Answer:
The resistance interval is \(R = 1.8 \pm 0.037\)
Explanation:
From the question we are told that
The voltage is V = 9 V
The current is \(I = 5 \pm 0.1\)
The maximum current would be
\(I_{max} = 5 + 0.1 = 5.1 \ A\)
The minimum current would be
\(I_{min} = 5 - 0.1 = 4.9 \ A\)
The maximum resistance is
\(R_max = \frac{V}{I_{min}}\)
\(R_max = \frac{9}{4.9}\)
\(R_max = 1.837 \Omega\)
The minimum resistance is
\(R_{min} = \frac{V}{I_{max}}\)
\(R_{min} = \frac{9}{5.1}\)
\(R_{min} = 1.765 \Omega\)
and \(R = \frac{9}{5} = 1.8 \Omega\)
The interval R lies is
\(R = 1.8 \pm 0.037\)
Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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What is momentum?.
.
.
.
The quantity of motion of a moving body, measured as a product of its mass and velocity.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.velocity is a term that describes the speed and direction of a point's motion.Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.To learn more about : Velocity
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Suppose that a series RL circuit is connected to a voltage source whose input voltage (Vin) is shown in the figure above. As shown in the figure above, the input voltage Vin = Vmax only within time interval 0 ≤ t ≤ T. The input voltage Vin = 0 outside this time interval. Assume that initially (at t = 0), no current is flowing in this circuit (I = 0)! A Determine the output voltage Vout as a function of time t! B Assume that the time interval T is very short so that T → 0, and also assume the the maximum voltage Vmax is quite high, so that VmaxT ≈ Φimp. Show that the output voltage Vout can be approximated by the following equation : Vout(t) ≈ Φimp τ e −t/τ where τ = L R
A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:
Vout(t) = Vmax * (1 - e^(-t/τ))
Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:
Vout(t) ≈ Vmax * e^(-t/τ)
In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.
Rearranging the equation, we get:
Vout(t) ≈ Φimp * e^(-t/τ)
This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.
The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.
Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.
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what is the 'Water Column"
Answer:a vertical expanse of water stretching between the surface and the floor of a body of water
Explanation:
If the Moon did not rotate at the same rate that it revolved, which of the following would be true?
Answer:
There will be no tides
Explanation:
16. A car A is moving at a speed of 6m/s due north and car B is moving at a speed of 8m/s due east. Find the magnitude and direction of the velocity of car A relative to car B
What is the potential difference across the source?
60 V
220 V
440 V
120 V
Answer:
120 v
Explanation:
The two resistors have an equivalent of 20 * 30 /(20+30) = 12 ohms
10 amps of current in the circuit
v = ir
= 10 * 12 = 120 volts
Here is another way:
The two resistors are in prallel so the voltae across both is the same
use the one on the right v = ir = 4 x 30 = 120 v
Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by
a push when the support string is at an angle of 45° from the vertical direction. The initial
speed of the suspended mass at the release point is 3.0 m/s.
(a) The maximum angle that pendulum moves in the second half of its swing is
(b) The mechanical energy of pendulum (measured relative to its lowest point) is
Answer:
A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?
Explanation:
According to the principal of superposition,
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
Classify each characteristic as either a metal or a nonmetal.
shiny surface
dull surface
good conductor of electricity
good conductor of heat
poor conductor of electricity
poor conductor of heat
malleable
brittle
Answer:
metal, non, metal, metal, non, non, metal, non
Explanation:
knowledge
Which one is the answer
The graph that shows the relationship between the speed and the kinetic energy is option B.
What is the relationship between kinetic energy and speed?Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy. The kinetic energy is the energy of an object that has a velocity
The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.
As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.
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If the distance between two equal masses is doubled and their individual masses are doubled. What would happen to the force between them?
Explanation:
the force will be reduced by a quarter
A certain force gives mass m1, an acceleration of 12 m/s² and mass m2 an acceleration of 3.3. m/s². What acceleration will this force give to the combined mass?
Acceleration is the rate of change of velocity. Usually, acceleration means the speed is transforming, but not always. When an object moves in a circular path at a steady speed, it is still accelerating, because the focus of its velocity is changing.
a = 4,552 m / s², b) a = 2,588 m / s²
Newton's second law is
F = ma
a = F / m
in this case the force remains constant
indicate us
* for a mass m₁
a₁ = F/m₁
a₁ = 12, m/ s²
* for a mass m₂
a₂= 3.3 m / s²
acceleration m = m₂-m₁
substitute
\($\begin{aligned}&a=\frac{F}{m_{2}-m_{1}} \\&1 / a=\frac{m_{2}}{F}-\frac{m_{1}}{F}\end{aligned}$\)
let's calculate
1/a=1/3.3 - 1/12 = 0.21969
a = 4,552 m / s²
a= 4,552m/s²
What is speed and acceleration?Speed estimates the rate of movement of an object, that is, the distance traveled per unit of time. Acceleration calculates the rate of change of velocity, that is, the change in velocity between two different moments
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knowing that the velocity of block b after the impact is observed to be 2.2 m/s to the right, determine the coefficient of restitution between the two blocks. the coefficient of restitution between the two blocks is
The coefficient of restitution between two objects is a measure of the elasticity of the collision between them.
It is defined as the ratio of the relative velocity of separation to the relative velocity of approach between the two objects.
In this problem, the velocity of block b after the impact is observed to be 2.2 m/s to the right. Let us assume that block a is moving to the left with a velocity of v1 just before the impact. According to the law of conservation of momentum, the total momentum of the two blocks before the impact is equal to the total momentum of the two blocks after the impact. Therefore:
\(m1v1 + m2v2 = m1v1' + m2v2'\)
where m1 and m2 are the masses of block a and block b, respectively, v1 and v2 are the velocities of block a and block b just before the impact, and v1' and v2' are their velocities just after the impact.
Since block b is moving to the right after the impact, we can take v2' = 2.2 m/s. We also know that the two blocks stick together after the impact, so v1' = v2'. Therefore, we can simplify the above equation to:
\(m1v1 + m2v2 = (m1 + m2)v1'\)
Solving for v1', we get:
\(v1' = (m1v1 + m2v2)/(m1 + m2)\)
The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation (v2' - v1') to the relative velocity of approach (v1 - v2) between the two blocks. Since the two blocks stick together after the impact, the relative velocity of separation is zero. Therefore:
\(e = (v2' - v1')/(v1 - v2) = 0/(v1 - v2) = 0\)
Hence, the coefficient of restitution between the two blocks is zero.
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2. A 7 kg. Mass is moved across the table at 25 m/sec. What force caused the acceleration?
A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.
To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Given:
Mass (m) = 7 kg
Acceleration (a) = 25 \(m/s^2\)
We can substitute these values into the equation:
Force (F) = mass (m) * acceleration (a)
F = 7 kg * 25 \(m/s^2\)
F = 175 kg·\(m/s^2\)
Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).
To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).
By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)
In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.
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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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Displacement vs. Time
80.0
60.0
40.0
20.0
Displacement (m)
0.0
-20.0
-40.0
-60.0
4.0
6.0
18.0
22.0
0.0 2.0
8.0 10.0 12.0 14.0 16.0 20.0
Time (s)
What is the velocity of the objected represented by the graph between 0.0 s and 4.0 s?
O 7.5 m/s
240 m/s
15 m/s
120 m/s
Please find attached photograph for your answer. Hope it helps. Please do comment. The option is c. 15m/s.
a bottle full of water has a mass of 45g when full of mercury.its mass is 360g if the mass of the empty bottle is 20g. calculate the density of the mercury. state the order in which the reading will be taken
The density of mercury can be calculated using the formula:
Density = (mass of mercury) / (volume of mercury)
To calculate the volume of the mercury, we need to subtract the volume of the bottle from the volume of the bottle filled with mercury.
Volume of bottle = Volume of bottle filled with mercury - Volume of mercury
Let's assume that the volume of the bottle filled with mercury is V1 and the volume of the bottle is V2. We can then write:
Density of mercury = (mass of mercury) / (V1 - V2)
Given that the mass of the empty bottle is 20g, we can calculate the mass of the mercury as follows:
Mass of mercury = (mass of bottle filled with mercury) - (mass of empty bottle)
= 360g - 20g
= 340g
The mass of the bottle filled with water is 45g. Therefore, the mass of the mercury in the bottle is:
Mass of mercury = 360g - 45g = 315g
Let's assume that the density of the bottle is negligible. We can then calculate the volume of the mercury as follows:
Volume of mercury = (mass of mercury) / (density of mercury)
Substituting the values we have:
315g / (density of mercury) = (V1 - V2)
We know that the mass of the water in the bottle is 45g, which means that the mass of the mercury is (360g - 45g) = 315g. Therefore, the volume of the mercury is equal to the volume of the water. We can then write:
Volume of mercury = Volume of water = (mass of water) / (density of water)
The density of water is 1 g/cm³. Substituting the values we have:
315g / (density of mercury) = 45g / 1 g/cm³
Solving for the density of mercury, we get:
Density of mercury = (315g * 1 g/cm³) / 45g
= 7 g/cm³
Therefore, the density of mercury is 7 g/cm³.
The order in which the readings will be taken is as follows:
1. Mass of empty bottle
2. Mass of bottle filled with mercury
3. Mass of bottle filled with water (or the mass of the bottle filled with mercury and the mass of the empty bottle, from which we can calculate the mass of the mercury)
4. Volume
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There is an experiment where hydrochloric acid is added to calcium salt, the gas carbon dioxide is given off, use the info to find out which calcium salt is being usedHow would u test the gas to check if its carbon dioxide remember to include tje change u would expect to see
A white precipitate of calcium carbonate is created when carbon dioxide combines with calcium hydroxide solution.
Thus, A calcium hydroxide solution is limewater. Limewater turns milky or hazy white when carbon dioxide is bubbled through it.
Therefore, you can infer that Co2 is created in the process when it becomes milky or murky white water.
A chemical reaction known as a gas evolution reaction creates a gas, such as oxygen or carbon dioxide. In the instances that follow, an acid and carbonate react to produce salt, carbon dioxide, and water, respectively. For instance, sodium nitrate, carbon dioxide, and water are produced when nitric acid interacts with sodium carbonate.
Thus, A white precipitate of calcium carbonate is created when carbon dioxide combines with calcium hydroxide solution.
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A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 8.33 mmHg. Density of mercury is 13.6 g/cm3.A .By how much does the fluid level rise in the side of the manometer that is open to the atmosphere? (cm)B. By how much does the fluid level rise in the side of the manometer that is open to the atmosphere if the manometer used mercury instead? (cm)
ANSWER:
(a) 6.3 cm
(b) 0.42 cm
STEP-BY-STEP EXPLANATION:
Given:
Density of oil = 0.9 g/cm^3
Density of mercury = 13.6 g/cm^3
Rise in the height of the mercury = 8.33 mm of Hg = 0.833 cm of Hg
(a)
The change in pressure is:
\(\Delta P=\rho\cdot g\cdot\Delta h\)The change in pressure when oil is used is:
\(\Delta P=\rho_{\text{oil}}\cdot g\cdot d\)Equating the above two equation
\(\begin{gathered} \rho\cdot g\cdot\Delta h=\rho_{\text{oil}}\cdot g\cdot d \\ \text{ solving for d:} \\ d=\frac{\rho\cdot\Delta h}{\rho_{\text{oil}}} \\ d=\frac{13.6\cdot0.833}{0.9} \\ d=12.59\text{ cm} \end{gathered}\)The amount of fluid rise is half the difference of level, so the height of rise in the oil
\(\begin{gathered} \Delta h_{oil}=\frac{d}{2} \\ \text{ replacing} \\ \Delta h_{oil}=\frac{12.59}{2}=6.295\cong6.3 \\ \Delta h_{oil}=6.3\text{ cm} \end{gathered}\)(b) If the manometer uses mercury then
\(\begin{gathered} \Delta h^{\prime}=\Delta h_{oil}\cdot\mleft(\frac{\rho_{oil}}{\rho}\mright) \\ \text{ replacing:} \\ \Delta h^{\prime}=6.3\cdot\mleft(\frac{0.9}{13.6}\mright) \\ \Delta h^{\prime}=0.42\text{ cm} \end{gathered}\)how are s waves and p waves simuliar?
A.they shake the ground
B.they travel through liquids
C. they arrive at the same time
D.they shake the ground from side to side
Answer:
A
Explanation:
hope this helps
A rocket uses 400.0 J of chemical potential energy stored in the fuel while shooting the 0.55 kg rocket straight up
into the air. The rocket reaches a height of 23 m. What was the efficiency of the rocket in transforming the chemical
potential energy of the fuel into gravitational potential energy?
Select one:
O a. 25%
Ob. 35%
O c. 31%
O d. 29%
Answer:
Approximately \(31\%\) assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).
