Answer:
3.456 × 10^(8) m
Explanation:
We are given;
Mass of earth; m_e = 5.98 × 10^(24) kg
Mass of moon; m_m = 7.36 × 10^(22) kg
Distance from earth to moon; L = 3.84 × 10^(8) m.
We are told that the Moon’s gravitational pull is stronger than that of Earth’s.
Thus;
F_EA ≤ F_MA
Formula for force due to gravity is;
F = GMm/r²
Applying to this question, we have;
(Gm_e•m_a)/x² ≤ (Gm_m•m_a)/(l - x)²
Where x is his distance from the center of the Earth
Now, G and m_a will cancel out from both sides and we plug on other values to get;
(5.98 × 10^(24))/x² ≤ (7.36 × 10^(22))/(3.84 × 10^(8) - x)²
Taking square root of both sides gives;
2445403852127.4966/x ≤ 271293199325.0107/(3.84 × 10^(8) - x)
Rearranging gives;
2445403852127.4966(3.84 × 10^(8) - x) ≤ 271293199325.0107x
Simplifying this gives;
9.0139(3.84 × 10^(8) - x) ≤ x
(34.613 × 10^(8)) - 9.0139x ≤ x
(34.613 × 10^(8)) ≤ x + 9.0139x
(34.613 × 10^(8)) ≤ 10.0139x
x ≥ (34.613 × 10^(8))/10.0139
x ≥ 3.456 × 10^(8)
A body initially at rest is accelerated at the rate of 0.2m/s for 5 seconds under contant force of 50 N. Calculate the workdone on the body
Answer:
the correct answer is 125 joule
You can’t pool the wool over my eyes!
Alliteration
Allusion
Assonance
Hyperbole
Metaphor
Onomatopoeia
Oxymoron
Personification
Simile
Answer:
Assonance
Hope this helps :)
Hope this helps :)Explanation below.
Explanation:
The oo sound is repeated many times, and oo is a vowel sound. So assonance would make the most sense.
Q1: A person uses a screwdriver to turn a screw and insert it into a piece of wood. The person applies a force of 20 newtons to the screwdriver and turns the handle of the screwdriver a total distance of 0.5 meter. How would these numbers be different if the person inserted a nail with a hammer instead of the screw with the screwdriver?
A: The force applied would be the same, but the distance would be shorter.
B: The force applied would be greater, but the distance would be shorter.
C: The force applied would be less, but the distance would be greater.
D: The force applied would be the same, but the distance would be greater.
------------------------------------
Q2: What are people trying to increase when using simple machines?
A: applied mechanical force
B: the distance over which a force is applied
C: the energy needed to complete a task
D: mechanical advantage
------------------------------------
Q3: What do a Class 1 lever and a Class 2 lever have in common?
Both levers place the fulcrum in between the applied force and the object being lifted.
A:Both levers place the fulcrum in between the applied force and the object being lifted.
B:Both levers have an output force in the same direction as the input force.
C:Both levers would lift an object on the same side of the fulcrum as the applied force.
D: Both levers result in a larger output force from a smaller input force.
------------------------------------
What makes this lever effective?
A: The rock has more mass than the man.
B: The man has more mass than the rock.
C: The man is farther from the fulcrum than the rock is.
D: The man is closer to the fulcrum than the rock is.
------------------------------------
What is the efficiency of a machine that uses 102 kJ of energy to do 98 kJ of work?
96.1%
0.961%
104%
4%
------------------------------------
A pulley system is used to lift an object. Which factor could affect the efficiency of the system?
the friction of the individual pulleys
the mass of the person pulling
the mass of the object
the distance the weight is lifted
------------------------------------
Based on the mass and speed data, which object will have the greatest amount of kinetic energy?
10 kg moving at 2 m/s
5 kg moving at 2 m/s
10 kg moving at 5 m/s
2 kg moving at 2 m/s
------------------------------------
Which statement accurately explains why the kinetic energy of the first rider is greater?
The first rider is taller.
The first rider is in front.
The potential energy of the first rider is greater.
The first rider has more mass.
------------------------------------
Which two factors affect the kinetic energy of an object?
mass and speed
speed and weight
mass and height above the ground
weight and height above the ground
------------------------------------
A single billiard ball, traveling at 20 m/s, strikes a cluster of 15 balls on a billiard table. What can be said about the balls on the table after the collision?
None of the balls will have a velocity greater than 20 m/s.
The kinetic energy will be divided equally among the 15 balls.
Each ball will have a velocity equal to 20 m/s.
The kinetic energy of the 15 balls will be greater than the kinetic energy of one ball.
------------------------------------
Where do the forces that make atoms interact come from?
from the electric fields of charged subatomic particles
from the electric fields of neutral molecules
from the electric fields of neutral subatomic particles
from the electric fields of charged molecules
------------------------------------
Q1: A: The force applied would be the same, but the distance would be shorter.
Q2: D: mechanical advantage
Q3: A: Both levers place the fulcrum in between the applied force and the object being lifted.
Q4: C: The man is farther from the fulcrum than the rock is.
Q5: 96.1%
Q6: the friction of the individual pulleys
Q7: 10 kg moving at 5 m/s
Q8: The first rider has more mass.
Q9: mass and speed
Q10: The kinetic energy of the 15 balls will be greater than the kinetic energy of one ball.
Q11: from the electric fields of charged subatomic particles
When two objects slide against oneanother, which of the following statements about the force offriction between them is true?- Themagnitude of the frictional force is always equal to μkn.- Themagnitude of the frictional force is always less than μkn.- Themagnitude of the frictional force is determined by other forces onthe objects so it can be either equal to or less than μkn
When two objects slide against one another, then the magnitude of the frictional force is always equal to μkn. Correct option is A.
Sliding friction is the resistance that any two things produce when they slide against one another. This friction, also referred to as kinetic friction, is the force required to maintain one surface moving along another.
It relies on two factors: the object's weight and the type of material used. The sliding friction is unaffected by changes in the surface area in touch. Sliding friction is typically less than static friction in most materials. There are some exceptions, such as metals, which have friction coefficients that are basically the same for large and small surfaces when molecular attraction forces are at work. Thus, the best choice is A.
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Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic (i.e., single-wavelength) EM radiation on a metal plate with unknown work function W, and then measuring the stop- ping voltage required to bring the ejected electrons to a halt. When he uses λ1= 400 nm, he finds that a stopping voltage of V1 = 0.7 V is required. When he uses λ2 = 500 nm, he finds that a stopping voltage of V2= 0.2 V is required. Based on these two data points, what is Ajani's measurement of Planck's constant?
Answer:
h = 1.01 x 10⁻³⁴ J.s
Explanation:
The energy applied by the voltage must be equal to the energy associated with the wavelength of light:
\(eV = \frac{hc}{\lambda}\\\)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = stopping potential
h = Planck's Constant = ?
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:
\((1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\\)
h = 1.49 x 10⁻³⁴ J.s
For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:
\((1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\\)
h = 0.53 x 10⁻³⁴ J.s
Taking average of both values:
\(h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}\)
h = 1.01 x 10⁻³⁴ J.s
What is Concave lenses ?
Explanation:
A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.
If a force is applied when using a lever over 2 meters to move the object 1 meter, the distance over which the force is applied is called the _____.
The distance over which the force is applied when using a lever is called the effort distance.
What is force?Force is defined as the rate of change of momentum.
Here,
The distance over which the force is applied when using a lever is called the effort distance. It refers to the distance between the point where the effort is applied and the fulcrum of the lever. In the case we described, where a force is applied when using a lever over 2 meters to move an object 1 meter, the effort distance would be 2 meters. The load distance, on the other hand, refers to the distance between the fulcrum and the point where the load is applied. Understanding the relationship between the effort and load distances is crucial to determining the mechanical advantage of a lever system.
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A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now
If initial speed was v, Kinetic energy was K = 1/2mv^2
When speed will be 4v, KE will be:
= 1/2 m (4v)^2
=1/2m 16 v^2
=16K
Now kinetic energy will become 16 times of initial Kinetic Energy
if a 50.0 kg mass weighs 554 n on the planet saturn, calculate saturn's radius
Answer:
this is impossible unless im doing my math wrong sorry
Explanation:
You perform an experiment to measure the speed of a car over time. The
results are shown in the graph below.
