Match the role played in a group to the scenario that portrays the role.
dysfunctional role
functional role
maintenance role
Dione is a supervisor who engages her team in team-building activities. She makes
sure that every member has an equal say on different matters. She listens to her team
members' inputs and values their opinions.
Dean is quite mean to his team members. He keeps looking for flaws in others, and if
someone performs badly or makes a mistake, he is quick to pounce on them. He also
tries to pit one member against the other, creating an unhealthy working environment.
Ronald assigns tasks to his team members depending on their abilities. He is clear
about what is expected of the member based on the assigned task. He encourages the
team to be supportive of one another and boost the overall team spirit.
Donna creates opportunities for her team members to interact with one another and
function as a productive team. She encourages her team to collectively find solutions
to problems and discuss topics based on the members' personal experiences and
knowledge.
task role

Match The Role Played In A Group To The Scenario That Portrays The Role.dysfunctional Rolefunctional

Answers

Answer 1

The role played in the group by the different members are:

Maintenance role - Dione Dysfunctional role - Dean Task role - Ronald Functional role - Donna

How are the roles played in the group ?

Dione locks in her group in team-building exercises, which makes a difference reinforce their connections and advances collaboration. Dean's mean-spirited behavior, steady feedback, and endeavors to form clashes among group individuals are counterproductive.

Ronald relegates errands to his group individuals based on their capabilities, ensuring that each part contains a part that adjusts with their aptitudes. Donna makes openings for her group individuals to connected with each other and work as a beneficial group.

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Related Questions

I will give brainliest to whoever is first

Answers

Answer:

first

Explanation:

also wat u need help with

Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.​

Answers

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

A wave travels at a constant speed. How does the wavelength change if the frequency is reduced by a factor of 4?

Answers

Answer:

The product of (wavelength) x (frequency) is always the same number ... the wave's speed.  

So if the wavelength is somehow reduced to  1/4  its original length, the frequency is immediately multiplied by 4 .  That's the only way their product can remain the same.

Explanation:

What is the frequency if you have a period of 5.1 seconds

Answers

Answer:

0.20 Hz

Explanation:

Period formula:

T = 1 / f

rearrange to solve for T (which is period)

F = 1/T

= 1/5.1

= 0.20 Hz

If you want 3 sig figures it would go up to 0.196, but I just rounded to two to get 0.20.

What force pushes the plane upwards

Answers

Answer: The force that pushes a plane upwards is the lift generated by the wings as the plane moves through the air. The lift force is created by the difference in air pressure above and below the wings, which creates an upward force that opposes the weight of the plane.

If an engine cannot be 100%
efficient, what happens to the
energy that is lost?
A. It disappears.
B. It reproduces.
C. It still exists, but in a different form.

Answers

Answer: Given the evidence in the explanation, I'm pretty sure it's C. It still exists, but in a different form.

Explanation: "Some part of the energy supplied is used to change the internal energy of the system. Some part is also released into the surroundings. Generally, frictional losses are more predominant for the machines being not 100% efficient. This friction leads to the loss of energy in the form of heat, into the surroundings."

The answer is C hope this helps

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Answers

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

A geosynchronous satellite orbits Mars once every Martian day, 88640 s then the radius of the orbit will be equal to 2.04 × 10⁷ m.

What is gravity?

The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.

As per the given data in the question,

Mass, m = 6.42 x 10²³ kg

Time, T = 88640 s

Use the formula of velocity for satellite,

v = 2πR/T

Where R represents the radius

Use the formula of centripetal acceleration,

\(a_c\) = v²/R

Thus;

\(a_c\) = (2πR/T)²/R

= 4π²R/T²

The formula for gravitational acceleration is:

\(a_g\) = Gm/R²

G = 6.674 × 10⁻¹¹ m³/kg. s²

Now, the satellite's gravitational acceleration is what is responsible for its centripetal acceleration. Thus,

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Substitute the values in the above equation,

R = ∛((6.674 × 10⁻¹¹ × 6.42 x 10²³ × 88640²)/(4 × π²))

R = 2.04 × 10⁷ m

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Joe went 4.2 km/h south and then went 4.1 kw/h west. From start to finish, joe went 5.9 kw/h southwest. 1. What are the instantaneous velocities? 2.what is the average velocity?

Joe went 4.2 km/h south and then went 4.1 kw/h west. From start to finish, joe went 5.9 kw/h southwest.

Answers

(1) The instantaneous velocities are 4.2 km/h south and 4.1 km/h west

(2) The average velocity of Joe is 5.9 km/h southwest.

What are the instantaneous velocities?

The instantaneous velocities are the velocities of Joe at any given time period and it is calculated as follows;

v (1 ) = 4.2 km/h south

v ( 2 ) = 4.1 km/h west

The average velocity of Joe is calculated from the ratio of the total displacement to total time of motion.

v (avg) = ( total displacement ) / ( total time of motion )

v (avg) = 5.9 km/h southwest

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What is the shape of a line graph that shows the temperature change over time of the liquid before it starts to boil.

Answers

The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.

In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.

This is because as heat is applied to the liquid, its temperature increases at a consistent rate.

During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.

Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.

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2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration versus timegraphs. (Assume the object starts at x= 0 m at time t= 0 s).Be sure to label bothaxes of each graph with the correctscale.

3.Given the acceleration versus timegraph shown below, sketch the corresponding velocity versus timeand position versus timegraphs. Assume that initial velocity and position at t= 0 s is equal to 0 m/s and 0 m respectively. Be sure to label bothaxes of each graph with the correctscale.

2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration

Answers

Graphical analysis of motion gives the graphical the relationships between position, velocity, and acceleration, versus time

2. Please find attached the required position versus time and acceleration versus time graphs

3. Please find attached the required velocity versus time and position versus time graphs

The reasons the attached graphs are correct are given as follows:

2. The given coordinates of the vertex points obtainable from the graph is first written as follows:

\(\begin{array}{|c|c|c|c|c|}\underline {Time, \ t}&\underline {Velocity, \ v}&Acceleration, a&\underline {Distance , \ s =v\cdot \Delta t+\dfrac{1}{2} \cdot a \cdot (\Delta t)^2}&Position\\0&-1&0&0&0\\2&1&1&0&0\\4&-1&-1&0&0\\6&1&1&0&0\\10&1&0&4&4\\12&0&-0.5&1&5\end{array}\)The distance covered between time intervals of time, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Other values on the graph obtained by calculation on a spreadsheet are;

\(\begin{array}{|l|cl|}Time \ (s)&&Position \ (m)\\0.5&&-0.375\\1&&-0.5\\1.5&&-0.375\\2.5&&0.375\\3&&0.5\\3.5&&0.375\\4.5&&-0.375\\5&&-0.5\\5.5&&-0.375\\6.5&&0.5\\7&&1\\7.5&&1.5\\8&&2\\8.5&&2.5\\9&&3\\10&&4\\10.5&&4.4375\\11&&4.75\\11.5&&4.9375\\12&&5\end{array}\right]\)

Please find attached the acceleration versus time graph

3. The coordinates of the points are presented as follows:

\(\begin{array}{|c|cc|}\underline{Time\ (s)}&&\underline{Acceleration\ (m/s^2)}\\0&&0.5\\2&&0.5\\2&&0\\4&&0\\4&&-0.5\\6&&-0.5\\6&&0\\8&&0\\8&&0.5\\10&&0.5\\10&&-0.5\\12&&-0.5\end{array}\right]\)

The distance covered between time intervals, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Using a spreadsheet application, more detailed values of the position can be found as shown in the graph created with MS Excel

Time

0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 7, 7.5, 8, 8.5, 9, 9.5, 10, 10.5, 11, 11.5, 12

Position

0, 0.06, 0.25, 0.56, 1.00, 1.50, 2, 2.5, 3, 3.5, 3.81, 4.00, 4.06, 4.06, 4.06, 4.06, 4.06, 4.13, 4.31, 4.63, 5.06, 5.50, 5.81, 6, 6.06

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2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration
2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration
2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration
2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration

magnetism/ magnetic field ana magnetic forces

magnetism/ magnetic field ana magnetic forces

Answers

Answer:

Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.  

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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An ohmic conductor has a resistance R = 100 Ω. It is crossed, for 30 min, by an electric current of intensity I = 0.50 A. a) Calculate the value W¹, of the thermal energy dissipated in this conductor. Give the answer in J and in kWh. b) Deduce the electrical energy consumed by this conductor for the same duration. c) Determine the value of the thermal power dissipated in this conductor. d) What will be the electrical energy W², consumed by this conductor, for a period of 30 min, if the value of the intensity I is doubled? Compare W¹ and W².

Answers

Answer:

a) The thermal energy in Joules, W¹ = 45000 Joules

The thermal energy in kWh, W¹ = 0.0125 kWh

b) The electrical energy consumed by this conductor for the same duration = 0.0125 kWh

c) The thermal power = 25 Watts

d) The electrical energy, W² = 180 kJ

Explanation:

The resistance of the ohmic conductor, R = 100Ω

The time taken, t = 30 min

t = 30 x 60 seconds

t = 1800 seconds

The current, I = 0.50 A

a) The thermal energy, W¹ dissipated in the conductor is claculated as:

W¹ = I² x R x t

Substitute I = 0.50, t = 1800, R = 100 into the formula above

W¹ = 0.50² x 100 x 1800

W¹ = 45000 Joules

W¹ = 45 kJ

\(\begin{gathered} 1\text{ Joule = 2.78}\times10^{-7}kWh \\ 45000\text{ Joules = 45000}\times2.78\times10^{-7} \\ 45000\text{ Joules = }0.0125\text{ kWh} \end{gathered}\)

W¹ = 0.0125 kWh

b) The electrical energy consumed by the conductor for the same duration

According to the principle of energy conservation

The electrical energy consumed by the conductor = Thermal energy dissipated in the conductor

Therefore:

The electrical energy consumed by this conductor for the same duration = 0.0125 kWh

c) The value of the thermal power dissipated in this conductor

The thermal power = The thermal energy / Time

The thermal power = 45000/1800

The thermal power = 25 Watts

d) The electrical energy W², consumed by this conductor, for a period of 30 min, if the value of the intensity I is doubled

If the current intensity is doubled, I = 2(0.50)

I = 1 A

The resistance, R = 100 Ω

The time, t = 30 min = 30 x 60 seconds

t = 1800 seconds

W² = I² x R x t

W² = 1² x 100 x 1800

W² = 1 x 100 x 1800

W² = 180000 Joules

The electrical energy if the value of the intensity is doubled, W² = 180 kJ

Mr. Patel is photocopying lab sheets for his first period class. A particle of toner carrying a charge of 4.0 * 10^9 C in the copying machine experiences an electric field of 1.2 * 10^6 N/C as it’s pulled toward the paper. What is the electric force acting on the toner particle?

Answers

Answer:

4.8 × 10^15 N

Explanation:

Electric Field is defined as Force per unit Charge.

This is expressed mathematically as;

E= F/Q

Where E- Electric Field

F- Force

Q- charge

From the expression above by change of subject of formula for F, we have;

F=E×Q

= 1.2 * 10^6 ×4.0 * 10^9

= 4.8 × 10^15 N

A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed 4.20 m/s makes a perfectly elastic collision with a block of mass M at rest. After the collision, the 8.40 block recoils with a speed of 0.400 m/s. In the figure; the blocks are in contact for 0.200 s.

Answers

For A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed of 4.20 m/s  is mathematically given as

F = 193.2N

What is the magnitude of the average force on the 8.40-kg block, while the two blocks are in contact, is closest to?

Generally, the equation for the  magnitude of the average force mathematically given as

F = m(v1+v2)/t

F = 8.40(4.2+O.4)/t

F = 193.2N

In conclusion magnitude of the average force is

F = 193.2N

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If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300 watts 600 watts 750 watts

Answers

Answer:

150 watts

Explanation:

300/2 = 150 watts

Answer:

150 watts

Explanation:

The explanation is in the picture

PLEASE MARK BRAINLIEST

If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300

Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform circular pulley of mass 2m and radius a. Using the angular position of the pulley as generalized coordinate, write down the Lagrangian function and Lagrange's equation. Find the acceleration of the masses.​

Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform

Answers

Answer:   the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity,  they are in equilibrium.

five point charges​ placed on a​ straight line, at intervals d​= 2 cm. We give Q3​=Q5 ​= 8C and Q4 = 4 . For what values ​​of q1 and q2 is the resultant electric force exerted on each of the other three charges zero?

Answers

The values ​​of q1 and q2 in which the resultant electric force exerted on each of the other three charges zero is - 4C.

What is the value of q1 and q2?

The value of charges q1 and q2 is calculated by applying the formula for electric force as shown below.

F = (kqₙqₓ) / (d²)

where;

K is Coulomb's constantq is the magnitude of the chargesd is the distance between the charges

If the force exerted on each of the other three charges is zero, then

F₁₃ + F₃₄ = 0

F₂₃  +   F₃₄ = 0

F₁₃ = (k x q₁ x 8) / (d²)

F₂₃ = (k x q₂ x 8 ) / (d²)

F₃₄ = (k x 8 x 4 ) / (d²)

F₁₃ = - F₃₄

(k x q₁ x 8) / (d²)  = -  (k x 8 x 4 ) / (d²)

8q₁ = - 32

q₁ = -32 / 8

q₁ = - 4 C

F₂₃ = - F₃₄

(k x q₂ x 8 ) / (d²) = -  (k x 8 x 4 ) / (d²)

q₂  = - 4 C

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What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?

Please help!!

Answers

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

P.S. This is part of the answer of another brainly user this is not my knowledge.

But Hope I helped you

Answer:

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²

Help me please I need it as soon as possible

Help me please I need it as soon as possible

Answers

Answer: B im sorry if its wrong

Explanation:

I think the answer would be D

3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).

Answers

The radii of the first five Fresnel zones is 3.6 mm.

Distance from the light source to the wave surface, d₁ = 1 m

Distance from the wave surface to the observation point, d₂ = 1 m.

Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm

The expression for the radius of the Fresnel zones is given by,

rₙ = √[nλd₁d₂/(d₁ + d₂)]

Therefore, the radii of the first five Fresnel zones is,

r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]

r₅ = √(25 x 10⁻⁶/2)

r₅ = 3.6 x 10⁻³m

r₅ = 3.6 mm

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A car travels 1,139 meters South, and 37 seconds what is the average velocity in meters per second to the South?

Answers

Answer:

see below

Explanation:

1 139 m / 37 s = 30.784 m/s   South

The separation distance in B is_____ times greater than in A, the force of attraction is
than A.

Answers

The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

What is the force of attraction between two object?

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

k is Coulomb's constant
q₁ is magnitude of first chargeq₂ is the magnitude of the second charger is the distance between the charges

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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Use the data from Table D of your Student Guide to answer the questions. Be sure to round your answers to the nearest tenth.

Answers

Answer:

table??

Explanation:

What statement best describes the gravitational force of an object?

Answers

The gravitational force of an object is describes as amount of force of attraction of the massive object due to another massive object.

What is gravitational force?

Regardless of whether two objects have equivalent masses or not, the gravitational force will pull them together. Newton's Universal Law of Gravitation also states that everything in the universe, including you, pulls everything else. Newtons, abbreviated N, are the standard unit of gravitational force.

Mathematically, gravitational force between two objects of mass m₁ and m₂ separated by a distance r is given by:

F = Gm₁m₂/r²

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Are we within earths Roche limit

Answers

Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest

Explanation:

In the following calculations, be sure to express the answer in standard scientific notation with the appropriate number of
significant figures.
3.88 x 1079 - 4.701 x 1059
x 10
g

Answers

Answer:

-45,597.07

Explanation:

if not in scientific calculator and yung answer nung sa scientific sa comment na lang dinadownload ko ka eh

Question 1 of 10
A business must decide whether to open a new office in China. If it opens the
branch, it will increase its chances of selling a high volume of its products in
China. On the other hand, the business will have to spend a lot of money to
make the branch operational.
What would be an opportunity cost for the business if it chooses not to open
the new branch in China?
A. The business would lose the chance to make more money in
China.
B. The business would increase its marginal benefits on each
product it makes.

Answers

A. The opportunity cost for the business if it chooses not to open the new branch in China would be that the business would lose the chance to make more money in China.

Opportunity cost refers to the cost of the next best alternative that must be forgone in order to pursue a certain action. In this case, if the business chooses not to open the new branch in China, the opportunity cost would be the potential revenue and profits that could have been generated by selling products in China.

explain the statement that what is matters in an experiment is asking the right questions and not finishing the right answer​

Answers

The statement that what matters in an experiment is asking the right questions and not necessarily finding the right answer potryas the importance of the scientific process and inquiry-based approach.

How do we explain ?

The aim of scientific study is to learn about and comprehend the natural world. This is accomplished through developing hypotheses, posing questions, carrying out experiments, and evaluating the outcomes. While getting the right response is critical, it's just as important to ask the right questions in the first place.

Asking the right questions helps to define the scope and objectives of the experiment and also  guides the researcher to focus on specific variables, design appropriate experiments, and gather relevant data.

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Anita Knapp needs to get hay to cows in a frozen field using an airplane flying 80.0 m/s, at a height of 300,m. If at the last minute, how far from the cow would she have to release the hay in order to hit the cow? *

Answers

Answer:

Explanation:

If we ignore wind resistance, the time needed for the hay to drop from vertical rest is

t = √(2h/g) = √(2(300)/9.81) = 7.82 s

d = vt = 80.0(7.82) = 626 m before passing over the cow.

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