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Thanks+ BRAINLIST only for correct answers it’s due in 10 mins I really need help

1.what is the order if visible light in increasing energy?
-violet, indigo, blue, green, yellow, orange, red
-red, orange, yellow, green, blue, indigo, violet

2.visible light is a mixture of
-refraction and reflection
-atoms and molecules
-many colors
-ultra violet and non violet rays

Answer:

1. i would think C

2. D

3. B

4.A

Explanation:

Answer:

1-C

2-D

3-B

4-A

Got it right on the post-test

Answer:

12.25 meters

Explanation:

s=1/2(v+u)t

s= displacement

v= final velocity

u= initial velocity

t= time

7m/s+0m/s divide by 2= 3.5 m/s velocity  Times 3.5 seconds=  12.25 meters

Answer:

Potential, tell me if that's wrong, and sorry if its wrong.

Explanation:

This question involves the concepts of induced emf and magnetic field.

The wire has to move at a speed of "20 m/s".

The emf induced in a current carrying conductor when it passes through a magnetic field is given by the following formula:

\(E = vBl\\\\v=\frac{E}{Bl}\)

where,

Therefore,

\(v=\frac{10\ volts}{(2.5\ T)(0.2\ m)}\)

v = 20 m/s

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The final velocity of the bat would be 10.18 m/s.

We can use the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it. We can write:

(mass of bat) x (initial velocity of bat) + (mass of ball) x (initial velocity of ball) = (mass of bat) x (final velocity of bat) + (mass of ball) x (final velocity of ball)

Plugging in the given values, we get:

(1.4 kg)(15 m/s) + (0.15 kg)(-45 m/s) = (1.4 kg)(final velocity of bat) + (0.15 kg)(50 m/s)

Simplifying the equation, we get:

21 + (-6.75) = 1.4(final velocity of bat) + 7.5

14.25 = 1.4(final velocity of bat)

Final velocity of bat = 10.18 m/s

Therefore, the bat's final velocity is approximately 10.18 m/s.

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Assuming the speed of the wave is taken as the speed of sound wave in air that is 340 m/s. The wavenumber for 262 Hz is 0.77 m⁻¹ and that for 294 Hz is 0.86 m⁻¹ .

The wave number of a wave is the number of wavelengths passing through unit length. It is the inverse of wavelength.

Wave number is directly proportional to the frequency.

The relation between frequency and wave number is written as:

wave number = ν/v

where v is the speed of the wave and ν is the frequency.

The wave number of the wave with the frequency of 330 Hz is then,

330 Hz/ 340 m/s = 0.97  m⁻¹

and for the remaining frequencies:

349 Hz /340 m/s =  1.052  m⁻¹

for 392 Hz,

392 Hz/340 m/s = 1.15  m⁻¹

For 440 Hz,

440 Hz/340 m/s = 1.29  m⁻¹.

for 494 Hz,

494 Hz/340 m/s = 1.45  m⁻¹

and  for 523 Hz,

523 Hz/340 m/s = 1.53  m⁻¹

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The statement $(a)dx = 0.25 implies that the probability of a newborn puppy having a weight between $a$ and $a + dx$ is equal to 0.25. This can be interpreted as the probability that a randomly selected newborn puppy has a weight between a and a + dx, where the unit of weight is grams.The statement "dx = 0.25" is not complete without specifying the variable being referred to. Assuming that the variable in question is the weight of the newborn puppy in grams, then the statement can be interpreted as follows:

The differential change in probability density function with respect to the weight of a newborn puppy is 0.25 grams. In other words, if we consider a small interval of weights centered around a specific weight value, the probability of a newborn puppy having a weight within that interval will increase by 0.25 units for each gram of weight in that interval.

For example, if we consider a weight interval of [500, 501] grams, the probability of a newborn puppy having a weight within that interval will increase by 0.25 x 1 = 0.25 units. Similarly, if we consider a weight interval of [500, 502] grams, the probability of a newborn puppy having a weight within that interval will increase by 0.25 x 2 = 0.5 units.

It is important to note that the PDF represents the relative likelihood of different weight values for a newborn puppy, while the CDF represents the cumulative probability of a newborn puppy weighing less than or equal to a certain weight value. The relationship between the PDF and CDF is given by integration, where the CDF is the integral of the PDF over the range of possible weight values.

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The distance over which the puck accelerates in a slap shot is 0.64 m.

Distance (d) = Acceleration (a) × Time (t)²/2

The final velocity (v) of the puck is given as 38 m/s and initial velocity (u) as 7 m/s. The time taken for the shot is given as 0.03 seconds. Since the velocity is increasing in the same direction, the acceleration (a) is given as

a = (v - u)/t

a = (38 m/s - 7 m/s)/(0.03 s)

a = 1037 m/s²

Therefore, using the above equation, the distance (d) over which the puck accelerates can be calculated as

d = a × t²/2d

= (1037 m/s²) × (0.03 s)²/2d

= 0.64 m

Therefore, the distance over which the puck accelerates in a slap shot is 0.64 m.

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Answer:

4 seconds is -45.2 m/s.

Explanation:

Answer:

A trough

Explanation:

A trough is an elongated area of relatively low pressure extending from the center of a region of low pressure.

I HoPe ThIs Helps!!!

A compass works the way it does because Earth has a magnetic field that looks a lot like the one in a magnet.

The Earth's field is completely invisible, but it can be felt by a compass needle on the Earth's surface, and it reaches thousands of miles out into space.

Mathematically, the magnetic field is represented as a vector field. This vector field can be easily visualized as a collection of several vectors laid out in a grid. Each vector has a length based on the strength of the magnetic field and points in the same direction as a compass would.

This method is demonstrated by placing a grid of numerous small compasses in a magnetic field. The only distinction is that a compass does not reveal the strength of a field in this instance.

Therefore, A compass works the way it does because Earth has a magnetic field that looks a lot like the one in a magnet.

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Answer:

10,000 m/s per 100 seconds

The electric field due to charge 1 at the origin is 2.24 x 10^5 N/C in the direction to the left.

Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It is represented as F = (k * q1 * q2) / r2, where F is the force, k is a constant, q1 and q2 are the charges, and r is the distance between the two particles.

Charge 1: 50.0 nC, located 20.0 cm to the left of origin

Charge 2: 35.0 cm to the right of origin

Using Coulomb's Law, the electric field at the origin due to charge 1 is:

E1 = kQ1/r^2

Where:

k = 8.99 x 10^9 Nm^2/C^2

Q1 = 50.0 nC = 5.00 x 10^-7 C

r = 20.0 cm = 0.20 m

Therefore,

E1 = (8.99 x 10^9 Nm^2/C^2)(5.00 x 10^-7 C)/(0.20m)^2

E1 = 2.24 x 10^5 N/C

Hence, the electric field due to charge 1 at the origin is 2.24 x 10^5 N/C in the direction to the left.

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Answer: The energy to move the fluid is provided by the pressure on the fluid surface.

Explanation:  The frictional losses in the suction pipework and rises in the suction pipework system will reduce the fluid pressure at the pump inlet. If the pump inlet connection is removed the fluid will not flow out of the suction pipework. Hope this helps! :)

Answer:

a=2 m/s²

Explanation:

v=u+at

25=15 +5a

5a=10

a=2 m/s²

Mars has a gravitational field that is roughly 3.71 m/s² strong.

Newtons per kilogramme (N/kg) are used to measure the gravitational field strength (g). At or near the surface, the gravitational field strength of the Earth is 10 N/kg. This implies that an item will experience 10 N of force for every kilogramme of mass.

To get the gravitational field strength, use the following equation:

g = G*M/r²

where:

g = gravitational field strength

G = gravitational constant = 6.6743 × 10⁻¹¹ N(m/kg)²

M = mass of Mars

r = radius of Mars

Plugging in the values:

g = (6.6743 × 10⁻¹¹ N(m/kg)² * 6.39×10²³ kg) / (3.3895×10⁶ m)²

g = 3.71 m/s²

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Answer: 1.61

Explanation:

Seawalls create barriers that prevent floodwaters from entering the protected area. The correct option is C.

Installing a seawall helps mitigate flood damage by creating a barrier that prevents floodwaters from entering the protected area.

Seawalls are typically constructed along coastlines or riverbanks and act as a physical barrier against incoming floodwaters.

When flood events occur, the seawall helps to block and redirect the force of the water, reducing the impact on the protected area.

By preventing floodwaters from inundating the land, seawalls help to safeguard infrastructure, homes, and communities from damage caused by flooding.

They provide a measure of protection and help to mitigate the potential risks and consequences associated with flooding events.

Thus, the correct option is C.

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Your question seems incomplete, the probable complete question is:

How does installing a seawall help mitigate flood damage?

A) Seawalls redirect floodwaters away from the protected area.

B) Seawalls absorb floodwaters to prevent overflow.

C) Seawalls create barriers that prevent floodwaters from entering the protected area.

D) Seawalls increase the capacity of nearby water bodies to hold floodwaters.

The image of a sound wave does not contain any visible wavelengths as sound waves are not visible to the human eye. Therefore, there are no wavelengths seen in the image.

In order to understand why sound waves are not visible, it is important to consider the nature of sound and light waves. Sound waves are mechanical waves that propagate through a medium, such as air or water, by compressing and decompressing the particles of the medium. These waves have specific characteristics, such as frequency and amplitude, which determine their pitch and volume, respectively. However, sound waves do not emit or reflect visible light, which is necessary for our eyes to detect wavelengths and perceive colors.

On the other hand, light waves are electromagnetic waves that consist of oscillating electric and magnetic fields. These waves have a wide range of frequencies, including those within the visible spectrum. When light waves interact with objects, they can be absorbed, transmitted, or reflected, which allows our eyes to perceive the colors and wavelengths associated with different objects.

Therefore, while an image of a sound wave may depict its characteristics, such as its shape or amplitude, it does not show any visible wavelengths as sound waves do not emit or reflect visible light.

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Answer:

negative

Explanation:

positive charges attract negative charges and vice versa. and are possible to nullify

Answer:

You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. Even things that appear to be at rest move.

Explanation:

A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:

Period = 1/Frequency

Given that the frequency of vibration is 5.0Hz, the period of vibration is:

Period = 1/5.0 s

Period = 0.2 s

B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.

C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.

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Answer:

a person appears at a specified time and place and gives sworn testimony

Explanation:

Hope this helps

The magnitude of the magnetic field at a distance r is given by 8 × 10^-6 T·m divided by r.

Ampere's law states that the line integral of the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space.
In this case, we have two parallel wires carrying currents of 14 A and 30 A. Let's consider a closed loop around the first wire. The current enclosed by this loop is 14 A. Applying Ampere's law, we have:
∮B⋅dl = μ₀ × 14 A
The left-hand side of the equation represents the line integral of the magnetic field around the loop. The right-hand side represents the product of the current and the permeability of free space, μ₀.
Since the wires are parallel and right next to each other, the magnetic field due to the first wire will be in the opposite direction to the magnetic field due to the second wire. Therefore, the net magnetic field at a distance r from the wire will be the difference between the magnetic fields due to the two wires.
Using the Biot-Savart law, we can find the magnetic field due to each wire at a distance r. The magnetic field due to a long, straight wire is given by:
B = (μ₀ × I) / (2π × r)
Plugging in the values, we get:
B1 = (μ₀ × 14 A) / (2π × r)
B2 = (μ₀ × 30 A) / (2π × r)
The net magnetic field Bnet at a distance r from the wire is the difference between B2 and B1:
Bnet = B2 - B1
Simplifying the equation, we have:
Bnet = [(μ₀ × 30 A) - (μ₀ × 14 A)] / (2π × r)
Bnet = (μ₀ × 16 A) / (2π × r)
Finally, we can substitute the value of the permeability of free space, μ₀, which is approximately 4π × 10^-7 T·m/A, to find the magnitude of the magnetic field Bnet at a distance r:
Bnet = (4π × 10^-7 T·m/A × 16 A) / (2π × r)
Bnet = (8 × 10^-6 T·m) / r

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Answer:

The new pressure will be 12 atm

the answer to this problem is 15

Answer:itts 20 15 is incorrect ill show u proof

Explanation:

1. Five major external forces that affect organizations are economic, social, cultural, demographic, and technological. Economic factors such as inflation and interest rates can impact a company's profitability and purchasing power. Social factors like changing consumer preferences and lifestyles can influence demand for products and services.

Cultural factors like values and beliefs can shape consumer behavior and market trends. Demographic factors such as population size and age distribution can affect target markets.

Technological factors like advancements in automation or digitalization can disrupt industries and create new opportunities. These external forces shape the business environment and organizations must monitor and adapt to them to stay competitive.

2. Gathering competitive intelligence is crucial for businesses because it provides valuable insights about their competitors' strategies, strengths, weaknesses, and market position.

By understanding the competitive landscape, businesses can identify opportunities and threats, make informed decisions, and develop effective strategies.

Competitive intelligence helps businesses stay ahead of their competitors, anticipate market trends, identify emerging technologies, and improve their own products or services. It allows businesses to benchmark their performance, evaluate their competitive advantage, and identify areas for improvement.

Ultimately, gathering competitive intelligence empowers businesses to make proactive and strategic decisions that can lead to sustainable growth and competitive advantage.

3. In business, various economic variables need to be monitored as they have significant impacts on strategy applications. Some important economic variables include GDP (Gross Domestic Product), inflation rate, exchange rates, interest rates, consumer spending, unemployment rate, and industry-specific factors like raw material prices or energy costs.

Monitoring these variables helps businesses understand the overall economic conditions, identify market opportunities, and assess potential risks. For example, a high inflation rate may impact pricing strategies, while a favorable exchange rate can benefit export-oriented businesses.

By monitoring economic variables, businesses can adapt their strategies accordingly and make informed decisions to navigate the dynamic business environment.

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1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum