Answer:
Noble gases are stable as they have fully filled outermost orbital. Hence they do not participate in chemical reactions.
But Xenon reacts in some cases in favourable conditions
How many oxygen atoms are there in one formula of AI2(SO4)3?
There are 12 atoms of Oxygen, since 3 times 4 is 12.
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Becca is a forensic technician analyzing the fragments of a window. She sees that there is a hole in the window, and that the outside hole is smaller than the inside hole. What might she deduce from this information?
The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.
From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:
The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.
The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.
The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.
Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.
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how many grams of P3O9 contain 9.67x10^23 atoms of oxygen?
Answer:
49.1 g
Explanation:
First we convert 9.67x10²³ atoms of oxygen into moles, using Avogadro's number:
9.67x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.60 mol OThen we calculate how many P₃O₉ moles there would be with 1.60 O moles:
1.60 mol O * \(\frac{1molP_3O_9}{9molO}\) = 0.18 mol P₃O₉Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:
0.18 mol P₃O₉ * 237 g/mol = 49.1 gHELP ME WITH THIS ASSIGNMENT! IT'S DUE TODAY AT 7.
Answer:
At the top of a seamount, the temperature is generally cooler and the pressure is lower compared to the bottom of a trench. This is because the its closer to the ocean surface, where sunlight and atmospheric conditions can affect the temperature and pressure.
The bottom of a trench is located at a much greater depth and is subject to extreme pressure and temperatures. The temperature at the bottom of a trench can be very high due to the heat generated by tectonic activity and volcanic processes.
Explanation:
Why 5.67 + 0.00032 = 5.67 (and not 5.7 or 5.67032 or any other number).
Answer:
5.67 + 0.00032 = 5.67032
Usually for decimal answers, we write 2 digits that come after decimal. We can't write all the numbers that come after the decimal because sometimes it can go on for infinte times, so we write the 2 numbers that come after decimal. So, 5.67 is the answer.
5.7 is also right if you round off the answer but 5.67 is more accurate.
Hope this helped!
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Answer:
For the question given, this shows that the answer is in 2 d.p. (2 decimal places). This means that the final answer has been rounded to 2 numbers after the decimal point!
We know that it would be 5.67 as the number after the 7 is 0, this means that the answer would be rounded down or in other terms the 7 would stay the same.
When answering a question, most of the time we would be told what decimal place to round the number to!
Hope this helps, have a lovely day! :)
calculate the modaliti of 2.89 of NaCI dissolved in 0.159 L of water (Given Density of water is 1.00 g/mol)
Answer:
[NaCl] = 0.31 m
Explanation:
Molality is a sort of solute's concentration, that indicates the moles of solute contained in 1kg of solvent.
In this problem:
solute → NaCl
solvent → H₂O
We need the mass of solvent in kg and we have the volume, so let's convert the volume to mass by the use of density.
1 g/mL = mass / 159 mL
(Notice we needed to convert the volume from L to mL)
159 g is the mass of water. We convert to kg
159 g . 1 kg/1000 g = 0.159 kg
We convert the mass of solute to moles → 2.89 g . 1mol/ 58.45 g = 0.049 moles of NaCl
Molality → mol/kg → 0.049 mol /0.159 kg = 0.31 m
What are the variables in Gay-Lussac’s law
Answer:
The variables in Gay-Lussac's law are the initial temperature (T1), the initial pressure (P1), the final temperature (T2) and the final pressure (P2)....
Explanation:
A 0.700L sample of gas at STP is compressed to a volume of 0.200L and the temperature is increased to 30 degrees Celcius . What is the new pressure of the gas (in atm)?
Answer: the pressure of the gas after the compression is 3.88 atm
Explanation:
The question requires us to calculate the new pressure of a gas, given its initial volume at STP, new volume after compression and temperature after compression.
The following information was provided by the question:
Initial volume = V1 = 0.700 L
Final volume = V2 = 0.200 L
Final temperature = T2 = 30 °C = 303.15 K
To solve this problem, we can apply the equation for ideal gases (shown below) considering the conditions after the compression:
\(P\times V=n\times R\times T\rightarrow P_2=\frac{R\times n\times T_2}{V_2}\)where R is the constant of gases (R = 0.082057 L.atm/K.mol), n is the number of moles of gas, T2 is the temperature after compression and V2 is the volume after compression.
