NEED ANSWER ASAP
Common topics of physics include:
a forms of energy
b sound
C magnetism
d evolution

Answer:

Explanation:

Given:

p = 110 kg·m/s

V = 2 m/s

___________

M - ?

Momentum

p = M·V

Mass

M = p / V = 110 / 2 = 55 kg

Answer:

1530.4?

Explanation:

1500.0

+030.4

1530.4

The force on the roof that has a surface area of 20000cm² with 100000Pa of pressure exerted is 5N.

Pressure is the amount of force that is applied over a given area divided by the size of this area.

The pressure of a substance can be calculated by using the following formula:

Pressure = Force × area

According to this question, a roof has a surface area of 20000cm². If the atmospheric pressure exerted on the roof is 100000Pa, the amount of force on the roof can be calculated as follows:

100000Pa = Force × 20,000cm²

20000F = 100000

F = 100,000 ÷ 20,000

F = 5N

Therefore, 5N is the force acting on the roof.

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Answer:

if they both face each other they cancel out

Explanation:if there is one on 1 side and on the other as well they cancel out and it is 0

Answer:

If the forces are equal and the forces act in oppposite direction then the net force is equal to zero

When pilots on Instrument Flight Rules (IFR) flights seek Air Traffic Control (ATC) in-flight weather avoidance assistance, they should keep in mind that ATC radar limitations and frequency congestion may limit the controller's capability to provide this service. The correct answer is C.

This means that while ATC can provide weather information and assistance in avoiding hazardous weather conditions, their ability to do so may be limited by factors such as the number of planes in the area, the capabilities of the radar equipment, and the available frequencies. Pilots should therefore be prepared to make their own weather-related decisions and take appropriate action if necessary, even if they are unable to obtain assistance from ATC.

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Answer:

If a powerful gravitational wave passed through you body, moving from your back to your chest, what would happen to your body? Your width and height would both oscillate in such a way that you would get taller as you got narrower and shorter as you got wider.

Explanation:

(b) the presence of technetium in giant star spectra. Astronomers have direct evidence supporting the formation of heavy elements in stars through the observation of certain elements in their spectra.

Here correct answer is B.

One such element is technetium (Tc), which is not naturally occurring on Earth and has no stable isotopes. The presence of Tc in the spectra of certain types of stars, particularly red giants and Mira variables, is a strong indicator of heavy element nucleosynthesis in stars.

This is because Tc is a radioactive element with a short half-life, so any Tc present in a star's atmosphere must have been produced relatively recently through nuclear reactions within the star itself.

Gamma-ray emissions from cobalt 56 decay in supernovae (a) and observed elemental abundances (c) are also used to support the idea of heavy element formation in stars, but they are not direct evidence.

The light curves of type-I supernovae (d) are used to study the expansion and evolution of these events and are not directly related to heavy element formation in stars. Therefore, the correct answer is (b) the presence of technetium in giant star spectra.

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The velocity of the exhaust gas from the jet is approximately 818.18 m/s considering an air speed of 250 m/s,

To calculate the velocity of the exhaust gas from the jet, we can use the conservation of energy principle. The total energy entering the engine equals the total energy leaving the engine.

The total energy entering the engine is the sum of the kinetic energy and the enthalpy of the air:

Energy in = (1/2) * (air velocity)^2 + enthalpy of air

The total energy leaving the engine is the sum of the kinetic energy and the enthalpy of the exhaust gas:

Energy out = (1/2) * (exhaust gas velocity)^2 + enthalpy of exhaust gas

Since we know the air velocity, enthalpy of air, enthalpy of exhaust gas, and the fuel-air ratio, we can calculate the exhaust gas velocity.

First, let's convert the temperatures from Celsius to Kelvin:

Ambient air temperature = -14°C = 259 K

Exhaust gas temperature = 610°C = 883 K

Next, we need to calculate the enthalpy of the fuel-air mixture. The enthalpy of the fuel-air mixture is given by:

Enthalpy of fuel-air mixture = (fuel-air ratio) * (enthalpy of fuel) + (1 - fuel-air ratio) * (enthalpy of air)

Enthalpy of fuel-air mixture = 0.0180 * 45 MJ/kg + (1 - 0.0180) * 250 kJ/kg

Enthalpy of fuel-air mixture = 0.81 MJ/kg + 245.5 kJ/kg

Enthalpy of fuel-air mixture = 810 kJ/kg + 245.5 kJ/kg = 1055.5 kJ/kg

Now, let's calculate the energy in and energy out using the given values:

Energy in = (1/2) * (250 m/s)^2 + 250 kJ/kg

Energy in = 31,250 kJ/kg + 250 kJ/kg = 31,500 kJ/kg

Energy out = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg

Now we can equate the energy in and energy out:

31,500 kJ/kg = (1/2) * (exhaust gas velocity)^2 + 900 kJ/kg

Subtracting 900 kJ/kg from both sides:

31,500 kJ/kg - 900 kJ/kg = (1/2) * (exhaust gas velocity)^2

30,600 kJ/kg = (1/2) * (exhaust gas velocity)^2

Multiplying both sides by 2:

61,200 kJ/kg = (exhaust gas velocity)^2

Taking the square root of both sides:

exhaust gas velocity = √(61,200 kJ/kg)

exhaust gas velocity ≈ 247.97 m/s

However, this velocity only represents the gas velocity with respect to the stationary observer. To find the velocity of the exhaust gas in m/s from the jet, we need to consider the airspeed of the jet.

The velocity of the exhaust gas from the jet is given by:

Velocity of exhaust gas from jet = exhaust gas velocity + air velocity

Velocity of exhaust gas from jet ≈ 247.97 m/s + 250 m/s

Velocity of exhaust gas from jet≈ 497.97 m/s

So, the velocity of the exhaust gas from the jet is approximately 818.18 m/s.

The velocity of the exhaust gas from the jet is approximately 818.18 m/s, considering an air speed of 250 m/s, an ambient air temperature of -14°C, an exhaust gas temperature of 610°C, a fuel-air ratio of 0.0180, and heat loss from the engine of 21 kJ/kg of air.

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P waves arrive first because they move the most quickly. P and  S waves arrive later because they move at a speed that is roughly half that of P waves.

Seismic P waves, also known as compressional , longitudinal waves, oscillate (squeeze and expand) the ground forth and forth in direction of travel, much like how sound waves oscillate as they go from source towards receiver. The quickest wave is P wave.

S-waves are referred to as transverse waves since they cause the ground to vibrate perpendicular to the wave's path of propagation. When a transverse wave travels parallel to the direction it is traveling, it passes over the earth. They are transverse waves, S-waves.

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Beryllium (Be) is the only alkaline earth metal that does not react with water.

What are alkali metals and their properties?

Alkali is a substance that produces hydroxide ions in aqueous solution.

PHYSICAL PROPERTIES OF ALKALIS:

CHEMICAL PROPERTIES OF ALKALI METAL

Beryllium (Be) is the only alkaline earth metal that does not react with water.

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The net force is (40 Newtons) (down the road).

But 40 Newtons is not going to move a piano very enthusiastically.

Answer:

The skater has mechanical/gravitational potential energy at the two meter mark. The skater gets to two meters high on the other end of the ramp. In terms of the conservation of energy, the skater will never go higher than two meter on the other end of the the ramp because energy can be neither created nor destroyed.

Explanation:

I hoping it is right!!!∪∧∪     ∪ω∪

Answer:

the reason it wont go higher is because some of the energy converts into thermal energy

Explanation:

I'm the energy master

The third sphere, C, should be located 750 cm away from both sphere A and B. This is because the magnitude and direction of the forces created at the midpoint of the line connecting two spheres is equal to zero.

Thus, for there to be a net force of zero, the sphere C should be placed at the midpoint of that line which is 500 cm from both spheres A and B, i.e. 750 cm away from each sphere. sphere, C, must be placed at a distance of 900 cm away from sphere A and 800 cm away from sphere B in order for the net force on it to be zero. This can be deduced from using the equation F=Gm1m2/r^2, where F is the gravitational attraction between two masses m1 and m2 that are separated by a distance r.

The net force will be zero when the gravitational attraction of each sphere are equal.The location of the third sphere C must be at a distance 250 cm away from Sphere A and 250 cm away from Sphere B in order for the net force to be zero. This can be determined using F=G*mA*mB/r2, where F is the force of gravity, G is the universal gravitational constant, mA and mB are the masses of the two spheres, and r is the distance between them. If mA is 5m and mB is 8m, the net force of gravity will be zero when r is equal to 500 cm.

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The angled cable's tension force is about 1530.09 N.

To solve the problem, consider the forces acting on the beam and the hanging object.

Calculate the gravitational force acting on the hanging object:

F_gravity = m×g

F_gravity = 110 kg × 9.81 m/s²

Calculate the torque produced by the gravitational force:

torque_gravity = F_gravity × L

torque_gravity = 1079.1 N × 4.2 m

torque_gravity = 4533.72 N·m

Since the beam is in equilibrium, the torque produced by the tension force in the angled cable must be equal and opposite to the torque produced by the gravitational force of the hanging object.

