Answer:
When objects from space (meteoroids, space shuttles) enter the atmosphere, they start heating up in the mesosphere.
Explanation:
What is the style of Vincent Van Gogh's Starry Night (1889)?
Post Impressionism
Symbolism
Pointilism
Surrealism
The style of Vincent Van Gogh's Starry Night (1889) is Post-Impressionism.
Understanding post-impressionalismPost-Impressionism is an art movement that developed in France in the late 19th century as a reaction against the limitations of Impressionism. It is characterized by a focus on subjective emotions and personal interpretations of the world, as well as an interest in the formal qualities of art, such as color, line, and form.
Van Gogh's work is known for its expressive use of color and texture, and Starry Night is a prime example of his Post-Impressionist style, with its swirling brushstrokes, intense colors, and dreamlike quality.
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Identify the common indicators that a chemical reaction has occurred.
a. A color change
b. A phase change
c. Precipitate being formed
d. A solid being dissolved
e. A change in temperature
f. Bubbles being produced
Answer:
a. A color change
c. Precipitate being formed
e. A change in temperature
f. Bubbles being produced
Explanation:
Two types of changes occur namely: physical changes and chemical changes. A physical change does not affect the chemical composition of the substance involved. Physical changes include change of state etc.
However, on the other hand, a chemical change alters the chemical composition of the substances involved, hence, leading to the formation of new product(s). It is also called a chemical reaction. Since a new product is formed from the alteration of the chemical nature of the reacting substances, the following changes or indicators will be present or evident in a chemical reaction:
- color change of substance
- Precipitate being formed i.e. solid deposit
- A change in temperature
- Bubbles being produced (evolution of gas)
For reactions in the gas phase, an equilibrium constant may be written in terms of molarity (Kc) or in terms of partial pressures (Kp).
The value of Kc for the reaction shown below is equal to 2.9×10⁻⁴ at 298K.
2 NOBr(g) ⇄ 2NO(g) + Br₂(g)
What is the value for Kp at 298K for the reaction represented by the equation shown below? The value for the gas constant, R, is 0.08206 L . atm/mol. K.
NOBr(g) ⇄ NO}(g) + 1/2 Br₂(g)
The equilibrium constant of the reaction on the basis of concentration is 1.2 * 10^-7.
What is the Kc?We know that the equilibrium constant has to do with the value that shows the extent to which the reactants can be converted into products in the reaction as shown. We have been given in the question, the equilibrium constant that is based on the partial pressures of the reactants.
We then have the formula that we have to use to solve the problem as;
Kp = Kc(RT)^Δn
Kp = Equilibrium constant based on partial pressure
Kc = Equilibrium constant based on concentration
R = Gas constant
T = temperature
n = Number of moles
Thus we have;
Kc = Kp/(RT)^Δn
Kc = 2.9×10⁻⁴/(8.314 * 298)^(3-2)
Kc = 2.9×10⁻⁴ /2477.57
Kc = 1.2 * 10^-7
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Bromine monochloride is synthesized using the reaction Br2(g)+Cl2(g)↽−−⇀2BrCl(g)p=1.1×10−4 at 150 K A 201.0 L flask initially contains 0.902 kg of Br2 and 1.066 kg of Cl2. Calculate the mass of BrCl , in grams, that is present in the reaction mixture at equilibrium. Assume ideal gas behavior.
The mass of BrCl that is present in the reaction mixture at equilibrium is 0.519 grams
What is a mass of BrCl?Generally, To calculate the mass of BrCl present at equilibrium, we need to use the equilibrium constant expression (Kp) for the reaction:
Kp = [BrCl]^2 / [Br2] [Cl2]
where [BrCl], [Br2], and [Cl2] are the concentrations of the respective gases at equilibrium.
Since we know the initial amounts of Br2 and Cl2, and the volume of the flask, we can calculate the initial concentrations of each gas.
