Name two types of mechanical weathering in NewBedford

Answer:

8 M/S

Explanation:

This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.

Differentiation

Derivative Rule [Basic Power Rule]:

\(\displaystyle\begin{aligned}f(x) & = cx^n \\f'(x) & = c \cdot nx^{n - 1} \\\end{aligned}\)

Derivative Rule [Chain Rule]:
\(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)

Let's define what the problem gives us:

We know from our trigonometric derivatives that the derivative of \(\displaystyle \sin x\) is equal to \(\displaystyle \cos x\). However, since we have some arbitrary constant \(\displaystyle a\) multiplying \(\displaystyle x\) inside our \(\displaystyle \sin x\) function, we will have to apply the derivative rule of Chain Rule:

\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \boxed{ \cos (ax) (ax)' } \\\end{aligned}\)

To further simply the derivative, we now apply the derivative rule of Basic Power Rule and simplify:

\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \cos (ax) (ax)' \\& = (ax)' \cos ax \\& = 1 \cdot ax^{1-1} \cos ax \\& = ax^0 \cos ax \\& = \boxed{ a \cos ax } \\\end{aligned}\)

∴ the derivative of the function \(\displaystyle y = \sin ax\) is equal to \(\displaystyle \boxed{ y' = a \cos ax }\).

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Topic: Calculus

Unit: Differentiation

The arcsine of 1 is 90 degrees, the critical angle is 90 degrees.the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox.

To determine the minimum depth of the Batbox below the surface of the water for Batman to remain hidden from the Joker, we need to consider the principle of total internal reflection. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, it can undergo total internal reflection if the angle of incidence exceeds the critical angle. In this case, the light traveling from water (refractive index nw = 1.333) to the Batplastic (refractive index np = 1.333) can undergo total internal reflection at the interface between the two.

To calculate the minimum depth, we need to find the critical angle. The critical angle can be determined using the formula:

Critical angle = arcsin(np/nw)

Given:

Refractive index of water, nw = 1.333

Refractive index of Batplastic, np = 1.333

Calculating the critical angle:

Critical angle = arcsin(1.333/1.333)

Critical angle = arcsin(1)

Since the arcsine of 1 is 90 degrees, the critical angle is 90 degrees.

To ensure that Batman remains hidden, the Batbox should be placed at a depth below the surface of the water such that the light undergoes total internal reflection. In this case, the minimum depth is determined by the height of the Batbox. Therefore, the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox. However, the specific height of the Batbox is not provided in the question, so it cannot be determined without additional information.

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Answer:

Newton's laws of motion and gravity explained Earth's annual journey around the Sun. Earth would move straight forward through the universe, but the Sun exerts a constant pull on our planet. This force bends Earth's path toward the Sun, pulling the planet into an elliptical (almost circular) orbit.

The centripetal acceleration of a point on the edge of the flywheel is 3.40 x 10^3 m/s^2.

What is centripetal acceleration?

Centripetal acceleration is the acceleration of an object moving in a circular path. It is directed towards the center of the circle and is necessary to keep the object moving in a circular path.

To calculate the centripetal acceleration of a point on the edge of the flywheel, we can use the formula:

a = (v^2) / r

where a is the centripetal acceleration, v is the velocity of the point, and r is the radius of the flywheel.

First, we need to calculate the velocity of the point. We know that the flywheel is spinning at 1,953 RPM (revolutions per minute), so we can convert this to revolutions per second (RPS) by dividing by 60.

v = 1,953 RPM / 60 sec/min = 32.55 RPS

Next, we need to convert the diameter of the flywheel to radius by dividing by 2.

r = 30.7 cm / 2 = 15.35 cm = 0.1535 m

Now we can substitute these values into the formula to calculate the centripetal acceleration.

a = (v^2) / r = (32.55 RPS)^2 / 0.1535 m = 3.40 x 10^3 m/s^2

So the centripetal acceleration of a point on the edge of the flywheel is 3.40 x 10^3 m/s^2.

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Answer:

a. Valid

b. Invalid

c. Invalid

d. Invalid

e. Valid

f.  Valid

g. Invalid

Explanation:

a.

Since, it follows all the four rules,

Therefore, this number is Valid

b.

It uses upper case E, instead of lower case e.

Therefore, it is Invalid

c.

It violates third rule for including unit.

Therefore, it is Invalid

d.

It violates the first rule. As, there is a space between 6 and e. While in the example given in question, there is no gap.

Therefore, it is Invalid

e.

Since, it follows all the four rules,

Therefore, this number is Valid

f.

Since, it follows all the four rules,

Therefore, this number is Valid

g.

It violates third rule for including unit.

Therefore, it is Invalid

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The velocity of Jill is 0.02 miles per second due south, the correct option is b.

The total displacement covered by any object per unit of time is known as velocity.

the mathematical expression for velocity is given by

\(Velocity = \dfrac{Displacement }{Time }\)

1 hour = 3600 seconds

4 hours = 4*3600 seconds

             = 14400 seconds

Total displacement covered by the Jill = 300 miles

Total time taken by Jill =  14400 seconds

\(Velocity =\dfrac{300 miles }{14400seconds}\)

The velocity of Jill is 0.02 miles per second due south

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Answer: 10%

Explanation:

n this case, if the earth' mass goes up by 10%, then the force of gravity on you, or your weight, will increase by the same amount, that is 10%

Answer: please find the answer in the explanation.

Explanation:

Harmonic can be experienced by any body that repeats itself. The pattern can be sinusoidal, square, tooth etc.

The fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics are:

1.) The harmonic oscillator dynamics can be sinusoidal or square wave so far the motion is periodic while the simple pendulum dynamics is always sinusoidal.

2.) In simple pendulum dynamics, the period of oscillation is independent of the amplitude. While the period in harmonic oscillator dynamics depends on the amplitude.

3.) Differential equation is only one method to analyze the simple pendulum dynamics where there are several methods to analyze the harmonic oscillator dynamics.

a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².

The relationship between the temperature,T and the peak wavelength, \(\lambda\) emitted by a black body is given by wien's displacement law:

\(\lambda\) = b / T

Where, b is a constant and it's value is 2.898 * 10-3 m-K

Given: T = 8400 K

So, \(\lambda\) =   (2.898 * 10-3 )/8400

\lambda = 3.45 * 10-7  

\lambda = 345 nm

Hence, the peak wavelength of the object at this temperature is 345 nanometre.

The amount of power emitted per unit area, P is given by Stefan Boltzmann law:

P =\(\sigma\)T⁴

Where,

Absolute temperature, T = 8400 K

Stefan Boltzmann constant, \(\sigma\) = 5.67 * 10-8 W/m²K⁴

So, P = 5.67 * 10-8 * (8400)⁴

P = 2.82 * 10⁸  W/m²

Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².

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If the wind bounces backward from the sail, the boat will not be set in motion as no forward force is generated. For the boat to move forward, the sail must be positioned to catch the wind and create lift in the desired direction.

If the wind bounces backward from the sail, the craft will not be set in motion. In order for a sailboat to move forward, the wind must push on the sail, creating a force that propels the boat forward through the water. When the wind hits the sail, it creates lift in a direction perpendicular to the sail's surface, which results in a forward force that propels the boat.

However, if the wind bounces backward from the sail, it does not create lift and therefore does not result in a forward force on the boat. Instead, the wind is redirected in a different direction, and the boat remains stationary. In order for the boat to move forward, the sail must be positioned to catch the wind and create lift in the desired direction, propelling the boat forward.

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Answer:

There are almost 5000 known mineral species, yet the vast majority of rocks are formed from combinations of a few common minerals, referred to as “rock-forming minerals”.

The gravitational field strength at Pluto's surface is 5.827 x 10⁹ N/kg.

The force of gravity between the object and Pluto's surface is 5.827 x 10¹³ N.

The gravitational field strength at Pluto's surface is calculated as follows;

G_E = GM/r²

where;

G_E = (6.67 x 10⁻¹¹ x 1.2 x 10²²) / (1.172 x10)²

G_E = 5.827 x 10⁹ N/kg

The force of gravity between the object and Pluto's surface is calculated as follows;

F = GMm/r²

F = (6.67 x 10⁻¹¹ x 1.2 x 10²² x 100) /(1.172 x 10)²

F = 5.827 x 10¹³ N

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Answer:

a . Long wavelengths and low frequencies

Explanation:

Low energy waves usually show long wavelengths and a low frequency.

Energy of a wave is dependent on the wavelength and frequency of such a wave.  

   The wavelength of a wave is the distance between successive crests and troughs of a wave. The frequency of a wave is the number of waves that passes through a particular point per unit of time.

  Mathematically, wave energy;

               Energy  = h x f

 where h is the planck's constant

             f is the frequency

 Also,

              Energy  = \(\frac{h x speed of light}{wavelength}\)

 A high energy wave will have a high frequency and a long wavelength.

 A low energy wave have a low frequency and a long wavelength

Answer:

the speed of light in air is about 299,000,000 and 3×10⁸ m/s

Answer:

Both are subject to a persons interpretation

Explanation:

We hear people describe this when somebody is making an irresistible sound. usually people say the baby has a pitch scream.

(a) The work done by the frictional force is -33.1 J.

(b) The work done by the gravitational force is 175.58 J

The work done by frictional force is calculated as follows;

W = -μmgsinθ x L

W = -μmgsinθ  x L

where;

W = -0.18 x (12.7 + 14)9.8 x sin(17) x 2.4

W = -33.1 J

W = mgh

W = mgcosθ  x h

W = mgcosθ  x Lsinθ

W = (26.7)(9.8)cos(17) x 2.4 x sin(17)

W = 175.58 J

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Answer:

Total distance covered (scalar quantity) = 23 km

Displacement (vector quantity) = 3 km north from the original starting point

Explanation:

Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km

On the other hand, his displacement was 3 km north from where he started.

Answer: Please see the attached image.

Explanation:

A diagram of the Lewis dot structure depicts the valence electrons of the atoms of a molecule. It makes use of dots to represent lone electron pairs and lines to represent atomic bonds.

Valence Electrons are the s and p subshells on the periodic table. You count the total s and p subshells of the corresponding atom to find how much valence electrons it has.

The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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Answer: \(278\ Hz\)

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

\(\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m\)

Condition for destructive interference is

\(\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}\)

for second destructive interference; n=2

\(\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz\)

= 2(4+6)

= 2×10

= 20

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The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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Given data:

* The speed of the water coming out of the pipe is,

* The diameter of the left side of pipe is,

* The diameter of the right side of the pipe is,

Solution:

(a). The area of the right side of pipe is,

The radius of the right side of pipe is,

Thus, the area of the right side of pipe is,

The volume of the water coming out from the right side of the pipe is,

Where t is the time taken, v_1 is the velocity of the water, and A_1 is the area of right side of pipe,

Substituting the known values,

Thus, the volume of water flows into the atmosphere is 1.97 meter cube.

Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.

Average Velocity = Displacement / Time

Displacement = 55 km (since he rode 55 km to the east)

Time = 51 minutes

Average Velocity = 55 km / 51 min

To express the average velocity in km/min, convert the time from minutes to minutes.

1 hour = 60 minutes

Average Velocity = 55 km / 51 min × (1 hour / 60 min)

Average Velocity = 55 km / 51 min × (1/60) hour

Simplifying the expression:

Average Velocity = 1.078 km/min

Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

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