with much that remains unknown and mysterious. Scientists continue to study the universe through telescopes, satellites, and other observation tools to understand more about its origins, structure and evolution.

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Answer:

210 grams

Explanation:

just add them all up

The Earth's surface is not covered with the same materials ; however, some areas share similar materials.Several drilling sites have been dug in various regions of the planet to analyze the Earth's surface.

Each drilling site is unique, with differing characteristics and results. Despite these differences, all of the drilling sites analyzed offer scientists a more in-depth knowledge of the Earth's surface.In essence, the scientific drilling sites each had different lithologies, stratigraphies, and geologies. Each site had different types of rocks, depths, and ages, which led to varying drilling conditions, depths, and equipment used. Different types of equipment were also used to reach the depths required, which was a significant difference in each drilling site.The scientific drilling sites also had different purposes. Scientists had specific goals they wanted to achieve at each location. For example, the scientific drilling site in the Iceland region was focused on analyzing a unique layer of igneous rocks. The primary objective was to investigate the formation of the rock layer.The same materials were not found at each scientific drilling site.

Still, they had some similarities. They all provided geologists with vital information about the Earth's surface. The data provided from each drilling site was used to piece together the Earth's geologic history and how it has changed over time.

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Answer:

522 Kilometers per Hour

Explanation:

Hi there! :)

Answer:

\(\huge\boxed{522 km/hour}\)

\(\text{Express 145 m/s as a fraction:} \frac{145m}{s}\)

\(\text}Convert to km/hour by multiplying by the equivalents in terms of meters and seconds to cancel out the units}\)

\(\frac{145m}{sec} * \frac{3600 sec}{1 hour} * \frac{1 km}{1000 m} = \\\\\text {Cross out similar units and multiply the coefficients:}\\\\\frac{145 * 3600 * 1km}{1 * 1hour * 1000} = \frac{522000km}{1000hour}= 522 km/s.\)

The problem requires calculating the time required for water vapor to achieve a partial pressure of 0.0150 atm on the back surface of a new type of porous material used as food packaging film.

The film is 0.20 cm thick, rests on a nonporous metal plate, and contains liquid water with a vapor pressure of 0.030 atm at 25°C. The effective diffusion coefficient of water vapor in the porous film is 1.3 10 4 cm2/s, and the molecular diffusion coefficient of water vapor in air is 0.26 cm2/s. Assuming that the total system pressure is constant at 1.0 atm and the gas space in the porous film initially contains air, it will take approximately 1100 seconds or 18.3 minutes for the water vapor to reach the desired partial pressure at the back surface of the film.

To determine the time required for the water vapor to achieve a partial pressure of 0.0150 atm at the back surface of the porous film, we need to use Fick's first law of diffusion: J = -D(dC/dz), where J is the diffusion flux, D is the effective diffusion coefficient (1.3 x 10^-4 cm^2/s), and dC/dz is the concentration gradient.

The concentration gradient can be found using the vapor pressure difference (0.030 - 0.0150 atm) and the film thickness (0.20 cm). Convert the pressure difference to concentration using the Ideal Gas Law: C = P/RT, where R is the gas constant (82.06 cm^3.atm/mol.K) and T is the temperature (25°C or 298 K).

Once the concentration gradient is found, solve for the diffusion flux J using Fick's first law. Then, divide the initial concentration of water vapor by the diffusion flux to find the time required for the water vapor to achieve a partial pressure of 0.0150 atm at the back surface of the film.

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Answer:

Filled below

Explanation:

#v.e means number of valence electrons.

Also, the column total v.e is gotten by adding the v.e of the metal to the v.e of the non metal based on the chemical formula of both of the 2 elements combined.

K: Cl: 5; KCl; 1 + 5 = 6

Be: S: 6; BeS; 2 + 6 = 8

Na: F: 7; NaF; 1 + 7 = 8

Mg: Se: MgSe; 2 + 6 = 8

Al; N; AlN; 1 + 5 = 6

Be; F; BeF2; 2 + 2(7) = 16

Mg; N; Mg3N2; 3(2) + 2(7) = 20