0.49 M is the molarity of the 4.9% \(H_{2}SO_{4}\) solution.
To find the molarity of a solution, we need to calculate the number of moles of the solute (\(H_{2}SO_{4}\)) present in a given volume of the solution. Here's how to determine the molarity of a 4.9% \(H_{2}SO_{4}\)solution with a density of 0.98 g/ml:
Determine the mass of the solute: The 4.9% concentration implies that 4.9 g of \(H_{2}SO_{4}\) is present in 100 g of the solution.
Calculate the volume of the solution: Divide the mass of the solution by its density. In this case, 100 g / 0.98 g/ml = 102.04 ml.
Convert the volume of the solution to liters: Divide the volume by 1000 to convert from milliliters to liters. 102.04 ml / 1000 = 0.10204 L.
Calculate the number of moles: Multiply the mass of the solute by its molar mass. The molar mass of \(H_{2}SO_{4}\) is 98.09 g/mol. Therefore, 4.9 g / 98.09 g/mol = 0.0499 mol.
Calculate the molarity: Divide the number of moles by the volume of the solution in liters. 0.0499 mol / 0.10204 L ≈ 0.49 M.
Thus, the molarity of the 4.9% \(H_{2}SO_{4}\) solution is approximately 0.49 M.
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If a fluorine atom and nitrogen atom combine to form a compound, what type of bond will they form
Answer:
I guess covalent bond is formed
I need to know what’s the error in each equation help !!!
What is the term used to describe the scientific study of how living things are classified?
Answer:
Taxonomy
Explanation:
The term used to describe the scientific study of how living things are classified is known as taxonomy.
Taxonomy describes includes the nomenclature and classification of organisms based on several relationships between organisms.
Carl Linnaeus introduced the basis of modern classification system and this has been refined through the years.
Different relationships between organisms are used to classify them.
A cell is placed in a salt solution that has the same concentration as the inside of the cell. What will happen to the cell
A. The cell will contract
B. The cell will expand slightly
C. The cell will burst
D. The cell will remain the same size
By the way I had to ask again because I f forgot to put the answer choices
Answer:
B
Explanation:
If not B then its d
Answer:
D
Explanation:
This would be an isotonic solution. If a cell is placed in a solution of salt with the same concentration of salt in the cell, nothing will happen.
Please help with this question
Answer:
I am guessig B
Explanation:
Answer:bro
Explanation: you cant cheat on test
Which of these is an example of a physical property?
A: The fact that iron rusts
B: The texture of a piece of chocolate
C: The effect of acid rain on automobiles
D: The fact that gasoline in a car engine combusts
Which bone is located between the incus and the inner ear?
cochlea
stapes
incus
malleus
Answer: The answer is incus
Select the correct answer.
Which unit is used for measuring atomic mass?
A atomic mole
B. grams/mole
C. grams
D. atomic mass unit
E. atomic mass weight
Answer:
D
Explanation:
The unit used to measure atomic mass is the atomic mass unit (amu). A single amu is equivalent to 1/12 the mass of an atom from the carbon-12 isotopIsotopes with different numbers of protons and neutrons will have an actual mass slightly different from the atomic mass calculated in atomic mass units.
Which of the following natural processes will NOT directly result in the formation of sedimentary rock?
A. River Flow
B. Windstorm
C. Metamorphic change
D. Glacial Motion
Answer:
Windstorm Hope it helped brainiest plz and thank you have a great day!!!
Explanation:
Which of the following natural processes will NOT directly result in the formation of sedimentary rock?
B. Windstorm
a. Identify the structures shown in the diagram. b. Identify the information that is contained within these structures. c. Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person. d. Explain why the structures are in pairs.
The answer responses to the structures shown in the diagram are:
A. chromosomes
C. They would be the same.
B. They are in pairs because each one comes from a different parent.
What is the structure about?The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.
The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.
Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.
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Identify the structures shown.
A. chromosomes
B. mitochondria
C. nuclei
D. vacuoles
C
Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.
A. There would be longer.
B. They would be shorter.
C. They would be the same.
D. They would be different.
Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.
A. There would be longer.
B. They would be shorter.
C. They would be the same.
D. They would be different.
Explain why the structures are in pairs.
A. They aren't in pairs.
B. They are in pairs because each one comes from a different parent.
C. This cell is making a copy of itself.
D. The cell always has 2 copies in case 1 is damaged.
A family is another name for a _____
on the periodic table of elements.
Answer:
Groups
Explanation:
A "family" on the periodic table is also called a "group".
A "group" or a "family" of elements are elements of the same type on the periodic table, for example, all of the transition metals on the periodic table are a "group" or a "family".