[Br2]_initial = 0.902 kg / (201.0 L * 0.08206 Latm/molK * 150 K)
= 0.0014 mol/L [Cl2]_initial
= 1.066 kg / (201.0 L * 0.08206 Latm/molK * 150 K)
= 0.0017 mol/L
We are also given the value of Kp, so we can substitute the initial concentrations into the Kp expression and solve for [BrCl].
Kp = [BrCl]^2 / 0.0014 mol/L * 0.0017 mol/L
= (1.1×10^-4)
[BrCl] = √(Kp * [Br2]_initial * [Cl2]_initial)
=√(1.1×10^-4 * 0.0014 mol/L * 0.0017 mol/L)
= 1.61802349*10^{-5} mol/L
To convert molarity to mass, we need to multiply the molarity by the molar mass of BrCl.
The molar mass of BrCl is
(2 * 79.904 g/mol) = 159.808 g/mol.
mass of BrCl = [BrCl] * V * M
=1.61802349*10^{-5}mol/L * 201.0 L * 159.808 g/mol
= 0.519 grams
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Iron reacts with chlorine to form iron(III) chloride.
2Fe + 3Cl2 → 2FeCl3
What mass (in grams) of chlorine gas is needed to react with 251 grams of iron?
Select one:
a.
71 grams
b.
392 grams
c.
479 grams
d.
622 grams
The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.
To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:
2Fe + 3Cl2 → 2FeCl3
From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).
To calculate the mass of chlorine gas, we can follow these steps:
Step 1: Convert the given mass of iron (Fe) to moles.
Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:
moles of Fe = mass of Fe / molar mass of Fe
moles of Fe = 251 g / 55.85 g/mol
moles of Fe ≈ 4.5 mol (rounded to one decimal place)
Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.
From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:
moles of Cl2 = (moles of Fe / 2) * 3
moles of Cl2 = (4.5 mol / 2) * 3
moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)
Step 3: Convert the moles of chlorine gas to grams.
Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:
mass of Cl2 = moles of Cl2 * molar mass of Cl2
mass of Cl2 = 6.75 mol * 70.90 g/mol
mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.
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Magnesium hydroxide reacts with chlorine to form magnesium chloride,
magnesium chlorate and water. How many grams of magnesium hydroxide is
needed to yield 8.00 moles of magnesium chlorate?
77.8 g Mg(OH)2
9178.1 g Mg(OH)2
2799.6 g Mg(OH)2
.823 g Mg(OH)2
How many grams of sodium sulfato pro
The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.
To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.
The balanced equation is as follows:
2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O
From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.
Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.
To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.
Given:
Moles of Mg(ClO3)2 = 8.00 moles
Using the stoichiometric ratio, we have:
8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2
To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.
The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol
Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g
Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.
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1.4 1.4.1 Define exothermic reaction. (2) 1.4.2 Referring to the energies absorbed and released, describe why this reaction is considered to be exothermic. Marks will not be awarded for restating the definition. (2) BEST 1.5 ACADEMY 1.5.1 Other than correct orientation of reacting particles, state ONE condition for an effective collision. (1) 1.5.2 Using the collision theory, explain the effect of using a LESS-concentrated sodium hydroxide solution on the rate of its reaction with aluminium. (4) 1.6 How would an increase in pressure (at constant temperature) affect the rate of this reaction? State only INCREASE, DECREASE, or REMAIN THE SAME. (2)
1.4.1 An exothermic reaction releases energy in the form of heat or light.
1.4.2 An exothermic reaction releases more energy than it absorbs due to the higher potential energy of the reactants compared to the products.
1.5.1 Effective collision requires sufficient energy or activation energy.
1.5.2 Increasing the concentration of sodium hydroxide solution increases the rate of reaction with aluminum due to more frequent effective collisions.
1.6 Increasing the pressure would not affect the rate of the reaction between sodium hydroxide and aluminum.
1.4.1 Exothermic reaction: An exothermic reaction is a chemical reaction that releases energy in the form of heat or light, resulting in an overall decrease in the internal energy of the system.
1.4.2 In an exothermic reaction, the energy released as a result of the reaction is greater than the energy absorbed. This is because the reactants have a higher potential energy compared to the products. The excess energy is released to the surroundings, leading to an overall decrease in the system's internal energy.