Speed (m/s)
30
25-
20
15
10
5
0+
O
5
10
A. 24 m/s
B. 22 m/s
15
Time (s)
What was the speed of the car after 20 seconds?
C. 20 m/s
D. 30 m/s
20
25
The speed of the car after 20 seconds are 20 m/s.
What is the speed ?The speed of an object is a measure of how quickly the object is moving in a particular direction. It is typically measured in units such as meters per second (m/s). Speed is a scalar quantity, which means it is only concerned with the magnitude of the velocity (or speed) and not the direction
The graph shows that the speed of the car was 20 m/s after 20 seconds.
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Suppose that scientists observe violent gas eruptions on a planet with an acceleration due to gravity of 3.8 m/s2. The jets throw sand and dust about 75 m above the surface.
What is the speed i of the material just as it leaves the surface?
Scientists estimate that the jets originate as high‑pressure gas speeds through vents just below ground at about 160 km/h. How much energy per kilogram of material does the jet lose to non conservative forces as the high‑speed matter forces its way to the surface and into the air?
Answer:
linarkuoouonpnpjjñihy
Explanation:
Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 220 m/s^2 for 20 msms, then travels at constant speed for another 30 ms.
Required:
During this total time of 50 ms, 1/20 of a second, how far does the tongue reach?
Solution :
We know,
Distance,
\($S=ut+\frac{1}{2}at^2$\)
\($S=ut+0.5(a)(t)^2$\)
For the first 20 ms,
\($S=0+0.5(220)(0.020)^2$\)
S = 0.044 m
In the remaining 30 ms, it has constant velocity.
\($v=u+at$\)
\($v=0+(220)(0.020)\)
v = 4.4 m/s
Therefore,
\($S=ut+0.5(a)(t)^2$\)
\($S'=4.4 \times 0.030\)
S' = 0.132 m
So, the required distance is = S + S'
= 0.044 + 0.132
= 0.176 m
Therefore, the tongue can reach = 0.176 m or 17.6 cm
Answer:
The total distance is 0.176 m.
Explanation:
For t = 0 s to t = 20 ms
initial velocity, u = 0
acceleration, a = 220 m/s^2
time, t = 20 ms
Let the final speed is v.
Use first equation of motion
v = u + at
v = 0 + 220 x 0.02 = 4.4 m/s
Let the distance is s.
Use second equation of motion
\(s = u t + 0.5 at^2\\\\s = 0 + 0.5 \times 220 \times 0.02\times 0.02\\\\s = 0.044 m\)
Now the distance is
s' = v x t
s' = 4.4 x 0.03 = 0.132 m
The total distance is
S = s + s' = 0.044 + 0.132 = 0.176 m
Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2
The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2
Step 1: used the ideal gas equation to calculate the moles of O2
that is Pv=n RT where;
P(pressure)= 1.00 atm
V(volume) =3.90 L
n(number of moles)=?
R(gas constant) = 0.0821 L.atm/mol.K
T(temperature) = 273 k
by making n the subject of the formula by dividing both side by RT
n= Pv/RT
n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles
Step 2: use the Avogadro's law constant to calculate the number of molecules
that is according to Avogadro's law
1 mole = 6.02 x10^23 molecules
0.174 moles=? molecules
by cross multiplication
the number of molecules
= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2
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Measuring the average energy of motion of the particles in a substance is the same as measuring the substance's A. pressure. B. mass. C. heat capacity. D. temperature.
Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds
The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].
The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.
The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.
To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]
Y = 4.95sin[π(3.80x - 1180t - 0.206)]
The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.
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-- The given question is incomplete, the complete question is
"Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --
What is the weight, on Earth, of a book with a mass of 1.5 kg?
0 1,5 N
0 6,5 N
O 11.3N
0 14 7 N
Answer:
\(\boxed {\tt 14.7 \ Newtons}\)
Explanation:
Weight is force due to gravity.
The formula for weight is:
\(W=m*g\)
where m is the mass and g is the acceleration of gravity.
On Earth, the acceleration due to gravity is 9.8 meters per seconds squared.
The mass of the book is 1.5 kilograms. Therefore:
\(m= 1.5 \ kg \\g=9.8 \ m/s^2\)
Substitute the values into the formula.
\(W= 1.5 \ kg *9.8 \ m/s^2\)
Multiply.
\(W=14.7 \ kg*m/s^2\)
1 kg meter per second squared is equal to 1 Newton, so our answer of 14.7 kg*m/s² is equal to 14.7 Newtons.
\(W=14.7 \ N\)
The weight of a 1.5 kilogram book on Earth is 14.7 Newtons.
Answer:
Answer:
Explanation:
Weight is force due to gravity.
The formula for weight is:
where m is the mass and g is the acceleration of gravity.
On Earth, the acceleration due to gravity is 9.8 meters per seconds squared.
The mass of the book is 1.5 kilograms. Therefore:
Substitute the values into the formula.
Multiply.
1 kg meter per second squared is equal to 1 Newton, so our answer of 14.7 kg*m/s² is equal to 14.7 Newtons.
The weight of a 1.5 kilogram book on Earth is 14.7 Newtons.
Explanation:
How much net- work is required to accelerate a 1200-kg car from 25 m/s to 45 m/s?
The net-work required to accelerate the car of mass 1200 kg is 840000 J.
What is work done?Work can be deifned as the product of force and distance.
To calculate the amount of net-work required to accelerate 1200 kg car from 25 m/s to 45 m/s, we use the formula
Formula:
W' = m(v²-u²)/2............ Equation 1Where:
W' = Net-work required to accelerate the carm = Mass of the carv = Final velocityu = Initial velocityFrom the question,
Given:
m = 1200 kgv = 45 m/su = 25 m/sSubstitute these values into equation 1
W' = 1200(45²-25²)/2W' = 1200×1400/2W' = 840000 JHence, the net-work required is 840000 J.
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Which parts of the warm-up did you find most difficult? Why?
Answer:
Can't really answer that for now. More context please?
Explanation:
I will answer it in a comment when you give some context.
Surviving a Large Deceleration On July 13, 1977, while on a test drive at Britain's Silverstone racetrack, the throttle on David Purley's car stuck wide open. The resulting crash subjected Purley to the greatest "g-force" ever survived by a human - he decelerated from 173 km/h to zero in a distance of only about 0.66 m.
Calculate the magnitude of the acceleration experienced by Purley (assuming it to be constant), and express your answer in units of the acceleration of gravity, g=9.81m/s2 .
The magnitude of the acceleration experienced by Purley is -1749.82 m/s²
How to convert 173 Km/h to m/sWe'll begin by converting 173 Km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
173 Km/h = (173 Km/h × 1 m/s) / 3.6 Km/h
173 Km/h = 48.06 m/s
How to determine the accelerationThe following data were obtained from the question:
Initial velocity (u) = 48.06 m/sFinal velocity (v) = 0 m/sDistance (s) = 0.66 mAcceleration (a) = ?The acceleration can be obtained as follow:
v² = u² + 2as
0² = 48.06² + (2 × a × 0.66)
0 = 2309.7636 + 1.32a
Collect like terms
1.32a = 0 - 2309.7636
1.32a = -2309.7636
Divide both sides by 1.32
a = -2309.7636 / 1.32
a = -1749.82 m/s²
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How can we break an atom
Answer:
Breaking an atom refers to a process called nuclear fission, which involves splitting the nucleus of an atom into smaller nuclei. This is typically accomplished by bombarding the atom with a neutron, which causes the nucleus to become unstable and split apart, releasing a large amount of energy in the process. This energy is what is harnessed in nuclear power plants to generate electricity. However, it should be noted that nuclear fission can also have potentially harmful effects, such as the release of radioactive material and the potential for nuclear accidents.
Some runners train with parachutes that trail behind them to provide a large drag force. These parachutes are designed to have a large drag coefficient. One model expands to a square 1.8 m on a side, with a drag coefficient of 1.4. A runner completes a 200 m run at 5.0 m/s with this chute trailing behind. Part A How much thermal energy is added to the air by the drag force
Answer:
13.9 kJ
Explanation:
Given that
Length of the side, l = 1.8 m
Drag coefficient, C(d) = 1.4
Distance of run, d = 200 m
Velocity of run, v = 5 m/s
Density, ρ = 1.23
Using the Aerodynamics Drag Force formula. We have
F(d) = 1/2.ρ.A.C(d).v²
The Area, A needed is 1.8 * 1.8 = 3.24 m². So that,
F(d) = 1/2 * 1.23 * 3.24 * 1.4 * 5²
F(d) = 139.482/2
F(d) = 69.74
recall that, energy =
W = F * d
W = 69.74 * 200
W= 13948
W = 13.9kJ
Therefore, the thermal energy added to the air by the drag force is 13.9kJ
What is occurring when two waves traveling along the same medium meet and cancel each other out?
O destructive interference
O constructive interference
O reflection
O refraction
Answer:
Destructive interference
Explanation:
Destructive interference occurs when two waves traveling along the same medium meet and cancel each other out. The resultant wave has a smaller amplitude than the individual waves. In this case, the maxima of two waves are 180 degrees out of phase.
Hence, the correct option is (A) "destructive interference"
Answer: the answer is A. Destructive inference
Explanation: I took the test
If an object can make 10 revolutions in two minutes what’s it’s period
Answer:
12\(s^{-1}\)
Explanation:
Period= how long for each revolution
Since we have 10 revolutions in 120 seconds.
120/10=12s
label each marked position of mars with the phrase that most accurately describes its apparent motion in our sky against the background stars. A - Retrograde
B - Prograde - moving faster
C - Prograde - moving slower
The phrase that most accurately describes its apparent motion in our sky against the background stars is west then Prograde - moving slower then Retrograde then Prograde - moving faster and at last east.
The apparent motion of a planet or other object as seen from Earth against a background of stars, moving from west to east (looking or viewing to the south - apparent right to left) which is called Prograde motion.
Retrograde motion is defined as "the apparent motion of a planet or other object as seen from Earth against the background of stars, moving from east to west (looking/viewing to the south - apparent left to right) motion."
When a superior planet (Mars, Jupiter, Saturn, Uranus, etc.) orbits the Sun at a distance greater than that of the Earth and is passed by the latter, which is moving with a higher relative velocity, the 'Superior' planet's normal direct motion appears to stop and then temporarily turn retrograde, giving it the appearance of undergoing a loop or zigzag in the sky.
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Kam does 4000J of work in climbing a set of stairs. if he does work in 6 seconds, whi is his power output?
Answer:
666.7 W
Explanation:
Power = P = W/t = 4000 J/6 s = 666.7 W (watts)
which of the following statements is correct about force f, kinetic energy k and momentum p of an object of mass m a) force is the rate at which momentum changes b) kinetic energy \displaystyle k
The following statements is correct about force f, kinetic energy k and momentum p of an object of mass m are (a) Force is the rate at which momentum changes.
What is momentum?Momentum is a concept in physics that describes the motion of an object. It is determined by the mass and velocity of an object, and is represented by the formula: momentum = mass x velocity.
Momentum plays an important role in physics, as it is the conserved quantity of motion for a system. It is a vector quantity, which means it has both a magnitude and a direction. In a collision, momentum is conserved, meaning that the total momentum of the system remains the same before and after the collision.
Momentum is also important in sports, as it can be used to understand how to maximize or minimize the speed and direction of a ball.
We know that
Force = m × a
m = f/a
And
Momentum = m × v
m = p/v
Also
= 1/2mv²
m = 2K.E./v²
Now taking M into account for all we can say that
\($ \frac{\text{Force}}{\text{Acceleration}} = \frac{\text{Momentum}}{\text{velocity}} = \frac{2 \ \text{Kinetic Energy}}{\text{velocity}^2}\)
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Q5) Name the unit for expressing nuclear cross-sections.
Answer:
The unit is the barn, which is equal to 10-28 m^2 or 10-24 cm^2
Explanation:
The standard unit for measuring a nuclear cross section (denoted as σ)
A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during this
acceleration?
0 3600 N
0 2000 N
2400 N
O ON
Answer:
3600 N
Explanation:
F=ma
1200*3 = 3600
Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters
Answer:
7000 meters
Explanation:
obviously 99.99 is less than 7000
10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000
10 squared is 100, which × 9 is only 900, which is also less than 7000
have a good day