Need help with how to calculate the Gravitation potential energy and kinetic energy

Answer:

option d is the answer of given statement

The surface area of the right cone is 54π units². Hence option D correct.

The surface area of a solid object is a total area measured that the surface of the object occupies. the surface area of the cube is 6 times side², cause it has 6 faces.

The surface area is total area occupied by the surface of the object.

A cone is geometrical shape which is having circular base and cone shaped body. when a line is drawn from tip to the center of the base it will make right angle between radius and height of the cone. We can apply Pythagoras theorem to get values of radius, height and hypotenuse.

The total area of the cone is nothing but area of the base plus curved area of the body.

Hence area of the cone is,

A = πr²+πr\(\sqrt[]{r^{2}+h^{2} }\)

Given,

r = 3

hypotenuse = \(\sqrt[]{r^{2}+h^{2} }\) = 15

A = ?

A = π3²+π3*15

A = π (9+45)

A = 54π units²

Hence area of the cone is 54π units².

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Answer:

  v = 10 m / s

Explanation:

For this exercise we will use the relationship between the speed of a wave and its frequency and wavelength

         v = λ f

the wavelength is the distance at which the wave repeats, in this case the distance between the two ridges λ = 48 m.

the frequency is the number of oscillations per unit of time, it is also the inverse of the period which is the time in a complete oscillation, in this case they give us the time of half a period, ½ T = 2.4 s

   T = 4.8 s

the frequency is

        f = 1 / T

        f = 1 / 4.8

        f = 0.2083 Hz

let's calculate

        v = 0.2083 48

        v = 10 m / s

Answer:

B 1,3, and 4

Explanation:

Answer:

2 m/s

Explanation:

The electromagnetic flow-metre work on the principle of electromagnetic induction. The induced voltage is given as

\(E = Blv\)

where \(E\) is the induced voltage = 2.88 mV = 2.88 x 10^-3 V

\(l\) is the distance between the electrodes in this field which is equivalent to the diameter of the tube = 1.2 cm = 1.2 x 10^-2 m

\(v\) is the velocity of the fluid through the field = ?

\(B\) is the magnetic field = 0.120 T

substituting, we have

2.88 x 10^-3 = 0.120 x 1.2 x 10^-2 x \(v\)

2.88 x 10^-3 = 1.44 x 10^-3 x \(v\)

\(v\) = 2.88/1.44 = 2 m/s

Answer:

Answer:

1distance --------- lightyear

2power------------- watt

3energy ----------- joule

4resistance ------ Ohm

5Force---------------- Newton

The highlighted phenomenon in the graph is called the Doppler effect, which involves a modification of frequency for sound waves (or any kind of wave) due to the difference in motion between the observed and the source.

An example of this effect present in the medical field is through ultrasound imaging; doctors use it to measure the velocity and route of blood circulating throughout the patient's body by sending out high-frequency sound waves and analyzing the reflected waves.

What appears in the graphed illustration specifically is linear proportionality, meaning that there is a direct correlation between f and fs, the former being the observed frequency and the latter the source frequency.

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In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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Answer:

d. J. 15 N, right

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

20N force right

5N force left.

The net force is equal to the summation of all the forces in Newton

Net force= +20-5

Net force=+15N

The direction is right.

As the temperature of the flask increases, the molecules in the air become more energetic, resulting in an increase in air pressure.

Given the total pressure measured for the each trail = vapor pressure of liquid +  pressure due to any air trapped in the flask.

a) The pressure of the gas rises because the molecules collide with the container walls more frequently as a result of the faster collisions between the molecules and the walls. This is because the molecules are moving faster and collide more often with the walls of the flask, creating a greater force.

b) To calculate the corrected air pressure, the ideal gas law can be used (P1/T1 = P2/T2). The atmospheric pressure (P1) and temperature (T1) must be known for the trial and the temperature (T2) of the flask must be known. The corrected air pressure (P2) can then be calculated.

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Answer:Weather satellites provide vital information about cloud patterns and ground and sea temperatures. They collect and share information with remote data collecting stations such as weather buoys, and observatories from around the world.

Explanation:

The current density in the electron beam is 397.6 A/m^2. The electric field strength needed to accelerate electrons from rest to a velocity of 3.3 × 10^7 m/s in a distance of 5.0 mm is 3.62 × 10^4 V/m. The power delivered to the screen by the electron beam is 1.76 × 10^-2 W.

a. The current density, J, in the electron beam is given by:

J = I / A

A = πr^2 = π(0.20 × 10^-3)^2 = 1.26 × 10^-7 m^2

Substituting the values given for I and A, we get:

J = 50 × 10^-6 / 1.26 × 10^-7 = 397.6 A/m^2

b. The acceleration of an electron, a, in an electric field, E, is given by:

a = eE / m

E = mv^2 / 2de

Substituting the values given for m, v, and d, we get:

E = (9.11 × 10^-31 kg)(3.3 × 10^7 m/s)^2 / (2 × 5.0 × 10^-3 m)(1.60 × 10^-19 C)

E = 3.62 × 10^4 V/m

c. The kinetic energy of an electron, K, is given by:

K = (1/2)mv^2

K = (1/2)(9.11 × 10^-31 kg)(3.3 × 10^7 m/s)^2 = 5.67 × 10^-17 J

The power delivered to the screen is then:

P = nK

P = (3.1 × 10^14)(5.67 × 10^-17) = 1.76 × 10^-2 W

An electron beam is a stream of high-energy electrons that are generated by accelerating electrons through a high voltage potential difference. The beam can be produced by an electron gun or an electron accelerator, and can be used for a variety of applications such as welding, cutting, drilling, and surface treatment.

