Electron transport chain use NADH and FADH2 molecules formed in Glycolysis and Krebs Cycle processes.
The third stage of cellular respiration is the electron transport chain. In cellular respiration, high-energy electrons are transported by NADH and FADH2 to the electron transport chain. In photosynthesis, NADPH transports energetic electrons to the electron transport chain.
Krebs cycle or the TCA cycle, the process of oxidizing acetyl-CoA, which is produced from proteins, carbs, and lipids, releases stored energy.
The process by which glucose is broken down to provide energy is known as glycolysis. It generates two pyruvate molecules, ATP, NADH, and water. There is no need for oxygen throughout the process, which occurs in the cytoplasm of a cell. Both aerobic and anaerobic respiration experience it.
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+ 50 PLEASE HELP ME IM SO CONFUSED
Answer:
Place the nickel at 1" point on the ruler for each trial. Then, drop the quarter from 12" for each trial.
Here are the results-
Middle Trials (6")
T1: moved right about 0.5"
T2: moved left 1" and backwards 0.5" (-0.5")
T3: moved right 2" and backwards 0.5" (-0.5")
______________________________________
9" trials
T1: Right about 1"
T2: Right 0.5"
T3: around 0.8" foward
______________________________________
12" trials were all at 0" in change
______________________________________
The 12" trial requires more force for movement while the 9" trial gave the most positive changes forwards.
Explanation:
Information-
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a 40-µc charge is positioned on the x axis at x = 4.0 cm. where should a –60-µc charge be placed to produce a net electric field of zero at the origin?
The -60 µC charge should be placed at approximately x = 4.89 cm from the origin to produce a net electric field of zero at the origin.
To find the position where a -60 µC charge should be placed to produce a net electric field of zero at the origin, we can use the principle of superposition of electric fields.
Let's assume that the -60 µC charge is positioned at a distance x from the origin. According to the principle of superposition, the net electric field at the origin is the vector sum of the electric fields produced by each charge.
The electric field produced by a point charge is given by Coulomb's Law:
\(\[E = \frac{{k \cdot q}}{{r^2}}\]\)
Where:
E is the electric field
k is the electrostatic constant \((\(9.0 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2\))\)
q is the charge
r is the distance between the charge and the point where the electric field is being calculated
Using this formula, we can calculate the electric field produced by the 40 µC charge at the origin (r = 0):
\(\[E_1 = \frac{{(9.0 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2) \cdot (40 \times 10^{-6} \, \text{C})}}{{(0.04 \, \text{m})^2}}\]\)
Simplifying:
\(\[E_1 = \frac{{9.0 \times 10^9 \times 40 \times 10^{-6}}}{{0.04^2}} \\\\= \frac{{36}}{{4}} \times 10^4 \, \text{N/C} \\\\\= 9 \times 10^4 \, \text{N/C}\]\)
For the net electric field at the origin to be zero, the electric field produced by the -60 µC charge at the origin must cancel out the electric field produced by the 40 µC charge. Therefore, we have:
\(\[E_2 = -E_1\]\)
Substituting the known values:
\(\[\frac{{k \cdot (-60 \times 10^{-6})}}{{(x)^2}} = -\frac{{9 \times 10^4}}\)
Solving for x:
\(\[(x)^2 = \frac{{9 \times 10^4}}{{9 \times 10^9 \times 60 \times 10^{-6}}}\\\\= \frac{{10^4}}{{10^3 \times 6}} = \frac{{10}}{{6}}\\\\x = \sqrt{\frac{{10}}{{6}}} \\\\= \frac{{\sqrt{10}}}{\sqrt{6}} \approx 4.89 \, \text{cm}\]\)
Therefore, the -60 µC charge should be placed at approximately x = 4.89 cm from the origin to produce a net electric field of zero at the origin.
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What is the unit of work? Explain whether the unit of work is a fundamental uint
or derived unit
1.
What do you mean by a unit?
2.
unit or a derived unit.
are the fundamental units used in physics?
al Bureau of Weights and Me
Answer:
1)the unit of work is joule. 2)it is derived unit because it is made by two different unit force and displacement .3)
Which current is produced in homes? magnetic voltage alternating direct
Answer:
Alternating
Explanation:
Edge 2020
A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?
A.
0.034 newtons/amp·meter
B.
0.17 newtons/amp·meter
C.
0.26 newtons/amp·meter
D.
0.77 newtons/amp·meter
E.
6.0 newtons/amp·meter
Answer:
the answer is letter D.
Explanation:
i hope this is help
Answer:
great answer warstep8! add me on disc colludy#8415
Explanation:
The fatty layer contains many nerves and blood vessels. True or False
Answer:
False , The fatty layer do not contains many nerves and blood vessels. The fatty layer is related to skin layers.
Explanation:
The fatty layer is the most under a layer of skin. It made up of a system of collagen and fat cells. It helps maintain the body's temperature and shields the body from harm by serving as a shock absorber.
The dermis is the central layer of the skin. The dermis is maintained collectively by a protein termed collagen. This layer gives skin elasticity and power. The dermis also holds shock and feel receptors.
A 35kg barrel is rolled up a 5m long plank which makes a 30° angle to the plank. What is the potential energy of the barrel at the top?
Answer:
100°
will be the angle of the planks
I'LL MARK YOU BRAINLIST !!!!!!!!!!!!
Answer:
d. collection of photo.....
object Travels 24 M with a speed of 4 metre per second and then another 32 with a speed of 8 metre per second the average speed of the object is
(a)6m/s (b)4m/s (c)5.6m/s (d)6.5m/s
Answer:
Total distance covered S=16+16=32 m
Total time t=4+2=6 s
Average speed V
avg
=
t
S
=
6
32
=5.33 m/s
c) Name the type of error described in the two cases of measurements below. Case 1: A stopwatch that runs fast or slow. Case 2:
The description of the measurement is incomplete, and therefore it is impossible to determine the type of error.
What is Measurement?
Measurement is the process of quantifying or determining the size, amount, or degree of something using standard units or scales. It involves assigning a numerical value to a physical quantity, property, or characteristic of an object, event, or phenomenon.
Measurement is a fundamental tool used in science, engineering, commerce, and everyday life. It allows us to make comparisons, establish standards, and assess the accuracy and precision of our observations and experiments. Some common examples of measurements include length, mass, time, and volume, which are typically expressed in units such as meters, kilograms, seconds, degrees Celsius, and liters, respectively.
The error described in this case is systematic error, also known as a bias. The stopwatch consistently measures time intervals that are either longer or shorter than the actual time.
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a density of lead is just over 10 the power of 4 kg/m3 find the mass of a cylinderical rod of length 0.5m and radius 0.020m
The mass of a cylindrical rod is 6.29 kg.
What is density?The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition.
Density of lead = 10⁴ kg/m³.
Volume of a cylindrical rod of length 0.5m and radius 0.020m = πr²l
= (22/7)(0.020)²(0.5) m³
=6.29×10⁻⁴ m³.
Hence, mass of the cylindrical rod = volume × density
= 6.29×10⁻⁴ m³ × 10⁴ kg/m³.
= 6.29 kg.
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Activity: Solve each problem involving acceleration. Be sure to show all solutions and to use the correct units. 1. While traveling along a highway a driver slows from 45 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? 2. A biker accelerates at a rate of 7 m/s2. How long will it takes the biker to reach a speed of 18 m/s?
Answer:
1. a = - 2.5 m/s²
2. t = 2.57 s
Explanation:
1.
The acceleration of the driver can be found using the first equation of motion:
\(v_f = v_i + at\)
where,
vf = final speed = 15 m/s
vi = initial speed = 45 m/s
a = acceleration = ?
t = time = 12 s
Therefore,
\(15\ m/s = 45\ m/s +a(12\ s)\\\\a = \frac{15\ m/s-45\ m/s}{12\ s}\)
a = - 2.5 m/s²
negative sign indicates deceleration
2.
The time taken by the biker to accelerate can be found by using the first equation of motion again:
\(v_f = v_i + at\)
where,
vf = final speed = 18 m/s
vi = initial speed = 0 m/s
a = acceleration = 7 m/s²
t = time = ?
Therefore,
\(18\ m/s = 0\ m/s +(7\ m/s^2)t\\\\t = \frac{18\ m/s}{7\ m/s^2}\)
t = 2.57 s
I need help on this question.
Answer:
A
Explanation:
3. The brakes of a certain car can produce an acceleration of 6 m/s.
a. How long does it take the car to come to a stop from a velocity of 30 m/s?
Answer:
5s
Explanation:
initial distance: 0 m
distance: ? (we don't know)
initial velocity: 0 m/s
velocity: 30 m/s
acceleration: 6 \(m/s^{2}\)
time: ? (we are looking for)
v = v0 + at
plug the numbers in:
30 = 0 + 6(t)
= 30 = 6t
= t = 5
5s
what is the force exerted by the cord on the ceiling when the ball is at the lowest point. provide explanation.
Force exerted by the cord on ceiling will be equal to the tension (T1) in the rope i.e. 60 N
Force is an external agent able of changing a body’s state of rest or stir. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force, and the operation of force is the point where force is applied.
The Force can be measured using a spring balance. The SI unit of force is Newton( N).
In drugs, stir is defined as the change in position with respect to time. In simpler words, stir refers to the movement of a body. generally, stir can either be described as
Change in speed
Change in direction
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A book weighing 18.0 N is lifted from the floor and placed on a shelf 1.5 m high. What is the minimum amount of work required to accomplish this
task?
a. 120J
B. 12 J
c.270J
D. 27 J
A book weighing 18.0 N is lifted from the floor and placed on a shelf 1.5 m high. The minimum amount of work required to accomplish this task is
What is Work ?Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule. Writing for it's dimension, W=F× s Force has dimension [L¹ M¹ T²] Displacement has dimension [L¹] multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].
Given,
Weight F = 18 N
Height h = 1.5 m
Work W = F × h = 18 × 1.5 = 27 J
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a body of mass 5kg moving on a horizontal ground has a coefficient of friction 0.36.find the normal reaction acting on the body?
Answer:
50 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 Kg
Coefficient of friction (μ) = 0.36
Normal reaction (N) =?
Next, we shall determine the weight of the body. This can be obtained as follow:
Mass (m) = 5 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = mg
W = 5 × 10
W = 50 N
Finally, we shall determine the normal reaction. This can be obtained as follow:
Weight (W) = 50 N
Normal reaction (N) =?
Normal reaction = weight of the body
N = W = 50 N
Thus, the normal reaction acting on the body is 50 N
Ou pull straight up on the string of a yo-yo with a force 0.235 n, and while your hand is moving up a distance 0.18 m, the yo-yo moves down a distance 0.70 m. the mass of the yo-yo is 0.025 kg, and it was initially moving downward with speed 0.5 m/s and angular speed 124 rad/s. what is the increase in the translational kinetic energy of the yo-yo
The increase in the translational kinetic energy of the yo-yo is 0.0423 J.
To find the increase in the translational kinetic energy of the yo-yo, we need to calculate the work done on the yo-yo by the force applied by the hand.
The work done is given by: W = Fdcos(theta), where F is the force applied, d is the distance moved, and theta is the angle between the force and the displacement.
In this case, theta is 180 degrees since the force and displacement are in opposite directions.
Substituting the given values, we get:
W = (0.235 N)*(0.18 m)*cos(180 deg)
W = -0.0423 J
Since the yo-yo initially had kinetic energy due to its downward motion, the work done by the hand increases the yo-yo's total kinetic energy. The increase in kinetic energy is given by: ΔK = -W
Substituting the value of W, we get: ΔK = 0.0423 J
Therefore, the increase in the translational kinetic energy of the yo-yo is 0.0423 J.
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A frictionless piston-cylinder device as shown in Figure Q4 contains 7.5 liters of saturated liquid water at 275kPa. An electric resistance is installed in it and is being turned on until 3050 kJ of energy is transferred to the water. Assume the piston-cylinder device is well insulated, determine i) the mass of water, kg, ii) the final enthalpy of water, k J/kg, iii) the final state and the quality (x) of water, iv) the change in entropy of water, kJ/kg, and v) whether the process is reversible, irreversible, or impossible. Sketch the process on P−v diagram with respect to the saturation lines.
A frictionless piston-cylinder device contains 7.5 liters of saturated liquid water at 275 kPa. An electric resistance is turned on until 3050 kJ of energy is transferred to the water.
i) The mass of water can be determined by using the specific volume of saturated liquid water at the given pressure and volume. By using the specific volume data from the steam tables, the mass of water is calculated to be 6.66 kg.
ii) To find the final enthalpy of water, we need to consider the energy added to the water. The change in enthalpy can be calculated using the energy equation Q = m(h2 - h1), where Q is the energy transferred, m is the mass of water, and h1 and h2 are the initial and final enthalpies, respectively. Rearranging the equation, we find that the final enthalpy of water is 454.55 kJ/kg.
iii) The final state and the quality (x) of water can be determined by using the final enthalpy value. The final enthalpy falls within the region of superheated vapor, indicating that the water has completely evaporated. Therefore, the final state is a superheated vapor and the quality is 1 (x = 1).
iv) The change in entropy of water can be obtained by using the entropy equation ΔS = m(s2 - s1), where ΔS is the change in entropy, m is the mass of water, and s1 and s2 are the initial and final entropies, respectively. The change in entropy is found to be 10.13 kJ/kg.
v) The process described is irreversible because the water started as a saturated liquid and ended up as a superheated vapor, indicating that irreversibilities such as heat transfer across a finite temperature difference and friction have occurred. Therefore, the process is irreversible.
On a P-v diagram, the process can be represented as a vertical line from the initial saturated liquid state to the final superheated vapor state, crossing the saturation lines.
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determine the force in member bd and the components of the reaction at c if the force applied at a is 330 n. (round the final answers to their nearest whole number.)
The force in member BD is 330 N, and the reaction at C consists of two components: 130 N along the x-axis and 200 N along the y-axis.
What is force?
A force is indeed an influence that really can alter an object's motion according to physics. A motion of an object to mass to accelerate when it changes its velocity, such as when it moves away from rest. An intuitive way to describe force is as a push or a pull. A force is a vector quantity because it has both direction and magnitude. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P). The net force acting on an object is proportional to the frequency that its momentum changes over time, according to Newton's second law in its original formulation.
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An automobile traveling at 72 km/h hits a tree. The driver who has a mass of 55 kg
comes to rest in 0.10 seconds after the impact.
a. What is the average force that acts on the driver?
The average force that acts on the driver is equal to 1100N.
What is the equation of motion?The equations of motion have described the relationship between the velocity, acceleration, time, and displacement of a moving object.
The mathematical expressions of the equations of motions can be written as:
\(v= u+at\)
\(S = ut+\frac{1}{2}at^2\)
\(v^2-u^2=2aS\)
Given, the automobile is traveling with velocity, u = 72 Km/hr = 20m/s
The final velocity of the automobile, v = 0
The time for which the driver comes to rest, t = 0.10 sec
From the 1st equation of motion: v = u + at
0 = 20 + a (0.10)
a = - 200 m/s²
The mass of the driver, m = 55 Kg
The average force, F = ma = 55 × 20 = 1100 N
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Help me to solve the question
Answer:
https://brainly.com/question/24997963 this will help you. You need to sq rt the added values then divide a+b by the square value. Keeping anything thats negative negative if negative is answer and set to = cos theta. then convert from cos theta = 1 cos will = 0. But if cos theta = decimal then ensure its positive number and that's your answer. Formula a+b/ sqrt a+b
Explanation:
I honestly don't know how to answer the last part of this question, it makes no sense to me:
A SR-71 reconnaissance aircraft, the world's fastest aircraft, is flying east at 3000 km/h. If the plane encounters a cross-wind of 300 km/h that is directed to the north,what is the magnitude and direction of its resultant velocity? If the border is a straight north/southline, will it take more, less or the same time to reach the eastern border of the country with the cross wind vs. without the crosswind? Explain
The resultant velocity of the aircraft is 3015 Km/hr while the direction is 5.7 degrees North of east
What is the resultant velocity?The resultant vector is that vector that has the same effect is magnitude and direction as the two vectors acting together. Recall that velocity is a vector quantity. This implies that the magnitude and the direction of the velocity is very important.
The resultant velocity would now be obtained by considering the directions of the two velocities hence we have to work geometrically and not algebraically. We have to know that the plane is flying east at 3000 km/h. If the plane encounters a cross-wind of 300 km/h that is directed to the north
Thus the resultant velocity is;
R = √(3000)^2 + (300)^2
R = √9 * 10^6 + 9 * 10^4
R = 3015 Km/hr
The direction of this resultant velocity is;
Tan-1 (300/3000)
= 5.7 degrees North of east
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Which of the following is true about the mass of an object?
O It is equal to its weight.
O It is proportional to its weight.
O it is always more than its weight.
Olt changes at different locations
Two 0.967 kg masses are 4.439 m apart on a frictionless table. Each has 16.074 microCoulombs of charge. What is the initial acceleration of each mass if they are released and allowed to move?
Firstly, we can write the equation for the electric force. It is:
\(F_e=k\frac{q_1q_2}{d^2}\)By applying our values we get
\(F_e=(9*10^9)\frac{(16.074*10^{-6})*(16.074*10^{-6})}{(4.439)^2}=0.118N\)Now, if we remind ourselves of Newton's law, we know that
\(\vec{F}=m.\vec{a}\)We know the mass, and we know the Force, so we can find out the acceleration, this gives us:
\(0.118=0.967*a\)Thus
\(a=\frac{0.118}{0.967}=0.122\frac{m}{s^2}\)Our final acceleration is 0.122 m/s^2
The linear speed of a rotating wheel of radius 2 feet is 200f(t)/(m)in. What is the angular speed of the wheel in radians per minute? Round your answer to two decimal places. i
The angular speed of the wheel is **100π** radians per minute.
The linear speed of a rotating wheel is the distance traveled by a point on the circumference of the wheel per unit time. In this case, the linear speed is given as 200f(t)/(m)in, where f(t) represents an arbitrary function of time and m represents an arbitrary unit of measurement.
To find the angular speed of the wheel, we need to convert the linear speed into angular speed. Angular speed is defined as the rate at which an object rotates or travels around a circular path. It is measured in radians per unit time.
To convert the linear speed into angular speed, we need to relate the linear speed to the circumference and radius of the wheel. The circumference of a circle is given by 2π times the radius. In this case, the radius of the wheel is given as 2 feet.
Since the linear speed is the distance traveled per unit time, we can calculate the distance traveled in one minute by multiplying the linear speed by 60. Dividing this distance by the circumference of the wheel gives us the number of revolutions per minute. To convert this into radians per minute, we multiply the number of revolutions by 2π.
In summary, to calculate the angular speed of the wheel, we take the given linear speed and convert it into the number of revolutions per minute. We then multiply this value by 2π to obtain the angular speed in radians per minute.
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a beam of monochromatic light in material a enters material b , which has a higher index of refraction than material a . how do the speed, frequency, and wavelength of the light in material b compare to those in material a ?\
In denser medium, speed is slower but frequency remains same. So, as v = f lambda, so wavelength will also decrease. Hence, answer is: Option c.
What is speed?
The definition of speed. a direction or speed at which an object's location changes. The distance traveled relative to the time it took to travel that distance is how fast something is moving. As it just has a direction and no magnitude, speed is a scalar quantity.
What is frequency ?
The number of full wave cycles that pass a spot in a unit of time is described as frequency. The frequency in SI is measured in Hertz (Hz).
Therefore, In denser medium, speed is slower but frequency remains same. So, as v = f lambda, so wavelength will also decrease. Hence, answer is: Option c.
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Compare the direction that a transverse wave travels with the direction that matter in the wave vibrates
In a transverse wave, matter vibrates in a direction that is parallel to the wave motion, whereas the direction of energy transfer is perpendicular to the wave's direction of motion.
How can the direction that a transverse wave moves be compared to the direction that the wave's constituent matter vibrates?A transverse wave transfers energy in a direction that is perpendicular to the way that the wave's constituent matter vibrates. For instance, when a rope is shaken back and forth to produce a wave, the energy moves perpendicular to the rope's motion from one end to the other.
In contrast, the path of energy transfer in a longitudinal wave is parallel to the direction in which the wave's constituent matter vibrates. For instance, as sound waves pass through air, the molecules in the air oscillate back and forth parallel to the wave's motion.
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The smith family is travelling in their car at 50 km/h due east. Mr. Smith is using cruise control to maintain a constant speed. Describe the net force acting on the smith car.
Answer:
The net force would be zero
Explanation:
Since, F = m*a
So, if the speed is constant, similarly if we include direction the Velocity is constant and that means that acceleration is zero as acceleration itself is change in velocity per time so constant velocity and since,
a = (Vf - Vi)/change in time
a = 0
then
F = m*0
so F is also zero
The acceleration due to gravity on the moon is 1.6 2. If an astronaut weighs 96 N on
the moon, what is the astronaut's mass on Earth? (2 points)
Answer:
60kg
Explanation:
F= ma
96 = m ×1.6
m= 96/1.6
=60 kg