math
Determine if the function below is continuous.

graph of a piecewise function, with 2 pieces. The first piece is a line that starts at negative infinity and goes through point (-4,5) and ends with an open dot at (1,0). The second piece is a line that starts with a closed dot at (1,-1), goes through point (2,1) and continues to infinity.

A. not continuous at x = 1
B. not continuous at x = 0
C. not continuous at x = -1
D. continuous

MathDetermine If The Function Below Is Continuous. Graph Of A Piecewise Function, With 2 Pieces. The

Answers

Answer 1

The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.


Related Questions

Five ramps lead from the ground to the second floor of a workshop, as sketched below. All five ramps have the same height; ramps B, C, D and E have the same length; ramp A is longer than the other four. You need to push a heavy cart up to the second floor and you may choose any one of the five ramps.Assuming no frictional forces on the cart, which ramp would require you to do the least work?

Answers

The mechanical advantage of ramp A is greater than others and it will require the least force to move the load to greater distance.

Let the height of the ramp = hLet the length of ramp B, C, D and E = LLet the length of the ramp A = 2L

The mechanical advantage of the ramp is calculated as follows;

\(M.A = \frac{L}{h}\)

The mechanical advantage of the ramp B, C, D and E is calculated as;

\(M.A = \frac{L}{h} \\\\\)

The mechanical advantage of the ramp A is calculated as follows;

\(M.A = \frac{2L}{h} \\\\M.A = 2(\frac{L}{h} )\)

Since the length of the ramp A is greater than other ramps, the mechanical advantage will be greater and it will require the least force to move the load to greater distance.

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is it true or false if a force is a push or a pull on a object

Answers

Answer: true

Explanation: a force can be anything that effects an object, as long as the object moves

Answer:True

Explanation:Because anything that is being pushed of pulled is called force.

HOPE IT HELPED :)

Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s

Answers

The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

How to find time?

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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What is the term for the basic unit of electric current?
The basic unit of electric current is the

Answers

The term for basic unit of electric current is called the ampere

What is Electricity?

Electricity is a collection of physical phenomena related to the presence and motion of matter having an electric charge. Both electricity and magnetism are related to the phenomenon of electromagnetic, as defined by Maxwell's equations.

For electricity generation, the three basic forms of energy are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. The majority of electricity is produced by steam turbines powered by fossil fuels, nuclear, biofuels, geothermal, and solar thermal energy.

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if a gold atom is considered to be a cube with sides 2.5x10^-9m, how many gold atoms could stack on top of one another in gold foil with a thickness of 1.0x10^-7m?

Answers

This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

NO. OF GOLD ATOMS THAT CAN STACK

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

2.5 x 10⁻⁹ m  thick gold foil can stack = 1 gold atom1 m thick gold foil can stack = \(\frac{1}{2.5\ x\ 10^{-9}\ m}\) gold atoms1 x 10⁻⁷ m  thick gold foil can stack = \(\frac{1\ x\ 10^{-7}\ m}{2.5\ x\ 10^{-9}\ m}\) gold atoms1 x 10⁻⁷ m  thick gold foil can stack = 40 gold atoms

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what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2​

Answers

The pressure of a tank of uniform cross-sectional area 4.0m2 when the tank is filled with water at a depth of 6m is 58800 Pa.

Pressure calculation

To find the pressure in the tank, we can use the formula for pressure:

Pressure = density x gravity x height

Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 6 m

Thus:

Pressure = 1000 kg/m³ x 9.8 m/s² x 6 m

Pressure = 58800 kg/(m·s²)

Since the unit of pressure is Pascal (Pa), which is equivalent to kg/(m·s²), the pressure in the tank is:

Pressure = 58800 Pa

Therefore, the pressure in the tank when it is filled with water to a depth of 6 m is 58800 Pascal.