1.5.1 One condition for an effective collision is the presence of sufficient energy, often referred to as activation energy. The reacting particles must possess enough energy to overcome the activation energy barrier for successful collision and reaction to occur.
1.5.2 According to collision theory, increasing the concentration of a reactant, such as sodium hydroxide (NaOH) in its reaction with aluminum (Al), would increase the rate of reaction. A higher concentration provides more particles per unit volume, resulting in more frequent collisions and an increased chance of effective collisions.
1.6 An increase in pressure (at constant temperature) would not significantly affect the rate of the reaction between sodium hydroxide and aluminum. The reaction rate is primarily dependent on the concentration of the reactants and the frequency of effective collisions, rather than the pressure. Therefore the rate would remain the same.
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The table describes a gas stored in four different containers. Properties of Stored Gas Container Properties 1 · Low number of collisions with container walls · Medium average kinetic energy · Large number of particles 2 · Large number of collisions with container walls · Medium average kinetic energy · Small number of particles with little spaces between them 3 · Large number of collisions with container walls · High average kinetic energy · Large number of particles with large spaces between them 4 · Few collisions with container walls · Low average kinetic energy · Small number of particles Which container has gas stored at the highest temperature? 1 2 3 4
Container 3 has the gas stored at the highest temperature.
Temperature is a measure of the average kinetic energy of the particles in a substance. In the given table, it is stated that container 3 has a large number of collisions with container walls, high average kinetic energy, and large number of particles with large spaces between them.
These properties indicate that the gas in container 3 has higher kinetic energy and more vigorous movement compared to the other containers.
Container 1 has a low number of collisions with container walls and a medium average kinetic energy. This suggests that the gas in container 1 has lower energy and less movement than the gas in container 3.
Container 2 has a large number of collisions with container walls, but it also has a small number of particles with little spaces between them. While the collisions may be frequent, the limited number of particles and the lack of space between them may result in lower overall kinetic energy compared to container 3.
Container 4 has few collisions with container walls, low average kinetic energy, and a small number of particles. These properties indicate that the gas in container 4 has the lowest energy and least movement among all the containers.
Container 3
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Which of the following is a compound? *
A. aluminum
B. carbon
C. oxygen
D. sugar
Answer:
C. OXYGEN
Explanation:
What is the pH of a 0.235 M Ba(OH)2 solution?
Answer:
13.672
Explanation:
2 moles of OH in Ba(OH)₂
0.235 M × 2 mol OH = 0.47 M OH
pOH = -log[OH-] ; pOH = -log[0.47 M OH] ; 0.328 = pOH (consider significant figures)
14 - pOH = pH because pH + pOH = 14
14 - 0.328 = 13.672 [there are three decimal places after the OH concentration, so there should be in the answer as well - 13.672]
Question 5 of 10 Phosphorous is a nonmetal. Which property would you expect it to have? OA. It is a good conductor of heat. B. It is very shiny. C. It is a solid at room temperature. D. It is a gas at room temperature. SUBMIT D
At ambient temperatures, it is a gas. A periodic table element is phosphorus. It belongs to group 15 of the periodic table and is categorised as a nonmetal.
It is well known that nonmetals differ from metals in both their physical and chemical characteristics. The right response is D. At ambient temperatures, it is a gas. At room temperature, nonmetals may exist in all three states of matter: liquid, gas, and solid.
With a boiling point of 44.2 °C, phosphorus is a nonmetal that is a gas at ambient temperature. It is neither highly glossy nor an excellent heat conductor.
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A balloon is filled to a volume of 2.20L at a temperature of 25.0*C. The balloon is then heated to a temperature of 51*C. Find the new volume of the balloon
The new volume of the balloon after heating it to a temperature of 51 °C is approximately 2.39 L.
What is the final volume of the balloon?Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.
It is expressed as;
\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)
Given that:
Initial temperature of gas T₁ = 25°C = (25.0 + 273.15) = KInitial volume of gas V₁ = 2.2 LFinal temperature T₂ = 51 °C = ( 51 + 273.15 ) = 324.15 KFinal volume V₂ = ?Substituting the given values and solve for V₂:
\(V_1T_2 = V_2T_1\\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{2.2\ *\ 324.15}{298.15 }\\ \\V_2 = 2.39 \ L\)
Therefore, the final volume is 2.39 litres.
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what is meant by density
Answer:
The degree of compactness of a substance
3. Lily is studying the core of Earth. Which sphere is she examining?
biosphere
atmosphere
hydrosphere
lithosphere
Answer:
D: lithosphere
A liquid ester used to flavour food is believed to be impure. What would be the best way of testing its purity?
Answer:
Filter it
Explanation:
What is the molarity of a solution if 325ml of the solution contains 46.8 grams of NaHCO3?
Answer:
1.714 M
Explanation:
We'll begin by calculating the number of mole in 46.8 g of NaHCO₃. This can be obtained as follow:
Mass of NaHCO₃ = 46.8 g
Molar mass of NaHCO₃ = 23 + 1 + 12 + (3×16)
= 23 + 1 + 12 + 48
= 84 g/mol
Mole of NaHCO₃ =?
Mole = mass / molar mass
Mole of NaHCO₃ = 46.8 / 84
Mole of NaHCO₃ = 0.557 mole
Next, we shall convert 325 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
325 mL = 325 mL × 1 L / 1000 mL
325 mL = 0.325 L
Thus, 325 mL is equivalent to 0.325 L.
Finally, we shall determine the molarity of the solution. This can be obtained as shown below:
Mole of NaHCO₃ = 0.557 mole
Volume = 0.325 L
Molarity =?
Molarity = mole / Volume
Molarity = 0.557 / 0.325
Molarity = 1.714 M
Therefore the molarity of the solution is 1.714 M
Please if you know the answer put it thanks
The diagram shows a picture of a compound.
What is a compound?A compound is a substance that is made up of two or more different elements that are chemically bonded together in a specific ratio.
This means that the elements are combined in a way that creates a new substance with different physical and chemical properties than the individual elements.
Compounds can be formed through a variety of chemical reactions, such as combining elements through a chemical bond or through a reaction between an acid and a base.
So for the given diagram, we can see that it represents two or more elements chemically combined.
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(3 sig figs) Given the chemical equation below, with 202 grams of Barium Oxide being produced how many grams of Aluminum Oxide would you need? 3 BaSO4 + Al203 —>
3 Ba0 + Al2(SO4)3
44.4 g is the mass of Aluminum Oxide is required for the given chemical reaction 3 BaSO\(_4\) + Al\(_2\)O\(_3\)—> 3 BaO + Al\(_2\)(SO\(_4\))\(_3\).
It is the most fundamental characteristic of matter as well as one of the essential quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A body's bulk remains constant at all times. only in rare instances where an enormous quantity of energy is supplied to or taken away from a body.
3 BaSO\(_4\) + Al\(_2\)O\(_3\)—> 3 BaO + Al\(_2\)(SO\(_4\))\(_3\)
moles of BaO =202/ 153.3
=1.32
moles of Al\(_2\)O\(_3\) = 1/3×1.32=0.44
mass of Al\(_2\)O\(_3\) = 0.44×101.9=44.4 g
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.If the reaction of 125 g of C6H6O3 reacts in excess of oxygen (O2) and produces 51
g of H2O.
C6H6O3 + 3O2 → 6CO + 3H2O
a) How many grams of the excess reactant left over?
b) What is the percent yield?
If the reaction of 125 g of C₆H₆O₃ reacts in excess of oxygen (O₂) and produces 51. The calculations for the following are:
a. 51 grams.
b. 95.20 %
What is the percent yield?Percent yield is the calculation of the difference between actual and estimated yields.
C₆H₆O₃ + 3O₂ -------> 6CO + 3H₂O
Molar mass of C₆H₆O₃
6 x 12 + 6 x 1 + 3 x 16 = 72 + 6 + 48 = 126 g per mole.
