Of the 89 million tons of waste that was recycled 9 percent was metal.How much metal was recycled in million tons

If a local park is open for biking every 12 day open for paddling every 8 day and if today the park is open for both options, then the next date when the park will be open will be on the 24th day. So Hana should pick 24th day from today next.

Every 12 day the local park is open its path for biking and every 8 day they open their lake or paddling. That is in every multiple of 12 days the biking option is available and every multiple of 8 days the paddling option is available.

If today both the biking and paddling option are open, then the next day where both options will be open can be determined by calculating the least common multiple of 12 and 8.

12 = 2×2×3

8 = 2×2×2

LCM (12, 8) = 2×2×2×3

LCM(12, 8) = 24

LCM of 12 and 8 is 24. So 24 days from today, the park will be open for both options.

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Answer:

Well you can divide 4.41 by 3 and then use that number and multiply it by 4

Step-by-step explanation:

Answer:

Using this equation: f(x) = 1.47x

The cost of 4 erasers is 5.88

each costs 1.47

Answer:

180 quarters

Step-by-step explanation:

Answer:

0.06

Step-by-step explanation:

Yes, there is a difference of squares in mathematics. A difference of squares is an algebraic expression in the form of (a - b)(a + b), where a and b are two real numbers. This expression can be expanded into a polynomial using the distributive property of multiplication over addition.

The difference of squares can be helpful in solving equations and in factoring polynomials. When we have an equation in the form of a^2 - b^2, we can use the difference of squares to factor the expression into (a - b)(a + b). This can simplify the equation and make it easier to solve.

For example, consider the equation x^2 - 4. This equation can be factored into (x - 2)(x + 2) using the difference of squares. By factoring, we can see that the solutions to the equation x^2 - 4 are x = 2 and x = -2.

In summary, the difference of squares is a useful concept in algebra and helps in solving equations and factoring polynomials.

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x ≤ 2.6 would look like this on the number line, the 2.6 part would be shaded in as well and not left open since x is less than OR EQUAL to 2.6

To find the number of people who like all three fruits, we can use the principle of inclusion-exclusion.In a group of 6 people, 45 like apples, 30 like bananas, and 15 like oranges.

The total number of people who like only two fruits is 22, and they like at least one of the fruits.

Let's break it down:
- The number of people who like apples only is 45 - 22 = 23.
- The number of people who like bananas only is 30 - 22 = 8.
- The number of people who like oranges only is 15 - 22 = 0 (since there are no people who like only oranges).
To find the number of people who like all three fruits, we need to subtract the number of people who like only one fruit from the total number of people in the group:

6 - (23 + 8 + 0)

= 6 - 31

= -25.
Since we can't have a negative number of people, there must be an error in the given information or the calculations. Please check the data provided and try again.

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There are no people in the group who like all three fruits. In a group of 6 people, 45 like apples, 30 like bananas, and 15 like oranges. We need to find the number of people who like all three fruits. To solve this, we can use a formula called the inclusion-exclusion principle.

This principle helps us calculate the number of elements that belong to at least one of the given sets.

Let's break it down:

1. Start by adding the number of people who like each individual fruit:
  - 45 people like apples
  - 30 people like bananas
  - 15 people like oranges

2. Next, subtract the number of people who like exactly two fruits. We know that there are 22 people who fall into this category, and they also like at least one of the fruits.

3. Finally, add the number of people who like all three fruits. Let's denote this number as "x".

Using the inclusion-exclusion principle, we can set up the following equation:

    45 + 30 + 15 - 22 + x = 6

Simplifying the equation, we get:

    68 + x = 6

Subtracting 68 from both sides, we find that:

    x = -62

Since the number of people cannot be negative, we can conclude that there are no people who like all three fruits.

In conclusion, there are no people in the group who like all three fruits.

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Answer: \(x=\dfrac{3240}{83}\)

Step-by-step explanation:

Given: 83 : 45 :: 72 : ?

Let unknown quantity (?) be x.

Now, x : y :: a : b

\(\Rightarrow\ \dfrac{x}{y}=\dfrac{a}{b}\)

83 : 45 :: 72 : x

\(\Rightarrow\ \dfrac{83}{45}=\dfrac{72}{x}\\\\\Rightarrow\ x=\dfrac{72}{83}\times45\\\\\Rightarrow\ x=\dfrac{3240}{83}\)

Hence, \(x=\dfrac{3240}{83}\)

Answer:

Step-by-step explanation:

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

In order to use t*, we need to check conditions for using a t-distribution first.

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

Now we can use the formula at the very top to construct a confidence interval for two sample means.

Substitute the variables into the formula: \(\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }\).

Simplify this expression.

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

in this case since it's a cylinder always have to do is multiply the two given measurements dancing that she gets all you need to do is run it off to the nearest two decimal places when you say to the nearest two decimal places while trying to say they are two numbers after the coma

Answer: 2.0  (choice D)

Reason:

We divide the two mean absolute deviation (MAD) values to get (1.2)/(0.6) = 2.0

The variability in the first set (the 6th graders) is exactly twice that of the variability of the second set (the 7th graders).

The MAD is one measure of variability or spread. Another would be the standard deviation. The larger the value, the more spread out the data points will be.

Answer:

5years

Step-by-step explanation:

I=70

P=350

R=4

➜PRT=100 I

➜T=100 I/PR

➜100×70/350×4

➜7000/1400

➜5years

Henry opens a savings account with an annual interest rate of 4.5 percent. After a year, he gets $75,000 in payment. He made a deposit into the savings account of $72,831.68.

Here are the steps on how to calculate the amount Henry invested:

Convert the annual interest rate to a monthly rate.

\(\begin{equation}4.5\% \div 12 = 0.375\%\end{equation}\)

Calculate the number of years.

\(\begin{equation}\frac{18 \text{ months}}{12 \text{ months/year}} = 1.5 \text{ years}\end{equation}\)

Use the compound interest formula to calculate the amount Henry invested.

\(\begin{equation}FV = PV * (1 + r)^t\end{equation}\)

where:

FV is the future value ($75,000)

PV is the present value (unknown)

r is the interest rate (0.375%)

t is the number of years (1.5 years)

\(\begin{equation}\$75,000 = PV \cdot (1 + 0.00375)^{1.5}\end{equation}\)

\$75,000 = PV * 1.0297

\(\begin{equation}PV = \frac{\$75,000}{1.0297}\end{equation}\)

PV = \$72,831.68

Therefore, Henry invested \$72,831.68 in the savings account.

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Step-by-step explanation:

1/5=1/5×1000=200

1/2 of 200

1/2×200=100

If you write your question just a little more specifically, I will answer.

The equation "ax2 = y," which has one solution unless a = 4, and none unless a = 4, has a solution. x = √(-4ay) / (2a) restricted by the condition that y be negative.

We may use the quadratic formula to determine the solutions to an equation for various values of an to construct a solution to the equation "ax² = y," which has no solution when a = 4 & just one solution in all other cases.

According to the quadratic formula, the answers to the problem "ax2 + bx + c = 0" are provided by

x = (-b +/- √(b² - 4ac)) / (2a)

In this formula, if we add "ax² = y," we obtain

x = (-0 +/- √(0² - 4ay)) / (2a)

which simplifies to

x = √(-4ay) / (2a)

If a = 4, the equation becomes

x = √(-16y) / 8

The equation has no solutions if y is positive because the value of (-16y) is fictitious. The value of (-16y) is real if y is negative, but the equation is still unsolvable since x cannot have a negative value. As a result, when a = 4, the problem has no solutions.

The equation has a single solution provided by any other value of a.

x = √(-4ay) / (2a)

For example, if a = 3, the equation becomes

x = √(-12y) / 6

Since √(-12y) is imaginary if y is positive, the problem has no solutions. If y is negative, √(-12y) has a real value, and there is only one solution to the problem.

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The price of the watch before the discount is calculated to be £24.44.

As the total price of the watch and a pair of trainers is £53. 55 and the price of the trainer before the discount was £38, we first calculate the price of the trainers after the discount as follows;

discount on a pair of trainers = 15/100 × 38 =  £5.7

cost of trainers after discount =  £38 - 5.7 =  £32.3

Now the price of the watch after the discount can be calculated by subtraction as follows;

price of watch after discount = total price - price of trainers after discount

price of watch after discount =  £53. 55 - £32.3

price of watch after discount = £21.25

Now the price of the watch before the discount can be calculated as follows;

price of watch before discount = £21.25 × 15/100

price of watch before discount = £21.25 + £3.1875

price of watch before discount = £24.44

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The series converges, and we need to add 7 terms to find the sum with an error less than 0.00005.

To test the given series for convergence or divergence, we can use the Alternating Series Test. The series is in the form:

Σ((-1)^(n+1))/(5n^4) for n=1 to infinity

1. The terms are alternating in sign, as indicated by the (-1)^(n+1) factor.
2. The sequence of absolute terms (1/(5n^4)) is positive and decreasing.

To show that the sequence is decreasing, we can show that its derivative is negative. The derivative of 1/(5n^4) with respect to n is:

d/dn (1/(5n^4)) = -20n^(-5)

Since the derivative is negative for all n ≥ 1, the sequence is decreasing.

Since both conditions for the Alternating Series Test are satisfied, the series converges.

Now, we need to use the Alternating Series Estimation Theorem to find how many terms we need to add to achieve an error less than 0.00005. The theorem states that the error is less than the first omitted term, so we have:

1/(5n^4) < 0.00005

Now, we need to solve for n:

n^4 > 1/(5 * 0.00005) = 4000

n > (4000)^(1/4) ≈ 6.3

Since n must be an integer, we round up to the nearest integer, which is 7. Therefore, we need to add 7 terms to achieve the desired error.

The series converges, and we need to add 7 terms to find the sum with an error less than 0.00005.

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I am a bit confused by the way this is worded, but I believe I understand.

So, here you go.

6(x + 3) + 11x

6x + 18 + 11x -- Distribute the 6.

17x + 18 -- Add like terms.

If this is not an option, then please clarify your question and I will attempt to answer again.

===========================================================

Explanation:

Hakim and Aziz have savings in the ratio 3:5. This means that Hakim has 3x dollars while Aziz has 5x dollars. The x is some positive real number.

We're then told that Hakim saved another $82, which means it goes from 3x to 3x+82

At the same time, Aziz spent $110 which means the 5x decreases to 5x-110

At this point, the two people have the same amount of money. Set the expressions we found equal to one another and solve for x.

3x+82 = 5x-110

3x-5x = -110-82

-2x = -192

x = -192/(-2)

x = 96

Then use this x value to compute each expression like so

Both have $370 after Hakim saved that additional $82 and after Aziz spent that $110.

------------------

Extra info:

If we rewind things a bit, Hakim would have 3*x = 3*96 = 288 dollars while Aziz would have 5x = 5*96 = 480 dollars. This is before any additional saving or spending.

Then note how the ratio 288:480 fully reduces to 3:5 after dividing both parts by the GCF 96.

The number of ways is 1 billion.

We are asked to determine the possible number of ways of the social security number that is 9 digits if the numbers can be repeated.

In this case, using fundamental counting, there are 10 possible numbers in each digit that is from zero to nine.

Thus, the number of ways is 10*10*10*10*10*10*10*10*10 equal to 1 billion ways.

Hence the number of ways is 1 billion.

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Answer:

x(x-2)

Step-by-step explanation:

the common multiple here is the x, notice how it appears in both both terms. thus, we can factor it out of the equation going from x²-2x to x(x-2)

x(x-2)

Im assuming you meant x² - 2x but correct me if i'm wrong!

so x is common in both terms so you can take it out and factorise it.

Hope this helps!

Answer:

A. 5 × ( 3 + 2 + 2 1/4 )

Step-by-step explanation:

Hayden rode his bike 5 times. Each time, he biked a 3-mile path, a 2-mile path, and a 2 1/4 -mile path.

The expression represents the total number of miles he biked is calculated as:

The number of times he rode his bike × (sum of the number of miles he biked)

= 5 × ( 3 mile + 2 miles + 2 1/4 miles)

= 5 × (3 + 2 + 2 1/4)

Therefore, Option A is the correct option

Answer:

Voy a usar la siguiente notación:

N es el numero de canicas que tiene Nico

G es el numero de canicas que tiene Gustavo

Donde esos dos valores representan las cantidades iniciales que tiene cada uno.

Nosotros sabemos que:

"Nico tiene el triple de canicas que Gustavo"

N = 3*G

"a la hora del recreo Nico jugó con Paco y ganó 14 canicas más ahora Nico y Gustavo poseen 62 canicas entre los dos"

(N + 14) + G = 62.

Entonces tenemos un sistema de dos ecuaciones:

N = 3*G

(N + 14) + G = 62.

Para resolver esto, el primer paso es reemplazar el primero ecuación en la segunda:

N + 14 + G = 62

3*G + 14 + G = 62

4*G = 62 - 14 = 48

G = 48/4 = 12

Entonces, Gustavo tiene 12 canicas.

E inicialmente Nico tiene 3*12 = 36 canicas.

Pero Nico luego gana 14 canicas, entonces Nico al final tiene:

36 + 12 = 48 canicas.

False. The given statement is not a valid proof of the theorem because it is circular.

The proof starts with the assumption that there exists an integer k such that n < k < n^2 and then uses this assumption to conclude that the theorem is true. However, this does not actually prove the existence of k, it simply restates the theorem. A valid proof would need to start with some other set of premises and use logical deduction to arrive at the conclusion that such a k exists. The given statement is not sufficient to establish the truth of the theorem.

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