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An object can travel a distance of 20 meters at the same time that it has a displacement of zero.
A. True
B. False

The hole is 5.10 m underneath the water's surface.

On earth, air is indeed a natural attribute that supports life. It occurs in the atmospheric and is essentially a mixture of many different gases, with oxygen, nitrogen, and carbon dioxide making up the majority of it and argon, water vapor, and other gases making up considerably less of it. Aerosolized dust, spores, and germs are also present in the air.

To breathe, we all require oxygen. All living things, both those that are aquatic and those that are on land, require oxygen to survive. Without the basic component of air, life would not be possible.

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The capacitors are connected, each capacitor has a charge of Qdc=6C. The capacitors' capacitances are C1=1.0F and C2=2.0F, and the source's emf is equal to 10V. The potential difference between A and B is 5.0V.

You add each of the capacitances using the method below to determine the total can be of the a number more capacitors joined in this way: CTotal Equals C1 Plus C2 + C3, etc. Example: to determine the combined capacitance of these three parallel capacitors.

C1 and C2 serve as coupling capacitors primarily, letting AC signals travel while block DC at the inputs and outputs in order to prevent voltages from earlier or later circuits from upsetting the biased condition for the this amplifier.

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Answer:

с

creates its own light, which is blocked by the Sun during an eclipse.

Explanation:

might not be right but its what i remember

106 °F is equivalent to 41.11 °C

Temperature conversion from Fahrenheit to Celsius is done using the formula °C = (°F - 32) × 5/9. In this case, we can plug in the given temperature of 106 °F and solve for °C.

Here is the step-by-step process:

1. Subtract 32 from the Fahrenheit temperature: 106 - 32 = 74
2. Multiply the result by 5: 74 × 5 = 370
3. Divide the result by 9: 370 ÷ 9 = 41.11

Therefore, 106 °F is equivalent to 41.11 °C.

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The boundary conditions have a positive effect on the finite difference formulation of interior nodes of the medium. Boundary conditions provide constraints or information at the edges of a computational domain to determine the behavior of the system. In the finite difference method, the values at the boundary nodes are usually known or specified. By incorporating these boundary conditions into the formulation, the behavior of the system is better represented.

When the boundary conditions are properly applied, they help ensure that the finite difference scheme accurately captures the desired physics within the interior nodes. This positive effect allows for more accurate and reliable simulations, as the behavior at the boundaries influences the behavior of the entire system. Boundary conditions have a positive effect on the finite difference formulation of interior nodes. By incorporating the known or specified conditions at the boundaries, the accuracy and reliability of the finite difference method are improved, allowing for a more faithful representation of the desired physics within the system.

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Batteries can be connected in either series or parallel to increase the voltage or current, respectively. When batteries are connected in series, the voltage is added together while the current remains the same. On the other hand, when batteries are connected in parallel, the current is added together while the voltage remains the same.

Batteries connected in series example, if two batteries with a voltage of 1.5V each are connected in series, the total voltage would be 3V. The current, however, would remain the same. This method is useful when the device you are powering requires a higher voltage but doesn't need more current.

Batteries connected in parallel example, if two batteries with a current of 1A each are connected in parallel, the total current would be 2A. The voltage, however, would remain the same. This method is useful when the device you are powering requires a higher current but doesn't need more voltage.

It is worth noting that when connecting batteries in series, the capacity of the batteries is not added together. The capacity is the amount of energy that can be stored in the battery. If two batteries with a capacity of 1Ah are connected in series, the total capacity would still be 1Ah. This is because the current is flowing through both batteries, and the capacity of each is being used. However, when connecting batteries in parallel, the capacity is added together. In the above example, the total capacity would be 2Ah.

Additionally, when batteries are connected in parallel, the state of charge of each battery should be similar. If one battery has a much higher state of charge than the other, the current will be drawn primarily from the battery with the higher state of charge, which can cause the battery to overheat, shorten its life and even cause damage.

In summary, connecting batteries in series will increase the voltage while keeping the current the same, while connecting batteries in parallel will increase the current while keeping the voltage the same. Both have their uses depending on the device that is being powered and the power requirements.

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The back side of a polished spoon has f = -6.50 cm (convex). If you

hold your nose 5.00 cm from it then the  magnification of the image is

0.864.

The formula for calculating magnification in such a case is: Magnification = -di/do

Here, f = -6.50 cm is the focal length of the mirror, and the object is the back side of a polished spoon.

The distance between the object and the mirror, in this case, is the distance between your nose and the spoon, which is 5.00 cm.

Thus, the distance of the image from the mirror is:di = -f/(1/do - 1/f)

Putting the values in the formula, we get:di = -6.50/(1/5 - 1/-6.50) = -4.32 cm (negative sign indicates that the image is virtual)

Using the magnification formula, we have: Magnification = -di/do = -(-4.32)/5.00 = 0.864

Thus, the magnification of the image is 0.864.

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Answer:

An object in motion will stay in motion at the same speed and in the same direction (ie with constant velocity) unless a force makes it change.

Explanation:

Answer: Energy is released to the environment.

Explanation:

The final velocity of the man would be 2.11 m/s in the opposite direction of the motion.

Information provided,

Mass of the man [M] = 36 kg

Mass of the ball [m] = 0.548 kg

Speed of the ball [v] = 15.8 m/s

As of, the conservation of the momentum

MV + mv = 0

[36 × V] + [0.548 × 15.8] = 0

36V = -8.6584

V = -0.2405 m/s

The sign shows that the direction of the man is opposite to the direction of the ball.

After rebounded the direction of the ball would change

MV + m[-v] = [m+M] × \(V_{f}\)

MV - mv = [m+M] × \(V_{f}\)

[36 × -0.2405] - [0.548 × 15.8] = [36 + 0.548] × \(V_{f}\)

-8.658 - 8.6584 = 36.548 × \(V_{f}\)

-17.3164 = 36.548 × \(V_{f}\)

\(V_{f}\) = -2.1106 m/s

The final velocity of the man would be 2.11 m/s in the opposite direction of the motion.

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Answer:

6000 N toward west

Explanation:

F = ma

a = 30-15/10 = 1.5 m/s^2 towards west

m = 4000 kg

F = 4000 x 1.5 = 6000 N towards west

Answer:

The speed of light is a constant, but it can accelerate by changing direction. For instance, light accelerates under the influence of gravity like every other falling object. Reflection is not a very meaningful form of acceleration since the Δt≈0, but it certainly a change in velocity.

The rate of heat rejection from the condenser in kW is 9.305 kW, compressor power in kW is 9.305 kW, and the coefficient of performance would be 1.

Determining heat rejection, compressor power, and coefficient of performance:

(a) To find the rate of heat rejection from the condenser, we can use the equation Q_out = m_dot*h_out - m_dot*h_in, where Q_out is the heat rejected, m_dot is the mass flow rate, h_out is the enthalpy leaving the condenser, and h_in is the enthalpy entering the compressor. We can find the enthalpies using the refrigerant tables for 134a.

At the compressor inlet, the refrigerant is saturated vapor, so the enthalpy is h_in = 292.87 kJ/kg.
At the condenser outlet, the refrigerant is saturated liquid, so the enthalpy is h_out = 311.48 kJ/kg.

Plugging in the values, we get:
Q_out = (0.5 kg/s)(311.48 kJ/kg - 292.87 kJ/kg) = 9.305 kW

Therefore, the rate of heat rejection from the condenser is 9.305 kW.

(b) To find the compressor power, we can use the equation W_compressor = m_dot*(h_out - h_in). Plugging in the values, we get:
W_compressor = (0.5 kg/s)(311.48 kJ/kg - 292.87 kJ/kg) = 9.305 kW

Therefore, the compressor power is 9.305 kW.

(c) The coefficient of performance (COP) is defined as the ratio of the heat removed from the refrigerated space to the work input to the system. We can calculate it using the equation COP = Q_out/W_compressor. Plugging in the values, we get:
COP = 9.305 kW / 9.305 kW = 1

Therefore, the coefficient of performance is 1. This means that for every 1 kW of work input, the system removes 1 kW of heat from the refrigerated space.

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The frequency of the dripping is 1.33 Hz.

The number of full oscillations that any wave element performs in one unit of time is how we determine the frequency of a sinusoidal wave.

The frequency of the dripping can be calculated using the formula:

frequency = number of cycles ÷ time

In this case, each drip is a cycle, and we know that there are 40 drips in 30.0 s, so:

frequency = 40 ÷ 30.0 s = 1.33 Hz

Therefore, the frequency of the dripping is 1.33 Hz.

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Answer:

True

True

Explanation:

The one that is farthest away is the youngest one if we looked at many galaxies formed at the same time.

This consists of stars and interstellar matter which are held together by gravity and make up the universe.

The age of galaxies are gotten by finding its distance from us. In this scenario,  gravitational lensing makes the galaxy brighter and can only be observed at very far distances which is why a young galaxy will be the farthest away.