So, 125 grams is 125 / 1 26 moles = 0.992 moles of C6H6O3.
From the equation, we can see that 1 part of C₆H₆O₃ reacts with 3 parts of Oxygen gas to give 6 parts of Carbon Monoxide and 3 parts of water.
So, 1 part = 0.992 moles
Hence, 3 parts of water is 0.992 x 3 = 2.976 moles of H2O.
Molar mass of H2O = 2 x 1 + 1 x 16 = 18 grams per mole.
So, 2.976 moles of H2O has a mass of 2.976 x 18 = 53.568 grams
So, the mass of water that should have been formed = 53.568 g
Thus, the grams of the excess reactant left over is 51 grams.
Percentage yield = (51 / 53.568) x 100 is 95.20 % (approx.)
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Answer:
If the reaction of 125g C6H6O3 REACTS in excess of O2and produced 51g of H2O what is the % yeild
Explanation:
can u pls help me with this question
Two asteroids are 75,000 m apart one has a mass of 8 x 10^7 N what is the mass of the other asteroid
The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg
To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:
F = (G * m1 * m2) / \(r^{2}\)
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.
Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):
1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)
Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.
The question was incomplete. find the full content below:
Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid
A. 3.4 x \(10^{11}\) kg
B. 8.3 x \(10^{12}\) kg
C. 1.2 x \(10^{12}\) kg
D. 1.2 x \(10^{10}\) kg
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3. What is the picture displayed? *
1 point
Captionless Image
Answer:
(not sure what's the question ) Captionless image??
C + H2O → CO + H2
What is the starting substance?
Answer:
Explanation:
Carbon and water = carbon dioxide and hydrogen
we can smell because we have nose
yes it's true.
we can smell cause we have nose have smelling sense.
Answer:
Really? I thought we had noses to poke in other people's business
The chemical equation here describes a reaction between nickel(Il) carbonate and sulfuric acid.
NiCO3(s) + H2SO4(aq) -> NiSO4(aq) + H20(1) + CO2(g)
Which statement most accurately identifies a reactant dissolved in water?
O NiCO3
O H2S04
O NiSOA
ОН20
NiCO3(s) + H2SO4(aq) ---> NiSO4(aq) + CO2 (g) + H2O (l). The reaction results in the formation of carbonic acid, H2CO3, which breaks down into water and carbon dioxide gas.
What is the chemical equation for sulfuric acid and magnesium carbonate to react?When magnesium carbonate and diluted sulfuric acid H2SO4 are combined, magnesium sulfate, water, and carbon dioxide gas are produced. The following is the balanced chemical equation for the reaction of magnesium carbonate with diluted sulfuric acid: MgSO4 aq + H 2 O + CO 2 g = H 2 SO4 aq.
What occurs when sulfuric acid and sodium carbonate react?As a result, sodium carbonate and sulfuric acid react to generate sodium sulfate, which has the chemical formula Na2SO4. Water and carbon dioxide are the other byproducts. So, in the aforementioned reaction, sodium sulfate, water, and carbon dioxide were all produced.
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Answer:H2SO4 or B
Explanation: I TOOK THE TEST
How many moles of iron are in 2.34 x 10^22 iron atoms?
answer
.03886 grams or 3.886 x 10^‐2 grams
steps
avogadros number
6.022×10²³ atoms of ANY ELEMENT = 1 mole
whats different for every element is the number of GRAMS or MASS
1 mole of iron is 55.847 grams
2.34 x 10²² ÷ 6.022×10²³ =
.03886 grams or
3.886 x 10^‐2 grams
Question 1.4) Two bottles of the same gas are connected. One bottle has 15 particles at first and one has 2 particles. What will happen over time? Why?
We know that in gas the particles are loosely packed, that is it can move freely compared to solid and liquid. Two bottles of the same gas are connected. One bottle has 15 particles at first and one has 2 particles. Diffusion will occur. The particles will move until the volume in both the bottles will be equalized.
For gas there are three laws which are applied. Boyles law, Charles law and Avogadro's law.
