often a vector is specified by a magnitude and a direction; for example, a rope with tension t⃗ exerts a force of magnitude t

Answer:

wavelength

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.

The distance from one peak to the next peak is called wavelength. This distance is also equal to the distance from one trough of a wave to another.

Mathematically, wavelength is calculated using this formula;

\( Wavelength = \frac {speed}{frequency} \)

The resultant of the two given vectors is 346.4 units.

The resultant of the three vectors is the sum of all the three vectors acting together. The resultant vector is the single vector that will represent all the three vectors in terms of magnitude and direction.

The sum of the vectors in x-direction;

Vx = V cosθ

where;

for 200 units, θ = 0⁰ (above the horizontal)

for 400 units, θ = 60⁰ (above the horizontal)

Vx = 200 cos(0) - 400 cos(60)

Vx = 0

The sum of the vectors in y-direction;

Vy = 200 sin(0) + 400 sin(60)

Vy = 346.4 units

The resultant vector is calculated as;

V = √(Vx² + Vy²)

V = √(0² + 346.4²)

V = 346.4 units

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Answer:

I think it's D

Explanation:

because kinetic basically means moving and potential mean sitting still so ig it's c or D

Explanation:

potential energy = mass × gravity force × height

=20 × 10 × 25

= 5000 joules

Answer:

Solution,

Displacement(s)=200 m

Initial velocity (u)=?

Final velocity(v)=0 m/s^2

acceleration due to gravity(g)=-9.8 m/s^2

now,

\( {v}^{2} = {u}^{2} + 2as \\ {(0)}^{2} = {u}^{2} + 2 \times ( - 9.8) \times 200 \\ {u}^{2} = 2 \times 9.8 \times 200 \\ {u}^{2} = 3920 \\ u = \sqrt{3920} \\ u = \sqrt{ {62.6}^{2} } \\ u = 62.6 \: metre \: per \: second\)

Again,

Finding time taken,

\(v = u + at \\ t = \frac{v - u}{a} \\ = \frac{0 - 62.6}{ - 9.8} \\ = \frac{ - 62.6}{ - 9.8} \\ = 6.39 \: seconds\)

Hope this helps...

Good luck on your assignment...

Answer:

A.The objects must be different temperatures and they must be in contact.

Explanation:

Taking into account the Newton's second law, the acceleration of the 100 g mass is 50 m/s².

Newton's second law states that this force will change the speed of an object because the acceleration and/or direction will change.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object:

F= m×a

where:

In this case, you know:

Replacing in Newton's second law:

5 N= 0.1 kg× a

Solving:

a= 5 N÷ 0.1 kg

a= 50 m/s²

Finally, the acceleration is 50 m/s².

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The amount of energy radiated by a star is directly proportional to its surface area and the fourth power of its temperature. Therefore, the more luminous star radiates 81 times more energy than the less luminous star.

If two stars have the same surface area but one has 3 times the temperature of the other, we can calculate the ratio of the energy radiated by the more luminous star compared to the less luminous star.

Let's assume the surface area of both stars is A. The energy radiated by the less luminous star can be represented as E1, and the energy radiated by the more luminous star can be represented as E2.

Since both stars have the same surface area, we can say that \(E1 ∝ T1^4\) and\(E2 ∝ T2^4\), where T1 is the temperature of the less luminous star and T2 is the temperature of the more luminous star.

Given that T2 = 3T1, we can substitute this value into the equations:

\(E1 ∝ T1^4\)
\(E2 ∝ (3T1)^4\)

Simplifying, we get:
\(E1 ∝ T1^4\)
\(E2 ∝ 81T1^4\)

Therefore, the more luminous star radiates 81 times more energy than the less luminous star.

In conclusion, if two stars have the same surface area but one has 3 times the temperature of the other, the more luminous star will radiate 81 times more energy than the less luminous star.

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A) 4π radians did the carousel rotate through.

B) v=rω, v =2*20 = 40 m/s is the tangential velocity of the carousel at a point 2 m from the center of the carousel.

C) α =ω²r = 20²× 5 = 2000 rad/s² is the angular acceleration of the carousel during this time.

D)  the tangential acceleration of the carousel at a point on the outside of the platform is zero cause a(t) = r dω/dt change in angular velocity is zero after it reaches 20 rad/s.