The component of the tension force at 0 perpendicular to the beam:

tension_perpendicular = torque_gravity / L

tension_perpendicular = 4533.72 N·m / 4.2 m

tension_perpendicular = 1080.41 N

Find the tension force in the angled cable using trigonometry:

tension = tension_perpendicular / sin(θ)

tension = 1080.41 N / sin(45°)

tension = 1530.09 N

Therefore, the tension force in the angled cable is approximately 1530.09 N.

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Resolving power refers to the ability of a lens to distinguish between two closely spaced objects. It is determined by the wavelength of light and the numerical aperture of the lens.

Magnifying power, on the other hand, refers to the ability of a lens to enlarge the size of an object. It is determined by the focal length of the lens.
The term "parfocal" refers to a type of lens system where multiple lenses have the same focal point when the focus is adjusted. This means that when switching between different lenses, the focus remains the same, making it easier for the user to switch between lenses without losing focus.
Differentiating between the resolving power and magnifying power of a lens involves understanding their respective functions. Resolving power refers to the ability of a lens to distinguish between two closely spaced objects, or in other words, the clarity with which the lens can produce an image. Magnifying power, on the other hand, refers to the degree to which a lens can enlarge the image of an object.

The term "parfocal" is used to describe a set of lenses that, when interchanged on a microscope or other optical instrument, maintain their focus on the same object. This means that when you switch from one parfocal lens to another, only minimal adjustments to the focus are needed, allowing for a seamless transition between lenses with different magnifying powers.

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Resolving Power: It is the ability of a lens to separate or distinguish between closely spaced objects, reflecting the detail that can be seen with the lens.

Magnifying Power: It denotes how much larger an object appears through a lens compared to its actual size. High magnification doesn't necessarily mean better image quality.

Parfocal: This term refers to lenses that remain in focus even when the magnification or focal length changes. It enables swift adjustments in magnification without needing constant refocusing.

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Answer:

D. Electric Charges

Answer:

1. is held

2. was

3. be cancelled

4. has been moved

5. is being filmed

Explanation:

If you read them out, you can find out which ones flow the best! Hope this helps!

As a result, when seen from the electron source, the spot on the screen will be deflected to the right.

The scanning electron microscope ( sem (TEM), the first type of electron microscope, produces images of the specimen by illuminating it with a high voltage electron beam. An electron gun is used to create the electron beam; typically, the electron source is a tungsten filament cathode.

Both high-energy collisions, such as those that occur when cosmic rays penetrate the atmosphere, and the beta decay or radioactive isotopes can produce electrons. The name "positron" refers to the electron's antiparticle, which is essentially the same as the electron with the exception that it has electrical charge that is in the opposite direction.

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The linear homogeneous recurrence relation with constant coefficients that the sequence is: An = -(-1)n + (3)n or An = (1)n + (3)n

The sequence An = (n-3)(2n) + n(2n) satisfies the linear homogeneous recurrence relation with constant coefficients. In order to prove this, we need to first find the general formula of the sequence.

The formula can be found by replacing n with n+1 as follows:

An+1 = (n+1-3)(2n+2) + (n+1)(2n+2)

An+1 = n(2n+4) + (n+1)(2n+2)

An+1 = 2n² + 4n + 2n² + 4n + n + 2n + 2

An+1 = 4n² + 7n + 2

The characteristic equation of the linear homogeneous recurrence relation is given by:

r² - 2r - 3 = 0

Solving this quadratic equation, we get:r = -1 or r = 3

Hence, the general formula of the sequence is given by:An = A(-1)n + B(3)n

Now, we need to find the values of A and B using the initial values of the sequence. The first two terms of the sequence are given by:

A0 = -6 and A1 = 2

Substituting these values in the general formula, we get:

-6 = A + B2 = -A + 3B

From the above two equations, we can solve for A and B to get:

A = -1 and B = 1

Hence, the linear homogeneous recurrence relation with constant coefficients that the sequence An = (n-3)(2n) + n(2n) satisfies is given by:

An = -(-1)n + (3)n or An = (1)n + (3)n

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Answer:

Explanation:

Density = mass/volume

132g/(48.9 cm³) = 2.7 g/cm³

(27 g)/(3 cm³) = 9 g/cm³

512 g/(65 cm³) = 7.9 g/cm³

1.2 kg/(3243 cm³) cm³ = 1200 g/(3243 cm³) = 0.37 g/cm³

Answer:

At \(t = (70 / 3) \; {\rm s}\) (approximately \(23.3 \; {\rm s}\).)

Explanation:

Note that the acceleration of the car between \(t = 0\; {\rm s}\) and \(t = 20\; {\rm s}\) (\(\Delta t = 20\; {\rm s}\)) is constant. Initial velocity of the car was \(v_{0} = 0\; {\rm m\cdot s^{-1}}\), whereas \(v_{1} = 35\; {\rm m\cdot s^{-1}}\) at \(t = 20\; {\rm s}\!\). Hence, at \(t = 20\; {\rm s}\!\!\), this car would have travelled a distance of:

\(\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}\).

At \(t = 20\; {\rm s}\), the truck would have travelled a distance of \(x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}\).

In other words, at \(t = 20\; {\rm s}\), the truck was \(400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}\) ahead of the car. The velocity of the car is greater than that of the truck by \(35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}\). It would take another \((50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}\) before the car catches up with the truck.

Hence, the car would catch up with the truck at \(t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}\).

Answer:

25 joules

Explanation:

Not sure I understood correctly but since 15 are taken up by mechanical energy and 10 are taken in by electrical, 50-10-15 would result in 25 joules which must belong to heat energy

Answer:

vega the first one

pb

p

Explanation:

The total flux through the balloon depends on the size of the balloon and the charge enclosed within it.

Flux is a measure of the electric field passing through a given area.

The total flux through a closed surface is proportional to the charge enclosed within that surface.

In the case of a balloon, the total flux through it would depend on the size of the balloon and the charge enclosed within it.

A larger balloon with more charge inside would have a greater total flux than a smaller balloon with less charge inside.

Summary: The total flux through a balloon is not fixed and depends on the size of the balloon and the charge enclosed within it. Therefore, the statement "The total flux through the balloon is q/o, regardless of the size of the balloon" is false.

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Extension of the first metatarsophalangeal joint would be necessary for a patient to stand on tiptoe is d.) 55 degrees and hence the correct answer is option d).

Extension of the first metatarsophalangeal joint is necessary for the patient to stand on the tiptoes. The first metatarsophalangeal joint is a joint between the metatarsal bone of the foot and the proximal phalanx of the great toe. Dorsiflexion and plantarflexion are the main movements that occur in this joint.

When a person stands on the tiptoes, the ankle joint plantarflexes and the metatarsophalangeal joint dorsiflexes. In the case of normal individuals, an extension of about 50 to 60 degrees of the first metatarsophalangeal joint is necessary to stand on tiptoe.

The dorsiflexion at the ankle joint occurs before the dorsiflexion at the metatarsophalangeal joint. If there is any restriction in the movement of the first metatarsophalangeal joint, then it will lead to difficulty in standing on the tiptoe. Therefore, option d. 55 degrees is the correct option.

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Answer:

ATP

During cellular respiration, a glucose molecule is gradually broken down into carbon dioxide and water. Along the way, some ATP is produced directly in the reactions that transform glucose. Much more ATP, however, is produced later in a process called oxidative phosphorylation.

Explanation:

have a nice day.

The kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.

Kinetic energy refers to the energy of a body due to its motion. The kinetic energy can be calculated as follows:

K.E = ½ m × v²

Where;

According to this question, an object that has a mass of 50.0 kg and a velocity of 18m/s. The kinetic energy can be calculated as follows:

K.E = ½ × 50 × 18²

K.E = ½ × 16,200

K.E = 8100J.

Therefore, the kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.

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Answer:

GALELOI GALELEI:HE WAS A FAMOUS SCIENTIST WHO MADE PENDULAM ALSO HE EXPLAINED THE MOTION AND INERTIA

ISAAC NEWTON:3 LAWS OF MOTION,3 FORMULAS OF MOTION,GRAVITY

When a chunk of cosmic material the size of a golf ball or a baseball hits the Earth's atmosphere it makes a fireball.

Meteor shower is an event that occurs when tiny particles of stones that are of the size of a golf ball or baseball hits the earth's atmosphere.

As the particles enters the earth's atmosphere, they create friction through rubbing against the particles of the air. This eventually causes the particles to heat up leading to the formation of a fireball.

Meteor shower usually occurs between midnight and the very early hours of the morning.

Therefore, when a chunk of cosmic material the size of a golf ball or a baseball hits the Earth's atmosphere it makes a fireball.

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saitama is the strongest