McKenna was asked to write the following expression in standard form.
When writing the expression in standard form, McKenna made a mistake.
a. McKenna made her first mistake in .
b. The correct expression in standard form is .
3 − 5(3a + 6)
3 − 5(3a + 6)
3 + (−5)(3a + 6)
−2(3a + 6)
−6a + (−12)
−6a − 12
Step 1
Step 2
Step 3
Step 4
Answers
a) The step in which McKenna made her first mistake is given as follows: Step 4.
b) The correct simplified expression in standard form is given as follows: -15a - 15.
How to simplify the expression?The expression in this problem is defined as follows:
3 − 5(3a + 6)
On the third step, the expression is given as follows:
3 + (−5)(3a + 6)
And on the fourth step, the expression is given as follows:
−2(3a + 6).
This is where the mistake happened, as the multiplication takes precedence over the subtraction.
Then to obtain the correct expression the first step is applying the distributive property, as follows:
3 − 5(3a + 6) = 3 - 15a - 18.
Then the like terms 3 and -18 are combined to obtain the correct simplified expression, as follows:
3 - 15a - 18 = -15a - 15.
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Related Questions
Where in real life we come across something that is more than 100 %example 135 give 3 examples
Answers
Real life scenarios where percentage exceeds 100% include :
Profit change Inflation Population growth100% is used to represent the total percentage of a whole. Such that the highest percentage value of a whole such as the number of people who reside in a country, the mark obtainable in a examination and so on.
The mark obtainable in an examination cannot exceed 100%
However, there are circumstances whereby percentage values are represented as more than 100%.
These scenarios usually involves instances where values are compared and expressed as percentages.
Comparing the change in price of goods between two periods :
A good that cost $20 in 2005 which is now being sold at $50. The percentage change in price in this scenario will be :
[($50 - $20) / $20] × 100% = (30/20 × 100%) = 150%
Similary ;
In Finance, profit comparison usually involves using percentages greater than 100%.
For instance ;
if a firm makes double it previous year's profit, the would be said to have made an 100% increase from previous year's profit.
If the profit is 3 times, then that would mean a 200% profit increase.
For example :
Previous year's profit = $50,000
This year's profit = $150,000
Percentage profit increase :
[($150,000 - $50,000) / $50,000] × 100%
($100,000 / $50000) × 100%
2 × 100% = 200%
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A 13 km 13km13, start text, k, m, end text stretch of road needs repairs. Workers can repair 3 1 2 km 3 2 1 km3, start fraction, 1, divided by, 2, end fraction, start text, k, m, end text of road per week. How many weeks will it take to repair this stretch of road?
Answers
you can start by dividing the total length of the road by the distance that can be repaired per week:
13 km ÷ 3 1/2 km/week = 3.71 weeks
Rounding up, it will take 4 weeks to repair the entire 13 km stretch of road.
For every 10 children 4 wore glasses. There were 30 children. How many did not wear glasses?
Answers
Answer:
18
Step-by-step explanation:
If 4 out of 10 wore glasses, then 6 out of 10 did not wear classes. This would be 60% or .6
.6x30 = 18
-5b = -20 b= need help with homwork
Answers
Answer:
b = 4
Step-by-step explanation:
you must divide both sides of the equation by -5 to get b by itself. division cancels out multiplication but also keeps both sides equal
b = -20/-5
b = 4
hope this helped
4.8 + 2.2w − 1.4w + 2.4
Answers
Answer:
7.2 + 0.8w
Step-by-step explanation:
combine like terms. Like terms have same variable with same power.
2.2w and (-1.4w) are like terms & 4.8 and 2.4 are like terms.
4.8 + 2.2w - 1.4w + 2.4 = 4.8 + 2.4 + 2.2w - 1.4w
= 7.2 + 0.8w
Answer:
7.2+0.8w
Step-by-step explanation:
4.8+2.2w-1.4w+2.4
4.8+2.4=7.2 2.2w-1.4w=0.8w
(08.03|08.04 HC)
For the regions A and B shown in the graph:
Part A: Discuss the limits of integration. (3 points)
Part B: Set up an integral expression that represents the total area. (4 points)
Part C: Calculate the total area. (3 points)
Answers
The total area from the graph is 2.737.
What is area?Area is the amount of space occupied by a two-dimensional figure. In other words, it is the quantity that measures the number of unit squares that cover the surface of a closed figure. The standard unit of area is square units which is generally represented as square inches, square feet, etc.
First of all, lets calculate the points of intersection (P, Q, R)
x²+3=(x+2) +5
x²-2=√(x+2)
x⁴+4-4x²=x+2
x⁴-4x²-x+2=0
(x-2)(x³+2x²-1)=0
(x-2)(x+1)(x²+x-1)=0
x=2, -1, -1±√(1+4)/2
Clearly, the x-coordinate of Q is -1, P is -1-√5/2, R is -1+√5/2, S is 2
So the limit of integration will be
P( (-1-√5)/2, (-1-√5/2)² +3)=P((-1-√5)/2, (3+√5/2))
Q(-1, (-1)²+3)=Q(-1, 4)
Area A:
\(\int\limits^\frac{3+\sqrt{5} }{2} _4 {-\sqrt{-y-3}-((y-5)^2 -2)} \, dx\)
= \([\frac{-(y-3)^\frac{3}{2} }{\frac{3}{2} }-\frac{(y-5)^3}{3}+3y]^{\frac{3+\sqrt{5} }{2} }_4\)
= 2.07
Area B:
\(\int\limits^\frac{-1+\sqrt{5} }{2} _4 {-\sqrt{x+2}+5-(x^2+3)} \, dx\)
= \([\frac{-(x+2)^\frac{3}{2} }{\frac{3}{2} }+5x-\frac{x^3}{3}-3x]^{\frac{-1+\sqrt{5} }{2} }_{-1}\)
= 0.667
Total area = 2.07+0.667
= 2.737
Therefore, the total area from the graph is 2.737.
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What is the meaning of "the universal class V is a proper class"?
Answers
The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.
We have,
In set theory, a proper class is a class that is not a set.
A class is a collection of objects, and a set is a class that can be a member of other classes.
On the other hand, a proper class cannot be a member of another class.
The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.
This means that V cannot be an element of any other class or set within the context of the set theory being considered.
The concept of proper classes is used to prevent paradoxes and contradictions that can arise when unrestricted comprehension is allowed in set theory.
Thus,
The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.
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The solution of the equation 3x + 4 =1 is a) 1 b) 0 c) -1 d) 2
Answers
Hello!
3x + 4 = 1
3x + 4 - 4 = 1 - 4
3x = -3
3x/3 = -3/3
x = -1
The solution of the equation 3x + 4 = 1 is -1.
The answer is:
C) x = -1
Work/explanation:
To solve this equation, I subtract 4 from each side:
\(\sf{3x+4=1}\)
Subtract :
\(\sf{3x=-3}\)
Divide each side by 3:
\(\sf{x=-1}\)
Hence, C is correct.
Solve for r 1+3r>10 please I need this solved aspap
Answers
The solution to the inequality 1 + 3r > 10 is r > 3.
This means that any value of r greater than 3 will satisfy the inequality.
To solve the inequality 1 + 3r > 10, we need to isolate the variable r on one side of the inequality sign.
Let's begin by subtracting 1 from both sides of the inequality:
1 + 3r - 1 > 10 - 1
This simplifies to:
3r > 9
Next, we can divide both sides of the inequality by 3 to solve for r:
(3r)/3 > 9/3
This simplifies to:
r > 3
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7. Mrs. Dyson asked her students to draw a figure with a perimeter of 4x+4.
Shown below are 4 drawings made by her students. (They are not drawn to
scale.) Which one is NOT correct? *
Answers
Answer:
the answer is b
Step-by-step explanation:
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Write the quotient
6+8i
2i
Answers
The quotient when 6+8i is divided by 2i is given by -3i+4.
We know that, complex number \(i^1=-1\).
Given the divisor is = 2i and dividend is = 6+8i
Dividing the dividend by divisor we get,
(6+8i)/2i = 6/2i + 8i/2i = 3/i + 4 \(=\frac{3i}{i^2}+4\) = 3i/(-1)+4 = -3i+4
Hence the quotient is = -3i+4.
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Use the quadratic formula to solve x2 – 3x - 2 = 0.
Answers
Answer:
x = 2 , 1
Step-by-step explanation:
Answer:
2.5 or 3.5
Step-by-step explanation:
The quadratic formula is \(x = -b +/- \frac{\sqrt{b^2 + 4ac}}{2a}\) .
a, b, and c are determined by the terms in the formula ax^2 + bx + c
They gave you the equation x^2 - 3x - 2, which fits that formula. a is 1, b is -3, and c is -2. So plug those values into the equation:
\(x = -(-3) +/- \frac{\sqrt{(-3)^2 + 4(1)(-2)}}{2(1)}\)
\(x = 3 +/- \frac{\sqrt{9 -8}}{2}\)
\(x = 3 +/- \frac{\sqrt{1}}{2}\)
\(x = 3 +/- \frac{1}{2}\)
So x is 3 plus or minus -1/2. 3 plus -1/2 is 2.5
3 minus -1/2 is 3.5
So the 2 possible x values are 2.5 and 3.5.
x²+x-6=-4 in quadratic formula please help I been struggling on this one
Answers
Answer:
x = 1, −2
Step-by-step explanation:
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula. The answers are x = 1, −2.
Hope this helps:)
Which sequence shows the numbers in order from least to greatest?
A. -2.14<3.16227766017<2.8
B. 2.8<3.16227766017<2.14
C. 2.14<3.16227766017 <2.8
D. 2.14<2.8<3.16227766017
Answers
The sequence that shows the numbers in order from least to greatest is D. 2.14 < 2.8 < 3.16227766017.
The sequence that shows the numbers in order from least to greatest is D. 2.14 < 2.8 < 3.16227766017.What is the meaning of the inequality symbols?The inequality symbols are mathematical symbols that are used to compare two values.
They indicate the relationship between two values that are not equal to each other. Here are the inequality symbols:
< (less than)≤ (less than or equal to)> (greater than)≥ (greater than or equal to)What is the meaning of the sequence?
A sequence is a set of numbers arranged in a particular order. The order of the numbers in a sequence can be from smallest to largest or largest to smallest.
The sequence D. 2.14 < 2.8 < 3.16227766017 is arranged from smallest to largest because the first number in the sequence, 2.14, is the smallest, and the last number in the sequence, 3.16227766017, is the largest.
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am I right for part A. And please help me with B
Answers
a) The radius of the sphere is given as follows: 27.13 ft.
b) The surface area can be checked as follows: S = 4 x 3.14 x 27.13² = 9244.
How to obtain the surface area?The surface area for a sphere of radius r is given by the equation presented as follows:
S = 4πr².
The surface area for this problem is given as follows:
9244 ft².
Hence the radius is given as follows:
\(r = \sqrt{\frac{9244}{4 \times 3.14}}\)
r = 27.13 ft.
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The 5-gallon bucket of paint that Kenzie bought from the hardware store weighs 55 pounds. CJ is buying 1 gallon of paint.
How many pounds does 1 gallon of paint weigh?
Answers
Answer:
n
Step-by-step explanation:
please help me find the slope of the line graphed below ! (will mark brainliest) and spammers will be reported.
Answers
Answer:
Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities
Answer:
Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities
3x+50
2x=20
x+48
95
findx
Answers
Step-by-step explanation:
what do you mean by 95 I didn't get
can you explain it in the comment section
Select the correct answer.
Each statement describes a transformation of the graph of f(x) = x. Which statement correctly describes the graph of g(x) if g(x) = f(x - 11)?
A. It is the graph of f(x) where the slope is increased by 11.
It is the graph of f(x) translated 11 units to the left.
It is the graph of f(x) translated 11 units up.
It is the graph of f(x) translated 11 units to the right.
B.
C.
OD.
Answers
The correct answer is C. It is the graph of f(x) translated 11 units to the left.
The correct answer is:
C. It is the graph of f(x) translated 11 units to the left.
When we have a function of the form g(x) = f(x - a), it represents a horizontal translation of the graph of f(x) by 'a' units to the right if 'a' is positive and to the left if 'a' is negative.
In this case, g(x) = f(x - 11), which means that the graph of f(x) is being translated 11 units to the right. However, the answer options do not include this specific transformation. The closest option is option C, which states that the graph of g(x) is translated 11 units to the left.
The graph of f(x) = x is a straight line passing through the origin with a slope of 1. If we apply the transformation g(x) = f(x - 11), it means that we are shifting the graph of f(x) 11 units to the right. This results in a new function g(x) that has the same shape and slope as f(x), but is shifted to the right by 11 units.
Therefore, the correct answer is C. It is the graph of f(x) translated 11 units to the left.
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Winnie wants to find the zeros of the function
g(x) = 8(x) = 8x2 + 14x – 15. Which of the following equations could Winnie use to find the zeros of
g(x)?
1.) (X - 5)(8x + 3) = 0
2.) (x + 1)(8x – 15) = 0
3.) (4x + 15)(2x - 1) = 0
4.) (4x – 3)(2x + 5) = 0
Answers
g(x) = 8(x) = 8x2 + 14x – 15. Which of the following equations could Winnie use to find the zeros of
g(x)?
1.) (X - 5)(8x + 3) = 0
2.) (x + 1)(8x – 15) = 0
3.) (4x + 15)(2x - 1) = 0
4.) (4x – 3)(2x + 5) = 0
2.x+1)
A Mars rover traveled from point a to point b at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rover to travel at a speed of 2.5 cm/sec, and increased travel time by 15 minutes. What is the distance between point a and point b.
Answers
At a speed of 4 cm/sec, the distance between point a and point b is equal to 6,000 cm or 60 m.
How to calculate the speed?Mathematically, the speed of a physical object can be calculated by using this formula;
Speed = distance/time
Making time the subject of formula, we have:
Time = distance/speed
Let d represent the distance travelled by Mars rover.Let t represent the time taken.At a speed of 4 cm/sec, the time taken is given by:
Time = distance/speed
t = d/4
4t = d .....equation 1.
At a speed of 2.5 cm/sec, the time taken is given by:
Note: 1 minute is equal to 60 seconds.
(t + 15 × 60) = d/2.5
t + 900 = d/2.5
Cross-multiplying, we have:
2.5(t + 900) = d
2.5t + 2250 = d ......equation 2.
Equating equation 1 and equation 2, we have:
4t = 2.5t + 2250
4t - 2.5t = 2250
1.5t = 2250
Time, t = 2250/1.5
Time, t = 1,500 seconds
Now, we can determine the distance between point a and point b:
Distance, d = 4t
Distance, d = 4 × 1,500
Distance, d = 6,000 cm
In meters we have:
Distance, d = 6,000/100
Distance, d = 60 meters.
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What value of x is in the solution set of 8x-6 > 12 + 2x?
3
5
Answers
A man wants to mesure the height of a nearby building. He places a 7ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building. The total length of the building’s shadow is 162ft, the pole casts a shadow that is 5.5ft long. How tall is the building? Round your answer to the nearest foot.
Answers
The height of the building is approximately 227 feet.
In the given question, a man wants to measure the height of a nearby building. He places a 7 ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building.
The total length of the building's shadow is 162 ft, and the pole casts a shadow that is 5.5 ft long. We have to determine the height of the building.The given situation can be explained with the help of a diagram.
As shown in the figure above, let AB be the building and CD be the 7 ft pole. The height of the building is represented by the line segment AE, which is to be determined. Let the length of the shadow of the pole be CD and that of the building be BD.
Therefore, the length of the total shadow will be BC or CD + BD.According to the question, the shadow of the pole is exactly covered by the shadow of the building. This implies that the two triangles AEF and CDF are similar. Hence, the corresponding sides are proportional. Therefore, we have:AE/EF = CD/DF
On substituting the values from the given data, we get:
AE/(EF + 5.5) = 7/5.5.... (1)
Similarly, we can write from the given data:
BD/DF = 162/5.5.... (2)
From equations (1) and (2), we can write:
AE/(EF + 5.5) = BD/DF => AE/(EF + 5.5) = 162/5.5.... (3)
On solving the above equation for AE, we get:
AE = (7/5.5) × (162/5.5 - 5.5)≈ 226.6 ft
Therefore, the height of the building is approximately 227 feet.
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How do I uses these
Answers
Answer:
To understand a graph you need to interpret a graph or a chart, read the title, look at the key, read the numbers and lables. then study the graph to understand what it shows. read the title graph or chart. the title tells what information is being displayed.
Step-by-step explanation:
If DA is a diameter of OZ and m/DZC = (2x)°, find m/CZB.A. 22°B. 58°C. 69°D. 73°
Answers
Since DA is the diameter the formed angle equals 180
since DZC=2x
then
\(180=DZC+CZB+BZA\)\(180=(2x)+(7x-4)+85\)\(180-85+4=9x\)\(x=\frac{99}{9}\)\(x=11\)since x= 11
then the measure of the angle CZB is given by
\(7(11)-4\)\(mCZB=73\)measure of the angle CZB is 73°
Correct answer option D
73°
If f(x)=3x-5, g(x)=7x-3, find (f+g)(x) and (f-g)(x
Answers
Answer:
Step-by-step explanation: To find (f+g)(x), we simply add the two functions:
(f+g)(x) = f(x) + g(x)
= (3x - 5) + (7x - 3)
= 10x - 8
Therefore, (f+g)(x) = 10x - 8.
To find (f-g)(x), we subtract g(x) from f(x):
(f-g)(x) = f(x) - g(x)
= (3x - 5) - (7x - 3)
= -4x - 8
Therefore, (f-g)(x) = -4x - 8.
Can someone help me please i really need help with this.
use the Remainder Theorem and synthetic division please
Answers
The value of the functions are,
⇒ f (- 10) = 20201
⇒ f (2) = 17
⇒ f (3) = 143
What is mean by Function?A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
Given that;
The value of function is,
⇒ f (x) = 2x⁴ + x² - 10x + 1
Now, We can find all the values as;
At x = - 10;
⇒ f (x) = 2x⁴ + x² - 10x + 1
⇒ f (- 10) = 2 (- 10)⁴ + (- 10)² - 10 (- 10) + 1
⇒ f (- 10) = 20000 + 100 + 100 + 1
⇒ f (- 10) = 20201
At x = 2;
⇒ f (x) = 2x⁴ + x² - 10x + 1
⇒ f (2) = 2 (2)⁴ + (2)² - 10 (2) + 1
⇒ f (2) = 32 + 4 - 20 + 1
⇒ f (2) = 17
At x = 3;
⇒ f (x) = 2x⁴ + x² - 10x + 1
⇒ f (3) = 2 (3)⁴ + (3)² - 10 (3) + 1
⇒ f (3) = 162 + 9 - 30 + 1
⇒ f (3) = 143
Thus, The value of the functions are,
⇒ f (- 10) = 20201
⇒ f (2) = 17
⇒ f (3) = 143
Learn more about the function visit:
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Can you prove these similar triangle step by step?
Answers
Answer:
If an angle of one triangle is congruent to the corresponding angle of another triangle and the lengths of the sides including these angles are in proportion, the triangles are similar. the remaining sets of angles will be congruent and the remaining corresponding sides will be in proportion.
hopes this helps
Step-by-step explanation:
Zayan is putting ribbon around a picture of her dog. The picture is 300 millimeters wide and 150 millimeters tall. How many meters of ribbon will she need?
Answers
Answer:
150mm*300mm is equal to 45000mm and 1m is equal to 1000mm therefore 45000mm/1000 is equal to 45m
Step-by-step explanation:
she need 45 m ribbon to put around dog picture