A carousel, also known as a merry-go-round (international), roundabout (British English), or hurdy-gurdy (an archaic phrase in Australian English), is a type of amusement attraction that consists of a spinning circular platform with seats for passengers. Traditional "seats" are rows of wooden horses or other animals set on poles, many of which are moved up and down by gears to mimic galloping to the tune of looping circus music. carousel rotates with a particular velocity.

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The time that separates successive beats is approximately 56644.7 seconds.

To calculate the time that separates successive beats, we need to find the difference in wavelengths between the two pianos and use the formula:

Time (seconds) = 1 / (Frequency of beats)

The frequency of beats can be calculated by taking the reciprocal of the time it takes for one beat to occur. The time for one beat can be determined by finding the difference in time it takes for each piano to produce one complete wavelength.

Given:

First, we need to calculate the frequency of beats (f) using the difference in wavelengths:

Δλ = |λA - λB|

Δλ = |0.770 m - 0.776 m|

Δλ = 0.006 m

Next, we can calculate the time for one beat:

Time for one beat (seconds) = Δλ / v

Time for one beat = 0.006 m / 340 m/s

Time for one beat ≈ 1.7647 x 10^(-5) seconds

Finally, we can find the time that separates successive beats:

Time (seconds) = 1 / (Frequency of beats)

Time = 1 / (1.7647 x 10^(-5) seconds)

Time ≈ 56644.7 seconds

Therefore, the time that separates successive beats is approximately 56644.7 seconds.

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According to the question the maximum force Fmax with which you can lean against the table before it slides is 216.49 N.

When you lean against a table, your weight exerts a force F on the edge of the table that is directed at an angle of θ of 14.0° below a line drawn parallel to the table's surface.
The table has a mass of 39.0 kg and the coefficient of static friction between its feet and the ground is 0.550.
We have to find the maximum force Fmax with which you can lean against the table before it slides.
The force of static friction between the table and the floor is given by:
f = µN
where µ is the coefficient of friction and
N is the normal force.
The normal force is the force exerted by the ground on the table and is equal to the weight of the table.
Therefore :N = mg

= (39.0 kg)(9.81 m/s²)

= 383.59 N
where g is the acceleration due to gravity.
Now, we can calculate the maximum force Fmax by considering the horizontal and vertical components of the force F.
The vertical component of F is given by:Fsinθ = N + mg Fsin14.0°

= 383.59 N + (39.0 kg)(9.81 m/s²)
Fsin14.0° = 764.04 N
The horizontal component of F is given by:
Fcosθ ≤ f
Fcos14.0° ≤ 0.550f = 0.550µN

= 0.550(383.59 N)
= 210.98 NFcos14.0° ≤ 210.98 NF ≤ 210.98 N/cos14.0°F ≤ 216.49 N
Therefore, the maximum force Fmax with which you can lean against the table before it slides is 216.49 N.

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The recommended minimum length of time that water should remain motionless in service lines prior to first-draw residential lead sampling is 6 hours.

Lead can leach into drinking water from the service lines and plumbing fixtures, particularly in older homes that may have lead pipes or lead-based solder. When water sits stagnant in these pipes for a period of time, such as overnight or during the day when no one is home, the lead particles that have accumulated in the plumbing system can dissolve into the water. This is why it's important to collect first-draw samples after a period of stagnation.

The EPA recommends a 6-hour stagnation period for collecting first-draw samples from residential plumbing systems because this is typically the longest period of time that water remains stagnant in home plumbing systems. This means that the water has been sitting in the pipes long enough to allow any lead particles to leach into the water, but not so long that the water quality may be affected by other factors, such as microbial growth or chemical reactions.

It's important to note that first-draw samples are used to identify the presence of lead in the plumbing system, but they may not be representative of the actual exposure to lead that a person may experience. This is because the lead concentration in the water can vary depending on factors such as the age and condition of the plumbing system, the water chemistry, and the length of time that water has been sitting in the pipes.

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The other string is approximately 0.526 Hz off in frequency from the 350 Hz string.

To find how far off in frequency the other string is when a piano tuner hears one beat every 1.9 seconds with one string sounding at 350 Hz, we can use the following steps,

Determine the beat frequency,
The beat frequency is the rate at which the beats occur, which is one beat every 1.9 seconds. To find the beat frequency in Hz, take the reciprocal of the time:
Beat frequency = 1 / 1.9 s ≈ 0.526 Hz

Determine the frequency of the other string,
Since the beat frequency is the difference in frequency between the two strings, we can set up the following equation to find the frequency of the other string:
Frequency of other string = 350 Hz ± Beat frequency

Calculate the possible frequencies of the other string,
We have two possibilities, either the other string has a higher or a lower frequency:
Higher frequency: 350 Hz + 0.526 Hz ≈ 350.526 Hz
Lower frequency: 350 Hz - 0.526 Hz ≈ 349.474 Hz

Therefore, the other string's frequency is roughly 0.526 Hz lower than the 350 Hz string's.

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The gravitational force that exerts on the outer out in space is 1.73 ×\(10^{-7}\)N.

Gravitational force:

The force of gravity or gravitational force pulls objects with mass towards each other. The gravitational force between two objects can be calculated as a function of the product of their masses (M and m), the square of the distance between them(r), and the universal gravitational constant.

The formula is:

F = G Mm/r²

Let us assume that g = 10 m/s².

M = 11000/ 10 = 1100kg

m = 3400/10 = 340kg

The distance was given:

r = 12m

We can look up a value of G:

G = 6.674 ×\(10^{-11}\) m³ / kgs²

F = 6.674 \(10^{-11}\) ( 1100 × 340)/ 12²

  = 17333.86 ×\(10^{-11}\)

  = 1.73×\(10^{-7}\)N

Therefore the gravitational force is 1.73 ×\(10^{-7}\)N.

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A cube of metal weighing 0.317 kg and measuring 3.01 cm on each side has a mass of 0.317 kg.

The metal cube described has a mass of 0.317 kg. The given information states that the cube measures 3.01 cm on each side. The mass of an object is a measure of the amount of matter it contains, and in this case, it refers to the total mass of the metal cube.

When calculating the mass of the cube, we can use the formula:

Density = Mass / Volume

Given that the cube is made of metal and has a uniform density, we can assume that the density is constant throughout. The volume of a cube can be calculated by cubing the length of one of its sides:

\(Volume = (Side length)^3\)

Substituting the given values into the equations:

\(Density = Mass / (Side length)^3\)

Rearranging the equation, we can solve for the mass:

\(Mass = Density x (Side length)^3\)

Since the density of the metal is not given in the question, we cannot determine the specific metal type. However, we can calculate the mass of the cube using the given values.

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The fermi energy for silver, assuming the effective mass equals the free electron mass is 5.58 x 10⁻¹⁹ J.

To calculate the Fermi energy for silver, use the following formula:

E_F = (h² / 2m) × (3π² × n)^(2/3)

where:

h = Planck's constant = 6.626 x 10⁻³⁴ J s

m = effective mass of electron = mass of free electron = 9.109 x 10⁻³¹ kg

n = number density of free electrons = 6.1 x 10²² electrons/cm³

Substituting the given values into the formula:

E_F = (6.626 x 10⁻³⁴ J s)² / (2 × 9.109 x 10⁻³¹ kg) × (3π² × 6.1 x 10²² cm⁻³)^(2/3)

E_F = 5.58 x 10⁻¹⁹  J

Therefore, the Fermi energy for silver is approximately 5.58 x 10⁻¹⁹ J.

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Answer: Pole star can be located using Ursa Major by extending an imaginary line from the last two stars towards the North direction.

Explanation:

Answer:

The pole star can be located using the Ursa Major constellation, by imagining a line towards the Northern direction connecting two stars present at the end of the bowl, This imaginary line meets Pole Star. The length of the imaginary line from the bowl is about five times the distance between the two stars of the bowl.

Explanation:

Answer:

The thickness of the tissue is : 2.4 x 10⁷ mm

Explanation:

The general formula for speed is the distance travelled divided by the time taken.

In this case,

Speed = 1600 m/s  ------speed of sound in human tissue

Time = 1.5 * 10 seconds -----time of taken for the ultrasound pulse to go through a certain thickness of a tissues

The thickness of the tissue here is the distance as per the speed formula, hence;

Tissue thickness = Speed of sound * time taken by ultrasound pulse

Tissue thickness= 1600 * 1.5*10 =24000 m

1 m= 1000 mm

24000m = 24000*1000 mm

= 2.4 x 10⁷ mm

Answer:

60 Ns

Explanation:

change in momentum = Fxt

6*10

60 Ns

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

change in momentum = force . time

change in momentum = 6 . 10 = 60

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

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Answer:

V1/T1 = V2/T2 => V2 = V1/T1 * T2 Using the information given, V1 = 1.9 m3 T1 = 32.0 C T2 = 18.0 C we can get: V2 = 1.9/32 * 18 = 1.06875, the volume that would be taken up by the existing ethanol after the temperature change is 1.07. If the capacity is 1.9 m3, then the amount of additional that can be added is 1.90-1.07 which is 0.83 m3.

Explanation:

Answer:

\(0.027m^{3}\)

Explanation:

First, we write down what we know:

\(\Delta{V}_{ethanol} = Change\; in\; volume\; of\; the\; ethanol.\\\beta_{ethanol} = 75\times{10^{-5}}\;{^\circ{C}^{-1}}\\\beta_{steel} = 36\times{10^{-5}}\;{^\circ{C}^{-1}}\\V_{0} = 2.90m^3\\\Delta{T} = T_1-T_0 = 20 - 33 = -13{^\circ{C}}\)

In order to solve this problem, we have to calculate the final volumes of the ethanol and steel respectively and then find their difference, which will give us the volume of ethanol that we can add once the container in cooled.

\(\Delta{V}_{ethanol}= V_{ethanol}-V_0\\Rearrange\; to\; find\; V_{ethanol}\\ V_{ethanol} = \Delta{V}_{ethanol} +V_0\)

\(\Delta{V}_{steel}= V_{steel}-V_0\\Rearrange\; to\; find\; V_{steel}\\ V_{steel} = \Delta{V}_{steel} +V_0\)

Which gives:

\(V_{steel}-V_{ethanol}=volume\;we\;can\;add=V_{free}\\V_{free} = \beta_{steel}V_0\Delta{T}+V_0-(\beta_{ethanol}V_0\Delta{T}+V_0)\\V_{free} = V_0\Delta{T}( \beta_{steel}-\beta_{ethanol})\\V_{free} = (2.9m^3)( -13{^\circ{C}})(36\times{10^{-5}}\;{^\circ{C}^{-1}}-75\times{10^{-5}}\;{^\circ{C}^{-1}})\\V_{free} = 0.027m^3 = 27l\)

a. The hydroxide concentration required to initiate precipitation is 2.50 x 10⁻² M.

b. To lower the Al³⁺ concentration in the solution to 2.00 x 10⁻⁷ M, we can use the common ion effect by adding excess OH⁻ ions.

(A). To initiate the precipitation of Al³⁺ from a 2.50 x 10⁻² M solution of Al(SO₄)₃, the solubility product constant (Ksp) of aluminium hydroxide (Al(OH)₃) is determined. The balanced equation for the dissociation of Al₂(SO₄)₃ is:

Al₂(SO₄)₃(s) ⇌ 2Al³⁺(aq) + 3SO₄²⁻(aq)

The Ksp expression for aluminium hydroxide is Ksp = [Al³⁺][OH⁻]³.

At the point of precipitation, the concentration of Al³⁺ will be equal to the concentration of OH- ions.

Therefore, [Al³⁺] = [OH⁻].

Given [Al³⁺] = 2.50 x 10⁻² M,

So,the hydroxide concentration required to initiate precipitation is also 2.50 x 10⁻² M.

(B). To lower the Al³⁺ concentration in the solution to 2.00 x 10⁻⁷ M, we can use the common ion effect by adding excess OH⁻ ions.

As the desired concentration is much lower than the initial concentration, we can assume that the OH⁻ concentration will be equal to the change in Al³⁺ concentration.

By using the solubility product expression,

Ksp = [Al³⁺][OH⁻]³, and substituting the given values, we have (2.00 x 10⁻⁷+ Δ[Al³⁺])(Δ[Al³⁺])³ = (2.50 x 10⁻² - Δ[Al³⁺])(2.50 x 10⁻² - Δ[Al³⁺])³.

Solving this equation will yield the value of Δ[Al³⁺], which corresponds to the change in Al³⁺ concentration. Subtracting this value from the initial Al³⁺ concentration of 2.50 x 10⁻² M will give us the desired concentration of 2.00 x 10⁻⁷ M.

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The specific internal energy of water is approximately 2607.7 kJ/kg.

The specific internal energy is the amount of energy contained within a substance per unit mass. It is a measure of the internal energy of a substance and is typically denoted by the symbol "u." It can be determined using the steam tables.

According to the steam tables, the specific internal energy of water at 50 kPa and 220°C is approximately 2607.7 kJ/kg. This value can be found by locating the corresponding pressure and temperature values in the table and reading the specific internal energy value in the "u" column.

It is important to note that the specific internal energy of water can vary depending on the pressure and temperature conditions. Therefore, it is important to use the correct values from the steam tables in order to obtain an accurate result.

The problem seems incomplete, it must have been...

"What is the specific internal energy of water at 50 kPa and 220°C? Use data from the steam tables.

The specific internal energy of water is _____ kJ/kg."

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Answer:A

Explanation

B a compound can ha e the same properties as it’s elements

C water is H2O- Hydrogen and oxygen

D water is the most common compound

Therefore A must be correct

Answer:

1) 2.388ohms

2) R1 3.36A

R2 1.682A

R3 2.88A

R4 2.16A The current has 5.048A over all

3) Voltage in R1 is 3.36v

Voltage in R4 is 8.63v

Explanation:

1. Each of the resistance R1 and R2 are in parallel in series combination with R3 and R4 so we calculate

R1 and R2 which is 1×2÷(1+2)= 0.6667ohms

R3 and R4 which is 3×4÷( 3+4)= 1.71ohms

so the equivalent resistance is 0.667+ 1.71= *2.377ohms*

2. The overall current = voltage source ÷ total resistance

= 12÷ 2.377= 5.048Amps

so current in every resistor will be

current in 1ohms will be (2÷3)×5.048= 3.36Amps

current in 2ohms will be (1÷3)×5.048= 1.68Amps

current in 3ohms will be (4÷7)×5.048= 2.88amps

current in 4ohms will be (3÷7)× 5.048= 2.16amps

3. voltage in R1 is 0.667ohms × 5.048amps= 3.36v

voltage in R4 is 1.71ohms × 5.048amps= 8.63v

Answer:

The molecules of the soup in the pot move faster than those in the freezer.

Explanation:

The soup in the freezer is closer to being a solid than that in the pot. Therefore, it has more energy which will make the molecules move faster.

No, magnetic fields do not exist on every planet. The magnetic fields of the four gas giants are extremely strong, while those of the Earth and Mercury are fairly strong and Venus and Mars have essentially no detectable magnetic fields.

Mars and Venus don't have much of a magnetic field, according to probes. The magnetic fields of Jupiter, Saturn, Uranus, and Neptune are all far stronger than those of the Earth. Jupiter is the winner since it has the biggest magnetic field. The magnetosphere grows in size as the magnetic field gets stronger. Jupiter's magnetic field, which is around 20,000 times stronger than Earth's magnetic field, generates a magnetosphere that extends over 3 million kilometers from Jupiter before it starts to deflect solar wind.

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We need to determine the maximum length of the spring during the ensuing motion. This maximum length will be greater than the initial length of 1.25 m.

To find the maximum length of the spring, we need to consider the conservation of mechanical energy. Initially, when the mass is at rest, the total mechanical energy is equal to the potential energy of the spring, given by the equation (1/2)kx², where k is the spring constant and x is the displacement of the spring from its unstretched length.

When the mass is pulled down and released, it will undergo harmonic motion. At the maximum length of the spring, all the initial potential energy is converted into kinetic energy, given by the equation (1/2)mv², where m is the mass and v is the velocity.

By equating the initial potential energy to the maximum kinetic energy, we can solve for the maximum displacement (length) of the spring. This maximum length will be greater than the initial length of 1.25 m, as the spring stretches during the motion that follows.

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