Boyles law here it is the relationship between the pressure and the volume. when the volume of the gas at constant temperature varies with pressure applied on it inversely. Formula
P₁V₁=P₂V₂
Charles law is explained in the terms of temperature and volume. it states that the volume of the gas in a fixed amount is directly proportional to its temperature if and only the pressure remains constant. formula
V₁/T₁=V₂/T₂
Avogadro's law is related with the amount and the volume. it says that under the same condition the pressure and the temperature, the equal volume of different gases contains equal number of molecules.
V₁/n₁=V₂/n₂
Diffusion will occur and the particles will be same in both.
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In each test, iron(II) sulfate and iron(III) nitrate were combined with the same substance or substances. However, the sulfate and nitrate parts of the compounds didn’t participate in any of the chemical reactions; only the iron ions reacted. Comparing the results for each pair of tests, what can you conclude about the iron(II) and iron(III) ions?
The reason behind this is that
Both Nitrate and sulphate are ions .So they stayed unchangedThere are various kind of reaction like combustion reaction, displacement reaction. So to solve this problem we must be knowing the displacement reaction. Displacement reaction is taking place over here
What is displacement reaction?Displacement reaction is a reaction in which one atom replaces other atom from a molecule on the basis of reactivity strength. The element which on the top of reactivity series displace the element that is lying below to that reactive element
According to our question the balanced equation is
FeSO₄+Zn\(\rightarrow\) ZnSO₄+Fe(II)
Fe(NO₃)₂+Zn \(\rightarrow\) Zn(NO₃)₂+Fe(II)
In both reaction Zn is more reactive than Fe(II) and Fe(III) that is why Zn replace or displace iron ion from its compound of sulfate and nitrate. Metal displace metals. anions are displaced by anions. So, here metal is displaced by zinc.
Thus we can conclude that zinc is more reactive than iron Fe(II) and Fe(III). Displacement reaction is taking place over here
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What are five constitutional isomers of hydroxymethylcyclohexane that contain the cyclohexane ring?
The five constitutional isomers of hydroxymethylcyclohexane that contain the cyclohexane ring are:
hydroxymethylcyclohexanemethyl cyclohexanol2-methyl cyclohexanol3-methyl cyclohexanol4-methyl cyclohexanolHydroxymethylcyclohexane is an alcohol that contains a cyclohexane ring, as shown in the attached picture.
Constitutional or structural isomers are compounds with the same molecular formula but different structural formulas.
We can find the five constitutional isomers of hydroxymethylcyclohexane that contain the cyclohexane ring by attaching the hydroxyl group to the cyclohexane ring and varying the positions of the methyl group, as shown in the picture.
The five constitutional isomers of hydroxymethylcyclohexane that contain the cyclohexane ring are:
hydroxymethylcyclohexanemethyl cyclohexanol2-methyl cyclohexanol3-methyl cyclohexanol4-methyl cyclohexanolLearn more: https://brainly.com/question/14391080
KCIO3 decomposes according to thereaction below:
2KCIO3 → 2KCI + 302
How many moles of O2 form when
2.0 mole of KCIO3 decomposes?
When 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
The balanced chemical equation shows that 2 moles of KCIO3 decompose to produce 3 moles of O2. Therefore, we can use the stoichiometric ratio from the balanced equation to determine the number of moles of O2 formed when 2.0 moles of KCIO3 decompose.
According to the stoichiometry, 2 moles of KCIO3 produce 3 moles of O2. Therefore, we can set up a proportion:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
where x represents the unknown number of moles of O2 formed.
Simplifying the equation:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
1 = (2.0 moles KCIO3 / x moles O2),
Cross-multiplying:
x moles O2 = (2.0 moles KCIO3 / 1),
x moles O2 = 2.0 moles KCIO3.
Therefore, when 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
It is important to note that this calculation assumes complete and ideal conditions, where the reaction proceeds with 100% efficiency. In reality, the actual yield of O2 may be lower due to various factors such as side reactions or incomplete decomposition. To determine the actual yield, additional information or experimental data would be required.
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