Answer:
RiRi
Explanation:
A helicopter travels from point C to point A to perform a medical supply drop. The helicopter then needs to land at point B. How many degrees should the helicopter turn at point A to travel towards point B? A right-angled triangle A B C, with an exterior angle. The right angle is formed at angle B and angle C is marked as 32 degrees. Angle B and angle C is a pair of opposite inferior angles to the exterior angle. The helicopter should turn
Answer:
32 degrees
Explanation:
Using the principle of geometry, after dropping the supply at point A, the helicopter will need to make a turn of 122° to travel towards point B.
From the triangle :
The angle at A ; which can be obtained as the sum of the interior angles in a triangle is defined as :
A + B + C = 180
A + 90 + 32 = 180
A = 180 - 122
A = 58°
The helicopter will have to turn around the straight line, forming a straight line angle with A ;
Hence,
Angle turned by helicopter + 58° = 180° (angle on a straight line)
Angle turned by helicopter = 180° - 58° = 122°
Hence, the angle turned by the helicopter to navigate to point B is 122°
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2. Which of the following will have no effect on the reaction time of a person driving an
automobile?
age
of the driver
b) Distractions in the environment
c) The speed of the automobile
d) Talking on a cell phone while driving
a) The
A downward force of 18-N is applied to a book sitting on a table. The table where the book is placed provides a static friction with a maximum value of 20-N and Kinetic friction of roughly 12-N. If the book has a mass of 3.0-kg, what is the acceleration of the book?
Given :
Force applied on book, F = 18 N.
Kinetic friction, \(K_f = 12\ N\).
Mass of book, M = 3 kg.
To Find :
The acceleration of book.
Solution :
Equation of force applied on book is :
\(F_{net} = F - K_f\\\\ma= 18 - 12 \\\\a=\dfrac{6}{3}\ m/s^2\\\\a = 2\ m/s^2\)
Therefore, acceleration of book is 2 m/s².
Hence, this is the required solution.
Freud was an influential and controversial psychologist who believed that psychology should study the unconscious mind. Describe
the two books Freud published in the early 1900s. (Site 2)
Answer:
The Interpretation of Dreams": Freud noticed that dreams played an important role in his analysis of neurotic and "hysterical" patients. When he asked his patients to talk about whatever came into their minds, they often referred to their dreams, which would set off other associations and often illuminate other important connections in their past experience. It took Freud about two years to write the book, finishing it in September 1897.
what evidence do we have that galaxies collide with one another?
we have observational evidence of distorted and irregular-shaped galaxies, computer simulations that reproduce the observed features of colliding galaxies, measurements of Doppler shift, and observations of high-energy phenomena such as X-rays and radio waves. Together, these provide compelling evidence that galaxies collide with one another.
What is the galaxy?A galaxy is a vast system of stars, gas, dust, and other matter bound together by gravity. Galaxies come in a variety of shapes and sizes, ranging from small dwarf galaxies with a few hundred million stars to massive elliptical galaxies that can contain trillions of stars.
The stars in a galaxy are not distributed evenly, but are clustered together in various structures such as spiral arms, bars, and globular clusters. In addition to stars, galaxies also contain interstellar gas and dust, which can be used to form new stars.
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If an object is in free fall for four seconds, about how fast
will it be falling?
a) 10 m/s
b) 20 m/s
c) 30 m/s
d) 40 m/s
draw a figure of a simple pendulum explain its amplitude and effective length ?
Answer:
Explanation:
A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.
In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.
Amplitude:
The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."
Effective Length:
The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."
It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.
Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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what is force of gravity
Answer:
On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.
How fast will a bug that is going 640cm in 320 seconds travel across the
floor? *
O 2 seconds
O 2.56 cm/s
O 40,000 seconds
O 2 cm/s
Answer:
2 cm/s
Explanation:
As, 640cm/320s = 2cm/1s
Therefore, 2cm/ s
Two packing crates of masses 10.0kg and 5.00kg are connected by a light string that passes over a frictionless pulley as shown in Figure. The 5.00kg crate lies on a smooth incline of angle 40.0 degree . Find the acceleration of the crates and the tension in the string.
The acceleration of the string is 4.3 m/s2.
What is Acceleration?We regard the positive direction for the vertical motion of mass m1 to be downward and the positive direction for the motion of mass m2 on the incline to be to the right and parallel to the incline.
There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing. The information on the right depicts an object that is speeding as it moves northward.
Therefore, The acceleration of the string is 4.3 m/s2.
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.
A potato is launched from the ground at an 73 degree angle with a velocity of 48 m/s.
What maximum height will the potato reach? (Answer in meters)
Type your answer...
Answer:
107.4 meters
Explanation:
gravity is 9.8m/s^2
max height = (velocity squared times sin squared angle) ÷ ( speed of gravity times 2 )
max height = (48 squared times sin of 73 squared) ÷ ( 9.8 times 2 )
The current through the 30 Ω resistor in (Figure 1) is measured to be 0.50A.
What is the emf E of the battery?
The emf E of the battery is 25V.
To find the emf E of the battery, we need to use Ohm's law and Kirchhoff's voltage law.
First, let's find the voltage drop across the 30 Ω resistor using Ohm's law:
V = IR
V = (0.50A)(30 Ω)
V = 15V
Next, let's apply Kirchhoff's voltage law to the circuit:
E - V - IR = 0
where E is the emf of the battery, V is the voltage drop across the 30 Ω resistor, and IR is the voltage drop across the 20 Ω resistor.
Substituting the values we know:
E - 15V - (0.50A)(20 Ω) = 0
Simplifying:
E - 25V = 0
E = 25V
Therefore, the emf E of the battery is 25V.
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What two objects does conduction start with?
Answer: It could be many things. For example liquid, gaseous or solid objects.
Explanation: For conduction to take place between two objects, they must be touching each other. For conduction to occur between atoms within the same object, they must also be touching (or nearly touching).
or R, how does the cofinite topology compare with the usual topology? With the left ray topology? With the cocountable topology?
The cocountable topology is coarser than the usual topology and is not Hausdorff.
Let X be an infinite set and P (X) the power set of X. We define three topologies on X: the cofinite topology, the left ray topology, and the cocountable topology. We will compare each topology to the usual topology on X. We denote the usual topology by u.
The Cofinite Topology Let F be the family of subsets of X such that F is either finite or X. That is, F = {A ⊆ X : A is finite or A = X}. The cofinite topology on X is defined by Tcf = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cofinite topology are the complements of finite sets plus the empty set.
A subset A of X is closed if and only if A is either X or finite. Thus, in the cofinite topology, every infinite subset of X is dense in X. Compared to the usual topology, the cofinite topology has fewer open sets and is coarser. In other words, the cofinite topology is a weaker topology than the usual topology.
The cofinite topology is also Hausdorff since given any two distinct points x, y ∈ X, the complements of the cofinite sets containing x and y are disjoint
. The Left Ray Topology Let F be the family of subsets of X such that F contains the empty set and all sets of the form L(a) = {x ∈ X : x < a}, where a is any element of X. The left ray topology on X is defined by TL = {U ⊆ X : U = ∅ or U contains some set L(a) from F}.
The open sets in the left ray topology are the empty set, all left rays L(a), and all sets that contain a left ray L(a). A subset A of X is closed if and only if A is the empty set, X, or contains the right endpoint of every left ray it meets. The left ray topology is finer than the cofinite topology but coarser than the usual topology.
Thus, the left ray topology is a weaker topology than the usual topology but stronger than the cofinite topology.
The left ray topology is also Hausdorff. The Cocountable Topology Let F be the family of subsets of X such that F is countable or all of X. The cocountable topology on X is defined by Tcc = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cocountable topology are the complements of countable sets plus the empty set.
A subset A of X is closed if and only if A is either countable or all of X. Thus, in the cocountable topology, every countable subset of X is nowhere dense.
Compared to the usual topology, the cocountable topology is coarser. The cocountable topology is also not Hausdorff since any two nonempty open sets have nonempty intersection. Hence, in the cocountable topology, the closure of a singleton set is the whole space X.
Among the three topologies, the cofinite topology is the weakest topology, and it is also a Hausdorff space. The left ray topology is a topology that is weaker than the usual topology but stronger than the cofinite topology, and it is also a Hausdorff space. Finally, the cocountable topology is coarser than the usual topology and is not Hausdorff.
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A sound wave with speed of 375m/s find the temperature?
Answer:
The temperature of the gas is approximately 349.76980 K
Explanation:
The given parameter for the speed of the sound wave, v is v = 375 m/s
The formula for the speed of sound in a gas given the temperature of the gas, is given as follows;
\(v = 331.3 \times \sqrt{ \dfrac{T_K}{273 \ K } }\)
Where;
\(T_K\) = The temperature of the gas through which the sound travels
Therefore, for a speed of sound of 375 m/s, we have;
\(375 = 331.3 \times \sqrt{ \dfrac{T_K}{273 \ K } }\)
\(T_K = 273 \ K \times \left (\dfrac{375}{331.3} \right )^2 \approx 349.76980 \ K\)
\(T_K\) ≈ 349.76980 K
The temperature of the gas, \(T_K\) ≈ 349.76980 K.
heat transfer that occurs through liquids and gases is called
Heat transfer that occurs through liquids and gases is called Convection.
Heat transfer is the exchange of thermal energy between physical systems. It occurs when there is a temperature difference between two objects or regions of space, causing heat to flow from the hotter system to the cooler one. There are three modes of heat transfer: conduction, convection, and radiation.
Conduction is the transfer of heat through a material by direct contact. In this mode, heat flows from a region of higher temperature to a region of lower temperature. Convection is the transfer of heat through a fluid (liquid or gas) by the movement of the fluid itself. This mode of heat transfer occurs through convection currents, where hot fluids rise and cooler fluids sink.
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a catcher "gives" with the ball when he catches a 0.196 kg baseball moving at 31 m/s. if he moves his glove a distance of 5.32 cm, what is the average force acting on his hand?
Answer:
3540.5N
Explanation:
Step one:
given data
mass m= 0.196kg
speed v= 31m/s
distance r= 5.32cm = 0.0532m
Step two
The expression relating force, mass, velocity and distance is
F= mv^2/r
substitute we have
F=0.196*31^2/0.0532
F=0.196*961/0.0532
F=188.356/0.0532
F=3540.5N
Experiment 1: Exploring Charge with Scotch® Tape
In this experiment, you will observe the behavior of charged objects using pieces of Scotch® tape.
Materials
Scotch® Tape
Ruler
*Pen
*Flat Work Surface
Procedure
Part 1
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down the piece of tape 1 cm from the end, leaving a 9 cm sticky piece with a 1 cm handle.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Repeat Steps 1 – 4 with a second 10 cm piece of tape. Stick the second piece of tape at least 15 cm away from the first piece on the same surface.
6. Quickly pull off both strips of tape from the surface and ensure that the pieces do not touch.
7. Carefully bring the non-sticky sides of the tape together and record observations about the behavior of the pieces in Table 1.
8. Discard the tape.
Part 2
1. Use the ruler to measure a piece of tape that is 10 cm long.
2. Tear the tape to remove the 10 cm piece from the roll.
3. Create a "handle" on one side of the piece of tape by folding down 1 cm of tape from one end.
4. Stick the entire sticky surface of the tape to a table top, counter top, or another flat surface.
5. Use a pen and write "B1" on the tape. "B" stands for bottom.
6. Repeat Steps 1 – 4 with a second 10 cm piece of tape. This time, press the second strip of tape on top of the one labeled "B1".
7. Use the pen to label the top piece with a "T1". "T" stands for top.
8. Create a second pair of pieces of tape by repeating Steps 1 – 7. This time, label the bottom piece "B2" and the top piece "T2".
9. Use the T1 handle to quickly pull off T1 strip of tape from the flat surface.
10. Use the B1 handle to peel off the bottom strip from the flat surface. Keep both B1 and T1 pieces away from each other.
11. Bring the non-sticky sides of B1 and T1 together and record observations about the behavior of the pieces in Table 1.
12. Set the pieces of tape, non-sticky side down, on the table approximately 15 cm away from each other. Do not stick them back on the table!
13. Repeat Steps 9 - 12 for B2 and T2.
14. Carefully bring the non-sticky sides of piece "T1" and "B2". Record observations about the behavior of the pieces in Table 1.
15. Set them back down, non-sticky side down.
16. Repeat Steps 14 - 15 for "T1" and "T2". Record your observations in Table 1.
17. Repeat Steps 14 - 15 for "B1" and "B2". Record your observations in Table 1.
18. Repeat Steps 14 and 15 for "T1" and the hair on your leg or arm. Record your observations in Table 1.
19. Repeat Steps 14 and 15 for "B1" and the hair on your leg or arm. Record your observations in Table 1.
Table 1: Electric Charge Observations
procedure
interacting pieces observation
Part 1 Two pieces on table Part 2 T1 / B1 T2 / B2 T1 / B2 T2 / B1 B1 / B2 T1 / Arm Hair B1 / Arm Hair ***The observation is filled.
Post-Lab Questions
1. Describe the interaction between the top and bottom strips as they relate to electric charge. Did the behavior of the pieces change when the tape was from different sets?
2. Describe the interaction between two top and two bottom pieces of tape as they relate to electric charge. Is this consistent with the existence of only two types of charge? Use your results to support your answer.
3. Did the top tape attract your arm hair? Did the bottom tape attract your arm hair? Usually arm hair is neutral; it has equal number positive and negative charges. Use this information to explain your results.
4. Which pieces of tape are positively charged? Which pieces of tape are negatively charged? Explain your reasoning.
5. Use your data to create a rule describing how like charges, opposite charges, and neutral bodies interact.
6. What do you observe about the force of attraction or repulsion when the pieces of tape are closer together and farther apart? Does this change happen gradually or quickly?
1.When the non-sticky sides of the two pieces of tape recording are brought together, they repel each other. This is due to the buildup of electric charge on the face of the tape recording when it was hulled off from the flat face.
2.The pieces didn't change when the tape recording was from different sets. When two top or two nethermost pieces of tape recording are brought together, they repel each other.
3.When a top and nethermost piece of tape recording are brought together, they attract each other. This is harmonious with the actuality of only two types of charge, positive and negative. The results support the fact that the top and nethermost pieces of tape recording had contrary charges. The top tape recording attracted the arm hair, while the bottom tape recording didn't attract the arm hair. Arm hair is generally neutral, but it can be concentrated by the electric field of the charged tape recording.
4.The top tape recording is negatively charged, and it concentrated the arm hair, which has a positive charge. This redounded in magnet between the top tape recording and the arm hair. The pieces of tape recording labeled" T1" and" B2" are appreciatively charged, while the pieces of tape recording labeled" B1" and" T2" are negatively charged. This can be determined from the compliances.
5.When the appreciatively charged tape recording was brought near to a negatively charged tape recording, they attracted each other. When two appreciatively charged videotapes or two negatively charged videotapes were brought near together, they repelled each other. Like charges repel each other, contrary charges attract each other, and neutral bodies aren't affected by electric fields.
6.The force of magnet or aversion between the pieces of tape recording increases as they get near together and decreases as they move further piecemeal. This change happens gradationally, not snappily.
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A biker goes out for a ride and begins riding North at 18 km/h for 200 minutes, then the driver turns around and rides at 12 km/h South for another 50 minutes.
Answer:
Explanation:
18 km / h
= 300 m / min
12 km / h = 200 m / min
distance travelled in 200 minutes = 300 x 200 = 60000 m
distance travelled in 50 minute in return journey = 200 x 50 = 10000 m
total distance travelled = 70000 m
total time = 250 minute
speed = 70000 / 250
= 280 m / min
= 16.8 km / h
Total displacement = 60000 - 10000 = 50000 m
total time = 250 min
velocity = 50000 / 250
= 200 m / min
= 12 km / h
two long, parallel wires with currents are placed in a uniform magnetic field. if the current in one wire is doubled and the current in the other wire is halved, what happens to the magnitude of the force between these two wires?
Using the concepts of magnetic force, we got that magnitude remains same between two long, parallel wires with currents when placed in a uniform magnetic field and if the current in one wire is doubled and the current in the other wire is halved.
We know very well that if the two wires are placed at same distance with each other, then both of them exerts a force on each other, the direction of the force will depend on the direction flow of current.
Force exerted by the two wires is given by =[(μ\(_o\)/4\(\pi\))×I₁×I₂×B]/r² where r the distance between the two wires and I₁ and I₂ are the current flowing in the two separate wires.
When amount of current in first wire is doubled then I₁=2I₁,
similarly when amount of current in second wire is halved then I₂=(1/2)I₂
Then force =[(μ\(_o\)/4\(\pi\))×2I₁×(I₂/2)×B]/r²
which is equal to [(μ\(_o\)/4\(\pi\))×I₁×I₂×B]/r².
Hence, for two long, parallel wires with currents are placed in a uniform magnetic field. if the current in one wire is doubled and the current in the other wire is halved, the magnitude of the force between these two wires remains same.
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Are we really real or are we all an allusion?Do you believe in past lives?How do you think you died in past life?
Answer:
I don't even know
Explanation:
Shower thoughts
Answer:we could be an allusion but we prolly will never kno.. so much of the world is convinced, its all jus a convincing game.. i believe in past lives, future lives. i think in my past life i was stabbed and then the slit my side from the chest to right below my stomach, due to freckles lining up
A box sits on a platform supported by a compressed spring. The box has a mass of 1.0 kg. When the spring is released, the spring gives 14.7 J of energy to the box. What will be the maximum height above the platform reached by the box before it begins to fall
The maximum height above the platform reached by the box before it begins to fall is 1.5 m.
The given parameters:
Mass of the box, m = 1.0 kgEnergy stored in the spring, E = 14.7 JThe maximum height above the platform reached by the box before it begins to fall is calculated as follows;
\(mgh = E\\\\h = \frac{E}{mg} \\\\h = \frac{14.7}{1 \times 9.8} \\\\h = 1.5 \ m\)
Thus, the maximum height above the platform reached by the box before it begins to fall is 1.5 m.
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Match the words on the left with the words on the right.Group ofanswer choices Wind Turbine[ Choose ] Tar Sands MountaintopRemoval Geothermal Power Albert Einstein No carbon dioxide produced Photovoltaic[ Choose ] Tar Sands Mountaintop Removal Geothermal Power Albert Einstein No carbon dioxide producedCoal[ Choose ] Tar Sands Mountaintop Removal Geothermal Power Albert Einstein No carbon dioxide producedAlberta, Canada[ Choose ] Tar Sands Mountaintop Removal Geothermal Power Albert Einstein No carbon dioxide producedWestern USA
The Western USA is a region of the United States
Group of answer choices Wind Turbine[ Choose ]
No carbon dioxide produced Photovoltaic Tar Sands Mountain top Removal Geothermal Power
Albert Einstein[ Choose ] No carbon dioxide produced Photovoltaic Tar Sands Mountaintop Removal Geothermal
PowerCoal[ Choose ] No carbon dioxide produced Photovoltaic Tar Sands Mountaintop Removal Geothermal
PowerAlberta, Canada[ Choose ] Tar Sands No carbon dioxide produced Mountaintop Removal Geothermal Power
Albert EinsteinWestern USA[ Choose ] No carbon dioxide produced Photovoltaic Tar Sands Mountaintop Removal Geothermal
PowerAlbert Einstein is related to the theory of relativity.
The Wind Turbine is a device that converts the kinetic energy of wind into mechanical energy.
No carbon dioxide is produced in photovoltaic, Geothermal Power, and Wind Turbine as they do not involve combustion.
A tar sand is a sandstone that contains bitumen.
Mountaintop Removal is the practice of mining through the summit of a mountain.
Coal is a combustible black or brownish-black sedimentary rock.
Alberta, Canada is one of the largest oil reserves in the world, known as Tar Sands.
Finally, the Western USA is a region of the United States.
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the temperature of a 2.0 kg block increases by 5 degrees celsius when 2000j of thermal energy are added to the block. what is the specific heat of the block?
Specific heat is quantity of heat required to increase the temperature of a substance by one degree celsius.
The formula to calculate heat energy is
Q=mc∆T
How to calculate specific heat capacity using heat energy formula?We know, Q=mc∆T
Where Q = heat energy
m = mass
c= specific heat capacity
∆T= change in temperature
Thus,
According to above formula
c= Q/m∆T
Here m= 2 kg
∆T= 5 degrees
Q= 2000 joules
c= 2000/2×5
c= 200
Thus, the specific heat capacity of the block is 200.
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what plant produces energy
Explanation:
Well it depends on what type of energy all plants produce energy for them to survive but if its a certain energy your looking for make sure to put it in you quesion
You have finished running a marathon and you are relaxing and your body is
slowing down. What part of the autonomic nervous system is at work?
A. Sympathetic
B. Aphasic
C. Parasympathetic
D. Encoding
SUBMIT
If a stream drops 45 meters in 15 kilometers, what is its gradient? a) 333.3
meters per kilometer b) 0.33 meters per kilometer c) 3 meters per kilometer d) 0.003 meters per kilometer
To calculate the gradient of the stream, we need to determine the change in elevation per unit of horizontal distance.
In this case, the stream drops 45 meters over a horizontal distance of 15 kilometers. To find the gradient, we divide the vertical drop (45 meters) by the horizontal distance (15 kilometers). However, to ensure consistent units, we convert the 15 kilometers to meters by multiplying it by 1,000 (since there are 1,000 meters in a kilometer).
So, the calculation becomes:
Gradient = Vertical drop / Horizontal distance
= 45 meters / (15,000 meters)
= 0.003 meters per meter
This means that for every meter of horizontal distance, the stream drops by 0.003 meters vertically. Simplifying the expression, we can also express it as 3 millimeters (mm) per meter.
Therefore, the correct answer is d) 0.003 meters per kilometer.
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What is an essential characteristic of an object in equilibrium?
1) zero velocity
2) zero acceleration
3) zero potential energy
4) zero kinetic energy
Answer:
2) zero acceleration
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
Mathematically, the motion of an object is described in terms of time, distance, speed, velocity, position, displacement, acceleration, etc.
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
Generally, an object is said to be in equilibrium when neither the energy possessed by the object not state of motion changes with respect to time. Thus, the vector sum of all the forces acting upon an object that's in equilibrium is zero.
In conclusion, an essential characteristic of an object in equilibrium is zero (0) acceleration because there's no change in its velocity with respect to time.
The velocity of a particle movie along the x-axis is v(t) = t^2 - 2t, with t measured in minutes and v(t) measured in feet per minute. To the nearest foot find the total distance traveled by the particle from t = 0 to t = 3 minutes.
zero
Explanation
we know that when derivantind the position function respecto to time we got the function for velocity, so we can integrate the given function to obtain the function for velocity
hence
Step 1
a) integrate to find the function for distance travelede
\(\begin{gathered} v(t)=t^2-2t \\ integrate \\ \int(t^2-2t)\text{ dt} \\ \int(t^2-2t)\text{ dt=}\frac{t^{2+1}}{2+1}-\frac{2t^{1+1}}{2} \\ \int(t^2-2t)\text{ dt=}\frac{t^3}{3}-t^2 \end{gathered}\)so
\(\begin{gathered} d(t)=\frac{t^3}{3}-t^2+C \\ C=initial\text{ distance , so c=0} \end{gathered}\)Step 2
now,we have the functio for the distance,
a) evaluate for t=0
\(\begin{gathered} d(t)=\frac{t^3}{3}-t^2 \\ d(0)=\frac{t^{3}}{3}-t^2=\frac{0^3}{3}-0^2=0-0=0 \\ d(0)=0 \end{gathered}\)b) evaluate for t=3 minutes
\(\begin{gathered} d(t)=\frac{t^3}{3}-t^2 \\ d(3)=\frac{3^3}{3}-3^2=\frac{27}{3}-9=9-0 \\ d(3)=0 \end{gathered}\)now, find the total distance traveled by the particle from t = 0 to t = 3 minutes., subtract the positions
\(distance=\Delta d=0m-0m=0m\)so, the total displacement would be zero,but :
the particle actually travels ,it start in negative direction,and then it moves to positive direction, after 3 minutes the particle is in the same place
so, the answer is zero