Nucleus A decays into the stable nucleus B with a half-life of 14.19 s. At t=0 s there are 1,891 A nuclei and no B nuclei. At what time will there be 832 B nuclei?

Answer:

Cyberpunk has worst Physics

The force between these charges, according to Coulomb's law would be -54 N.

We can solve this problem applying "Coulomb's Law" which states-

\(\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ \)

\( \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

Where-

According to the given parameters -

Now that required values are given, so we can plug the values into the formula and solve for Force -

\(\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

\( \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ \)

\( \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ \)

\( \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ \)

\( \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ \)

\( \qquad\longrightarrow \sf Force = -5.4 \times 10\\ \)

\( \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ \)

Answer:

(a) a = - 201.8 m/s²

(b) s = 197.77 m

Explanation:

(a)

The acceleration can be found by using 1st equation of motion:

Vf = Vi + at

a = (Vf - Vi)/t

where,

a = acceleration = ?

Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)

Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s

t = time = 1.4 s

Therefore,

a = (0 m/s - 282.53 m/s)/1.4 s

a = - 201.8 m/s²

(b)

For the distance traveled, we can use 2nd equation of motion:

s = Vi t + (0.5)at²

where,

s = distance traveled = ?

Therefore,

s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²

s = 395.54 m - 197.77 m

s = 197.77 m

The distance traveled by the Spacecraft is  2.3 x 10² m.

To have a constant velocity, the change in velocity or speed of the object must be zero.

Constant speed will elapse equal distance in an identical period of time as a result is an example of steady speed.

For a Spacecraft is traveling in inner planetary space at a constant velocity and a given time of motion, the distance traveled by the Spacecraft is calculated as follows;

Distance = speed x time

the speed is given as 24.21 m/s

the time of motion is given as 9.5 seconds

distance = 24.21 m/s  x 9.5 s

distance = 2.3 x 10² m

Thus, the distance traveled by the Spacecraft is  2.3 x 10² m.

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The complete question is below;

Spacecraft is traveling in inner planetary space at a constant velocity of 24.1 m/s. What it estimated distance traveled by the spacecraft in 9.50 seconds?

Answer: i believe it’s c

Answer:

B. A computer combines many 2D images into a 3D image.

Explanation:

Did the test

If a rose with the genotype Yy is pale yellow in color, then there is not complete dominance for neither allele and it is a case of incomplete dominance. Nonetheless, since allele Y is for pale yellow and the hybrid has this phenotype, then it is partially dominant (pale yellow, Y, option 3).

Incomplete dominance is a genetic phenomenon in which one of the two alleles present for a given gene locus is expressed more strongly when compared to the other allele, which is called partially dominant and partially recessive alleles, respectively.

Conversely, complete dominance is due to the presence of an allele that completely masks the expression of the recessive allele in heterozygous hybrid individuals.

Therefore, with this data, we can see that incomplete dominance is associated with the expression of both alleles in the heterozygous hybrid individuals.

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The planets Earth, Mars, and Jupiter are well known. But before recent findings sparked a passionate argument about how to best characterize them, both Pluto and Ceres were thought of as planets.

This dispute is still going strong today. The International Astronomical Union established the most recent definition of a planet in 2006. It specifies three requirements for a planet.

It must move about a star (in our cosmic neighborhood, the Sun). It must be large enough for gravity to pull it in a spherical direction.

It must have been large enough that any nearby objects of a similar size were removed by its gravitational pull.

Therefore, The planets Earth, Mars, and Jupiter are well known. But before recent findings sparked a passionate argument about how to best characterize them, both Pluto and Ceres were thought of as planets.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

A) 10.0 m/s

Explanation:

the formula for average speed is  v=d/t

the distance is 100 meters

The time is 10.0 seconds

so  v=100m/10.0s

       = 10.0m/s

so the runners average speed was 10.0m/s

The average speed of the runner is equal to 10.0 m/s. Therefore, option (A) is correct.

The speed of a body can be described as the distance covered in a definite time interval. The average speed can be defined as a scalar parameter as it possesses magnitude with no direction.

The speed can be determined from the ratio of the distance traveled by the object to the time taken to travel that distance.

The speed of any object can be calculated from the formula equation mentioned below:

Speed =  total distance /time taken

Given, the distance covered by the runner = 100 m

The time taken by the runner, t = 10.0 s

The average speed of the runner can be calculated from the formula as shown below:

Speed = 100/10 = 10 m/s

Therefore, the average speed of the runner is 10.0 m/s.

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Answer:

making sense of a 3-d world from 2-d data

Explanation:

Answer:

37.3 km/h at N 2.70° E

Explanation:

Find the horizontal and vertical components of the initial velocity (u) and final velocity (v).  Remember that N 55° E means 55° east of north.

uₓ = 55.0 km/h

uᵧ = 0 km/h

vₓ = 65.0 km/h × sin 55° = 53.24 km/h

vᵧ = 65.0 km/h × cos 55° = 37.28 km/h

Find the difference.

vₓ − uₓ = -1.76 km/h

vᵧ − uᵧ = 37.28 km/h

The magnitude is:

|v − u| = √((-1.76 km/h)² + (37.28 km/h)²)

|v − u| = 37.3 km/h

The direction is:

θ = tan⁻¹(37.28 / -1.76)

θ = 92.70°

θ = N 2.70° E

Answer:

32.67km

Explanation:

~= round off

11.2km/h~3.11m/s

175minutes=10500s

10500*3.11~32, 666.67m

=32.66667km

~ 32.67km

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.

This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point  in the sunlight is equal to the pressure at any other point not in the sunlight.

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As the time of motion increases, the velocity of the object increases downwards.

The given parameters;

The final velocity of the object at different time is calculated as follows;

when the time = 1 second;

v = v₀ - gt

v = 9.8  - 9.8(1)

v = 0

when the time = 2 second;

v = v₀ - gt

v = 9.8 - 9.8(2)

v = -9.8 m/s

when the time = 3 second;

v = v₀ - gt

v = 9.8 - 9.8(3)

v = -19.6 m/s

Thus, we can conclude that as the time of motion increases, the velocity of the object increases downwards.

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Answer:

Forwarded

Explanation:

5/4 m/s^{2} would be its new acceleration .

What is centrifugal acceleration ?

The simplest case of circular motion is uniform circular motion, where an object moves in a circular trajectory with constant velocity. Note that the linear velocity of an object in circular motion is constantly changing because, unlike velocity, it is constantly changing direction. From kinematics we know that acceleration is a change in velocity, either in magnitude or direction, or both. Therefore, an object in uniform circular motion will always be accelerated even if the magnitude of its velocity is constant. You can feel this acceleration every time you get in the car while cornering. Keeping the handle steady while turning and moving at a constant speed creates a smooth circular motion. What you will notice is a feeling of skidding (or skidding depending on speed) out of the center of the turn.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

Explanation:

We can use the work-energy principle to solve this problem. The work-energy principle states that the work done on an object is equal to the change in kinetic energy of the object.

We can begin by finding the spring constant (k) of the spring. The spring constant is the force required to compress a spring by a certain distance. We can use the information given to us in the problem to find the spring constant:

k = F / x = 334 N / 0.024 m = 13,916.67 N/m

Now we can use the spring constant, the compression distance (3.5 cm) and the mass of the block (1.15 kg) to find the work done on the block as it compresses the spring:

work = 1/2 * k * x^2 = 1/2 * 13,916.67 N/m * (0.035 m)^2 = 97.4 J

Since the block is released from rest, its initial kinetic energy is zero. So, the work done on the block as it compresses the spring is equal to its final kinetic energy.

We know that the block slides down on a frictionless incline, so we need to consider the work done by gravity on the block during its motion. The work done by gravity is given by the equation:

work = force * distance * cos(theta)

where force is the force of gravity acting on the block, distance is the distance the block slides down the incline and theta is the angle of the incline with the ground.

force = m * g , where m = 1.15 kg and g = 9.8 m/s^2

distance = s

theta = 35°

substituting the values

work = (1.15 kg * 9.8 m/s^2) * s * cos(35°)

Now we can add the work done by gravity to the work done by the spring to find the total work done on the block.

work = 97.4 J + (1.15 kg * 9.8 m/s^2) * s * cos(35°) = 97.4 J + (11.37 N) * s * cos(35°)

Now we can solve for s, the distance the block travelled.

s = (97.4 J) / (11.37 N * cos(35°))

The final answer will be in meters.

Answer:

Explanation:

The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob  . Here monkey along with bunch of banana represents bob .

When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .

Hence the amplitude of oscillation too will remain unchanged .

Answer:

3*10^8 ÷ 475*10^-9

= 6.3 x 10^14

Answer:

\(100\ cm\)

Explanation:

Given

\(Height = 120\ cm\)

\(Distance = 50\ cm\)

Required

Determine the image's distance from the object's distance

Though, it's not stated but I'll assume that we're dealing with a plane mirror.

When an image is reflected in a plane mirror, the distance of the object is the twice the distance between the mirror and the object itself.

Mathematically,

Object Distance from Image = 2 * Image Distance from Mirror

So, we have:

Object Distance from Image = 2 * 50 cm

Object Distance from Image = 100cm

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

Answer:

faster than

Explanation:

because the sun gave it nutrients

Answer:

To perform hands-only CPR, you want your non-dominant hand on top of your dominant hand and interlocking fingers, and push right under the breast bone 30 times. A good way to remember how fast you should perform CPR, listen to the beat of "Staying Alive." If the hands don't work after 30 times, pinch their nose, tilt their head back and blow two big breaths into their mouth, then do the chest pushing again. Keep repeating these steps until they respond, you feel a pulse, or 911 arrives.

Explanation:

I actually just learned how to do CPR this week it is really cool!

May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

If truck and car moving with same velocity then the car will cover less distance , if the force of breaking is same .

The velocity of the truck and car are given to have equal velocity ,

the braking force is also equal ,

we know that , the mass of the truck(M)  is greater than mass of the car(m) ;

So , the truck will have more momentum ;

we know that momentum is = mass × velocity ;

let the velocity of car and truck be "v" ;

substituting the values in the momentum formula ;,

we get ; Mv > mv ;

Therefore , the car will cover less distance .

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Answer:

F_{players} = 2528.4[N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.

On the sled act two forces, the force of friction and The Force executed by the football players.

The movement of the football players will be taken as positive, while the friction will be taken as negative, since it is opposed to the movement of the sled.

ΣF = m*a

where:

F = force [N]

m = mass [kg]

a = acceleration = 0.580 [m/s²]

\(F_{players} - f_{friction} = m*a\)

The friction force is defected as the coefficient of friction by the normal force, the normal force on a horizontal surface can be calculated as the product of mass by gravitational acceleration.

\(f_{friction}=0.8*(300*9.81)\\f_{friction}=2354.4[N]\)

Now we can calculate the force exerted by the players.

\(F_{players}-2354.5=300*0.580\\F_{players}=2528.4[N]\)