need an answer asap
if u know physics pls answer the rest of my question!!
i will give brainliest
Answers
a] negative charge it's e-
Related Questions
The electric field in the region between the plates of a parallel plate capacitor has a magnitude of 6.2 x 10^5 V/m. If the plate separation is 0.53 mm, determine the absolute value of the potential difference between the plates.
Answers
The absolute value of the potential difference between the plates is approximately 3.286 x \(10^2\) V. The potential difference (V) between the plates of a parallel plate capacitor is directly related to the electric field (E) and the plate separation (d) by the equation:
V = E * d
Given:
Electric field magnitude (E) = 6.2 x \(10^5\) V/m
Plate separation (d) = 0.53 mm
First, let's convert the plate separation from millimeters to meters:
d = 0.53 mm = 0.53 x \(10^-3\) m
Now, we can calculate the potential difference using the formula:
V = E * d
V = (6.2 x \(10^5\)V/m) * (0.53 x \(10^-3\) m)
V = 6.2 x 0.53 x \(10^5\) x \(10^-3\) V
V = 3.286 x \(10^2\) V
Therefore, the absolute value of the potential difference between the plates is approximately 3.286 x \(10^2\) V.
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A dolphin propels itself through the water, increasing its speed from 5.0 m/s to 8.7 m/s in only 0.70 s. What is the magnitude of the dolphin's average acceleration during this time?
Answers
Answer:
5.29 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 5.0 m/s
Final velocity (v) = 8.7 m/s
Time (t) = 0.70 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
a = (v – u) /t
Where:
a is the acceleration.
v is the final velocity.
u is the initial velocity.
t is the time.
Thus, with the above formula, we can obtain the acceleration of the dolphin as illustrated below:
Initial velocity (u) = 5.0 m/s
Final velocity (v) = 8.7 m/s
Time (t) = 0.70 s
Acceleration (a) =?
a = (v – u) /t
a = (8.7 – 5)/0.7
a = 3.7 / 0.7
a = 5.29 m/s²
Therefore, the dolphin's acceleration is 5.29 m/s².
Si observamos un incremento de temperatura en un termómetro de 24 oC, ¿a cuántos grados Fahrenheit corresponde dicho incremento? ¿Y si el incremento de temperatura fuese de 24 K?
Answers
Responder:
24 ° C = 75.2 ° F 24K = -416.47 ° FExplicación:
La fórmula se utiliza para convertir grados Celsius (° C) en grados Fahrenheit (° F).
x ° C = (y ° F - 32) × 5/9.
Convertir 24 ° C a Fahrenheit
24 = (y ° F - 32) × 5/9.
24 * 9 = 5 (y ° F-32)
216 = 5 años ° F-160
5 ° F = 216 + 160
5 ° F = 376
y ° F = 376/5
y ° F = 75.2
24 ° C = 75.2 ° F
Para convertir Kelvin a Fahrenheit, usaremos la expresión;
(K - 273.15) × 9/5 + 32
Dado K = 24kelvin
24K a ° F = (24− 273.15) × 9/5 + 32
= -249.15 (9/5) + 32
= -448.47 + 32
= -416.47 ° F
24K = = -416.47 ° F
S) a dam has the cross-section of a square with side length of 10m. find the force due to hydrostatic pressure on the dam when the water is 75% of the way up the wall.
Answers
The force due to hydrostatic pressure on the dam when the water is 75% of the way up the wall is 735,750 N
The force due to hydrostatic pressure on the dam can be calculated using the formula
P = ρghA
where P is the force, ρ is the density of the water, g is the acceleration due to gravity, h is the height of the water column, and A is the cross-sectional area of the dam.
In this case, the cross-sectional area of the dam is 100 m2 and the height of the water column is 7.5 m (since the water is 75% of the way up the wall, which is a 10m tall wall). Therefore, the force due to hydrostatic pressure on the dam is
P = 1000 kg/m3 x 9.81 m/s2 x 7.5 m x 100 m2
= 735,750 N
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Two identical projectiles were projected at 200 km/h the first one is at an angle 60 to the horizontal while the second one is at angle of 60 to vertical which projectile reaches a greater horizonatal range
Answers
Answer:
The angle that will have the most range (Goes further) will be the one that is shot with 60 ° with the horizontal.
Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.
Greetings.
Danna.
The urban legend of the car thief is an example of what theme?
Societal Change
A Common Fear
A Cautionary Tale
A Prank
Answers
The urban legend of the car thief is an example of A Cautionary Tale.
What is the Cautionary Tale?A cautionary tale makes reference to a given tale aimed at the warning the person of some type of danger, which is generally used to alert about a given behavior and may be very useful to modify a behavior pattern in children.
Therefore, with this data, we can see that A cautionary tale is based on warning and can help to modify certain behavior in c children depending on the ability to create conscious.
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physicist at a fireworks display times the lag between seeing an explosion and hearing its sound, and finds it to be 0.900 s.
(a) How far away is the explosion if air temperature is 21.0°C, neglecting the time taken for light to reach the physicist?
m
(b) How much further away would the explosion be calculated to be if the speed of light is taken into account? m
Answers
(a) The distance to the explosion, neglecting the time taken for light to reach the physicist, is approximately 309.96 meters.
(b) Considering the speed of light, the distance to the explosion remains the same at approximately 309.96 meters.
How to determine the distance to the explosion without considering the time taken for light to reach the physicist?To determine the distance to the explosion without considering the time taken for light to reach the physicist, we can use the speed of sound in air. The speed of sound in air depends on the temperature, and it can be approximated using the formula:
v = 331.4 + 0.6 * T
where v is the speed of sound in meters per second and T is the temperature in degrees Celsius.
Given that the temperature is 21.0°C, we can calculate the speed of sound:
v = 331.4 + 0.6 * 21.0 = 344.4 m/s
To find the distance, we can use the formula:
distance = speed * time
distance = 344.4 m/s * 0.900 s ≈ 309.96 m
Therefore, neglecting the time taken for light to reach the physicist, the explosion is approximately 309.96 meters away.
How to calculate the distance to the explosion taking into account the speed of light?To calculate the distance considering the time taken for light to reach the physicist, we need to account for the speed of light. The speed of light in a vacuum is approximately 3.00 × 10⁸ m/s. Since the time taken for light to reach the physicist is negligible compared to 0.900 s, the distance calculated in part (a) remains the same.
Therefore, taking into account the speed of light, the explosion is still approximately 309.96 meters away.
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How is sea salt harvested from the ocean? Name and explain the process.
Answers
Answer:
Sea salt is harvested by evaporating the ocean water away and generally has little to zero processing involved. Major sea salt manufacturers pump sea water into huge shallow “ponds” and allow the sun to evaporate the water... Before harvesting seawater, be sure the body of water you are using is not polluted.
Explanation:
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A dog sleigh driver prepared for her race. Her sleigh was loaded with equipment, but on snow and ice, the dogs moved the heavy sled. Each dog pulled with a force of 600 N.
During the race, she came to an area of grass and dirt instead snow. The sled slowed to a stop.
The driver said, "There must be something wrong with one of the dogs. One of them is pulling with a force of less than 600 N.
How would you respond to the dog sled driver?
Answers
The dog slowed down and stop because of the high magnitude of friction opposing the motion due to the nature of the grass and dirt.
What is Friction ?Friction is a force that opposes motion. It depends on the nature of the surface in contact with the moving object.
Given that a dog sleigh driver prepared for her race. Her sleigh was loaded with equipment, but on snow and ice, the dogs moved the heavy sled with a force of 600 N each. On the snow and ice, the opposing force known as friction is small.
During the race, she came to an area of grass and dirt instead snow. The sled slowed to a stop because of the high magnitude of the opposing force or frictional force due to the nature of the grass and dirt.
Therefore, there is nothing wrong with one of the dogs. One of them is pulling with a net force of less than 600 N because of drastic increase in frictional force due to the nature of grass and dirt.
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Why Does Elasticity Matter?
Often, a lot of what is covered in courses has little application in the so-called "real world". In this discussion board, you need to post an entry to the discussion board stating why elasticity actually does matter in the everyday lives of businesses and consumers, using an example of a good or service as part of your explanation.
Part I
Using an example of a good or service, you will state why elasticity is applicable in the everyday lives of businesses and consumers. Please be clear in your explanation
Answers
Elasticity is of significant importance in the everyday lives of businesses and consumers as it helps them understand and respond to changes in prices and demand for goods or services. By considering elasticity, businesses can make informed decisions regarding pricing strategies, production levels, and resource allocation. Consumers, on the other hand, can assess the impact of price changes on their purchasing decisions and adjust their consumption patterns accordingly.
Elasticity, specifically price elasticity of demand, measures the responsiveness of consumer demand to changes in price. It indicates the percentage change in quantity demanded resulting from a one percent change in price. Understanding price elasticity allows businesses to determine how sensitive consumers are to changes in price and adjust their pricing strategies accordingly.
For example, let's consider the market for gasoline. Gasoline is a highly price-sensitive good, meaning that changes in its price have a significant impact on consumer demand. If the price of gasoline increases, consumers may reduce their consumption and seek alternatives such as carpooling or using public transportation. In this scenario, businesses need to consider the price elasticity of gasoline to predict and respond to changes in consumer behavior. They might lower prices to stimulate demand or introduce more fuel-efficient options to cater to price-conscious consumers.
In conclusion, elasticity matters because it provides valuable insights into the dynamics of supply and demand, enabling businesses and consumers to make informed decisions in response to price changes. By understanding elasticity, businesses can adapt their strategies to maintain competitiveness, while consumers can optimize their purchasing choices based on price sensitivity.
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A 0.48-kg ball is thrown with a speed of 8.8 m/s at an upward angle of 36 degrees.
(a) What is its speed at its highest point?
(b) How high does it go? (Use conversation of energy.)
Answers
Answer: (a) The velocity of the ball at its highest point is 10.12 m/s
(b) The height that the ball goes is 1.13 m.
Mass of ball, m = 0.48 kg
Initial velocity, u = 8.8 m/s
Initial angle, θ = 36°
Using the principle of conservation of energy, the final velocity at the highest point can be found. The potential energy of the ball is converted into kinetic energy at its highest point, where the ball will stop momentarily. Then, we know that the total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴
mgh + 1/2mu² = mgh(max) where h(max) is the maximum height the ball attains. At this point, the kinetic energy will be zero. Therefore,0.5mv² + mgh = mgh(max). Since the kinetic energy of the ball at the top is zero, the total energy at the top of the projectile’s trajectory is the potential energy at the start of the trajectory, which is mgh.∴ v = √(2gh).
This is the velocity at the maximum height.
(a) Speed at its highest point:
Initial velocity of ball, u = 8.8 m/s
Angle made with horizontal, θ = 36°
The vertical component of velocity, v_y = usinθv_y = 8.8 sin 36°v_y = 5.0 m/s
Now using the formula, v = √(u² + v_y²)v = √(8.8² + 5.0²)v = √(77.44 + 25)v = √102.44v = 10.12 m/s
Therefore, the velocity of the ball at its highest point is 10.12 m/s
(b) How high does it go: lets calculate the potential energy at the initial position. Potential energy, Ep = mgh
Ep = 0.48 * 9.8 * 0Ep = 0 J. The total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴ mgh + 1/2mu² = mgh(max). Substituting the values,0.48*9.8*h(max) + 0.5*0.48*8.8² = 0.48*9.8*0hmax = (0.5*0.48*8.8²)/(0.48*9.8)h(max) = 1.13 m.
Therefore, the height that the ball goes is 1.13 m.
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PLS HELP ME Which object has the greatest kinetic energy?
A: a truck with a mass of 3,500 kg moving at 30 m/s
B: a person with a mass of 73 kg running 6 m/s
C: a locomotive engine with a mass of 205,000 kg moving 5 m/s
D: a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
Answers
A locomotive engine with a mad of 205000kg moving with 5m/s
Explanation:
\(from \: the \: options \: substitute \: the \: formulars \: for \: kinetic \: energy \\ for \: opton \: a \: ke = \frac{1}{2} mv {}^{2} = \frac{1}{2} \times 3500 \times 30 {}^{2} = 1575000 \\ for \: option \: b \: ke = \frac{1}{2} mv {}^{2} = \frac{1}{2} \times 73 \times 6 {}^{2} = 1314 \\ for \: option \: \: c = \frac{1}{2}mv {}^{2} = \frac{1}{2} \times 205000 \times 5 {}^{2} = 2562500 \\ for \: option \: d \: = \frac{1}{2}mv {}^{2} = \frac{1}{2} \times 0.5 \times(46.9) {}^{2} = 549.9025 \\ from \: the \: analysis \: above \: the \: options \: that \: has \: the \: highest \: kinetic \: energy \: is \: a \: locomotive \: engine \: with \: a \: mass \: of \: 205000kg \: moving \: with \: a \: velocity \: of \: 5 \frac{m}{s} \)
according to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (cbr) the dark energy makes?
Answers
According to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (CBR), it has been determined that dark energy makes up approximately 68% of the total energy density of the universe.
This means that dark energy is the dominant force driving the acceleration of the expansion of the universe.
The CBR is the afterglow of the Big Bang, and by analyzing its properties, scientists can learn more about the structure and evolution of the universe. The Planck satellite, launched in 2009, has been instrumental in providing high-precision measurements of the CBR and contributing to our understanding of dark energy.
Despite being the dominant force in the universe, dark energy remains a mystery. Its nature and properties are still largely unknown, but it is thought to be a property of space itself rather than a type of matter or energy. Ongoing research and observations will continue to shed light on this elusive phenomenon and deepen our understanding of the universe as a whole.
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therm is a unit that is generally used to measure the energy contained in natural gas. true/false
Answers
Answer: True
Explanation: got it right
Refer to Figure 22-15 to answer the following
questions.
a. What should the ammeter reading be?
b. What should the voltmeter reading be?
c. How much power is delivered to the resistor?
d. How much energy is delivered to the resistor
per hour?
Answers
a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.
b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.
c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.
d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.
What is an ammeter?
An ammeter is a measuring instrument used to measure electric current flowing through a circuit. It is typically connected in series with the circuit so that all the current flowing in the circuit passes through the ammeter. Ammeters can be analog or digital, and they are designed to measure different ranges of current. They are an essential tool for diagnosing and troubleshooting electrical problems, and they are commonly used in industrial, commercial, and residential applications.
What is a voltmeter?
A voltmeter is a measuring instrument used to measure the electric potential difference (voltage) between two points in an electrical circuit. It is typically connected in parallel with the circuit component or circuit section whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter displays the measured value in volts, which can help to determine the performance or condition of the circuit.
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a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.
b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.
c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.
d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.
What is an ammeter?An ammeter is a measuring device used to determine the amount of electric current passing through a circuit. It is usually wired in series with the circuit so that all current passing through it goes through the ammeter. Ammeters can be analogue or digital, and they are used to detect various current levels. They are an indispensable instrument for diagnosing and troubleshooting electrical issues, and they are widely used in industrial, business, and domestic settings.
A voltmeter is a measuring device used to determine the difference in electric potential (voltage) between two locations in an electrical circuit. It is usually linked in parallel with the circuit component or portion whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter shows the measured value in volts, which can aid in determining the circuit's performance or state.
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find the moments m x , m y and the mass m , of the triangular lamina defined by the vertices (0,0), (0,3) and (6,3). the density function is rho ( x , y )
Answers
To find the moments and mass of the triangular lamina, we first need to determine the density function rho(x, y). Once we have the density function, we can calculate the moments mx and my and the mass m.
Given that the vertices of the triangular lamina are (0,0), (0,3), and (6,3), we can see that the base of the triangle is 6 units long, and its height is 3 units. Therefore, the area of the triangular lamina is (1/2) * base * height = (1/2) * 6 * 3
= 9 square units.
To find the density function rho(x, y), we need more information. The density function represents how the mass is distributed over the lamina. Without this information, we cannot proceed with finding the moments and mass accurately.
To find the moments mx and my, we need to integrate the product of the density function rho(x, y) and the coordinates x and y, respectively, over the triangular lamina. The moments mx and my can be calculated using the following formulas:
mx = ∫∫ x * rho(x, y) dA
my = ∫∫ y * rho(x, y) dA
where dA represents the infinitesimal area element.
To find the mass m, we need to integrate the density function rho(x, y) over the triangular lamina. The mass m can be calculated using the following formula:
m = ∫∫ rho(x, y) dA
However, since we don't have the density function rho(x, y) given, we cannot determine the moments mx and my or the mass m accurately.
In order to find the moments mx and my and the mass m of the triangular lamina, we need to know the density function rho(x, y). Without this information, we cannot proceed with the calculations. It is important to have all the necessary data and information to accurately solve problems involving moments and mass.
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What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per second, and the angle ofΘis 41.8 degrees?
Answers
Take into account that the vertical final velocity of the projectile is given by:
\(v^2_y=v^2_{oy}-2gy\)Now, consider that at the peak of the trajectory, the vertical final velocity is zero. Moreover:
\(v^2_{oy}=v^2_o\sin ^2\theta\)Then, by solving for y into the equation for vy^2, you obtain:
\(\begin{gathered} o=v^2_o\sin ^2\theta-2gy \\ y=\frac{v^2_o\sin \theta}{2g} \end{gathered}\)where g = 9.8m/s^2 is the gravitational acceleration constant.
By using the given values for the angle and vo you obtain for the height of the peak y:
\(y=\frac{(42.2\frac{m}{s})(\sin 41.8)^2}{2(9.8\frac{m}{s^2})}\approx40.36m\)Hence, the height of the peak of the projectil trajectory is approximately 40.36 m
If we increase the driving frequency in a circuit with a purely capacitive load, do (a) amplitude Vc and (b) amplitude I increase, decrease, or remain the same? If, instead, the circuit has a purely inductive load, do (c) amplitude V, and (d) amplitude 1, increase, decrease, or remain the same?
Answers
The amplitude of the current (I), however, will decrease, as the higher frequency results in a larger inductive reactance, leading to a decrease in current.
In a circuit with a purely capacitive load, if the driving frequency is increased, the amplitude of the voltage across the capacitor (Vc) will decrease.
This is because as the frequency increases, the capacitor has less time to charge and discharge, leading to a decrease in the voltage across it. The amplitude of the current (I) will increase, however, as the higher frequency results in a smaller capacitive reactance, leading to an increase in current.
In a circuit with a purely inductive load, if the driving frequency is increased, the amplitude of the voltage across the inductor (V) will increase.
This is because as the frequency increases, the inductive reactance increases, leading to an increase in voltage. The amplitude of the current (I), however, will decrease, as the higher frequency results in a larger inductive reactance, leading to a decrease in current.
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State the Doppler Effect in words.
Answers
Answer:
the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the source of the wave. When the observer is moving towards the source, the waves are compressed and the frequency increases (called a blue shift). Conversely, when the observer is moving away from the source, the waves are stretched and the frequency decreases (called a red shift). This phenomenon can be observed in sound waves, light waves, and other types of waves.
Answer: an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move toward (or away from) each other
Explanation:
Human pathogens are:
a. psychrophiles
b. mesophiles
c. hypermesophiles
d. thermophiles
e. hyperthermophiles
Answers
Human pathogens are typically mesophiles, which means they thrive in temperatures ranging from 20-45°C, the temperature range of the human body.
However, some human pathogens are also thermophiles, which means they prefer temperatures between 45-80°C, such as those found in hot springs. Hyperthermophiles, which thrive in temperatures above 80°C, are less commonly associated with human pathogens. Psychrophiles, which thrive in cold temperatures, and hypermesophiles, which thrive in even higher temperatures than mesophiles, are not commonly associated with human pathogens.
Human pathogens are mesophiles. Mesophiles are microorganisms that thrive at moderate temperatures, typically between 20°C and 45°C (68°F to 113°F). Most human pathogens fall into this category because the human body's average temperature is 37°C (98.6°F), creating an optimal environment for these microorganisms to grow and reproduce. In contrast, psychrophiles prefer cold environments, thermophiles prefer high temperatures, and hyperthermophiles thrive at extremely high temperatures. Hypermesophiles is not a recognized term in microbiology.
