Mercedis is going to have her car fixed

Answer:

Police officers, whether plain-clothed or uniformed, carry a variety of equipment with them on service calls. Police in uniform carry much more equipment than those in plain clothes, and members of special operations teams, such as SWAT and crowd-control units, carry even more, sometimes including full body armour complete with helmet, leg pads, and shield.

Step-by-step explanation:

hope it helped!

p.s it would be cool it you would give me brainliest

The paid amount including service fee, tip, and tax is $77.987.

the percentage is value per hundred.

bill value = $59.99

service fee = 3% of  $59.99 = 59.99*3/100 = $1.7997

tip = 20% of 59.99 =  $11.998

tax = 7 % of $59.99 = $4.1993

total payment = 59.99+1.7997+11.998+4.1993 = $77.987

therefore, the paid amount including service fee, tip, and tax is $77.987.

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Answer:

see explanation

Step-by-step explanation:

(a)

10x - 45 ← factor out 10 from each term

= 10(x - 4.5)

(b)

- 2x + 3 ← factor out - 2 from each term

= - 2(x - 1.5)

(c)

- x + 4 ← factor out - 1 from each term

= - 1(x - 4)

(d)

- x - 19 ← factor out - 1 from each term

= - 1(x + 19)

Thus the probability that a randomly selected woman from this university is 67.5 inches or taller is 0.16

Let x be the height of the woman. Mean height of women μ = 65 inches

Standard deviation σ = 2.5 inches

By theorem if X ~ N( 65 , 2.5² )

then normal distribution Z = X - μ / σ ~ N(0,1)

68% of women have a height that falls within 1 standard deviation of the mean. That is P ( 62.5 ≤X ≤ 67.5) = 0.68

From symmetry and using probability, we can find the area under the bell-shaped curve for this interval. This area to the right of 67.5 under the bell-shaped curve ultimately gives us that the probability a randomly selected woman from the university is 67.5 inches or taller. This probability = 0.16

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Th length of the enclosed area of the scale model in inches is 32 inches.

Joseph and Raquel are building a scale model of the Alamo Mission for their Texas history project using a scale in which 2 inches represents 30 feet.

The enclosed area of the Alamo Mission was 480 feet long and 160 feet wide.

The length of the enclosed area of the scale model in inches can be calculated as follows:

30 feet = 2 inches

480 feet = ?

cross multiply

length of the enclosed area = 480 × 2 / 30

length of  the enclosed area = 960 / 30

length of the enclosed area = 32 inches

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Answer:

do R-P-R-S-P-P-R-P

Step-by-step explanation:

This can be derived using Chebyshev's inequality, as Chebyshev's inequality and the law of large numbers are different in nature.

Let M_n be the maximum of n independent U(0, 1) random variables.

To derive the exact expression for P(|M_n − 1| > ε), we need to follow the below steps:

First, we determine P(M_n ≤ 1-ε). The probability that all of the n variables are less than 1-ε is (1-ε)^n

So, P(M_n ≤ 1-ε) = (1-ε)^n

Similarly, we determine P(M_n ≥ 1+ε), which is equal to the probability that all the n variables are greater than 1+\epsilon

Hence, P(M_n ≥ 1+ε) = (1-ε)^n

Now we can write P(|M_n-1|>ε)=1-P(M_n≤1-ε)-P(M_n≥1+ε)

P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n.

Thus we have derived the exact expression for P(|M_n − 1| > ε) as P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n

Now, to show that $lim_{n\to\∞}$ P(|M_n - 1| > ε) = 0 , we can use Chebyshev's inequality which states that P(|X-\mu|>ε)≤{Var(X)/ε^2}

Chebyshev's inequality and the law of large numbers are different in nature as Chebyshev's inequality gives the upper bound for the probability of deviation of a random variable from its expected value. On the other hand, the law of large numbers provides information about how the sample mean approaches the population mean as the sample size increases.

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Let the smaller angle be

The larger angle is 4 times bigger than the smaller angle means

Concept:

The sum of two or more angles on a straight line is always 180°

Therefore,

By substituting the value of y=4x in the equation above, we will have

substitute the value of x= 36° in y=4x to find the value of the bigger angle

Hence,

The larger angle is =144 °

OPTION D IS THE CORRECT ANSWER

An association class is frequently required for a many-to-many relationship.

In object-oriented programming, an association class is a class that is used to represent an association between two or more other classes. An association class is typically used when the relationship between the other classes is many-to-many, which means that each instance of one class can be associated with multiple instances of another class, and vice versa.

For example, consider a database that stores information about students and the courses they are enrolled in. Each student can be enrolled in multiple courses, and each course can have multiple students.

To represent this many-to-many relationship between students and courses, we can create an association class called "Enrollment" that has attributes such as the date of enrollment and the grade received. The Enrollment class would have a many-to-one relationship with both the Student class and the Course class.

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An association class is frequently required for a "c. many to many" relationship. therefore, option c. many to many is correct.

In this type of relationship, multiple instances of one class can be associated with multiple instances of another class.

The association class helps to capture additional information about the relationship between these instances.

An association class is most commonly required for a many-to-many relationship between two classes.

a relationship that explains the causes of the relationship and the rules that control it between two classifiers, such as

classes or use cases.

An association class is frequently required for a "c. many to many" relationship. therefore, option c. many to many is correct.

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The equation representing visual models is z+1/5=3/5.

Since it is given in the question that the hanger image represents a balanced equation therefore equating LHS with RHS it can be written as follows.

LHS = 1/5 + z

RHS = 3/5+ z

Equating both the equations it can be written as

LHS = RHS

1/5+z=3/5

or z=3/5-1/5

Therefore, z=2/5

Hence, for z=2/5 the hanger will represent a balanced equation.

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Mia works at a skateboard shop and she gets 25 dollars per month

y -intercept = $200

Since at y -intercept x = 0

So coordinate is : (0,200)

x -intercept = 8 months

Since, at x intercept y = 0

So, coordinate is (8, 0)

The general equation of line is express as :

Substitute the coordinates : (8,0) (0,200)

Equation : y = 200 - 25x

Substitute the coordinates on the graph :

So, the graph of the equation y = 200 - 25x is

The fractions which is greater than   \(\frac{2}{4}\)  , but denominator of 6 are \(\frac{4}{6} ,\frac{5}{6},\frac{6}{6}\) .

What is fraction?

The fraction contains both numerator and the denominator. The top number is known as the numerator, and the bottom number is known as the denominator. The numerator indicated the parts which is taken from whole portion.

Here Amount of Juice in Pedro glass is \(\frac{2}{4}\)

So, \(\frac{2}{4} = \frac{1}{2}\)

Now, we want fraction which is greater than  \(\frac{2}{4}\)  , but denominator of 6.

So ,the fraction having denominator 6 are,

\(\frac{1}{6},\frac{2}{6},\frac{3}{6} = \frac{1}{2} , \frac{4}{6} ,\frac{5}{6},\frac{6}{6}\)

Hence the fractions which is greater than   \(\frac{2}{4}\)  , but denominator of 6 are \(\frac{4}{6} ,\frac{5}{6},\frac{6}{6}\) .

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The Rounding this number to the nearest whole number, the surface area of the monument is approximately 1280 square feet.To find the surface area of the monument, we need to calculate the surface area of each component and then add them together.

The rectangular prism has a length, width, and height of 16 feet. Its surface area can be found using the formula:

Surface area of rectangular prism = 2lw + 2lh + 2wh

Plugging in the values, we get:

Surface area of rectangular prism = 2(16)(16) + 2(16)(16) + 2(16)(16) = 512 square feet.

The square pyramid has a base length of 16 feet and a slant height of 16 feet as well. The formula for the surface area of a square pyramid is:

Surface area of square pyramid = base area + (1/2)(perimeter of base)(slant height)

The base area is (16)(16) = 256 square feet, and the perimeter of the base is 4 times the length of one side, which is 4(16) = 64 feet. Plugging in these values, we get:

Surface area of square pyramid = 256 + (1/2)(64)(16) = 768 square feet.

Adding the surface areas of the rectangular prism and the square pyramid, we get:

Total surface area of the monument = 512 + 768 = 1280 square feet.

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Note the full question may be :

A swimming pool in the shape of a rectangular prism measures 10 meters in length, 5 meters in width, and 2 meters in height. The pool is surrounded by a deck that extends 1 meter from each side of the pool. What is the total surface area of the pool and the deck combined, rounded to the nearest whole number?

Please calculate the total surface area of the pool and deck, including all sides.

Answer:

A, B, and D

Step-by-step explanation:

When Tracey pours all the water from the smaller 5-inch cube container into the larger 7-inch cube container, the water will be approximately 7 inches deep in the larger container.

To find out how deep the water will be in the larger container, we need to consider the volume of water transferred from the smaller container. Since both containers are cube-shaped, the volume of each container is equal to the length of one side cubed.

The volume of the smaller container is 5 inches * 5 inches * 5 inches = 125 cubic inches.

When Tracey pours all the water from the smaller container into the larger container, the water completely fills the larger container. The volume of the larger container is 7 inches * 7 inches * 7 inches = 343 cubic inches.

Since the water fills the larger container completely, the depth of the water in the larger container will be equal to the height of the larger container. Since all sides of the larger container have the same length, the height of the larger container is 7 inches.

Therefore, the water will be approximately 7 inches deep in the larger container.

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We have to find the area under the graph but since we are not given the graph ,So let's learn how it is done. To estimate the area under the graph of function f from x, you can use rectangles. Here's how you can do it:

Step 1: Divide the interval [a, b] into six equal subintervals.
Step 2: Calculate the width of each rectangle by dividing the total width of the interval [a, b] by the number of rectangles (in this case, 6).
Step 3: For each subinterval, find the value of the function f at the right endpoint of the subinterval.
Step 4: Multiply the width of the rectangle by the value of the function at the right endpoint to find the area of each rectangle.
Step 5: Add up the areas of all six rectangles to estimate the total area under the graph of f from x.

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Answer: 2 pair of leggings is $24 she has $36 so she can buy 1 shirt

Answer: For plato users

Plot the numbers on your number line

Firstly plot =52

Secondly plot = 64

Step-by-step explanation:

Answer:

Option 3 and 4.

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

\(z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation\)

Given that mean (μ) = 82, standard deviation (σ) = 5

1) For x = 74:

\(z=\frac{x-\mu}{\sigma} \\\\z=\frac{74-82}{5} =-1.6\)

Option 1 is incorrect

2) For x < 87

\(z=\frac{x-\mu}{\sigma} \\\\z=\frac{87-82}{5} =1\)

From the normal distribution table, P(x < 87) = P(z < 1) = 0.8413 = 84.13%

Option 2 is incorrect

3) For x = 95:

\(z=\frac{x-\mu}{\sigma} \\\\z=\frac{95-82}{5} =2.6\)

Option 3 is correct

4) For x < 77

\(z=\frac{x-\mu}{\sigma} \\\\z=\frac{77-82}{5} =-1\)

From the normal distribution table, P(x < 77) = P(z < -1) = 0.16 = 16%

Option 4 is correct

5) For x > 92

\(z=\frac{x-\mu}{\sigma} \\\\z=\frac{92-82}{5} =2\)

From the normal distribution table, P(x > 92) = P(z > 2) = 1 - P(z < -2) = 1 - 0.9772 = 0.0228 = 2.28%

Option 5 is incorrect

The lower class limits for the given frequency distribution are 20, 25, 30, 35, 40, 45, and 50. The upper class limits are 24, 29, 34, 39, 44, 49, and 54.

The class width is 5 for all classes. The class midpoints are 22, 27, 32, 37, 42, 47, and 52. The class boundaries are 19.5, 24.5, 29.5, 34.5, 39.5, 44.5, 49.5, and 54.5. There are a total of 83 individuals included in the summary.

To calculate the class midpoints and class boundaries, we use the following formulas. The class midpoint (x) is calculated by adding the upper and lower class limits and dividing by two. The class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class limit. For example, for the first class, the lower class limit is 20 and the upper class limit is 24. The class midpoint is (20 + 24)/2 = 22. The class boundaries are 19.5 and 24.5.

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To find the percent of something, turn the percent into a decimal and multiply (move the decimal place 2 places left, e.g. 53% = .53)

The unit price of the pecans is $0.815 per ounce (rounded to three decimal places).

To calculate the unit price, we divide the total cost of the item by the quantity purchased. In this case, Averi bought a 6-ounce can of pecans for $4.89.

To find the unit price, we divide the total cost ($4.89) by the quantity purchased (6 ounces):

Unit price = Total cost / Quantity purchased

= $4.89 / 6 ounces

To simplify the unit price, we can divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4.89 and 6 is 3.

Dividing both the numerator and denominator by 3, we get: Unit price = ($4.89 / 3) / (6 ounces / 3)

= $1.63 / 2 ounces

Therefore, the unit price of the pecans is $0.815 per ounce (rounded to three decimal places). This means that Averi paid approximately $0.815 for each ounce of pecans she purchased.

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We have to determine whether the given series converges or diverges. The given series is as follows: `(n+4)! / 4!(n!)` Let's use the ratio test to find out if this series converges or diverges.

The Ratio Test: It is one of the tests that can be used to determine whether a series is convergent or divergent. It compares each term in the series to the term before it. We can use the ratio test to determine the convergence or divergence of series that have positive terms only. Here, a series `Σan` is convergent if and only if the limit of the ratio test is less than one, and it is divergent if and only if the limit of the ratio test is greater than one or infinity. The ratio test is inconclusive if the limit is equal to one. The limit of the ratio test is `lim n→∞ |(an+1)/(an)|` Let's apply the Ratio test to the given series.

`lim n→∞ [(n+5)! / 4!(n+1)!] * [n!(n+1)] / (n+4)!` `lim n→∞ [(n+5)/4] * [1/(n+1)]` `lim n→∞ [(n^2 + 9n + 20) / 4(n^2 + 5n + 4)]` `lim n→∞ (n^2 + 9n + 20) / (4n^2 + 20n + 16)`

As we can see, the limit exists and is equal to 1/4. We can say that the given series converges. The series converges. To determine the convergence of the given series, we use the ratio test. The ratio test is a convergence test for infinite series. It works by computing the limit of the ratio of consecutive terms of a series. A series converges if the limit of this ratio is less than one, and it diverges if the limit is greater than one or does not exist. In the given series `(n+4)! / 4!(n!)`, the ratio test can be applied. Using the ratio test, we get: `

lim n→∞ |(an+1)/(an)| = lim n→∞ [(n+5)! / 4!(n+1)!] * [n!(n+1)] / (n+4)!` `= lim n→∞ [(n+5)/4] * [1/(n+1)]` `= lim n→∞ [(n^2 + 9n + 20) / 4(n^2 + 5n + 4)]` `= 1/4`

Since the limit of the ratio test is less than one, the given series converges.

The series converges to some finite value, which means that it has a sum that can be calculated. Therefore, the answer is a).

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Answer:

44 :

Step-by-step explanation:

77/175 = 0.44

0.44x100

Answer:

428

Step-by-step explanation:

Plug the given values into the equation:

-4+9[-3(-6)+6(5)]

Remember that two negatives (in multiplication) make a positive

-4+9[18+30]

-4+9[48]

-4+432

428

Accοrding tο the data, cοpper has a density οf 3 g/cm³.

A basic fοrmula fοr vοlumes is length, breadth, and height, as οppοsed tο length, width, and height fοr the surface οf a rectangle. It dοesn't matter hοw yοu reference tο the variοus dimensiοns; yοu cοuld, fοr instance, use "depth" instead οf "height" withοut the calculatiοn changing.

We must first determine the vοlume οf a cοpper blοck in οrder tο determine its density. A rectangular blοck's vοlume is determined by:

Vοlume = Length x Width x Height

The dimensiοns in this instance are 8 cm lοng, 5 cm wide, and 4 cm high. As a result, the blοck's vοlume is:

Vοlume = 8 cm x 5 cm x 4 cm = 160 cm³

Then, we can use the fοllοwing fοrmula tο get cοpper's density:

Density = Mass / Vοlume

The blοck has a stated mass οf 480 g. Hence, cοpper has the fοllοwing density:

Density = 480 g / 160 cm³ = 3 g/cm³

Sο, the density οf cοpper is 3 g/cm³.

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Answer:

The expression is equivalent to\(A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}\) is  \(\frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}\).

Step-by-step explanation:

The expression provided is:

\(A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}\)

Simplify the expression A as follows:

\(A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}\)

   \(=\sqrt[4]{\frac{24}{128}\times x^{(6-4)}\times y^{(1-5)}}\\\\=\sqrt[4]{\frac{3}{16}\times x^{2}\times y^{-4}}\\\\=[\frac{3}{16}\times x^{2}\times y^{-4}]^{1/4}\\\\=[\frac{3}{16}]^{1/4}\times x^{(2\times (1/4))}\times y^{(-4\times (1/4))}\\\\=\frac{\sqrt[4]{3}}{2}}\times x^{1/2}\times y^{-1}\\\\=\frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}\)

Thus, the expression is equivalent to\(A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}\) is  \(\frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}\).

Equivalent expressions are expressions that have equal values

The equivalent expression of \(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}\) is \(\frac 1{2y}\sqrt[4]{ 3x^2}}\)

The expression is given as:

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}\)

Divide 24 and 128 by 8

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \sqrt[4]{ \frac{3x^6y}{16x^4y^5}}\)

Take 4th root of 16

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \frac 12\sqrt[4]{ \frac{3x^6y}{x^4y^5}}\)

Apply law of indices, to simplify the fraction

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \frac 12\sqrt[4]{ 3x^{6-4}y^{1-5}}\)

Simplify

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \frac 12\sqrt[4]{ 3x^{2}y^{-4}}\)

Rewrite as:

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \frac 12\sqrt[4]{ \frac{3x^{2}}{y^4}}\)

Take 4th root of y^4

\(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}= \frac 1{2y}\sqrt[4]{ 3x^2}}\)

Hence, the equivalent expression of \(\sqrt[4]{ \frac{24x^6y}{128x^4y^5}}\) is \(\frac 1{2y}\sqrt[4]{ 3x^2}}\)

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Answer:

True

Step-by-step explanation:

The results of the BCD addition for the two given numbers are a) 1001 0100 + 0110 0111 = 1111 1011 and b) 1001 1000 + 0001 0010 = 1010 1010

The first step in BCD addition is to add the two numbers together, just like you would add any two binary numbers. However, there are a few special cases to watch out for. If the sum of two digits is greater than 9, you need to add 6 to the sum. This is because the BCD code only has 10 possible values, so any number greater than 9 will be invalid.

In the first example, the sum of the first two digits is 10, so we add 6 to get 16. The sum of the next two digits is also 10, so we add 6 to get 16. The final digit is 1, so the overall sum is 1111 1011.

In the second example, the sum of the first two digits is 11, so we add 6 to get 17. The sum of the next two digits is 10, so we add 6 to get 16. The final digit is 0, so the overall sum is 1010 1010.

To verify the results, we can convert the BCD numbers to decimal and add them together. In the first example, the BCD number 1001 0100 is equal to 176 in decimal. The BCD number 0110 0111 is equal to 103 in decimal. When we add these two numbers together, we get 279 in decimal. This is the same as the BCD number 1111 1011.

In the second example, the BCD number 1001 1000 is equal to 160 in decimal. The BCD number 0001 0010 is equal to 10 in decimal. When we add these two numbers together, we get 170 in decimal. This is the same as the BCD number 1010 1010.

Therefore, the results of the BCD addition are correct.

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