Note that the number of moles of gas remains the same even after compression. Thus, we can calculate this number of moles considering the inital volume at STP, knowing that 1 mol of a gas at Standard Temperature and Pressure corresponds to 22.4 L of this gas:
22.4 L ------------------------- 1 mol
0.700 L ----------------------- x
Solving for x, we'll have:
\(x=\frac{(0.700L)\times(1mol)}{(22.4L)}=0.0312mol\)Therefore, the number of moles before and after compression is 0.0312 mol.
Now that we have the values for n, T2 and V2, we can calculate the pressure after compression (P2):
\(\begin{gathered} \begin{equation*} P_2=\frac{R\times n\times T_2}{V_2} \end{equation*} \\ P_2=\frac{(0.082057L.atm/K.mol)\times(0.0312mol)\times(30+273.15)K}{(0.200L)}=3.88atm \end{gathered}\)Therefore, the pressure of the gas after the compression is 3.88 atm.
Is wind non-living? And the reason why if it's living or non-living?
Answer:
yes wind is nonliving because it has no form of life to it
A group of students is comparing the graphs of strong acid-strong base and weak acid-strong base titration curves, where the base is the titrant. Which statement inaccurately describes a difference between the two curves?
A. The initial pH for the weak acid-strong base curve is higher than the initial pH for the strong acid-strong base curve.
B. At the equivalence points, the pH of the weak acid-strong base is greater than the pH of the strong acid-strong base.
C. At the half-equivalence points, the pH of the weak acid-strong base is greater than the pH of the strong acid- strong base.
D. The steep-rise interval in the weak acid-strong base curve is more pronounced than in the strong acid-strong base curve.
The initial pH for the weak acid-strong base curve is higher than the initial pH for the strong acid-strong base curve. Hence, option A is correct.
What is a weak acid?Weak acids are acids that don't completely dissociate in solution.
A weak acid is an acetic acid. It has a of 1.8⋅\(10^{-5}\). Calculate how much it will dissociate in water. Since acetic acid is a weak acid so large part will not dissociate completely.
\(k_a=\frac{[CH_3COO^-]H^+]}{[CH_3COOH]}\)
B is not true, it shows the titration curve for weak/strong acid titrated with a strong base. When choosing an indicator for colourimetric titration select one so that the pH jump at the equivalence point contains the interval p±1. Phenolphthalein has a p≈9, so to decide if it is a suitable indicator check if the pH jumps from 8 to 10 at the equivalence point.
C is not true either because of the very slow reaction.
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An aqueous solution of Ca(OH)2 at 25 oC has a pH of 12.4. Assume Ca(OH)2 fully dissociates. Calculate the concentration (in M) of Ca(OH)2. Report to 3 decimal places.
Answer:
the first one may be more complex so the second one will be simplified :)
Explanation:
A sentence with the word atom
Answer:
we use atom in our sentences all the time
Explanation:
that what i put
Hypochlorous acid is a weak acid. Write an equation showing how HCIO acts in solution; then
write the K, expression for HCIO.
Hypochlorous acid is a weak acid. Its equation is following:-
HClO ⇄ H⁺ + ClO⁻
K = [H⁺] [ClO⁻] / [HClO]
Weak Acids are the acids that do not completely dissociate into their constituent ions when dissolved in solutions.
When dissolved in water, an equilibrium is established between the concentration of the weak acid and its constituent ions.
The awareness of a substance is the quantity of solute present in a given amount of answer. Concentrations are typically expressed in phrases of molarity, defined as the wide variety of moles of solute in 1 L of answer.
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A food stall owner was preparing dough for making bhatura. He added a pinch of yeast and sugar to the dough and left it in a warm place. After a few hours, the dough had risen. There was our sell too.
1. Why did the dough rise?
2. Why did the dough smell sour?
3. Why was sugar added to the dough? 4.What would have happened if the dough was kept in the refrigerator, soon after it prepared?
Explanation:
yeast and sugar was present
how are elements classified organized?
It is the highest point in a wave.
Answer:
Crest is the highest point of a wave
60 points!! Look at picture please don’t troll
Calcium nitrate- make an evidence based argument for why acid rain would cause the calcium carbonate in the marble to slowly break down and wash away over time when calcium nitrate is produced
Following are the effects of acid rain.
What is Acid Rain?
Acid rain is caused by the accumulation of nitric and sulfuric acids in the atmosphere. These compounds are strong acids and are very soluble in water, dissolving in droplets in clouds.
Limestone effect:
Calcium carbonate, [Ca][CO3], is a very common mineral. A limestone is a well-known form of calcium carbonate. The acid contained in acid rain reacts with carbonate ions and promotes the dissolution of calcium carbonate.
This will create a bicarbonate solution. The presence of limestone and other calcium carbonates in lakes and streams helps maintain a constant pH as the mineral reacts with excess acidity. However, acid rain can eventually exceed the buffering capacity of surface waters.
How does acid rain affect buildings made of marble and limestone?
It is mainly affected in 2 ways: dissolution and alteration. Calcite dissolves when sulfuric, sulfuric and nitric acids in polluted air react with calcite in marble and limestone. Exposed areas of buildings and statues show rough surfaces, worn materials, and loss of sculptural detail. Stoneface material can be lost anywhere or only in more reactive areas.
Hence, this is how acid rain affects.
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Choose the correct statement
a) The maximum value of principal quantum number (n) is 7
b) The angular quantum number (l) can receive value from 1 to (n-1)
c) The magnetic quantum number (ml) shows the energy of electron
d) The magnetic quantum number (ml) show how many orbitals in each subshell
Answer:
maybe number b is correct. ...thank you
the role of haemoglobin in the transport of oxygen and carbon dioxide
Hemoglobin with bound carbon dioxide and hydrogen ions is carried in the blood back to the lungs, where it releases the hydrogen ions and carbon dioxide and rebinds oxygen. Thus, hemoglobin helps to transport hydrogen ions and carbon dioxide in addition to transporting oxygen.
The complex ion Cu(NH3)42+ is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.300 M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant*, Kf, of Cu(NH3)42+ is 1.70 × 1013.
The concentrations Cu(NH3)42+ at equilibrium is [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4.
The concentrations of Cu2+ is [Cu(NH3)42+] + [Cu2+]
The concentrations of NH3 is 4[Cu(NH3)42+] + 4[NH3]
What is concentration equilibrium?Equilibrium concentration is described as a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction.
The equilibrium constant expression for the formation of the complex ion Cu(NH3)42+ is:
Kf = [Cu(NH3)42+] / [Cu2+] * [NH3]^4
where [Cu(NH3)42+], [Cu2+], and [NH3] are the molar concentrations at equilibrium.
The initial concentrations of Cu2+ and NH3 are 0.0200 M and 0.300 M respectively.
We have that Kf = 1.70 × 1013, we then rearrange the equation to solve for [Cu(NH3)42+]:
1.70 × 1013 = [Cu(NH3)42+] / (0.0200M) * (0.300M)^4
[Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4
Therefore at equilibrium, the concentration of Cu(NH3)42+ is [Cu(NH3)42+] = 1.70 × 1013 * (0.0200M) * (0.300M)^4
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A 45.0 beaker of water cools from 67.0°C to 45.0°C. How many joules of
heat are released?
Answer:
4142.16J
Explanation:
Given parameters:
Mass of water in the beaker = 45g
Initial temperature = 67°C
Final temperature = 45°C
Unknown:
Quantity of heat released = ?
Solution:
To solve this problem, we use the expression below:
H = m cФ
H is the quantity of heat
m is the mass
c is the specific heat = 4.184J/g°C
Ф is the change in temperature
H = 45 x 4.184 x (45 - 67) = 4142.16J
The amount of heat released is 4142.16J
I need some help on this question please!
A chemist has 3.45 x 1022 molecules of P2O5. How many grams of P2O5 does the chemist have?
Thanks to anyone who helps!
To convert the number of molecules of P₂O₅ to grams, we need to use the Avogadro's number and the molar mass of P₂O₅ .
How many grams of P₂O₅ does the chemist have according to the question?The molar mass of P₂O₅ can be calculated as follows:
2 × molar mass of P + 5 × molar mass of O
= 2 × 30.97 g/mol + 5 × 15.99 g/mol
= 61.94 g/mol + 79.95 g/mol
= 141.89 g/mol
Therefore, the molar mass of P₂O₅ is 141.89 g/mol.
Now, we can use Avogadro's number to convert the number of molecules to moles:
3.45 × 10²² molecules / 6.022 × 10²³ molecules/mol
= 0.0573 moles
Finally, we can use the molar mass of P₂O₅ to convert moles to grams:
0.0573 moles × 141.89 g/mol = 8.14 grams
Therefore, the chemist has 8.14 grams of P₂O₅ .
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A 3.24-gram sample of NaHCO3 was completely decomposed in an experiment.
2NaHCO3 → Na2CO3 + H2CO3
In this experiment, carbon dioxide and water vapors combine to form H2CO3. After decomposition, the Na2CO3 had a mass of 2.19 grams.
Determine the mass of the H2CO3 produced.
Calculate the percentage yield of H2CO3 for the reaction. Show your work or describe the calculation process in detail.
PLEASE HELP, WILL MARK BRAINLIEST!!!
Mass of H2CO3 = 1.05g
Givens: NaHCO3 = 3.24
Na2CO3 = 2.19
Mass of H2CO3 = mass of NaHCO3 - mass of Na2CO3
Mass of H2CO3 = 3.24g - 2.19g
Mass of H2CO3 = 1.05g
How do you find the mass number?The number of protons and the number of neutrons combine to determine the mass number of an element. Mass number = proton + neutron. If you want to calculate the number of neutrons an atom has, you can simply subtract the number of protons or atomic numbers from the mass number.
Divide the mass of a substance in grams by the molecular weight. This will give you the number of moles of the substance in a particular mass. For 12 g of water, (25 g) / (18.015 g / mol) = 0.666 mol.
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61. Given the following information:
Ag2 CrO4(s)=2Agt (aq) + CrO4²- (aq)
Ag+ (aq) + e- Ag(s)
find the standard reduction potential at 25°C for the half-reaction
Ksp = 1 × 10-12
E = +0.799 V
Ag2 CrO4(s) + 2e¯ 2Ag(s) + CrO4²- (aq)
Q = Ksp = 1 × 10^(-12).
Substituting the values into the Nernst equation, we have:
0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))
Now, solving for E°:
E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))
The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.
To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).
The Nernst equation is given as follows:
E = E° - (RT/nF) * ln(Q)
Given information:
Ksp = 1 × 10^(-12)
E = +0.799 V (standard reduction potential of Ag+ to Ag)
Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].
Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.
Therefore, Q = Ksp = 1 × 10^(-12).
Substituting the values into the Nernst equation, we have:
0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))
Now, solving for E°:
E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))
The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.
Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.
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Which of the following are excited in ultraviolet photoelectron spectroscopy?
A. Core electrons
B. Nonvalence electrons
C. X-rays
D. Valence electrons
Answer:
D. Valance Electrons
Explanation:
A 10.0 mL sample of calcium hydroxide solution required 26.85 mL of 0.225 M hydrochloric acid for neutralization. The balanced equation is:
Answer:
\(C_{base}=0.302M\)
Explanation:
Hello,
In this case, we can evidence that when calcium hydroxide solution reacts with hydrochloric acid solution, the balanced neutralization reaction turns out:
\(2HCl(aq)+Ca(OH)_2\rightarrow CaCl_2(aq)+2H_2O(l)\)
Moreover, the concentration of neutralized calcium hydroxide can be computed by using the 2:1 mole ratio between the base and the acid:
\(C_{acid}V_{acid}=2*C_{base}V_{base}\\\\C_{base}=\frac{C_{acid}V_{acid}}{2*V_{base}} =\frac{0.225M*26.85mL}{2*10.0mL}\\ \\C_{base}=0.302M\)
Regards.
Why is a different product formed at the anode when copper sulfate is electrolysed using graphite electrodes rather than copper electrodes?
Carbon-14 has a half-life of 5730 years. If an original sample was 100g of C¹4 and it is now 0.781g of C14, how old is your sample?
Answer:
40,113 years
Explanation:
To find the age of the sample, you need to use the half-life formula:
\(N(t)=N_0(\frac{1}{2})^{t/h\)
In this formula:
------> N(t) = current mass (g)
------> N₀ = initial mass (g)
------> t = time passed (yrs)
------> h = half-life (yrs)
You can plug the given values into the equation and rearrange the formula to find "t".
N(t) = 0.781 g t = ? yrs
N₀ = 100 g h = 5730 yrs
\(N(t)=N_0(\frac{1}{2})^{t/h\) <----- Half-life formula
\(0.781=100(\frac{1}{2})^{t/5730}\) <----- Insert values
\(0.00781=(\frac{1}{2})^{t/5730}\) <----- Divide both sides by 100
\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\) <----- Take \(log_{1/2}\) of both sides
\(7.00 = \frac{t}{5730}\) <----- Solve \(log_{1/2}\)
\(40,113 = t\) <----- Multiply both sides by 5730
The given sample is 40,113 years .
What do you mean by half-life ?Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.
Half-life formula,
\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\) .......(1)
where,
N(t)=current mass
N₀=initial mass
t=time period
h=half -life
Given,
N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years
\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)
put the values, in ......(1)
0.781=100(1/2) \(t/5730\\\)
log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)
7=t/5730
40,113=t
Hence, the given sample is 40,113 years .
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When you give the molecules in a gas sample more room to move,