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Please can you explain what this paragraph is trying to say. Also what does it mean in the sentence 'the difference in charge across the battery provides push for current' and what is the difference in charge.



Here's paragraph I need to have a simple definition of:


A high waterfall is also like a large voltage. It will transfer a lot of energy to the water (charge), making the river flow very fast (a large current) the difference in height makes the river flow. In a circuit , the difference in charge across battery provides push for the current.

The 66 percent of Millennials were employed in the year 2018.

Millennials are the people who are born between 1982 and 1998 while on the other hand, 87% of men in the Silent Generation were employed so there is a decrease occur in the employment rate from silent generation to Millennial generation.

The reason behind this decrease is the unavailability of employment opportunities and jobs for the people of Millennial generation so we can conclude that 66 percent of of Millennial men were employed in the year 2018.

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Answer:

Lead is melted into a liquid to form pellets.

Answer:

C. lead is melted into a liquid to form pellets

Explanation:

Answer:

x-component = 0.237 [m]

Explanation:

In order to solve this problem in an easy way, we must first make a sketch of the vector and its respective angle with the X-axis, in the attached image we can see that sketch.

Since the X component of the vector is needed, this component can be found by means of the cosine of the angle and its hypotenuse.

x-component = 0.250*cos(18.4)

x-component = 0.237 [m]

Answer:

x = 0.237

y = -0.0789

Explanation:

Answer:

d) electrical repulsion

Explanation:

When you stand on a floor, the two different bodies i.e your shoes and the floor on which you stand, are in a very close contact, the electrons that surround your shoes and that of the floor exert a repulsive force on each other, also known as Coulomb's force of repulsion or  electrical repulsive force.

This electrical repulsive force prevents you from falling through the floor.

By dividing an object's charge by its basic charge, one can calculate the quantity of extra electrons (or protons, in the case of positive charges), in a system.

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Answer:

Magnitude of gravitational force between this planet and its moon: approximately \(1.37 \times 10^{20}\; \rm N\).

Acceleration of this moon towards the planet: approximately \(5.49 \times 10^{-3}\; \rm m \cdot s^{-2}\).

Acceleration of this planet towards its moon: approximately \(2.29 \times 10^{-5}\; \rm m \cdot s^{-2}\).

Explanation:

Look up the gravitational constant, \(G\):

\(G \approx 6.67 \times 10^{-11}\; \rm m^3\cdot kg^{-1} \cdot s^{-2}\).

Assume that both this planet and its moon are spheres of uniform density. When studying the gravitational interaction between this planet and its moon, this assumption allows them to be considered as two point masses.

The formula for the size of gravitational force between two point masses \(m_1\) and \(m_2\) with a distance of \(r\) in between is:

\(\displaystyle F = \frac{G \cdot m_1 \cdot m_2}{r^2}\),

where \(G\) is the gravitational constant.

Let \(m_1\) and \(m_2\) denote the mass of this planet and its moon, respectively.

Calculate the size of gravitational force between this planet and its moon:

\(\begin{aligned} F &= \frac{G \cdot m_1 \cdot m_2}{r^2} \\ &\approx \frac{6.67 \times 10^{-11}\; \rm m^3 \cdot kg^{-1} \cdot s^{-2} \times 6.00 \times 10^{24}\; \rm kg \times 2.50 \times 10^{22}\; \rm kg}{{\left(2.70 \times 10^{8}\; \rm m\right)}^2} \\ &\approx 1.37 \times 10^{20}\; \rm N\end{aligned}\).

Assume that other than the gravitational force between this planet and its moon, all other forces (e.g., gravitational force between this planet and the star) are negligible. The magnitude of the net force on the planet and on the moon should both be approximately \(1.37 \times 10^{20}\; \rm N\).

Apply Newton's Second Law of motion to find the acceleration of this planet and its moon:

\(\displaystyle \text{acceleration} = \frac{\text{net force}}{\text{mass}}\).