Which compound has a functional group that contains two oxygen atoms?
The compound that has a functional group containing two oxygen atoms is peroxide. In addition to peroxides, there are other compounds that contain functional groups with two oxygen atoms. These include carboxylic acids and esters.
Peroxide compounds, such as hydrogen peroxide (H₂O₂) or organic peroxides, have a functional group (-O-O-) where two oxygen atoms are bonded together. This group is responsible for the characteristic properties and reactivity of peroxides.
Carboxylic acids: Carboxylic acids have the functional group -COOH, which consists of a carbonyl group (C=O) and a hydroxyl group (-OH) bonded to the same carbon atom. While carboxylic acids have one oxygen atom from the carbonyl group, the hydroxyl group provides the second oxygen atom.
Esters: Esters have the functional group -COO-, which consists of a carbonyl group (C=O) and an oxygen atom (-O-) bonded to the same carbon atom. This arrangement gives esters two oxygen atoms within their functional group.
Hence, the compounds with functional groups containing two oxygen atoms include peroxides, carboxylic acids, and esters.
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In using the Haber process in the formation of ammonia, what mass of hydrogen is needed to produce 51.0 grams of ammonia? 3 H₂(g) + N2 (g) → 2 NH3(g).
The mass of hydrogen needed to produce 51.0 grams of ammonia is ≈ 9.07 grams.
To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.
From the balanced chemical equation:
3 H₂(g) + N₂(g) → 2 NH₃(g)
We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).
First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.
Number of moles of NH₃ = Mass / Molar mass
= 51.0 g / 17.03 g/mol
≈ 2.995 moles
Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.
Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃
= (2.995 moles × 3) / 2
≈ 4.493 moles
Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).
Mass of H₂ = Moles × Molar mass
= 4.493 moles × 2.02 g/mol
≈ 9.07 grams
Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.
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Once alchol is in the bloodstrram it will reach the brain I'm a few
Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.
Alcohol's Effects on BrainAlcohol can swiftly cross the blood-brain barrier after it is ingested, having an impact on the brain and neurological system. Depending on the quantity and frequency of drinking, alcohol's effects on the brain can range from minor disturbances in judgment and coordination to more serious consequences including loss of consciousness and, in the worst circumstances, death.
Long-term changes in brain structure and function, such as cognitive impairment and a higher chance of developing specific neurological and mental illnesses, can also result from chronic alcohol consumption.
Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.
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How does the density of salt water differ from that of freshwater
Answer:
denser than freshwater due to the sodium chloride dissolved in it.
Explanation:
t. This means that a specific volume of salt water is heaver than the same volume of freshwater. ... While colder water is denser, when water freezes into ice, it becomes less dense and floats on the surface
convert 8.42x10^8 mol/(kg*m^2) to mol/(g*cm^2)
Answer:
gguhg
Explanation:
no te es caso drama me están muy una las y y que las te
I have a cup of 50 ml of water resting at 25 degrees Celsius in an isolated system. I heat a 30g rock to 75 degrees Celsius and place it into the water. The final temperature of the water is 50 degrees Celsius. The specific heat of water is 4.186 J/gC. What is the specific heat of the rock? (Hint: Remember, the change in temperature is calculated by T final-T initial. Also 1 ml of water is equal to 1g)
The specific heat of water is 4.186 J/gC, the specific heat of the rock is approximately 6.97 J/gC.
To solve for the specific heat of the rock, we can use the equation:
q1 = -q2
where q1 is the heat gained by the water, and q2 is the heat lost by the rock. We can use the formula for heat:
q = mcΔT
where q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature.
For the water, we have:
q1 = mcΔT = (50 g)(4.186 J/gC)(50-25 C) = 5232.5 J
For the rock, we have:
q2 = mcΔT = (30 g)(c)(75-50 C)
We can now substitute these values into the first equation:
5232.5 J = -(30 g)(c)(75-50 C)
Solving for c, we get:
c = -5232.5 J / (30 g)(25 C) = -6.97 J/gC
Since specific heat cannot be negative, we take the absolute value to get:
c = 6.97 J/gC
Therefore, the specific heat of the rock is approximately 6.97 J/gC.
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A welding torch produces a flame by burning acetylene fuel in the presence of oxygen. The energy released from the acetylene fuel is then used to melt a metal.
Answer:
Chemical energy turns into thermal energy.
Explanation:
Based on Chromium's position on the periodic table, which statement describes the element
chromium (Cr), atomic number 24?
Answer:
C. chromium is a metal that is less reactive than sodium.
Explanation:
Hello.