Explanation:
Consider an object of mass \(m\) in a uniform gravitational field of strength \(g\). If the height of that object increased by \(\Delta h\), the gravitational potential energy of that object would increase by \(m\, g\, \Delta h\).
In this question, the mass of the rocket is given to be \(m = 0.55\; {\rm kg}\). Assume that \(g = 9.81\; {\rm N \cdot kg^{-1}}\). The rocket has gained a height of \(\Delta h = 23\; {\rm m}\). Thus, the gravitational potential energy of this rocket would have increased by:
\(\begin{aligned} m\, g\, \Delta h &= 0.55\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 23\; {\rm m} \\ &\approx 124.1\; {\rm J} \end{aligned}\).
In other words, the useful energy output from the combustion of the rocket fuel was approximately \(124.1\; {\rm J}\).
The energy input to this rocket was given to be \(400.0\; {\rm J}\). Thus, the efficiency of the energy conversion would be:
\(\begin{aligned} \text{efficiency} &= \frac{(\text{useful energy out}\text{put})}{(\text{energy in}\text{put})} \times 100\% \\ &\approx \frac{124.1\; {\rm J}}{400.0\; {\rm J}} \times 100\% \\ &\approx 31\%\end{aligned}\).
What is the unit of pressure
is it P=F/A?
Answer:
Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2
Explanation:
P = F/A is a formula for pressure not a unit.
Pa = Pascal
Bar = Bar
at = Technical Atmosphere
Torr = Torr
lbf/in^2 = pounds per square inch
A wagon, Initially traveling at a constant 3.6 m/s, starts going down a hill that creates an acceleration of
1.6 m/s2. What is the wagon's velocity 4.8 s after it starts accelerating down the hill?
1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B
(More in the photo provided)
For the roller coaster on a frictionless track:
a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.How to solve speed and height?a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.
Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.
Answer: A. 5.0 m/s
b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.
At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:
Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A
At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."
Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B
Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.
Equating the mechanical energy at Point A to the mechanical energy at Point B:
Initial mechanical energy at Point A = Mechanical energy at Point B
Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B
Since the kinetic energy is the same at both points, simplify the equation:
Potential energy at Point A = Potential energy at Point B
The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:
mgh = mghA
Since the mass and acceleration due to gravity are the same, cancel them out:
h = hA
This means that the height where kinetic energy equals potential energy is the same as the height at Point A.
Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.
c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.
Potential energy at Point B = mghB
Potential energy at Point C = mghC
Given that the height at Point C is 8.0 m, compare the potential energies:
Potential energy at Point B ≥ Potential energy at Point C
mghB ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hB ≥ hC
Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.
d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.
Potential energy at Point A = mghA
Potential energy at Point C = mghC
Given that the height at Point A is 5.0 m, compare the potential energies:
Potential energy at Point A ≥ Potential energy at Point C
mghA ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hA ≥ hC
Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.
To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.
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4:01HOMEWORKThe parallel plates of a vacuum capacitor are 5mm apart and have 2m ^ 2 in area. A potential difference of 10,000 V (10.0 kV) is applied across the capacitor. Calculate a) the capacitance, b) the charge on each plate, and c) the magnitude of the electric field in the space between them.
RESPUESTA
a) C = 3.54 x 10⁻⁹ F = 3.54 nF
b) Q = 35.4 x 10⁻⁶ C = 35.4 μC
c) E = 2,000,000 V/m
EXPLICACIÓN
a) La capacitancia de un capacitor de placas paralelas se define como la razón entre la magnitud de la cantidad de carga en cada placa y la diferencia de potencial aplicado. A su vez, ésta depende de la geometría del capacitor. La ecuación que la define es:
\(C=\epsilon_0\cdot\frac{A}{d}\)donde C es la capacitancia, A es el área de las placas y d es la distancia que separa las placas. Además ε0 es la permitividad del vacío. En general la fórmula también incluye la permitividad relativa del material dielétrico (el material entre las placas del capacitor) pero en este problema no nos interesa, dado que el material entre las placas de este capacitor es el vacío.
