name the first artificially prepared fiber
. nylon
. rayon
. silk
. polymers​

i. The mass of air inside the tank is calculated using the ideal gas law: m₁ = (P₁V₁) / (RT₁), and m₂ = (P₂V₂) / (RT₂).

ii. The final pressure inside the tank after cooling is determined using Boyle's Law: P₁V₁ = P₂V₂.

iii. Repeat the calculations for heating from 25°C to 175°C using the given temperatures and equations to determine mass and final pressure, then compare the results.

a) Charles' Law states that at constant pressure, the volume of a gas is directly proportional to its temperature, expressed mathematically as V₁ / T₁ = V₂ / T₂. Boyle's Law states that at constant temperature, the pressure of a gas is inversely proportional to its volume, expressed as P₁V₁ = P₂V₂.

b)

i. To determine the mass of air inside the tank, we need to use the ideal gas law equation:

PV = mRT, where P is pressure, V is volume, m is mass, R is the gas constant, and T is temperature.

Step 1: Convert temperatures to Kelvin:

T₁ = 110°C + 273.15 = 383.15 K

T₂ = 55°C + 273.15 = 328.15 K

Step 2: Calculate the initial mass using the ideal gas law:

m₁ = (P₁V₁) / (RT₁)

Step 3: Calculate the final mass using the ideal gas law:

m₂ = (P₂V₂) / (RT₂)

ii. To determine the final pressure inside the tank after cooling, we can use Boyle's Law:

P₁V₁ = P₂V₂

c)

To calculate the mass and final pressure for heating from 25°C to 175°C, we follow the same steps as in part b, using the given temperatures and applying the ideal gas law and Boyle's Law.

Step 1: Convert temperatures to Kelvin:

T₁ = 25°C + 273.15 = 298.15 K

T₂ = 175°C + 273.15 = 448.15 K

Step 2: Calculate the mass using the ideal gas law:

m₁ = (P₁V₁) / (RT₁)

m₂ = (P₂V₂) / (RT₂)

Step 3: Calculate the final pressure using Boyle's Law:

P₁V₁ = P₂V₂

Finally, compare the obtained results for both cases to analyze the effect of cooling and heating on the mass and final pressure of the air inside the tank.

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Answer:

Anything below 7.0 is acidic, and anything above 7.0 is alkaline, or basic. pH scale, ranging from 0 (very acidic) to 14 (very basic/alkaline) and listing the pH values of common substances.

Explanation:

PRESS THE CROWN

The pH scale ranges from 0 to 14. A pH of 7 is neutral. A pH less than 7 is acidic. A pH greater than 7 is basic.

Explanation:

If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .

Using the ideal gas law equation:

PV = nRT

n = (PV) / (RT)

= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)

= 42.71 moles

the balanced equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl -> \(ZnCl_{2}\)  + \(H_{2}\)

1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.

The molar mass of zinc is 65.38 g/mol.

Mass of zinc = moles of zinc * molar mass of zinc

= 42.71 moles * 65.38 g/mol

= 2796.96 g

Therefore, the mass of the zinc is 2796.96 grams.

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Hydrogen sulfide is fatal at 400 ppm. Option D is correct

The fatal concentration of hydrogen sulfide can vary depending on the exposure time. Short-term exposure to concentrations of 500-1000 ppm can be lethal, while long-term exposure to concentrations as low as 10 ppm can also have harmful effects on health.

Therefore, it is important to always use proper safety precautions and equipment when working with hydrogen sulfide.

Hydrogen sulfide (H2S) is a colorless, flammable gas with a strong and unpleasant odor resembling that of rotten eggs. It is highly toxic and can be lethal in high concentrations. It is commonly found in natural gas and petroleum deposits, as well as in volcanic gases and some bacterial processes. It is also used in the production of sulfuric acid, in the chemical industry, and in mining operations. Some of the health hazards associated with exposure to hydrogen sulfide include respiratory irritation, headache, nausea, dizziness, unconsciousness, and even death.

Option D is correct

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Answer:Hydrogen

Explanation:is the most abundant element in the universe (75%by weight or 88% of all of the atoms of the universe)

Answer: Thus the yield of uranium from 2.50 kg \(U_3O_8\) is 2.12 kg

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number \((6.023\times 10^{23})\) of particles.

To calculate the number of moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}\)

moles of \(U_3O_8=\frac{2.50\times 1000g}{842g/mol}=2.97mol\)    (1kg=1000g)

As 1 mole of \(U_3O_8\) contains = 3 moles of U

2.97 mole of \(U_3O_8\) contains = \(\frac{3}{1}\times 2.97=8.91moles\) moles of U

Mass of Uranium=\(moles\times {\text {Molar mass}}=8.91mol\times 238g/mol=2120g=2.12kg\)  

 ( 1kg=1000g)

Thus the yield of uranium from 2.50 kg \(U_3O_8\) is 2.12 kg

Answer:

When atoms are excited they emit light of certain wavelengths which correspond to different colors. Each element produces a unique set of spectral lines. Since no two elements emit the same spectral lines, elements can be identified by their line spectrum.

Explanation:

Answer:

the answer is D

Explanation:

The molar mass (denoted by symbol M) of an element is the mass of one mole of the element. The abbreviation for mole is 'mol'. The molar mass has units of g/mol ('grams per mole'). The molar mass of a compound, or molecule, is the sum of all the molar masses of each individual element that makes up the compound/molecule. Molar mass can be found on a standard IUPAC Periodic Table.

Percentage composition is the percentage mass of each element in the total mass of substance.

\(\large \textsf{M($\rm C_{\,6}H_{\,12}O_{\,6}$) = $12.01\times 6+1.008\times 12+16.00\times 6$}\\\\ \large \textsf{\phantom{M($\rm C_{\,6}H_{\,12}O_{\,6}$)} = $180.156 \rm \ g/mol$}\\\\\)

\(\normalsize \textsf{Hence, percentage composition = molar mass of element $\div$ total molar mass:}\\\\\large \textsf{$\therefore \% \rm \ carbon = \frac{6\times12.01}{180.156}\times100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ carbon}\approx 40\, \%$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ hydrogen = \frac{12\times1.008}{180.156}\times100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ hydrogen}\approx 6.7\, \%$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ oxygen = \frac{6\times16.00}{180.156}\times100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ hydrogen}\approx 53.3\, \%$}\\\\\)

\(\normalsize \textsf{Now applying this technique to the other questions:}\\\\\large \textsf{M($\rm NaCl$) = $22.99 +35.45$}\\\\ \large \textsf{\phantom{M($\rm NaCl$)} = $58.44 \rm \ g/mol$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ sodium = \frac{22.99}{58.44} \times 100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ sodium}\approx 39.3\, \%$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ chlorine = \frac{35.45}{58.44} \times 100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ chlorine}\approx 60.7\, \%$}\\\\\)

\(\normalsize \textsf{And finally:}\)

\(\large \textsf{M($\rm Fe_{\,2}(SO_4)_3$) = $55.85\times2+(32.07+16.00\times4)\times3$}\\\\ \large \textsf{\phantom{M($\rm Fe_{\,2}(SO_4)_3$)} = $399.91 \rm \ g/mol$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ iron = \frac{2\times55.85}{399.91} \times 100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ iron}\approx 27.9\, \%$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ sulfur = \frac{32.07\times 3}{399.91} \times 100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ sulfur}\approx 24.1\, \%$}\\\\\)

\(\large \textsf{$\therefore \% \rm \ oxygen = \frac{4\times16.00\times3}{399.91} \times 100$}\\\\\large \textsf{$\phantom{\therefore \% \rm \ oxygen}\approx 48.0\, \%$}\\\\\)

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it is thinner, denser, younger, and of different chemical composition.

It's the solid rock we live on. It is either continental or oceanic. The Continental crust is typically thirty to fifty km thick while the oceanic crust is only five to ten km thick. The oceanic crust is densely subduable, and constantly being destroyed and replaced at plate boundaries.

Earth has three layers crust, mantle, and core. The crust is made up of solid rocks and minerals. Beneath the crust is the mantle, also mostly solid rocks and minerals, but broken by malleable regions of semi-solid magma. At the center of the Earth is a hot, dense metallic core. The Continental crust is typically forty km twenty-five miles thick while the oceanic crust is much thinner, averaging about six km four miles thick.

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The largest pKa value for a triprotic acid H₃A would be pKa₁. Option 3 is correct.

The pKa values of a triprotic acid H₃A represent the dissociation constants for each successive ionization step, as H₃A loses one hydrogen ion to become H₂A⁻, then loses a second hydrogen ion to become HA₂⁻, and finally loses a third hydrogen ion to become A₃⁻.

In general, the pKa values of a triprotic acid decrease with each successive ionization step, indicating that it becomes progressively easier to remove each additional hydrogen ion. Therefore, the largest pKa value for a triprotic acid H₃A would usually be pKa1, which corresponds to the ionization of the first hydrogen ion.

This is because the first hydrogen ion is typically the most strongly held by the molecule, and requires the greatest amount of energy to remove. As a result, the dissociation of the first hydrogen ion usually occurs at the highest pH, and therefore has the largest pKa value among the three ionization steps.

Hence, 3. pKa₁ is the correct option.

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Answer: 2KNO3 + H2CO3 >>> K2CO3 + 2HNO3

Explanation:

Answer:

balancing of charges of both sides

Answer:

A

Explanation:

A...............................

Answer:

because metal A is not suitable for electric connection and metal B is suitable

A metallic wire is a cylindrical and flexible wire that carries electricity. Metal A wire gets hot as it is not suitable to conduct electricity.  

A conductor is a substance that can carry or pass the electricity and heat through it. The thickness and the length of the wire play a role in resistivity.

The metallic wire with good conductivity passes the electricity easily through it, while bad conductivity results in the release of heat through the wires making them lose energy.

Therefore, metal A wire gets hot.

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We can see that 0.00184 moles of \(H_2SO_4\) would be needed when the battery produces 0.00092 moles of \(H_2SO_5\)

We first of all discuss the stoichiometry of the reaction between \(H_2SO_5\)and \(H_2SO_4\).

We then write down the balanced equation for the reaction:

\(H_2SO_5\) + \(H_2SO_4\) -> \(2 H_2SO_4\)

We see that in  1 mole of  \(H_2SO_5\), we obtain 2 moles of \(H_2SO_4\).

Number of moles of \(H_2SO_4\) = 2 × Number of moles of \(H_2SO_4\)

Number of moles of \(H_2SO_4\) = 2 × 0.00092 moles

Number of moles of \(H_2SO_4\) = 0.00184 moles

In conclusion, we would need  0.00184 moles of\(H_2SO_4\) for  the battery to produce 0.00092 moles of\(H_2SO_5\)

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Answer:

can be replaced in a short amount of time

Explanation:

done

Answer:

A climate change

Explanation:

the surrounding area would be effected in all ways imaginable, such as change in air, soil, water, plants, animals. and if you eat those said animals those harmful things can transfur into you

At 25°C, the species with the highest entropy is E) CO(g), because it has the most energetically accessible microstates due to its small size and low molecular weight.

The entropy of a substance is related to the number of energetically accessible microstates for the system at a given temperature. Generally, substances with more atoms or molecules and more degrees of freedom have higher entropy.

So, we can compare the number of particles and the complexity of the molecular structure of each species to determine which has the highest entropy.

The other substances are in a more ordered state, which means they have a lower entropy.

Here's a brief explanation of the entropy of each species:

A) Ni(s) - The solid metal has a low entropy because its atoms are in a highly ordered and closely packed crystalline lattice.

B) H₂O(l) - The liquid water has a higher entropy than Ni(s) because the molecules are more disordered and have more freedom of movement. However, it is still less entropic than the other species due to its lower number of particles.

C) CH₃OH(l) - Like water, liquid methanol has a higher entropy than a solid metal due to the increased molecular disorder and freedom of motion. However, it has a lower entropy than CO(g) because it is a larger molecule with more internal degrees of freedom.

D) MgCO₃(s) - The solid carbonate has a lower entropy than liquid methanol because the molecules are more ordered and have less freedom of motion due to the strong bonding between the ions.

E) CO(g) - The gas has the highest entropy because it has the most energetically accessible microstates due to its small size and low molecular weight.

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The temperature change obtained by Al is accurate

From the question, we were told that the thermometer is faulty, given a reading that is 2.0 °C too high.

Al obtained a temperature change of 11.4 °C.

This value (11.4 °C.) is consider accurate because twhen we subtract 2 from both the initial and final temperature, the change in temperature obtained will still be the same. This is illustrated below:

ΔT = T₂ - T₁

ΔT = 54.7 - 43.3

ΔT = 11.4°C

Thus, we can see that the result obtained is still 11.4°C. Therefore, the temperature change obtained by Al is accurate

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The cell potential (Ecell) for this electrochemical cell at 240K is 1.499 V.

The cell potential (Ecell) for an electrochemical cell is the measure of the potential difference between the anode and cathode of the cell. It is determined by the standard reduction potentials of the half-reactions occurring at each electrode and the concentrations of the reactants and products in the cell.
In the given electrochemical cell, the half-reaction occurring at the anode is Au(s) → Au3+(0.19M) + 3e-, and the half-reaction occurring at the cathode is Au3+(1.9M) + 3e- → Au(s). The standard reduction potential for the Au3+/Au half-reaction at standard conditions (298K and 1 atm) is 1.498 V.
To calculate the cell potential at 240K, we can use the Nernst equation:
Ecell = E°cell - (RT/nF)ln(Q)
Where E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the cell reaction, F is Faraday's constant, and Q is the reaction quotient.
Substituting the given values and solving for Ecell, we get:
Ecell = 1.498 V - (0.00831 J/K/mol)(3/6.022 x 10^23)(ln[(0.19M)/(1.9M)])
Ecell = 1.498 V - (0.00831 J/K/mol)(3/6.022 x 10^23)(-1.902)
Ecell = 1.498 V + 0.00159 V
Ecell = 1.499 V
Therefore, the cell potential (Ecell) for this electrochemical cell at 240K is 1.499 V.

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Density is inversely proportional to volume the smaller the volume occupied by a given mass, the higher the Density of the star is 1,587,553.58 g/cm³.

Density is defined as the  quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies.

density= mass÷ volume

Density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

Replacing in the definition of density:

Density= 2×10³⁹ g÷ 1.2598×10³³ cm³

             =1,587,553.58 g/cm³

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Answer:

Oxygen

Silicon

Aluminium

Iron

Calcium

Explanation:

Oxygen=47 percent

Silicon=28 percent

Aluminium=8 percent

Iron=5 percent

Calcium=3.5 percent

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Answer:
To calculate the number of atoms of H and C in 0.160 mol of C6H14O, we need to first determine the number of moles of each element present in C6H14O.

The molecular formula of C6H14O shows that there are 6 carbon atoms, 14 hydrogen atoms, and 1 oxygen atom in each molecule of C6H14O.

The molar mass of C6H14O can be calculated as:

Molar mass of C6H14O = (6 × atomic mass of C) + (14 × atomic mass of H) + (1 × atomic mass of O)

= (6 × 12.01 g/mol) + (14 × 1.01 g/mol) + (1 × 16.00 g/mol)

= 86.18 g/mol

Therefore, 0.160 mol of C6H14O has a mass of:

Mass = molar mass × number of moles

= 86.18 g/mol × 0.160 mol

= 13.79 g

Now we can calculate the number of atoms of H and C in 0.160 mol of C6H14O.

Number of atoms of H:

Number of moles of H = 14 × 0.160 mol = 2.24 mol

Number of atoms of H = 2.24 mol × Avogadro's number

= 2.24 mol × 6.022 × 10^23/mol

= 1.35 × 10^24 atoms of H

Therefore, there are 1.35 × 10^24 atoms of hydrogen in 0.160 mol of C6H14O.

Number of atoms of C:

Number of moles of C = 6 × 0.160 mol = 0.96 mol

Number of atoms of C = 0.96 mol × Avogadro's number

= 0.96 mol × 6.022 × 10^23/mol

= 5.78 × 10^23 atoms of C

Therefore, there are 5.78 × 10^23 atoms of carbon in 0.160 mol of C6H14O.

Explanation:

Outcome B, where the spinner landed on "Prize" 75 times and on "No Prize" 15 times, simulates the claim made by the food company.

The claim made by the food company states that 1 out of 5 boxes of its breakfast cereal contains a prize. In other words, the probability of getting a prize is 1/5 or 0.2. To simulate this claim, we need the spinner to land on the "Prize" section approximately 1 out of 5 times. In Outcome B, the spinner landed on "Prize" 75 times and on "No Prize" 15 times. To determine the probability of landing on "Prize," we divide the number of times the spinner landed on "Prize" by the total number of spins:

Probability of landing on "Prize" = 75 / (75 + 15) = 75 / 90 ≈ 0.833

The probability of landing on "Prize" in Outcome B is approximately 0.833, which is greater than the desired probability of 0.2. Therefore, Outcome B does not accurately simulate the claim made by the food company. None of the given outcomes accurately simulate the claim made by the food company.

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Answer:

The atomic number is the number of protons in the nucleus of an atom . The number of protons define the identity of an element

Answer: i think 250ML

Explanation: