Name and explain the
various types of friction.

Answer:

d

Explanation:

The quantity that must be squared in the equation of gravitational force is distance d.

According to the universal gravitational law, the square of the distance between two objects is inversely proportional to the force of gravity.

The formula is given as:

  Fg  = \(\frac{G m_{1} m_{2} }{d^{2} }\)  

So d is the quantity that must be squared

The distance travelled in that month is 870.92 miles

We'll begin by calculating the circumference of the tyre. This can be obatined as follow:

C = 2πr

C = 2 × 3.14 × 13

C = 81.64 in

63360 inches = 1 mile

Therefore,

81.64 inches = (81.64 inches × 1 mile) / 63360 inches

81.64 inches = 0.00129 mile

Distance = number × circumference

Distance = 0.00129 × 675135

Distance = 870.92 miles

Thus, the distance travelled in that month is 870.92 miles

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Lower frequencies (red) move faster in a glass prism than higher frequencies.

Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.

Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.

Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.

Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

Explanation:

The force engine exert on the car can be found by using the formula

\(f = \frac{w}{d} \\ \)

w is the workdone

d is the distance

From the question we have

\(f = \frac{520}{260} = 2 \\ \)

We have the final answer as

Hope this helps you

Answer:−4.05

Explanation:

Answer:

5 m/s

Explanation:

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg

Solution :

It is given that a system is released from rest where no slack is attached to the cable and the spring is unstretched.

Mass of the cart = 30 kg

Applying the conservation of energy of the system,

Loss of the gravitational potential energy (PE) = the energy stored in the spring.

i.e., \(mg \Delta h = \frac{1}{2}kx^2\)

      \(mg (x\sin 25^\circ)=\frac{1}{2}kx^2\)

      \((30 \times 9.81) (x\sin 25^\circ)=\frac{1}{2}(125)x^2\)

       x = 1.98

Therefore the distance travelled by the 30 kg cart is 1.98 m.

The magnitude of the electric field at a point directly between the two balls is\(-2.81 \times 10^6 N/C\)

The electric field magnitude is the strength of the electric field in a certain region or at a point. It is usually measured in units of volts per meter (V/m). The electric field is a vector quantity that represents the force exerted by an electric field on a charged particle, such as an electron. It is defined by the equation E = F/q, where E is the electric field magnitude, F is the force exerted on the particle, and q is the charge of the particle.

The electric field magnitude can be calculated by measuring the force applied to a charged particle in a certain region and then dividing it by the charge of the particle.

Calculation of Electric field magnitude

The electric field equation, which states that the electric field is equal to the constant \(k (8.99 \times 10^9 Nm^2/C^2)\) times the charge \((3.80 nC + -7.40 nC = -3.60 nC)\) divided by the distance between the two balls \((32.5 cm)\) squared.

Electric field =\(kQ/r^2\)

\(r = 32.5 cm\\Q = 3.80 nC + -7.40 nC = -3.60 nC\\k = 8.99 \times 10^9 Nm^2/C^2\\Electric field = (8.99 \times 10^9 Nm^2/C^2)(-3.60 nC)/(32.5 cm)^2\\Electric field = -2.81 \times 10^6 N/C\)

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The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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The average velocity of a car driving down the highway if it’s displacement is 123 m west during a time period of 14.0 s is 8.79 m/sec.

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity. Unit of velocity is m/sec.

Given in the question a car driving down the highway  it’s displacement is 123 m west during a time period of 14.0 s then the average velocity is given as,

Average velocity = displacement / time

                            = 123/14

                            = 8.79 m/sec

The average velocity of a car driving down the highway if it’s displacement is 123 m west during a time period of 14.0 s is 8.79 m/sec.

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Answer:

i think it should be 18

Explanation:

180kg is mass of metal .

The definition of specific heat capacity

The amount of heat per unit mass needed to raise the temperature by one degree Celsius is known as the heat capacity or specific heat. The ability to distinguish between two polymeric composites using specific heat can be useful in calculating the processing temperatures and volume of heat required.

The heat capacity per unit mass of a material is known as the specific heat capacity (or simply the specific heat). The results of experiments indicate that three variables affect the amount of heat that is transferred: (1) the temperature change, (2) the mass of the system, and (3) the substance and phase of the material.

Eo is 9.9*10^6 J

ΔT is 55K

c is 1*10^3 J/kg.K

Eo = Mo. c. ΔT

Mo = Eo/ c. ΔT

Mo = 9.9*10^6/ 5 5*1*10^3

Mo = 180kg

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The centripetal acceleration of this ball is equal to 12 \(m/s^2\)

Given the following data:

Radius = \(\frac{Diameter}{2} = \frac{1.5}{2} = 0.75 \;meters\)

To find the centripetal acceleration of this ball:

The acceleration of an object along a circular track is referred to as centripetal acceleration.

Mathematically, the centripetal acceleration of an object is given by the formula:

\(A_c = \frac{V^2}{r}\)

Where:

V is the velocity of an object.

Substituting the given parameters into the formula, we have;

\(A_c = \frac{3^2}{0.75}\\\\A_c = \frac{9}{0.75}\\\\A_c = \frac{9}{0.75}\)

Centripetal acceleration = 12 \(m/s^2\)

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The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.

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Answer: Left cheek from the sun

Explanation:

Answer:

Below

Explanation:

Her POTENTIAL energy , mgh , is converted to KINETIC energy , 1/2 mv^2

mgh = 1/2 mv^2     You can divide through by 'm' to get:

gh = 1/2 v^2       solve for 'v'

v = sqrt (2gh)

   = sqrt ( 2 * 9.81 * 25.8) = 22.5 m/s

( NOTE that her mass, 64.6 kg , is irrelevant)

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

Answer:

b

Explanation:

The answer is B. Why is the ocean floor not flat and smooth like the bottom of a bathtub?

Scientists were surprised to find that the ocean floor was not a flat and featureless plain, but rather had mountains, valleys, and other geological features. This discovery raised questions about how these features formed and what processes were involved. Scientists began to investigate the causes of these features, such as plate tectonics and volcanic activity, and how they might have shaped the ocean floor over millions of years. Understanding the complex and dynamic nature of the ocean floor has since become an important area of study in earth science and oceanography.

The five steps of conducting survey research are:

1)Instrumentation

2)Pre-testing

3)Surveying

4)Coding

5) Analysis

The definition of survey research is research that is used to solve actual large-scale issues with very large populations, so a large sample size is needed. However, the measurement of variables is simpler with simple and short instruments.

The characteristics in survey research are;

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A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student cannot tell that if the elevator is moving upward or downward. The correct answer is option C.

The reason for this is that the scale reading depends not only on the weight of the student but also on the acceleration of the elevator. If the elevator is accelerating upwards, the scale will read more than the actual weight of the student.

Similarly, if the elevator is accelerating downwards, the scale will read less than the actual weight of the student.

In this case, we know that the scale reads 645 N, which is 30 N more than the actual weight of the student (615 N).

However, we don't know whether the elevator is accelerating upwards or downwards. It could be accelerating upwards with an acceleration of 3 m/s^2 (in which case the apparent weight would be 645 N), or it could be accelerating downwards with an acceleration of 3 m/s^2 (in which case the apparent weight would be 585 N).

Therefore, based on the information given, we cannot determine whether the elevator is moving upwards or downwards. The correct option is c.

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Answer:

A) Pitch

Explanation:

Wavelength determines the pitch  ( or frequency which is 1/wavelength)

Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

Answer:

136 meters.

Explanation: If it can go 17 meters a second, then after 8 seconds, it will go 136 meters. Multiple 17 by 8 to get your answer.