The kinetic energy of the ball when it has a mass of 0.7 kg is 14000J.
When the speed is 180 m/s its K.E. changes to 11340 J.
Calculate the kinetic energy of the following options?
A. Kinetic energy E = 1/2 \(mv^{2}\)
mass (m) = 0.7 kg
speed (v) = 200 m/s
K.E = 1/2 (0.7) (200)^2
K.E = 1/2 (28000)
K.E = 14,000J
K.E = 14 x 10^3 J
The kinetic energy of the ball has a mass of 0.7 kg is 14 x \(10^{3}\) J
B. The kinetic energy is directly proportional to the square of the speed or velocity. When the speed increases its kinetic energy also increases. When the speed decreases also its kinetic energy is decreases.
K.E. = 1/2 \(mv^{2}\)
K.E. = 1/2 (0.7) (180)^2
K.E. = 11,340 J
So, the speed of the kinetic energy is decreased, the value of K.E. is also decreased.
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A dog starts at position x=2.50m, and undergoes a displacement of 8.25m. What is its final position?
Answer:
Civil law deals with behavior that constitutes an injury to an individual or other private party, such as a corporation. Examples are defamation (including libel and slander), breach of contract, negligence resulting in injury or death, and property damage.
Explanation:
Hello Everyone
Which one has higher density and lower density
cooking oil
water
this two materiels i used in density tower experiment
Now they are saying to like you know compare which is higher density and which is lower density
Send ASAP
Answer:
cooking oil has a higher density than water
Explanation:
A simple harmonic oscillator has a mass of 8 kg, a spring constant 75 N/m, and Total energy of 135 J. Solve for maximum velocity, Vmax (in m/s )
The maximum velocity, Vmax (in m/s) of a simple harmonic oscillator with a mass of 8 kg, a spring constant 75 N/m, and Total energy of 135 J can be determined using the formula: Vmax = √(2E/m) where E is the Total energy and m is the mass.
Substituting the given values into the formula, we get: Vmax = √(2E/m) = √(2 x 135 J/8 kg) = √(33.75)≈ 5.81 m/s Therefore, the maximum velocity of the simple harmonic oscillator is 5.81 m/s. Here is a detailed explanation for your understanding:
Given,Mass of the oscillator, m = 8 kgSpring constant, k = 75 N/mTotal energy, E = 135 J We know that the total energy of a simple harmonic oscillator is given by:E = 1/2 kx² + 1/2 mv²where x is the amplitude and v is the velocity of the oscillator.Substituting the given values, we get:135 J = 1/2 × 75 N/m × x² + 1/2 × 8 kg × v²The maximum velocity occurs at the equilibrium position, where x = 0.Therefore, the equation becomes:135 J = 1/2 × 8 kg × v²Simplifying and solving for v, we get:v = √(2E/m) = √(2 x 135 J/8 kg) = √(33.75)≈ 5.81 m/s
Therefore, the maximum velocity of the simple harmonic oscillator is 5.81 m/s.
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Under normal conditions, humans radiate electromagnetic waves with a wavelength of about 9.0 microns. a) What is the frequency of these waves? f = __ Hz b) To what portion of the electromagnetic spectrum do these waves belong?a. microwave
b. infrared
c. visible
d. ultraviolet
e. x-rays
Humans emit waves at a frequency of 33.3 THz, which correspond to the infrared portion of the electromagnetic spectrum.
a) With a wavelength of 9.0 microns, the frequency of electromagnetic waves emitted by humans is roughly 33.3 THz. (terahertz).
b) These waves are part of the electromagnetic spectrum's infrared region, which is responsible for heat transfer and is widely used in technologies such as remote controls and thermal imaging cameras. Infrared waves belongs to the region of the spectrum where the wavelength is high but the frequency is low but they have shorter wavelength and longer frequency than the microwaves.
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60-cm
c
m
-diameter wheel accelerates uniformly about its center from 130 rpm
r
p
m
to 320 rpm
r
p
m
in 4. 1 s
s
A 60-cm diameter wheel accelerates uniformly from 130 rpm to 320 rpm in 4.1 s.
The problem gives us two important pieces of information about the wheel's motion: its initial and final rpm, and the time it took for the acceleration to occur.
To solve for the wheel's acceleration, we can use the following equation:
a = (v_f - v_i) / t
where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time. In this case, substituting the given values gives:
a = (320 rpm - 130 rpm) / 4.1 s
a = 46.34 rpm/s
Next, we can use the wheel's diameter to convert its rpm into linear velocity, using the formula:
v = πdN / 60
where v is velocity, d is diameter, and N is rpm. Substituting the given values gives:
v_i = π(60 cm)(130 rpm) / 60 = 409.16 cm/s
v_f = π(60 cm)(320 rpm) / 60 = 1022.91 cm/s
Finally, we can use the time and acceleration to find the distance the wheel traveled during its acceleration, using the formula:
d = vi*t + (1/2)at^2
where d is distance, vi is initial velocity, t is time, and a is acceleration. Substituting the given values gives:
d = (409.16 cm/s)(4.1 s) + (1/2)(46.34 rpm/s)(4.1 s)^2
d = 782.34 cm
Therefore, the wheel traveled approximately 7.82 meters during its acceleration.
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Now let's see what the face of the Moon looks like from the Earth over the course of a month. Change the date to March 7, 2008, at 6:00 AM. Find the Moon and zoom in until it fills the screen (you can do this by simply using the zoom feature. You should be looking at the face of a dark moon. To understand why the Moon is dark at this moment, zoom out until the FOV is about 5°. You should now be able to see both the Sun and the Moon on the screen. • Why is the Moon dark at this moment? Would you be able to see the Moon if it was in this phase? What is this phase of the Moon called? Now zoom back out until the (dark) Moon fills the screen again. Change the hour to advance time and watch as the hours and days pass. What happens to the Moon? . Stop time when the Moon is half illuminated. What is the date? . This phase of the Moon is called First Quarter. How many days have passed since New Moon? Advance time again to answer the following questions What date is it? What phase of the moon is it? ● . D How many days have passed since the First Quarter Moon? How many days have passed since the New Moon? What day is it? What phase of the moon is it?
A lunar month is the period of time during which the Moon's phases repeat. There are around 29 days in a lunar month. There are therefore twelve lunar months Every two or three years, there is a lunar year with 13 full moons, which is used to adjust the days to the calendar like we do with leap years.
The Moon is a satellite that may have been created when the Earth was struck by the enormous planet Theia 4.5 billion (4500 million) years ago. A portion of the Earth broke off and was retained by gravity in an orbit around the planet.
The Moon has a 1738 km average radius. While the Moon travels around 4 cm away from Earth year, the average distance between them is 384400 km.
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A student wants to calculate how far his boxcar starting from rest will go when it reaches an acceleration of 13.1 m/s and a velocity of 24.5 m/s
The distance traveled by the student's boxcar that starts from rest and reaches an acceleration and velocity of 13.1 m/s² and 24.5 m/s, respectively, is 22.9 meters.
We can find the distance traveled by the boxcar with the following kinematic equation:
\( v_{f}^{2} = v_{i}^{2} + 2ad \)
Where:
\( v_{f}\): is the final velocity = 24.5 m/s
\( v_{i}\): is the initial velocity = 0 (it starts from rest)
a: is the acceleration = 13.1 m/s²
d: is the distance =?
By solving the above equation for d, we have:
\( d = \frac{v_{f}^{2} - v_{i}^{2}}{2a} = \frac{(24.5 m/s)^{2}}{2*13.1 m/s^{2}} = 22.9 m \)
Therefore, the boxcar will travel 22.9 meters.
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6. I ran 12.2 km in 1.4 hours. Then I ran another 19.3 km uphill in 2.2 hours. What was my average speed?
Answer: 8.75 km/hr
Explanation:
Concept to know
Average speed: total distance/total time
-------------------------------------------------------
total distance/total time
=(12.2+19.3)/(1.4+2.2) ⇔ add the numbers of two time running together
=31.5/3.6 ⇔ simplify
=8.75 km/hr
Hope this helps!! :)
Please let me know if you have any question
Find the weight of an object of mass 5 kg
on
i. Surface of the earth
ii. b) Surface of the moon
Answer:
weight on earth is mg
which is 5*9.8
49 Newton
weight on moon is 1/6 th of weight on earth
1/6*49
8.166 Newton..
Answer:
1
For instance, on Earth, a 5.0-kg object weighs 49 N; on the Moon, where g is 1.67 m/s2, the object weighs 8.4 N.
2
The weight of the object on the surface of earth would be 5kg. The weight of the object on the surface of moon would be 5/6= 0.83 as the weight of any object on earth is six times than that on moon.
If you free the cork in a highly pressurized champagne bottle, the resulting launch of the cork will, in principle, cause the bottle to recoil. A filled champagne bottle has a mass of 1. 8 kg. The cork has a mass of 7. 5 g and is launched at 22 m/s.
The speed of the bottle when recoiling if it could move freely is 0.092 m/s.
The problem isn't complete. A similar problem is in the attachment. When we free the cork from the bottle, the cork and the bottle have a collision. According to the law of conservation of momentum, the momentum before and after the collision is the same.
p = p'
m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
m₁ = the mass of the cork = 7.5 grams = 0.0075 kgm₂ = the mass of the bottle = 1.8 kgv₁ = the speed of the cork before collision = 22 m/sv₁' = the speed of the cork after collision = 0m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
(0.0075 × 22) + (1.8 × 0) = (0.0075 × 0) + (1.8 × v₂')
0.165 + 0 = 0 + 1.8v₂'
1.8v₂' = 0.165
v₂' = 0.165 ÷ 1.8
v₂' = 0.092 m/s
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There is a current of 2.95 A in one of the copper wires for 60 seconds. Calculate the charge flow through the wire.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
What is the root cause of earths magnetic field?
Answer:
I'm not sure but I think it is electric currents in the outer core
17. If a good is a luxury, what type of response will it cause?
a long wooden board is at rest on a horizontal surface, and there is negligible friction between the board and the surface. a block is sliding along the board, and there is friction between the block and the board. at the instant shown in the figure, the block is moving but the board is still at rest. what happens to the board and block after the instant shown, and what reasoning supports this claim?
The friction force on the board is in the direction of motion of the block thus the board would proceed in the same direction as the block as it began to slow down.
Here are the items:
The bottom surface of the board and there is no resistance.
The board and the block are in contact with one another.
As a result, the block's kinetic energy would be lost, and effort would be required to overcome the frictional force. In contrast to the direction of motion of the block, the friction force on the board is in the direction of motion of the block. The board would proceed in the same direction as the block as it began to slow down.
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List 4 forms of energy
Answer:
Chemical energy is energy stored in the bonds of atoms and molecules. ...
Mechanical energy is energy stored in objects by tension. ...
Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together. ...
Gravitational energy is energy stored in an object's height.
Answer:
Nuclear power
Electricity
Mechanic
Gravity
Explanation:
#1)
A 500 Hz triangular wave with a peak amplitude of 50 V is applied to
the vertical deflecting plates of a CRO. A 1 kHz saw tooth wave with a
peak amplitude of 100 V is applied to the horizontal deflecting plates.
The CRO has a vertical deflection sensitivity of 0. 1 cm/V and a
horizontal deflection sensitivity of 0. 02 cm/V. Assuming that the two
inputs are synchronized, determine the waveform displayed on the
screen?
[2 Marks]
The CRO (Cathode Ray Oscilloscope) will display a triangular wave that is vertically stretched and horizontally compressed.
The vertical deflection plates will cause the triangular wave to be displayed with a peak-to-peak amplitude of\(100 cm (50 V * 0.1 cm/V)\), while the horizontal deflection plates will cause sawtooth wave to be displayed with a peak-to-peak amplitude of \(5000 cm (100 V * 0.02 cm/V).\) The synchronization of the two inputs will ensure that the triangular wave and the sawtooth wave are displayed in a coordinated manner, with each cycle of the sawtooth wave corresponding to five cycles of the triangular wave. The resulting display will show a pattern of diagonal lines that gradually rise and then quickly drop back to the starting position, with each line representing a cycle of the sawtooth wave.
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why are nuclear reactions used in nuclear power plants
Answer:
Nuclear reactors are the heart of a nuclear power plant. They contain and control nuclear chain reactions that produce heat through a physical process called fission. That heat is used to make steam that spins a turbine to create electricity.
Answer:
A nuclear power plant's heart is made up of nuclear reactors. They contain and regulate nuclear chain reactions, which produce heat via a physical process known as fission. This heat is converted to steam, which powers a turbine to generate energy.
Bernoulli's principle indicates that increasing the velocity of a fluid will cause its pressure to increase. which answer choice rewords the false statement so that it becomes true? responses
"Bernoulli's principle indicates that increasing the velocity of a fluid will cause its pressure to increase." According to the Bernoulli's principle this statement is incorrect or false.
What is Bernoulli's principle?According to Bernoulli, when he research about flow of the liquid, he finds out that when the speed of liquid is increasing then the pressure on the liquid is decreasing. In other words the potential energy of the liquid will become less.
How can we conclude that the statement is incorrect?According to the Bernoulli's principle, when the speed of liquid is increasing then the pressure on the liquid is decreasing. In other words the potential energy of the liquid will become less.
That means when there is less pressure on a tube that gives less pressure in the water and gives a lot of area to flow. Then the flow of the liquid increases.
Not only pressure many other forces that acting on the liquid, if its become less efficient on the liquid. Like gravitational potential energy and many more. Then the liquid flows verry frequently.
But the statement tells opposite to the Bernoulli's principle, So from the discussion we can easily conclude that this statement is incorrect or false.
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At what velocity will a 300.W motor pull a mass if it applies a force of 13.9N?
4170m/s
286m/s
21.6m/s
0.0463m/s
To answer this question, we need to use the formula that relates force, mass, and acceleration: F=ma. We can rearrange this formula to solve for acceleration: a=F/m.
In this case, we are given that the force applied by the motor is 13.9N, and we need to find the velocity at which it will pull a mass. We are not given the mass directly, but we can calculate it using the power of the motor (300W) and the velocity we are trying to find.
Power is defined as the rate at which work is done, or P=W/t, where W is the work done and t is the time it takes to do that work. In this case, we can assume that the work done is moving the mass a certain distance, and we can use the velocity to calculate the time it takes to do that work. So, we have:
P=Fv
where P=300W, F=13.9N, and v is the velocity we want to find. Rearranging this equation gives:
v=P/F
Now we can substitute in the values for P and F to get:
v=300/13.9
v≈21.6 m/s
So, at a velocity of 21.6 m/s, a 300.W motor applying a force of 13.9N can pull a mass.
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the frictional force acting in the drum set does negative work does friction always do negative work if yes explain why if no give an example of friction doing positive work
Yes,Sometimes friction does positive work
What is friction?Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
Friction is a type of contact force and one of it's best advantage is that it enables walking and enables the application of brake in vehicles and other automobile.
Though friction has many disadvantags like wear and tear of material, loss of heat energy and reducing efficiency but it also have some positive effect in daily life as mentioned above.
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A light ray has an angle of incidence of 34º. The reflected ray will make what angle with the reflecting surface?
Answer:
Angle of incidence = Angle of Reflection
34° = Angle of Reflection
So, Angle of Reflection is equal to 34°
hope it helps!
Answer: 56 degrees
Explanation:
The angle of incidence is equal to the angle of reflection, but it is not asking us for the angle of reflection. It is asking us for the angle with the reflected SURFACE. It is 90-34= 56. Look at the pic attached if you need a labelled diagram
(Q022) A negative magnetic anomaly a. occurs when the Earth's magnetic field measured in ancient rocks is the same as it is today. b. is created when weak magnetic forces in basalt grains add to the force produced by the Earth's dipole. c. describes the sawtooth pattern of magnetic signal strength measured along the Atlantic Ocean seafloor. d. is indicated when a magnetometer measures intervals of magnetism that are weaker than expecte
Answer:
d. Is indicated when a magnetometer measures intervals of magnetism that are weaker than expected
Explanation:
Magnetic field intensity is measured with a magnetometer on the surface of the Earth. Areas in which the magnetic field strength is lower or more than average are known as areas with magnetic anomalies, which may be due to the presence of rocks that have a different magnetic characteristics
Where the magnetic anomaly is negative, it is indicative of a magnetic field strength reading that is lower than average magnetic field which is generally obtainable
Therefore, the correct option is indicated when a magnetometer measures intervals of magnetism that are weaker than expected
What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a
velocity of 3.0 m/s?
46.6666 that is the mass number
Explanation:
14 divided 3.0
The radius of Mars is 3397 km; and its mass is 6.42x10²³ kg. What is the acceleration due to gravity at an altitude of 485 km above the surface of Mars?
Answer:nfeergnjknrtgrth
Explanation:
Answer:
F = GMm/r^2
MA = GMm/r^2
A = GM/r^2
A = (6.67 * 10^-11)(6.42 * 10^23) / (3.37 * 10^6)^2
A = 3.77 m/s^2
Explanation:
much like a battery these generate electricity from chemical events
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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A thin partition divides a container of volume V into two parts. One side contains na moles of gas Ain a fraction fA of the container; that is, VA = fAV. The other side contains ng moles of a different gas B at the same temperature in a fraction fo of the container. The partition is removed, allowing the gases to mix. Find an expression for the change of entropy. This is called the entropy of mixing. Express your answer in terms of some or all of the variables na, fa, np, fb, and constant R.
The entropy change is positive and proportional to the number of moles of gas and the natural logarithm of 2 and the entropy of mixing is given by ΔS = -R(nAfa ln fa + nBfb ln fb).
How can the change in entropy be calculated when a partition is removed and two gases mix?The change in entropy when the partition is removed and the gases mix can be calculated using the formula:
ΔS = -R[na(fA ln fA + (1-fA) ln (1-fA)) + ng(fB ln fB + (1-fB) ln (1-fB))]
where R is the gas constant, na and ng are the number of moles of gases A and B, respectively, and fA and fB are the fractions of the container that they occupy before mixing.
The formula for entropy change is based on the idea that the number of ways in which the molecules can be arranged in the combined volume is greater than the number of ways in which they could be arranged if they were separated into two volumes. This increase in the number of possible microstates leads to an increase in entropy.
The first term in the equation represents the contribution of gas A to the entropy change, while the second term represents the contribution of gas B. The logarithmic terms arise from the fact that the number of microstates is proportional to the natural logarithm of the number of ways in which the molecules can be arranged.
In the case where the two gases are identical (i.e., na = ng and fA = fB), the entropy change simplifies to:
ΔS = R[na ln 2]
This result shows that the entropy change is positive and proportional to the number of moles of gas and the natural logarithm of 2.
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Part C how far ( dμ ) would the muon travel before it decayed, if there were no time dilation? Part D Now; let us conslder the elfects ol llme dilation. How far would Ihe muon travel, taking time dilation into account? Express your answer In kilometers to two significant figures.
Without time dilation, the muon would travel approximately 659.54 meters before decaying. Due to time dilation, the muon's lifetime appears longer to an observer on Earth.
Part C: Without time dilation, the average lifetime of a muon in its rest frame is approximately 2.2 microseconds (2.2 μs). In this case, we can use the formula:
dμ = vμ * tμ,
where
dμ is the distance traveled by the muon,
vμ is the velocity of the muon, and
tμ is the average lifetime of the muon.
Let's assume that the muon is traveling at a velocity close to the speed of light, which is approximately 299,792,458 meters per second (m/s). Converting the lifetime to seconds, we have tμ = 2.2 μs = 2.2 × 10^(-6) s. Plugging these values into the formula:
dμ = (299,792,458 m/s) * (2.2 × 10^(-6) s)
≈ 659.54 meters.
Therefore, without time dilation, the muon would travel approximately 659.54 meters before it decayed.
Part D: Now, let's consider the effects of time dilation. According to special relativity, when an object moves at a high velocity relative to an observer, time appears to run slower for the moving object.
From the muon's perspective, its average lifetime remains unchanged at 2.2 μs. However, for an observer on Earth, the muon's lifetime appears longer due to time dilation. The time dilation factor can be calculated using the Lorentz transformation:
t' = tμ / γ,
where
t' is the time experienced by the observer,
tμ is the muon's proper time (2.2 μs), and
γ is the Lorentz factor, given by γ = 1 / sqrt(1 - (vμ/c)^2).
Given that the muon's velocity is close to the speed of light (299,792,458 m/s), we can substitute these values into the formula to find γ.
γ = 1 / sqrt(1 - (299,792,458 m/s / 299,792,458 m/s)^2)
= 1 / sqrt(1 - 1)
= 1 / sqrt(0)
= 1 / 0 (undefined).
As the denominator approaches zero, γ approaches infinity. This means that time dilation becomes extremely significant as the muon approaches the speed of light.
For the observer on Earth, the muon's lifetime will appear significantly longer due to time dilation. However, from the muon's perspective, it experiences its proper lifetime of 2.2 μs.
To calculate the distance traveled by the muon, we can use the formula:
dμ = vμ * t',
where
dμ is the distance traveled by the muon (which we need to find),
vμ is the velocity of the muon (299,792,458 m/s), and
t' is the time experienced by the observer on Earth (the dilated time).
Since γ is extremely large, t' will be much larger than the muon's proper time. However, without knowing the specific velocity of the muon, it's not possible to calculate the exact time dilation factor or the distance traveled by the muon.
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A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end is allowed to fall. What is the angular acceleration as it is released
Answer:
The angular acceleration α = 14.7 rad/s²
Explanation:
The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod and L = length of rod = 4.00 m. α = angular acceleration of rod
Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.
So Iα = Wr
Substituting the value of the variables, we have
mL²α/12 = mgL/2
Simplifying by dividing through by mL, we have
mL²α/12mL = mgL/2mL
Lα/12 = g/2
multiplying both sides by 12, we have
Lα/12 × 12 = g/2 × 12
αL = 6g
α = 6g/L
α = 6 × 9.8 m/s² ÷ 4.00 m
α = 58.8 m/s² ÷ 4.00 m
α = 14.7 rad/s²
So, the angular acceleration α = 14.7 rad/s²
a neutral atom that consists of positive and negative charge is placed at location . this neutral atom has a known polarization . what is the separation length of the induced dipole? define the net electric field at a as 'e'. please answer as a formula; you may use the terms 'k', 'alpha', 'q', 'd', 'e', and 's'.
The separation length of induced dipole is \(E_{net}\) =\(\frac{kq}{d^{2} }\) ( 1 + \(\frac{s}{8d}\) ) leftward.
What is dipole moment?
A charge separation results in dipole moments. Dipole moments are caused by changes in electronegativity and can appear in ionic bonds between two ions or covalent bonds between atoms. The dipole moment increases with increasing electronegativity disparity. Another element affecting the size of the dipole moment is the distance between the charge separations. A molecule's polarity can be determined by its dipole moment.
We have,
Electric field due to dipole = E₂
As negative charge is nearer then the electric field will be toward the dipole.
E₁ = \(\frac{kqs}{r^{3} }\) = \(\frac{kqs}{(2d)^{3} }\) = \(\frac{kqs}{8d^{3} }\)
Now, electric field due to single charge -q = E₂
E₂ = \(\frac{kq}{r^{2} }\) = \(\frac{kq}{d^{2} }\)
\(E_{net}\) = E₁ + E₂ = \(\frac{kq}{d^{2} }\) ( 1 + \(\frac{s}{8d}\))
So, \(E_{net}\) = \(\frac{kq}{d^{2} }\) (1 + \(\frac{s}{8d}\) ) leftward.
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when the frictionless system shown above is accelerated by an applied force of magnitude f, the tension in the string between the blocks is:
The tension in the string between the blocks depends on the applied force F and the ratio of the masses mB/mA.
When the frictionless system is accelerated by an applied force of magnitude F, the tension in the string between the blocks can be determined using Newton's Second Law of Motion. The equation for this law is F = m*a, where F is the force, m is the mass, and a is the acceleration.
For the block connected to the applied force, let's call it block A, the force equation would be F = mA*aA. For the other block, block B, the force equation would be T = mB*aB, where T is the tension in the string. Since both blocks are connected by the string and moving together, their acceleration (aA and aB) is the same.
We can now express the tension T in terms of the applied force F, masses mA and mB, and the acceleration a:
T = mB*(F/mA).
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