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Explain one way the pattern of the moon would be affected if the moon took longer time to orbit the earth

Answers

Each day the Moon's appearance changes depending on where it is in its earth orbit. The pattern of day and night is followed only due to the rotation of the earth.

What is the rotation of the Earth?

The phrases revolution and rotation describe the various movements of the earth. Rotation is the tendency of the planet on its axis.

The movement of the earth around the sun is a definite path or orbit known as revolution. The earth's axis, a fictional line, makes a 6612° angle with its orbital plane.

The rotation of the earth on its axis does not cause night and day. The occurrence of night and day is caused by the rotation of the earth.

The lunar cycle begins when the Sun, Moon, and Earth are aligned (the Moon is between the Earth and the Sun, and the hemisphere of the Moon faces away from the Earth.

As a result, if the moon took longer to orbit the Earth, the pattern would be disrupted.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?

Answers

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Find the focal length of a thin plano-convex lens. The front surface of this lens is flat, and the rear surface has a radius of curvature of Assume that the index of refraction of the lens is

Answers

The focal length is the sum of the focal lengths of the front and back surfaces, which equals 70 cm.

How long is the piano's focal length?The one who gives it, The F universe encompasses us. Inversely, it was R minus 1 over 1. When we enter the values and multiply them by one, we see that f is equivalent to 70 centimetres. The worst case scenario is one point 5/1 minus one, the best case is infinite minus one, and the other case is negative 35 centimetres with the indoor sign.You can use the following equation to get the lens' focal length: The focal length is the sum of the focal lengths of the front and back surfaces, which equals (35 cm + 35 cm) or 70 cm.

The complete question is,

A narrow plano-convex lens' focal length should be determined. This lens's back surface is curved at a radius of R 2R 2 = approximately 35 cm, while its front surface is flat. Let's say the lens has an index of refraction of 1.5.      

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Damon purchased a pair of sunglasses that were advertised as being polarized. Describe how Damon could test the sunglasses to verify they are polarized.

Answers

Answer:

To verify that they're polarized, he could hold the two lenses perpendicular (90 degrees) to each other, one lens in front of the other, and point it at a light source. If no light passes through then the lenses are polarized

The test of Polarization of pair of sunglasses is , hold the two lenses perpendicular to each other, one lens in front of the other, and point it towards a light source. If no light passes through then the lenses are polarized.

When a beam of light is reflected from a smooth surface, such as water or ice, it becomes polarized.Polarized light irritates the eyes and makes it hard to see clearly.

For example, when fishing on a sunny day, you wouldn't see through the water. You would only see a reflection of the sun hitting the water.

Polarized lenses will neutralize the reflection of the water, and you will be able to into the water.

To verify that  pair of sunglasses are  polarized, he could hold the two lenses perpendicular  to each other, one lens in front of the other, and point it towards a light source. If no light passes through then the lenses are polarized.

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1. Calculate the increase in length of an iron wire that is 30m long at 20°c when it is warmed to 45°c (take airon 1.1x10³J/k)
2. If 2200 Joule of heat is added to a 190 g object its temperature increases by 12°c.W hat is
a. specific heat capacity
b. heat capacity of the object​

Answers

The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.

ΔL = L × α × ΔT

Where:

ΔL is the change in length

L is the original length of the wire

α is the coefficient of linear expansion for iron

ΔT is the change in temperature

The coefficient of linear expansion for iron is typically 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\).

Given:

L = 30 m (original length of the wire)

α = 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\) (coefficient of linear expansion)

ΔT = 45°C - 20°C = 25°C (change in temperature)

ΔL = 30 m × (1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\)) × 25°C

= 30 m × 1.1 x\(10^(^-^5^)\) × 25

= 8.25 x \(10^(^-^3^)\) m

2) Q = mcΔT

Where:

Q is the heat energy transferred

m is the mass of the object

c is the specific heat capacity

ΔT is the change in temperature

Given:

Q = 2200 J (heat energy transferred)

m = 190 g (mass of the object)

ΔT = 12°C (change in temperature)

a. Specific heat capacity (c):

one need to rearrange the formula to solve for c:

c = Q / (m × ΔT)

Substituting the given values:

c = 2200 J / (190 g × 12°C)

First, need to convert the mass to kilograms:

m = 190 g = 190 g / 1000 = 0.19 kg

Now can calculate the specific heat capacity:

c = 2200 J / (0.19 kg × 12°C)

= 9.62 J/(kg°C)

b. Heat capacity (C):

The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.