For this moon:

\(\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{2.50 \times 10^{22}\; \rm kg} \approx 5.49\times 10^{-3}\; \rm m \cdot s^{-2}\).

For this planet:

\(\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{6.00 \times 10^{24}\; \rm kg} \approx 2.29 \times 10^{-5}\; \rm m \cdot s^{-2}\).

Answer:

-48cm

Explanation:

For a convex lens f is +ve and V is +ve

Using the formula 1/f=1/v+1/u

u=12cm and f=16cm

1/16-1/12=1/v

1/v=-1/48

v=-48cm

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:

The value is  \(C = 30729\ c\)

Explanation:

From the question we are told that

  The power rating of the stove is  \(P = 4.4 KW = 4.4 *10^{3} \ W\)

   The duration of its use everyday is \(t_1 = 70 \ minutes = 1.167 \ hours\)    

    The rating of the light bulbs is \(P_2' = 150 W\)

   The number is \(n = 7\)

   The power rating of the total  bulb is  \(P_2 = 7 * 150 = 1050 \ W\)

    The duration of its use everyday is  \(t_2 = 7 hours\)

    The power rating of miscellaneous appliance \(P_3 = 1.8 \ KW = 1.8 *10^{3} \ W\)

    The duration of its use everyday is \(t_3 = 1 hour\)

     The power rating of hot water \(P = 4 KW = 4 *10^{3} \ W\)

      The duration of its use everyday is \(t_4 = 120 \ minutes = 2 hours\)

Generally the total electrical energy used in 1 month is mathematically represented as

    \(E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30\)

=>  \(E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30\)

=>  \(E = 614598 \ W \cdot h\)

=>   \(E = 614.6 \ K W \cdot h\)

Generally the monthly electricity  bill is mathematically represented as

    \(C = 614.6 * 50\)

=> \(C = 30729\ c\)

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 25 N

distance = 3 m

We have

work done = 25 × 3

We have the final answer as

Hope this helps you

Explanation:

We can use the Lorentz transformation to calculate the distance to the star system as measured by an observer in the rocket ship.

The Lorentz transformation for length is:

L = L0 / sqrt(1 - v^2/c^2)

where L0 is the proper length (the distance as measured by an observer at rest with respect to the distance), v is the velocity of the rocket ship, c is the speed of light, and L is the length as measured by the observer in the rocket ship.

In this case, L0 = 38 trillion km, v = 0.68c, and c = 299,792.458 km/s.

Plugging these values into the equation, we get:

L = 38 trillion km / sqrt(1 - (0.68c)^2/c^2)

= 38 trillion km / sqrt(1 - 0.68^2)

= 38 trillion km / 0.748331

= 50.8 trillion km

Therefore, the distance to the star system as measured by an observer in the rocket ship is approximately 50.8 trillion km.

This is actually an advantage of a parallel circuit. In a parallel circuit, the resistance in each branch is the same as if there was just one light bulb in the whole circuit.

In a parallel circuit, the current has multiple pathways to flow through. Each component, such as a light bulb, is connected across its own branch. The total resistance in a parallel circuit is determined by the sum of the reciprocals of the individual resistances in each branch.

Having the same resistance in each branch ensures that the current is distributed equally among the branches. This means that each component receives the same amount of current as if it were the only component in the circuit. As a result, the brightness of the light bulbs in a parallel circuit will be the same.

This characteristic of parallel circuits is advantageous because it allows for independent operation of each component. If one light bulb were to burn out or be removed, the other bulbs would continue to operate unaffected. Additionally, parallel circuits offer lower overall resistance compared to a series circuit, enabling the flow of more current.

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Answer:

Halide

Explanation:

It has at least one element from the halogen group (17)

Halide describes any compound that has at least one element from group 17, therefore the correct option is option A.

When the elements belonging to group 17 of the periodic table form ionic compounds with other electropositive elements, then these compounds are known as halides.

These elements from group 17 are also known as halogens. Generally, these halides have very high electronegativity as they reside on the right side of the periodic table.

Generally, the valency of the halogens element involved in the halide compound is one and they form ionic compounds with the alkali and alkaline earth metals.

Thus, halides are compounds that have at least one element from group 17.

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With the use of formula, the the diver will enters the water with the speed of 22.1 m/s

Speed is how fast an object is moving which can be defined as distance over time.

Given that a cliff diver stands at the top of a cliff and falls forward off the cliff. If the cliff is 25 m tall, to know how fast  the diver going as she enters the water below, let us make use of the equation below

v² = u² + 2gH  Where

Substitute all the parameters into the equation

v² = 2× 9.8 × 25

v² = 490

v = √490

v = 22.1 m/s

Therefore, the diver is going as she enters the water with the speed of 22.1 m/s

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Answer:

61.6886 kg

Explanation:

Answer:

61 kg

Explanation:

there ya go hope this was useful

Answer:

yes friction is needed hope this helps might of been to long tho

Answer:

false

Explanation:

The maximum compression in the spring is 0.06883 meters.

Given to us,

mass of bullet, \(m= 16.2\ grams\)

velocity of bullet, \(v= 850\ meter/second\)

mass of the block, \(m_2= 40\ kilograms\)

velocity of block, \(v_2= 0\ meter/second\)

spring constant, \(k = 1000\ Newton/meter\)

Combined mass after collision,

\(\begin{aligned}M&= m_1+m_2\\&= 40.0162\ Kilograms\end{aligned}\)

Using the momentum conservation equation, to find out final velocity of the system(bullet and block combined)

\(m_1v_1+m_2v_2= MV\\\)

\(0.0162\times 850+40\times 0 = 40.0162\times V\\V= 0.3441 meter/sec\)

Now using the Conservation of Energy (Kinetic energy of the system will be equal to potential energy in the spring), to find out the displacement of the spring \((x)\)

\(\frac{1}{2}kx^2 = \frac{1}{2}MV^2\\\\\frac{1}{2}\times 1000\times x^2= \frac{1}{2} \times40.0162\times0.3441^2\\\\x^2= 0.004738\\\\x= 0.06883\ meters\)

Hence, the maximum compression in the spring is 0.06883 meters.

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Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

Given:

Apparent power (S) = 10 KVA = 10,000 VA

Line voltage (V) = 380 V

Frequency (f) = 50 Hz

Xd = 12 ohms

Xq = 8 ohms

Ra = 1 ohm

Power factor (pf) = 0.8 lagging

Load angle (δ) = 16.15 degrees

(i) Armature current's direct axis and quadrature axis components

We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:

S = 3Vphase Iphase cos(φ)

Iphase = S / (3Vphase cos(φ))

For a lagging power factor, cos(φ) = 0.8, so

Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A

The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current.  Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:

Id = (VL - IaRa) / Xd

Iq = (VL - IaRa) / Xq

where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,

Ia = Iphase / √3 = 10.46 / √3 = 6.03 A

Substituting the given values:

Id = (380 - 6.03 x 1) / 12 = 30.28 A

Iq = (380 - 6.03 x 1) / 8 = 46.92 A

(ii) Excitation voltage of the generator:

The excitation voltage (E) of the generator is given by:

E = Vphase + IqXq

Substituting the given values:

E = 380 + 46.92 x 8 = 765.36 V

Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

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The distance travelled by the vehicle around the circular track is 1,052.4 m.

The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.

d = 2πr

d = πd

Where;

In one complete cycle, the  vehicle will travel the circular track only once.

d = π(335 m)

d = 1,052.4 m

Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.

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The complete question is below:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?

The mass of a material with density is required to make a hollow spherical shell having an inner radius of r1 and an outer radius of r2 is given as \(\frac{4\pi.p(r^3_2-r^3_1)}{3}\)

The amount of anything in relation to a unit of volume, area, or length: as. : the substance's mass in relation to its volume. grams per cubic centimeter is a unit of density.

The volume of a spherical shell can be calculated from:

V= \(V_o - V_1 = \frac{4}{3}\pi(r^3_2 - r^3_1)\)

From the definition of density, ρ = m/v

So,

m = pv = p\((\frac{4}{3} \pi)\)\((r^3_2 - r^3_1)\) = \(\frac{4\pi.p(r^3_2-r^3_1)}{3}\)

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Answer:

By the Pythagorean Theorem the distances from the speakers os

5 and 5.5 (rounding) meters   - let y be the wavelength in the solution

n y = 5      n is number of wavelengths from speaker

(n + m) y = 5.5      m must be integral for constructive interference

m y = .5       subtracting equations

m = 2      and y = ,25   for the above conditions

(n + 2) y = 5.5     substituting for m

n = 5.5 / .25 - 2 = 20

f = v / y     using frequency of sound

f = 340 / .25 = 1360 / sec    for lowest frequency

Check: D1 = y n  = ,25 * 20 = 5

and D2 = .25 * 22 = 5.5     for the distances traveled

Hi there!

1.

To find the maximum angle that the ramp can have, we must find the angle at which the net force on the wheelchair wheel along the axis of the plane is still 0 N.

We can do this using a summation of forces. The only two forces acting on the wheelchair wheel in this situation is the force due to STATIC friction and gravity:

⇒ Force due to static friction: Fs = μN

In this case, N = mgcosθ, so :
\(F_s = \mu mgcos\theta\)

⇒ Force due to gravity along the axis:
\(F_g = mgsin\theta\)

These two must sum up to zero, so:
\(\Sigma F = mgsin\theta - \mu mgcos\theta = 0 \\ \\ mgsin\theta = \mu mgcos\theta\)
Cancel the mass and gravity:
\(sin\theta = \mu cos\theta\\ \\ tan\theta = \mu \\ \\ tan\theta = 0.4\\ \\ tan^{-1}(0.4) = \boxed{21.80^o}\)

2.

Yes. The coefficient of static friction provides you with the MAXIMUM amount of friction force (resistance) that must be overcome for the object to begin moving, while the coefficient of kinetic friction allows you to find the friction force experienced by a MOVING object. In this instance, the coefficient of KINETIC friction is most appropriate because the wheelchair is moving on the ramp. However, if finding the maximum angle of a ramp with an object placed on it, the coefficient of STATIC friction would need to be used in determining the angle that will cause the object to begin sliding.

3.

A switch-back decreases the angle of inclination that a car must travel, so the risk of the car sliding down is decreased because as the angle DECREASES, the force due to friction INCREASES. Friction is what prevents a car from sliding, so minimizing the angle of a ramp/road will increase the friction force and lower the risk of sliding down.

The horizontal force that was exerted by the wind on the mast based on the power is 67.3KN.

Blade Stan, d = 75m

Radius of Blade, r = 75m

wind velocity, V = 30 km/h V = 8.333 m/s

Turbine Generator efficiency or Power Co-efficient ((p) = 32% 0.32.

Flow rate across the turbine (in) = 125X8.333X X (75) 2 m

= 46017.583 kg/s

Air Exit velocity, Ve = V×√1 - Nterbine

Ve = 8.333 x √1 1- 0.32

Ve = 6.872 mls

Horizental force in x-direction (F); -

Fx = m (ve-v)

Fx = 46017-583X(6-872-8.333) = 67265.381 N

The Horizental force Extered on the Supporting mast F = -F F= 67.2654 KN

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Determine the horizontal force that was exerted by the wind on the mast base

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

Explanation:

2^5=32-20=-12 meters per sec (going backwards).

If this is correct pls mark me. brainly to let me know, tyy C:

Answer:

True

Explanation: