my heart strike him to dead.what figure of speech is that?​

a) , it would take approximately 0.4638 seconds for the magnetic energy to decay to 13% of its maximum value.. b)  the voltage across the inductor at the instant when the magnetic energy has decayed to 13% of its maximum value is 6.4 times the initial current in the circuit.

An RL circuit consists of a resistor (R) and an inductor (L) connected in series. When a battery is connected to the circuit, the inductor stores magnetic energy, which creates a magnetic field. When the battery is removed, the magnetic energy in the inductor begins to decay, and the magnetic field collapses, inducing a voltage across the inductor.

a) The time constant (τ) of an RL circuit is given by the formula:

τ = L/R

where L is the inductance in henries, and R is the resistance in ohms. The time constant represents the time required for the magnetic energy to decay to approximately 36.8% of its maximum value.

In this case, L = 5 H and R = 22 ohms. Therefore, the time constant of the circuit is:

τ = L/R = 5 H / 22 ohms = 0.2273 seconds

To calculate the time required for the magnetic energy to decay to 13% of its maximum value, we can use the formula:

t = -ln(0.13) * τ

where ln is the natural logarithm. Plugging in the values, we get:

t = -ln(0.13) * 0.2273 seconds

t = 0.533 seconds

Therefore, it would take approximately 0.533 seconds for the magnetic energy in the inductor to decay to 13% of its maximum value.

b) To find the voltage across the inductor at that instant, we can use the formula:

V = L * di/dt

where V is the voltage across the inductor, L is the inductance, and di/dt is the rate of change of the current in the circuit.

At the instant when the magnetic energy in the inductor has decayed to 13% of its maximum value, the current in the circuit is given by:

I = I0 * e^(-t/τ)

where I0 is the initial current, and e is the mathematical constant approximately equal to 2.71828. Plugging in the values, we get:

I = I0 * e^(-0.533/0.2273)

I = 0.292 * I0

Therefore, the rate of change of current (di/dt) at that instant is given by:

di/dt = I / τ = (0.292 * I0) / 0.2273

Now, we can calculate the voltage across the inductor:

V = L * di/dt = 5 H * (0.292 * I0 / 0.2273)

V = 6.4 * I0 volts

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The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

W = (10 N) (-1.0 m) = -10 J

The work done by gravity on the book is -10 Joules. The correct option is 2.

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given are the three positions. The Earth has the acceleration due to gravity, g =  9.81 m/s²,

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = 10 N x( -9.80 m/s² )= -9.8 N

F ≈ -10 N

The book is raised by  1.0 m in the opposite direction, so the work done is

W =- 10 N x 1.0 m = -10 J

Thus, the correct option is 2.

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Electronegativity is a tendency of a atom/element to attract the pair of electrons.

electronegativity order = O>B>Ga

electronegativity order = Mg>Ba>Ca

electronegativity order =P>Ga>Al

electronegativity order =O>C>Al

When an atom of a certain chemical element forms a chemical bond, it has a propensity to draw shared electrons (or electron density). The atomic number and the separation of the valence electrons from the charged nucleus have an impact on an atom's electronegativity. An atom or a substituent group will draw electrons in greater amounts the higher the associated electronegativity. The sign and amplitude of a bond's chemical polarity, which characterizes a bond along the continuous scale from covalent to ionic bonding, can be quantitatively estimated using electronegativity. The inverse of electronegativity is electropositivity, which describes an element's propensity to accept valence electrons.

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Answer:Because you just really need help on your work!

Explanation:

Answer:

Gravity is on our side. On top of that, the optimal body position allows us to do it.

The angle of projection given that the range is 256√3 m and the maximum height reached is 64 m is 30°

R = u²Sine(2θ) / g

256√3 = u²Sine(2θ) / 9.8

Cross multiply

256√3 × 9.8 = u²Sine(2θ)

Divide both sides by Sine(2θ)

u² = 256√3 × 9.8 / Sine(2θ)

H = u²Sine²θ / 2g

64 = [256√3 × 9.8 / Sine(2θ)] × [Sine²θ / 2 × 9.8]

64 = [256√3 / Sine(2θ)] × [Sine²θ / 2]

Recall

Sine²θ = SineθSineθ

Sine2θ = 2SineθCosθ

Thus,

64 = [256√3 / 2SineθCosθ] × [SineθSineθ / 2]

64 = 256√3 × Sineθ / 4Cosθ

Recall

Sineθ / Cosθ = Tanθ

Thus,

64 = 256√3 / 4 × Tanθ

Divide both side by 256√3 / 4

Tanθ = 64 ÷ 256√3 / 4

Tanθ = 0.5774

Take the inverse of Tan

θ = Tan⁻¹ 0.5774

θ = 30°

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Answer:

t=8

Explanation:

u have solution I give solution also

don't mark plzz follow y

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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Answer:

12,000 grams = 12 kg

Explanation:

Volume V = 20 x 20 x 30 cm³ = 12,000 cm³

density of water d = 1 g/cm³

so the mass is 12,000 grams = 12 kg

Answer:

Δv/Δt

Explanation:

I beat your game SAW.

Alkali and alkaline earth metals invariably produce cations.

Calcium (Ca2+), potassium (K+), and hydrogen (H+) are a few examples of cations.

Positively charged ions are referred to as cations. Less electrons than protons make up cations. An ion can be made up of a single atom of an element (a monatomic ion, monatomic cation, or monatomic anion) or many atoms that are chemically connected to one another (a polyatomic ion or polyatomic cation or anion)

Alkali and alkaline earth metals always create cations, whereas halogens always produce anions. Most nonmetals normally create anions, while the majority of other metals typically produce cations (such as iron, silver, and nickel) (e.g. oxygen, carbon, sulfur)

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Answer:

So, the answer is eather B or D.

Explanation:

It could be b because she needs to make sure everything is good but it could be d because yopu need to keep everything the same. I personally would go d

Explanation:

Thanx for the figure;
The force component of F   UP the ramp that  moves the crate must equal the force of the crate DOWN the ramp

75 kg = mg Newtons = 735.8 Newtons

    Downplane force is   735.8 sin 34°  = 411.4 Newtons

   Fn =The horizontal force will be found by   cos 34 = 411.4/ F                                                                       F = 411.4/cos (34) = 496 N

Normal Force =  735.8 cos 34°  = 610 N   This part is due to the mass of the crate....there is additional normal force from the force pushing the crate up the hill  (from below)

   = F sin34   =  496 sin 34 = 277.4 N

            SUM of normal forces = 610 + 277.4 = 887.4 N

Answer:

  a.  |F| ≈ 496 N

  b.  normal force ≈ 887 N

Explanation:

You want the magnitude of the horizontal force F that moves a crate up a 34° ramp at constant speed, and you want the magnitude of the normal force on the crate.

The constant speed of the crate tells you the net force up the ramp is zero. This is the sum of the component of force F in that direction and the force due to gravity in the opposite direction:

  F·cos(34°) - m·g·sin(34°) = 0

  F = mg·tan(34°) = (75 kg)(9.8 m/s²)tan(34°) ≈ 496 N

The magnitude of force F is about 496 N.

The normal force on the crate will be the sum of the component of F in that direction and the force due to gravity in the same direction:

  F·sin(34°) +m·g·cos(34°) ≈ 887 N

The magnitude of the normal force is about 887 N.

Answer: The dependent Variables include: Size and Types of trees.

The independent Variables include:

geographic elevations that is, valleys and the higher elevations.

Explanation:

The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.

Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the

geographic elevations that is, the valleys and the higher elevations.

Answer:

c. Was an idea created and supported by Congress.

Explanation:

The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803) was an idea created and supported by Congress.

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The vector characteristics of the electric field allow to find the result for the electric field at the point of interest is;

Given parameters.

    1) Electric charges:

    2)Charge positions

   3) Points of interest r = (0,0,1) = 1 \(\hat k\)  

To find.

the electric field at point r.

The intensity of the electric field is given by the ratio of the electric force to the positive test charge at the point of interest.

          \(E= k \frac{q}{r^2 }\)  

where E is the electric field, k the constant of Coulomb, q the charge and r the distance.

In the attached we see a diagram of the test charges and the distance to the point of interest on the z axis.

The total field is the vector addition of the fields created by each charge

          \(E_{total} = E_1 +E_2\)

Let's look for the components of each electric field.

Field created by charge q₁

          tan θ = \(\frac{z}{x}\)  

          tan θ = 1/1 = 1

          tea = 45º

x-axis

          cos 45 = \(\frac{E_{1x}}{E_1}\)

z axis

          sin 45=  \(\frac{E_{1z}}{E_1}\)  

          E₁ₓ = E₁ cos 45

          \(E_{1z}\)  = E₁ sin 45

Field created by load 2

y-axis

        cos 45 = \(\frac{E_{2y}}{E_2}\)  

z- axis

        sin 45 = \(\frac{E_{2z}}{E_2}\)  

        \(E_{2y}\) = E2 cos 45

        \(E_{2z}\) = E2 sin 45

We look for the components of the total electric field, where the signs are taken from the direction of the vectors in the attached.

    \(E_{total} = - E_{1x} \hat i + E_{2y} \hat j + ( E_{1z} - E_{2z} ) \hat k\)

Let's substitute.

         \(E_{total } = - E_1 cos 45 \hat i + E_2 cos 45 \hat j + (E_1 sin 45 - E_2 sin 45) \hat k\)

Let's find the distance for each charge to the test point using the Pythagorean Theorem.

         r₁₃² = x² + z²

         r₁₃² = 1 + 1

         r₁₃² = 2

         r₂₃² = y² + z²

         r₂₃² = 1² + 1²

         r₂₃² = 2

Let's look for the magnitud of the electric fields.

Charge q₁

        \(E_1 = k \frac{q_1}{r_{13}^2}\)  

        E₁ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₁ = 20 N / m

Charge q₂

        \(E_2 = k \frac{q_2}{r_{23}^2}\)  

        E₂ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₂ = 20 C / N

Let's substitute in the expression of the total eletric field.

         \(E_{total} = -20 \ cos45 \ \hat i + 20 \ cos 45\ \hat j + ( 20 -20) sin 45 \ \hat k\)

         \(E_{total} = 14.1 ( - \hat i + \hat j) \ \frac{N}{C}\)  

In conclusion using the vector characteristics of the electric field we can find the result for the electric field at the point of interest is;

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Answer:

like fixing are car engine would be an example of a mechanical wave

Answer:the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

Explanation:

Answer:

suppose the

quantity of water on the earth is 1.32 1021 kg and remains constant

the

During the nuclear change we can expect to see different chemical symbols before and after the change

Chemical and nuclear reactions are quite different from one another. Atoms can share electrons with other atoms or participate in an electron transfer to increase their stability in chemical reactions. In nuclear reactions, the atom's nucleus stabilizes itself by going through some sort of alteration. Compared to the energies involved in chemical reactions, the energies produced in nuclear reactions are many orders of magnitude higher. Environmental factors like temperature or pressure do not significantly affect nuclear reactions like they do with chemical ones.

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei

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Answer:

As light waves transmit from one medium to another medium ( of different optical densities ), the speed of the light wave changes. When speed changes the direction of the wave changes hence refracted.

\(.\)

Answer:

Explanation:

\(y(t) = 5t-5t^2\)

When y(t) = 0, the ball is on the hand.

\(0=5t-5t^2\\0=5t(1-t)\\t=0,1\)

It takes 1 second.

There are several different possibilities.

==>  If the 5.0 means 5 miles per hour, that's 2.24 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (2.24/9.8) = 0.229 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 0.457 second.

==>  If the 5.0 means 5 meters per second, up . . .

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (5.0/9.8) = 0.51 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 1.02 second.

==>  If the 5.0 means 5 km/minute, that's about 83.33 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (83.33/9.8) = 8.503 seconds.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 17.01 seconds.

==>  If the 5.0 means 5 furlongs per fortnight, that's about 0.00083 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (0.00083/9.8) = 0.000085 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 0.00017 second.

This is why all of your numbers always need their units.

In order to calculate the value of the sine of 40°, let's use a calculator with the value 40 and use the sine function.

We need to check if the calculator is in the "degree" mode, instead of the "radians" mode.

Then, calculating the sine of 40°, the result rounded to two decimal places is:

Therefore the correct option is B.

When taking the measurement, the estimate part of a millimeter when recording the block’s length can be expressed as ± 0.5 mm.

Measurements are the processes by which the attributes and properties of a given object or substance is quantified.

There are two types of measurements that can be obtained from any given object and they are:

Quantitative measurements measures the properties of objects in terms of numbers. Some examples of quantitative measurements are length, temperature, time, mass, etc.

Qualitative measurements describe the non-numerical features of objects such as color, texture, etc.

The measurement of length of a block of wood is a quantitative measurement.

The uncertainty or estimate of a measurement is half plus or minus the smallest division in the measurement.

The uncertainty or estimate of the millimeter block = ¹/₂ * 1 mm

The uncertainty or estimate of the millimeter block = ±0.5 mm

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The graph that shows the relationship between the speed and the kinetic energy is option B.

Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy.  The kinetic energy is the energy of an object that has a velocity

The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.

As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.

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The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours

Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)

To get the time that was saved on the 8.6-mile trip, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.

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First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is -9,835 Newtons.

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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