De esta manera, si reemplazamos los datos de este problema:
• ε0 = 8.85 x 10⁻¹² F/m
,• A = 2 m²
,• d = 5 mm
Nota que tanto la permitividad como el área de las placas tienen unidades de metros, pero la distancia de separación entre placas está en milímetros, por lo tanto debemos convertirla a metros:
\(d=5\operatorname{mm}=0.005m\)Ahora sí, reemplazamos en la ecuación de arriba y obtenemos la capacitancia:
\(C=8.85\cdot10^{-12}\frac{F}{m}\cdot\frac{2m^2}{0.005m}=3.54\cdot10^{-9}F\)Cuando escribimos una cantidad en notación científica, y el exponente del 10 es -9 podemos no escribir esta parte y usar el prefijo nano. De esta manera, decimos que la capacitancia es de 3.54 nF.
b) La carga de las placas podemos obtenerla de la otra ecuación para definir la capacitancia:
\(C=\frac{Q}{V}\)C es la capacitancia que encontramos en el punto a), V es la diferencia de potencial aplicada y Q lo que estamos buscando, la carga de las placas. Del enunciado, tenemos que la diferencia de potencial es V = 10,000V. Reemplazando y resolviendo para Q:
\(\begin{gathered} 3.54\times10^{-9}F=\frac{Q}{10,000V} \\ Q=3.54\times10^{-9}F\cdot10,000V \\ Q=3.54\times10^{-5}C \end{gathered}\)Si movemos el punto decimal un lugar hacia la derecha tenemos: 35.4 x 10⁻⁶ C, que puede llevar el prefijo de micro. Para el prefijo micro usamos la letra griega mu (μ). Entonces la carga de las placas es 35.4 μC
c) Finalmente, para encontrar la magnitud del campo eléctrico, utilizaremos la relación entre la diferencia de potencial y la distancia entre las placas:
\(E=\frac{V}{d}\)Reemplazando con V = 10,000V y d = 0.005m, el campo eléctrico es:
\(E=\frac{10,000V}{0.005m}=2,000,000\frac{V}{m}\)Leticia timed how fast five apple slices turned brown (oxidate) after being being dipped in different preservatives such as lemon juice, fruit freshener, salt water and lime soda. another part of the experiment had the apple slices simply set out without any chemical on them. all parts of the experiment had the apple slices in the same indoor conditions such as humidity temperature and lighting; also only one variety of apple-red delicious was used.
Identify each of the following independent variable, dependent variable, constants, control experiment and repeated trials.
Answer:
Independent Variable: Choice of preservative
Dependent Variable: Time it took to brown
Controlled Variables/Constants: Climate, Size of apple slices, and amount of preservative on each slice
Control: Apple Slices without preservatives on them
Repeated Trials: One?
Explanation:
c = speed of light = 3.00 × 108 m/s
A gamma ray has a very high frequency of about 1019 s−1. What is the wavelength of the gamma ray?
A.
3.00 × 10−11 m
B.
3.00 × 1027 m
C.
3.33 × 1010 m
D.
3.33 × 10−12 m
URGENT!!!!!!!!!!
Answer:
The correct answer is option A: 3.00 × 10^(-11) m.
Explanation:
To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:
wavelength = speed of light / frequency
Given:
Speed of light (c) = 3.00 × 10^8 m/s
Frequency (f) = 10^19 s^(-1)
Substituting the values into the equation:
wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))
To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:
wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s
To divide by a fraction, we multiply by its reciprocal:
wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)
Applying the properties of exponents, we can add the exponents when multiplying with the same base:
wavelength = 3.00 × 10^(-11) m
Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.
Sound waves will travel faster through a wooden table than through the air. Is this true or false?
Sound waves travel faster on a medium if it is more dense.
The density of wood is greater than the density of air. Then, sound waves would travel faster through wood than through air.
Therefore, the answer is:
\(\text{True}\)Р.
Use the information to answer the following question.
The information shows the masses after the compounds are balanced.
2 LiCl + Na,o
-
Li,O +2 NaCl
84
+
62
=
X +
118
If the following materials are used during the reaction of Lithium, Oxygen, Sodium, and Chlorine, what mass of Lithium Oxide would we
expect to see after the reaction and why?
O A. 28g of Li,O, because all mass must be conserved, it would be half of the compound LiCl in the products
O
B. 44g of Li,O, because all mass must be conserved, it would be half of the compound LiCl in the products
o
C. 28g of Li_0, because all mass must be conserved
D. 44g of Li2O, because all mass must be conserved
Answer:
C. 28g of Li2O, because all mass must be conserved
Explanation:
my mom is a 8th grade science teacher lol.