C = mc

Substituting the given values:

C = 0.19 kg × 9.62 J/(kg°C)

= 1.83 J/°C

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A sinusoidal function has a frequency of 1/6π, a maximum value of 12, a minimum value of −6 , and a y-intercept of 3.Which function could be the function described?

A sinusoidal function has a frequency of 1/6, a maximum value of 12, a minimum value of 6 , and a y-intercept

Answers

Given the frequency is 1/6π

A maximum value is 12

A minimum value is -6

A y-intercept is 3.

The general form of the sinusoidal function,

\(f=a.\sin (bx+c)+d\)

Given

\(\begin{gathered} b=\frac{1}{3} \\ T=\frac{2\pi}{b} \\ T=\frac{2\pi}{\frac{1}{3}} \\ T=6\pi \end{gathered}\)\(\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{6\pi} \end{gathered}\)

The maximum value is 12.

\(9+3=12\)

The minimum value is -6.

\(-(9-3)=-6\)

the y-intercept of 3.

\(f(x)\text{ = }9\text{ sin(}\frac{1}{3}x)+3\)

Thus, the given option (a) is correct.

A Cadillac Escalade has a mass of 2,569.6 kg, if it accelerates at 4.65 m/s^2 what is the net force of the car?

Answers

Answer:

11948.64 Newtons

Explanation:

A box slides across a frictionless horizontal surface with constant acceleration 4.70 m/s2 and over a time interval reaches a final velocity of 13.0 m/s. (a) If its initial velocity is 6.50 m/s, what is its displacement (in m) during the time interval?

Answers

The displacement of the box is obtained as 13.48 m along the horizontal surface.

What is the displacement?

Let us recall that the displacement is the distance covered in a specific direction. The displacement is a vector quantity because it has both magnitude and direction.

In this case, we want to obtain the displacement of the box when;

Initial velocity u = 6.50 m/s

final velocity v =  13.0 m/s

Acceleration a = 4.70 m/s2

Now;

v^2 = u^2 + 2as

s = v^2 -  u^2 /2a

s = (13)^2 - (6.5)^2/ 2 (4.70)

s = 126.75/9.4

s = 13.48 m along the horizontal surface

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What is the force between two balloons with a negative charge of 1.6 × 10−10 C if the balloons are 0.05 m apart?

Answers

Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Coulomb's Law

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

Force between two balloons

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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Which of the following diagrams would be a good, strong magnet?​

Which of the following diagrams would be a good, strong magnet?

Answers

I think A but I’m most likely wrong

What kind of life cycle do insects that undergo a complete metamorphosis have?
Group of answer choices

A. Pupal lifecycle

B. Hemimetabolous

C. Incomplete lifecycle

D. Holometabolous

Answers

Answer:

A

Explanation:

insects undergo Pupal life cycle

A 20000kg railroad car is traveling at 5 m/s when it collided and coupled with a second, identical car at rest. What is the resulting speed of the combined cans?

Answers

We know that in a collision the momentum of the system is conserved, that is:

\(p_i=p_f\)

In this case, since the railroad cars coupled together and have the same mass we have:

\(mv_1+mu_1=2mv\)

Now, we know the initial velocity of the cars, one is traveling at 5 m/s and the other is at rest; plugging the values and solving for the final velocity we have:

\(\begin{gathered} 20000(5)+20000(0)=2(20000)v \\ v=\frac{5(20000)}{2(20000)} \\ v=2.5 \end{gathered}\)

Therefore, the velocity of the combined cars is 2.5 m/s

A ski resort can manufacture enough machine made snow in 4 h to open its steepest run, whereas it would take 12 h of naturally falling snow to provide enough snow. If the resort makes snow while it is snowing naturally, how long (in h) will it take until the run can open?

Answers

The run will be able to open in 4 hours when machine-made snow is produced while it is snowing naturally.

Let the rate of production of machine-made snow be m units/hour, and the rate of snowfall be n units/hour. From the given information, we know that:

m × 4 = n × 12 => m/n = 3/1

Let the time taken for the run to open when both types of snow are produced simultaneously be t hours.

In that time, the ski resort will have produced mt units of machine-made snow and nt units of naturally falling snow.

We also know that mt + nt is equal to the amount of snow required to open the run. Therefore:

mt + nt = m × 4 => nt = m(4 - t) (1) and

mt + nt = n × t => mt = n(t - 12) (2)

Substituting the value of m/n obtained above in (1), we have:

nt = 3n(4 - t) => nt = 12n - 3nt => nt = 6n (3)

Substituting the value of mt obtained above in (2), we have:

n(t - 12) = 3nt => t = 4 hours

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Two objects are held close together. When they are released, they move toward one another. Which conclusion is supported by this evidence? A) The objects are both positively charged. B) The objects are both negatively charged. C) The objects have no charge. D) The objects have opposite charges.

Answers

When two objects held close together and then released, they move toward each other. The phenomenon can be explained by the Coulomb's Law. Coulomb's Law is given by: $F=k\frac{q_{1}q_{2}}{r^2}$ where F is the electrostatic force, q1 and q2 are the magnitudes of the charges, r is the distance between the centers of the charged objects, and k is Coulomb's constant.

This law states that like charges repel and opposite charges attract. This means that when two charged objects of the same charge are held close together, they will repel one another, and when released, they will move away from each other. Therefore, option A (The objects are both positively charged) and B (The objects are both negatively charged) are ruled out. The only conclusion that is supported by the evidence is that the objects have opposite charges, which is option D. The objects attract each other because of the electrostatic force of attraction between opposite charges.In conclusion, when two objects held close together and then released, they move towards each other. This is due to the Coulomb's Law which states that like charges repel and opposite charges attract. Therefore, the conclusion that is supported by this evidence is that the objects have opposite charges.

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3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)

Answers

When viewed from the boat, the velocity of the rock will be equal to the sum of the velocity of the rock relative to the passenger (3.0 m/s north) and the velocity of the passenger relative to the boat (4.0 m/s south).

Therefore, the velocity of the rock when viewed from the boat will be:

Vrock (boat) = Vrock (passenger) + Vpassenger (boat)

Vrock (boat) = 3.0 m/s north + (-4.0 m/s south)

Vrock (boat) = -1.0 m/s south

So, when viewed from the boat, the velocity of the rock will be 1.0 m/s south.

When viewed from the shore, the velocity of the rock will be equal to the velocity of the boat relative to the shore (15.0 m/s south) plus the velocity of the rock relative to the boat (which we calculated as -1.0 m/s south).

Therefore, the velocity of the rock when viewed from the shore will be:

Vrock (shore) = Vrock (boat) + Vboat (shore)

Vrock (shore) = -1.0 m/s south + (-15.0 m/s south)

Vrock (shore) = -16.0 m/s south

So, when viewed from the shore, the velocity of the rock will be 16.0 m/s south.

Describe the elements that are present in this dance. (10pts)

A. Dancer
____________
_____________


B. Choreography
______________
______________

C.Subject
________
_________

D. Movements
___________
___________

E. Costume
___________
___________​

Answers

/Answer:/

;;

/Explanation:/

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the fastest tennis service by a man is 246,2 km.hr-1 by Andy Roddick of the United States of America during a match in London in 2004. Calculate the ball's momentum if it has a mass of 58 g?

Answers

Answer:

Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).

Explanation:

Convert velocity to the standard units (meters per second):

\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).

Convert mass to standard units (kilograms):

\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).

When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:

\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

A certain cylinder has a height of 10.0 cm and a radius of 5.0 cm. To how many significant figures can its volume be determined?

Answers

Answer:

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height. Substituting the given values, we get:

V = π(5.0 cm)^2(10.0 cm) = 785.4 cm^3

The radius and height are both given to two significant figures, so the answer should also be reported to two significant figures. Therefore, the volume of the cylinder can be determined to 780 cm^3.

Explanation:

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16. An object with a mass of 20.0 kg has a force of 5.0 newtons applied to it. What is the resulting acceleration of the object?

Answers

Answer:

0.25m/s^2

Explanation:

F = ma

a = F/m

(Newton's Second Law)

12 Ω resistor and a 15 Ω resistor are connected in series across a 9.0 V potential difference. What is the current in the circuit

Answers

The current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

Current in the series circuit

The current in the series circuit is determined by applying ohms law as shown below;

V = IR

where;

I is the currentR is equivalent resistance of the circuit

R = 12 Ω  + 15 Ω  = 27 Ω

I = V/R

I = 9/27

I = 0.333 A

Thus, the current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

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Calculate the magnitude of the magnetic field at a point 16.0 cm from a long, thin conductor carrying a current of 3.50 A.

Answers

Answer:

The magnitude of the magnetic field is  \(B = 1.392 *10^{-6} \ T\)

Explanation:

From the  question we are told that

     The distance of the position that is being considered to the conductor is

         \(d = 16 \ cm = 0.16 \ m\)

      The current  flowing through  conductor is  \(I = 3.50 \ A\)

Generally the magnitude of the magnetic  field due to a current carrying conductor  is mathematically represented as

          \(B = \frac{\mu_o I}{2 \pi d}\)

Where   is the permeability of free space with value  \(\mu_o = 4\pi * 10^{-7} N/A^2\)

substituting values

           \(B = \frac{ 4\p *10^{-7} *3.50}{2 * 3.142* 0.16}\)

            \(B = 1.392 *10^{-6} \ T\)

Select the correct graph. Coach Hagen times Gabe as he runs around the school's track. He records the time it takes Gabe to complete four laps in the table below. Lap Time (min) Total Time (min) Lap 1 1:01 1:01 Lap 2 1:01 2:02 Lap 3 1:01 3:03 Lap 4 1:01 4:04 Which of the following could be the total distance traveled vs. time graph for Gabe's run?

Select the correct graph. Coach Hagen times Gabe as he runs around the school's track. He records the

Answers

Answer:

upper part second pic

Explanation:

if you observe the trend it increases with each lap and the guy increases the distance he has covered with each lap so distance increases with time

Graph B is correct graph with increase in time distance increases linearly. Displacement is not like that.

What is Displacement?

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

Distance is scalar quantity it will increase linearly with time as Hagen is running in the ground.

The two graphs, x vs. t that are distance vs time  appear as linear.

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A 115 kg hockey player, Adam, is skating east when he tackles a stationary 133 kg player, Bob. Afterward, they move at 1.35 m/s east. What was Adam's velocity before the collision? (Unit = m/s) ​

Answers

Answer:

Explanation:

Conservation of momentum

115v + 133(0) = (115 + 133)1.35

v = 2.911304...

v= 2.91 m/s east

Answer:

The velocity east is 2.91

Explanation:

Fill in the box

2.91

If a jet travels 350 m/s, how far will it travel each second?

Answers

Answer:

It will travel 350 meters each second.

Explanation:

The unit rate, 350 m/s, tells us that the jet will travel 350 meters per every second elapsed.

Answer:

5.83 seconds

Explanation:

60 seconds in 1 minute

350 meters per second

350/60

=5.83

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