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Answer:

(D) 421 kPa

Explanation:

The absolute pressure of the tire is equal to the pressure measured plus the atmospheric pressure of 101 kPa. Then, the absolute pressure is

P = 320 kPa + 101 kPa

P = 421 kPa

So, the answer is

(D) 421 kPa

The velocity of the rocket, at the instant, the fuel is exhausted is 2103 m/s

Given that,

m = \(m_{0}\) - k t                               ⇒ ( 1 )

m dv / dt = ck - mg                   ⇒ ( 2 )

dv / dt = ( ck / m ) - g

dv = ( ck / ( \(m_{0}\) - k t ) - g ) dt

∫ dv = c ∫( k / ( \(m_{0}\) - k t ) dt - ∫ g dt

v = -c ln ( \(m_{0}\) - k t ) - gt + \(C_{1}\)       ⇒ ( 3 )

\(C_{1}\) = Constant of integration

At t = 0, v = 0 i.e. v ( 0 ) = 0

Substitute v ( 0 ) = 0 in ( 3 )

0 = -c ln ( \(m_{0}\) - 0k ) - 0 g + \(C_{1}\)    

\(C_{1}\) = c ln ( \(m_{0}\) )

Substitute \(C_{1}\) in ( 3 )

v = -c ln ( \(m_{0}\) - k t ) - gt + c ln ( \(m_{0}\) )

v = c ln ( \(m_{0}\) /  \(m_{0}\) - kt ) - gt     ⇒ ( 4 )

After the fuel is fully consumed after 140 s, the mass of rocket is 25% of initial mass.

m ( 140 ) = 0.25 \(m_{0}\)

From ( 1 )

m ( t ) = \(m_{0}\) - k t    

m ( 140 ) = \(m_{0}\) - 140k

0.25 \(m_{0}\) = \(m_{0}\) - 140k

From ( 4 )

v ( 140 ) = 2500 ln ( \(m_{0}\) /  \(m_{0}\) - 140k ) - 9.8 ( 140 )

v ( 140 ) = 2500 ln ( \(m_{0}\) / 0.25 \(m_{0}\) ) - 1372

v ( 140 ) = 2500 ln ( 4 ) - 1372

v ( 140 ) = ( 2500 * 1.39 ) - 1372

v ( 140 ) = 2103 m / s

Velocity at a given instant is the displacement at that given instant.

The given question is incomplete. The complete question is:

A rocket, fired upward from rest at time t=0, has an initial mass of \(m_{0}\)(including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m = \(m_{0}\) - k t. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity v of the rocket will satisfy the equation m  dv / dt  = c k - m g where g is the acceleration due to gravity. Suppose that the fuel accounts for 75% of the initial mass of the rocket and that all of the fuel is consumed in 140 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g=9.8 m/s and c=2500 m/s.]

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Answer:

Explanation:

Power is the rate at which work is done and can be found by using the formula

\(p = \frac{w}{t} \\ \)

p is power in Watts ( W)

w is the workdone in J

t is time in s

From the question

w = 10,000 J

t = 4 s

We have

\(p = \frac{10000}{4} = 2500 \\ \)

We have the final answer as

Hope this helps you

Answer:

8 valence electrons

Explanation:

Fluoride is F^-, so it has one additional electron, which is expected to be in a valence level (completing a closed-shell inert-gas structure). Thus fluoride should be 1s^2,2s^2,2p^6 , and have 8 valence electrons.

Answer:

A. Their shape

Explanation:

The name clearly shows that the shape of these canals are semi-circular. The semi-circular canals consist of three tubes filled with fluid and located in the inner ear. They help to maintain balance and transmit impulses through the movement of the fluids. The impulses sent through these fluids are sent to the brain for interpretation.

The function of the canals are not indicated by the name, rather the shape is hinted through the name.

Answer:

Incomplete question, but let analyse generally a torque acting on a rotating body

Explanation

Toque is given as

τ = r × F

Where

τ is the torque (Nm)

r is the position vector (m)

F is the force (N).

Let assume we have the following data

F= x•i + y•j + z•k

Also let assume the position vector is

r'= a•i + b•j + c•k

a. The first question, torque at the origin

The origin will have a position vector of r1(0,0,0)

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(0,0,0)

r=(a, b, c)

Then, the torque is given as

τ = r×F

τ = (a, b, c) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ = (a•i + b•j + c•k) × (x•i + y•j + z•k)

τ = a•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + c•k×(x•i + y•j + z•k)

τ = (a•i × x•i)+ (a•i × y•j) + (a•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + (c•k × x•i) + (c•k × y•j) + (c•k × z•k)

Now, using the above law.

τ = 0 + ay•k - az•j - bx•k + 0 + bz•i + cx•j - cy•i + 0

τ= ay•k - az•j - bx•k + bz•i + cx•j -cy•i

Then, rearranging

τ = (bz - cy)•i + (cx - az)•j + (ay - bx)•k

This is general formula for the torque at the origin, so you can apply it to the given values in your question because the question given is not complete.

b. Now let, analyse at the position vector (2.61 m, 0, -8.03 m)

Using the same analysis

position vector of r1(2.61, 0, -8.03)m

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(2.61,0,-8.03)

r=(a-2.61, b, c+8.03)

Then, the torque is given as

τ = r×F

τ = (a-2.61, b, c+8.03) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ =([a-2.61]•i, b•j, [c+8.03]•k) × (x•i + y•j + z•k)

τ = (a-2.61)•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + (c+8.03)•k×(x•i + y•j + z•k)

τ = ((a-2.61)•i × x•i)+ ((a-2.61)•i × y•j) + ((a-2.61)•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + ((c+8.03)•k × x•i) + ((c+8.03)•k × y•j) + ((c+8.03)•k × z•k)

Now, using the above law.

τ = 0 + (a-2.61)y•k - (a-2.61)z•j - bx•k + 0 + bz•i + (c+8.03)x•j - (c+8.03)y•i + 0

τ= (a-2.61)y•k - (a-2.61)z•j - bx•k + bz•i + (c+8.03)x•j -(c+8.03)y•i

Then, rearranging

τ = (bz - cy - 8.03y)•i + (cx + 8.03x - az - 2.61z)•j + (ay - 2.61y - bx)•k

This is general formula for the torque at the point (2.61 m, 0, -8.03 m), so you can apply it to the given values in your question because the question given is not complete.

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.

Here,

The position coordinates of the pebble, r = (0.5 m)j - (2 m)k

Force acting on the pebble, F =  (2 N)i - (3 N)k

(a) About the origin

 Torque acting on the pebble, τ = r x F

   τ = (0.5j - 2k) x (2i - 3k)

   τ = (0.5j x 2i) + (0.5j x -3k) + (-2k x 2i) + (-2k x -3k)

   τ = -1k - 1.5i - 4j + 0

   τ = (-1.5i - 4j - 1k) Nm

(b) At a point with coordinates (8.62m, 0, -2.93m)

    Torque acting on the pebble,

   τ = r x F

   τ = (8.62i - 2.93k) x (2i - 3k)

   τ = (8.62i x 2i) + (8.62i x -3k) + (-2.93k x 2i) + (-2.93k x -3k)

   τ = 25.86j - 5.86j

   τ = 20j Nm

Hence,

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

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Your question was incomplete, but most probably your question was:

Force (2 N)i - (3 N)k acts on a pebble with position vector (0.5 m)j - (2 m)k, relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (8.62 m, 0, -2.93 m)

The change in the internal energy of the system will increase.

The given parameters;

The change in the internal energy of the system is calculated by applying first law of thermodynamics as follows;

ΔU = Q + w

where;

ΔU = 150 J + 270 J

ΔU = 420 J

Thus, the change in the internal energy of the system increases.

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The initial velocity and the height of this building are 29 m/s and 780 meters respectively.

In order to calculate the initial velocity, we would apply the second equation of motion:

S = ut - ½at²

200 = u10 - ½(9.8 × 10²)

200 = u10 - 490

u10 = 490 - 200

u10 = 290

u = 290/10

Initial velocity, u = 29 m/s.

Next, we would determine the height of the building:

H = ut + ½at²

H = 29(10) + ½(9.8 × 10²)

H = 290 + 490

Height, H = 780 meters.

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Answer:

a) 8 seconds if you are using earth's gravity.

b) 48m if the velocity does not change

c) 9.8m/s

Explanation:

As a nebula shrinks under the influence of gravity, its radius decreases and its rate of spin (angular momentum) increases.

This is due to the conservation of angular momentum, which states that the total angular momentum of a system remains constant unless acted upon by an external torque. As the nebula contracts, its mass becomes more concentrated towards the center, which causes it to spin faster in order to maintain its angular momentum. This is similar to the way a figure skater spins faster when they pull their arms in towards their body. The shrinking radius also leads to an increase in the gravitational force, which accelerates the contraction and causes the nebula to spin faster. Eventually, the nebula may collapse under its own gravity and form a protostar, which will continue to spin faster as it becomes a fully-formed star. Overall, the shrinking of a nebula and the increase in its rate of spin are natural consequences of the laws of physics and can provide important insights into the formation and evolution of celestial bodies.

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The chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level of measurement.

In statistics, the level of measurement refers to the nature and properties of the data being collected. There are four levels of measurement: nominal, ordinal, interval, and ratio. Nominal and ordinal levels are considered categorical, while interval and ratio levels are considered numerical. The chi-square test is specifically designed for analyzing categorical data, where the observations can be classified into distinct categories or groups. It is used to determine whether there is a significant association or relationship between two categorical variables.

The test calculates the difference between the observed frequencies and the expected frequencies under the assumption of independence between the variables. It compares the observed and expected frequencies using a chi-square statistic and determines the p-value to assess the statistical significance of the association. Therefore, the chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level because it deals with categorical data and evaluates the relationship between different categories or groups.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer:

Below

Explanation:

CO2 buildup during exercise stimulates respiration