Electron beams are widely used in industries such as aerospace, automotive, and electronics, where high precision and accuracy are required. They can be focused to very small diameters, allowing them to be used for micro-fabrication and nano-fabrication. Electron beams are also used in medical applications such as radiation therapy to treat cancer. Electron beams are typically used in a vacuum environment to prevent the electrons from colliding with air molecules and losing energy.

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Answer:

T1 = 417.48N

T2 = 361.54N

T3 = 208.74N

Explanation:

Using the sin rule to fine the tension in the strings;

Given

amass = 42.6kg

Weight = 42.6 * 9.8 = 417.48N

The third angle will be 180-(60+30)= 90 degrees

Using the sine rule

W/Sin 90 = T3/sin 30 = T2/sin 60

Get T3;

W/Sin 90 = T3/sin 30

417.48/1 = T3/sin30

T3 = 417.48sin30

T3 = 417.48(0.5)

T3 = 208.74N

Also;

W/sin90 = T2/sin 60

417.48/1 = T2/sin60

T2 = 417.48sin60

T2 = 417.48(0.8660)

T2 = 361.54N

The Tension T1 = Weight of the object = 417.48N

Answer:

divide the distance by the time and get average velocity in units of s. the detection to the left

The pressure exerted by Clive in N/cm² when he stands on one foot, given that one foot is 180 cm² and he has a mass of 72 Kg, is 3.92 N/cm²

We'll begin by obtaining the weight of Clive. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

W = 72 × 9.8

W = 705.6 N

Finally, we shall determine the pressure exerted. Details below:

Pressure exerted  = Weight of Clive  / Area

Pressure exerted = 705.6 / 180

Pressure exerted = 3.92 N/cm²

Thus, from the calculation made above, we can conclude that the pressure exerted is 3.92 N/cm²

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In a parallel circuit, the total resistance (Rt) can be determined using the following formula:

1/Rt = 1/r1 + 1/r2 + 1/r3

where r1, r2, and r3 are the individual resistances of the components in the parallel circuit.

By taking the reciprocal of each resistance, adding them together, and then taking the reciprocal of the sum, you can find the total resistance of the parallel circuit.

I hope this helps. Cheers! ^^

Answer:

Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts

Explanation:

Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.

We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.

A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."

Hope this helps ^_^ and have a great day

If the elastic component of a viscoelastic material were completely removed, the material would behave purely as a viscous fluid.

The term viscous component is generally used to describe the behavior of viscoelastic materials, which exhibit both elastic and viscous properties.

The viscous component in that type of material refers to the portion of the deformation brought on by viscous forces, which are forces that oppose the motion and are related to the deformation's velocity.

A viscoelastic substance would act solely as a viscous fluid if the elastic component were fully removed.

Given that only the rate of deformation would depend on the material's deformation and not the total amount of deformation, it would be wholly caused by viscous forces.

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Kinetic energy decreases if either the mass or the velocity of the object decreases or if both decrease. and  Kinetic energy increases if either the mass or the velocity of the object increases or if both increase.

Explanation:

These statements explain the relationship between mass, velocity, and kinetic energy .i.e KE = ½mv², (3) Kinetic energy decreases if either the mass or the velocity of the object decreases or if b decrease. (4)Kinetic energy increases if either the mass or the velocity of the object decreases or if both decrease.

When a body has a mass of m kg and travels a velocity of v m/s then the kinetic energy is given by,

KE=1/2mv²

In the above relation, it is clearly shown that,

Kinetic energy is directly proportional to the mass of the body,

i.e

KE∝m

and also Kinetic energy directly varies with the square of the velocity of the body.

I.e

KE∝v²

Therefore, From the given expression we can conclude that when mass and velocity increased either one of them or both, the kinetic energy also gets increased.

And when mass and velocity decreased either one of them or both, the kinetic energy also gets decreased. Hence options (3) and (4) are correct.

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Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh =  0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:

1. Convection (Moving Water)

2. Radiation (Sunlight)

3. Conduction (Direct Contact)

4.  Convection or Radiation (Most Likely Convection) (Moving Air/Sunlight)

5. Convection (Moving Air)

6. Radiation (Feeling Heat)

Explanation:

See Above

Answer:

  1.15 N

Explanation:

You want to know the force exerted on a mass of 0.003 kg to accelerate it from 0 to 23 m/s in a period of 0.06 s.

The acceleration of the mass is the change in velocity divided by the change in time:

  a = ∆v/∆t

  a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²

The force applied is the product of mass and acceleration:

  F = ma

  F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N

The applied force is 1.15 newtons.

Answer:

The quarterback applies a force of 8.08 N to the ball during the pass.  

Explanation:

To find the force we need to calculate the acceleration first so we can use the following equation:

\( F = ma \)                        

Now, we can calculate the acceleration as follows:

\( x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2} \)    

Since the ball starts from rest \(v_{0} = 0\) and \(x_{0} = 0\):

\( a = \frac{2*x_{f}}{t^{2}} = \frac{2*1.909 m}{(0.439 s)^{2}} = 19.81 m/s^{2} \)

Now we can find the force:

\( F = 0.408 kg*19.81 m/s^{2} = 8.08 N \)                

Therefore, the quarterback applies a force of 8.08 N to the ball during the pass.  

I hope it helps you!                                              

Answer:

interphase

Explanation:

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules