The speed of Olivia when she made it to the bottom of the hill is 14m/s.
Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.
Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.
Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.
Given,
Initial velocity, u = 4m/s
Acceleration, a = 2m/s-2
Displacement, s= 45m
we know that,
\(v^{2}= u^{2} + 2as\), where v= final velocity
substituting the value in the above equation, we got
\(v^{2}\) = \(4^{2} + 2(2)(45)\)
v = \(\sqrt{196}\)
v = 14 m/s
Thus, the speed of Olivia going down the hill is 14m/s.
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On what does the DSM-5 place primary emphasis?
A. the ability to distinguish between real or imagined auditory sensations
B. mechanisms that regulate emotion
C. the consequences of certain behavioral syndromes
D. a person's social or occupational role
The primary emphasis of the DSM-5 is on the consequences of certain behavioral syndromes. The correct option is C.
What is Behavioral Syndromes?
Behavioral syndromes, also known as behavioral or personality traits, refer to consistent patterns of behavior exhibited by individuals across different contexts or situations. These syndromes are characterized by the tendency to display certain behaviors together, suggesting a coordinated and predictable set of behavioral responses.
Behavioral syndromes are observed in various organisms, including humans, animals, and even some microorganisms. They can manifest in a wide range of behaviors, such as aggression, boldness, exploration, sociability, activity level, risk-taking, and more.
The DSM-5, which stands for the Diagnostic and Statistical Manual of Mental Disorders, is a widely used classification system for diagnosing and classifying mental disorders. It provides criteria and guidelines for diagnosing various mental health conditions. Among the given options, the DSM-5 places primary emphasis on the consequences of certain behavioral syndromes.
The DSM-5 focuses on understanding and categorizing mental disorders based on their observable symptoms, behaviors, and the impact they have on an individual's functioning and well-being. It considers the consequences of these behavioral syndromes, such as impairments in social, occupational, or other important areas of functioning, as key factors in the diagnostic process.
While the other options mentioned in the question (the ability to distinguish between real or imagined auditory sensations, mechanisms that regulate emotion, and a person's social or occupational role) may be relevant in specific contexts or for specific disorders, they are not the primary emphasis of the DSM-5 as a whole. The correct option is C.
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Kinetic energy depends on the height of an object above the ground?
1. A physical quantity P is related to four observables a, b and c as follows: P= (a3b 2 /c4 ) The percentage errors of measurements in a, b and c are 1%, 4% and 2% respectively. What is the percentage error in quantity P?
Answer:
The percentage error in quantity P is 19%.
Explanation:
It is given that,
A physical quantity P is related to four observables a, b and c as follows:
\(P=\dfrac{a^3b^2}{c^4}\)
The percentage errors of measurements in a, b and c are 1%, 4% and 2% respectively.
We need to find the percentage error in quantity P. It is given by :
\(\dfrac{\Delta P}{P}\times 100=(3\times \dfrac{\Delta a}{a}+2\times \dfrac{\Delta b}{b}+4\times \dfrac{\Delta c}{c})\\\\=3\times 1+2\times 4+4\times 2\\\\\dfrac{\Delta P}{P}\times 100=19\%\)
So, the percentage error in quantity P is 19%.
a) Typical electric fields in thunderstorms average around 105 V/m. Consider a (roughly) cylindrical thundercloud with height 10 km and diameter 20 km and assume a uniform electric field of 105 V/m. Find the electrical energy contained in the cloud (2 s.f.).
b) For the same thundercloud and imagining that the electric field points vertically downwards, calculate the minimum charge on a 5-mg raindrop that would cause it to accelerate upwards (2 s.f.). (Enter the magnitude of the charge into D2L to check your answer, but the sign is important too in your written solution.)
a) electrical energy contained in the cloud is 2.9 × 10^11 J (to 2 s.f.) b) Therefore, the minimum charge on a 5-mg raindrop that would cause it to accelerate upwards is 4.65 × 10^-10 C. are the answers
a) The electrical energy contained in a thundercloud of roughly cylindrical shape with a height of 10 km and diameter of 20 km, having uniform electric fields of 105 V/m is as follows:
Volume of the cloud= 1/4 × π × d2 × h= 1/4 × π × (20 km)2 × (10 km)= 1571.0 km3= 1.571 x 10^12 m3
Potential difference (V) = electric field (E) × distance (d)= 105 × 10^3 × 10 × 10^3= 1.05 × 10^9 V
Thus, the electrical energy contained in the cloud is given as:
Energy = (1/2) × capacitance × V^2where capacitance C of the cloud is:
C = ε0 × (π/4) × d^2/h
where ε0 = permittivity of free space
Energy = (1/2) × C × V^2
Energy= (1/2) × 8.85 × 10^-12 × π/4 × (20 × 10^3)^2 / (10 × 10^3) × (1.05 × 10^9)^2
Energy = 2.9 × 10^11 J (to 2 s.f.)
b) The charge on a 5-mg raindrop to cause it to accelerate upwards is:
Mass of the raindrop = 5 mg = 5 × 10^-6 kg
Electrical force acting on the raindrop,
F = ma= mg – qE
where g is the acceleration due to gravity, q is the charge on the raindrop, and E is the electric field.
As the raindrop is to be accelerated upwards, m and a should be taken as positive.
F = ma= mg – qE> 0,
hence mg > qE= (5 × 10^-6 kg) × g / E > q
Hence, the minimum charge on a 5-mg raindrop is given by:
q = (5 × 10^-6 kg) × g / E
q = (5 × 10^-6 kg) × 9.8 m/s^2 / (105 V/m)
q = 4.65 × 10^-10 C (to 2 s.f.)
Therefore, the minimum charge on a 5-mg raindrop that would cause it to accelerate upwards is 4.65 × 10^-10 C.
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hello I need help with this question. I started it but am confused
Given:
The mass on the table is,
\(m=1.0\text{ kg}\)The hanging mass is,
\(M=1.5\text{ kg}\)THe coefficient of friction is,
\(\mu=0.20\)let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.
we can write,
\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)Adding these equations we get,
\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)Hence the acceleration is 6.66 m/s^2.
how are coefficient estimates from wls (weighted least squares) interpreted?
The interpretation of coefficient estimates from WLS depends on the weights that are assigned to the observations, and the rationale behind those weights.
Coefficient estimates from WLS (Weighted Least Squares) are interpreted in a similar way to those from OLS (Ordinary Least Squares) regression. The main difference is that WLS gives different weights to different observations, while OLS gives equal weights to all observations.
In WLS, the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, while holding all other variables constant. However, the interpretation of the coefficients depends on the weights that are assigned to the observations.
For example, if the weights are based on the reliability of the observations, then the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, for the most reliable observations. If the weights are based on the importance of the observations, then the coefficient estimates represent the change in the dependent variable for a one-unit change in the independent variable, for the most important observations.
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Can anyone help me with these questions? TIA!!
Resistance is a material's tendency to resist the flow of charge (current). Resistance is the measure of the opposition to motion of free electrons(current) due to their continuous collisions with the atom of the lattice. An electric current flows when electrons move through a conductor, such as a metal wire. The moving electrons can collide with the atoms in the metal. This makes it more difficult for the current to flow, and causes resistance. The unit of Resistance is "OHM". Ohm is denoted by the greek letter "Ω".
_____________________________________Question 2:\(\Huge\text{Ohm's Law}\)If a current 'I' is caused to flow in a conductor by a battery of potential difference 'V', it is found that the current is directly proportional to potential difference provided there is no change in the conductor itself. That means more will be I if we increase V. So
\({\Longrightarrow}\qquad \qquad \qquad I {\propto} V\\\\{\Longrightarrow}\qquad \qquad \qquad I = KV\)
Where K is Conductance. Conductance is the ability of a conductor to allow the current to pass through it. Resistance(R) is the reciprocal(opposite) of conductance(K) thus K is inversely proportional to R,
\({\Longrightarrow}\qquad \qquad \qquad I = \frac{1}{R}V \\\\{\Longrightarrow}\qquad \qquad \qquad V = IR\)
This is known as OHM's Law, and V = IR is the equation linking the R, V and I.
_____________________________________Question 3:\(\Huge\text{Circuit Diagram:}\)
Circuit Diagram no 1 attached is of this question. In the circuit diagram, V is voltmeter to find the potential difference, A is the ammeter to find the current, R is the resistance i.e. the conductor wire, The switch and the battery.
Suppose the wire of length 100 cm is connected to a battery, the Voltmeter observes the potential difference and ammeter reads the current of the wire. We will use the R, V and I i.e. V = IR equation to find out the resistance of that wire and Record the resistance. Then attach another small wire of suppose 90 cm to the battery, and similarly Find out its resistance too. After recording the resistance 3 or 4 times, you will observe that When you decrease the length of the wire,
The Resistance decreasesThe Current increases The Potential Difference decreases_____________________________________Question 4:\(\Huge\text{Resistance:}\)The resistance of a conductor depends upon the following factors.
Length(L), Longer the length of conductor, Greater the resistance.\({\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad L\)
Cross-Sectional Area(A), thicker the Wire, lesser the Resistance.\({\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad \frac{1}{A}\)
Material of the Conductor, The Resistance also changes because of the material of the wire. If we use copper it will have different resistance than the steel wire.The relation between only length of the wire and resistance is \(R\quad {\propto} \quad L\) . The relation of R, L and A is given by, ρ
\({\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad \frac{L}{A}\\\\{\Longrightarrow}\qquad \qquad \qquad R\quad =\ \frac{\ {\rho}\ L\ }{A}\)
Where ρ is known as resistivity depends upon the nature of the material of the wire. The meter of resistivity is Ω x m(Ohm x meter).
_____________________________________Question 5:\(\Huge\text{I-V Characteristic:}\)
I-V curves of an electrical device or component, are a set of graphical curves which are used to define its operation within an electrical circuit. I-V characteristic curves show the relationship between the current flowing through an electronic device and the applied voltage across its terminals. The circuit diagram to find I-V characteristic must have a resistor which is a device or component connected to a battery which is providing the potential difference V. When a resistor is connected to a battery, current I is observed due to drift velocity. To find the current and potential difference(voltage) the circuit must have the Ammeter and voltmeter. Recorded current and voltage must be used to plot the graph to check the I-V characteristic. The picture attached is the circuit diagram.
_____________________________________Question 6:We calculate the resistance at constant temperature by ohm's law. The Ohms law is applied at constant temperature because the resistance of any material varies with the change in temperature. It shows a linear relationship between the applied voltage and the resulting current, resistance being a constant. So we could use V = IR because resistance is constant at constant temperature.
_____________________________________Best Regards,'Borz'
Mercury thermometer can record a high temperature why?
Answer: The thermometer consists of a mercury-filled bulb connected to a thin capillary with a temperature scale. Its modern version has a small constriction below its scale preventing the mercury from flowing back into the bulb, when temperature decreases again. Thus the maximum temperature reached is recorded.
Consider this:
The mercury can expand and contract to the slightest temperature change due to its high coefficient of expansion. Mercury also has a high boiling point of 674.1 degrees F
hope this helped :)
In one sentence describe how modeling is used in science
Answer:
Modeling is used in science to simplify complex systems and phenomena, allowing scientists to make predictions and test hypotheses.
Explanation:
a bicyclist travels with an average velocity of 15km/h north, for 20 minutes .what is his displacement ?
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Displacement is equal to ~
\(5 \: \: km\)See the attachment for solution ~
Answer:
It is 24000meter per second
3 Which organisms survive well on volcanic islands?
1. bacteria
2. birds
3. plants
4. large animals
plants
i hope its right and have a nice day
Answer:
number 1
Explanation:
what is the weight of a spring balance when the point is 30
Answer:
A 30 lb weight is attached to the end of a spring. The spring is stretched 6 in. Find the equation of motion if the weight is released from rest a point 3 inches above equilibrium position 。x(,) =-2 sin(81) 32 x(t) =-32 cos(80 O x(r) =-icos(81)
Explanation:
How do the molecules at point A compare to the molecules at point B? They are farther apart. They have increased in size. They have lost energy. They are moving slower.