Given the options:
A. chromium is a nonmetal and therefore a good conductor of heat and electricity .
B. chromium is a metal that is more reactive than potassium .
C. chromium is a metal that is less reactive than sodium .
D. chromium is a noble gas that is not reactive.
In this case, since chromium is in period 4 group VIB we infer it is a transition metal which slightly reacts with acids and poorly reacts with oxygen and other oxidizing substances. Thus, in comparison with both sodium and potassium which are highly reactive even with water as they get on fire, we can say that it is less reactive than both potassium and sodium, therefore, answer is: C. chromium is a metal that is less reactive than sodium.
Best regards.
Is a dish sponge a heterogenous mixture or homogenous mixture
Answer:
Heterogeneous mixture.A dish sponge is considered a heterogeneous mixture. A heterogeneous mixture is one that consists of visibly different components or substances that are not uniformly distributed throughout the mixture. In the case of a dish sponge, it is typically made up of a porous material, such as a sponge or foam, which is combined with other components like detergents or cleaning agents. These different components can be observed as distinct regions or phases within the sponge, making it a heterogeneous mixture.
Solid Snake is being chased up the communications tower. Solid Snake is 75 kg and is carrying 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, how much work was done against gravity?
a.
4.04 kJ
b.
109.15 kJ
c.
135.34 kJ
d.
5.01 kJ
Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).
What is work?In physics, work is the energy transferred to or from an object via the application of force along a displacement.
In this problem, the force that does the work is the one that opposes the weight.
Step 1: Calculate the total weight of the system.Solid Snake is 75 kg and is carrying 18 kg of equipment. The total mass is:
m = 75 kg + 18 kg = 93 kg
We can calculate the weight using Newton's second law of motion.
F = m . g = 93 kg . 9.8 m/s² = 911.4 N
Step 2: Calculate the total displacement.Solid Snake climbs 27 flights of stairs, each 5.5 m in height.
27 . 5.5 m = 148.5 m
Step 3: Calculate the work done.We will use the definition of work.
w = F . s = (911.4 N) . (148.5 m) . (1 kJ/1000 J) = 135.34 kJ
Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).
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If 123 kJ of heat are evolved when the reaction described below is carried out, the mass of HCl gas (36.46 g/mol) produced is ____ g.
3 Cl2(g) + PH3 (g) → PCl3 (g) + 3 HCl (g) ∆H = - 570.4 kJ
Based on the heat of reaction, if 123 kJ of heat is evolved when the reaction described below is carried out, the mass of HCl gas (36.46 g/mol) produced is 23.6 g.
What is the heat of a reaction?The heat of a reaction is the amount of heat energy given off or absorbed in the reaction.
During a reaction, energy changes occur as a result of the breaking of bonds in the reactants as well as the formation of bonds in the products.
The sum of the overall energy change that accompanies the formation of products from the reactants gives the heat change of a reaction.
Considering the heat change of the given reaction below:
3 Cl₂ (g) + PH₃ (g) → PCl₃ (g) + 3 HCl (g) ∆H = - 570.4 kJ
The formation of 3 moles of HCl results in the evolution of 570.4 kJ of heat.
If 123 kJ of heat are evolved, then the moles of HCl produced will be:
Moles of HCl produced = 123 kJ * 3 moles / 570.4 kJ
Moles of HCl produced = 0.647 moles
Mass of HCl produced = 0.647 * 36.46
Mass of HCl produced = 23.6 g
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What is the molarity of a solution that contains 4.53 moles of lithium nitrate (LiNO3) in 2.85 liters of solution
Answer:
M= ml - 45301 - 11.59M.
Explanation:
How many moles of CO2 are PRODUCED if 6.0 moles O2 are used?
Answer:
6 mol CO2
Explanation:
According to the equation, 6 moles of O2 will produce 6 moles of CO2, so the ratio is 1:1
therefore 6 moles of O2 will produce 6 moles of CO2
The Rutherford atom has a small, positively charged nucleus, so most a particles
will pass through empty space far from the nucleus and not be deflected. Those a
particles that pass near the nucleus will be deflected from their paths due to
positive-positive repulsion. Which of the following would be true for an atom with
fewer protons than gold in its nucleus?
A) The alpha particle fired at the nucleus
would have the same strength of repulsive
forces deflecting it, even if the atom's nucleus
had fewer protons than gold.
B) If there were fewer protons in the atom's
nucleus, it would not deflect the alpha
particle.
C) The alpha particle fired at the nucleus
would have stronger repulsive forces
deflecting it, if the atom's nucleus had fewer
protons than gold.
D) The alpha particle fired at the nucleus
would have weaker repulsive forces deflecting
it, if the atom's nucleus had fewer protons than
gold
Answer:
Option A is the correct answer.
Explanation:
• According to Rutherford every atom consists of dense positively charged particle at the centre known as nucleus.
• Nucleus consists of positively charged particle known as proton and neutral particle known as neutron.
• Alpha particles are the protons thus, it also have a positive charge.
• Since, both alpha particles and nucleus are positively charge, repulsion occurs between them which deflects the alpha particle from their actual path.
• This repulsion doesn’t depend on the number of protons present in the nucleus.
• Thus, the alpha particle fired at the nucleus would have the same strength of repulsive forces deflecting it, even if the atom’s nucleus had fewer protons than gold is a correct answer.
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convert 7.54 x 10^-8 m to nanometers
7.54 *\(10^8\) meters is 75.4 nanometers.
To convert 7.54 * \(10^8\) meters to nanometers, you can multiply the value by \(10^9\)
as, \(10^9\)nanometers = 1 meter.
7.54 * \(10^8\) m * \(10^9\) = 7.54 x \(10^1\) nm
Therefore, 7.54 *\(10^8\) meters is equal to 75.4 nanometers.
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To convert 7.54 x 10^-8 meters to nanometers, you multiply 7.54 x 10^-8 by 1 x 10^9 to get 75.4 nanometers.
Explanation:To convert meters to nanometers, you need to know that 1 meter is equivalent to 1 x 109 nanometers. Therefore, if you were to convert 7.54 x 10-8 m to nanometers, you would multiply 7.54 x 10-8 by 1 x 109.
Here's how you'd do it: 7.54 x 10-8 m * 1 x 109 nm/m = 75.4 nm. So, 7.54 x 10-8 meters is equivalent to 75.4 nanometers.
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Predict and explain the structure of the major and minor products when hydrogen bromide is added to 2-methylbut-2- ene, (Ch3)2CCHCH3
Pls help with homework!!!!
When hydrogen bromide is added to 2-methylbut-2-ene, two products are expected to be produced: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product).
The addition of HBr to 2-methylbut-2-ene follows the Markovnikov addition rule. This means that the hydrogen atom and the bromine atom will add to the carbon atoms in the double bond, such that the hydrogen atom adds to the carbon with the greater number of hydrogen atoms, and the bromine atom adds to the carbon with the lesser number of hydrogen atoms.
In this case, the hydrogen atom will attach to the second carbon atom, which has three hydrogen atoms, while the bromine atom will attach to the third carbon atom, which has only one hydrogen atom. This produces the major product, 2-bromo-2-methylbutane.
The formation of the minor product, 3-bromo-2-methylbutane, occurs due to the rearrangement of the carbocation intermediate formed during the addition reaction. The carbocation can rearrange either by shifting a methyl group from the second to the third carbon, or by shifting a hydrogen atom from the third to the second carbon. This rearrangement produces the minor product, 3-bromo-2-methylbutane.
In conclusion, the addition of HBr to 2-methylbut-2-ene produces two products: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product). The major product forms due to Markovnikov addition rule, while the minor product forms due to carbocation rearrangement.
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What is the molarity of a solution which contains 58.5 g of NaCl dissolved in 0.25 L of solution
The molarity of the solution, which contains 58.5 g of NaCl dissolved in 0.25 L of solution, is approximately 4.004 M.
To calculate the molarity of a solution, we need to determine the number of moles of solute (NaCl) and then divide it by the volume of the solution in liters.
Given:
Mass of NaCl = 58.5 g
Volume of solution = 0.25 L
Step 1: Calculate the number of moles of NaCl.
To find the number of moles, we need to divide the mass of NaCl by its molar mass. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl).
Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
= 58.5 g / 58.44 g/mol
≈ 1.001 mol
Step 2: Calculate the molarity.
Molarity (M) is defined as moles of solute per liter of solution.
Molarity = Moles of solute / Volume of solution
= 1.001 mol / 0.25 L
≈ 4.004 M
Therefore, the molarity of the solution, which contains 58.5 g of NaCl dissolved in 0.25 L of solution, is approximately 4.004 M.
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Molecules can be composed of
__. Select all that apply. ...
two of more of the same atoms
two or more smaller molecules
two or more different atoms
one or more particle
Answer:
Molecules can be composed of two or more of the same atom
Explanation:
Two asteroids are 75,000 m apart one has a mass of 8 x 10^7 N what is the mass of the other asteroid
The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg
To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:
F = (G * m1 * m2) / \(r^{2}\)
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.
Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):
1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)
Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.
The question was incomplete. find the full content below:
Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid
A. 3.4 x \(10^{11}\) kg
B. 8.3 x \(10^{12}\) kg
C. 1.2 x \(10^{12}\) kg
D. 1.2 x \(10^{10}\) kg
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