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ANSWER QUICK PLS
1. What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.0001 N?
Answers
Answer:
what was the answer? Was it 0.98?
Answer:
it's 98
Explanation:
Which of the following statements correctly summarizes the events in the early universe according to the Big Bang theory?A. The Big Bang began with the initiation of what we call inflation, which gradually slowed to the current expansion rate of the universe. Forces came to exist for a different reason, having to do with quantum fluctuations in the space-time continuum. Particles came to exist as a result of cracks made when forces froze. Once there were particles, gravity brought them together to make stars, and the stars then turned the particles into hydrogen, helium, and other elements.B. An episode of what we call inflation initiated the event of the Big Bang. Once the Big Bang got underway, particles and forces began to appear one by one. The forces produced protons, which fused to make hydrogen and helium until the universe was about 380,000 years old. Then gravity began to act, turning the hydrogen and helium into galaxies.C. Forces and various subatomic particles began to appear during the first second after the Big Bang. For reasons not understood, the particles were all made of ordinary matter and none were made of antimatter, thus explaining why we live in a universe made of matter. The particles underwent some fusion for the first 380,000 years after the Big Bang, at which time the first stars were born.D. The universe began with the forces unified. During the first fraction of a second, the forces separated and there was a brief but important episode of inflation. Subatomic particles of both matter and antimatter then began to appear from the energy present in the universe. Most of the particles annihilated to make photons, but some became protons, neutrons, electrons, and neutrinos. The protons and neutrons underwent some fusion during the first three minutes, thereby determining the basic chemical composition of the universe.
Answers
The correct statement summarizing the events in the early universe according to the Big Bang theory is option D.
After the forces of the cosmos came together, there was a time of inflation. Then subatomic matter and antimatter particles appeared, the majority of which annihilated to produce photons. Protons, neutrons, electrons, and neutrinos were among the particles that did not decay, though. During the first three minutes, protons and neutrons fused, revealing the universe's basic chemical make-up.
All of the fundamental forces of nature were combined in the early moments of the Big Bang. But the forces split into various interactions as the cosmos grew and contracted. This trend was accompanied by inflation, a rapid expansion. After inflation, a hot, thick soup of energy flooded the entire cosmos.
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20
All electromagnetic waves travel at the speed of light (300,000,000 m/s). However, even at this speed, if a radio
transmission is sent to astronauts on the Moon, there is a delay between the time that the message was sent
and the time that the astronauts receive it. Why?
0/1
Radio waves travel at a slower speed through a vacuum than they do through air.
The Moon is very far away from the Earth and it takes time for radio messages to travel.
Ο Ο Ο Ο
Asteroids and other space debris interfere with radio transmissions from Earth.
Radio waves are delayed as they pass through Earth's atmosphere.
Answers
Answer:
t = S / V = 3.8E8 / 3E8 = 1.3 sec
It takes over 1 second for a radio signal to travel between the earth and the moon.
A unit is an amount used to measure something True or false
Answers
I do not know
hi I thinks the answer is Tralse
Action-reaction forces do not cancel each other because the action force is always greater than the reaction force
True
False
Answers
calculate how far the worker must move away in meters from the source to reduce the equivalent dose rate by a factor of 4? [2.5 pts]
Answers
The worker must move approximately 2.0 meters away from the source to reduce the equivalent dose rate by a factor of 4.
The relationship between distance and radiation intensity follows the inverse square law, which states that the intensity of radiation is inversely proportional to the square of the distance from the source. Mathematically, this can be expressed as I1/I2 = (D2/D1)^2, where I1 and I2 are the intensities of radiation at distances D1 and D2 from the source, respectively.To reduce the equivalent dose rate by a factor of 4, we need to find the distance D2 that satisfies the equation I1/I2 = 4. Since the intensity of radiation is inversely proportional to the square of the distance, we can rewrite this equation as (D2/D1)^2 = 4, which simplifies to D2/D1 = 2.Solving for D2, we get D2 = 2 x D1. If the worker is initially located at a distance of D1 = 1.0 meter from the source, then they must move 2.0 meters away to reduce the equivalent dose rate by a factor of 4.Therefore, the worker must move approximately 2.0 meters away from the source to reduce the equivalent dose rate by a factor of 4.For such more questions on worker
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Please help me with this psychics problem, forever thankful!
Place the following in order of increasing frequency (low to high).
Radio Waves
X-Rays, (1018 Hz to 1022 Hz), (1 nm to 10-3 nm)
:
Ultraviolet, (7 x 1014 Hz to 1018 Hz), (103 nm to 1 nm)
Visible Light, (4 x 1014 Hz to 7 x 1014 Hz) (700 nm to 380 nm)
Infrared, (1010 Hz to 4 x 1014 Hz), (106 nm to 103 nm)
Microwaves, (106 Hz to 1010 Hz), (1 m to 106 nm)
Gamma Rays
Answers
Answer:
I don't know how it works, but I found this on the internet. image does not belong to me.
hope it helps!
Answer:
X-RAY
Explanation:
I took the test on study island
What mechanisms do astronomers believe is responsible for making the sun's outer atmosphere?
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The Sun's magnetic field interacts with the charged particles that make up the atmosphere this mechanism is believed by astronomers.
Astronomers measure the Sun's absorption line spectrum. The components that are present in the outer layers are revealed by these absorption lines. Analyzing the solar spectrum (shown) can provide information about the sun's composition. Specific colors are absorbed by atoms on the surface of the sun, leaving dark spectral lines in the measured spectrum. The power of each line reveals an abundance of the elements.
A magnetograph, a device for measuring the strength and direction of magnetic fields, can also be used to measure the footpoints on the photosphere, or surface, of these magnetic loops. The negatively charged electrons and positively charged ions that make up the plasma of the Sun move about a lot due to the high temperatures of the Sun. Multiple intricate, twisted magnetic fields are produced by the moving plasma. A magnetic field is produced by the solar wind, which is composed of the incredibly hot plasma that the Sun emits.
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"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
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Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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. Shown below is a roller coaster. At points A, B and C find the potential energ ki net tic energy and speed of a passenger whose mass is 60 kg h 35m Figure 1: Roller Coaster otal PE " KE- KE
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At point A, the potential energy is 20,580 J, the kinetic energy and speed are both zero. At point B, the kinetic energy is 20,580 J, and the speed is 26.2 m/s. At point C, the kinetic energy is 14,580 J, and the speed is 11.9 m/s.
At point A, the potential energy of the passenger is highest, while the kinetic energy and speed are both zero since the passenger is at rest. Therefore, at point A, the potential energy (PE) is:PE = mghPE = 60 kg x 9.8 m/s^2 x 35 mPE = 20,580 JAt point B, the roller coaster has reached its maximum speed and the potential energy is at its lowest. Therefore, at point B, the kinetic energy (KE) is equal to the initial potential energy at point A:KE = PE at AKE = 20,580 JThe total kinetic energy and speed can be found using the conservation of energy equation, assuming negligible friction and air resistance:KE at B = PE at A1/2 mv^2 = mghv^2 = 2ghv = sqrt(2gh)v = sqrt(2 x 9.8 m/s^2 x 35 m)v = 26.2 m/sAt point C, the height of the roller coaster track is lower than at point B, therefore, the potential energy is less than the kinetic energy. The kinetic energy can be found using the conservation of energy equation:KE at C = KE at B - PE at CKE at C = 20,580 J - (60 kg x 9.8 m/s^2 x 10 m)KE at C = 14,580 JThe total kinetic energy and speed at point C can be found using the equation:KE at C = 1/2 mv^2v = sqrt((2 x KE at C) / m)v = sqrt((2 x 14,580 J) / 60 kg)v = 11.9 m/sTherefore, at point A, the potential energy is 20,580 J, the kinetic energy and speed are both zero. At point B, the kinetic energy is 20,580 J, and the speed is 26.2 m/s. At point C, the kinetic energy is 14,580 J, and the speed is 11.9 m/s.For more such question on potential energy
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