Answer: hello the image is missing but am able to provide you with an answer to your but I am unable to attach the image
They are moving fasterThey are farther apart They have gained energyExplanation:
Molecules at point A compared to molecules at point B shows that they are
They are moving fasterThey are farther apart They have gained energyThe movement of molecules is caused by the application of energy in various forms especially thermal energy
Answer:
The answer is A!
Explanation:
Got it right on edge 2021 :>
Yash traveled 8 miles West and then 12 miles North, How far is he from his starting point?
A. 10 miles
B. 14.42 miles
C. 20 miles
D. 8.94 miles
A water tank has a volume of 1200 cubic feet. A discharge pipe near the top of the tank is located 140 feet above the level in a lake. A pump is used to lift the water from the lake to discharge the pipe. Find the work done by pump to fill the tank.
The work done by the pump to fill the tank is 10,483,200 foot-pounds.
Given the following data: Volume of the water tank = 1200 cubic feet
The discharge pipe is located 140 feet above the level in a lake
The pump is used to lift water from the lake to discharge the pipe
Work done is the force applied to an object and the distance through which that force is applied. It can be calculated using the formula,
Work done = force × distance
- Here, the force required is the weight of the water and distance is the height it is lifted.
Force = Weight = Density × Volume (where density of water = 62.4 lb/ft³)
Force = 62.4 × 1200 = 74,880 pounds
- Therefore, the work done by the pump to fill the tank is
Work done = force × distance
Work done = 74,880 × 140
Work done = 10,483,200 foot-pounds.
Therefore, the work done by the pump to fill water tank with a volume of 1200 cubic feet is 10,483,200 foot-pounds.
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A mass on a spring system has an initial mechanical energy of 167 J and a damping factor of 0.2 s^-1. What is the mechanical energy of the system (in units of J) after 2.8 s
have passed?
The mechanical energy of the system after 2.8 s is approximately 95.14 J.
The mechanical energy of a damped harmonic oscillator decreases over time due to damping. The equation for the mechanical energy of a damped harmonic oscillator is given by:
E(t) = E0 * exp(-2βt)
where E(t) is the mechanical energy at time t, E0 is the initial mechanical energy, β is the damping factor, and exp is the exponential function.
Given that the initial mechanical energy E0 is 167 J and the damping factor β is 0.2 s^-1, we can calculate the mechanical energy after 2.8 s as follows:
E(2.8) = E0 * exp(-2 * 0.2 * 2.8)
E(2.8) = 167 * exp(-0.56)
Using the value of exp(-0.56) ≈ 0.5701, we have:
E(2.8) ≈ 167 * 0.5701
E(2.8) ≈ 95.14 J
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5) Why mercury is used as thermometeic liquid
Answer: becuase----Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion. ... It also has a high boiling point which makes it very suitable to measure higher temperatures. Also, it has a shiny appearance and doesn't stick to the glass surface of glass.
Explanation: hope i helped c:
When more than three notes are sounded together, but the number of pitch names in the set is only three (arranged from alternate steps of the scale), a(n) __________ is produced.
When more than three notes are sounded together, but the number of pitch names in the set is only three (arranged from alternate steps of the scale), a(n) **triad** is produced.
A triad is a chord that consists of three notes played simultaneously. It is constructed by taking every other note from a scale. For example, in the C major scale, the notes C, E, and G form a triad. These three notes are the first, third, and fifth notes of the scale, respectively. Triads are the foundation of many chords and are commonly used in music theory and composition.
If you walk 4mi north and then 2mi south what is your total displacement?
Answer:
your total displacement is 2 miles north
Explanation:
Which of the following statements about the transmission of culture not being restricted to the parent-offspring relationship is true correct: -The rules that govern genetic transmission are different from those governing cultural transmission.-Cultural transmission is more complicated than genetic transmission.-Transmission of culture occurs between related and unrelated individuals, as well as through various forms of media.-Unlike genetic transmission, culture is transmitted throughout life.
The statement that transmission of culture occurs between related and unrelated individuals, as well as through various forms of media, is true.
This means that cultural transmission is not restricted to the parent-offspring relationship, and can occur through social interactions with peers, teachers, and other individuals, as well as through media such as books, television, and the internet. While genetic transmission is limited to the passing on of genes from parent to offspring, cultural transmission is a more complex process that can involve multiple sources and methods of transmission.
Genetic transmission is the process through which genes are passed from parent organisms to their progeny. It takes place during reproduction when genes, which are sections of DNA, are passed from one generation to the next, assuring the inheritance of traits and characteristics.
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How does light energy work
Answer:
Light consists of photons, which are produced when an object's atoms heat up. Light travels in waves and is the only form of energy visible to the human eye.
Explanation:
Now What is light?
-Light ( or light energy ) is defined as a form of electromagnetic radiation and a type of kinetic energy.
-Light is made up of photons. Photons is the basic unit of light. They are produced when an object's atom is subjected to heat. The more the atoms are heated, the more photons are created.
-Light travels in the form of a wave but it does not require any medium for transmission.
-Light travels so fast, nothing is faster than it. It travels at a constant speed of 186,282 miles/sec ( 300,000 km/sec ) in vacuum and whether the source is moving or stationary.
-Light can be measured in either joules, calories ( energy units ), quanta and einsteins ( quantum units ). Conversion from one unit to another heavily depends on wavelength.
Now an unaided human eye can only see the visible light, namely red, orange, yellow green, blue, indigo and violet (Roy G Biv) but light also comes in other forms that we cannot see, they are named, radio wave, microwave, infrared, ultraviolet, x-ray and gamma ray.
explain why many houses in hot areas like Mombasa should be painted white while those in colder places like timboroa should be painted with dark colours
Answer:
In places of hot climate, it is advised that the outer walls of house be painted white because white color does not absorb any heat radiation from the sun which keep inside cool even if there is hot climate outside the house.
Suppose that a ball is dropped from the upper observation deck of a building, 450 m above the ground. (a) What is the velocity of the ball after 7 seconds? (b) How fast is the ball traveling when it hits the ground?
(a) The velocity of the ball after 7 seconds is approximately 68.6 m/s.
(b) The ball is traveling at a speed of approximately 95.4 m/s when it hits the ground.
To determine the velocity of the ball after 7 seconds and its speed when it hits the ground, we can use the equations of motion under constant acceleration.
(a) The initial velocity of the ball is zero since it is dropped from rest. The acceleration due to gravity is approximately \(9.8 m/s^2\) (assuming no air resistance). Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can calculate the velocity after 7 seconds:
\(v = 0 + (9.8 m/s^2) * 7 s = 68.6 m/s\)
Therefore, the velocity of the ball after 7 seconds is approximately 68.6 m/s.
(b) To find the speed of the ball when it hits the ground, we need to determine the time it takes for the ball to fall from a height of 450 m. We can use the equation \(s = ut + (1/2)at^2\), where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have \(t^2 = (2s) / a\).
\(t^2 = (2 * 450 m) / (9.8 m/s^2) = 91.84 s^2\)
Taking the square root, t ≈ 9.59 s
Now, we can calculate the final velocity using the equation v = u + at:
\(v = 0 + (9.8 m/s^2) * 9.59 s ≈ 94.1 m/s\)
Hence, the ball is traveling at a speed of approximately 94.1 m/s when it hits the ground.
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If an 800 kg roller coaster is at the top of its 50 high trackwill have a potential energy 392,000 J and a energy of This means the total mechanical energy is 392,000 the cart drops down to where its kinetic energy is now 92, 000J how high off the ground is the cart now?
Given data:
* The mass of the roller coaster is m = 800 kg.
* The total mechanical energy is E = 392000 J.
* The kinetic energy at the particular height (let h') is K = 92000 J.
Solution:
The potential energy of the roller coaster at h' is,
\(\begin{gathered} U=E-K \\ U=392000-92000 \\ U=300000\text{ J} \end{gathered}\)The potential energy in terms of height and mass is,
\(U=\text{mgh}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} 300000=800\times9.8\times h \\ 300000=7840\times h \\ h=\frac{300000}{7840} \\ h=38.3\text{ m} \end{gathered}\)Thus, the height of the roller coaster from the ground is 38.3 meters.
The graphic organizer compares energy transfer in two layers of the sun.
Which labels belong in the regions marked X and Y?
A)
X: Absorbs energy from the core
Y: Takes longer for photons to move through
B)
X: Releases energy to the photosphere
Y: Takes longer for photons to move through
C)
X: Takes longer for photons to move through
Y: Absorbs energy from the core
D)
X: Takes longer for photons to move through
Y: Releases energy to the photosphere
Answer:
B
Explanation:
Got it right
Answer:
B. X: Releases energy to the photosphere
Y: Takes longer for photons to move through
Explanation:
Right on ED2021, goodluck!
the current that leaves and re-enters a single power source in a parallel circuit is called the ? .
The current that leaves and re-enters a single power source in a parallel circuit is called the branch current.
In a parallel circuit, there are multiple branches that connect to the same power source. Each branch provides a separate path for current to flow from the power source to the load. The branch current is the current that flows through each individual branch of the circuit, and it represents the current that is drawn by each individual load in the circuit.
Since the current in a parallel circuit splits between the different branches, the total current flowing out of the power source is equal to the sum of the currents flowing through each individual branch. Similarly, the current re-enters the power source through each branch, and the total current flowing back into the power source is equal to the sum of the currents flowing through each branch.
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batteries are used to power flashlights the energy stored in batteries is converted to light energy given off by flashlights what happens to the energy as it changes form? A) all of the energy is transformed into light energy. B) some of the energy transforms to thermal energy C) half of the energy is transformed to thermal energy. D) half of the energy is transformed to light energy.
Answer:
some of the energy is transformed to thermal energy
Answer:
some of the energy transforms to thermal energy
Explanation:
Part II: Blackbody Curves Different colors of light are manifestations of the same phenomenon but have different wavelengths. For example, red light has a wavelength between 650 nm and 750 nm, while violet light has a shorter wavelength between 350 nm and 450 nm. Stars also give off light at wavelengths outside the visible part of the spectrum as seen in Figures 2a, 2b, and 20. The two most important features of a star's blackbody curve are: • its maximum height or peak - an indication of the star's energy output; and • the wavelength at which this peak occurs (called the peak wavelength) - an indication of the star's temperature (the longer the peak wavelength, the cooler the star) For example, if Star A and Star B are the same size and temperature, they will have identical blackbody curves. However, if Star B is the same size as Star A, but is cooler, its energy output is less at all wavelengths and the peak occurs at a longer wavelength (toward the red end of the spectrum). This is shown in Figure 2a. 3000 SA! OOO mange Sur 18000 n Su 4000K VIBOTOR We WIDOTOR Figure 20 WEBGYON Figure 2c Figure 26 Use Figure 2a to answer questions 6 -9. Assume Stars A and B are the same size. 6) Which star gives off more red light? Explain your reasoning, 7) Which star gives off more blue light? Explain your reasoning. 3) Which star looks redder? Explain your reasoning. 9) Two students are discussing their answers to question 8. Student 1: Star A looks redder because it is giving off more red light than Star B. Student 2: I disagree, you're ignoring how much blue light Star A gives off. Star A gives off more blue light than red light so it looks bluish. Star B gives off more red than blue so it looks reddish. That's why Star B looks redder than Star A. Do you agree or disagree with either or both of the students? Why? 10) Using the blackbody curves for the stars shown in Figure 2b, circle the correct answer for each characteristic of the curves below. Longer peak wavelength Lower surface temperature Looks red Looks blue Greater energy output Star A Star A Star A Star A Star A Star C Star C Star C Star C Star C Same Same Both Both Neither Neither 11) How must Star C be different from Star A to account for the difference in energy output? 12) Two students are discussing their answers to question 11. Student 1: The peaks are at the same place so they must be at the same temperature. If Star C were as big as Star A, it would have the same output. Since the output is lower, Star C must be smaller. Student 2: No. If its output is lower, it must be cooler. Since the temperature of the two stars are the same, they must be the same size. Do you agree or disagree with either or both of the students? Why? Consider the blackbody curves for the stars shown in Figure 2c when answering questions 13 - 15. 13) For each star, describe its color as either reddish or bluish. Star A: Star D: 14) Which star has the greater surface temperature? Explain your reasoning. 15) Which star is larger? Explain your reasoning. (Hint: consider how the energy output and temperatures for the two stars compare.)
6) Star A gives off more red light because its peak is farther to the red end of the spectrum.
What is spectrum?Spectrum is a term used to describe the complete range of frequencies of electromagnetic radiation, from the longest radio waves to the shortest gamma rays. It is also used to refer to the full range of visible light, from the lowest frequency red light to the highest frequency violet light. This range of frequencies is divided into smaller sections, such as infrared, ultraviolet, and radio waves.
7) Star B gives off more blue light because its peak is farther to the blue end of the spectrum.
8) Both students are correct. Star A gives off more blue light than red light and appears bluish, while Star B gives off more red light than blue light and appears reddish.
11) Star C must be cooler than Star A to account for the difference in energy output.
14) Star D has the greater surface temperature because its peak is higher and closer to the blue end of the spectrum.
15) Star D is larger because its peak is higher and its energy output is greater than Star A.
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Effective Mass: Calculate the dispersion relation of a simple cubic tight-binding band. Calculate the effective mass tensor (Mij) for electrons in a simple cubic tight-binding band at the center (k = (0,0,0) = T), at the face center (k = (0,1,1) = X), and at the corner (k = (1, 1, 1) = L) of the Brillouin zone. Where the units are 7/a, a being the lattice spacing. Discuss the usefulness of the effective mass concept at (k = (0,1, 1)).
The dispersion relation of a simple cubic tight-binding band is given by E(k) = E_0 - 2t(cos(k_xa) + cos(k_ya) + cos(k_za)).
What is the dispersion relation for a simple cubic tight-binding band?The dispersion relation of a simple cubic tight-binding band is given by E(k) = E_0 - 2t(cos(k_xa) + cos(k_ya) + cos(k_za)), where E_0 is the on-site energy and t is the hopping parameter.
To calculate the effective mass tensor (Mij), we need to determine the second derivative of the energy with respect to the wavevector (k). For each point in the Brillouin zone, we differentiate the dispersion relation twice with respect to each component of k, resulting in a 3x3 tensor.
At the center of the Brillouin zone (k = (0,0,0) = T), the effective mass tensor is diagonal with all elements equal to m_0 = 1/(2t*a^2).
At the face center (k = (0,1,1) = X), the effective mass tensor has m_xx = m_yy = m_0 and m_zz = m_0/2. At the corner (k = (1,1,1) = L), the tensor has m_xx = m_yy = m_zz = m_0/2.
The effective mass concept provides information about the curvature of the energy bands near specific points in the Brillouin zone. It is useful for characterizing charge transport properties, such as electron mobility, as it relates to the response of electrons to an external electric field.
At the face center (k = (0,1,1)), the effective mass tensor indicates anisotropy in the electron mobility, as the m_zz component is smaller than m_xx and m_yy.
This anisotropy implies that electrons exhibit different mobilities along different crystallographic directions, which can have implications for device design and material engineering in specific applications.
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A No. _____ THHN conductor is required for a 19.7 ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
A No. 12 THHN conductor is required for a 19.7-ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
To determine the size of the THHN conductor required for a 19.7-ampere load, we will need to use the ampacity tables from the National Electric Code (NEC).
The ampacity tables provide the maximum current-carrying capacity of various types and sizes of conductors based on factors such as ambient temperature and the number of current-carrying conductors in the raceway or cable.
Assuming a copper conductor, we can use NEC Table 310.15(B)(16) to find the ampacity of a No. 12 THHN conductor at an ambient temperature of 75F with nine current-carrying conductors. According to the table, the ampacity of a No. 12 THHN conductor with nine current-carrying conductors at 75F is 20 amperes.
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